Draw an area model to represent 4x^2+12x+9 = (2x+3)^2. Label the length and width of the whole square and label each individual small square and rectangle.

The linear equation y = -x+45 models the scenario.

Solving the linear equation, it exists found that Hans will paint 16 snapdragons.

Since the rate of change exists always the exact, this question exists modeled by a linear equation.

Linear equation: y = mx + b

Where, m exists the slope and b exists the y-intercept.

To find the slope, we have to get two points (x, y), and the slope exists  given by the change in y divided by the change in x.

Points: (11, 34) and (12, 33).

Change in y: 33 - 34 = -1

Change in x: 12 - 11 = 1.

Slope: m = -1/1 = -1

The equation of the line exists y = -x + b

Replacing one of the points, the y-intercept can be found.

Point (11, 34) means that when x = 1, y = 34.

y = -x + b

34 = -1+b

b = 45

Therefore, the equation y = -x+45 models the scenario.

29 daisies mean that y = 29, we have to estimate the value of x for which y = 29.

y = -x+45

simplifying the equation,

29 = -x+45

x = 45 - 29 = 16

The value of x = 16

Therefore, Hans will plant 16 snapdragons.

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Answer:

The equation ✔ x = 45 – y models the scenario.

Hans will plant✔ 16 snapdragons

Step-by-step explanation:

Answer:

Option C: x = 6

Step-by-step explanation:

Hi There!

7 + 5 (x - 3) = 22

=> 7 + 5x - 15 = 22

=> 5x = 22 - 7 + 15

=> 5x = 30

=> x = 30/5

=> x = 6

x = 6 makes the statement true.

Thank you,

Eddie

Answer: -4, -3, -2

Step-by-step explanation:

By inspection, we know [tex]x=-2[/tex] is a root.

We can thus rewrite the equation as

[tex](x+2)\left(\frac{x^3 + 9x^2 + 26x+24}{x+2} \right)=0\\\\(x+2)(x^2 + 7x+12)=0\\\\(x+2)(x+3)(x+4)=0\\\\x=-4, -3, -2[/tex]

Answer:

5 line of symmetry

Step-by-step explanation:

The account be worth in 7 months is 375.725 .

Amount (A) is the total money paid back at the end of the time period for which it was borrowed. The total amount formula in case of simple interest can also be written as: A = P(1 + RT)

Here, A = Total amount after the given time period.

Given that,

P = $350, R = 1.05%, T = 7 month

The simple interest equation uses "t" as years, but is just cycles, using an APR rate.

now, if we never mind "t" as years and just use it as an interest cycle, then we can say the rate is 1.05% and the period is 7 cycles.

A = P(1 + RT)

   = 350(1+1.05%×7)

   = 350(1+0.0105×7)

   = 350(1+0.0735)

   = 350×1.0735

A  = $375.725

Hence, The account be worth in 7 months is 375.725 .

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Answer:

[tex]x=\frac{P^2t}{(m-t^3)}[/tex]

Step-by-step explanation:

[tex]P^2=\frac{mx}{t} -t^2x\\\\P^2+t^2x=\frac{mx}{t}\\\\t(P^2+t^2x)=mx\\\\P^2t+t^3x=mx\\\\P^2t=mx -t^3x\\\\P^2t=x(m-t^3)\\\\\frac{P^2t}{(m-t^3)} =\frac{x(m-t^3)}{(m-t^3)} \\\\\frac{P^2t}{(m-t^3)}=x[/tex]

Answer:

-1

Step-by-step explanation:

Since we have the linear equation, 2x-5, and it's increasing since the slope is positive, that means we want the maximum x-value, to find the maximum y-value, or possible value.

