Determine whether the center of mass of the system consisting of the earth and moon lies inside or outside the earth. Assume that the radius of the earth is 6.37 x 10^3 km, the mass of the earth is 5.98 x 10^24 kg, the mass of the moon is 7.35 x10^22 kg, and the distance between the centers of the earth and the moon is 3.84 x 10^5 km. When computing the center of mass, consider the earth and the moon as point masses.

Answers

Answer 1

Answer:

R_cm = 4.66 10⁶ m

Explanation:

The important concept of mass center defined by

         R_cm = 1 / M   ∑  x_i m_i

where M is the total mass, x_i and m_i are the position and masses of each body

Let's apply this expression to our case.

Let's set a reference frame where the axis points from the center of the Earth to the Moon,

       R_cm = 1 / M (m_earth 0 + m_moon d)

the total mass is

      M = m_earth + m_moon

     

the distance from the Earth is zero because all mass can be considered to be at its gravimetric center

let's calculate

      M = 5.98 10²⁴ + 7.35 10²²

      M = 6.0535 10₂⁴24 kg

we substitute

      R_cm = 1 / 6.0535 10²⁴ (0 + 7.35 10²² 3.84 )

      R_cm = 4.66 10⁶ m


Related Questions

Einstein’s theory of general relativity was published in 1916 it became fully accepted by scientists in the 1960s and is currently the best explanation of gravity, ignore c filled in

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Answer:

It is C

Explanation:

i just answered it on apex

Answer:

C. More evidence needed to be gathered to validate the ideas in the theory.

Explanation:

A P E X

True or false. ciliary muscles are responsible for accommodation of the eye. ​

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Answer:

true

Explanation:

The ciliary muscle is a smooth muscle ring that controls accommodation by altering the shape of the lens

True or false. cones are sensitive to bright light.

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Answer:

false

Explanation:

they r not as sensitive as the rods

pLEASE HURRY !!! ILL GIVE BRAINLIEST!!!!!!!!!!!!!

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I think acceleration

At the lowest point in the jump when the student is stationary, the extension of the bungee
cord is 35 metres.
The bungee cord behaves like a spring with a spring constant of 40 N / m.
Calculate the energy stored in the stretched bungee cord.

Answers

Given parameters:

Extension of the cord = 35m

Spring constant (K ) = 40N/m

Unknown:

The energy stored in the string = ?

Elastic potential energy is a mechanical energy form usually stored in strings.It accrues when an elastic body is stretched or undergoes extension.

mathematically, we can solve for it using the expression below;

   Elastic potential energy  = 0.5 x K x e²

where K is the spring constant

           e is the extension

To solve this problem simply input the parameters;

             Elastic Potential energy  = 0.5 x 40 x 35²

                                                       = 24500J

The energy stored in the stretched bungee cord is 24500J .

A tiger runs at 58 km/h [S]. What is the displacement of the tiger in 38 s?

Answers

58 K/h = 58000/3600= 16.1 m/s
In 38 s displacement is 38x16.1= 612.2 m

A car is traveling at a speed of 70 km/hr for 2 hours​

Answers

Answer:

the answer is 140

Explanation:

70 × 2 = 140km 2hr

the car will travel 140 km in 2 hours.

Give one hazard caused by electrostatic charges and state how the risk from this hazard can be reduced​

Answers

A fire can be started from a spark caused by electrostatic charges. Connection to the ground (earthing) of houses, large appliances often reduces the risk.

One hazard that can be caused by electrostatic charge is :  Electrical equipment damage and it can be reduced by proper earthing of a building

what are electroststic charges ?

Electrostatic charges are electrical charges at rest. They are produced when two bodies rub against each other( contact) or when a naturally charged body comes close to an uncharged body( induction). these charges are mostly felt when there is lightning and thunderstorms.

Buildings are normally designed with spikes are the top of the roof. these spikes attract charges and direct them to the earth, where they are neutralized. so that the effect of lighting is not felt.

In conclusion, electrical discharges cause damages to electrical equipment like televisions. The risk from this hazard can be reduced by proper earthing of the building.

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IF A = (10i -16j) m/s B = (3i + 8j) m/s C = (6i + 20j) m/s determine a and b Such that aA + bB + C=0​

Answers

The value of a and b is 2.7 and -2.9 respectively.

The vectors A, B, and C can be represented as:

A = 10i - 16j m/s

B = 3i + 8j m/s

C = 6i + 20j m/s

The equation and equate the coefficients of the 'i' and 'j' terms on both sides:

ai + 3bi + 6 = 0 (for the 'i' component)

-16aj + 8bj + 20 = 0 (for the 'j' component)

From the first equation:

a + 3b = -6 (equation 1)

From the second equation:

-16a + 8b = -20 (equation 2)

Multiply equation 1 by 8 and equation 2 by 3 to eliminate 'b':

8a + 24b = -48 (equation 3)

-48a + 24b = -60 (equation 4)

Adding equation 3 and equation 4 eliminates 'b':

8a + 24b + (-48a + 24b) = -48 + (-60)

-40a = -108

a = -108 / -40

a = 2.7

Substituting the value of 'a' into equation 1:

2.7 + 3b = -6

3b = -6 - 2.7

3b = -8.7

b = -8.7 / 3

b = -2.9

Therefore, 'a' is  2.7, and 'b' is -2.9, such that aA + bB + C = 0.

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what is kinetic friction in a easy way to understand?

Answers

Answer:

Let's say when you are in a car and the is moving but that stands for potential energy but when it stops it's called KINETIC ENERGY. i hope that help......

Explanation:

Two point charges, with charge magnitudes q and ????, are placed a distance r apart. In this arrangement, each point charge experiences a force of magnitude F. In the three scenarios, q, ????, and r are changed to some multiple of their original values. In each case, fill in the missing value on one of the variables that will result in a force between the point charges that is equal in magnitude to the original F.

Original q Q r
Scenario 1 2q ...Q 4r
Scenario 2 ...q 2Q (1/2)r
Scenario 3 (3/2)q (3/8)Q ...r

Answers

Answer:

1)  Q ’= 8 Q ,  2)    q ’= 16 q ,  3)   r ’= ¾ r

Explanation:

For this exercise we will use Coulomb's law

      F = k q Q / r²

It asks us to calculate the change of any of the parameters so that the force is always F

Original values

                q, Q, r

Scenario 1

      q ’= 2q

       r ’= 4r

     F = k q ’Q’ / r’²

we substitute

     F = k 2q Q ’/ (4r)²

     F = k 2q Q '/ 16r²

we substitute the value of F

      k q Q / r² = k q Q '/ 8r²

       Q ’= 8 Q

Scenario 2

       Q ’= Q

       r ’= 4r

we substitute

      F = k q ’Q / 16r²

      k q Q / r² = k q’ Q / 16 r²

      q ’= 16 q

Scenario 3

      q ’= 3/2 q

      Q ’= ⅜ Q

we substitute

        k q Q r² = k (3/2 q) (⅜ Q) / r’²

        r’² = 9/16 r²

        r ’= ¾ r

Arthur made a labeling the diagram of the three stages of the cell cycle.
What is the error in the diagram

Answers

answer;aExplanation:

match the properties with the subatomic particles

Answers

proton: symbol P, + 1
neutron: symbol n, 0
Electron: symbol e, -1

Gases have a definite shape and volume. O A. True O B. False​

Answers

Answer:

FALSE

Explanation:

wo cars are moving in the same velocity.Car A has a mass of 95 kilograms while car B has a mass of 110 kilograms.How much internia does the car b have compared to car a

Answers

Explanation:

Intertia of an object is defined as its tendency to remain in the state or rest or in state of uniform motion. It is basically the measure of mass of an object. The greater the mass of an object, greater will be its tendency to change its state of motion or state or rest. Also, lesser the mass of the object, lesser will be its tendency to change its state of motion or state of rest.

