The probability of randomly meeting a three-child family with either exactly one or exactly two boy children is 3/4.
The events described are non-overlapping. Let E be the event of randomly meeting a three-child family with exactly one boy child.
Let F be the event of randomly meeting a three-child family with exactly two boy children.
P(E) = probability of meeting a family with exactly one boy child
P(F) = probability of meeting a family with exactly two boy children
Given that the events E and F are non-overlapping.
So, we can use the formula of either/or probability:
P(E or F) = P(E) + P(F)P(E or F)
= probability of meeting a family with exactly one or two boy children
P(E or F) = P(E) + P(F)P(E or F)
= (number of ways to get a family with exactly one boy child) / (total number of three-child families) + (number of ways to get a family with exactly two boy children) / (total number of three-child families)
P(E or F) = (3 * 2 * 1) / (2 * 2 * 2 * 3) + (3 * 2 * 1) / (2 * 2 * 2 * 3)
P(E or F) = 6/8
P(E or F) = 3/4
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Solve each literal equation for the indicated variable.
11. For h: V = (1/3)bh
Answer:
[tex]h = \frac{3V}{b} \\ [/tex]Step-by-step explanation:
[tex]V = \frac{1}{3} bh \\ [/tex]
To solve for h multiply through by 3 to eliminate the fraction
That's
[tex]3V = 3 \times \frac{1}{3} bh \\ 3V = bh[/tex]
Divide both sides by b to make h stand alone
[tex] \frac{bh}{b} = \frac{3V}{b} \\ [/tex]
We have the final answer as
[tex]h = \frac{3V}{b} \\ [/tex]
Hope this helps you
please help me with the baryon questions!!!
Large N Independent Samples T-Tests 2) Mean Differences: Do athletes in different sports vary in terms of their readiness for college? Reported here are College Board scores of random samples of college basketball and football players. Is there a significant difference at a .05 alpha level? Basketball Football Xbar = 460 442 S= 92 57 n = 102 117
0.5983 falls within the range of -1.9719 to 1.9719, it does not surpass the critical value. Therefore, we fail to reject the null hypothesis.
To determine if there is a significant difference in the readiness for college between basketball and football players, we can perform an independent samples t-test.
Sample size for basketball (n1) = 102
Mean for basketball (Xbar1) = 460
Standard deviation for basketball (S1) = 92
Sample size for football (n2) = 117
Mean for football (Xbar2) = 442
Standard deviation for football (S2) = 57
We can set up the hypotheses as follows:
Null hypothesis (H0): There is no significant difference in the means of readiness for college between basketball and football players.
Alternative hypothesis (H1): There is a significant difference in the means of readiness for college between basketball and football players.
Assuming equal variances, we can calculate the pooled standard deviation (Sp) using the formula:
Sp = sqrt(((n1-1) * S1^2 + (n2-1) * S2^2)/(n1 + n2 - 2))
Plugging in the values:
Sp = sqrt(((101 * 92^2) + (116 * 57^2))/(101 + 116 - 2))
≈ sqrt((850048 + 190278)/(215))
≈ sqrt(1049026/215)
≈ sqrt(4875.182)
≈ 69.81
Next, we calculate the t-statistic using the formula:
t = (Xbar1 - Xbar2)/sqrt((Sp^2/n1) + (Sp^2/n2))
Plugging in the values:
t = (460 - 442)/sqrt((69.81^2/102) + (69.81^2/117))
≈ 18/sqrt(483.5271 + 421.9679)
≈ 18/sqrt(905.4950)
≈ 18/30.09
≈ 0.5983
Finally, we compare the calculated t-statistic with the critical t-value at the desired significance level and degrees of freedom (df = n1 + n2 - 2) to determine if the difference is significant.
At a .05 alpha level with (102 + 117 - 2) = 217 degrees of freedom, the critical t-value is approximately ±1.9719.
Since 0.5983 falls within the range of -1.9719 to 1.9719, it does not surpass the critical value. Therefore, we fail to reject the null hypothesis.
Conclusion: Based on the given data, there is insufficient evidence to conclude that there is a significant difference in the means of readiness for college between basketball and football players at a .05 alpha level.
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What is the probability that at least one of the stocks will rise in price? (Round your answer to 2 decimal places.
The probability that at least one of the stocks will rise in price is 0.92. Rounded to 2 decimal places, the answer is 0.92.
To calculate the probability that at least one of the stocks will rise in
, we can use the complement rule of probability. The complement rule of probability states that the probability of an event occurring is equal to one minus the probability of the event not occurring. Therefore, the probability of at least one stock rising in price can be found by subtracting the probability that none of the stocks will rise in price from one.
Let P(A) be the probability that a stock will rise in price and P(A') be the probability that a stock will not rise in price.
The probability that none of the stocks will rise in price is:
P(A') * P(A') * P(A') = (0.2) * (0.5) * (0.8) = 0.08
The probability that at least one of the stocks will rise in price is:
1 - 0.08 = 0.92
Therefore, the probability that at least one of the stocks will rise in price is 0.92. Rounded to 2 decimal places, the answer is 0.92.
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A contractor is preparing a bid to install swimming pools at a new housing addition. The estimated time to build the first pool is 30 hours. The contractor estimates an 85 percent learning rate. Using POM for Windows or OM Explorer, how long do you estimate the time required to install the fifth pool? The time required to install the fifth pool is __ hours. (Enter your response rounded to two decimal places.) What is your estimate of the total time for all five pools? The total time for all five pools is __ hours. (Enter your response rounded to two decimal places.)
Previous question
The estimated total time for all five pools is approximately 13.85 hours.
To estimate the time required to install the fifth pool using the learning curve, we can use the formula:
Time for nth unit = Time for first unit * (n^b)
Where:
Time for nth unit is the estimated time to install the nth pool
Time for first unit is the estimated time to build the first pool (30 hours)
n is the number of units (in this case, n = 5 for the fifth pool)
b is the learning curve exponent (85% learning rate corresponds to b = log(0.85) / log(2))
Let's calculate the estimated time for the fifth pool:
b = log(0.85) / log(2) ≈ -0.157
Time for fifth pool = Time for first pool * (5^b)
Time for fifth pool = 30 * (5^(-0.157))
Calculating this, we find:
Time for fifth pool ≈ 30 * 0.6764 ≈ 20.29 hours
Therefore, the estimated time required to install the fifth pool is approximately 20.29 hours.
To calculate the total time for all five pools, we need to sum the time required for each pool from the first to the fifth. Since the learning curve assumes decreasing time with increasing units, we can use a summation formula:
Total time for all units = Time for first unit * ((1 - (n^b)) / (1 - b))
Using this formula, let's calculate the total time for all five pools:
Total time for all five pools = Time for first pool * ((1 - (5^b)) / (1 - b))
Total time for all five pools = 30 * ((1 - (5^(-0.157))) / (1 - (-0.157)))
Calculating this, we find:
Total time for all five pools ≈ 30 * 0.4615 ≈ 13.85 hours
Therefore, the estimated total time for all five pools is approximately 13.85 hours.
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Whats does x and y equal?
Answer:
ill help
Step-by-step explanation:
simplify. y^3•y^-7 write with a positive exponet only.
Answer: 1/y^4
Step-by-step explanation:
Solve each of the quadratic equations 3x=0.5x2
Answer:
[tex]3x = 1 \\ x = \frac{1}{3} [/tex]
A bag contains {6} red marbles, {5} yellow marbles, and {7} green marbles. How many additional red marbles must be added to the {18} marbles alredy in the bag so that the probability of randomly drawing a red marble is {3/5}?
Answer:
[tex] \frac{6 + r}{18 + r} = \frac{3}{5} [/tex]
[tex]5(6 + r) = 3(18 + r)[/tex]
[tex]30 + 5r = 54 + 3r[/tex]
[tex]2r = 24[/tex]
[tex]r = 12[/tex]
12 additional red marbles should be added to the 18 marbles already in the bag.
A science textbook is 2/3 of an inch thick if i need 16 textbooks stacked
Answer:
32/3 is the answer and please write it easy
Step-by-step explanation:
Describe a graph of the height of the object over time.
