divide (x3−8x2+2)÷(x−3)

Answers

Answer 1

Answer: -37

Step-by-step explanation:

standard: -13 -[tex]\frac{37}{x-3}[/tex]

quotient: -13

Remainder: -37

Answer 2

Answer:

[tex]x^{2} + \frac{-5x^{2} + 2}{x - 3}[/tex]

Step-by-step explanation:

Attached on file below.

Divide (x38x2+2)(x3)

Related Questions

hey guys im confused

Answers

The values of the function are-

Part a: Value of (f/g)(x) = x - 9Part b: Domain of (f/g)(x) = Real numbers.What is termed as the domain and range of the function?The domain of the a function is the collection of values that can be plugged into it. This set contains the x values inside a function like f(x). A function's range is the set of values which the function can take. This is the set of values which the function returns after we enter an x value.

For the given function;

f(x) = x - 3

g(x) =(x - 3)/(x - 9)

Part a: Value of (f/g)(x)

For the finding the value of  (f/g)(x) simply divide the function g(x) by f(x).

(f/g)(x) = (x - 3)/ [(x - 3)/(x - 9)]

As, (x -3) will get cancelled.

(f/g)(x) = x - 9

Part b: Domain of (f/g)(x)

(f/g)(x) = x - 9

As, the resultant function is a polynomial function, thus the domain of the function is all real numbers.

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The coordinates of point T are (0,5). The midpoint of ST is (6,-7).Find the coordinates of point S.S =(

Answers

If the midpoint of ST is (6, -7) then its distance from S and T must be the same!

The distance from point T (0,5 ) to (6, -7) is from the Pythagorean theorem:

[tex]d=\sqrt{\left(0-6\right)^2+\left(5--7\right)^2}[/tex]

which is

[tex]d=6\sqrt{5}[/tex]

Which equation represents a line that is perpendicular to Line L on the graph below?A. Y= -1/2x+3B. Y= 1/2x+3C. Y=2x+3D. Y= -2x+3

Answers

In this question, we are given a line. The standard equation of line is:

y = mx + b

Here, m is the slope, that is the difference of y values over the x values.

m = (y2 - y1) / (x2 - x1)

b is the y-intercept, where the value of x is zero.

If we see the line, x = 0, when y = -4. Hence, the y-intercept = b = -4

Also,

(x1, y1) = (0, -4)

(x2, y2) = (-4, 4)

m = [4 - (-4)]/ [-4 - 0]

m = 8/-4

m = -2

Hence, the equation of given line is

y = -2x - 4

The rule is: two lines are perpendicular if their slopes are negative reciprocal of each other.

In other words, two lines with slope m1 and m2 are perpendicular if

m1 = -1/m2

Now, the slope (m1) of the given line is -2. Hence, the slope (m2) of the perpendicular line would be m2 = 1/-(-2) = 1/2

Now, just put this value, we get

Y = 1/2 x - 4

As there is no solution closer to this one, I believe the 2nd answer Y = 1/2x + 3 would be correct.

The Cougars scored a total of 84 points in their basketball game last nightagainst the Bears. The Cougars made no one-point shots, and a total of38 two-point and three-point shots. Let x represent the number of two-pointshots and y represent the number of three-point shots.a. How many two-point shots did the Cougars make? How many three-pointshots did the Cougars make? Write and solve a system of equations that canbe used to solve this problem.

Answers

Step 1: Write out the values

For Cougars

Total Points = 84

Number of 1 point shot = 0

Number of 3 and 2 points shots = 38

Step 2: Write out the system of equations

[tex]x+y=38---------------------(1)[/tex]

Since there are x number of two-point shots, then the total number of points from the two-point shots is 2x

Also, there are y number of three-point shots, then the total number of points from the three-point shots is 3y

Hence, the total number of points is 2x + 3y

Therefore,

[tex]2x+3y=84----------------(2)[/tex]

Step 3: Solve the system of equation simultaneously

x + y = 38 ------ equation 1

2x + 3y = 84 ------ equation 2

Using the elimination method to eliminate x

Multiply equation 1 by 2 to get a new equation

2x + 2y = 76 ------ equation 3

Step 4: combine equation 2 and 3 and solve simultaneously

2x + 3y = 84------- equation 2

2x + 2y = 76 ------ equation 3

Subtract equation 3 from 2

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Name the constant variation for this equation y = 5x

