Dr. Smith is interested in the relationship between nicotine and hand steadiness. Two groups participated in the experiment. One group smoked 5 cigarettes in an hour, while another group read during the same hour. Participants are then tested on the hand steadiness apparatus (yielding a score with the number of errors made). What is the independent variable

Answer:

52mtrs

Step-by-step explanation:

if length is 56meeters and the width is 4meeters less then 56 -4 = 52 so width is 52mtrs

Answer:

[tex]\frac{p-2l}{2}[/tex]

Step-by-step explanation:

move the 2l to the other side by subtracting 2l on both sides. you get P - 2l = 2w. now divide both sides by 2 to get the answer.

Answer: y= -3/7x + 3

Step-by-step explanation:

I used some graph paper for this, mark the two points and use a ruler to connect the lines. y=-3/7x is slope, and 3 is the y intercept.

Answer:

3x + 7y -2=0

Step-by-step explanation:

Two points are given to us and we need to find the Equation of the line passing through the two points . The points are (0,3) and (7,0) . We can use here two point form of the line as ,

[tex]\implies y-y_1 = \dfrac{y_2-y_1 }{x_2-x_1} ( x - x_1) \\\\\implies y - 3 =\dfrac{3-0}{0-7}(x - 0 ) \\\\\implies y - 3 =\dfrac{-3}{7}x \\\\\implies 7y - 2 = -3x \\\\\implies \underline{\underline{3x + 7y -2 = 0 }}[/tex]

Answer:

-6

Step-by-step explanation:

V = 6x + b

 1/2 V -3 x = -3

V - 6x = -6

V - 6x  =  b

Answer:

0.88

Step-by-step explanation:

x 01234

f(x) 0.41 0.37 0.16 0.05 0.01

The mean or average is the expected value :

E(X) = Σ(x * p(x)) = (0 * 0.41) + (1 * 0.37) + (2 * 0.16) + (3 * 0.05) + (4 * 0.01)

E(X) = 0 + 0.37 + 0.32 + 0.15 + 0.04

E(X) = 0.88

3 maybe is a correct ans thxxxxxx

Answer:

i think possible the last one...

I'm not sure but i hope you get it correct!

Answer:

5 + c > -22

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Sum of 5 and c is greater than -22

↓ Identify

Sum = addition

Is greater than = inequality

Add them all together:

5 + c > -22

Step-by-step explanation:

0 is the ans my guy

dngjdjvkdkckgkdkgkskfkfkv

Answer:

(1.218 ; 1.322)

the confidence interval is appropriate

Step-by-step explanation:

The confidence interval :

Mean ± margin of error

Sample mean = 1.27

Sample standard deviation, s = 0.80

Sample size, n = 914

Since we are using tbe sample standard deviation, we use the T table ;

Margin of Error = Tcritical * s/√n

Tcritical at 95% ; df = 914 - 1 = 913

Tcritical(0.05, 913) = 1.96

Margin of Error = 1.96 * 0.80/√914 = 0.05186

Mean ± margin of error

1.27 ± 0.05186

Lower boundary = 1.27 - 0.05186 = 1.218

Upper boundary = 1.27 + 0.05186 = 1.322

(1.218 ; 1.322)

According to the central limit theorem, sample means will approach a normal distribution as the sample size increases. Hence, the confidence interval is valid, the sample size of 914 gave a critical value at 0.05 which is only marginally different from that will obtained using a normal distribution table. Hence, the confidence interval is appropriate

Answer:

Function has a minimum value

So, f(x)=0 and f(4)=-3

f(4)=-3 and f(x)=-x+4

f(4)=0

OAmalOHopeO

Step-by-step explanation:

Given: [tex]f'(x) = x^2e^{2x^3}[/tex] and [tex]f(0) = 0[/tex]

We can solve for f(x) by writing

[tex]\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx[/tex]

Let [tex]u = 2x^3[/tex]

[tex]\:\:\:\:du=6x^2dx[/tex]

Then

[tex]\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du[/tex]

[tex]\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k[/tex]

We know that f(0) = 0 so we can find the value for k:

[tex]f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}[/tex]

Therefore,

[tex]\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)[/tex]

Answer:

y + 1 = 3(x+ 1)

Step-by-step explanation:

(2,3) , (0 ,-3)

Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

         [tex]= \frac{-3-3}{0-2}\\\\=\frac{-6}{-2}\\\\= 3[/tex]

m = 3

Parallel lines have same slope.

m = 3; (-1 , -1)

y -y1 = m (x -x1)

y -[-1] = 3(x -[-1])

y + 1 = 3(x+ 1)

Answer:

D. y+1=3(x+1)

12.8, pythagorean theorem.

Answer:

B. Ray FD

Step-by-step explanation:

A common side of two angles is the side shared by the two angles. It is part of the sides that forms both angles.

The common side of <CFD and <DFE is therefore ray FD. Ray FD is part of the sides that forms <CFD and also <DFE.

Answer:

B. Ray FD

Step-by-step explanation:

A common side of two angles is the side shared by the two angles. It is part of the sides that forms both angles.

The common side of <CFD and <DFE is therefore ray FD. Ray FD is part of the sides that forms <CFD and also <DFE.