An elevator fills with people on the ground floor. Most get off at the seventh floor and the remainder get off at the ninth floor. Then two people get on at the tenth floor and are carried back to the ground floor without any more stops.
What is the y axis labeled? What is the x axis labeled? What does the graph look like?
Answer: Projectile motion involves objects that are dropped, thrown straight up, ... pjm1. bracketleft. y = height t = time in seconds a = acceleration due to gravity ... Notice that this formula is a quadratic function, which means its graph will be a parabola.
Step-by-step explanation:
Anybody know these answers this is my et for the day
Derrick's Dog Sitting and Darlene's Dog Sitting are competing for new business. The companies ran the ads shown. a. Write and solve an equation to find the number of hours for which Derrick's Dog Sitting $12 plus $5 per hour the total cost will be the same for the two services. b. Analyze Relationships Which dog sitting service is more economical to use if you need 5 hours of service? Explain.
By solving we gets for 6 hours of service, both Derrick's Dog Sitting and Darlene's Dog Sitting will cost the same.
Given the rates for Derrick's Dog Sitting and Darlene's Dog Sitting as shown in the given image. We need to write and solve an equation to find the number of hours for which Derrick's Dog Sitting $12 plus $5 per hour the total cost will be the same for the two services. We are also required to analyze which dog sitting service is more economical to use if we need 5 hours of service.The cost of Derrick's Dog Sitting can be represented as:
C = 12 + 5h
where C is the total cost for h hours.
The cost of Darlene's Dog Sitting can be represented as:
C = 7h where C is the total cost for h hours.To find the number of hours for which both services cost the same, we can equate both equations.
12 + 5h = 7h
Subtracting 7h from both sides, we get:
12 = 2h
Dividing both sides by 2, we get:h = 6
Therefore, for 6 hours of service, both services will cost the same
Therefore, Derrick's Dog Sitting and Darlene's Dog Sitting will cost the same for 6 hours of service.
From the given information, we know that the cost of Derrick's Dog Sitting is $12 plus $5 per hour and the cost of Darlene's Dog Sitting is $7 per hour. To find the number of hours for which the total cost will be the same for both services, we wrote and solved an equation. The equation was 12 + 5h = 7h. On solving it, we found that the number of hours for which the cost will be the same is 6 hours. Therefore, both services will cost the same for 6 hours of service.Now, we need to analyze which dog sitting service is more economical to use if we need 5 hours of service. We can calculate the cost for 5 hours of service for both services using their respective rates. For Derrick's Dog Sitting, the cost for 5 hours of service will be:
12 + (5 x 5) = $37
For Darlene's Dog Sitting, the cost for 5 hours of service will be:7 x 5 = $35
Therefore, if we need 5 hours of service, Darlene's Dog Sitting will be more economical to use as it will cost $2 less than Derrick's Dog Sitting.
Therefore, we can conclude that for 6 hours of service, both Derrick's Dog Sitting and Darlene's Dog Sitting will cost the same. However, if we need 5 hours of service, Darlene's Dog Sitting will be more economical to use as it will cost $2 less than Derrick's Dog Sitting.
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Without knowing any pricing information for Darlene's Dog Sitting, we can't fully answer the question. However, for Derrick's Dog Sitting the equation representing the cost is C = 12 + 5*H, where C is the total cost, and H is the number of hours.
Explanation:In order to find the number of hours for which the total cost for both Derrick's and Darlene's dog sitting services is the same, we need to write and solve an equation. Let's denote the total cost using the symbol C, and the number of hours using H.
For Derrick's Dog Sitting, we know the cost is $12 for the initial fee, plus $5 per hour, which results in the following equation: C = 12 + 5*H.
However, we haven't been given the cost structure for Darlene's service, so we can't complete this part of the question without more information.
Regarding your second question, without knowing the cost for Darlene's Dog Sitting, we cannot say which one is more economical for 5 hours of service.
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a meal consisting of a cheeseburger, large fries, and a chocolate shake provides a total of 1120 kcal. if 40% of total kcal in this meal come from fat, how many grams of fat are in this meal?
There are 49.78 grams of fat in the meal consisting of a cheeseburger, large fries, and a chocolate shake.
A meal that comprises of a cheeseburger, large fries, and a chocolate shake contains a total of 1120 kcal. If 40% of total calories in this meal are from fat, how many grams of fat are in this meal?To calculate the grams of fat in the meal, we have to find out the total calories that come from fat, as 40% of the total calories in the meal come from fat.To find out how many calories come from fat, we have to convert the percentage of calories from fat into actual calories. Therefore, we can use the following formula:Fat percentage = (Calories from fat/Total calories) × 100%Let C be the total number of calories in the meal, then the number of calories from fat is given by:Calories from fat = 40% of CUsing this information, we can rewrite the formula as:Fat percentage = (40% of C/C) × 100%We know that the total number of calories in the meal is 1120 kcal, so we can substitute this value in the formula:Fat percentage = (40% of 1120/1120) × 100%Fat percentage = (448/1120) × 100%Fat percentage = 0.4 × 100%Fat percentage = 40%So 40% of 1120 kcal come from fat. To find out how many calories from fat this is, we can use the formula:Calories from fat = 40% of 1120Calories from fat = 0.4 × 1120Calories from fat = 448 kcalTo calculate the number of grams of fat in the meal, we need to convert the number of calories from fat into grams of fat. We can use the following formula:1 g of fat = 9 kcalUsing this information, we can rewrite the formula as:Calories from fat = grams of fat × 9 kcalDividing both sides of the equation by 9 kcal gives:Grams of fat = Calories from fat/9 kcalSubstituting the value of Calories from fat we calculated earlier gives:Grams of fat = 448 kcal/9 kcalGrams of fat = 49.78 g
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write 0.131313 as a fraction
Answer:
[tex]\frac{13}{99}[/tex]
Step-by-step explanation:
We require to create 2 equations with the repeating numbers after the decimal point.
let x = 0.1313.... → (1) ( multiply both sides by 100 )
100x = 13.1313.... → (2)
Subtract (1) from (2) thus eliminating the repeating numbers
99x = 13 ( divide both sides by 99 )
x = [tex]\frac{13}{99}[/tex]
That is 0.1313.... = [tex]\frac{13}{99}[/tex]
The factory tires for your vehicle are P220/55R17 with circumference of 94.4086 inches. You have decided to purchase some used P265/65R17 with circumference of 96.0165
inches and have a friend install them for you. Since the calibration was not changed in your vehicle, when the speedometer reads 55 mph, how fast will you actually be
traveling?
Answer:
55.94 mph
Step-by-step explanation:
The speedometer is measuring the speed of the vehicle according to the initial configuration.
The number of the revolution, n, that the wheels made in 1 hour is
[tex]n=\frac {\text{Speed}}{\text{Perimeter of the wheel}}[/tex]
Let p and p' be the perimeter of the old and the new wheels respectively.
[tex]P=\pi\times 94.4086[/tex] inches,
[tex]P'=\pi\times 96.0165[/tex] inches.
Since the speedometer is not calibrated according to the new configuration, so, the perimeter of old wheel has been used for the calculation of indicated speed.
[tex]\Rightarrow n=\frac{\text{Speed}}{P}[/tex]
Actually, this number of revolutions in 1 hour is made with the new tires having perimeter P'.
So, the actual speed with new tires is
[tex]=n\times P'[/tex]
[tex]= \frac{\text{Speed}}{P}\times P'[/tex]
[tex]=\frac {55}{\pi\times 94.4086}\pi\times 96.0165[/tex]
[tex]=\frac {55} {94.4086}\times 96.0165[/tex]
[tex]=55.94[/tex] mph
So, the actual speed of traveling is 55.94 mph.
what is the y intercept of the table
-1
1.5
-3
1
Answer:
-3
Step-by-step explanation:
this is a linear equation, it goes up by 2, y intercept is when x=0 so take away 2 from -1 which is -3
Answer:
-3
Step-by-step explanation:
Your slope is 2:1 or 2 y's per 1 x...
the y-intercept is at x = 0...
you must subtract 1 from x = 1 to get x = 0...
therefore, you must subtract 2 from y = -1...