Answers

Answer:

The constant is 5 and the variation is known as the slope of the equation which is the rate of change of y with respect to x. In other words how much does y change when x changes by 1 unit

Step-by-step explanation:

find figure 0 for the tile pattern below. write a rule that will give the number of tiles in any figure, record the data for the first six tiles 0-5 in a table, and graph the data

Answers

Solution

for this case we can see that for

Figure 0 = 6 tiles

Figure 1 = 7 tiles

Figure 2 = 8 tiles

Figure 3= 9 tiles

Figure 4 = 10 tiles

Figure 5= 11 tiles

Then the table would be given by:

Figure number (x) 0 1 2 3 4 5 x

Number of tiles (y) 6 7 8 9 10 11 6+x

And the line should be like this:

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.Two workers in a holiday boutique are filling stockings with small gifts and candy. Katie has already filled 3 stockings and will continue to fill them at a rate of 1 stocking per hour. Peter, who just arrived to help, can fill 4 stockings per hour. At some point, Peter will catch up with Katie and they will have completed the same number of stockings. How long will that take? How many stockings will each worker have filled by then?In ____ hours, the workers will each have filled _____ stockings.

Answers

Two workers in a holiday boutique are filling stockings with small gifts and candy.

Katie has already filled 3 stockings and will continue to fill them at a rate of 1 stocking per hour.

3 + x

Peter, who just arrived to help, can fill 4 stockings per hour.

4 x

At some point, Peter will catch up with Katie and they will have completed the same number of stockings.

3 + x = 4x

3 = 4x -x

3 x =3

x = 3/3

x =1 hour How long will that take?

How many stockings will each worker have filled by then?

Katie = 3 + 1 = 4

Peter = 4 x 1 = 4

A local salesman receives a base salary of $925 monthly. He also receives a commission of 7% on all sales over $1350. How much would he have to sell in a month if he needed to have a monthly income of $2200?

Answers

The local salesman has to sell $19564.3 in a month if he needed to have a monthly income of $2200.

The monthly salary will be the sum of the fixed part or base salary and the commission part.

The base salary of the local salesman is $925.

The salesman commission part is 7% on all sales over $1350.

Let x be the total amount of sales, and x must be greater than $1350.

Then,

The amount of sales over $1350 is x - 1350.

He earns 7% on that amount, so the commission part is 7% of (x - 1350),

or 0.07( x - 1350 ).

So,

monthly salary = fixed part + commission part

monthly salary = 925 + 0.07( x - 1350)

925 + 0.07(x - 1350) = 2200

0.07(x - 1350) = 1275

0.07x - 94.5 = 1275

0.07x = 1369.5

x = 19564.3

He would have to sell $19564.3 in a month if he needed to have a monthly income of $2200.

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Could you please check this answer for me? Use the following equation to solve Y:2y-6x=18 The answer I got is: y=3(x+3)

Answers

The answer is y=3(x+3)

[tex]\begin{gathered} 2y-6x=18 \\ 2y=18+6x \\ y=\frac{2(9+3x)}{2} \\ y=9+3x \\ y=3(3+x) \end{gathered}[/tex]

BRAINLEST AND 69 POINTS ANSWER PLEASE ASAP
The length of a bacterial cell is about 3 x 10^−6 m, and the length of an amoeba cell is about 4.5 x 10^−4 m. How many times smaller is the bacterial cell than the amoeba cell? Write the final answer in scientific notation with the correct number of significant digits.
2 x 10^2
2 x 10^3
0.7 x 10^1
6.67 x 10^2

Answers

Answer:6.67x10^2

Step-by-step explanation:

I need help with the following questions. Please show your work.

1) Find the inverse of f(x)=3 sqrt x-1/2

2) Let f(x)-2/2x-1
Show that this function is one-to-one algebraically.

3) Determine whether f(x)=3x-5 and g(x)=x/3+5 are inverses. Explain how you know.

please help

Answers

For the given functions, it is found that:

1) The inverse is: [tex]f^{-1}(x) = \frac{4x^2}{9} + 1[/tex]

2) f(a) = f(b) if, and only if, a = b, hence the function is one-to-one.

3) The composite of these two functions is different of x, hence the two functions are not inverses.

Item 1

The function is defined by:

[tex]y = 3\frac{\sqrt{x - 1}}{2}[/tex]

To find the inverse, we exchange x and y on the original function and then isolate y, hence:

[tex]x = 3\frac{\sqrt{y - 1}}{2}[/tex]

[tex]3\sqrt{y - 1} = 2x[/tex]

[tex]\sqrt{y - 1} = \frac{2x}{3}[/tex]

[tex](\sqrt{y-1})^2 = \left(\frac{2x}{3}\right)^2[/tex]

[tex]y - 1 = \frac{4x^2}{9}[/tex]

[tex]y = \frac{4x^2}{9} + 1[/tex]

[tex]f^{-1}(x) = \frac{4x^2}{9} + 1[/tex]

Item 2

To show that the function is one-to-one, we need to show that f(a) = f(b) if, and only if, a = b, then:

f(a) = -2/(2a - 1).f(b) = -2/(2b - 1).

Equaling the functions:

-2/(2a - 1) =  -2/(2b - 1).

Applying cross multiplication:

-2(2b - 1) = -2(2a - 1)

2b - 1 = 2a - 1

2b = 2a

b = a.

Hence the function is one-to-one.

Item 3

The functions will be inverses if the composition of the functions result in x, hence:

f(g(x)) = f(x/3 + 5) = 3(x/3 + 5) - 5 = x + 15 - 5 = x + 10.

Hence the functions are not inverses.

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Select all the correct answers.Which two transformations preserve the side lengths and angles of the preimage? a reflection across line a stretch by a factor of 4 a dilation by a factor of 4 a translation to the right

Answers

Which two transformations preserve the side lengths and angles of the preimage:

Rotations and reflections both preserve a polygon's side lengths. Dilations and translations both preserve a polygon's angle measures.

A reflection across line will preserve the angles

A dilation by a factor of 4 will preserve the both

Hence the correct answer is Option A and D

Answer:

1: a translation to the right

2: a reflection across line m

Step-by-step explanation:

I'm not sure how to find the degrees for angle d

Answers

Answer

a° = 58°

b° = 48°

c° = 74°

d° = 122°

Explanation

To answer this, we need to first know

- what alternate angles are.

- that the sum of angles in a triangle is 180°.

- The sum of angles on a straight line is 180°.

Alternate angles are angles that are in opposite positions relative to a transversal intersecting two lines. If the two lines are parallel to each other, then alternate angles are equal.

We can see that

a° = 58°

b° = 48°

Then, for c°,

48° + 58° + c° = 180° (Sim of angles in a triangle is 180°)

106° + c° = 180°

c° = 180° - 106°

c° = 74°

Then, for d°,

58° + d° = 180° (Sum of angles on a stright line is 180°)

d° = 180° - 58°

d° = 122°

Hope this Helps!!!

determine if the following are rotations

Answers

Answer: D and C are the other rotations

Step-by-step explanation: A is mirrored

In ∆VWX, w=680 cm, < X =80° and

Answers

1) We know that the sum of the interior angles within a triangle is 180º

So we can state that :

∠X = 80º , ∠V=32º and ∠W = 180º-(80+32), ∠W=68º

2) The area of a triangle can be found by the Heron formula, but before that, we need to find out the other legs. Let's sketch this and use the Law of Sines:

The Law of Sines:

[tex]\begin{gathered} \frac{v}{\sin(V)}=\frac{w}{\sin(W)}=\frac{x}{\sin(X)} \\ \frac{v}{\sin(32)}=\frac{680}{\sin(68)} \\ 680\text{ sin(32) = vsin(68)} \\ \frac{680\text{ }\sin(32_{}}{\sin(68)}=v \\ v\text{ =}388.65 \\ \\ \end{gathered}[/tex]

Now let's proceed to find the length of side x:

[tex]\begin{gathered} \frac{w}{\sin(W)}=\frac{x}{\sin(X)} \\ \frac{680}{\sin(68)}=\frac{x}{\sin (80)} \\ x\sin (68)=680\cdot\sin (80) \\ x=\frac{680\cdot\sin (80)}{\sin (68)} \\ x\approx722.26 \end{gathered}[/tex]

Now we can add the three sides and find out the Perimeter:

2p: 722.26 +388.65 +680

2p=1790.91

And the semi perimeter is p =2p/2, p =895.455.

2.2) Finally we can find out the area using the Heron Formula:

[tex]\begin{gathered} A=\sqrt[]{p(p-v)(p-w)(p-x)} \\ A=\sqrt[]{895.455(895.455-388.65)(895.455-722.455)(895.455-680)} \\ A=130059.9757\approx130060 \end{gathered}[/tex]

3) Hence, the area is 130,060 cm²

Hi guys.I was sick today and I’m still not feeling good.I missed out on class and I’ll be giving 25 points to whoever helps me.Thank you

Answers

Answer:

x = -12

Step-by-step explanation:

these two angles are same side interior angles. These two angles will add up to 180.
so we have the equation:

(x + 142) + (x + 62) = 180

Now just simplify:

(x + 142) + (x + 62) = 180

___-142_________-142

x + (x + 62) = 38

_____-62___-62

x + x = -24

2x = -24

-24/2 = -12

Therefore, x = -12

Simplify.10(15 + n)150 n150 + n150 + 10 n50 + n

Answers

The Solution:

Given:

[tex]10(15+n)[/tex]

We are required to simplify.

[tex]\begin{gathered} 10(15+n) \\ 150+10n \end{gathered}[/tex]

Therefore, the correct answer is:

[tex]undefined[/tex]

multiply and/ or divide and put into lowest terms

Answers

[tex]\frac{\frac{3}{a^2-81}}{\frac{9}{a-9}}[/tex]

the division of fractions follows the stes

[tex]\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot d}{b\cdot c}[/tex]

Applying this into the expression given

[tex]\frac{3\cdot(a-9)}{9\cdot(a^2-81)}[/tex]

simplify the coefficients by decomposing 9 into a product and cancelling the common factors

[tex]\frac{3\cdot(a-9)}{3\cdot3\cdot(a^2-81)}[/tex]

simplify

[tex]\frac{a-9}{3\cdot(a^2-81)}[/tex]

In the denominators there is a difference of squares that can be rewriten as a product, in which by definition the difference of square is described as

[tex]a^2-b^2=(a+b)\cdot(a-b)[/tex]

In the denominator of the expression we can see that a is squared and that 81 has an exact root which is 9, reason why we can write this as a difference of squares, it should look like this:

simplify the expression

[tex]\frac{1}{3\cdot(a+9)}[/tex]

distribute the 3

[tex]\frac{1}{3a+27}[/tex]

On the driving range, Tiger Woods practices his swing with a particular club by hitting many, many balls.
When Tiger hits his driver, the distance the ball travels follows a Normal distribution with mean 304 yards and standard deviation 8 yards.
a) What percent of Tiger's drives travel at least 290 yards?
b) What percent of Tiger's drives travel between 305 and 325 yards?
Q) What if our z does not show on table A?

Answers

Using the normal distribution, it is found that:

a) 95.99% of Tiger's drives travel at least 290 yards.

b) 44.40% of Tiger's drives travel between 305 and 325 yards.

c) If the z-scores do not show on table A, they represent too low or too high values, with probabilities very close to either 0 or 1.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is given by the following rule:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure X is above or below the mean, depending if the z-score is positive or negative.From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X.If the z-score does not show on the z-table, they represent too low or too high values, with probabilities very close to either 0 or 1.

The mean and the standard deviation for the length of Tiger Woods's swings are given as follows:

[tex]\mu = 304, \sigma = 8[/tex]

The proportion of golf swings that are at least 290 years is one subtracted by the p-value of Z when X = 290, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (290 - 304)/8

Z = -1.75

Z = -1.75 has a p-value of 0.0401.

1 - 0.0401 = 0.9599.

Hence the percentage is of 95.99%.

The proportion of golf swings that are between 325 yards and 305 yards is the p-value of Z when X = 325 subtracted by the p-value of Z when X = 305, hence:

X = 325:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (325 - 304)/8

Z = 2.63

Z = 2.63 has a p-value of 0.9957.

X = 305:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (305 - 304)/8

Z = 0.13

Z = 0.13 has a p-value of 0.5517.

0.9957 - 0.5517 = 0.4440.

Hence the percentage is of 44.40%.

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What is the present value of an investment that will be worth $7000 at the end of five years? Assume an APR of 6% compounded monthly. (Round your answer to the nearest cent.)

