Distributions of data can be characterized along three aspects or dimensions. Which aspect represents the spread or distribution of the data?

The smaller number is 28.

Answer:

Solution Given:

let the smaller number be a.

and larger number be a+4.

By question

a+(a+4)=60

a+a+4=60

2a=60-4

2a=56

a=[tex] \frac{56}{2} [/tex]

a=28

Answer:

y = 28

Step-by-step explanation:

Given variables:

Create two equations with the given information.

Equation 1

If one number is 4 more than another, then:

⇒ x = y + 4

(Remembering that x is the larger number and y is the smaller number).

Equation 2

If their sum is 60, then:

⇒ x + y = 60

Substitute Equation 1 into Equation 2 and solve for y:

⇒ (y + 4) + y = 60

⇒ 2y + 4 = 60

⇒ 2y + 4 -4 = 60 - 4

⇒ 2y ÷ 2 = 56 ÷ 2

⇒ y = 28

Therefore, the value of the smaller number (y) is 28.

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The equation of a line that exists perpendicular to line g contains (P, Q) exists x + 4y = 4Q + P.

Given: Coordinate plane with line g that passes through the points (-2,6) and (-3,2).

The coordinate of G: (-2,6) and (-3,2)

Let, [tex]$&\left(x_{1}, y_{1}\right)=(-2,6) \\[/tex] and [tex]$&\left(x_{2}, y_{2}\right)=(-3,2)[/tex]

The slope of a line [tex]$\mathbf{g}$[/tex] :

[tex]$m &=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\[/tex]

[tex]$m &=\frac{2-6}{-3-(-2)} \\[/tex]

[tex]$m &=\frac{-4}{-1} \\[/tex]

m = 4

So, the slope of a line g exists 4.

To find the slope of a line perpendicular to g,

[tex]$&m_{1}=-\frac{1}{m} \\[/tex]

[tex]$&m_{1}=-\frac{1}{4}[/tex]

The equation of the slope point form of the line exists

[tex]$\left(y-y_{1}\right)=m\left(x-x_{1}\right)$[/tex]

[tex]$y-Q=-\frac{1}{4}(x-P)$[/tex]

[tex]$4 y-4 Q=-x+P$[/tex]

[tex]$x+4 y=4 Q+P$[/tex]

Therefore, the equation of a line that exists perpendicular to line g contains (P, Q) exists x + 4y = 4Q + P.

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Answer:

When the data are nominal or ordinal.

Step-by-step explanation:

Spearman's correlation

Spearman's correlation measures the strength and direction of monotonic association between two variables.

Monotonicity is "less restrictive" than that of a linear relationship.

For example, the middle image above shows a relationship that is monotonic, but not linear.

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The data exists nominal or ordinal. Spearman's correlation estimates the strength and direction of the monotonic relationship between two variables.

a) Pearson correlation

b) Kendall rank correlation

c) Spearman correlation

d) Point-Biserial correlation.

The data exists nominal or ordinal. Spearman's correlation estimates the strength and direction of the monotonic relationship between two variables.

Monotonicity exists as "less restrictive" than that of a linear relationship.

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Answer:

Let Ji and Bi represent the initial amounts that Joe and Bill have at the start.  Number after J and B will be used to indicate subsequent steps in the problem.

We are told that "Joe has five times as much money as Bill," which we can write as:

   1)  Ji = 5Bi

We learn that "Joe pays Bill $5," which we can represent as:

   2)  J1 = Ji - 5

This would mean that Bill has added $5:

   3)  B1 = Bi + 5

We are then told that "Joe has just twice the amount Bill now has," which we can write as:

   4)  J1 = 2B1

===

We can rearrnage and substitute the above relationships to eliminate one of the two variables (B1 or J1)

J1 = Ji - 5                [from 2]

2B1 = Ji - 5              [Substitute 4 to eliminate J1]

Ji = 5Bi                    [from 1]

2B1 = 5Bi - 5           [Substitute 1 to eliminate Ji]

B1 = Bi + 5               [Rearrange]

2(Bi + 5) = 5Bi - 5    [Use the above expression in the previous equation to eliminate B1]

2Bi + 10 = 5Bi - 5    [Simplify]

-3Bi = -15                  [Simplify]

Bi = $5                       [Solve]

Ji = 5Bi                    [from 1]

Ji = 5*(5)                  [Since Bi = $5]

Ji = $25                    [Solve]  

===

CHECK:

Does Joe has five times as much money as Bill?

Ji = $25 and Bi = $5  YES

When Joe pays Bill $5 he owes him, does Joe has just twice the amount Bill now has?

J1 = $25 - $5 = $20

B1 = $5 + $5  = $10    YES

2a is 2 x a

Substitute a =5

2 x 5 =10

Now we have:

10^2-c

Substitute c = 10

(2 - 10 = - 8)

So,it's now 10^ - 8 (10 to the power of - 8)

Ans: 10^ - 8 (or 1 x 10^ -8)

Hope this helps!

Answer:

312,847,415

Step-by-step explanation:

1. Define the given values:

2. Now interpret what other information the question gives:

3. upscale the ratio:

therefore, the total population in Texas = 312,847,415

Hope this helps :)

Answer:

HL

Step-by-step explanation:

The hypotenuses and the long legs of the right triangles are congruent, therefore using the rule HL, the triangles are congruent.

Step-by-step explanation:

step 1: how many dolphins

there are 6 sharks

sharks to dolphins is 3 to 5

3 S to 5 D

we can divide 6 (amount of sharks known) by 3, to get what a ratio of 1 is

6 ÷ 3 = 2

so 2 sharks is = 1 part or ratio

now we can times by 5 to get a ratio of 5

5 × 2 = 10

there are 10 Dolphins

Step 2: How many starfish

repeat the steps above but for the ratio 2: 7 where 2 is the Dolfin ratio and there are 10 dolphins

put in questions answer you got

Answer:

35 starfish

Step-by-step explanation:

shark/dolphin  *  dolphin /starfish = shark / starfish

Now. put in the numbers given:

3/5 * 2/7 =      6/35  = shark / starfish    put in '6' for shark (given)

        6/35 = 6/starfish        cross multiply

        6 * starfish = 35* 6

           starfish = 35  

Answer:

16b > 94

Step-by-step explanation:

16b > 94

b > 5.875

Crystal needs 6 boxes to fit all 94 discs.

This might help a bit, i hope

The difference between the mean times is about 2 times the absolute deviation of the data sets.

Given that the difference of the means is found.

The difference in the means is basically the absolute difference between the mean of two groups. It explains the mean of two groups. It explains how much difference that exists between the average between two groups.Calculating mean difference is significant during clinical trials where we have the experimental group and the control group. The mean absolute deviations is basically the variation of each data value from the mean. It tells us how much the values in a set of data differ from the mean value. It explains the reach of values in a data set. There is a relationship that exists between the difference of the mean absolute deviations.

Hence the difference between the mean times is about 2 times the absolute deviation of the data sets.

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The remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

The expression is given as:

x^2y - 2xy - 24y

Factor out y from the expression

y(x^2 - 2x - 24)

Expand the equation

y(x^2 + 4x - 6x - 24)

Factorize

y(x - 6)(x + 4)

Hence, the remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

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Answer:

80

Step-by-step explanation:

The 9 eights would be

8, 18, 28, 38, 48, 58, 68, 78, 80

Answer:

20 lorries are needed to transport.

Mark brainliest

Answer:

14day

Step-by-step explanation:

lorries trip per day. crates

3. 5 2500

? 6 10000

(6×3×10000)÷(5×2500)=14days

Answer:

x = 3

Step-by-step explanation:

4x + 3 = 2x + 9
1. Remove 3 from both sides
4x = 2x + 6
2. Remove 2x from both sides
2x = 6
3. x = 3

Answer:

here is the answer

hope it helps u

stay safe and healthy

{ BTS ARMY GIRL }

Rashmi

The system that can help to model this are

We have the following equation. Remember that a good understanding of the question is what would help us to write the equation

The condition says:

The square of first number is equal to the sum of the second number and 16:

First number = x. Square of x = x²

second number = y + 16

For the second

The difference of 4 times the second number and 1 is equal to the first number multiplied by 7:

second number is y

4*y - 1= x*7

= 4y - 1 = 7x

Hence we would have the following as our equations

x² = y + 16

4y - 1 = 7x

The solution to the equation when graphed = 5, 9

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The distance between  the points (–3,k) and (2, 0) exists k = ± 3.

How to estimate the distance between points (–3, k) and (2, 0)?

To calculate the distance between two points exists equal to

[tex]$d=\sqrt{(y 2-y 1)^{2}+(x 2-x 1)^{2}}$[/tex]

we have (-3, k) and (2, 0)

[tex]$&d=\sqrt{34}[/tex]

substitute, the values in the above equation, and we get

[tex]$\sqrt{34} &=\sqrt{(0-k)^{2}+(2+3)^{2}} \\[/tex]

simplifying the above equation

[tex]$\sqrt{34} &=\sqrt{(-k)^{2}+(5)^{2}} \\[/tex]

[tex]$\sqrt{34} &=\sqrt{k^{2}+25}[/tex]

squared both sides

[tex]$&34=k^{2}+25 \\[/tex]

[tex]$&k^{2}=34-25 \\[/tex]

[tex]$&k^{2}=9 \\[/tex]

k = ± 3

Therefore, the value of k = ± 3.

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The approximate solution to the given system of equation is (-2.71, 2.14)

From the question, we are to determine the approximate solution to the given system of linear equations.

The given equations are

y = 0.5x + 3.5

y = -2/3 x+ 1/3

From the given information, we are to show the solutions on a graph

The graph that shows the solution to the given system of equation is shown below.

The solution to the given system is the point of intersection of the lines. The coordinate of the point of intersection of the lines is (-2.71, 2.14). That is, x = -2.71, y = 2.14.

Hence, the approximate solution to the given system of equation is (-2.71, 2.14)

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Answer:

D

Step-by-step explanation:

Your equation would be 2x^2-3=y

This means that it should touch the y axis at -3, but since there is an exponent, it should be a parabola, not a straight line. Hence the answer is D

The factors illustrate they the sides of the rectangles are:

The first equation given is x² - 3x + 2.

= x² - 3x + 2.

= x² - x - 2x + 2

= x(x - 1) - 2(x - 1)

= (x - 1)(x - 2)

Therefore, the side lengths are (x - 1) and (x - 2).

In the rectangular figure, the length and width should be the expressions above.

The second equation given is 2x² + x - 6.

= 2x² + x - 6.

= 2x² + 4x - 3x - 6

= 2x(x + 2) - 3(x + 2)

= (2x - 3)(x + 2)

Therefore, the side lengths are (2x - 3) and (x + 2).

In the rectangular figure, the length and width should be the expressions above.

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The total area of the composite figure is 176 ft

The area of a composite figure can be found as follows;

Therefore,

Total area = area of rectangle + area of triangle

area of rectangle = lw

where

Therefore,

area of a rectangle = 16 × 8

area of a rectangle = 128 ft²

area of triangle = 1 / 2 bh

where

Therefore,

area of triangle = 1 / 2 × 12 × 8

area of triangle = 48 ft²

Total area of the composite figure = 48 + 128 = 176 ft

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The points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)

We are given the equations of the linear graphs as;

y = ⁷/₄x + ⁵/₂

y = ³/₄x - 3

Notice that the lines intersect each other and by definition, if the lines of the system of equations intersect, then the system has one solution. This means that the point of intersection of the lines is the solution of the system. It can be written as:

(x, y)

x is the x-coordinate .

y is the y-coordinate.

In this case, we can identify that:

- the x-coordinate of the point of intersection is between; x = 2 and x = 3

- The y-coordinate of the point of intersection is between y = -1 and y = -2

Based on the above, we can conclude that the points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)

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Answer: B and C) 2.2, -1.4 and 2.2, -1.35

Step-by-step explanation:

Hope this helps!

Mark me brainliest!

Pls and Ty!

By applying inverse of a matrix, we find that the solution of the system of linear equations is (x, y) = (5/7, - 2/7).

In linear algebra, systems of linear equations with a unique solution can be represented by the following expression:

[tex]\vec A \cdot \vec x = \vec B[/tex]      (1)

Where:

The solution of such systems is defined by:

[tex]\vec x = \vec A^{-1}\cdot \vec B[/tex]

[tex]\vec x = \frac{1}{\det(\vec A)}\cdot adj\left(\vec A\right) \cdot \vec B[/tex], where [tex]\det \left(\vec A\right) \ne 0[/tex].

Where:

For the case of [tex]\vec A \in \mathbb{R}_{2\times 2}[/tex], the inverse of [tex]\vec A[/tex] is:

[tex]\vec A^{-1} = \frac{1}{\det \left(\vec A\right)} \cdot \left[\begin{array}{cc}a_{22}&-a_{12}\\-a_{21}&a_{11}\end{array}\right][/tex]     (2)

If we know that [tex]\vec A = \left[\begin{array}{cc}3&4\\5&2\end{array}\right][/tex] and [tex]\vec B = \left[\begin{array}{cc}1\\3\end{array}\right][/tex], then the solution of the system of linear equations is:

[tex]\vec A^{-1}= \frac{1}{(3)\cdot (2) - (5) \cdot (4)}\cdot \left[\begin{array}{cc}2&-4\\-5&3\end{array}\right][/tex]

[tex]\vec A^{-1} = -\frac{1}{14}\cdot \left[\begin{array}{cc}2&-4\\-5&3\end{array}\right][/tex]

[tex]\vec A^{-1} = \left[\begin{array}{cc}-\frac{1}{7} &\frac{2}{7} \\\frac{5}{14} &-\frac{3}{14} \end{array}\right][/tex]

[tex]\vec x = \left[\begin{array}{cc}-\frac{1}{7} &\frac{2}{7} \\\frac{5}{14} &-\frac{3}{14} \end{array}\right] \cdot \left[\begin{array}{cc}1\\3\end{array}\right][/tex]

[tex]\vec x = \left[\begin{array}{cc}\frac{5}{7} \\-\frac{2}{7} \end{array}\right][/tex]

By applying inverse of a matrix, we find that the solution of the system of linear equations is (x, y) = (5/7, - 2/7).

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Answer: If your opponent is winning 3:1 then they are probably better then you if they are winning more then you are. (or you are just having a bad day)

Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134

Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466

Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400

Let's denote the three possibilities as follows:

A: Equally talented, each player has a 0.5 probability of winning a game.

B: You are slightly better, with a 0.6 probability of winning a game.

C: Your opponent is slightly better, with a 0.6 probability of winning a game.

Given that you won the second game but lost the first, third, and fourth games, we want to find the probability of scenario C given this outcome. Let P(C) represent the prior probability of scenario C being true.

According to the given information, each of the three scenarios (A, B, and C) is equally likely, so P(A) = P(B) = P(C) = 1/3.

Now, let's update the probabilities based on the outcome of the match:

In scenario A:

The probability of winning the second game is 0.5, and the probability of losing the first, third, and fourth games is 0.5 each. Therefore, the overall probability of the observed outcome in scenario A is (0.5 * 0.5 * 0.5 * 0.5) = 0.0625.

In scenario B:

The probability of winning all three games (assuming you are slightly better) is (0.6 * 0.6 * 0.6) = 0.216.

In scenario C:

The probability of winning the second game (assuming your opponent is slightly better) is 0.4, and the probability of losing the first, third, and fourth games is 0.6 each. Therefore, the overall probability of the observed outcome in scenario C is (0.4 * 0.6 * 0.6 * 0.6) = 0.05184.

Now, we can update the probabilities based on Bayes' theorem:

Posterior probability of scenario A: P(A|data) = (P(data|A) * P(A)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

Posterior probability of scenario B: P(B|data) = (P(data|B) * P(B)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

Posterior probability of scenario C: P(C|data) = (P(data|C) * P(C)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

P(data|A) = 0.0625

P(data|B) = 0.216

P(data|C) = 0.05184

Plugging in the values, we get:

Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134

Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466

Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400

So, after the match, the posterior probability that your opponent is slightly better than you is approximately 0.400 or 40%.

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Answer:

1/2

Step-by-step explanation:

Assume the coin is a fair coin.

Since we already know that the first 9 tosses were heads, the probability of 9 straight heads in the first 9 tosses is 1.

It all depends on the last toss. There is an equal probability of heads and tails in a single toss of a fair coin.

p(heads) = 1/2

p(10 heads) = 1/2

Ok so the answer is 1/2

The worth of the share of stock is $[tex]34\frac{3}{4}[/tex].

A fraction is a non-integer that is made up of a numerator and a denominator. The numerator is the number above and the denominator is the number below.

A mixed fraction is a fraction that is made up of a whole number and a proper fraction.  A proper fraction is a number where the numerator is less than the denominator.

The worth of the stock now = purchase price + increase in the share price

28 1/8 + 6 5/8

[tex]34 \frac{1 + 5}{8}[/tex]

[tex]34\frac{6}{8}[/tex] = [tex]34\frac{3}{4}[/tex]

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Answer:

Sum of 374 and 25 = 374+25 = 399

now subtract 9 from the sum, i.e. 399 = 399 - 9 = 390 is your answer

Answer:

Step-by-step explanation:

374+25

=399

Now, subtracting the sum from 9

9-399

=   -390