The first experiment is not a binomial experiment because it does not meet the criteria of a binomial experiment. The criteria of a binomial experiment are:
1. The experiment consists of a fixed number of trials, n.
2. Each trial has only two possible outcomes: success or failure.
3. The trials are independent of each other.
4. The probability of success, p, remains constant for each trial.
In the first experiment, the trials are not independent of each other because the marbles are selected without replacement. This means that the probability of success changes with each trial. Therefore, it is not a binomial experiment.
The second experiment is a binomial experiment because it meets the criteria. There are a fixed number of trials (100), each trial has only two possible outcomes (steel penny or not steel penny), the trials are independent of each other (one penny is selected and then replaced), and the probability of success remains constant (1% for each trial). Therefore, p = 0.01 and n = 100.
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(1 point) Given the function f(x)=x+3x−8 find the following. (a)
the average rate of change of f on [−3,1]: (b) the average rate of
change of f on [x,x+h]:
a) The average rate of change of f on [−3,1] is 4.
b) The average rate of change of f on [x,x+h] is 3+16/h.
The average rate of change of a function f(x) on an interval [a,b] is given by the formula:
Average rate of change = (f(b)-f(a))/(b-a)
(a) To find the average rate of change of f on [−3,1], we plug in the values of a=-3 and b=1 into the formula:
Average rate of change = (f(1)-f(-3))/(1-(-3))
= (f(1)-f(-3))/4
Now, we need to find the values of f(1) and f(-3) by plugging in the values of x into the given function:
f(1)=1+3(1)-8=-4
f(-3)=-3+3(-3)-8=-20
Plugging these values back into the formula, we get:
Average rate of change = (-4-(-20))/4
= 16/4
= 4
Therefore, the average rate of change of f on [−3,1] is 4.
(b) To find the average rate of change of f on [x,x+h], we plug in the values of a=x and b=x+h into the formula:
Average rate of change = (f(x+h)-f(x))/(x+h-x)
= (f(x+h)-f(x))/h
Now, we need to find the values of f(x+h) and f(x) by plugging in the values of x and x+h into the given function:
f(x+h)=x+h+3(x+h)-8
=4x+3h-8
f(x)=x+3x-8
=4x-8
Plugging these values back into the formula, we get:
Average rate of change = (4x+3h-8-(4x-8))/h
= (3h+16)/h
= 3+16/h
Therefore, the average rate of change of f on [x,x+h] is 3+16/h.
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Can somebody tell me If this is right or wrong because I don’t know.
The simple interest values are all wrong
What is simple interest?Simple Interest (S.I) is a method of charging or yielding a specific percentage on the principal amount borrowed/deposited in a particular period. It is calculated using the formula
SI = (Principal*Rate*Time)/100,
a) SI = (450*25.2*3)/100,
SI = %70.2
2) SI = (Principal*Rate*Time)/100,
SI = (250*3.75*5)/100,
$46.875
(3) SI = (Principal*Rate*Time)/100,
SI = (1800*2.1*2)/100,
SI = $75.6
4) SI = (Principal*Rate*Time)/100,
SI = (1500*2.9*2)/100,
SI = $87
5) SI = (Principal*Rate*Time)/100,
SI = (50*1.9*10)/100,
SI =$9.5
6) SI = (Principal*Rate*Time)/100,
SI = (8*0.7*300)/100,
SI = $16.8
7) SI = (Principal*Rate*Time)/100,
SI = (125*2.03*4)/100,
SI = $10.15
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3. Solve by factoring the equation 3x2 – 12x – 15 = 0 and explain what your solutions mean for the equation. Show your work.
The equation 3x² - 12x - 15 = 0 when solved by factoring has the solutions x = 5 and x = -1
How to get to the equation's solutionThe equation 3x² - 12x - 15 = 0, is a representation of the equation in the question.
The aforementioned problem is a quadratic equation, and factoring is one way to solve this kind of issue.
Divide 3 from the equation.
As a result, we have the following
x² - 4x - 5 = 0.
Expanding the equation, we get
x² + x - 5x - 5 = 0.
Factoring the equation, we get
x(x + 1) - 5(x + 1) = 0
The result is
(x - 5)(x + 1) = 0.
We can solve for x by getting
x = 5 and x = -1.
Thus, the equation's answers are 5 and -1.
And it means that there are actually two solutions to the equation.
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2. A billboard is two different colors. What is the area of the white part of the billboard? Explain how you found your answer. 4ft height and 4.5ft base
Answer: To find the area of the white part of the billboard, we first need to find the area of the entire billboard and then subtract the area of the non-white part.
The area of a triangle can be found using the formula:
Area = (1/2) x base x height
In this case, the white part of the billboard is a right-angled triangle with a height of 4 ft and a base of 2.5 ft (half of the total base of 4.5 ft).
The area of the entire billboard is:
Area = (1/2) x base x height
Area = (1/2) x 4.5 ft x 4 ft
Area = 9 ft²
The area of the non-white part of the billboard is:
Area = (1/2) x base x height
Area = (1/2) x 2.5 ft x 4 ft
Area = 5 ft²
Therefore, the area of the white part of the billboard is:
Area of white part = Total area - Area of non-white part
Area of white part = 9 ft² - 5 ft²
Area of white part = 4 ft²
So the area of the white part of the billboard is 4 square feet.
Step-by-step explanation:
Question 3(Multiple Choice Worth 2 points)
(Theoretical Probability MC)
When rolling a 6-sided die twice, determine P(sum of 5).
O
2/6
4/36
5/36
10/36
The probability of rolling a sum of 5 when rolling a 6-sided die twice is 1/9.
The Law of Big Numbers is what?According to the Law of Large Numbers, a fundamental tenet of probability theory, the average of the results of an experiment approaches the predicted value of the random variable being measured as the number of trials in the experiment rises. In other words, the Law of Big Numbers states that the observed results will be closer to the predicted outcomes the more times an experiment is conducted.
The total number of outcomes when a die is rolled two times is 36.
The sum of 5 is obtained for the following outcomes:
(1,4), (2,3), (3,2), and (4,1)
Thus,
P(sum of 5) = 4/36 = 1/9
Hence, the probability of rolling a sum of 5 when rolling a 6-sided die twice is 1/9.
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The star-spangled banner that flew over fort mchenry during the war of 1812 had a perimeter of 144 ft. Its length measured 12 ft more than its width. Use a system of equations to find the dimensions of this flag, which is displayed in the Smithsonian Institution's Museum of America History in washington, D. C
If the length of the flag is 12 ft more than its width, then the width of the flag is 30ft and length of the flag is 42ft.
Let "w" represent the width of the flag.
We know that the length of the flag is 12 feet more than its width, which means:
⇒ Length = w + 12
We also know that the perimeter of the flag is 144 feet,
The Perimeter of flag can be expressed as:
⇒ Perimeter = 2(Length + Width),
Substituting the expression for Length from above,
We get,
⇒ 144 = 2(w+12 + w)
Simplifying the equation:
We get,
⇒ 144 = 2(2w + 12)
⇒ 72 = 2w + 12
⇒ 60 = 2w
⇒ w = 30
So, width of flag is 30 feet. and Length = w + 12,
⇒ Length = 30 + 12
⇒ Length = 42
Therefore, the dimensions of the flag are 42feet by 30feet.
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Natasha wants to average at least 90% in math class. Her test scores so far are 94%, 89%,88%,92%, and 85% What score does she need to earn on her next test to reach her goal
Answer:
Let x be the score Natasha needs to earn on her next test to reach an average of 90%.
To find x, we can use the formula for the average:
average = (sum of scores) / (number of scores)
We know that Natasha has taken 5 tests so far, with scores of 94%, 89%, 88%, 92%, and 85%. We can plug these values into the formula and solve for x:
90% = (94% + 89% + 88% + 92% + 85% + x) / 6
Multiplying both sides by 6, we get:
540% = 448% + x
Subtracting 448% from both sides, we get:
92% = x
Therefore, Natasha needs to earn a score of at least 92% on her next test to reach an average of 90%.