Answers

The Solution:

Let the present value of the investment be represented with P.

We shall use the formula below:

[tex]\begin{gathered} A=P(1+\frac{r}{100\alpha})^{n\alpha} \\ \text{Where} \\ A=\text{amount (after 5years)}=\text{ \$7000} \\ r=rate\text{ (in \%)=6 \%} \\ n=\text{ number of years =5 years} \\ \alpha=\text{ number of periods per annum =12} \\ P=\text{ Principal = initial investment=?} \end{gathered}[/tex]

Substituting these values in the formula above, we get

[tex]\begin{gathered} 7000=P(1+\frac{6}{100\times12})^{(5\times12)} \\ \\ 7000=P(1+\frac{6}{1200})^{60} \end{gathered}[/tex]

So,

[tex]\begin{gathered} 7000=P(1+0.005)^{60} \\ \\ 7000=P(1.005)^{60} \\ \text{Dividing both sides by 1.005}^{60},\text{ we get} \\ P=\frac{7000}{1.005^{60}}=\frac{7000}{1.348850153}=5189.605\approx\text{ \$5189.61 (518961cent)} \end{gathered}[/tex]

Thus, the present value of the investment that will yield $7000 at the end of 5 years is $5189.61 (or 518961 cents )

Therefore, the correct answer is $5189.61 (or 518961 cents )

the data to the right represent the top seed in kilometers per hour of all the players a certain soccer of a construct a frequency distribution is a frequency histrogram in a realative frequency histogram.what percentage of players had top speed between 18 and 21.9 km H what percentage of players had a top speed less than 13.9 kmh

Answers

The relative frequency is the percentage of a count over the total count.

To get the relative frequency, here are the steps:

1. Get the total count.

[tex]\begin{gathered} N=4+8+20+74+336+212 \\ N=654 \end{gathered}[/tex]

2. Divide each frequency or count by 654.

For example, the frequency between 10 - 13.9 km/h is 4 players.

[tex]\begin{gathered} P=\frac{x}{N} \\ P=\frac{4}{654} \\ P=0.0061 \end{gathered}[/tex]

Hence, the relative frequency for the first class interval is 0.0061.

Moving on to the next interval 14 - 17.9 km/h. x = 8 players

[tex]P=\frac{x}{N}=\frac{8}{654}=0.0122[/tex]

Moving on to the next interval 18-21.9 km/h. x = 20 players

[tex]P=\frac{x}{N}=\frac{20}{654}=0.0306[/tex]

Moving on to the 4th interval 22 - 25.9 km/h . x = 74 players

[tex]P=\frac{x}{N}=\frac{74}{654}=0.1131[/tex]

At 5th interval 26 - 29.9 km/h, x = 336 players.

[tex]P=\frac{x}{N}=\frac{336}{654}=0.5138[/tex]

Finally, at the last interval 30 - 33.9 km/h, x = 212 players.

[tex]P=\frac{x}{N}=\frac{212}{654}=0.3242[/tex]

Completing the table, we have:

Lucy bought four paint brushes from the Art Supply Store. She had a coupon for 25% off.
How much money does she owe? Each paint brush is 10.50

Answers

Answer: $31.50 for the four brushes after using the coupon

Step-by-step explanation:

$10.50 (Amount for EACH brush) * 0.75 (coupon 25% off)  = $7.875 (Amount for each after coupon)


$7.875* 4 brushes = $31.5


or


$10.50 (regular price) * 4 brushes = $42 (4 brushes at regular price)


$42 * 0.75(25% coupon) =$ 31.5

1. ¿Cuántas millas por minuto son 55 millas por hora?

Answers

Answer:

0.91

Step-by-step explanation:

Suppose we want to choose 5 objects, without replacement, from 9 distinct objects. If the order of the choices is relevant, how many ways can this be done? If the order of the choices is not relevant, how many ways can this be done?

Answers

If the order of choice is relevant, use permutation. We have to choose 5 objects in a total of 9:

[tex]9\times8\times7\times6\times5=15120\text{ ways}[/tex]

Obs: Initially we have 9 objects, you choose one, then we have 8, you choose another, then you have 7..... (this is the reasoning)

If the order of choice is not relevant, use a combination. This can be done by the equation above:

[tex]C_{9,5}=\frac{9!}{(9-5)!\times5!}[/tex][tex]C_{9,5}=\frac{9!}{4!\times5!}[/tex][tex]C_{9,5}=\frac{9\times8\times7\times6\times5!}{4!\times5!}[/tex][tex]C_{9,5}=\frac{9\times8\times7\times6}{4\times3\times2\times1}[/tex][tex]C_{9,5}=126\text{ ways}[/tex]

Obs: It is a combination of 9 elements chosen 5 by 5.

what is the equation of the line that contains point (-2, -2) and a slope of 4

Answers

Given the a point and a slope

point coordinate ( -2 , -2 )

Slope (m) = 4

Step 1: Write the formula for the point-slope equation

[tex]y-y_1=m(x-x_1)[/tex]

Step 2: Identify the x and y values

[tex]\begin{gathered} x_1=-2 \\ y_1=-2 \\ m=4 \end{gathered}[/tex]

Step 3: substitute the values in the point-slope equation formula

[tex]\begin{gathered} y-(-2)=4(x-(-2)) \\ y+2=4(x+2) \\ y+2=4x+8 \\ y=4x+8-2 \\ y=4x+6 \end{gathered}[/tex]

Hence, the equation of the line is y = 4x+6

If one third of a number is substrates from twice the number the result is 55. What is the number. ?

Answers

Let the number be x:

So intepreting the word problem into words we will have:

[tex]2x-\frac{1}{3}x=55[/tex]

Simplifying further, we will have:

[tex]\begin{gathered} \frac{5}{3}x=55 \\ \end{gathered}[/tex]

Cross multiply:

[tex]\begin{gathered} 5x=165 \\ x=\frac{165}{5} \\ x=33 \\ \text{The number is 33} \end{gathered}[/tex]

Select the correct answer.
What is the solution to the equation 41xl - 8 = -8?
O A.
O B.
O C.
O D. No solutions exist.
X=0
X = -16
x = -4 or x = 4

Answers

Answer:

A

Step-by-step explanation:

Adding 8 to both sides,

[tex]4|x|=0 \\ \\ |x|=0 \\ \\ x=0[/tex]

19. Jaylen makes the statement shown below. "When multiplying two whole numbers that end in zeros, the
product always has the exact same number of zeros at the end as the number of zeros from the end of the two
numbers combined. For example, the product of 70 x 300 has exactly three zeros at the end since 70 ends in
one zero and 300 ends in two zeros."
Which expression proves Jaylen's statement is not correct?
A. 20 x 100
B. 20 x 700
C. 50 x 600
D. 90 x 500

Answers

50 x 600= 30,000 which has more zeros than 50 and 600 combined

Evaluate the function f(x) = x² + 9x− 7 at the given values
a. f(2) b. f(x+8) c. f(-x)
b. f(x+8)
c. f(-x)

Answers

The given values the equation evaluate is:

f(2) = 15,

f(x+8) = x² + 25x + 129,

f(-x) = x² - 9x - 7

What in mathematics is a quadratic equation?

x ax2 + bx + c = 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. a 0. Since it is a second-order quadratic equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution. The solution might be straightforward or difficult.

According to the given data:

f(x) = x² + 9x− 7

a) At, f(2)

f(2) = (2)² + 9(2) - 7

f(2) = 4 + 18 - 7

f(2) = 15

b) At, f(x+8)

f(x+8) = (x + 8)² + 9(x + 8) - 7

f(x+8) = x² + 8² + 16x + 9x + 72 - 7

f(x+8) = x² + 64 + 25x + 72 - 7

f(x+8) = x² + 25x + 129

c) At,  f(-x)

f(-x) = (-x)² + 9(-x) - 7

f(-x) = x² - 9x - 7

Hence,

The given values the equation evaluate is:

f(2) = 15,

f(x+8) = x² + 25x + 129,

f(-x) = x² - 9x - 7

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Solve the following equation. Show your work.
7y = −84

Answers

Answer:

-11

Step-by-step explanation:

7y=-84

7y=-84/7 you have to divide the whole equation by 7 to get rid of the 7 in fron of the y

y=-11

Answer:

7y = -84

y = -84/7

y = -12

Final answer after checking will be the following:-

7(-12) = -84

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