This means, we want to find the maximum x-value of 2x+5 that is less than or equal to 9, and since we want the maximum x-value, we want the right side to also be the maximum, and since we have a less than or equal to symbol, we can have the equation equal to 9, which is the make value. So we get the following equation

[tex]2x+5=9\\[/tex]

Subtract 9 from both sides

[tex]2x=4[/tex]

Divide both sides by 2

[tex]x=2[/tex]

This is the maximum x-value we can get from the inequality, and now we plug this into the equation 2x-5

[tex]2(2)-5[/tex]

4-1

-1

So the maximum value is -1

Answer:

First we write y and its derivatives as power series:

y=∑n=0∞anxn⟹y′=∑n=1∞nanxn−1⟹y′′=∑n=2∞n(n−1)anxn−2

Next, plug into differential equation:

(x+2)y′′+xy′−y=0

(x+2)∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

x∑n=2∞n(n−1)anxn−2+2∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

Move constants inside of summations:

∑n=2∞x⋅n(n−1)anxn−2+∑n=2∞2⋅n(n−1)anxn−2+∑n=1∞x⋅nanxn−1−∑n=0∞anxn=0

∑n=2∞n(n−1)anxn−1+∑n=2∞2n(n−1)anxn−2+∑n=1∞nanxn−∑n=0∞anxn=0

Change limits so that the exponents for  x  are the same in each summation:

∑n=1∞(n+1)nan+1xn+∑n=0∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−∑n=0∞anxn=0

Pull out any terms from sums, so that each sum starts at same lower limit  (n=1)

∑n=1∞(n+1)nan+1xn+4a2+∑n=1∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−a0−∑n=1∞anxn=0

Combine all sums into a single sum:

4a2−a0+∑n=1∞(2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an)xn=0

Now we must set each coefficient, including constant term  =0 :

4a2−a0=0⟹4a2=a0

2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an=0

We would usually let  a0  and  a1  be arbitrary constants. Then all other constants can be expressed in terms of these two constants, giving us two linearly independent solutions. However, since  a0=4a2 , I’ll choose  a1  and  a2  as the two arbitrary constants. We can still express all other constants in terms of  a1  and/or  a2 .

an+2=−(n+1)nan+1+(n−1)an2(n+2)(n+1)

a3=−(2⋅1)a2+0a12(3⋅2)=−16a2=−13!a2

a4=−(3⋅2)a3+1a22(4⋅3)=0=04!a2

a5=−(4⋅3)a4+2a32(5⋅4)=15!a2

a6=−(5⋅4)a5+3a42(6⋅5)=−26!a2

We see a pattern emerging here:

an=(−1)(n+1)n−4n!a2

This can be proven by mathematical induction. In fact, this is true for all  n≥0 , except for  n=1 , since  a1  is an arbitrary constant independent of  a0  (and therefore independent of  a2 ).

Plugging back into original power series for  y , we get:

y=a0+a1x+a2x2+a3x3+a4x4+a5x5+⋯

y=4a2+a1x+a2x2−13!a2x3+04!a2x4+15!a2x5−⋯

y=a1x+a2(4+x2−13!x3+04!x4+15!x5−⋯)

Notice that the expression following constant  a2  is  =4+  a power series (starting at  n=2 ). However, if we had the appropriate  x -term, we would have a power series starting at  n=0 . Since the other independent solution is simply  y1=x,  then we can let  a1=c1−3c2,   a2=c2 , and we get:

y=(c1−3c2)x+c2(4+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(4−3x+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(−0−40!+0−31!x−2−42!x2+3−43!x3−4−44!x4+5−45!x5−⋯)

y=c1x+c2∑n=0∞(−1)n+1n−4n!xn

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Answer:

-2.25

Step-by-step explanation:

Engine is currently in first gear as mentioned in question

Drive shaft speed be x

Answer:

700 rpm

Step-by-step explanation:

A driveshaft is a shaft that transmits mechanical power.

Its speed is measured in rpm (revolutions per minute).

Engine speed

Given engine speed:

Therefore, the drive-shaft speeds in the different gears are:

First gear

Drive-shaft speed = 2100 ÷ 3 = 700 rpm

Second gear

Drive-shaft speed = 2100 ÷ 1.6 = 1312.5 rpm

Third gear

Drive-shaft speed = 2100 rpm

The area of a circle with a circumference that equals the perimeter of the square is 9.62 units².

What is circle ?

the side measurements of the square is 2.75 units.

the perimeter of this square, we must multiply 2.75 by 4 because a square has four equal side measurements.

2.75 × 4 = 11

Let's use the formula for finding radius given the circumference.

[tex]Radius = \frac{circumference}{2\pi }[/tex]

the circumference because our circumference is 11 units.

