difference between atom and radical

Answers

Answer 1
A radical is electrically neutral but chemically unstable because it contains an odd number of electrons in its outer shell. Atoms can be chemically stable and neutral, as in noble gases, which abide by the octet rule to the letter.

Related Questions

A rocket can be powered by the reaction between dinitrogen tetroxide and hydrazine:

20a

An engineer designed the rocket to hold 1.35 kg N2O4 and excess N2H4. How much N2 would be produced according to the engineer's design? Enter your answer in scientific notation.

Answers

According to the engineer's design, 14.67 moles of N2 would be produced in the reaction.

To determine the amount of N2 that would be produced according to the engineer's design, we need to understand the stoichiometry of the reaction between dinitrogen tetroxide (N2O4) and hydrazine (N2H4).

The balanced chemical equation for the reaction is:

N2H4 + N2O4 → N2 + 2H2O

From the balanced equation, we can see that one mole of N2H4 reacts with one mole of N2O4 to produce one mole of N2. Therefore, the mole ratio between N2H4 and N2 is 1:1.

Given that the engineer designed the rocket to hold 1.35 kg of N2O4, we need to convert this mass to moles using the molar mass of N2O4. The molar mass of N2O4 is approximately 92.01 g/mol.

Moles of N2O4 = Mass of N2O4 / Molar mass of N2O4

= 1.35 kg / 92.01 g/mol

= 14.67 mol

Since the mole ratio between N2H4 and N2 is 1:1, the number of moles of N2 produced would be the same as the number of moles of N2O4, which is 14.67 mol.

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__________ 1. What valuable contribution will my study make to the field?

Answers

Answer:

I'm not entirely sure what your study is about, but I can tell you that any research or study that contributes new knowledge or insights to a particular field can be valuable. It's important to identify gaps in the existing literature and to approach your research with a clear and focused question or objective. Ultimately, the value of your study will depend on the quality of your research and the significance of your findings.

Question:
Seawater contains salt, a/an
molecule that consists of a metal ion and a nonmetal ion.

Answers

Answer:

sodium chloride is an ionic molecule . which is typically the case when metals and nonmetals form bonds

Final answer:

Seawater contains salt, or sodium chloride, which is an ionic compound formed from the bonding of a metal ion (sodium) and a nonmetal ion (chloride) through the transfer of electrons. The ions' opposite charges attract to form the ionic bond.

Explanation:

Seawater contains a significant amount of salt, often referred to as sodium chloride. This is a type of ionic compound that consists of a metal ion, sodium (Na), bonded with a nonmetal ion, chloride (Cl). The bond between these ions is formed through the transfer of electrons, resulting in a neutral compound. This is typical of salts, which often consist of a metal and nonmetal ion. The sodium ion carries a positive charge and the chloride ion carries a negative charge, and their attraction forms the ionic bond which holds the salt molecule together in seawater.

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Wavelength
#1
Ampl
#1
Speed
#1
Wavelength
#2
Ampl
#2
Speed
#2
Frequency = 1
Hz
28 cm
20 cm
78
30 cm
20 cm
30
Frequency = 2 15 cm
Hz
20 cm
13 cm
20 cm
15
Frequency = 3 9 cm
20 cm
10 cm
20 cm
Hz
Question: How do wavelength, speed, amplitude, and frequency relate in a coiled spring?

Answers

In a coiled spring, wavelength, speed, amplitude, and frequency are interconnected through the properties and behavior of waves. When a wave travels through a coiled spring, it exhibits certain characteristics.

Wavelength refers to the distance between two consecutive points in a wave that are in phase, such as two adjacent crests or troughs. In the context of a coiled spring, it would be the distance between two consecutive coils.

Speed, on the other hand, represents how quickly the wave propagates through the medium. In a coiled spring, the speed of the wave depends on the properties of the spring material and the tension applied to it.

Amplitude refers to the maximum displacement of a wave from its equilibrium position. In a coiled spring, it would be the maximum distance the coils are stretched or compressed from their resting position.

Frequency measures the number of complete oscillations or cycles of a wave per unit time. It is expressed in hertz (Hz). In the case of a coiled spring, frequency would represent the number of complete cycles or vibrations the spring undergoes in one second.

These properties are related through the wave equation: speed = frequency x wavelength. In the context of a coiled spring, as the frequency increases, the wavelength decreases, and vice versa, while the speed of the wave remains constant. The amplitude, however, does not directly affect the relationship between wavelength, speed, and frequency in a coiled spring.

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Which cycle is affected by the burning of fossil fuels and the release of CO2 into the atmosphere?

Question options:

oxygen cycle


carbon cycle


nitrogen cycle


water cycle


HELPING PEOPLE IN NEED:

Answers

Answer:

B - The carbon cycle

Explanation:

The carbon cycle is one of earth's cycles that exchanges carbon within all the spheres of earth. Because the burning of fossil fuels releases carbon dioxide into the atmosphere, it affects the carbon cycle.

1)The concentration of [Mg+2] ions in the Mg(NO3)2 saturated solution is given as 1.0x10^-2 M. When this (strong electrolyte) saturated solution was mixed with NaOH(strong base),its final concentration was 1.0x10^-4 M Mg(NO3)2.
Do you think a precipitate will form?
Calculate and prove it whether there is a precipitate due to presence of the mixture using the clue given below. (Ksp=16*10^-12)

Answers

Answer:

Since this value is less than the Ksp of Mg(OH)2, which is 16*10^-12, no precipitate will form. Therefore, the solution will remain clear.

Explanation:

Based on the given information, we can calculate the initial concentration of Mg+2 ions in the Mg(NO3)2 saturated solution as 1.0x10^-2 M. When the solution is mixed with NaOH, a precipitation reaction may occur if the resulting concentration of Mg+2 ions exceeds the solubility product constant (Ksp) of Mg(OH)2, which is 16*10^-12.

The balanced chemical equation for the precipitation reaction is:

Mg+2 + 2OH- → Mg(OH)2

To determine if a precipitate will form, we need to calculate the concentration of Mg+2 ions in the final solution after mixing with NaOH. Since Mg(NO3)2 is a strong electrolyte, it will dissociate completely in water to give Mg+2 and NO3- ions. Therefore, the initial concentration of Mg+2 ions can be used to calculate the number of moles of Mg+2 ions present in the solution.

n(Mg+2) = C(Mg+2) x V

where C(Mg+2) is the initial concentration of Mg+2 ions and V is the volume of the solution.

n(Mg+2) = 1.0x10^-2 x V

After mixing with NaOH, Mg+2 ions will react with OH- ions to form Mg(OH)2. Since Mg(OH)2 is a sparingly soluble salt, it will precipitate out of solution until the concentration of Mg+2 and OH- ions reaches a value corresponding to the Ksp of Mg(OH)2.

The concentration of Mg+2 ions in the final solution can be calculated using the following equation:

[Mg+2] = n(Mg+2) / (V + V')

where V is the initial volume of the Mg(NO3)2 solution and V' is the volume of NaOH added.

Since we know that the final concentration of Mg(NO3)2 is 1.0x10^-4 M, we can use the dilution equation to calculate V':

C1V1 = C2V2

where C1 is the initial concentration of Mg(NO3)2, C2 is the final concentration, V1 is the initial volume of the solution and V2 is the final volume after mixing.

V' = (C1V1 - C2V2) / C2

Substituting the values, we get:

V' = (1.0x10^-2 x V - 1.0x10^-4 x (V + V')) / 1.0x10^-4

Solving for V', we get:

V' = 98.04 mL

Therefore, the total volume of the final solution is 100 mL (V + V').

Substituting the values in the equation for [Mg+2], we get:

[Mg+2] = 9.8x10^-5 M

Since this value is less than the Ksp of Mg(OH)2, which is 16*10^-12, no precipitate will form. Therefore, the solution will remain clear.

Answer: Since Q (1.0x10^-10) is less than Ksp (16x10^-12), a precipitate will not form

Explanation: To calculate Q, we need to determine the concentration of OH- ions in the solution. Since NaOH is a strong base, it completely dissociates in water to form Na+ and OH- ions. Therefore, the concentration of OH- ions in the solution is equal to the concentration of NaOH, which is 1.0x10^-4 M.

Now we can calculate Q: Q = [Mg+2][OH-]^2 = (1.0x10^-2)(1.0x10^-4)^2 = 1.0x10^-10.

Therefore, a precipitate will not form.

The sun, the moon, the stars, the earth all are made up of 4) Symbol 2) Mixture 3) Matter 1) Material ​

Answers

The sun, the moon, the stars, the earth all are made up of matter.

Matter refers to anything that has mass and occupies space. It is the substance that makes up all physical objects in the universe, including both living and non-living things. Matter can exist in different states, namely solid, liquid, and gas, depending on the arrangement and movement of its particles. Matter is composed of atoms, which are the smallest units of matter that retain the chemical properties of an element. Atoms combine to form molecules, which can be made up of one or more different types of atoms bonded together. These molecules then come together to form different substances.

The properties of matter, such as its density, color, texture, and ability to conduct heat or electricity, are determined by the composition, arrangement, and interactions of its particles. Matter can undergo physical and chemical changes, including phase transitions (such as melting, freezing, and vaporization) and chemical reactions, where substances can be transformed into new substances with different properties. It is important to note that matter also includes forms that are not directly visible to the  eye, such as subatomic particles

The sun, the moon, the stars, and the Earth are all made up of matter. Matter refers to anything that has mass and occupies space. It is composed of atoms and molecules, which are the building blocks of all substances. While symbols can represent or signify various concepts or objects, they are not physical entities made up of matter. A mixture is a combination of two or more substances, but it does not encompass celestial bodies like the sun, moon, stars, or Earth. Material is a more general term that can refer to various physical substances, but it does not specifically indicate the composition or nature of celestial bodies.

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What converts nitrogen into a usable substance during the nitrogen cycle?

Question options:

decomposers


nitrogen-fixing bacteria


legumes


consumers

HELPING PEOPLE IN NEED:

Answers

Answer:

B. nitrogen-fixing bacteria

Explanation:

Nitrogen is converted from atmospheric nitrogen (N2) into usable forms such as NO2-,

In a process known as fixation. The majority of nitrogen is fixed by bacteria, most of which are symbiotic with plants.

Recently fixed ammonia is then converted to biologically useful forms by specialized bacteria.

given the incomplete reaction which compound is represented by x

Answers

The compound that is shown as X can be seen in the option labelled C

What is esterification?

The process of esterification involves the condensation of an alcohol (or phenol) with an acid to produce an ester. To create the ester bond, the water molecule must be removed from the alcohol and acid (dehydration).

Usually, an acid catalyst is used to catalyze the reaction, which makes it easier to remove water and encourages the creation of the ester. The acid catalyst aids in protonating the acid's carbonyl oxygen, which increases its electrophilicity and makes it more vulnerable to alcohol's nucleophilic attack.

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Which is the middle of the three ear bones?

cochlea

stapes

incus

malleus

Answers

The incus I believe

When the Keq value is large, the number representing [A]a[B]b must be

Answers

When the equilibrium constant (Keq) value is large, it indicates that the forward reaction is favored and the concentration of products is significantly higher than that of the reactants at equilibrium.

In the expression for Keq, [A]a[B]b represents the concentrations of reactants and products raised to their respective stoichiometric coefficients

.For a large Keq value, it implies that the numerator of the expression, which corresponds to the concentrations of the products raised to their stoichiometric coefficients, is much larger than the denominator, which represents the concentrations of the reactants raised to their stoichiometric coefficients.

Consequently, the number representing [A]a[B]b must be relatively small compared to the number representing the products. This suggests that the concentrations of reactants [A] and [B] are considerably lower than the concentrations of products, emphasizing the strong predominance of the forward reaction at equilibrium.

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PLEASE HELP QUICKK

Calculate the energy of combustion for one mole of butane if burning a 0.367 g sample of butane (C4H10) has increased the temperature of a bomb calorimeter by 7.73 °C. The heat capacity of the bomb calorimeter is 2.36 kJ/ °C.

Answers

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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If the charge in coulombs carried by the passage of an electric current in aqueous solution of NaOH is 192358.8C, calculate the mass of NaOH. [Na = 23, 0 = 16, H = 1, F = 96500C / mol]​

Answers

The mass of NaOH is approximately 79.84 grams.

To calculate the mass of NaOH, we need to determine the number of moles of NaOH first, and then use its molar mass to find the mass.

Given:

Charge (q) = 192358.8 C

Molar charge of 1 mole of electrons (F) = 96500 C/mol

We can use Faraday's law of electrolysis to relate the charge and the number of moles of the substance. The formula is:

q = Fn

where:

q = charge in coulombs

n = number of moles

F = Faraday's constant

Rearranging the formula to solve for the number of moles:

n = q / F

Plugging in the values:

n = 192358.8 C / 96500 C/mol

n ≈ 1.996 moles

Now, to find the mass of NaOH, we'll use its molar mass.

The molar mass of NaOH = (23 g/mol) + (16 g/mol) + (1 g/mol) = 40 g/mol

Finally, to calculate the mass of NaOH:

Mass = n * molar mass

Mass = 1.996 moles * 40 g/mol

Mass ≈ 79.84 g

Therefore, the mass of NaOH is approximately 79.84 grams.

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the characteristic property of an acid is due to the presence of what ions​

Answers

The characteristic property of an acid is due to the presence of hydrogen ions.

How many moles of carbon are in 300 mg of graphite​

Answers

Answer:

Explanation: First, convert the mass of graphite from milligrams (mg) to grams (g).

As 1,000 milligrams in 1 gram

therefore,

300 mg = 300/1000 = 0.3 grams

Now, we can use the molar mass of carbon to calculate the number of moles. We divide the mass of the sample by the molar mass:

Number of moles = Mass (g) / Molar mass (g/mol)

Number of moles = 0.3 g / 12.01 g/mol

Number of moles ≈ 0.02498 moles (rounded to five decimal places)

Therefore, there are approximately 0.02498 moles of carbon in 300 mg of graphite.

Which statements are true about catalysts

Answers

The true statements about catalysts are the statement 1,2 and 3.

1. Catalysts increase the rate of reaction: Catalysts facilitate chemical reactions by providing an alternative reaction pathway with lower activation energy. They enhance the rate of the reaction without being consumed in the process.

2. Catalysts behave as reactants in the reaction mixture: Catalysts participate in the reaction by interacting with the reactants. They form temporary bonds with the reactant molecules, leading to the formation of an intermediate complex that ultimately results in the desired products.

3. Catalysts decrease the activation energy of a reaction: Catalysts lower the energy barrier required for a reaction to occur by providing an alternative pathway with a lower activation energy. This enables the reactants to overcome the energy barrier more easily, thus increasing the reaction rate.

4. Catalysts show no physical change at the end of the reaction: Catalysts are not consumed or permanently altered in the reaction. They remain chemically unchanged and are available to participate in subsequent reaction cycles.

The statement "Catalysts are required in large concentrations in a reaction" is false. Catalysts work effectively even in small concentrations, as their role is to facilitate the reaction rather than being directly involved in the stoichiometry of the reaction.

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PROJECT: HYDROELECTRIC POWER
Assignment Directions:
Compose an essay on hydroelectric power of at least 400 words.

Assignment Guidelines:
In your report, be sure to address:

How a hydroelectric power plant works, including why dams are built as parts of large hydropower plants;
The environmental and economic benefits of hydroelectricity, giving examples from the case studies; and
The environmental and cultural disadvantages of hydropower, giving examples from the case studies.

Answers

Hydroelectric Power: Harnessing Nature’s Energy

Let's imagine a huge wall blocking a river. On one side, the water level is high, and on the other, it's low. Now imagine that this wall has a mechanism to let the water flow from the high side to the low side, and in the process, it produces electricity. This is, in simple terms, how a hydroelectric power plant works!

Hydroelectric power plants work by using water to turn turbines that generate electricity. They are often built with dams, which are like giant walls across rivers. The dams are essential because they raise the water level on one side, creating a reservoir or a lake. This reservoir stores a huge amount of potential energy. When the water is released, it flows down through turbines, and this energy is converted into mechanical energy. The turbines are connected to generators, which turn the mechanical energy into electricity.

Now, let's talk about some of the environmental and economic benefits of hydroelectricity. It's like hitting two birds with one stone! Firstly, hydroelectric power doesn’t produce greenhouse gases or pollutants during operation, which means it’s much cleaner for our air compared to coal or gas power plants. For example, the Itaipu Dam in Brazil and Paraguay is a great case study. It generates so much electricity from hydro power that it reduces CO2 emissions equivalent to what 21.6 million cars would produce in a year!

Another economic benefit is that the electricity produced is usually cheaper in the long run. Hydroelectric plants have high upfront costs but can operate for a very long time. The Hoover Dam in the USA, built in the 1930s, still generates electricity at low cost, providing power to millions of homes.

However, there is no such thing as a free lunch. There are also environmental and cultural disadvantages to hydroelectric power. When a dam is built, the area behind it gets flooded. This means that plants, animals, and even people's homes can be submerged. For instance, the Three Gorges Dam in China displaced over 1.2 million people and flooded archaeological sites. Additionally, dams can impact fish populations. In the United States, salmon populations in the Pacific Northwest have decreased partly because dams block their migration routes.

Dams also affect the natural flow of rivers, which can have far-reaching consequences for ecosystems. The Aswan Dam in Egypt, for example, has reduced the fertility of the Nile Delta because the nutrients that used to flow down the river and enrich the soil are now trapped behind the dam.

In conclusion, hydroelectric power is an incredible way to generate clean energy, but it's important to weigh these benefits against the environmental and cultural costs. Finding ways to mitigate the negative impacts or looking at alternative renewable energy sources can help us move towards a more sustainable future.

*Keep in mind, you should paraphrase this or use it as your frame of reference, otherwise it would be plain plagiarism.*

The power of water has been harnessed by humans for centuries to generate electricity, and hydroelectric power is a renewable and sustainable energy source that has been used for many years. In this essay, we will explore the inner workings of hydroelectric power plants, the advantages and disadvantages of this energy source, and the potential it holds for a sustainable energy future. Hydroelectric power plants use the force of falling water to turn turbines, generating electricity through a process that is clean and efficient. Dams are built as part of large hydropower plants to control the flow of water and store it for later use. When the water is released from the dam, it flows through a penstock and turns the turbine, which generates electricity. Moreover, hydropower plants can be easily adjusted to meet peak demand for electricity, making them a valuable source of reliable and flexible energy.

One of the main advantages of hydroelectricity is its sustainability. Water is a renewable resource that is constantly replenished by the water cycle, making hydropower an almost infinite source of energy. Additionally, hydropower plants can provide a range of ecosystem services, such as flood control, irrigation, and recreation. For example, the Itapúa Dam on the Paraná River in Brazil provides water for irrigation, supports local fishing industries, and generates electricity for millions of homes. Nevertheless, there are also environmental and cultural drawbacks to hydropower. Large dams can cause significant harm to river ecosystems, altering the natural flow of water and affecting the habitats of fish and other aquatic species. Moreover, the construction of dams can displace local communities and destroy cultural heritage sites. For example, the construction of the Three Gorges Dam in China has caused the displacement of over one million people and has destroyed numerous cultural heritage sites.

Despite these challenges, the potential of hydroelectric power for a sustainable energy future cannot be ignored. As we move towards a world that is less reliant on fossil fuels, hydropower can play a critical role in providing clean, renewable, and reliable energy. Furthermore, new technologies are being developed to reduce the environmental impact of hydropower, such as fish ladders and other measures to support fish migration. Furthermore, hydroelectric power is a powerful and sustainable source of energy that harnesses the power of falling water to generate electricity. Although there are challenges associated with hydropower, such as the environmental and cultural impacts of large dams, the benefits of this energy source are significant. As we continue to seek sustainable solutions to our energy needs, hydroelectric power will undoubtedly play a critical role in meeting our energy demands while also protecting the environment and supporting economic growth.

Thank you, I genuinely hope this helps.

+
The answer to the calculation below with the correct number of significant figures
is
15.4 + 9.87 +0.002 =

A) 25.27
B) 25.272
C) 25
D) 25.3

Answers

The answer is 25.3.

Adding 15.4, 9.87, and 0.002 gives us 25.272. Since 9.87 has two decimal places, we should round the answer to two decimal places as well. Therefore, the answer with the correct number of significant figures is 25.3.
Final answer:

The correct answer to the problem 15.4 + 9.87 +0.002 taking into account the correct significant figures is D) 25.3. The rule of Significant Figures in addition dictates this.

Explanation:

The subject of this question is Significant Figures in mathematical addition, a concept in Mathematics. When adding numbers, the resulting answer can only be as precise as the least precise number. In the numbers given (15.4, 9.87, 0.002), the least precise number is 15.4 as it has the highest position of uncertainty (the decimal place). So, our answer should only go as far as this uncertain position. If you sum up the numbers, you get 25.272. But we only need to keep it to one decimal place, so we round it to the nearest tenth, which gives us 25.3. So, the correct answer is D) 25.3.

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How many moles of N are in 0.217 g of N2O ?

Answers

There are twice the molar quantity of nitrogen atoms in nitrous oxide, i.e.
1 x 10^-2.
Final answer:

There are approximately 0.00493 moles of N in 0.217 g of N2O.

Explanation:

To determine the number of moles of N in 0.217 g of N2O, we need to convert the mass of N2O to moles using the molar mass of N2O, which is 44.0128 g/mol. We can use the formula:

moles = mass / molar mass

So, moles of N = 0.217 g / 44.0128 g/mol = 0.00493 mol. Therefore, there are approximately 0.00493 moles of N in 0.217 g of N2O.

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What would be the kinetic energy, in J, of an electron with a wavelength of 0.445 nm, which would be equivalent to the wavelength of electromagnetic radiation in the X-ray region? (The mass of an electron is 9.11 × 10⁻²⁸ g.)

Answers

Answer:

The kinetic energy of the electron is approximately 4.45 × 10^-15 J, assuming that the electron is moving at a velocity of about 1.198 × 10^7 m/s.

Explanation:

We can use the formula for the energy of a photon of electromagnetic radiation:

E = hc/λ

where h is Planck's constant (6.626 × 10^-34 J·s), c is the speed of light (2.998 × 10^8 m/s), and λ is the wavelength of the radiation.

Since the wavelength of the electron in this question is equivalent to the wavelength of X-ray radiation, we can assume that the energy of the electron is equal to the energy of a photon of X-ray radiation with the same wavelength.

So, we can calculate the energy of the photon:

E = hc/λ = (6.626 × 10^-34 J·s × 2.998 × 10^8 m/s)/(0.445 × 10^-9 m) ≈ 4.45 × 10^-15 J

Since the electron has the same energy as the photon, its kinetic energy is also approximately 4.45 × 10^-15 J.

To convert the mass of the electron from grams to kilograms, we divide by 1000:

mass of electron = 9.11 × 10^-28 kg

Using the formula for kinetic energy:

KE = (1/2)mv^2

where m is the mass of the electron and v is its velocity, we can solve for the velocity of the electron:

KE = (1/2)mv^2

v^2 = (2KE)/m

v = √((2KE)/m)

Substituting the values we have calculated, we get:

√((2KE)/m) = √((2 × 4.45 × 10^-15 J)/(9.11 × 10^-28 kg)) ≈ 1.198 × 10^7 m/s

A balloon filled with 0.0303 mol of helium at 30°C and a pressure of 1.0 atm occupies a volume of 0.75 L and has a density of 0.161 g/L. What would the density of the helium gas be if the balloon was placed in the freezer at -10 C and a pressure of 2.0 atm?

Answers

Answer:

the density of the helium gas would be approximately 0.369 g/L when the balloon is placed in the freezer at -10°C and a pressure of 2.0 atm.

Explanation:

To calculate the density of helium gas in the balloon after it is placed in the freezer at -10°C and a pressure of 2.0 atm, we can use the ideal gas law and the relationship between density, molar mass, and molar volume.

First, let's find the initial molar volume of the helium gas using the given conditions:

PV = nRT

Where:

P = pressure = 1.0 atm

V = volume = 0.75 L

n = number of moles = 0.0303 mol

R = ideal gas constant = 0.0821 L·atm/(mol·K)

T = temperature in Kelvin

To convert Celsius to Kelvin, we add 273.15:

T = 30°C + 273.15 = 303.15 K

Using the ideal gas law, we can calculate the initial molar volume:

V_initial = (n * R * T) / P

V_initial = (0.0303 mol * 0.0821 L·atm/(mol·K) * 303.15 K) / 1.0 atm

V_initial ≈ 0.754 L

Next, we can calculate the molar mass of helium (He) using the atomic mass of helium:

Molar mass of He = 4.003 g/mol

Now we can calculate the initial density of the helium gas in the balloon:

Initial density = (mass of helium gas) / (volume of helium gas)

Initial density = (0.0303 mol * 4.003 g/mol) / 0.754 L

Initial density ≈ 0.161 g/L

Now let's find the final density of the helium gas when the balloon is placed in the freezer at -10°C and a pressure of 2.0 atm.

We will use the ideal gas law again with the new conditions:

P_final = 2.0 atm

T_final = -10°C + 273.15 = 263.15 K (converted to Kelvin)

To find the final molar volume, we rearrange the ideal gas law equation:

V_final = (n * R * T_final) / P_final

V_final = (0.0303 mol * 0.0821 L·atm/(mol·K) * 263.15 K) / 2.0 atm

V_final ≈ 0.328 L

Finally, we can calculate the final density of the helium gas:

Final density = (mass of helium gas) / (volume of helium gas)

Final density = (0.0303 mol * 4.003 g/mol) / 0.328 L

Final density ≈ 0.369 g/L

Following world war l many artists began adopt to new style that

Answers

Answer:A. abandoned realism in favor of conveying feelings of anxiety and instability.

Rather than depicting the habitual esthetical artworks charged with beauty standards, artists from this period begin to express in works representing the struggles of the time. Some went far to represent distorted figures

Explanation:

Chemical formula for barium chromate

Answers

Answer:

Ba + Cr + O₄

The chemical formula for barium chromate is Ba+ Cr+ O4. It is a compound of barium, chrome, and oxygen that is used as a pigment and for other industrial applications.

Considering the following reaction, calculate the mass (in g) of carbon dioxide that will be produced if 12.5 g of methane (CH4) reacted. CH 4(g) +2O 2(g) -> CO 2(g) +2H 2 O (g) . beta H=-211 kcal

Answers

Taking into account the reaction stoichiometry, 34.375 grams of CO₂ are formed if 12.5 g of methane reacted.

Reaction stoichiometry

In first place, the balanced reaction is:

CH₄ + 2 O₂  → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CH₄: 1 moleO₂: 2 moles CO₂: 1 moleH₂O: 2 moles

The molar mass of the compounds is:

CH₄: 16 g/moleO₂: 32 g/moleCO₂: 44 g/moleH₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CH₄: 1 mole ×16 g/mole= 16 gramsO₂: 2 moles ×32 g/mole= 64 gramsCO₂: 1 mole ×44 g/mole= 44 gramsH₂O: 2 moles ×18 g/mole= 36 grams

Mass of CO₂ formed

The following rule of three can be applied: if by reaction stoichiometry 16 grams of CH₄ form 44 grams of CO₂, 12.5 grams of CH₄ form how much mass of CO₂?

mass of CO₂= (12.5 grams of CH₄×44 grams of CO₂)÷ 16 grams of CH₄

mass of CO₂= 34.375 grams

Finally, 34.375 grams of CO₂ are formed.

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Objects a and b are brought close to each other. Object a will soon become positively charged. Identify the charge that must transfer for this situation to occur

Answers

Answer:

A Negative Charge

Explanation:

Positive Charges Repel

Positive and Negative Charges Attract.

Negative Charges Repel.

Chlorofluorocarbons are ?

A. colorless, odorless gases that prevent red blood cells from carrying oxygen to the body

B. man-made chemicals containing chlorine and fluorine that cause
ozone molecules to break down

C. chemicals produced in factories that are used to prevent air
pollution

D. molecules containing chlorine and fluorine that block UV radiation
from reaching the Earth

Answers

D. molecules containing chlorine and fluorine that block UV radiation from reaching the Earth.

Chlorofluorocarbons (CFCs) are synthetic compounds that contain chlorine, fluorine, and carbon. They were widely used in the past as refrigerants, propellants in aerosol products, and foam-blowing agents. CFCs have been found to have a detrimental effect on the Earth's ozone layer when released into the atmosphere. They can reach the stratosphere, where they undergo a chemical reaction facilitated by ultraviolet (UV) radiation, resulting in the release of chlorine atoms. These chlorine atoms then participate in a destructive cycle that breaks down ozone molecules, leading to ozone depletion. Due to their harmful impact on the ozone layer, the production and use of CFCs have been phased out or regulated under international agreements like the Montreal Protocol to protect the Earth's ozone layer.

Chlorofluorocarbons (CFCs) are man-made chemicals containing chlorine and fluorine that cause ozone molecules to break down. Thus, option B is the answer.

Chlorofluorocarbons are non-toxic, synthetic compounds that contain atoms of Chlorine, Fluorine and Carbon. They are commonly used in the manufacture of aerosol sprays and are also used as solvents and refrigerants. CFCs were first introduced in 1928 by General Motors Company for its refrigerators.

While CFCs are very safe to use in most applications and are stable in the lower atmosphere, these chemicals when released to the upper atmosphere can cause significant reactions. CFCs when released into the upper atmosphere can lead to the destruction of the ozone molecules followed by the release of the UV radiation into the atmosphere.

Thus, CFCs are man-made chemicals which cause ozone molecules to break down.

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Diorite is a rock with crystals. It can form when molten lava cools down in the Earth's crust. Diorite is most likely
a(n)
rock.
A
igneous
B sedimentary
C metamorphic

Answers

Diorite is an igneous rock(Option A). Igneous rocks are formed from the solidification of molten materials, such as magma or lava.

Diorite specifically forms when molten lava cools and solidifies in the Earth's crust. During the cooling process, the minerals in the molten lava crystallize and combine to form the distinctive composition of diorite. It is composed mainly of plagioclase feldspar, biotite, hornblende, and/or pyroxene minerals. The presence of these crystals gives diorite its characteristic speckled appearance.

Unlike sedimentary rocks, which are formed through the deposition and compaction of sediments, diorite does not originate from the accumulation of loose particles. Similarly, it is not a metamorphic rock, which results from the transformation of pre-existing rocks due to intense heat and pressure.

In summary, diorite is an igneous rock formed through the cooling and solidification of molten lava in the Earth's crust. Its crystalline structure and composition make it distinct from sedimentary and metamorphic rocks.

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The volume of a gas at 99.0 kPa and 300.0 mL. If the pressure is increased to 188 kPa. What will be the new volume? (Assume temperature and amount of gas remains constant)

Answers

Answer:

158.0 mL.

Explanation:

P₁V₁ = P₂V₂

Given:

P₁ = 99.0 kPa

V₁ = 300.0 mL

P₂ = 188 kPa (new pressure)

V₂ = ? (new volume)

99.0 kPa * 300.0 mL = 188 kPa * V₂

V₂ = (99.0 kPa * 300.0 mL) / 188 kPa

V₂ = (29700 kPa * mL) / 188 kPa

V₂ ≈ 158.0 mL

Which of these is a possible mole
ratio for the reaction above?
A)
K3PO4 → 3K+ + PO³-
4
C)
3 mol K3PO4
3 mol K+
B)
3 mol K3PO4
1 mol K+
3 mol K+
1 mol PO³-
3 mol K+
4 mol O2-
Enter the answer choice letter.
D)

Answers

The correct answer choice letter is A) K3PO4 → 3K+ + PO³-4
Final answer:

For the given reaction K3PO4 → 3K+ + PO4³-, the correct mole ratio would be 3 mol K3PO4 to 1 mol K+ and 3 mol K+ to 1 mol PO4³-, as seen in answer option B.

Explanation:

The mole ratio in a chemical reaction is indeed determined by the coefficients of the balanced chemical equation. In the given reaction:

K3PO4 → 3K+ + PO43-

The correct mole ratio can be established as follows:

1 mole of K3PO4 corresponds to:

- 3 moles of K+

- 1 mole of PO43-

This accurately represents the stoichiometry of the reaction. Therefore, as you correctly pointed out, the mole ratios can be expressed as:

- 3 moles of K3PO4 to 1 mole of K+

- 1 mole of K3PO4 to 1 mole of PO43-

The correct answer choice, corresponding to this mole ratio, is indeed B) 3 mol K3PO4 to 1 mol K+ and 1 mol K3PO4 to 1 mol PO43-. This reflects the relationship between the reactants and products as described by the balanced chemical equation.

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how many moles of Cl2(g) will be present at equilibrium?

Answers

The moles of Cl₂(g) will be present at equilibrium is 3.94 × 10⁻⁴ mol

To determine the number of moles of Cl₂(g) at equilibrium, we need to use the given equilibrium constant (Kₑ) and the initial concentrations of CO(g) and COCl₂(g).

Given:

[CO(g)] = 0.3500 mol

[COCl₂(g)] = 0.05500 mol

Kₑ = 1.2 × 10²

The balanced equation for the reaction is:

CO(g) + Cl₂(g) ⇌ COCl₂(g)

Let's denote the number of moles of Cl₂(g) at equilibrium as x. At the start, we have [Cl₂(g)] = 0 mol, but it will change by x at equilibrium.

Using the equilibrium expression, we can write:

Kₑ = [COCl₂(g)] / ([CO(g)] * [Cl₂(g)])

Plugging in the values:

1.2 × 10² = [COCl₂(g)] / (0.3500 * [Cl₂(g)])

To solve for [Cl₂(g)], we need to isolate it on one side of the equation:

[Cl₂(g)] = [COCl₂(g)] / (0.3500 * Kₑ)

Now, let's substitute the given values:

[Cl₂(g)] = 0.05500 / (0.3500 * 1.2 × 10²)

[Cl₂(g)] ≈ 3.94 × 10⁻⁴ mol

Therefore, approximately 3.94 × 10⁻⁴ moles of Cl₂(g) will be present at equilibrium.

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The question was Incomplete, Find the full content below:

Starting with 0.3500 mol CO(g) and 0.05500 mol COCl₂(g) in a 3.050-L flask at 668 K, how many moles of Cl₂(g) will be present at equilibrium

CO(g) + Cl₂(g) ⇄ COCl₂(g)  Ke 1.2 x 10^{2} at 668 K

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