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A conducting sphere of radius 10cm has an unknown charge. If the electric field 20 cm from the centre of the sphere is [tex]1.5*10^{3}[/tex] N/C and points radially inwards what is the net charge on the sphere.

Answers

Answer 1

Answer:

To find the net charge on the sphere using electric flux, we can use the formula:  

Φ = Q/ε0

Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.  

Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:

E = kQ/r^2  

Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.  

Substituting the given values, we get:  

20 = (1/4πε0)(Q)/(0.2)^2  

Solving for Q, we get:  

Q = (20)(0.2)^2(4πε0)  

Q = 0.64πε0 C  

Now, substituting this value of Q in the formula for electric flux, we get:  Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C  

Therefore, the net charge on the sphere is 0.64π C.

Related Questions

what current flows through the 75 ohm resistor in the circuit below?

Answers

The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.

How to calculate current?

The current flowing through a circuit can be calculated using the Ohm's law equation as follows;

V = IR

Where;

V = voltage (V)I = current (A)R = resistance (ohm)

According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;

9 = I × 75

I = 0.12A

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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Matter can undergo chemical reactions which feature of the components only stays the same in chemical reactions

Answers

In chemical reactions, the total mass of the components remains the same.

Chemical reactions involve the transformation of substances into new substances with different chemical properties. During these reactions, various changes occur, such as the rearrangement of atoms, the breaking and forming of chemical bonds, and the conversion of reactants into products. However, one fundamental principle that remains constant is the law of conservation of mass.

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. This means that the total mass of the reactants must be equal to the total mass of the products. No matter can be lost or gained during the reaction; it simply undergoes a rearrangement at the atomic or molecular level.

This principle holds true regardless of the complexity of the chemical reaction. Whether it involves simple reactions between two elements or complex reactions with multiple reactants and products, the total mass before and after the reaction remains constant.

This concept is vital in understanding stoichiometry, which is the quantitative relationship between reactants and products in a chemical reaction. By balancing chemical equations and applying the law of conservation of mass, scientists can determine the relative amounts of substances involved in a reaction.

Overall, while the physical and chemical properties of substances may change during a chemical reaction, the total mass of the components involved in the reaction remains constant.

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A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above. ​

Answers

1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.

5.Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA = (-2, -2, -1)

1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.

The direction vector BA is given by:

BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)

To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:

|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3

Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.

5.The position vectors of points A and B are:

Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:

BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)

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a compound having 44 total atoms consists of 11 atoms of element x and 33 atoms of element y find the % element x in the compound

A. 11%
B. 33%
C. 25%
D. 44%
E. 22%

Answers

The % element x in the compound is option c.25%.

To find the percentage of element X in the compound, we need to calculate the ratio of the number of atoms of element X to the total number of atoms in the compound and then convert it to a percentage.

Given:

Total number of atoms = 44

Number of atoms of element X = 11

To calculate the percentage, we can use the following formula:

Percentage of element X = (Number of atoms of element X / Total number of atoms) * 100

Substituting the given values, we get:

Percentage of element X = (11 / 44) * 100

Simplifying the equation, we have:

Percentage of element X = 0.25 * 100

Percentage of element X = 25%

Therefore, the percentage of element X in the compound is 25%.

The correct answer is option C. 25%.

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A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad

Answers

Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.

1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.

This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.

2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.

The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.

Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.

However, the thrust force continues to be the dominant force propelling the rocket upward.

It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.

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If an object is placed between a convex lens and its focal point, which type of image will be produced?

Answers

Blury image or some type of incorrect postural image

2. A car of mass 1000kg is being tied along the horizontal road by a rope making an angle of 30° with the horizontal. If the tension in the north rope is 200N and what is the acceleration ​

Answers

The acceleration of the car is determined as 0.35 m/s².

What is the acceleration of the car?

The acceleration of the car is calculated by applying the formula for Newton's second law of motion as follows;

F(net) = ma

where;

F(net) is the net forcem is the mass of the cara is the acceleration of the car

Fy = F sinθ

200 = F x sin(30)

F = 200 / sin(30)

F = 400 N

The tension in horizontal direction;

Fₓ = 400 N x cos(30)

Fₓ = 346.4 N

The acceleration of the car is calculated as;

a = Fₓ / m

a = 346.4 / 1000

a = 0.35 m/s²

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