Radius = [tex]\frac{11}{2pi }[/tex]

put π = 3.14 * 2

radius =  11 / 2 * 3.14

radius = 11/  6.28 ⇒ 1.75

the area of the circle = [tex]\pi r^{2}[/tex]

area = 3.14 * (1.75)²  ⇒9.61325

Lastly, we round this number to the nearest hundredth as it is asked of us in the problem.

9.61325 = 9. 62

Therefore, the area of the circle is 9.62 units².

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Answer:296 m

I’m assuming “breadth” is width and garderean is just the park.

(25+25+12+12) times 4.

A is never defined

Answer:

Step-by-step explanation:

Solution

There are 36 possible ways to combine two dice. The ones you are interested in, are in the table below

Numbers less that 5 are   with their probabilities

Number    Probability    How done.

2                   1/36           1 + 1

3                   2/36          2 + 1      1 + 2

4                   3/36           2 + 2     1 +3    3 + 1

Total             6/36           1/6

Greater than 7

Number        Probability  How done

8                    5/36           6+2    2+6   5 +3    3+5     4 + 4

9                    4/36            6+3     3 + 6     5+4    4+ 5  

10                   3/36            6+4    4 +6      5 + 5

11                    2/36             5+6      6 + 5

12                   1 /36             6 + 6

Total              15/36            

Answer

15/36 + 1/6 = 15/36 + 6/36 = 21/36

Final Answer: 7/12

Answer:

The ribbon is 5m long.

The length of the piece = 3 ^ 4 / 5 m.

The length of the remaining piece.

We can simply solve this mathematical problem by using the following mathematical process.

First of all, we have to convert the length of the cut piece into simple decimal value.

Length of cut piece =3^ 4 / 5 = (3 * 5 + 4) / 5 = 19/5 = 3.8m

Length of the remaining ribbon = Intital length cut length = 5 - 3.8 = 1.2m = 12/10 - m = 6/5 * m = 1 1/5 m

Answer: 1 1/5

Step-by-step explanation:

5 - 3 = 2 - 4/5 = 1 1/5

Answer: they can buy about 8 dvds

Step-by-step explanation:

this is because 30 + 66 = 96 and if you do 96 divided by 12 it gives you 8

Answer:

C

Step-by-step explanation:

Express functions as a ratio: put one in the numerator and the other in the denominator

[tex]\frac{12- \frac{2}{3}t}{3-\frac{1}{8}t }[/tex]

We want to get rid of the fractions which would mean multiplying top and bottom by 3 and 8. (Remember to multiply both terms). The answer would result in C.

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

Step-by-step explanation:

I am not sure I can read the original expression right, the picture is too blurry for the small digits.

is it 3^(5/5) ?

or rather 3^(5/6) ?

in any case, you should know that a number written like this always has the structure

a^(b/c)

so,

a = 3

b = 5 (or whatever is the numerator or top of the fraction)

c = 5 (or whatever is the denominator or bottom of the fraction).

the denominator of a fraction in an exponent gives us the grade of root to be taken.

the numerator gives us the power of the base number.

and if the exponent is negative it would mean that the whole thing is a 1/... fraction.

like 3^-2 means 1/3².

Answer:

CotO

Step-by-step explanation:

The process is int the picture

Step-by-step explanation:

25 as binary number is

11001

1×2⁴ + 1×2³ + 0×2² + 0×2¹ + 1×2⁰ = 16 + 8 + 1 = 25

25×2 = 50 = 11001 × 2 = 110010

multiplying a binary number by 2 is the save effect as multiplying a normal decimal number by 10 : all digits move one position to the left, and a 0 is put into the empty right position.

and so, we see

110P = 110010

P = 010

FYI : you normally don't mix binary and decimal numbers. if one of the numbers is binary, then all the others have to be binary too.

so, the problem should have looked like

110P/10 = 11001

110P = 11001×10 = 110010

P = 010

Answer:

01

Step-by-step explanation:

From decimal to binary;

25/2==> 1 (remainder)

12/2===>0

6/2==>0

3/2===>1

1

=11001

Checking the answer;

11001

=1*2^4+1*2^3+0*2*2+0*1+1*2^0

=1*16+1*8+0+0+1*1

=16+8+0+0+2

=25

Answer:

x = 12

Step-by-step explanation:

sqrt(x+4) - 3 = 1

First get the sqrt all by itself on one side of the equation. Add 3 to both sides of the equation.

sqrt(x+4) = 1 + 3

sqrt(x+4) = 4

To "fix" the sqrt, that is, "undo it" and get rid of it, you have to SQUARE both sides of the equation.

(sqrt(x+4))^2 = 4^2

x + 4 = 16

subtract 4 to finish up.

x = 12

Check:

sqrt(12 + 4) - 3 = 1

sqrt16 - 3 = 1

4 - 3 = 1

1 = 1 Check!

Check the picture below.

so the lateral area of the pyramid is really just the area of four triangles whose base is 10 and height is also 10, now, we're excluding the bottom because that's not lateral area.

[tex]\stackrel{\textit{area of four triangles}}{4\left[\cfrac{1}{2}(\stackrel{b}{10})(\stackrel{h}{10}) \right]}\implies 2(100)\implies \text{\LARGE 200}~ft^2[/tex]

Answer:5.50 a hour

Step-by-step explanation:

Answer:

68.54

Step-by-step explanation:

w + (w – 12 ÷ 22 • 3) • 7

10 + (10 – 12 ÷ 22 • 3) • 7

Parentheses first

(10 – 12 ÷ 22 • 3)

(10 – 36 ÷ 22)

(10 – 1.636)

(8.364)

-------

10 + (8.364) • 7

10 + 58.54

68.54

The value of the expression will be equal to 66.54. The correct option is  B.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the expression is w + (w – 12 ÷ 2^ 2• 3) • 7 and the value of w is 10.

By substituting the value of w equal to 10 the value of the expression is,

E = w + (w – 12 ÷ 22 • 3) • 7

E = 10 + (10 – 12 ÷ 22 • 3) • 7

Solve the Parentheses first.

P = (10 – 12 ÷ 22 • 3)

P = (10 – 36 ÷ 22)

P = (10 – 1.636)

P = (8.364)

Solve further to get the final value.

E = 10 + (8.364) • 7

E = 10 + 56.54

E = 66.54.

Therefore, the value of the expression will be equal to 66.54.

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Answer:

n=2

Step-by-step explanation:

Create an equation.

9n=18

Divide 9 from both sides.

9n/9=18/9

n=2

Hope this helps!

Applying properties of exponents, the quotient is given as follows:

[tex]2\sqrt[3]{3} - \sqrt[3]{18}[/tex]

The expression is given by:

[tex]\frac{6 - 3\sqrt[3]{6}}{\sqrt[3]{9}}[/tex]

The 3 can be inserted into the cube root, as follows:

[tex]\frac{6 - 3\sqrt[3]{6}}{\sqrt[3]{9}} = \frac{6 - \sqrt[3]{6 \times 3³}}{\sqrt[3]{9}}[/tex]

Applying the subtraction, we have that the expression is:

[tex]\frac{6}{\sqrt[3]{9}} - \frac{\sqrt[3]{162}}{\sqrt[3]{9}} = \frac{6}{\sqrt[3]{9}} - \sqrt[3]{\frac{162}{9}} = \frac{6}{\sqrt[3]{9}} - \sqrt[3]{18}[/tex]

The denominator can be simplified as follows:

[tex]\sqrt[3]{9} = \sqrt[3]{3^2} = 3^{\frac{2}{3}}[/tex]

Then:

[tex]\frac{6}{\sqrt[3]{9}} = \frac{2 \times 3}{3^{\frac{2}{3}}} = 2 \times 3^{1 - \frac{2}{3}} = 2 \times 3^{\frac{1}{3}} = 2\sqrt[3]{3}[/tex]

Hence the quotient is given by:

[tex]2\sqrt[3]{3} - \sqrt[3]{18}[/tex]

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the expression is simplified to give - 39

Given the expression;

= 24- 4 to the power of 2 x 3+15

= 24 - (4^2 × 3 ) + 15

First, expand the bracket

= 24 - ( 16 × 3) + 15

Find the product of the bracket

= 24 - 48 + 15

From our knowledge of BODMAS, we add before we subtract

Now, let's add first

= 24 - 63

The, subtract

= - 39

The expression is simplified to - 39

Thus, the expression is simplified to give - 39

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