Answers
See the attached image.
Related Questions
To answer this question, you may need access to the periodic table of elements.
How many bonding electrons are in the Lewis structure of NH₃?
a.) 6
b.) 2
c.) 5
d.) 4
Answers
Answer:
6 bonding electrons are needed.
What is the amount of energy required to raise the temperature of 150 grams of aluminum by 10°C?
Group of answer choices
A. 13.45 J
B. 0.897 J
C. 1345.5 J
D. 4.18 J
Answers
Answer:
C.) 1345.5 J
Explanation:
To find the energy, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy (J)
-----> m = mass (g)
-----> c = specific heat (J/g°C)
-----> ΔT = change in temperature (°C)
The specific heat of aluminum is 0.89 J/g°C. You can plug the given values into the equation and solve.
Q = mcΔT
Q = (150 g)(0.89 J/g°C)(10 °C)
Q = 1335
*It is up to you whether you wish to trust this answer. My answer may be slightly different due to using a different specific heat.
the quantity PV/T must be held constant and both P and V are doubled, the value of T will necessarily have to,
Answers
Since we double both P and V in the numerator, the denominator (T) has to be doubled twice, or quadrupled (multiplied by 4)
Example:
P1 = 5
V1 = 2
T1 = 10
5*2/10 = 1
P2 = 5*2 = 10
V2 = 2*2 = 4
T2 = 10*4 = 40
10*4/40 = 40
Find the amount of heat energy needed to convert 400 grams of ice at -38°C to steam at 160°C.
Group of answer choices
A. 246840 Joules
B. 159984 Joules
C. 331056 Joules
D. 1284440 Joules
Answers
The amount of heat energy needed to convert 400 g of ice at -38 °C to steam at 160 °C is 1.28×10⁶ J (Option D)
How to determine the heat required change the temperature from –38 °C to 0 °C Mass (M) = 400 g = 400 / 1000 = 0.4 KgInitial temperature (T₁) = –25 °C Final temperature (T₂) = 0 °Change in temperature (ΔT) = 0 – (–38) = 38 °C Specific heat capacity (C) = 2050 J/(kg·°C)Heat (Q₁) =?Q = MCΔT
Q₁ = 0.4 × 2050 × 38
Q₁ = 31160 J
How to determine the heat required to melt the ice at 0 °CMass (m) = 0.4 KgLatent heat of fusion (L) = 334 KJ/Kg = 334 × 1000 = 334000 J/KgHeat (Q₂) =?Q = mL
Q₂ = 0.4 × 334000
Q₂ = 133600 J
How to determine the heat required to change the temperature from 0 °C to 100 °C Mass (M) = 0.4 KgInitial temperature (T₁) = 0 °C Final temperature (T₂) = 100 °CChange in temperature (ΔT) = 100 – 0 = 100 °C Specific heat capacity (C) = 4180 J/(kg·°C)Heat (Q₃) =?Q = MCΔT
Q₃ = 0.4 × 4180 × 100
Q₃ = 167200 J
How to determine the heat required to vaporize the water at 100 °CMass (m) = 0.4 KgLatent heat of vaporisation (Hv) = 2260 KJ/Kg = 2260 × 1000 = 2260000 J/KgHeat (Q₄) =?Q = mHv
Q₄ = 0.4 × 2260000
Q₄ = 904000 J
How to determine the heat required to change the temperature from 100 °C to 160 °C Mass (M) = 0.4 KgInitial temperature (T₁) = 100 °C Final temperature (T₂) = 160 °CChange in temperature (ΔT) = 160 – 100 = 60 °C Specific heat capacity (C) = 1996 J/(kg·°C) Heat (Q₅) =?Q = MCΔT
Q₅ = 0.4 × 1996 × 60
Q₅ = 47904 J
How to determine the heat required to change the temperature from –38 °C to 160 °CHeat for –38 °C to 0°C (Q₁) = 31160 JHeat for melting (Q₂) = 133600 JHeat for 0 °C to 100 °C (Q₃) = 167200 JHeat for vaporization (Q₄) = 904000 JHeat for 100 °C to 160 °C (Q₅) = 47904 JHeat for –38 °C to 160 °C (Qₜ) =?Qₜ = Q₁ + Q₂ + Q₃ + Q₄ + Q₅
Qₜ = 31160 + 133600 + 167200 + 904000 + 47904
Qₜ = 1.28×10⁶ J
Learn more about heat transfer:
https://brainly.com/question/10286596
#SPJ1
Given the reaction:
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution:
Group of answer choices
A. No changes in color occur
B. The solution turns darker red
C. The solution becomes colorless
D. The solution becomes more yellow
Answers
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution the solution turns darker red
While precipitating out Fe3+ (as Fe(OH)3) or SCN- (as AgSCN) will push the equilibrium to the left, consuming the complex and reducing color intensity, the addition of Fe3+ or SCN- will push the equilibrium to the right, creating more complex and intensifying the color.
The pace of reaction rises as Fe3+ levels rise. The concentration of SCN reduces as the rate rises.
The FeSCN2+ complex, which is created when iron(III) and thiocyanate ions react, displays an extremely strong blood red color (or orange in diluted solution), making it simple to detect and quantify using spectrophotometry.
To learn more about Fe3+ and SCN reaction please visit -
https://brainly.com/question/14575042
#SPJ1
What is an expression of Boyle's law (k = constant)?
A. V/T=K
B. V = kn
C. PV = k
D. Ptotal= P₁ + P₂ + P3 + &
Answers
Answer:
C.) PV = k
Explanation:
Boyle's Law is a variation of the Ideal Gas Law when all variables, except for pressure and volume, are held constant.
Pressure is represented by "P" and volume is represented by "V". In the Ideal Gas Law, pressure and volume are inversely proportional (if one goes up, the other goes down). That being said, the equation which best represents Boyle's Law is PV = k.
Determine which substance in the following pair has the greater tendency to be oxidized.
Li or K
Answers
Potassium (K) has the greater tendency to be oxidized when compared to Lithium (Li).
What is oxidation?Oxidation is a chemical process triggered by the reaction between an compound and an oxidizing agent. The agent is what gains electrons and undergoes reduction, causing what is called oxidation.
With that being said, as you go down the alkali metal group, the ionisation energy decreases. The tendency of an atom to give its electron (or get oxidised) increases. Therefore, potassium oxidises more easily than lithium or in other words, potassium has a lesser tendency to get reduced compared to lithium.
As lithium has a higher tendency to get reduced than potassium, lithium gets deposited instead of potassium.
See more about oxidation at: brainly.com/question/9496279
#SPJ1
H2O Is water. H10O5 Is Monohydrate trihydrate. What Is the chemical compound name for H50O25?
Answers
Answer:
THERE IS NO such compound
Explanation:
help! awarding 20 points
Answers
a. The circulatory system in fish is one-directional while it is two-directional in humans.
b. P has a high concentration of carbon dioxide and low oxygen concentration whereas Q has high oxygen concentration and low carbon dioxide concentration.
What is the circulatory system?The circulatory system is the system of organism and tissues which help to transport blood and other fluids through the body of a living organism.
The organs of the circulatory system include:
The heartThe blood vessels - veins, arteries, capillariesa. In the given diagram sowing the circulatory system of man and the fish, it can be seen that the direction of blood flow in the fish is one way through the heart. However, in humans, the direction of blood flow is two-way through the heart.
b. The gas in P has a high concentration of carbon dioxide and low oxygen concentration. However, the gas flowing through Q has high oxygen concentration and low carbon dioxide concentration.
In conclusion, the circulatory system is important in the exchange of gases in the body.
Learn more about circulatory system at: https://brainly.com/question/3597250
#SPJ1
The amount of heat transferred from an object depends on
Group of answer choices
A. The initial temperature of the object
B. All of the above
C. The specific heat of the object
D. The mass of the object
Answers
The amount of heat transferred from an object depends on the following;
The initial temperature of the object
The specific heat of the object
The mass of the object
Therefore, the answer is all of the above (option B).
What is heat?
Heat is the internal energy of a system in thermodynamic equilibrium due to its temperature.
The amount of heat absorbed or released by an object can be calculated using the following expression:
Q = m × c × ∆T
Where;
Q = quantity of heat
m = mass of object
c = specific heat capacity of object
∆T = change in temperature
Therefore, this suggests that amount of heat transferred from an object depends on the following;
The initial temperature of the object
The specific heat of the object
The mass of the object
Learn more about heat at:
#SPJ1
Which of the following chemical equations depicts a balanced chemical reaction?
A. 2H₂ +202-> H₂O
B. 2H₂ +202-> 2H₂O
C. H₂ + O2-> H₂O
D. 2H₂ + O₂-> 2H₂O
Answers
Answer:
D.) 2 H₂ + O₂ -----> 2 H₂O
Explanation:
An equation is balanced when there is an equal amount of each element on both sides of the reaction. If these amounts are unequal, coefficients can be added to modify the amount of particular molecules.
A.) Not balanced
2 H₂ + 2 O₂ -----> H₂O
Reactants: 4 hydrogen, 4 oxygen
Products: 2 hydrogen, 1 oxygen
B.) Not balanced
2 H₂ + 2 O₂ -----> 2 H₂O
Reactants: 4 hydrogen, 4 oxygen
Products: 4 hydrogen, 2 oxygen
C.) Not balanced
H₂ + O₂ -----> H₂O
Reactants: 2 hydrogen, 2 oxygen
Products: 2 hydrogen, 1 oxygen
D.) Balanced
2 H₂ + O₂ -----> 2 H₂O
Reactants: 4 hydrogen, 2 oxygen
Products: 4 hydrogen, 2 oxygen
1. Calculate the average atomic mass of rubidium. Rubidium has two isotopes, 85Rb and 87Rb. 85Rb has an atomic mass of 84.912 amu and occurs at an abundance of 72.17%. 87Rb has an atomic mass of 86.909 amu and occurs at an abundance of 27.83%. Show your work
Answers
What is the element that is located in the 2nd Period and a Halogen?
Group of answer choices
A. Oxygen
B. Nitrogen
C. Flourine
D. Chlorine
Answers
Answer:
C.) Fluorine
Explanation:
A period describes a row on the periodic table.
Halogens are located in the 17th column on the periodic table.
As such, the element located in the second row in the 17th column is fluorine.
Mercury-197 has a half-life of 3 days. Starting
with 300 grams, how much remains in 3
weeks? (Round to two places)
Answers
Answer:
2.34 gms left
Explanation:
3 weeks = 21 days = 7 half lives
300 * (1/2)^7 = 2.34 gms
if .709 j of heat is added to water and cause the temperature to go up by .036 degrees C what mass of water is present
Answers
Answer:
0.00471 grams H₂O
Explanation:
To determine the mass, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy/heat (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = temperature change (°C)
The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".
Q = 0.709 J c = 4182 J/g°C
m = ? g ΔT = 0.036 °C
Q = mcΔT <----- Equation
0.709 J = m(4182 J/g°C)(0.036 °C) <----- Insert values
0.709 J = m(150.552) <----- Multiply 4182 and 0.036
0.00471 = m <----- Divide both sides by 150.552
How many moles of HNO3 will be produced
from the reaction of 46.5 g of NO2 with excess
water in the following chemical reaction?
3 NO₂(g) + H₂O (1)→ 2 HNO3(g) + NO(g)
Answers
Answer:
0.674 moles HNO₃
Explanation:
To find the moles of HNO₃, you need to (1) convert grams NO₂ to moles NO₂ (via molar mass) and then (2) convert moles NO₂ to moles HNO₃ (via mole-to-mole ratio from equation coefficients). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (46.5 g).
Molar Mass (NO₂): 14.007 g/mol + 2(15.998 g/mol)
Molar Mass (NO₂): 46.003 g/mol
3 NO₂(g) + H₂O (l) ------> 2 HNO₃(g) + NO(g)
46.5 g NO₂ 1 mole 2 moles HNO₃
------------------- x ------------------- x -------------------------- = 0.674 moles HNO₃
46.003 g 3 moles NO₂
A student investigated the enthalpy of combustion (deltaHc) of methanol under standard conditions using the apparatus shown in the diagram. The measurements the student recorded are shown in the table. Use this information to answer the questions below.
_Clamp stand
_
_ _I__Thermometer
_ I I Beaker
_ I-----I
_ I___I Water
_ I Wick
_ -----
_ I I
_ ----- Alcohol
_ I __I
______________
Alcohol mass before burning: 80.6g
Alcohol mass after burning: 75.9g
Water heated: 100g
Methanol Mr: 32
Initial temperature of water: 21.5 C
Final temperature of water: 32.4 C
Enthalpy of combustion of 1 mole of methanol:
The student wanted to know if the value obtained in part 1 is similar to that calculated using average bond enthalpy data.
a) Using the balanced equation and the data in the table below, calculate the theoretical enthalpy of combustion.
Note: you will need to include the enthalpy of vaporisation for the liquid components which are also given.
CH3OH(l) + 1.5O2(g) → CO2(g) + 2H2O(l)
Average Bond Enthalpies KJmol-1
C-H 412
C-C 348
C-O 358
O=O 496
C=O 743
O-H 463
Enthalpy of vaporisation KJmol-1
Methanol 35
Water 41
b) Suggest some reasons as to why this value is different to the one obtained in the practical. (What are the reasons that the the theoretical and actual enthalpy changes are different)
Answers
The Molar enthalpy of combustion of methanol obtained from the practical is -31.02 kJ/mol.
The molar enthalpy of combustion from bond energies, ΔH is -543 kJ/mol
The differences in the values could be due to:
Heat losses from the calorimeter to the surroundingsInaccurate measurements of mass and temperature changesWhat is the enthalpy theoretical and actual enthalpy of combustion of methanol?The actual enthalpy of combustion of methanol is calculated from the data obtained from the laboratory work.
The enthalpy of combustion is equal to the heat energy given off from the combustion of methanol.
Quantity of heat gained by water , q = -mcθ
where:
m = massc = specific heat capacityθ = temperature changemass of water heated = 100 g
specific heat capacity of water = 4.18 J/g/°C
temperature change = 32.4°C - 21.5°C = 10.9°C
q = -(100 * 4.18 * 10.9) J
q = - 4556.2 J
moles of methanol reacted = mass/molar mass
mass of methanol = 80.6 - 75.9 = 4.7 g
molar mass of methanol = 32 g/mol
moles of methanol = 4.7/32 = 0.14687 moles
Molar enthalpy of combustion of methanol = -4556.2 J/0.14687 mole
Molar enthalpy of combustion of methanol = -31.02 kJ/mol
Calculating molar enthalpy of combustion from bond energies:
ΔH = sum of the bond energies of bonds broken - sum of the bond energies of the bonds formedSum of bond energies of bonds broken = (3 * 412) + 358 + 463 + (1.5 * 496) + 35 = 2836 kJ/mol
Sum of bond energies of bonds formed = (2 * 743) + 2(2 * 463) + 41 = 3379 kJ/mol
ΔH = 2836 kJ/mol - 3379 kJ/mol
ΔH = -543 kJ/mol
The value obtained from the practical is less than that from the bond energies
b. The possible reasons for the difference in value obtained from the practical is less than that from the bond energies include:
Heat losses from the calorimeter to the surroundingsInaccurate measurements of mass and temperature changes.In conclusion, the molar enthalpy of combustion of methanol is negative since heat is given off during the reaction.
Learn more about enthalpy and bond energies at: https://brainly.com/question/13981382
#SPJ1
Which of the following is NOT an example of a colligative property?
Group of answer choices
A. Salt is added to ice to make homemade ice cream.
B. Salt is added to roads before a snow storm.
C.Antifreeze is added to a radiator of a car.
D. Salt water dehydrates someone that drinks it.
Answers
Salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).
What are Colligative Properties?Colligative Properties make reference to physical properties associated with solute concentration instead of its intrinsical characteristics.
Some examples of colligative properties include boiling state, vapour pressure, and osmotic pressure due to the presence of ionic particles.
In conclusion, salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).
Learn more about Colligative Properties here:
https://brainly.com/question/23480761
#SPJ1
Which of the following elements has the highest electronegativity?
Group of answer choices
A. Boron
B. Nitrogen
C. Oxygen
D. Carbon
Answers
Answer:
The answer is Oxygen
The oxygen has the most electronegativity.
Consider the following reaction at 298K.
I2 (s) + 2 Cr2+ (aq) 2 I- (aq) + 2 Cr3+ (aq)
Which of the following statements are correct?
Choose all that apply.
n = 4 mol electrons
Eo cell < 0
delta G^o < 0
The reaction is reactant-favored.
K > 1
Answers
The true statements are;
ΔG < 0K > 1What are the correct statements?Now we can see that the reaction here is a redox reaction. Thus;
Eocell = cell potential = 0.54 - (-0.41) = 0.95 V
K = equilibrium constant = ?
n = number of moles of electrons = 2
ΔG = change in free energy = ?
Hence;
Eocell = 0.0592/n log K
0.95 = 0.0592/2 log K
K = 0.95 * 2/0.0592
K = 1.2 * 10^32
Now
ΔG = -nFEcell
ΔG = - (2 * 96500 * 0.95)
ΔG = -183.3kJ
Learn more about Ecell:https://brainly.com/question/3807566
#SPJ1
Why does direct titration of aspirin with NaOH have a side reaction and how to prevent it?
Answers
Direct titration of aspirin with NaOH have a side reaction simply because aspirin is a weak acid
What is direct titration?
Direct titration can simply be defined as a type of titration in which a titrant of known concentration and volume is added to a substance in order to analyze it.
As the name implies, it is called direct titration simply because the one approaches the endpoint of the experiment directly.
Furthermore, the significance of direct titration is that it is used to find the quantity of a substance within a solution with chemical reactions.
So therefore, direct titration of aspirin with NaOH have a side reaction simply because aspirin is a weak acid
Learn more about titration:
https://brainly.com/question/186765
#SPJ1
is Sn^2+ + Br2 ---> Sn^4+ + 2Br^- a spontaneous or non-spontaneous redox reaction?
Answers
Sn^2+ + Br2 ---> Sn^4+ + 2Br^- is referred to as a non-spontaneous redox reaction.
What is a Non spontaneous reaction?This type of reaction doesn't favor the formation of the product and must be endothermic.
In the reaction above under the given conditions, ΔG is positive and it is intended to form Sn(s) and Br(l) through the reduction of tin cation to make bromine liquid and tin solid. This therefore points to the direction of the reaction being non-spontaneous one.
Read more about Non spontaneous reaction here https://brainly.com/question/3754650
#SPJ1
28. What mass
0.120M HCI?
of Na₂CO3 (Molar Mass = 106.0 g/mol) is required to react completely with 21.6 mL of.
Answers
Mass of [tex]$\mathrm{Na}{2} \mathrm{CO} 3$[/tex] required [tex]$=0.55 \mathrm{~g}$[/tex]
What is meant by molar mass?The mass of one mole of a sample is its molar mass. Add the atomic masses (atomic weights) of all the atoms in the molecule to obtain the molar mass. Using the mass listed in the Periodic Table or atomic weights table, determine the atomic mass for each element.The total mass of all the atoms that make up a mole of a specific molecule, measured in grams, is known as the molar mass or molecular weight. The measurement is made in grams per mole.Molar mass is a crucial factor to consider while planning an experiment. The molar mass enables you to calculate the quantity you should weigh on your scale if you are testing theories involving precise amounts of a substance. Take a look at an experiment that needs 2 moles of pure carbon as an illustration.The mass 0.120M HCI:
Moles of [tex]$\mathrm{HCl}$[/tex]reacted [tex]$=0.120 \times 21.6 / 1000=0.00260$[/tex]
according to balanced reaction, [tex]$\mathrm{HCl}$ and $\mathrm{Na} 2 \mathrm{CO} 3$[/tex] reacts in [tex]$2: 1$[/tex] the ratio
moles of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.00260 \times 2=0.00520$[/tex]
convert moles to mass
mass [tex]$=$[/tex]moles [tex]$\times$[/tex]molar mass
mass [tex]$=0.00520 \times 106.0$[/tex]
mass [tex]$=0.55 \mathrm{~g}$[/tex]
mass of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.55 \mathrm{~g}$[/tex]
Mass 0.120M HC is [tex]$=0.55 \mathrm{~g}$[/tex]
To learn more about Molar Mass, refer to:
https://brainly.com/question/837939
#SPJ9
The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of:
Group of answer choices
A. All of the above
B. Increasing concentration to increase reaction rate
C. Increasing temperature to increase reaction rate
D. increasing surface area to increase reaction rate
Answers
Answer:
D
Explanation:
Grinding to a powder increases the surface area of the charcoal .
The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of increasing surface area to increase reaction rate. Option D is the answer.
Reason for the grindingGrinding charcoal into a fine powder enhances its reactivity by increasing surface area. This finer texture promotes more frequent collisions between charcoal particles and oxygen molecules, facilitating faster chemical reactions.
The heightened contact points enable efficient utilization of reactants, optimizing resource consumption. Shorter diffusion paths within smaller particles expedite reactant diffusion, aiding quicker reaction rates.
Additionally, the augmented surface area promotes efficient heat transfer, crucial in reactions involving temperature changes.
Grinding charcoal amplifies the reaction rate by maximizing interaction opportunities, accelerating the conversion of charcoal and oxygen into products.
Learn more on charcoal here https://brainly.com/question/1683998
#SPJ2
Which of these have the highest volume
A. - 1kg of lead
B. - 1kg of iron
C. - 1kg of gold
D. - 1kg of aluminum
Answers
Answer:
D. 1kg Aluminium
Explanation:
First of all, you have to know that you were given two quantities, volume and mass.
The relationship between both quantities is given by the formula of density which is:
Density = Mass / Volume
Volume = Mass / Density
Since mass is constant, it means that the volume is inversely proportional to the density.
Volume = k / Density where k is a constant.
This means that the substance with the lowest density would have the highest volume and the one with the highest density would have the highest lowest.
The density of the substances are given as:
Lead = 11.2
Iron = 7.874
Gold = 19.3
Aluminium = 2.7
This means that Aluminium would have the highest volume as its the least dense.
Can anyone please give me name of these disaccharides? My professor wrote these on whiteboard and didn't explain anything.
Answers
The name of the disaccharide above is sucrose
What are disaccharides?Disaccharides are substances which are composed of two molecules of simple sugars or monosaccharides linked to each other.
Below are some examples of disaccharides:
SucroseMaltoseLactoseCellobioseSo therefore, the name of the disaccharide above is sucrose
Learn more about disaccharides:
https://brainly.com/question/12921453
#SPJ1
Which of the following is NOT an example of a colligative property?
Group of answer choices
A. Salt is added to ice to make homemade ice cream.
B. Salt is added to roads before a snow storm.
C. Antifreeze is added to a radiator of a car.
D. Salt water dehydrates someone that drinks it.
Answers
D. The option that is NOT an example of a colligative property is salt water dehydrates someone that drinks it.
What is colligative property?
Colligative properties are the physical changes that result from adding solute to a solvent.
Colligative Properties depend on how many solute particles are present as well as the solvent amount, but they do NOT depend on the type of solute particles, although do depend on the type of solvent.
One important thing to note is that colligative property is going to change the melting point or the boiling point of a substance.
Thus, the option that is NOT an example of a colligative property is salt water dehydrates someone that drinks it.
The correct option is D.
Learn more about colligative property here: https://brainly.com/question/1831338
#SPJ1
The value of the entropy change for the process N₂ (g) + 3H₂ (g) --> 2NH₃ (g) is ________.
positive
unchanged
zero
negative
Answers
Answer:
negative
Explanation:
Entropy is a measure of the "disorder" in a system.
In this reaction, the amount of disorder decreases. This is because one gas molecule (NH₃) has more order than two gas molecules (N₂ and H₂). Therefore, the entropy change should be negative.
If 1.240g of carbon dioxide dissolves in 1.01L of water at 755mmHg, what quantity of carbon dioxide in grams will dissolve at 790mmHg?
Answers
Taking into account the Henry's Law, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.
Henry's LawA change in pressure does not appreciably influence the solubility of solids or liquids or liquids in liquids; however, that of gases in solvents increases when the partial pressure of the gases increases. The solubility of a gas depends on pressure and temperature.
In this way, Henry's Law describes the effect of pressure on the solubility of gases. This law states that the solubility of a gas in contact with the surface of a liquid at a given temperature is directly proportional to the partial pressure of said gas on the liquid.
Mathematically, Henry's law is expressed as:
C=k×P
Where:
P is the partial pressure of the gas.C is the concentration of the gas.k is Henry's constant, which depends on the nature of the gas, the temperature, and the liquid.At 2 different partial pressure values, the Henry's law is expressed as:
[tex]\frac{C1}{C2} =\frac{P1}{P2}[/tex]
Quantity of carbon dioxideIn this case, you know:
C₁ = [tex]\frac{1.240 g}{1.01 L}[/tex] =1.228 [tex]\frac{g}{L}[/tex]C₂ = ?P₁ = 755 mm HgP₂ = 790 mm HgReplacing in Henry's Law:
[tex]\frac{1.228\frac{g}{L} }{C2} =\frac{755 mmHg}{790mmHg}[/tex]
Solving:
[tex]1.228\frac{g}{L} =\frac{755 mmHg}{790mmHg}xC2[/tex]
C2= [tex]\frac{1.228\frac{g}{L} }{\frac{755 mmHg}{790mmHg}}[/tex]
C2= 1.285 [tex]\frac{g}{L}[/tex]
Then, the concentration of carbon dioxide at 790 mmHg is 1.285 g/L. But you have 1.01 L of water. So the amount of gas dissolved can be calculated as 1.01 L×1.285 g/L = 1.297 g
Finally, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.
Learn more about Henry's Law:
https://brainly.com/question/10655775
#SPJ1
what does it mean Emphasis on object vs woman
Answers
Emphasis on object vs woman simply means s- e- x- ual objectification
This goes to say that it emphasizes seeing women as objects of se- xu- al pleasure
What is objectification?Objectification simply refers to the act of treating or viewing a person as an object, devoid of thought or feeling.
Most of the time, objectification is targeted at women and reduces them to objects of se- xu- al pleasure
So therefore, emphasis on object vs woman simply means se- xu- al objectification
Learn more about se- xu- al objectification:
https://brainly.com/question/4231708
#SPJ1