-1 - (-2) = -3
Duncan is selling candy at a concession stand. He already has $2 in his money pouch and
hopes to earn $0.75 for each candy that he sells. This function, y = 2 +.75x, can be
represented by the total money after selling candies. Determine the domain and range if he
sells at least 7 and but no more than 10 candies.
The following is
. (discrete or continuous)
If he sells 9 candies, how much money did he make?
Answer: 6.75 cuz u caculate idk
Step-by-step explanation: why dont
you ask your parent or teacher.
Answer:
Add that
Step-by-step explanation:
what is the y-intercept of the line 6x+2y=7
Use substitution to write an equivalent quadratic equation.
(3x + 2)2 + 7(3x + 2) - 8 = 0
DONE
Answer:
z^2 +7z -8 = 0
Step-by-step explanation:
Let z = 3x+2. Then we can substitute z wherever we see 3x+2.
z^2 +7z -8 = 0 . . . . equivalent quadratic
__
This is easily factored to ...
(z -1)(z +8) = 0
So, the original quadratic has solutions ...
(3x +2) -1 = 0
x = -1/3
and
(3x +2) +8 = 0
x = -10/3
H=L^2/f•c solve for L
Answer:
±sqrt( H *f•c)= L
Step-by-step explanation:
H=L^2/f•c
Multiply each side by fc
H *fc=L^2/f•c * fc
H *f•c=L^2
Take the square root of each side
±sqrt( H *f•c)= sqrt(L^2)
±sqrt( H *f•c)= L
How do I do these? My math teacher didn’t explain it very well
Answer:WFG=116
Step-by-step explanation:
The managing partner of an advertising agency believes that his company's sales are related to the industry sales. He uses Microsoft Excel's Data Analysis tool to analyze the last 4 years of quarterly data (i.e., n 16) with the following results:
Regression Statistics
Multiple R 0.802
R Square 0.643
Adjusted R Square 0.618
Standard Error SYX 0.9224
Observations 16
There is a moderately strong positive correlation between the company's sales and industry sales.
The statistical results from the regression analysis indicate that there is a multiple R value of 0.802. This value represents the correlation coefficient, which measures the strength and direction of the relationship between two variables. In this case, the correlation coefficient suggests a moderately strong positive correlation between the company's sales and industry sales. Additionally, the R-squared value is 0.643, which indicates that approximately 64.3% of the variability in the company's sales can be explained by the variability in industry sales. This suggests that industry sales have a significant influence on the company's sales performance. Furthermore, the adjusted R-squared value is 0.618, which takes into account the number of variables and observations in the regression analysis. It provides a more accurate measure of the model's goodness of fit. Finally, the standard error SYX is 0.9224, which represents the average distance between the actual company sales data and the predicted values based on the regression model. A lower standard error indicates a better fit of the model to the data. Overall, based on the given statistics, it can be concluded that there is a moderately strong positive correlation between the company's sales and industry sales, and industry sales significantly influence the company's sales performance.
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You make a tape of your friend's three favorite TV shows: a comedy, a drama and a reality
show. An episode of the comedy lasts 30 minutes, while an episode of the drama or the
reality show lasts 60 minutes. The tape can hold 360 minutes of programming. You
completely fill the tape with 7 episodes and include twice as many episodes of the drama as
the comedy. How many episodes of each show are on the tape?
Answer:
comedy = 2
drama = 4
reality = 1
Step-by-step explanation:
comedy = 30min
denote as "c"
drama = 60min
denote as "d"
reality = 60min
denote as "r"
write in English
(30min of c) + (60 min of d) + (60min of r) totals to 360 min
translate to mathematics
(30c) + (60d) + (60r) = 360
we also know that there is a total of seven episodes
so we can say
c + d + r = 7
and we also know that there are twice as many episodes of drama as there is of comedy so it can be said that
d = 2c
now there is a system of equations
30c + 60d + 60r = 360
c +d + r = 7
d = 2c
all we know have to do is simplify and solve
substitute in the second equation, into the first
c + d + r = 7
d = 2c
c + 2c + r = 7
simplify
3c + r = 7
r = 7 - 3c
substitute this into the first equation
d = 2c
r = 7 -3c
30c + 60d + 60r = 360
30c + 60(2c) + 60(7 - 3c) = 360
distribute
30c + 120c + 420 - 180c = 360
simplify
-30c + 420 = 360
-420 -420
-30c = -60
c = 2
substitute back into the other equations and solve
d = 2c
d = 2 *2
d = 4
r = 7 - 3c
r = 7 - 3 * 2
r = 7 -6
r = 1
Detecting nonrandomness in errors can be done using:
Multiple Choice
A. MAPs.
B. strategies.
C. correlation coefficients.
D. MSEs.
E. control charts.
The correct answer for detecting nonrandomness in errors is E. control charts. Control charts are a statistical tool used to monitor processes and detect deviations from randomness or expected behavior. They are commonly used in quality control and process improvement to identify any systematic or nonrandom patterns in the data.
Control charts help visualize data over time and compare it to predetermined control limits. If the data falls within these limits and shows a random pattern, it suggests that the process is stable and operating within acceptable limits of variation. However, if the data exhibits nonrandom patterns, such as trends, cycles, or unusual points, it indicates the presence of special causes or systematic errors in the process. By analyzing the control chart, individuals can identify the sources of nonrandomness, investigate the underlying causes, and take corrective actions to improve the process and reduce errors. Therefore, control charts provide an effective method to detect nonrandomness and ensure the quality and consistency of processes.
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Determined three ways have a total cost of six dollars each apple cost $1.50 each banana cost $.30 and there’s two more bananas then apples.
The cost of the apples is 2.9 dollars.
The cost of the bananas is 5.7 dollars.
How to find the number of fruits bought?The total cost is 6 dollars, each apple cost $1.50 each banana cost $.30 and there’s two more bananas then apples.
Therefore,
let
x = number of apples
y = 2x
where
y = number of bananasTherefore, using equations,
1.5(x) + y(0.30) = 6
Hence,
where
y = 2x
1.5(x) + 2x(0.30) = 6
1.5x + 0.6x = 6
2.1x = 6
divide both sides by 2.1
x = 6 / 2.1
x = 2.9 dollars
y = 2(2.9) = 5.7 dollars
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Mr. Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, how much is his overall budget?
Answer:
$5000
Step-by-step explanation:
800/16=50
50*100=5000
Consider this equation:
-2x-4+5x=8
Generate a plan to solve for the variable. Describe the
steps that will be used.
Answer:
Plan: separate the variable term from the constant term; divide by the coefficient of the variable.Steps: add 4 to both sides; collect terms; divide both sides by 3.Step-by-step explanation:
The first step is to look a the equation to see where the variable is in relation to the equal sign, and whether there are any constants on that same side of the equal sign.
Here, the variable terms are on the left, and there is a constant there, as well. The plan for solving the equation is to eliminate the constant that is on the same side of the equation as the variable, then divide by the coefficient of the variable. To find that coefficient, we need to collect terms. In summary, the plan is to ...
add 4 to both sides of the equationcollect termsdivide by the coefficient of the variable (3)Executing that plan, the steps are ...
-2x -4 +5x +4 = 8 +4 . . . . add 4
3x = 12 . . . . . . . . . . . . . . . collect terms
x = 4 . . . . . . . . . divide by 3
Answer:
The goal is to get x all alone. First combine like terms. Apply the addition property of equality to add 4 to both sides. Apply the division property of equality to divide both sides by 3. The result will be x = 4. Finally, check the solution by substituting 4 into the original equation.
Step-by-step explanation:
There are 10 less red skittles than orange skittles in the bag. The orange skittles are also twice the number of red skittles. Find the number of red and orange skittles in the bag.
20 skittles double the number of red
the red skittles have 10 skittles the orange skittles have 20 so its additon
20
+
10
------
30
Answer: there isnt that much math into it but mk
20+10
---------
30
HELPPPPPPPPPPPPPPPpp!
Answer: -4
Step-by-step explanation:
g(2)=2²-4(2)
g(2)=4-8
g(2)=-4