Help me Pleaseee it would mean a lot
Answer:
D is the answer trust me
Restrict the domain of the function f so that the function is one-to-one and is increasing. Then find the inverse function. State the domains and ranges of both / and /-in interval notation, both fand fin Interval notation.
f(x)=(x+3)2 and its inverse is f -1(x)= f(x)'s domain: F-1(x)'s domain:
f(x)'s range: f(x)'s range:
The domain of f⁻¹(x) is [0, ∞) and the range of f⁻¹(x) is [-3, ∞).
The function f(x)=(x+3)² is not one-to-one, as it is a quadratic function and has a parabolic shape. However, we can restrict the domain of the function so that it is one-to-one and increasing. One way to do this is to restrict the domain to be greater than or equal to the x-coordinate of the vertex of the parabola. The vertex of the parabola is at (-3, 0), so we can restrict the domain to be x ≥ -3. In interval notation, this is [-3, ∞).
The inverse function of f(x) can be found by switching the x and y values and solving for y. This gives us:
x = (y+3)²
√x = y+3
y = √x - 3
So the inverse function is f⁻¹(x) = √x - 3. The domain of the inverse function is the range of the original function, and the range of the inverse function is the domain of the original function. Therefore, the domain of f⁻¹(x) is [0, ∞) and the range of f⁻¹(x) is [-3, ∞).
In summary:
f(x)'s domain: [-3, ∞)
f⁻¹(x)'s domain: [0, ∞)
f(x)'s range: [0, ∞)
f⁻¹(x)'s range: [-3, ∞)
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Evaluate the limit { lim_(x rarr 6) } 7(7 x+7)^ 3 Question 13 Evaluate the limit: lim−(x−>9)(7x−63)/(x^2−2x−63)=
Evaluating the limit given by [tex]{ lim_{(x- > 9)} } (7x-63)/(x^2-2x-63)[/tex], we will obtain as a result [tex]7/16[/tex]
How do we evaluate the limit?To evaluate the limit, we need to simplify the expression first. We can do this by factoring the numerator and denominator of the fraction:
[tex]lim_{(x->9)} (7x-63)/(x^2-2x-63) = lim_{(x->9)} (7(x-9))/((x-9)(x+7))[/tex]
Next, we can cancel out the [tex](x-9)[/tex] terms in the numerator and denominator:
[tex]lim_{(x->9)} (7)/(x+7)[/tex]
Now, we can plug in the value of x that the limit is approaching (9) into the expression:
[tex]lim_{(x->9)} (7)/(x+7) = (7)/(9+7) = (7)/(16)[/tex]
Therefore, the limit of the expression as x approaches 9 is 7/16.
Answer: [tex]{ lim_{(x->9)} } (7x-63)/(x^2-2x-63) = 7/16[/tex]
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Write an equation in slope-intercept form of the line that passes through
-9, 5 and -3, 3
Answer: y = 1/3x + 2
Step-by-step explanation:
y = mx+b
to find m: m = 3 - 5 / -3 - (- 9) = -2 / 6 = - 1 / 3
to find b:
3 = -1 / 3 (-3) + b
3 = 1 + b
b = 2
PLEASE HELP
A cylinder-shaped container is used to store water. The container has a height of 6 feet and
diameter of 3 feet.
About how much water is in the container when it is 3/4 full?
o 127 cubic feet
o 42 cubic feet
o 32 cubic feet
o 14 cubic feet
Answer:
32 cubic feet
Step-by-step explanation:
The formula for a cylinder is [tex]\pi r^{2} h[/tex].
The radius of the cylinder is equal to 1.5 feet, since it is [tex]\frac{diameter}{2}[/tex].
Plugging in, the cylinder's full volume is [tex]6\pi 1.5^2[/tex] which is approximately 42.4 cubic feet.
To find the amount of water when it is 3/4 full, multiply 42.4 x .75, to get around 31.8, and 32 when rounded
Math part 4 question 8
The function is decreasing in the interval (3, ∞).
Explain about the decreasing function?You must first compute the derivative, then make it equal to 0, and then determine whether zero values your function is negative between in order to determine whether a function is decreasing. In order to determine once the function is negative and, consequently, decreasing, test values from all sides of these.f(x) = -x² + 6x - 4
Differentiate the equation with respect to 'x'.
f'(x) = -2x + 6
Put f'(x) = 0
-2x + 6 = 0
x = 6/2
x = 3 (critical point)
Now, write the function as:
f(x) = -x² + 6x - 4
-(x² - 6x + 4) (negative form)
Thus, the function is decreasing in the interval (3, ∞)
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The linear regression equation for a data set is y = 3.2x - 1.2. The actual value at = 4 is 14. What is the residual value
at x = 4?
2.4
B 8.0
11.6
D 12.8
Answer: 11.6
Step-by-step explanation: plug in x for 4. 3.2(4)-1.2 = 11.6
Matt's car can travel 555 miles on 15 gallons of fuel. Work out the rate of consumption of fuel of Matt's car in mpg
The rate of consumption of fuel of Matt's car is 37 miles per gallon (mpg).
Matt's car can travel a total distance of 555 miles.
The fuel required to travel the total distance is 15 gallons by Matt's car.
Hence the rate of consumption of fuel of Matt's car can be measured in mpg (miles per gallons) as = Total distance travelled / Total gallons required to travel that distance
(that is, total distance travelled divided by the total amount of gallons to travel the same)
Thus the mpg of Matt's car is = 555 miles / 15 gallons
= 37 miles per gallon
(that is 37 mpg)
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Can someone answer this
Answer:
16
Step-by-step explanation:
g(x)=-5x+1
g(-3)
x=-3
-5(-3) +1
15+1
16
Answer:
See below.
Step-by-step explanation:
For this problem, we are asked to find the value of g(-3).
We are given a Linear Function.
What is a Linear Function?A Linear Function is a Polynomial Function that is commonly graphed. This function most of the time will simply be represented as a straight line when graphed.
For this problem;
[tex]g(x)=-5x+1 \ Find \ g(-3).[/tex]
We simply need to substitute -3 in for x.
[tex]g(-3)=-5(-3)+1[/tex]
Simplify:
[tex]g(-3)=16.[/tex]
Our final answer is g(-3) = 16.
Find the angle between \( \mathbf{u}=\langle-4,-1\rangle \) and \( \mathbf{v}=\langle-5,-2\rangle \) to the nearest tenth of a degree The angle between \( \mathbf{u} \) and \( \mathbf{v} \) is (Round
The angle between \( \mathbf{u}=\langle-4,-1\rangle \) and \( \mathbf{v}=\langle-5,-2\rangle \) is approximately 12.5 degrees. To the nearest tenth of a degree, we can round this to 12.5 degrees.
To find the angle between two vectors \( \mathbf{u} \) and \( \mathbf{v} \), we can use the formula:
\[ \cos \theta = \frac{\mathbf{u} \cdot \mathbf{v}}{\| \mathbf{u} \| \| \mathbf{v} \|} \]
where \( \theta \) is the angle between the vectors, \( \mathbf{u} \cdot \mathbf{v} \) is the dot product of the vectors, and \( \| \mathbf{u} \| \) and \( \| \mathbf{v} \| \) are the magnitudes of the vectors.
First, we need to find the dot product of \( \mathbf{u} \) and \( \mathbf{v} \):
\[ \mathbf{u} \cdot \mathbf{v} = (-4)(-5) + (-1)(-2) = 20 + 2 = 22 \]
Next, we need to find the magnitudes of \( \mathbf{u} \) and \( \mathbf{v} \):
\[ \| \mathbf{u} \| = \sqrt{(-4)^2 + (-1)^2} = \sqrt{16 + 1} = \sqrt{17} \]
\[ \| \mathbf{v} \| = \sqrt{(-5)^2 + (-2)^2} = \sqrt{25 + 4} = \sqrt{29} \]
Now we can plug these values into the formula and solve for \( \theta \):
\[ \cos \theta = \frac{22}{\sqrt{17} \sqrt{29}} \]
\[ \theta = \cos^{-1} \left( \frac{22}{\sqrt{17} \sqrt{29}} \right) \]
Using a calculator, we find that \( \theta \approx 12.5 \) degrees.
Therefore, the angle between \( \mathbf{u}=\langle-4,-1\rangle \) and \( \mathbf{v}=\langle-5,-2\rangle \) is approximately 12.5 degrees. To the nearest tenth of a degree, we can round this to 12.5 degrees.
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What are the solutions to the equation x2−4x−5=0
?
Answer:
I think the answer is x= 5, -1
Answer:
i got x= 5,-1
Step-by-step explanation:
i hope this helps and have a good day
Find any numbers for which the rational expression is undefined. (7x^(4)+8)/(5x^(2)+20x)
The numbers for which the rational expression is undefined are x=0 and x=-4.
To find the numbers for which the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined, we need to find the values of x that make the denominator equal to zero. This is because division by zero is undefined.
So, we need to solve the equation 5x^(2)+20x=0 for x.
We can factor out a common factor of 5x from the equation:
5x(x+4)=0
Now, we can use the zero product property to set each factor equal to zero and solve for x:
5x=0 or x+4=0
x=0 or x=-4
So, the numbers for which the rational expression is undefined are x=0 and x=-4.
In summary, the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined for x=0 and x=-4.
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Marco mixes 135 pounds of quartz
with some marble. If the ratio stays
the same for every bag, how many
pounds of marble will Marco need?
Marco will need 2025 pounds of marble.
What is the ratio?The ratio is defined as the relationship between two similar magnitudes in terms of the number of times the first includes the second.
Let's say that Marco mixes 1 bag of quartz with x pounds of marble. Then the ratio of quartz to marble in this bag is:
135 pounds quartz : x pounds marble
3 pounds quartz : x/45 pounds marble
Now we know that the ratio of quartz to marble in one bag is 3: (x/45). Since the ratio stays the same for every bag, we can set up a new proportion using the total amount of quartz and marble:
135 pounds quartz : x pounds marble = total pounds quartz : total pounds marble
We know the total pounds of quartz is 135. Let's call the total pounds of marble "m".
Substituting these values into the proportion, we get:
135 : x = 135 : m/45
To solve for x, we can cross-multiply and simplify:
135(m/45) = 135x
3m = 45x
m = 15x
So, Marco will need 15 times as many pounds of marble as he has of quartz, or:
m = 15 × 135 = 2025 pounds of marble.
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The table for the quadratic functions f(x) and g(x) are given. x f(x) g(x) −2 4 8 −1 1 2 0 0 0 1 1 2 2 4 8 Determine the type of transformation and the value of k.
g(x) = f(2x)
g(x) = 2f(x)
g of x equals f of one half times x
g of x equals one half times f of x
please ASAP!!
Using the scale factors obtained the values are -
The value of k is 8, since g(−2) = 8.
The value of k is 8, since g(−2) = 8.
The value of k is 8, since g(−2) = 1.
The value of k is 4, since g(−2) = 2.
What is scale factor?
The scale factor of a shape refers to the amount by which it is increased or shrunk. It is applied when a 2D shape, such as a circle, triangle, square, or rectangle, needs to be made larger.
For each part, we can use the given table to determine how the transformation affects the function values -
g(x) = f(2x)
This transformation is a horizontal compression by a factor of 2.
To see this, notice that when we evaluate g at x = -1, we get the same value as f evaluated at x = -2.
Similarly, when we evaluate g at x = 0, we get the same value as f evaluated at x = 0.
And so on. In other words, the function values of g(x) are the same as the function values of f(x) at every other point (starting with x = -2).
So, g(x) is a compressed version of f(x) horizontally by a factor of 2.
Therefore, the value of k is 8, since g(−2) = 8 = f(2×(-2)).
g(x) = 2f(x)
This transformation is a vertical stretch by a factor of 2.
To see this, notice that every value of g(x) is twice the corresponding value of f(x).
So, g(x) is a stretched version of f(x) vertically by a factor of 2.
Therefore, the value of k is 8, since g(−2) = 2f(−2) = 2×4 = 8.
g(x) = f(x/2)
This transformation is a horizontal stretch by a factor of 2.
To see this, notice that when we evaluate g at x = -2, we get the same value as f evaluated at x = -4.
Similarly, when we evaluate g at x = -1, we get the same value as f evaluated at x = -2.
And so on. In other words, the function values of g(x) are the same as the function values of f(x) at every other point (starting with x = -4).
So, g(x) is a stretched version of f(x) horizontally by a factor of 2.
Therefore, the value of k is 8, since g(−2) = f(−1) = 1.
g(x) = (1/2)f(x)
This transformation is a vertical compression by a factor of 2.