9514 1404 393

Answer:

  (c)

Step-by-step explanation:

  [tex]\displaystyle\sqrt[3]{xy^5}\sqrt[3]{x^7y^{17}}=\sqrt[3]{x^{1+7}y^{5+17}}=\sqrt[3]{x^6x^2y^{21}y}=\sqrt[3]{x^6y^{21}}\sqrt[3]{x^2y}\\\\=\boxed{x^2y^7\sqrt[3]{x^2y}}[/tex]

Answer:

the domain of given f is (-2,4)

Answer:

D: {-20, -13, 1, 6}

R: {-20, -8, 11, 13}

Step-by-step explanation:

Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.

Therefore:

Domain: {-20, -13, 1, 6}

Range: {-20, -8, 11, 13}

Answer:

Volume = 18 cm^3

Surface Area = 58 cm^2

Step-by-step explanation:

Find the volume with the formula V=w*h*l

W= width

H = height

L = length

W= 2cm

H= 1 cm

L= 9 cm

V= w*h*l

V= 2cm * 1 cm * 9cm

V= 18 cm^3

Find the surface area with the formula A= 2(w*l + h*l + h* w)

W= width

H = height

L = length

W= 2cm

H= 1 cm

L= 9 cm

A= 2(w*l + h*l + h* w)

A= 2(2cm*9cm + 1cm*9cm + 1cm* 2cm)

A= 2(29cm)

A= 58cm^2

Answer:

9ab+3a

Step-by-step explanation:

(2a+a)(3b+1)=(3a)(3b+1)

3a(3b+1)

=(3a×3b)+3a×1

=9ab+3a

To find the simple interest we'll plug it into one of the two available formulas. I will use both formulas so you can determine which is easiest for you, for future problems.

                                     r = I/Pt         or     I = Prt

                                     (the / represents division)

Let's define and plug.

r = the rate (we'll be solving for r)

I = the total interest earned within the time frame ($2)

P= the principal amount ($100)

t = the total time the principal accrued interest. (6 months/ .5years)

**Because this is in a monthly basis, lets change it into a year to make it easier**

we'll just divide 6 months by 12 months.

6 ÷ 12 = 0.5 years

============================================================

Let's use the first formula first. r = I / Pt

r = 2 / 100 (0.5)

100 x 0.5 = 50

We're now left with:            r = 2 / 50

Divide what we have left.

2 ÷ 50 = 0.04

This is our simple interest but we have to convert it into a percentage. To convert the decimal to the percentage, we'll move the decimal two places to the right to  make 4.0.

Therefore, our simple interest would be 4%

==========================================================

let's set up the second formula:  I = Prt

2 = 100 (r) (0.5)

2 = 50 (r)

2 ÷ 50 = 0.04

0.04 in percentage = 4%

Answer:

Step-by-step explanation:

correct me if I am wrong

Answer:

The farmer should plant 14 additional trees, for maximum yield.

Step-by-step explanation:

Given

[tex]Trees = 24[/tex]

[tex]Yield = 104[/tex]

[tex]x \to additional\ trees[/tex]

So, we have:

[tex]Trees = 24 + x[/tex]

[tex]Yield = 104 - 2x[/tex]

Required

The additional trees to be planted for maximum yield

The function is:

[tex]f(x) = Trees * Yield[/tex]

[tex]f(x) = (24 + x) * (104 - 2x)[/tex]

Open bracket

[tex]f(x) = 24 * 104 + 104x - 24 * 2x - x * 2x[/tex]

[tex]f(x) = 2796 + 104x - 48x - 2x^2[/tex]

[tex]f(x) = 2796 + 56x - 2x^2[/tex]

Rewrite as:

[tex]f(x) = - 2x^2 + 56x + 2796[/tex]

Differentiate

[tex]f'(x) = -4x + 56[/tex]

Equate [tex]f'(x) = -4x + 56[/tex] to 0 and solve for x to get the maximum of x

[tex]-4x + 56 = 0[/tex]

[tex]-4x =- 56[/tex]

Divide by -4

[tex]x =14[/tex]

The farmer should plant 14 additional trees, for maximum yield.

Answer:

[tex]\frac{851}{1000}[/tex]

Step-by-step explanation:

First, we can simply multiply that number by 1000, and divide again by 1000 to get a base fraction:

[tex].851\\\\= \frac{1000}{1000} \times .851\\\\= \frac{1000 \times .851}{1000}\\\\= \frac{851}{1000}[/tex]

851 is a secondary prime, having only two factors, both of which are prime.  Those factors are 23 and 37, neither of which is a factor of 1000, so this is already in simplest form.

Answer:

3x + 21

Step-by-step explanation:

(3)(x+7)

Now, we distribute the 3 in each term of (x+7)

So, 3*x = 3x and 3*7 = 21.

So our resulting term would be 3x+21.

Answer:

n= -10

Step-by-step explanation:

-20+n=1+2n which simplifies to -21n+n=2n which simplifies to -20n=2n which simplifies to

n= -10

hiiksbsjxbxjsoahwjsissnsks

Answer:

3.82

Step-by-step explanation:

[tex]\sqrt{(9+\sqrt{32}) }[/tex] Do not confirm the answer unless your equation looks like that?

[tex]\sqrt{(9+\sqrt{32}) }[/tex] Start by the [tex]\sqrt{32}[/tex]

[tex]\sqrt{(9+5.65) }[/tex] Now add (9 + 5.65)

[tex]\sqrt{14.65}[/tex]         Finally Simplify

[tex]3.82[/tex]              Final answer

=================================================

Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

(x+198)/4 = 80

x+198 = 4*80

x+198 = 320

x = 320 - 198

x = 122

So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

Answer:

b

Step-by-step explanation: