Determine whether the coordinate plane shows a reflection in the x-axis, y-axis, or neither.O neitherO X-axisy-axis
Answers
1) To determine a reflection across the x-axis, the rule to be followed is
Pre-Image Image
(x,y) --------------------> (x, -y)
A reflection across the y-axis follows this one:
Pre-Image Image
(x,y) --------------------> (-x, y)
2) Let's pick one point from the pre-image and the image on the graph
Since A (-2,0) and F (1,-3) then we cannot state that there was a reflection across the x-axis or y-axis.
3) The answer is neither
Related Questions
What are the solutions to the equation 3|x + 5| - 2 = 13 ?
Answers
To solve the absolute value equation;
[tex]3|x+5|-2=13[/tex]Note that the left side of the equation is an absolute value. The first step is to remove the absolute value sign, and then the next step is to solve while using the positive and negative value of the number on the right side of the equation.
This is shown below;
[tex]\begin{gathered} 3|x+5|-2=13 \\ \text{remove the absolute value sign;} \\ We\text{ now have;} \\ 3(x+5)-2=13 \\ 3(x+5)=13+2 \\ 3x+15=15 \\ \text{Subtract 15 from both sides;} \\ 3x+15-15=15-15 \\ 3x=0 \\ \text{Divide both sides by 3} \\ \frac{3x}{3}=\frac{0}{3} \\ x=0 \end{gathered}[/tex]Let us now solve for the equation when the right side is -13.
[tex]\begin{gathered} 3(x+5)-2=-13 \\ 3(x+5)=-13+2 \\ 3x+15=-11 \\ \text{Subtract 15 from both sides;} \\ 3x+15-15=-11-15 \\ 3x=-26 \\ \text{Divide both sides by 3;} \\ \frac{3x}{3}=-\frac{26}{3} \end{gathered}[/tex]ANSWER:
[tex]\begin{gathered} x=0, \\ OR \\ x=-\frac{26}{3} \end{gathered}[/tex]The last option is the correct answer
3. Find the volume of the
cylinder. Round to the nearest
tenth. Diameter = 15. Hight = 11
Answers
Answer:
518.4
Step-by-step explanation:
the volume of a cylinder is area of base x height
the radius is half of the diameter = 7.5
area of base = 2πr = 2xπx7.5 = 47.124
volume = 47.124 x 11 = 518.4
Answer please and thanks
Answers
A percentage of 100 · [p' - exp(- 4000 · k)] / p' of carbon-14 has decayed and lost in last 4000 years.
How to determine the remaining percentage of carbon-14 in ancient pollen
In this question we have the case of simple decay of a radioactive isotope (carbon-14) in time, which is represented by the following exponential formula:
p(t) = p' · exp(- k · t)
Where:
p' - Initial amount of pollen.p(t) - Current amount of pollen.k - Decay constant.t - Time, in years.If we know that t = 4000 years, then percentage of lost carbon-14 is:
p = 100 - 100 · p(t) / p'
p = 100 - [100 · exp(- 4000 · k)] / p'
p = 100 · {1 - [exp(- 4000 · k)] / p'}
p = 100 · [p' - exp(- 4000 · k)] / p'
An amount of 100 · [p' - exp(- 4000 · k)] / p' per cent has been decayed and lost.
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Solve for u.
(u-1)²=2u²+8u+25
Answers
Answer:
u = -4 or -6
Step-by-step explanation:
We know that,
( a + b ) = a² + 2ab + b²
Accordingly, let us solve the given equation.
( u - 1 )² = 2u² + 8u + 25
First, solve the brackets.
u² - 2u + 1 = 2u² + 8u + 25
Subtract u² by both sides.
-2u + 1 = 2u² - u² + 8u + 25
-2u + 1 = u² + 8u + 25
Now, add 2u by both sides.
1 = u² + 8u + 2u + 25
Subtract 1 by both sides.
0 = u² + 10u + 25 -1
0 = u² + 10u + 24
And solve the quadratic equation and solve for u.
0 = u² + 6u + 4u + 24
0 = u ( u + 6 ) + 4 ( u + 6 )
0 = ( u + 4 ) ( u + 6 )
Therefore,
u + 4 = 0
u = -4
or
u + 6 = 0
u = -6
Use f(x) = 4x – 2 and g(x) = 5 – x^2 to evaluate the expression.(a)(f o g)(-2)(b)(g o f)(-2)
Answers
Given the functions:
[tex]\begin{gathered} f(x)=4x-2 \\ g(x)=5-x^2 \end{gathered}[/tex]We will find (f o g)(-2)
So, first, we will find the function (f o g)(x) as follows:
[tex]\begin{gathered} \mleft(f\circ g\mright)(x)=f\lbrack g(x)\rbrack=4(5-x^2)-2 \\ (f\circ g)(x)=20-4x^2-2 \\ (f\circ g)(x)=18-4x^2 \end{gathered}[/tex]Now, substitute with x = -2
so,
[tex](f\circ g)(-2)=18-4\cdot(-2)^2=18-4\cdot4=18-16=2[/tex]so, the answer to the part (a) (f o g)(-2) = 2
b) (g o f)(-2)
We will find (g o f)(x) as follows:
[tex](g\circ f)(x)=g\lbrack f(x)\rbrack=5-(4x-2)^2[/tex]Substitute with x = -2
So,
[tex]\begin{gathered} (g\circ f)(-2)=5-(4\cdot-2-2)^2 \\ =5-(-8-2)^2 \\ =5-(-10)^2 \\ =5-100 \\ =-95 \end{gathered}[/tex]So, the answer to the part (b): (g o f)(-2) = -95
Which best describes the relationship between the lines with equations 4x−8y=9 and 8x−7y=9?A. parallelB. same lineC. neither perpendicular nor parallelD. perpendicular
Answers
The given equations are,
4x-8y=9 and 8x-7y=9
The slopes can be determined as,
[tex]\begin{gathered} m_1=\frac{-a}{b}=\frac{-(4)}{-8}=\frac{1}{2} \\ m_2=\frac{-a}{b}=\frac{-(8)}{-7}=\frac{8}{7} \end{gathered}[/tex]As, the slope are not equal nor their product is -1.
Thus, they are neither parallel nor perpendicular.
Thus, option (C) is correct.
help me pleaseeeeeeeeeeeeeeeeeeeeeee
thank you
Answers
Answer:
Domain: A, [1, 7]
Range: [-4, 2]
Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
this is geometry please help
Answers
Answer: 1st one is sometimes
2nd one is always
3rd one I think is always
4th one is always
Step-by-step explanation:
1st one the sum must equal 90 so either one could be greater
2nd one vertical angles always equal each other
3rd one if B is the midpoint it would be AB BC
4th one it will always equal 180
Kylie has an idea for how to calculate 23 23. She says,
"Twenty times 20 is 400, and 3 times 3 is 9;, so 23 23 should be 400 plus 9, which is 409."
What is wrong with Kylie's method? Don't just start over in a different way and don't compute 23-23
directly and compare the answer with Kylie's, work with Kylie's idea. Shade the large square below,
which consists of 23 rows with 23 small squares in each row, to help you explain your answer.
Answers
Answer:
Don't just start over in a different way, work with Kylie's idea. Use the large square below, which consists of 23 rows with 23; Question: 1. Kylie has an idea for how to calculate 23-23. She says, Twenty times 20 is 400, and 3 times 3 is 9, so 23-23 should be 400 plus 9, which is 409.
Step-by-step explanation:
A train can travel 225 kilometers in 3 hours. At this rate, how many kilometers can the train travel in 7 hours?
Answers
Answer: 1575
Step-by-step explanation: You can multiply 225x7 and you will get 1,575
.shvsguvsguvsguvsguss
Answers
Answer:
what is that ? What do you mean
Answer:
m
Step-by-step explanation:
First six non zero multiples of 21
Answers
Answer:
21, 42, 63, 84, 105, 126
Step-by-step explanation:
find the slope x intercept and y intercept of the standard form equation below 7x + 3y equals 42
Answers
Given the equation of the line :
[tex]7x+3y=42[/tex]To find the slope, we will write the equation of the line in slope- intercept form
So, it will be as following :
[tex]\begin{gathered} 7x+3y=42 \\ 3y=-7x+42 \end{gathered}[/tex]Divide all terms by 3
[tex]\begin{gathered} \frac{3y}{3}=-\frac{7x}{3}+\frac{42}{3} \\ \\ y=-\frac{7}{3}x+14 \end{gathered}[/tex]Which will be similar to the general form: y = m * x + b
Where m is the slope
So, the slope of the given equation = -7/3
To find y- intercept, substitute with x = 0
[tex]\begin{gathered} 7\cdot0+3y=42 \\ 3y=42 \\ \\ y=\frac{42}{3}=14 \end{gathered}[/tex]To find x- intercept , substitute with y = 0
[tex]\begin{gathered} 7x+3\cdot0=42 \\ 7x=42 \\ \\ x=\frac{42}{7}=6 \end{gathered}[/tex]so, the answer is :
[tex]\begin{gathered} x-\text{intercept}=6 \\ y-\text{inercept}=14 \\ \text{slope}=-\frac{7}{3} \end{gathered}[/tex]Donovan walked a total of 5 3/8 miles on Sunday and Saturday if he walked 2 and 1/4 Mile on Saturday how many did he walk on Sunday
Answers
The total miles Donovan walked were 5 3/8, we know that he walked 2 1/4 saturday then:
[tex]\begin{gathered} 5\frac{3}{8}-2\frac{1}{4}=\frac{43}{8}-\frac{9}{4} \\ =\frac{43}{8}-\frac{18}{8} \\ =\frac{25}{8} \\ =3\frac{1}{8} \end{gathered}[/tex]He walked 3 1/8 miles on sunday.
In \triangle NOP,△NOP, \overline{PN}\cong \overline{OP} PN ≅ OP and \text{m}\angle P = 50^{\circ}.m∠P=50 ∘ . Find \text{m}\angle O.m∠O.
Answers
The value of the measure of ∠O will be 65°
What is mean by Triangle?
A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.
Given that;
In ΔNOP;
PN ≅ OP
So, ∠O = ∠N
And, Measure of ∠P = 50°
Now,
In the ΔNOP;
The sum of all the three angles are 180°.
The value of the measure of ∠O = x
We get;
∠O + ∠N + ∠P = 180°
Substitute ∠P = 50° and ∠O = ∠N = x we get;
x + x + 50 = 180
2x + 50 = 180
2x = 180 - 50
2x = 130
x = 65
Thus, The value of the measure of ∠O will be 65°.
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Please explain how you got the question because i have no idea how to plug in the numbers
Answers
Given sequence:
[tex]\frac{1}{2},\text{ }1,\text{ }\frac{3}{2},2[/tex]To find the 109th term, we need to first determine whether the sequence follows an arithmetic progression or a geometric progression.
Check
The sequence is arithmetic if the successive terms of the sequence are formed by adding or subtracting a value.
The sequence is geometric if the successive terms of the sequence are formed by multiplying or dividing by a value.
We have that:
first term = 1/2
second term = 1
third term = 3/2
Taking the difference of the second term from the first term:
[tex]\begin{gathered} =\text{ 1-}\frac{1}{2} \\ \text{ = }\frac{1}{2} \end{gathered}[/tex]Taking the difference of the third term from the second term:
[tex]undefined[/tex]Pluto has a diameter of 1,413 miles. What does this distance equal in kilometers?
(1 mile = 1.6 kilometers)
A. 12,761 km
B. 2,275 km
C. 3,476 km
D. 143,042 km
Answers
Therefore, B (2,275 km) is correct.
Hii i forgot how to multiply fractions and I'm a bit rusty since the pandemic
Answers
Solution
The area of a rectangle is given as length(l) x width(w)
length = 2 1/4
width = 1 1/2
Hence substituting these values into the formula
[tex]\begin{gathered} \text{Area = 2}\frac{1}{4}\times1\frac{1}{2} \\ \text{Area = }\frac{(4\times2)+1}{4}\times\frac{(2\times1)+1}{2} \\ \text{Area = }\frac{9}{4}\times\frac{3}{2} \\ \text{Area = }\frac{27}{8}in^2 \\ \text{Area = 3}\frac{3}{8}in^2 \end{gathered}[/tex]I tried to solve this but I immediately got confused.
Answers
Firstly, let us find the perimeter.
Perimeter P is;
[tex]P=AB+BC+AC[/tex]The length of AB and AC can be calculated using the formula for distance between two points.
[tex]\begin{gathered} AB=\sqrt[]{4^2+2^2} \\ AB=\sqrt[]{16+4} \\ AB=\sqrt[]{20} \\ AB=4.47\operatorname{cm} \end{gathered}[/tex][tex]\begin{gathered} AC=\sqrt[]{4^2+4^2} \\ AC=\sqrt[]{16+16} \\ AC=\sqrt[]{32} \\ AC=5.66\operatorname{cm} \end{gathered}[/tex][tex]BC=6\operatorname{cm}[/tex]substituting we have;
[tex]\begin{gathered} P=AB+BC+AC \\ P=4.47\operatorname{cm}+6\operatorname{cm}+5.66\operatorname{cm} \\ P=16.13\operatorname{cm} \end{gathered}[/tex]The perimeter is 16.13 cm.
Secondly, The Area A.
[tex]A=\frac{1}{2}bh[/tex][tex]undefined[/tex]What is inverse of square root? How could the inverse be used to solve an equation that included a square root?
Answers
The power 2 (or exponent 2) is the inverse of the square root:
√x*√x = (√x)² = x
What is the inverse of the square root?
The square root of a number X, gives a number Y such that the product between Y and itself is equal to X, this means that:
if:
√x = y
Then:
y*y = x
So we could write:
√x*√x = (√x)² = x
So the exponent 2 is the inverse of the square root.
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Express x^2-3x+1 in the form (x-p)^2+q
Answers
By algebra properties, the equation x² - 3 · x + 1 in the form (x - p)² + q is equal to (x - 3 / 2)² - 5 / 4.
How to simplify a quadratic equation by completing the square
Completing the square is a method used to simplify quadratic equations of the form a · x² + b · x + c that are not perfect squares, where a part of it becomes into perfect square and is simplified. This can be found by using algebraic methods. The complete procedure is shown below:
x² - 3 · x + 1
(x² - 3 · x + 1) + 0
(x² - 3 · x + 1) + [9 / 4 + (- 9 / 4)]
(x² - 3 · x + 9 / 4) + [1 + (- 9 / 4)]
(x - 3 / 2)² - 5 / 4
The quadratic equation is equivalent to (x - 3 / 2)² - 5 / 4.
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I'm doing topic about classifying numbers can you please help me with these problems?
Answers
According to this question we have to classify what type of number is 10.
The number 10 should be considered as a natural number, real number, rational number, integer number, whole number because of the following reason:
It is a rational and a integer number because because it can be expressed as the quotient of two integers 10/1
Also, it is a natural number because natural numbers are numbers which are used for counting and ordering, and 10 is an example of them.
Also, it is a real number. Real numbers are any number on the real line. So, 10 it is on the real line so, is considered a real number.
Also it is a whole number because it is a natural number.
The radius of a circular pond is increasing at a constant rate, which can be modeled by the function r(t) = 5t, where tis time in months. Thearea of the pond is modeled by the function A(1) = 1+?. The area of the pond with respect to time can be modeled by the compositionA(r(t).Which function represents the area with respect to time?OAA(r(t) = 5x52OBA(r(t) = 25m€2O cA(r(E) = 10x92O D.A(-(t)) = 51t?
Answers
Explanation
We are asked to find the function that represents the area with respect to time A(r(t))
Given that
[tex]\begin{gathered} r(t)=5t \\ \\ A(r)=\pi r^2 \end{gathered}[/tex]what we will simply do will be to put in the value of r(t) into the equation of A(r)
Thus
[tex]\begin{gathered} A(r)=[\pi\times(5t)^2] \\ \\ A(r)=\pi\times25t^2 \\ \\ A(r)=25\pi t^2 \end{gathered}[/tex]Thus, the answer is option B
Express y in terms of x. Then find the value of y when x= -15 - y = 3xY in terms of x:Y=
Answers
first solve y
[tex]\begin{gathered} 5-y=3x \\ 5-y-5=3x-5 \\ -y=3x-5 \\ (-1)\times-y=(-1)\times(3x-5) \\ y=-3x+5 \end{gathered}[/tex]now replace x=-1
[tex]\begin{gathered} y=-3(-1)+5 \\ y=3+5 \\ y=8 \end{gathered}[/tex]Use a net to find the surface area of the rectangular prism the height of the rectangular prism meets the base at a 90° angle
Answers
Answer:
406 square inches
Explanation:
The net of a rectangular prism has 6 rectangular faces.
In this prism, the dimensions of the faces are:
• 2 rectangles with length 7 in. and width 5 in.
,• 2 rectangles with length 7 in. and width 14 in.
,• 2 rectangles with length 14 in. and width 5 in.
Next, we find the surface area of the prism:
[tex]\begin{gathered} \text{Surface Area}=2(7\times5)+2(7\times14)+2(14\times5) \\ =2(35)+2(98)+2(70) \\ =70+196+140 \\ =406in^2 \end{gathered}[/tex]The surface area of the rectangular prism is 406 in².
Solve for the unknown: K/2+3=5
Answers
Solve for K:
[tex]\frac{K}{2}+3=5[/tex]Subtracting 3 to each member of the equation:
[tex]\frac{K}{2}+3-3=5-3[/tex]Operating:
[tex]\frac{K}{2}=2[/tex]Now we multiply by 2:
[tex]2\cdot\frac{K}{2}=2\cdot2[/tex]Simplifying and operating:
[tex]K=4[/tex]Answer: K = 4
Liam is comparing the costs of phone plans at two different companies to determine which plan to buy. Company A charges $50 each month plus an additional $10 per gigabyte of data used. Company B charges $60 each month plus an additional $8 per gigabyte of data used. The following equation represents the cost of the phone plans for the two companies when they are equal, where g represents the amount of gigabytes of data used. 50+10g+60+8g Complete each of the statements below with the correct answer choice.
The cost of the phone plans will be the same for company A and company B when
5?10?15?18? gigabytes of data are used.
If company A changes the cost of data per gigabyte to
20?24?50?8? , then the two phone plans will never have the same cost.
If company B's initial monthly cost Increases by $10?Decreases by $10
and the cost of data per gigabyte Remains the same? Decreases by $2? Increases by $2, then the cost of the two phone plans will always be the same.
Answers
1. Using equations, the cost of the phone plans will be the same for company A and company B when A. 5 gigabytes of data are used.
2. If company A changes the cost of data per gigabyte to D. 8, then the two phone plans will never have the same cost.
3. If company B's initial monthly cost B. Decreases by $10 and the cost of data per gigabyte B. Decreases by $2, then the cost of the two phone plans will always be the same.
What is an equation?An equation is a mathematical statement that shows that two mathematical expressions are equal or equivalent in value.
Equations are represented using the equation sign (=) to establish the equality of two numerical values or mathematical expressions.
Company A Company B
Fixed charge $50 $60
Variable charge per gigabyte $10 $8
The equation to represent when the two plans are equal:
50 + 10g = 60 + 8g
10g - 8g = 60 - 50
2g = 10
g = 5
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4 x 107 is
?
times as much as 4 x 10³.
Answers
Step-by-step explanation:
I think thats 10 times
Answer: 4 x 10^4
Step-by-step explanation:
4 x 10^7= 40,000,000
4 x 10^3 = 4,000
Now 40,000,000 - 4,000 = 40,000
40,000 converts to 4 x 10^4
Complete the order pairs below so they satisfy the equation Y=-3x+2Complete the order pairs (0,__) (7,__) (__,17)
Help!!
Answers
The ordered pairs which satisfy the equation are (0,2) , (7,19) (-5,17) .
Finding the values of the variables that result in equality is the first step in solving a variable equation.
The values of the unknown variables that fulfil the equality are the equation's solutions, also known as the variables for which the equation must be solved. The two forms of equations are identity equations and conditional equations. All feasible values of the variables share the same identity. Only specific instances where the values of the variables coincide can result in the truth of a conditional equation. Two phrases are combined into one by using the equals sign ("="). The "left hand side" and "right hand side" of the equation refer to the expressions on each side of the equals sign. It's typical.At x = 0 the value of y from the equation is :
y = 2
At x = 7 , y =-19
at y=17 , x= -5
Therefore the ordered pairs are :(0,2) , (7,19) (-5,17) .
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The average speed, s, in miles per hour that a student walks the 3 miles from home to school varies inversely as the number of hours, h that the student walks.The formula is given by s = 3/hAs the number of hours it takes the student to walk from home to school increases, what happens to the speed?
Answers
If the number of hours it takes the student to walk home increases, then the speed decreases
Let us see an example
if h = 1
and we increase h to be = 3
[tex]\begin{gathered} \text{when h =1} \\ \text{The sp}eed,\text{ s =}\frac{3}{1}=3milesperhour \end{gathered}[/tex][tex]\begin{gathered} \text{When h increases to 3} \\ s\text{ =}\frac{3}{3}=1mileper\text{ hour} \end{gathered}[/tex]3miles/hour is more than 1 mile/hour so hence the speed will decrease when the time increases
The answer is option A, the speed decreases