To see this, notice that every value of g(x) is half the corresponding value of f(x).
So, g(x) is a compressed version of f(x) vertically by a factor of 2.
Therefore, the value of k is 4, since g(−2) = (1/2)f(−2) = (1/2)×4 = 2.
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Sheng has two credit cards. He used his credit card statements to make the summary table that follows. Sheng is also eligible for a debt consolidation loan with an APR of 10.7% that reduces his monthly payments to $179.37. This loan will take six years to pay off, and Sheng will pay a total of $3,414.39 in interest charges. How much more in interest charges will the debt consolidation loan cost Sheng?
The debt consolidation loan will cost Sheng an additional $1,997.69 in interest charges compared to his credit cards.
Calculating how much more in interest the debt consolidation loan will cost ShengFrom question, we are to calculate how much more in interest the debt consolidation loan will cost Sheng
To calculate the interest charges for Sheng's credit cards, we need to use the following formula:
Interest Charges = Balance x APR x Number of Days in Billing Cycle / 365
Using this formula, we can calculate the interest charges for each of Sheng's credit cards:
For Credit Card A:
Interest Charges = $2,500 x 0.19 x 30 / 365 = $4.94
For Credit Card B:
Interest Charges = $3,000 x 0.22 x 30 / 365 = $6.01
So, the total interest charges for Sheng's credit cards are:
Total Interest Charges = $4.94 + $6.01 = $10.95
Now, let's calculate the total cost of the debt consolidation loan:
Total Cost = Total Monthly Payments x Number of Payments - Loan Amount
Total Monthly Payments = $179.37
Number of Payments = 6 x 12 = 72
Loan Amount = ?
To find the loan amount, we need to solve for it using the interest rate and the total interest charges:
Loan Amount = Total Interest Charges / (APR x Number of Payments / 12)
Loan Amount = $3,414.39 / (0.107 x 72 / 12) = $25,000
So, the total cost of the debt consolidation loan is:
Total Cost = $179.37 x 72 - $25,000 = $2,008.64
Therefore, the additional interest charges for the debt consolidation loan compared to Sheng's credit cards are:
Additional Interest Charges = Total Cost - Total Interest Charges
Additional Interest Charges = $2,008.64 - $10.95 = $1,997.69
Hence, the debt consolidation loan will cost him an additional $1,997.69 in interest charges
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Write a recursive formula for an, the nth term of the sequence 2, 6, 10, 14, ....
The recursive formula for an, the nth term of the sequence is a(n) = a(n - 1) + 2 where a(1) = 2
How to determine the recursive formula of the sequenceFrom the question, we have the following parameters that can be used in our computation:
2, 6, 10, 14, ....
The above definitions imply that we simply add 4 to the previous term to get the current term
Using the above as a guide,
So, we have the following representation
a(n) = a(n - 1) + 2
Hence, the sequence is a(n) = a(n - 1) + 2 where a(1) = 2
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7-5 skills practice parts of similar triangles
The answer is (1) x = 22.5; (2) x = 16.7; (3) x = 13.5; (4) x = 16.8; (5) x = 24.5; (6) x = 16.15; (7.a) height of the image on film is 11.2mm; (7.b) distance between camera and her friend is 1,875mm.
(1) We can see that in the given figure all three corresponding angles are congruent and all three corresponding sides are in equal proportion so, these are similar triangles.
As per properties of similar triangle:
Three pairs of corresponding sides are proportional i.e. Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.
Therefore, [tex]\frac{32}{24} =\frac{30}{x}[/tex],
then by cross multiplying them, we get,
32x = 720
x = 720/32
x = 22.5
(2) As, this is already given that these are similar triangle and by applying the properties of similar triangle we get,
[tex]\frac{39}{26} =\frac{25}{x}[/tex]
39x = 650
x = [tex]16\frac{2}{3}[/tex]
x = 16.7
(3) As these are similar triangle again we can say that,
[tex]\frac{2x+1}{x+4} =\frac{40}{25}[/tex]
40(x + 4) = 25(2x + 1)
40x + 160 = 50x + 25
40x = 50x - 135
-10x = -135
(by cancelling (-) sign from both sides we get,
x = 135/10
x = 13.5
(4) By applying similar triangle's property, we can get
[tex]\frac{20}{30} =\frac{28-x}{x}[/tex]
20x = 840 - 30x
50x = 840
x = 840/50
x = 16.8
(5) As ΔJKL [tex]\sim[/tex] ΔNPR,
[tex]\frac{KM}{PT} =\frac{KL}{PR}[/tex]
[tex]\frac{18}{15.75} =\frac{28}{x}[/tex]
18x = 441
x = 441/18
x = 24.5
(6) As ΔSTU [tex]\sim[/tex] ΔXYZ,
[tex]\frac{UA}{ZB} =\frac{UT}{ZY}[/tex]
[tex]\frac{6}{11.4} =\frac{8.5}{x}[/tex]
6x = 96.6
x = 96.6/6
x = 16.15
(7.a) First we have to change 3 m and 140 cm into mm(millimeters).
So, 1m = 1000 mm
3m = 3000mm.
And 1cm = 10 mm
140cm = 1400 mm.
Then to find the height of the image on the film, we have to solve:
[tex]\frac{24}{3000} =\frac{x}{1400}[/tex]
by cross multiplication we get,
3000x = 33,600
x = 33,600/3000
x = 11.2 mm
the height of the image on the film is 11.2millimeters.
(7.b) For this also, we have to find x by solving the equation:
[tex]\frac{24}{3000} =\frac{15}{x}[/tex]
24x = 45,000
x = 45,000/24
x = 1,875 mm
The distance between camera and her friend is 1,875 millimeters.
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Full question is given below in the image.
the graph shows a population of butterflies, t weeks since their migration began.
c. Write an equation for the
population, q, after t weeks.
Answer:
q = 250,000·(0.6^t)
Step-by-step explanation:
You want an equation that models the graph of an exponential function that has an initial value of 250,000 and a value of 150,000 after 1 week.
Exponential functionAn exponential function has the form ...
q = a·b^t
where 'a' is the initial value, and 'b' is the decay factor over a period of one time unit of t.
ApplicationThe graph with this problem shows the initial value (for t=0) to be a=250,000. The decay factor will be ...
b = 150,000/250,000 = 3/5 = 0.6
Then the exponential function can be written as ...
q = 250000·(0.6^t) . . . . . . where t is in weeks
27. \( \left\{\begin{array}{c}x+y+z=-1 \\ 2 x+3 y+2 z=3 \\ 2 x+y+2 z=-7 \\ x-3 y+2 z=10 \\ -x+3 y-z=-6 \\ -x+3 y+2 z=6 \\ 6 x-2 y+2 z=4 \\ 3 x-y+2 z=2 \\ -12 x+4 y-8 z=8\end{array}\right. \)
Using the Gaussian elimination method, the general solution is: [tex]\[ x = -31t + 6 \][/tex], [tex]\[ y = 5 \][/tex], [tex]\[ z = 31t \][/tex].
To solve this system of equations, we can use the Gaussian elimination method. This method involves creating a matrix with the coefficients of the equations and using row operations to reduce the matrix to a form that can be easily solved.
First, we create a matrix with the coefficients of the equations:
[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 2 & 3 & 2 & 3 \\ 2 & 1 & 2 & -7 \\ 1 & -3 & 2 & 10 \\ -1 & 3 & -1 & -6 \\ -1 & 3 & 2 & 6 \\ 6 & -2 & 2 & 4 \\ 3 & -1 & 2 & 2 \\ -12 & 4 & -8 & 8 \end{array} \right) \][/tex]
Next, we use row operations to reduce the matrix to a form that can be easily solved:
[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 0 & 1 & 0 & 5 \\ 0 & -1 & 0 & -5 \\ 0 & -4 & 1 & 11 \\ 0 & 4 & 0 & -5 \\ 0 & 4 & 1 & 7 \\ 0 & -8 & -4 & 10 \\ 0 & -4 & -1 & 5 \\ 0 & 8 & 4 & -4 \end{array} \right) \][/tex]
[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 0 & 1 & 0 & 5 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 31 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 27 \\ 0 & 0 & -4 & 50 \\ 0 & 0 & -1 & 25 \\ 0 & 0 & 4 & -44 \end{array} \right) \][/tex]
[tex]\[ \left( \begin{array}{ccc|c} 1 & 0 & 1 & -6 \\ 0 & 1 & 0 & 5 \\ 0 & 0 & 1 & 31 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & -4 \\ 0 & 0 & 0 & 174 \\ 0 & 0 & 0 & 56 \\ 0 & 0 & 0 & -168 \end{array} \right) \][/tex]
From this reduced matrix, we can see that there are infinitely many solutions to this system of equations. The general solution can be written as:
[tex]\[ x = -31t + 6 \][/tex]
[tex]\[ y = 5 \][/tex]
[tex]\[ z = 31t \][/tex]
Where t is any real number.
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Consider the two functions x1 = y^2 and x2 = b on the y-interval [-a, a], if a = 6.2. What value does b have to be in order for the area between x, and x2 and [-a, a], to equal 50.5? Round your answer to five decimal places.
The value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2] is 29.64355.
To find the value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2], we need to set up an integral and solve for b.
First, we need to find the difference between the two functions:
x2 - x1 = b - y^2
Next, we need to integrate this difference over the given interval:
∫[-6.2, 6.2] (b - y^2) dy
Using the power rule for integration, we get:
[b*y - (y^3)/3] from -6.2 to 6.2
Plugging in the values for the interval and simplifying, we get:
(6.2b - 158.488) - (-6.2b - 158.488)
Simplifying further, we get:
12.4b - 316.976
Now, we can set this equal to the given area and solve for b:
12.4b - 316.976 = 50.5
12.4b = 367.476
b = 367.476/12.4
b = 29.64354839
Rounding to five decimal places, we get:
b = 29.64355
So, the value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2] is 29.64355.
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A food company conducted a survey and found that 4 out of 20 people had french toast for
breakfast yesterday.
What is the probability that a randomly selected person had french toast for breakfast?
The probability that a randomly selected person had French toast for breakfast is 20%.
What is the probability?Probability describes the result of a random event based on the expected successes or outcomes.
Probability is computed as the quotient of the expected outcomes, events, or successes out of many possible outcomes, events, or successes.
Probability values lie between zero and one based on the degree of certainty or otherwise and can be depicted as percentages, decimals, or fractions.
The total number of survey participants = 20
The number of participants found to be having French toast for breakfast = 4
The probability of selecting a person having French toast for breakfast = 20%,or 0.2, or 1/5 (4/20 x 100)
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An inequality is shown. -1/3x + 1/2 < 3.5 what is the solution to the inequality?
A. x > -12
B. x < -12
C. x > -9
D. x < -9
The solution to the inequality is option C. x > -9.
What is Linear Inequalities?Linear inequalities are defined as those expressions which are connected by inequality signs like >, <, ≤, ≥ and ≠ and the value of the exponent of the variable is 1.
The given inequality is,
-1/3x + 1/2 < 3.5
We have to find the solution of the inequality.
-1/3 x + 0.5 < 3.5
Subtracting both sides by 0.5, we get,
-1/3 x < 3.5 - 0.5
-1/3 x < 3
Multiplying both sides by -3,
x > -9
Hence the solution is x > -9.
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Given the equations of two lines, describe how to determine if the lines are parallel.
Answer:
For two linear equations : a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0;
To determine if two such straight lines are parallel, then you should check for the following conditions :
a₁/a₂ = b₁/b₂ ≠ c₁/c₂ , where a,b are coefficients of x and y for each line.
if this condition is true for the coefficients of x,y, and the intercept of lines (c₁ and c₂) then they are parallel.
for instance,
let's say we have two lines :
x + 2y - 4 = 0,
2x + 4y - 12 = 0;
Now to check if they are parallel you simply check if the condition for parallel lines is met or not.
for these two lines :
a₁ = 1 , b₁ = 2, and c₁ = -4;
a₂ = 2, b₂ = 4, and c₂ = -12;
evaluating the values in the condition we have :
[tex]\frac{1}{2}[/tex] = [tex]\frac{2}{4}[/tex] ≠[tex]\frac{-4}{-12}[/tex] ;
since the condition for parallel is true for these two lines, we can conclude they are parallel.