In this problem, car A has a mass of 95 kg and car B has a mass of 110 kg. Car B has more mass than car A, it will have more inertia than car A.

Hence, inertia of car B is 15 more than the inertia of car A.

a balloon brusts when more air is filled​

Answers

Answer:

It expands due to the elasticity of the rubber. but wen , the rubber is expanded to its maximum point and cannot be stretched further, it will burst because there will be no space for the rubber to accommodate the air.

Explanation:

Use the information below to answer the question(s) that follow(s) A student filled three beakers, each with 50 milliliters of liquid wafer. The student cooled Beaker 1 to form ice. The student heated Beaker 2 to form wafer vapor (gas). Beaker 3 remained at room temperature. The student removed Beaker 1 from the freezer the next day. When the student turned the beaker over, a block of ice fell out and broke into small pieces. Which statement describes the relationship between the mass of the block of ice and the mass of the small pieces of ice? *
4 points
A The mass of the block of ice was slightly greater because some of the small pieces melted.
B The mass of the block of ice was less than the total mass of the smaller pieces of ice.
C The mass of the block of ice was equal to the total mass of the smaller pieces of ice.
D The mass of the block of ice was greater than the total mass of the smaller pieces of ice.

Answers

All u gotta do is break the answer the questions in parts

When the automobile moves away from the listener, its horn seems

a. Low pitched (low frequency) b. High Pitched (high frequency)
c. Normal (no change in frequency)

Answers

Answer:

The exact opposite of the other question! This one's Low pitched (a)

Explanation:

See the explanation for the other question xD

If a car travels 500 m in 10 seconds how fast is it going?
O 50 m/s
O 5 m/s
O 5,000 m/s
O 5 Km/s

Answers

Answer:

50m/s

Explanation:

Divide 500 by 10 and keep same variables m/s. Hope this helps!

If an object can make 10 revolutions in two minutes what’s it’s period

Answers

Answer:

12[tex]s^{-1}[/tex]

Explanation:

Period= how long for each revolution

Since we have 10 revolutions in 120 seconds.

120/10=12s

Some machines do not multiply the force that is applied to them. Question 20 options: True False

Answers

Explanation:

it is true that some machines do not multiply the force that is applied on them


If two forces act at right angles to each other, the magnitude of the vector sum of the forces can be found by

Answers

Answer:

The formula for the hypotenuse via the Pythagorean Theorem

Explanation:

Notice that if the forces are perpendicular, since they add via the "parallelogram rule", the length of the diagonal of the rectangle they make as one constructs the parallelogram, carries the actual quantity we are looking for.

The diagonal divides  the rectangle formed by the two adding forces, in two right angle triangles, for which the hypotenuse is the diagonal of the rectangle. As such, the magnitude of it can be derived via the Pythagorean Theorem, looking for the length of the hypotenuse.

The use of the Pythagorean theorem

The ossicles (the three tiny bones in the middle ear) are responsible for __________.
A.
converting sound vibrations into neural signals
B.
relaying sound vibrations to the eardrum
C.
vibrating in response to sound waves
D.
amplifying sound vibrations from the eardrum

Answers

Answer:

D.amplifying sound vibrations from the eardrum

this is correct

Answer:

D.amplifying sound vibrations from the eardrum

Explanation:

right on edge

23. Two states of matter are described as follows.
In state 1. the molecules are very far apart. They move about very quickly at random in straight lines
they hit something.
until
In state 2, the molecules are quite closely packed together. They move about at random. They do not have
fixed positions
What is state 1 and what is state 2?*
(1 Point)
State 1 state 2
A solid liquid
B gas solid
Cliquid gas
D gas liquid​

Answers

Answer:

D gas liquid​

Explanation:

The states of matter in 1 and 2 are the gas and liquid phases.

State 1; the molecules are very far apart. They move about quickly at random straight lines.

This is an attribute of a gas. The particles or molecules of gases are very far apart. They are held together by very weak attractive forces. Gases are compressibleExamples are carbon(iv) oxide, oxygen gas

State 2:  the molecules are quite closely packed together. They move about at random. They do not have  fixed positions.

Liquids are held by much stronger attractive forces. Their molecules are closer to each other. They generally flowThey are partially compressible.

Solids are the most closely held together by very strong attractive forces. Their molecules have fixed position.

Therefore, State 1 is gas and State 2 is liquid.

A horizontal spring is attached to a wall at one end and a mass at the other. The mass rests on a frictionless surface. You pull the mass, stretching the spring beyond the equilibrium position a distance A, and release it from rest. The mass then begins to oscillate in simple harmonic motion with amplitude A. During one period, the mass spends part of the time in regions where the magnitude of its displacement from equilibrium is greater than (0.66)A— that is, when its position is between −A and(−0.66)A, and when its position is between (0.66)A and A. What total percentage of the period does the mass lie in these regions?

Answers

Answer:

54%

Explanation:

So, we have that the "magnitude of its displacement from equilibrium is greater than (0.66)A—''. Thus, the first step to take in answering this question is to write out the equation showing the displacement in simple harmonic motion which is = A cos w×t.

Therefore, we will have two instances t the displacement that is to say at a point 2π/w - a2 and the second point at a = a2.

Let us say that 2π/w = A, then, we have that a = A cos ^-1 (0.66)/2π. Also, we have that a2 = A/2 - A cos^- (0.66) / 2π.

The next thing to do is to calculate or determine the total length of of the required time. Thus, the total length is given as:

2a1 + ( A - 2a2) = 2A{ cos^-1 (0.66)}/ π.

Therefore, the total percentage of the period does the mass lie in these regions = 100 × {2a1 + ( A - 2a2) }/A = 2 { cos^-1 (0.66)}/ π × 100 = 54%.

Thus, the total percentage of the period does the mass lie in these regions = 54%.

Traveler A takes the train from New York to Boston. Traveler B flies from Boston to New York.
Describe how the size and direction of displacement of Traveler A is different from the size and
direction of displacement of Traveler B.

Answers

The size (distance) is the same the direction is opposite so one displacement is 180 degrees different to the other.

Geckos can walk on walls and ceilings—at least some of the adhesion is due to static electricity. Gecko feet are covered with microscopic hairs. When these hairs rub against a surface, charges separate, with the hair developing a positive charge and negative charge forming below the surface. There is an attractive force between the separated charges. This is an effective means of adhering to a surface, but it would not be without cost; two planes of charge are like two charged plates of a capacitor, which takes energy to charge. Doubling the amount of charge on each surface will increase the at- tractive force, but will also increase the energy required to separate the charge. By what factor will this energy increase?

Answers

Answer:

 U = 4 U₀

we see that the gecko must use 4 times more energy to double the force

Explanation:

For this exercise they indicate that we can approximate the situation to a charged capacitor, so the stored energy is

            U = Q² / 2C

where C is the capacitance that does not change since it is the same gecko and Q is the stored charge.  In the initial state

          U₀ = Q₀² /2C

They tell us that the load is doubled

         Q = 2Q₀

where Qo is the initial charge; the new energy is

         U = (2Q₀)² / 2C

         U = 4 Q₀² / 2C

         U = 4 U₀

where U₀ is the initial energy

Therefore we see that the gecko must use 4 times more energy to double the force

The force of air resistance acts to oppose the motion of an object moving through the air. A ball is thrown upward and eventually returns to the ground.

a. As the ball moves upward, is the net force that acts on the ball greater than, less than, or equal to its weight?

1. The net force will be greater than the weight of the ball.
2. The net force will be lesser than the weight of the ball.
3. The net force will be equal to the weight of the ball.

b. Repeat part (a) for the downward motion of the ball.

1. net force will be greater than the weight of the ball
2. net force will be lesser than the weight of the ball
3. net force will be equal to the weight of the ball

Answers

Answer:

a. As the ball moves upward, is the net force that acts on the ball greater than, less than, or equal to its weight?

1. The net force will be greater than the weight of the ball.

b. Repeat part (a) for the downward motion of the ball.

3. net force will be equal to the weight of the ball

Explanation:

In a tug-of-war game on one campus, 15 students pull on a rope at both ends in an effort to displace the central knot to one side or the other. Two students pull with force 190 N each to the right, four students pull with force 92 N each to the left, five students pull with force 64 N each to the left, three students pull with force 158 N each to the right, and one student pulls with force 260 N to the left. Assuming the positive direction to the right, express the net pull on the knot in terms of the unit vector. How big is the net pull on the knot? In what direction?

Answers

Answer:

94N to the left

Explanation:

Net force will be the net pull on the knot

Net force = Sum of Direction of force towards the right - Sum of Direction of force towards the left.

For direction of force towards the right:

Two students pull with force 190 N = 2(190) = 380N

Three students pull with force 158 N each to the right = 3(158) = 474N

Total sum of force towards the right = 380N+474N = 854N

For direction of force towards the left:

four students pull with force 92 N each to the left = 4(92) = 368N

Five students pull with force 64 N each to the left = 5(64) = 320N

One student pulls with force 260 N to the left = 1(260) = 260N

Total sun for forces towards the left = 368N+320N+260N = 948N

Net force = 854N - 948N

Net force = -94N

Hence the net pull on the knot is -94N

The net pull on the knot is 94N (Its magnitude) to the left (due to the negative value we arrived at)

A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min at 100.0 km/h, 10.0 min at 55.0 km/h, and 45.0 min at 35.0 km/h and spends 35.0 min eating lunch and buying gas.
(a) Determine the average speed for the trip. km/h
(b) Determine the distance between the initial and final cities along the route. km

Answers

Explanation:

Solution:

Let the time be

t1=35min = 0.58min

t2=10min=0.166min

t3=45min= 0.75min

t4=35min= 0.58min

let the velocities be

v1=100km/h

v2=55km/h

v3=35km/h

a. Determine the average speed for the trip. km/h

first we have to solve for the distance

S=s1+s2+s3

S= v1t1+v2t2+v3t3

S= 100*0.58+55*0.166+35*0.75

S=58+9.13+26.25

S=93.38km

V=S/t1+t2+t3+t4

V=93.38/0.58+0.166+0.75+0.58

V=93.38/2.076

V=44.98km/h

b. the distance is 93.38km

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By turns he would be very kind or very cruel, an animal or a bird, a man or a spirit, and yet, in spite of all these gifts, Manabozho was always getting himself involved in all sorts of troubles. . . .WHY THE DIVER DUCK HAS SO FEW TAIL FEATHERSHaving overcome the powerful Pearl Feather, killed his serpents and escaped all is wiles and charms, the heart of Manabozho welled within him. An unconquerable desire for further adventures seized upon him. He had won in a great fight on land, so he determined his next success should come to him from the water.He tried his luck as a fisherman and with such success that he captured an enormous fish, a fish so rich in fat that with the oil Manabozhowas able to form a small lake. 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There was not a drop left by the time the hare and the marten appeared on the shore of the lake, and they are, in consequence, the slenderest of all creatures.When this ceremony was over Manabozho suggested to his friends, the assembled birds and animals, that the occasion was proper for a little merrymaking; and taking up his drum he cried out:"New songs from the South! Come, brothers, dance!"They all fell in and commenced their rounds. Whenever Manabozho, as he stood in the circle, saw a fat fowl which he fancied pass him, he adroitly wrung its neck and slipped it under his belt, at the same time beating his drum and singing at the top of his lungs to drown the noise of the fluttering, crying out in a tone of admiration:"That's the way, my brothers; that's the way." At last a small duck of the diver family, thinking there was something wrong, opened one eye and saw what Manabozho was doing. Giving a spring, and crying: "Ha-ha- a! 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