Answer:
they will be the same amount at 6 months with a price of 212
Step-by-step explanation:
1. Make an equation for each in y=mx + b form
2. Y= 28x +44 and Y= 31x +26
3. set them equal to each other( 28x + 44 = 31x + 26) and solve for x (x=6)
4. plug x into each equation (28(6) + 44) and (31(6) + 26)
5. you'll get 212 for both which will be the price
Select the correct answer.
Given the following formula, solve for t.
V = u + at
A.
t = a(v + 2)
B.
t =v+u/a
C.
t = v-u/a
D.
t =
a(v - u)
Answer:
C.
t = v-u/a
is the Answer.
HELP
Mason usually practices piano for 3 1/4 hours every week. This week he practiced for half of his usual time. How long did he practice this week?
Answer:
1.625 hours
Step-by-step explanation:
Can someone help me please!
Answer:
4x^2+17x+15
Step-by-step explanation:
(4x-3)(x+5)
= 4x(x+5) -3(x+5)
= 4x^2+ 20x -3x + 15
= 4x^2 + 17x + 15
There is one and only one EQUATION for every Line in the coordinate plane.
O True
O False
Answer:
False
Step-by-step explanation:
Some friends are making cakes for bake sale. They need 6 cups of sugar. However, they only have 1/4 cup measuring cup. how many times will I need to fill the measuring cup.
You need to fill that 1/4th cup 24 times to get 6 cups of quantity you need for cake bake sale.
What is a fraction ?A fraction indicates how many parts of the total quantity it has.
According to the question given some friends are making cakes for bake sale.
They need 6 cups of sugar. However, they only have 1/4 cup for measuring cup.
Meaning they have a cup which measure 1/4th of the quantity to the previous cup.
∴ 1 cup of sugar that can contain in the previous cup they need 4 cups of sugar for the cup they have.
So, to make the cake they need (6×4) = 24 cups of sugar.
learn more about fractions here :
https://brainly.com/question/1301963
#SPJ2
Which equation has the same value as 46.5-17.32
HELP PLEASE !
In the diagram, PQ bisects ∠CPA.
Determine m∠CPA.
Show your work to support your answer in the box below.
Help plz:))) I’ll mark u brainliest
ASAP!!!
Answer:
x = 10
Step-by-step explanation:
A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is the number of 3-point questions and y is the number of 5-point questions, the system shown represents this situation.
x + y = 24
3x + 5y = 100
What does the solution of this system indicate about the questions on the test?
The test contains 4 three-point questions and 20 five-point questions.
The test contains 10 three-point questions and 14 five-point questions.
The test contains 14 three-point questions and 10 five-point questions.
The test contains 20 three-point questions and 8 five-point questions.
The number of research articles in a prominent journal written by researchers during 1983–2003 can be approximated by U(t) = 4.1e0.6t 0.2 + e0.6t thousand articles per year (0 ≤ t ≤ 20) where t is time in years (t = 0 represents 1983). (a) Find an (approximate) expression for the total number of articles (in thousands) written since 1983 (t = 0). HINT [See Example 5.] (Round your coefficients to two decimal places.) N(t) = (b) Roughly how many articles were written from 1983 to 2003? (Round your answer to the nearest whole number.) thousand articles
Answer:
Step-by-step explanation:
From the information given:
We are to find; an expression for the total no. of articles written since 1983
∴
The total no. of articles written since 1983 [tex]=\int \limts ^t_0 U(t) dt[/tex]
[tex]= \int ^t_0 \limits \dfrac{4.1 e^{0.6\ t}}{0.2+e^{0.6t}} \ dt[/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | 0.2 + e^{0.6 x} \bigg| \bigg]^t_0[/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | 0.2 + e^{0.6 x} \bigg| - \mathtt{In} \bigg|0.2+1\bigg|\bigg][/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | \dfrac{0.2 + e^{0.6 x}}{1.2} \bigg|\bigg][/tex]
[tex]=\dfrac{41}{6} \mathtt{In} \bigg | {0.2 + e^{0.6 x} \bigg|-\dfrac{41}{6} \mathtt{ In} \bigg | 1.2\bigg |[/tex]
[tex]=6.833\times \mathtt{In} \bigg | {0.2 + e^{0.6 x} \bigg|-1.2458[/tex]
[tex]=6.833\times \mathtt{In} \bigg | {0.2 + e^{0.6 x} \bigg|-1.25 \ \mathbf{thousand \ articles}[/tex]
Therefore, the total number of articles written since 1983 is [tex]=6.833\times \mathtt{In} \bigg | {0.2 + e^{0.6 x} \bigg|-1.25 \ \mathbf{thousand \ articles}[/tex]
b. To find how many articles were being written from 1983 to 2003
i.e. t = 2003 - 1983 = 20
∴
Total articles written from 1983 to 2003 is [tex]=\int \limts ^{20}_0 U(t) dt[/tex]
[tex]= \int ^{20}_0 \limits \dfrac{4.1 e^{0.6\ t}}{0.2+e^{0.6t}} \ dt[/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | 0.2 + e^{0.6 x} \bigg| \bigg]^{20}_0[/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | 0.2 + e^{0.6 *20} \bigg| - \mathtt{In} \bigg|0.2+e^{0.6*0}\bigg|\bigg][/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | 0.2 + e^{12} \bigg| - \mathtt{In} \bigg|0.2+e^0\bigg|\bigg][/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | 0.2 + e^{12} \bigg| - \mathtt{In} \bigg|0.2+1\bigg|\bigg][/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | 0.2 + e^{12} \bigg| - \mathtt{In} \bigg|1.2\bigg|\bigg][/tex]
[tex]=\dfrac{4.1}{0.6}\bigg [ \mathtt{In} \bigg | \dfrac{0.2 + e^{12}}{1.2} \bigg|\bigg][/tex]
= 80.75 thousand articles
18. Solve m +2n² = 7m for n.
Answer:
sqrt of 3m (sorry I can't figure out how to get the symbol)
Step-by-step explanation:
M+2n^2=7m
2n^2=7m-m
2n^2=6m
n^2=3m
n= sqrt(3m)
does someone know how to do this??
Answer:
Step-by-step explanation:
Question (1)
From the table showing arithmetic sequence,
First term of the sequence = 18
5th term of the sequence = -10
Explicit formula of an arithmetic sequence,
[tex]T_{n}=a+(n-1)d[/tex]
For 5th term,
-10 = 18 + (5 -1)d
-10 = 18 + 4d
4d = -28
d = -7
Therefore, explicit formula for the table will be,
[tex]T_n[/tex] = 18 + (n - 1)(-7)
= 18 - 7n + 7
= 25 - 7n
[tex]T_n=25-7n[/tex]
Recursive formula → [tex]T_n=T_{n-1}+d[/tex]
[tex]T_n=T_{n-1}-7[/tex]
Question (2),
From the table attached,
First term of the geometric sequence = 6
5th term = 96
Recursive formula of a geometric sequence = [tex]a(r)^{n-1}[/tex]
Here a = first term
r = common ratio
For 5th term from the table,
96 = [tex]6(r)^{5-1}[/tex]
r⁴ = 16
r = [tex]\sqrt[4]{16}[/tex]
r = 2
Therefore, explicit formula will be,
[tex]T_n=6(2)^{n-1}[/tex]
Recursive formula will be,
[tex]T_n=T_{n-1}\times (r)[/tex]
[tex]T_n=2\times T_{n-1}[/tex]
3x (4x – 1) - (x + 5)
Given the slope of a graph is 5 and the y-intercept is -2, identify the correct equation in slope-intercept form.
Answer: y=-2x+5
Step-by-step explanation:
I am not sure if this is exactly what you are asking but all you have to do is plug the variables into the formula y=mx+b
Which should give you the above answer of y=-2x+5
Select all of the ordered pairs (x,y) that are solutions to the linear equation 2x + 3y = 6
PLEASE HURRY I DONT WANNA FAIL
Answer:
b, d, e, f
Step-by-step explanation:
you plug the x and y values in
PPPPPLLLLLEEEEEAAASSSSEEEE I FEEELLL STUUUPIIDIDDDD
Which story could match the graph shown below?
A
Starting from home, Kyle jogs increasing his speed until he gets a cramp. He then slows his pace, begins walking, and returns home.
B
Starting from home, Kyle rides his motorcycle to the lake, and stops for a swim before returning home.
C
Starting from home, Kyle rides his bike up a steep hill, then rides down a hill. He crosses a bridge before he returns home.
D
Starting from home, Kyle rides his motorcycle to the lake, then turns around and returns home, stopping for gas on the return trip.
Answer:
I think its A
Step-by-step explanation:
Since the graph is measuring distance and time, A describes how he increases his speed while running, got a cramp, slowed his speed, then began walking until he returned home which relates to the graph the most.
The story that can match the graph is
Starting from home, Kyle jogs increasing his speed until he gets a cramp. He then slows his pace, begins walking, and returns home.
Option A is the correct answer.
What is speed?Speed is the ratio of distance and time.
It shows how fast an object is moving at a given time.
We have,
From the graph,
The y-axis is the distance.
The x-axis is the time.
This means,
The graph is about speed.
The first line shows a speed increase.
The second line shows a speed decrease.
The third line shows a constant speed.
The last line shows a decrease in speed.
Thus,
The graph shows,
Starting from home, Kyle jogs increasing his speed until he gets a cramp. He then slows his pace, begins walking, and returns home.
Learn more about speed here:
https://brainly.com/question/7359669
#SPJ2
find two numbers whose sum is 27 and product is 365
Answer:
There are no real number solutions to this.
Step-by-step explanation:
x + y = 27
xy = 365
y = 365/x
x + 365/x = 27
x^2 + 365 = 27x
x^2 - 27x + 365 = 0
x = [27 +/- sqrt(27^2 - 4 * 1 * 365)] / 2
x = (27 +/- sqrt (-731)/2
- No real roots.
A bag contains 120 marbles. Some red and the rest are black . There are 19 red marbles for every black marble how many red marbles are In the bag explain your reasoning
Can someone please explain this in a 6th grade way
Answer:
im good but the answer is 34 red marbles
Step-by-step explanation:
HELP!:
Isabella bought four chocolates. The chocolates cost $3.00, $5.00, $2.00, and $1.00. If she only had $14
to spend and wants to buy a fifth chocolate, how much money can she spend on the last chocolate?
Answer:
she can spend 3.00 dollar on he last chocolate
Step-by-step explanation:
14.00-3.00=11.00
11.00-5.00=6.00
6.00-2.00=4.00
4.00-1.00=3.00
please answer the question .
Answer:
The answer is A.
Step-by-step explanation:
I'm very sorry if this is wrong but A would make the most sense. the formula y=mx+b. m is the slope, and b is the y-intercept so A is the most reasonable.
If this helped you I would appreciate it if you marked me Brainliest. Thank you and have a nice day!
Please help me Brainliest for the first to answer or for whoever is correct... Please please please help me
As a construction manager, you are asked to build a new road, which crosses the point (1,0). There is another road already built, which can be expressed as y = -1/2 X − 3. You are asked to build your road such that it crosses this road at a perpendicular angle. Find the correct value for a and b in the following equation of your road. y = + b
Write your answer as an equation in slope-intercept form.
Thank you!
Answer:
y=2x+b
0=2×1+b
-2=b
y=2x-2
16.
The function f has a continuous derivative. The table below gives values of f and its
derivative for x= 0 and x = 4. if [ f(x) dx = 8 , what is the value of S*x f'(x)dx ?
a.--20
b. -13
C. -12
х
0
f(x)
2.
-3
f(x)
5
11
d. -7
4.
The value of ∫xf'(x)dx with upper and lower limits 0 to 4 is -20, option (a) is correct.
What is integration?It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.
We have a function f which has a continuous derivative and the value of
[tex]\rm \int\limits^4_0 {f(x)} \, dx =8[/tex]
To find the value of
[tex]\rm \int\limits^4_0 {x \ f'(x)} \, dx[/tex]
We will use integration by parts.
Let's suppose u = x and v = f'(x)
We know:
[tex]\rm \int u \ v \ dx =u\int v dx -\int u'(\int vdx)dx[/tex]
[tex]\rm \int x \ f'(x) \ dx =x\int f'(x) dx -\int 1(\int f'(x)dx)dx[/tex] (u' = 1)
[tex]\rm \int x \ f'(x) \ dx =xf(x) -\int f(x)dx[/tex] [tex](\rm \int f'(x) dx = f(x))[/tex]
After applying limits, we get:
[tex]\rm \int\limits^4_0 {xf'(x)}dx \, =|xf(x)|^4_0 - \int\limits^4_0 {f(x)} \, dx[/tex]
[tex]\rm \int\limits^4_0 {xf'(x)}dx \, = [ 4f(4)-0f(0)] - \int\limits^4_0 {f(x)} \, dx[/tex]
From the table f(4) = -3 and f(0) 2 put these values in the above expression, we get
[tex]\rm \int\limits^4_0 {xf'(x)}dx \, = [ 4(-3)] - 8 \Rightarrow -20[/tex] [tex]( \rm \int\limits^4_0 {f(x)} \, dx =8)[/tex]
Thus, the value of ∫xf'(x)dx with upper and lower limits 0 to 4 is -20, option (a) is correct.
Learn more about integration here:
https://brainly.com/question/18125359
What would be the slope of a line that is perpendicular If the equation is 4y-16x=24
Answer:
the slope of this equation is 4
so slope of the pendicular is -1/4
Find the average of numbers 0.74, 0.37, 0.42
Answer:
.51
Step-by-step explanation:
.74+.37+.42= 1.53
1.53/3= .51
उत्तम गाय के लक्षण लिखिए
See below
Step-by-step explanation:
उत्तम गाय के लक्षण निम्नलिखित हैं |
1. रंग – सर्वांग काली-श्याम एवं कपिला गाय सर्वोत्तम मानी जाती है. लाल, बादामी या चितकबरे रंगवाली गाय भी श्रेष्ठ मानी गई है. सफेद मोतिया या भूरे रंग की गायें भी अच्छी होती है.
2. चर्म – पतला, चिकना और रेशम-सा नर्म बलोंदार हो.
3. ऊंचाई – जाति के अनुसार बड़े कद की हो.
4. लम्बाई – शरीर लम्बा और छाती चौड़ी होनी चाहिए.
5. सिर – छोटा, मस्तक चौड़ा और गर्दन लम्बी व पतली हो, किन्तु साहिवाल आदि नस्ल के गोवंश भारी तथा छोटी गर्दन वाले होते है.
6. सींग – चिकने तथा जाति (नस्ल) के अनुसार आकार वाले हों. कपिला गाय के सींग हिलते तथा नीचे की ओर झुके हुए व चपटे होते है.
7. कान – उभरे हुए और बड़े हो. उनके भीतर की चमड़ी मुलायम तथा पीले रंग की हो.
8. ऑंखें – साफ, बड़ी, ममतामयी एवं स्निग्ध हो.
9. नाक – साफ हो और उससे पानी न बहता हो.
10. होंठ – कोमल, सटे हुए एवं ताम्बे के से लाल रंग के हो.
11. दांत – सफेद मजबूत तथा कीड़े- रहित हों.
12. जीभ – साधारण लम्बी, कुछ लाल-सी, मुलायम एवं कांटे रहित हो.
13. गला – साफ, सुरीला एवं ऊंचे स्वरवाला हो.
14. पूंछ – पतली, काली चौरी वाली और जाति के अनुसार लम्बी हो. सफेद चौरी वाली लक्षण अधिकतर नस्लों में दोष माना जाता है. किसी नस्ल का ही अच्छा होता है.
15. पुट्ठे – चौड़े, खुले हुए, स्थूल और ऊंचे हो.
16. धुन्नी (पेट के नीचे की चमड़ी) – बड़ी, फैली हुई और मुलायम हो.
17. जांघे – चौड़ी और फासले पर हो.
18. पैर – सुडौल, मजबूत एवं लम्बे हो, परंतु चलते समय आपस में न लगते हो.
19. खुर – सटे हुए, गोल एवं मजबूत हों और इनके भीतर की चमड़ी पीली व मुलायम हो.
20. ऐन – खुला, चौकोर, चौड़ा तथा बड़ा हो. अगले पैरों की तरफ से उभरी हुई रस्सी के आकार की दूध की नसें ऐन की ओर आती दिखाई पड़ती हो.
21. थन – लंबे, मुलायम और दूर-दूर हो. चारों थान एक-से तथा बड़े हों.
22. शरीर – नीरोग तथा भरा हुआ, किन्तु मोटा न हो. वस्तुतः मोटी गाय में केवल मांस ही ज्यादा बढ़ जाता है. जिससे उसकी दूध देने की शक्ति कम हो जाती है.
23. पसमाव (दूध का बहाव) – एक-सा और मोटी धार का हो एवं बर्तन से टकराकर घर-घर की-सी गंभीर ध्वनि करने वाला हो.
24. दूध – पीली झलक वाला और गाढ़ा हो.
25. स्वाभाव – गंभीर, सीधा, प्रेममय एवं उत्तेजना-रहित हो. वह ऐन के छूने पर क्रोध न करने वाली और सबसे सरलतापूर्वक दुहा लेने वाली हो.
26. चाल – मंद और सीधी हो.
27. ज्ञातवंशज – दुधारू गायों तथा बलिष्ठ सांडों के कुल की हो.
28. रूचि – सभी किस्म के अच्छे चारे-दाने को रुचिपूर्वक खाने वाली हो.
29. गलकम्बल एवं ककुंद – झालदार हो और ककुंद पूर्ण विकसित हो.
कहा गया है –
उदर, कुक्षि, कूल्हे दोऊ, माता, छाती, पीठ. ऊँचे उभरे अंग छै, यह शुभ लच्छन दीठ.
युगल नेत्र अरु कर्ण हों, विस्तृत और सामान. मस्तक ऊँचों लेखिये, सब विधि उत्तम जान.
गलकम्बल, गर्दन तथा, पूँछ रु थन दोऊ रान. लम्बे चौड़े अंग लखि, उत्तम कहत सुजान.
Rathna made a deposit into a savings account five years ago. She has not made any other deposits or withdrawals to that account. The money, m, in the account has increased by 6% since the account was opened. Which expression does NOT represent the current balance of Rathna’s savings account?
m(1+0.06)
1.06m
m+0.06m
1+0.06m
Answer:
- - - - - - - - - - - - > 1+0.06m (I think)
What is the solution to the system of equations? 3y+7x=10 and -3y+10x =24 A. (3,7) B. (-3,10) C. (2,-4/3) D. (4/7,2)
85 percent ia d.(4/7,2).
Help help help Helpppppp :cccccccccc
Answer:
[tex]2\frac{1}{6} x+2\frac{1}{6} y[/tex]
Step-by-step explanation:
___ x 4 = 12
___ x 5 = 20
___ x 2 = 10
Answer:
3 x 4 = 12
4 x 5 = 20
5 x 2 = 10
Step-by-step explanation:
3 + 3 + 3 + 3 = 12
3 four times equals 12
This is the same for the others
4 + 4 + 4 + 4 + 4 = 20
Four 5 times equals 20
Answer:
[tex]3 \times 4 = 12 \\ 4 \times 5 = 20 \\ 5 \times 2 = 10[/tex]
Step-by-step explanation:
#1
Let the unknown number be x
[tex]x \times 4 = 12 \\ 4x = 12 \\ \frac{4x}{4} = \frac{12}{4} \\ x = 3 [/tex]
#2
Let the unknown number be y
[tex]y \times 5 = 20 \\ 5y = 20 \\ \frac{5y}{5} = \frac{20}{5} \\ y = 4[/tex]
#3
Let the unknown number be z
[tex]z \times 2 = 10 \\ 2z = 10 \\ \frac{2z}{2} = \frac{10}{2} \\ z = 2[/tex]
Hope this helps you.
Let me know if you have any other questions:-):-)
Jill and Tom ate standing together in a park. Jill walks 25 feet north and Tom walks 45 feet west from the same spot. What is the approximate distance between Jill and Tom? A.20ft. B.37ft. C.52ft. D.70ft
Answer: jill and tom are 20ft
Answer:
20
Step-by-step explanation:
