Answer:
Base units are defined units based on specific objects or events in the physical world. Derived units are defined by combining base units.
Base units are defined by a particular process of measuring a base quantity whereas derived units are defined as algebraic combinations of base units. For example, length is a base quantity in both SI and the English system, but the meter is a base unit in the SI system only.
Which of the following statements is an example of a vector quantity. SP1.c.
A. acceleration
C. speed
B. distant
D. time
Answer: speed
Explanation:
Speed is the important key to the vector quantity
I tried zooming it in more, please help-
Answer:
Explanation:
a) 6 mm or 0.6 cm or 0.06 dm or 0.006 m or 0.000006 km
b) 12 mm or 1.2 cm or 0.12 dm or 0.012 m or 0.000012 km
c) 22 mm or 2.2 cm or 0.22 dm or 0.022 m or 0.000022 km
d) 37 mm or 3.7 cm or 0.37 dm or 0.037 m or 0.000037 km
e) 56 mm or 5.6 cm or 0.56 dm or 0.056 m or 0.000056 km
f) 67 mm or 6.7 cm or 0.67 dm or 0.067 m or 0.000067 km
g) 75 mm or 7.5 cm or 0.75 dm or 0.075 m or 0.000075 km
Add these two velocity vectors to find the magnitude of their resultant vector.
5.8 meters/seconds + 1.2 meters/seconds
The magnitude of their resultant vector is 4.6 meters/seconds
Since we are to add the velocity vectors in order to find the magnitude of their resultant vector.
Hence:
Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)
Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds
Resultant vector magnitude 4.6 meters/seconds
Inconclusion The magnitude of their resultant vector is 4.6 meters/seconds
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1. What is true about elements
3. Write "T" for true statements and "F" for false statements:
a. Protozoa are multi cellular animals.
b. Vacuoles are larger in plant cell.
c. Body of mammals is covered with feathers.
d. There is a pair of antenna on the head of a cockroach.
e. Birds have hollow and air filled bones.
Answer:
F
T
F
T
T
Explanation:
Thanks for this oppurtunity
Two boats start together and race across a 44 km wide lake and back. Boat A goes across at 44 km/h and returns at 44 km/h. Boat B goes across at 22 km/h, and its crew, realizing how far behind it is getting, returns at 66 km/h. Turnaround times are negligible, and the boat that completes the round-trip first wins.
Which boat wins and by how much? (Or is it a tie?)
(a) By how much? (Enter NONE if it was a tie.)
km
(b) What is the average velocity of the winning boat? (Enter NONE if it was a tie.)
km/h .... I put 44 for this answer and it was.
Answer:
a. 44 km
b. 0 km/h
Explanation:
For part a, the faster boat finishes when the second turns around to come back.
For part b, the average velocity is zero because he travels forward (+) and then back (-). 44km/h - 44 km/h = 0 km/h
An object accelerates uniformly from rest to a speed of
50 meters per second in 5.0 seconds. The average speed of
the object during the 5.0-second interval is
A 5.0 m/s
B 10 m/s
C 25 m/s
D 50 m/s
Answer:
25
Explanation:
v=u+at.
50=a(5)
a=10m/s^2.
distance= ut+ 1/2 at^2
=125
average speed = total distance/total time
=125/5
=25
The average speed of the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.
Hence, Option C) 25 m/s is the correct answer.
Given the data in the question;
Since the object was initially at rest,
Initial velocity; [tex]u = 0[/tex]Final velocity; [tex]v = 50m/s[/tex]Time; [tex]t = 5.0s[/tex]
First we determine the acceleration "a", using the First equation of motion:
[tex]v = u + at[/tex]
Where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
We substitute our values into the equation
[tex]50m/s = 0 + ( a \ * \ 5.0s)\\\\a = \frac{50m/s}{5.0s} \\\\a = 10m/s^2[/tex]
Next we Calculate the distance travelled by the object
From the Second Equation of Motion:
[tex]s = ut \ + \ \frac{1}{2}at^2[/tex]
Where, u is the initial velocity, a is the acceleration and t is the time and s is the distance travelled.
Wes substitute our values into the equation
[tex]s = (0\ * 5.0s) + ( \frac{1}{2} \ *\ 10m/s^2 \ * (5.0s)^2)\\\\s = \frac{1}{2} \ *\ 10m/s^2 \ * 25s^2\\\\s = 125m[/tex]
Now, we can get the Average speed of the object.
We know that, Speed is the distance travelled per unit time.
[tex]Speed = \frac{Distance}{Time}[/tex]
We substitute our values into the equation
[tex]Speed = \frac{125m}{5.0s}\\\\Speed = 25m/s[/tex]
The average speed of the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.
Hence, Option C) 25 m/s is the correct answer.
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The speed of sound through air is approximately 343 m/s. What is the speed in miles per hour
Answer:
At 20 °C (68 °F), the speed of sound in air is about 343 metres per second (1,235 km/h; 1,125 ft/s; 767 mph; 667 kn), or a kilometre in 2.9 s or a mile in 4.7 s.
PLEASE MARK ME BRAINLIEST.d. Hydrogen gas is filled in two
identical bottles, A and B, at the
same temperature. The mass of
hydrogen in the two bottles is 12
gm and 48 gm respectively. In
which bottle will sound travel
faster? How may times as fast as
the other?
(Ans: In A; Twice)
Explanation:
B I think it is because it has 48 gm than A
13.1 An object has an excess of 50 electrons. What
is the charge on the object in picocoulomb?
Answer:
-50* 1.6*10^-19 = -80*10^-19 = -8*10^-18 C
You were asked to make Kaleidoscope by your teacher for a school project. But no plane mirrors are available with you. How will you construct the Kaleidoscope without the plane mirror? Do you think it will work as good as a kaleidoscope with plane mirrors? Write a report in 4 to 6 sentences. Consider the following points- a. What alternate materials/ tools you will use instead of the plane mirror? b. How will you assemble those to construct the Kaleidoscope? c. How will these modifications affect the performance of the Kaleidoscope?
Answer:
A. Plastic cover.
B. Plastic cover will be shinny and clear which will be acting like a plane mirror, instead use the clear plastic cover.
C. This does not affect much performance.
Explanation:
a. Instead of plane mirror we will use clear plastic cover
b. The clear plastic cover will be shinny and clear which will be acting like a plane mirror. So, in place of plane mirror we will place the clear plastic cover.
c. This modification will not affect much in the performance of kaleidoscope as the clear plastic paper will be exactly the same as the plane mirror.
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https://brainly.com/question/23430564A car moves with uniform velocity of 40m/s for 5 s. It comes to rest in the next 10 s with uniform deceleration
Answer:
-8 m/s²
Explanation:
Initial velocity = 40 m/s
Final velocity = 0 m/s
Time (T1) = 5 s
Time (T2) = 10 s
Acceleration = v - u/t2 - t1
Acceleration = 0 - 40/10 - 5
Acceleration = -40/5
Acceleration = -8 m/s²
Determine the order of magnitude of the following small number by entering the appropriate exponent n below:
6,370 ≈ 10^n km
The complete question is;
Determine the order of magnitude of the following small number by entering the appropriate exponent n below: 6,370km≈10^n km .
Order of magnitude is 3.
Now, when dealing with order of magnitude, we first write the number in scientific notation. We will have; 6.37 × 10³ kmThe second thing we now do is to approximate the numerical part to either 1 or 10 as the case may be.In this case, we have 6.37 and it is closer to 10 than 1.
Thus, rewriting our number, we now have; 10 × 10³ kmThe order of magnitude is the exponent attached to the 10 on the right.
Thus, order of magnitude is 3.
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The order of magnitude of the given number will be "3.804".
According to the question, the number is:
→ [tex]6370 \ km = 10^n \ km[/tex]
By taking "[tex]log_{10}[/tex]" both sides, we get
→ [tex]log_{10}(6370) = log_{10} \ 10^n[/tex]
By putting the values accordingly, we get
→ [tex]log_{10} (6370) = n[/tex]
→ [tex]n = 3.804[/tex]
Thus the above answer is correct.
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show that Newton's first law is the special case of Newton's second law of motion
Please find attached photograph for your answer. Please do comment whether it is useful or not.
a simple machine has efficiency 90℅ what does it mean
Explanation:
A simple machine has efficiency 90℅, it means that 90% of the applied force is used in doing useful work and 10% is wasted due to overcoming friction.
A force of 5000 N is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 mm and a Young's modulus of 125 x 108 N/m^2. The elongation of the rod is:
a. 0.55 mm
b. 1.42 mm
c. 0.0040 mm
d. 0.11 mm
e. 0.022 mm
Answer:
0.55 mm
Explanation:
E = σ/ε
E = (F/A) / (ΔL/L₀)
ΔL/L₀ = F/EA
ΔL = FL₀/EA
ΔL = 5000(5.0) / (125e8(π(0.034²)))
ΔL = 0.00055070914... m
With that Young's modulus our shaft may be made of strong wood such as oak or douglas fir, or possibly lead.
If vector A has components Az = -3.00 and Ay = -4.00, then the magnitude of A is
Answer:
√((-3.00)² + (-4.00)²) = 5.00
Explanation:
The formula to determine the magnitude of a vector (in two dimensional space) v = (x, y) is: |v| =√(x2 + y2). This formula is derived from the Pythagorean theorem.
|v| =√(x2 + y2).
V = √((-3.00)² + (-4.00)²)
= 5.00
What is vector ?"A quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. "Although a vector has magnitude and direction, it does not have position.
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Learning Check: Ranking Elements
Use the following five elements to answer the next three questions: Na, K, Ca, He, Fr
1. Rank these elements from largest atomic radius to smallest.
2. Rank these elements from most metallic to least metallic.
3. Rank these elements from least electromagnetic to most electromagnetic.
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A car speeds up from 3 m/s to 10 m/s in 8 s. How far does the car travel while doing this? 2. A
Initial velocity=u=3m/s
Final velocity=v=10m/s
Time=t=8s
[tex]\boxed{\sf Acceleration=\dfrac{v-u}{t}}[/tex]
[tex]\\ \sf\longmapsto Acceleration=\dfrac{10-3}{8}[/tex]
[tex]\\ \sf\longmapsto Acceleration=\dfrac{7}{8}[/tex]
[tex]\\ \sf\longmapsto Acceleration=0.8m/s^2[/tex]
Distance =sUsing second equation of motion
[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \sf\longmapsto s=3(8)+\dfrac{1}{2}(0.8)(8)^2[/tex]
[tex]\\ \sf\longmapsto s=24+0.4(64)[/tex]
[tex]\\ \sf\longmapsto s=24+25.6[/tex]
[tex]\\ \sf\longmapsto s=49.6m[/tex]
7) Somewhere you place a 7.5 kg pumpkin on a spring scale. If the scale reads 78.4 N,
what is the acceleration due to gravity at that location?
Answer:
10.45m/s^2
Explanation:
Cause acceleration is the force divided by the mass
A cynical block on an air table vibrates horizontally in SHM with an amplitude of 8.0cm and a frequency of 1.50Hz. If a smaller block sitting on it is not to slide, what is the minimum value that the coefficient of static friction between the two blocks can have?
Answer:
μ = 0.724
Explanation:
maximum acceleration for SHM
a = ω²A
ω = 2πf
a = 4π²f²A
a = 4π²(1.50)²(0.080) = 7.106... m/s²
μ = F/N = ma/mg = a/g = 7.106/9.81 = 0.7243...
I'm cynical that a block can be cynical. Wassa madder, doesn't trust anyone?
What would make oppositely charged objects attract each other more?
o increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object
O decreasing the positive charge of the positively charged object and decreasing the negative charge of the negatively charged object
O increasing the distance between the positively charged object and the negatively charged object
O maintaining the distance between the positively charged object and the negatively charged object
Answer:
a: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object
Explanation:
The oppositely charged objects attract each other more is option a. It increased the positive charge and the negative charge.
The Attraction of the oppositely charged:At the time when the oppositely charged objects are attracted to each other more so here the positive charge should be increased with respect to the positive charge object and the negative charge is increased with respect to the negative charge object
Hence, the first option is correct.
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i though a=9.8 is in free fall?
Convert 27 Fahrenheit to Celsius
Answer:
27 degrees Fahrenheit is -2.78°c
Space explorers discover an 8.7 × 1017 kg asteroid that happens to have a positive charge of 4400 C. They would like to place their 3.3 × 105 kg spaceship in orbit around the asteroid. Interestingly, the solar wind has given their spaceship a charge of -1.2 C.
What speed must their spaceship have to achieve a 8300-km-diameter circular orbit?
We have that the speed of the spaceship must be
[tex]V=2.47m/s[/tex]
From the Question we are told that
Mass [tex]8.7*10^{17} kg[/tex]
Positive charge of 4400 C
Spaceship mass m_s=3.3* 10^5 kg
Solar wind has given their spaceship a charge of -1.2 C.
Diameter d=8300-km-diameter
Generally the equation for the force of attraction is mathematically given as
[tex]v^2=\frac{Gm}{r}+\frac{kQq}{rm}\\\\v^2=\frac{6.67*10^{-11}*8.7*10^{17}}{9.5*10^5}}+\frac{9*10^9*4400*-1.2}{9.5*10^5*3.3*10^{15}}[/tex]
[tex]V=2.47m/s[/tex]
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The speed will be "6.98 m/s". A complete solution is provided below.
The given values are:
Mass of asteroid,
M = [tex]8.7\times 10^{17}[/tex] kgMass of spaceship,
m = [tex]3.3\times 10^{5}[/tex] kgCharge,
[tex]q_1=4400 \ C[/tex][tex]q_2=1.2 \ C[/tex]As we know,
→ [tex]F_G +F_E = \frac{mv^2}{R}[/tex]
or,
→ [tex]\frac{GMm}{R_2} +\frac{kq_1 q_2}{R_2}=\frac{mv^2}{R}[/tex]
By putting the given values, we get
→ [tex]\frac{6.67\times 10^{-11}\times 8.7\times 10^{17}\times 3.3\times 10^5}{\frac{8.3\times 10^6}{2} } +\frac{9\times 10^9\times 4400\times 1.2}{\frac{8.3\times 10^6}{2} } = 3.3\times 10^5\times v^2[/tex]
→ [tex]v=6.98 \ m/s[/tex]
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Which of the following is the best order-of-magnitude estimate in meters
of the height of a mountain?
a. 1 m
b. 10 m
c. 100 m
d. 1000 m
Answer:2
Explanation:
Need answer
What are the conditions for a flow to be irotational flow
Answer:
Rotation of a fluid particle can be caused only by a torque applied by shear forces on the sides of the particle. Since shear forces are absent in an ideal fluid, the flow of ideal fluids is essentially irrotational. Generally when the flow is viscid, it also becomes rotational
A truck travels 40 m while slowing down from 15 m/s to 10 m/s. How long does it take to do this?
Answer:
4s
Explanation:
A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial, the student uses a different amount of sugar and a different temperature of water.
What is wrong with this experimental design?
A. The student does not have a dependent variable.
B. The student changed too many variables.
C. The student needs to perform more trials.
D. The student did not change enough variables.
Tina drove 3 miles north and 4 miles west to get to her grandmother’s house. Find the distance and displacement.
Answer:
distance = 3 + 4 = 7 mi
displacement is √(3² + 4²) = 5 mi
Explanation: