When two normal distributions have the same mean, but different standard deviations, the distribution with the larger standard deviation will have a wider spread, while the distribution with the smaller standard deviation will have a narrower spread.
We have,
Let's consider two normal distributions with a mean of 50.
One distribution has a standard deviation of 5, while the other has a standard deviation of 15.
The distribution with the smaller standard deviation of 5 will have the majority of the data points clustered closely around the mean of 50.
This means that there will be less variation in the data and the curve will be taller and narrower.
On the other hand,
The distribution with the larger standard deviation of 15 will have more variation in the data, resulting in a flatter and wider curve.
The data points will be more spread out, with some data points falling far away from the mean of 50.
Thus,
When two normal distributions have the same mean, but different standard deviations, the distribution with the larger standard deviation will have a wider spread, while the distribution with the smaller standard deviation will have a narrower spread.
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I need the percentage of 11
—
2
Some biologists model the number of species S in a fixed area A (such as an island) by the species-area relationship
log S = log c + k log A
where c and k are positive constants that depend on the type of species and habitat.
a. Solve the equation for S
b. Using part (a), if k = 3 and the area is doubled, then by what magnitude is the number of species increased?
When the area is doubled, the number of species increases by a magnitude of 8.
a. To solve the equation for S, we have:
log S = log c + k log A
To remove the logarithms, use the property a^(log a(x)) = x, so we have:
S = 10^(log c + k log A)
S = 10^(log c) * 10^(k log A)
Since 10^(log x) = x, we get:
S = c * A^k
b. Using part (a), if k = 3 and the area is doubled, we need to find the magnitude by which the number of species is increased:
Let A1 be the initial area and A2 be the doubled area (A2 = 2A1). Find the ratio of the number of species in A2 to the number of species in A1:
S2/S1 = (c * (2A1)^3) / (c * A1^3)
S2/S1 = (c * 8 * A1^3) / (c * A1^3)
S2/S1 = 8
So, when the area is doubled, the number of species increases by a magnitude of 8.
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the table show the lenght of coastline for the 13 states a long at atlantic cost
The arrival time will be 1:45 pm (13:45) on the day after the departure day.
To see why, we can add the travel time of 25 hours and 25 minutes to the departure time of 12:20 pm.
First, we convert 25 minutes to hours by dividing by 60:
25 minutes ÷ 60 minutes/hour = 0.42 hours
Then, we add the 25 hours and 0.42 hours to the departure time:
12:20 pm + 25 hours + 0.42 hours = 1:45 pm
So the train will arrive in Alice Springs at 1:45 pm on the day after it departs from Adelaide.
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17,500 in scientific notation
Step-by-step explanation:
in science notation 17,500 is expressed as 1.75 ×10^4
There are 3 black and 5 white balls in a box. Two balls are drawn
randomly one by one without replacement. Find the probability of both
the balls are of same colour.
Answer:5/8) * (4/7) + ( 3/8)* (2/7) = 13/28
Step-by-step explanation:
The explanation for my answer could go a bit longer but it’s pretty easy to understand the concept & a good approach to hit such questions right in few seconds. Hope it helps !!!!!!
(Remember: we always multiply for AND case & do addition for OR case)
Selection would be in 2 ways possible i.e ( WHITE AND WHITE ball “OR” BLACK AND BLACK ball ) because we have been asked to choose two balls of same color. You cant pick White & White AND Black & Black because in this way u ll end up picking 4 balls which is wrong. so we used “OR”
Now,,,,,Think it like , what is the probability of getting 1 white ball on your first selection out of all balls….???
(Most imp approach)- Don’t consider both selection only in one go !!! so just think it one by one. …..O.K!
Hopefully u too thought it = 5/8 ( i.e there are 5 white balls and you selected one from total 8 balls) ……………………………………….GOOD :)
Now, what about the next ball being white…………..is the most common mistake many could do.
Problem is we have 5 white balls & we have chosen 1 ball out from that,,,, Right?
So, there are only 7 balls left for next selection & How many are there white balls left to select now??? = 4 ( because we have already selected one, out from 5)….. :)
2. PROBABILITY OF GETTING WHITE BALL AGAIN IN SECOND CHANCE = 4/7
PROBABILITY OF GETTING BOTH WHITE = (5/8) * (4/7) (remember, getting the first ball changes the probability of another, since we wanted a white AND a white ball so we ll multiply them both )
3. Similarly, for black we have 2 scenarios, hopefully u thought =(3/8)
4. Can u tell me probability of getting another black now???? = (2/7) ( LIKE WE DID FOR WHITE BALLS)
ANSWER……Probability of getting white & white OR black & black =
= (5/8) * (4/7) + ( 3/8)* (2/7) = 13/28 (& - multiply, OR -addition )
Hope, my long explanation helped you to understand the easy approach for such questions. :)
Thanks for reading! :) have a good day :)
Which set of two variables is most likely to have a cause-and-effect relationship? A. The age of a teacher and the income of the teacher B. The height of a person and the weight of a person C. The weight of a box and the postage rate we have to pay to ship the box to California D. The make of a car and the mileage of the car
The set of variables that is most likely to have a cause-and-effect relationship is option C: the weight of a box and the postage rate we have to pay to ship the box to California.
Based on the given sets of variables, the set most likely to have a cause-and-effect relationship is:
B. The height of a person and the weight of a person
This is because there is a general correlation between a person's height and their weight, as taller individuals tend to have higher weights. While this is not an absolute rule, there is a stronger cause-and-effect relationship in this set compared to the other options.
This is because the weight of the box is a likely cause of the postage rate, as the heavier the box, the more postage we will have to pay to ship it. In options A and B, there may be a correlation between the variables, but it is less likely that there is a direct cause-and-effect relationship. In option D, the make of a car is not a likely cause of its mileage, as there are many other factors that can affect a car's mileage.
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Consider the logistic differential equation:
dy/dx = y/8(6 - y)
Let f(t) be the particular solution to the differential equationwith f(0) = 8
a. What is the limiting factor?
b. Use Euler's method, starting at t=0 with two steps of equalsize, to appropriate F(1).
c. What is the range of f for t > 0
Expert
a. To determine the limiting factor, we need to find the values of y when dy/dx = 0. Setting dy/dx = 0, we have:
y/8(6 - y) = 0
This equation is satisfied when y = 0 or y = 6. Thus, the limiting factors are 0 and 6.
b. Using Euler's method, we can approximate f(1) as follows:
We are given f(0) = 8, so we start with x0 = 0 and y0 = 8. Let h be the step size, which is the same for both steps. Then:
x1 = 0 + h = h
y1 = 8 + h(dy/dx)x0,y0 = 8 + h(f(0)/8(6 - f(0))) = 8 + h(f(0)/40 - f(0)^2/320)
Using f(0) = 8 and h = 1/2, we get:
x1 = 1/2
y1 = 8 + (1/2)(8/40 - 8^2/320) = 8 + 1/10 - 2 = 6.8
Using these values, we can repeat the process to find an approximate value of f(1):
x2 = 1/2 + h = 1
y2 = 6.8 + (1/2)(6.8/40 - 6.8^2/320) = 6.8 + 0.017 - 0.578 = 6.239
Therefore, an approximate value of f(1) using Euler's method with two steps of equal size is 6.239.
c. To determine the range of f for t > 0, we need to analyze the behavior of the logistic equation. The equation has two equilibrium points, y = 0 and y = 6, which are stable and unstable, respectively. This means that solutions starting below y = 6 will approach 0 as t increases, while solutions starting above y = 6 will increase without bound.
Since f(0) = 8 is above the unstable equilibrium point, we expect f(t) to increase without bound as t increases. Therefore, the range of f for t > 0 is (6, ∞).
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the angle of a body segment with respect to a fixed line of reference is known as a
The angle of a body segment with respect to a fixed line of reference is known as a "relative angle."
The angle of a body segment with respect to a fixed line of reference is known as a reference angle. This angle is measured between the segment and the reference line, and is used to determine the position and orientation of the segment relative to other parts of the body or external objects. The segment itself refers to a specific part of the body, such as an arm, leg, or torso, that is bounded by two or more joints or points of attachment. By measuring the reference angle of a segment, it is possible to quantify the degree of movement or displacement of that segment, and to track changes in its position over time.
In this context, the angle represents the measurement of the difference in orientation between the body segment and the reference line, while the segment refers to a specific part of the body, such as an arm or leg. The reference line serves as a fixed point for comparison, allowing you to determine the position or orientation of the body segment in relation to it.
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Write an expression to represent: 6 less than the product of 4 and x
Answer:
4x-6
Step-by-step explanation:
when it ask for less than, we are subtracting. subtract 6 from 4x and you have your expression.
have a great day and thx for your inquiry :)
What are the values of a and b in the relative frequency table for the survey results? round answers to the nearest percent. a = 40%, b = 4% a = 41%, b = 3% a = 47%, b = 3% a = 41%, b = 19%
This means that the remaining categories must add up to 40%.
A relative frequency table shows the proportion or percentage of observations that fall into each category. The sum of all the relative frequencies in the table should add up to 1 or 100%.
If a is 40% and b is 4%, the total relative frequency is:
a + b = 40% + 4% = 44%
Since the relative frequencies should add up to 100%, we know that the remaining categories must add up to 56%. Without more information about the survey results, we can't determine what those other categories are.
Similarly, if a is 41% and b is 3%, the total relative frequency is:
a + b = 41% + 3% = 44%
Again, the remaining categories must add up to 56%.
If a is 47% and b is 3%, the total relative frequency is:
a + b = 47% + 3% = 50%
This means that the remaining categories must add up to 50%.
If a is 41% and b is 19%, the total relative frequency is:
a + b = 41% + 19% = 60%
This means that the remaining categories must add up to 40%.
Without more information about the survey results or the other categories in the table, we can't determine which of these values for a and b is correct.
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What is the value of x? Round your answer to the nearest tenth as needed
Answer:
If two secant segments intersect outside a circle, then the product of one secant segment with its external portion equals the product of the other secant segment with its external portion.
x^2 = 2(6)
x^2 = 12, so x = 2√3 = 3.5
Which set of side lengths can be used to construct a triangle?
OPTIONS
3, 4, 9
3, 5, 7
3, 5, 8
2, 6, 8
The value of set of side lengths can be used to construct a triangle are,
⇒ 3, 5, 7
We have to given that;
To find the set of side lengths can be used to construct a triangle.
Now, We know that;
The sum of two side of a triangle is always greater than third side.
Hence, We can check all options as;
⇒ 3, 4, 9
Since, 3 + 4 = 7 < 9
Hence, It does not form a triangle.
⇒ 3, 5, 7
Since, 3 + 5 = 8 > 7
Hence, It form a triangle.
⇒ 3,5, 8
Since, 3 + 5 = 8 = 8
Hence, It does not form a triangle.
⇒ 2, 6, 8
Since, 2 + 6 = 8 = 8
Hence, It does not form a triangle.
Thus, The value of set of side lengths can be used to construct a triangle are,
⇒ 3, 5, 7
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A floor has a shape of a trapezium Gary is going to paint the floor each 5 litre tin of paint cost 21.99 1 litre of paint covers an area of 2.5m
Answer:
Step-by-step explanation:
step 1 : finding the area of a floor using trapezius area formula
A= [tex]\frac{(10+14)*6}{2} = \frac{24*6}{2} =72 m^{2} \\[/tex]
step 2 : the problem said 1 litre of paint convers an area of 2.5 m^2, so let's calculate how many liters of paint are needed to paint the floor
[tex]\frac{72 m^2}{2.5 m^2} = 28.8 litre\\[/tex]
so we need 28.8 litre to paint the floor
step 3 : Each tin is 5 litre of paint so let's calculate how many tins do we need
n=[tex]\frac{28.8}{5} = 5.76 \\[/tex]
we can't by 5.76 tins so it's 6 tins
step 4 : Each tin costs 21.99 and now we calculate how much 6 tins cost for us
cost = 6 × 21.99 = 131.94
step 5 : Gary has a budget of 150 and the total cost is 131.94. So, Gary has enough money to buy all the paint he needs.
Please answer! thankss
Answer:
48
Step-by-step explanation:
since this is a linear Angle, the total sum will be 180. Given Angle is 132. so answer will be:
180-132= 48
Answer:
n = 48°Step-by-step explanation:
The sum of adjacent angles on a straight line is 180°. i.e. In the figure, we are given is a straight line, then n and 132° are the adjacent angles.
n + 132° = 180
n = 180 - 132
n = 48
Hence, the measure of the unknown angle is 48°.
Let f(t) be the probability density function for the time it takes you to drive to school in the morning, where is measured in minutes. Express the following probabilities as integrals. (If you need to use coor-co, enter INFINITY or -INFINITY, respectively.) (a) The probability that you drive to school in less than 50 minutes S. RC) dt (b) The probability that it takes you more than a quarter of an hour to get to school S. (t) de
(a) The probability that you drive to school in less than 50 minutes is [tex]\int_{0}^{50} f(t) dt[/tex].
(b) The probability that it takes you more than a quarter of an hour to get to school is [tex]\int_{15}^{\infty} f(t) dt[/tex].
(a) The probability that you drive to school in less than 50 minutes can be expressed as the integral of the probability density function f(t) over the interval from 0 to 50 minutes. This is represented as:
[tex]\int_{0}^{50} f(t) dt[/tex]
(b) The probability that it takes you more than a quarter of an hour (15 minutes) to get to school can be expressed as the integral of the probability density function f(t) over the interval from 15 minutes to infinity.
This is represented as:
[tex]\int_{15}^{\infty} f(t) dt[/tex]
Remember that these integrals represent the probabilities we're looking for, and we would need to actually evaluate them with the specific probability density function f(t) to obtain numerical values.
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The ratio of winning raffle tickets to losing raffle tickets is 4 to 9. If Mr. Ticket purchases 117 raffle tickets, how many winning tickets can he expect to have?
HELP
The winning raffle ticket to losing raffle ticket ratio is 4 to 9. Mr. Ticket buys 117 raffle tickets, he expect to have 36 winning tickets.
We know the ratio of winning to loosing ticket is 4:9
Sum of ratio = 4 + 9 = 13
Winning tickets = (4 / 13) × 117
= 4 × 9
= 36
In mathematics, a ratio is a phrase used to compare two or more numbers. It is used to express how large or tiny an amount is in comparison to another. A ratio compares two quantities by dividing them. The dividend is referred to as the "antecedent," while the divisor is referred to as the "consequent."
Ratios are divided into two sorts. The first is a part-to-part ratio, and the second is a part-to-whole ratio. The part-to-part ratio expresses the relationship between two distinct entities or groupings.
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solve for all values of x
x-x+7/x-10=5/x-10
Answer: The value of x is 12
Definition of equation : In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal. For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.
An equation combines two expressions connected by an equal sign (“=”). These two expressions on either side of the equals sign are called the “left-hand side” and “right-hand side” of the equation. We generally assume the right-hand side of an equation is zero. This will not reduce the generality since we can balance this by subtracting the right-hand side expression from both sides’ expressions.
EXPLANATION : Given: to solve for X:
[tex]x -\frac{x+7}{x - 10} = \frac{5}{x -10}[/tex]
Solution: [tex]x - \frac{x+7}{x -10} = \frac{5}{x -10}[/tex]
[tex]= > x^{2} -11x -7 = 5[/tex]
[tex]= > x^{2} -11x-7-5=0[/tex]
[tex]= > x^{2} -11x -12 =0[/tex]
[tex]= > x^{2} -12x+x-12 =0[/tex]
[tex]= > x(x-12) +1(x-12)= 0[/tex]
[tex]= > (x-12) (x+1)=0[/tex]
[tex]x =12 , x\neq -1[/tex]
Final answer: The value of x is 12
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Triangle ABC is taken to triangle A'B'C' by a dilation. Select ALL the scale factors for the dilation that would result in an image that was smaller than the original figure
PLEASE ANSWER ASAP
The scale factors for the dilation that would result in an image that was smaller than the original figure 1/2 and 8/9.
As, Dilation is a transformation that produces an image that is similar to the original figure, but it may be larger or smaller depending on the scale factor.
If the scale factor is greater than 1, the image will be larger than the original figure, and if the scale factor is less than 1, the image will be smaller than the original figure.
Therefore, the scale factors that would result in an image that was smaller than the original triangle are:
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HELP NEEDED
*10points!*
If using the method of completing the square to solve the quadratic equation
�
2
−
10
�
+
21
=
0
x
2
−10x+21=0, which number would have to be added to "complete the square"?
The number that we have to add for completing the square is 25, that is square of half of the coefficient of x.
To use the method of completing the square to solve the quadratic equation x² - 10x + 21 = 0, we can first rearrange it to isolate the x² and x terms,
x² - 10x = -21
We then need to find a number to add to both sides of the equation to "complete the square". To do this, we take half of the coefficient of the x term (-10 in this case), square it, and add it to both sides of the equation. Half of -10 is -5, so we have,
x² - 10x + (-5)² = -21 + (-5)²
Simplifying the right-hand side, we get,
x² - 10x + 25 = -4
The left-hand side is now a perfect square trinomial, which we can write as,
(x - 5)² = -4
We can then take the square root of both sides, remembering to include both positive and negative roots,
x - 5 = ±√(-4)
x - 5 = ±2i (where i is the imaginary unit, √(-1))
Adding 5 to both sides, we get,
x = 5 ± 2i
Therefore, the number we would have to add to "complete the square" is (half of the coefficient of the x term) squared, which is (-5)² = 25.
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Complete question - If using the method of completing the square to solve the quadratic equation x² - 10x + 21 = 0, which number would have to be added to "complete the square"?
Question 4 of 10
What is the quotient of the following division problem?
18615489 = ?
A. 38 r33
B. 39 r32
C. 38 r34
D. 37 r33
Answer:
Step-by-step explanation:
b
an algorithm is a calculation that determines how long it will take to solve a problem.True/False
False, An algorithm is a step-by-step procedure or set of instructions for solving a problem or performing a specific task.
It is not limited to calculating the time it takes to solve a problem, but rather it provides a systematic approach to reach the desired solution. Algorithms can be designed to solve a wide range of problems, from simple mathematical calculations to complex computer programming tasks.
Their efficiency can be measured in terms of time and space complexity, which helps in determining the performance of the algorithm. However, the primary purpose of an logarithmic is to provide a clear and effective method for solving problems, not merely calculating the time it takes to solve them.
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Find a Cartesian equation for the curve and identify it.
r = 4csc(θ)
circle line parabola ellipse
The Cartesian equation for the curve r = 4csc(θ) is (x^2 + y^2) * y = 4, and it represents a semi-cubical parabola.
To find a Cartesian equation for the curve r = 4csc(θ) and identify it, we can follow these steps:
Step 1: Rewrite the equation using the definition of cosecant
Cosecant (csc) is the reciprocal of sine, so we can rewrite the equation as:
r = 4/sin(θ)
Step 2: Express r and θ in Cartesian coordinates
We know that r^2 = x^2 + y^2 and y = r * sin(θ). We can use these relationships to replace r and θ with x and y in our equation. First, we solve for sin(θ):
sin(θ) = y / r
Step 3: Substitute sin(θ) and r in the equation
Now, replace sin(θ) and r in the original equation:
r = 4/(y/r)
Step 4: Simplify and solve for y
To get a Cartesian equation, multiply both sides by y:
r * y = 4
Since y = r * sin(θ), we can replace y with r * sin(θ):
r * (r * sin(θ)) = 4
Step 5: Replace r with x^2 + y^2
Since r^2 = x^2 + y^2, we can replace r in the equation:
(x^2 + y^2) * (y) = 4
Step 6: Identify the curve
This equation represents a curve in the Cartesian plane. By analyzing the equation, we can see that it's a semi-cubical parabola.
In conclusion, the Cartesian equation for the curve r = 4csc(θ) is (x^2 + y^2) * y = 4, and it represents a semi-cubical parabola.
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I bought 3 books for $x each and 4 magazines for $y each, how much did I spend?
Richard walked 15.74 miles and James walk 12.98 miles how many more miles did Richard walk then James.
Answer: He walked 2.76 more miles.
Step-by-step explanation: In this problem, we would subtract James' miles from Richard's miles to get the answer.
15.74 miles - 12.98 miles = 2.76 miles.
Therefore, Richard walked 2.76 more miles than James.
sections of picket fence come ready-made and cost $2.89 for a 27-inches section. how much would it cost to put a fence along the borders of a flower patch shaped like the drawing below?
The cost to put a fence along the borders of the flower patch is $19.27
Calculating the cost to put a fence along the borders of the flower patchFrom the question, we have the following parameters that can be used in our computation:
Cost = $2.89 for a 27-inches section
Next, we calculate the perimeter of the patch by adding the side lengths
So, we have
Perimeter = 2 ft 3 in + 2 ft + 2 yd + 25 in + 3 ft 5 in
Evaluate
Perimeter = 15 feet 9 inches
Convert to inches
Perimeter = 180 inches + 9 inches
So, we have
Perimeter = 189 inches
Next, we have
Cost = 180 * 2.89/27
Evaluate
Cost = $19.27
Hence, the cost is $19.27
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T/F : An annuity due must have a present value at least as large as an equivalent ordinary annuity.
True. An annuity due is a series of equal payments made at the beginning of each period, while an ordinary annuity is a series of equal payments made at the end of each period.
Because payments made at the beginning of each period earn interest for one additional period, annuity due payments are worth more than equivalent ordinary annuity payments. This means that the present value of an annuity due must be larger than the present value of an equivalent ordinary annuity, assuming the same interest rate and number of payments.
Therefore, if we compare two annuities with the same payment amount, interest rate, and number of payments, the annuity due will always have a larger present value than the ordinary annuity. It is important to understand the difference between these two types of annuities as it can impact the amount of money you receive or need to save for your retirement.
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Which two choices are equivalent to the fraction below?
The equivalent fraction is 2/3. Option C
What are fractions?Fractions are simply described as expressions that are used for representing the part of a whole variable, a whole number or a whole element.
There are different types of fractions listed as;
Simple fractionsComplex fractionsProper fractionsImproper fractionsMixed fractionsExamples of these fractions are;
Mixed fractions are written as whole numbers attached to fractions, mostly proper fractions
2 1/3
Proper fractions are given as 2/3
Improper fractions are given as 4/3 , 5/6
From the information given, we have that;
4/6
Divide by a common value
2/3
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Halp me this question
The Complete sentence is 9 + (7 + 14).
We have the number (9 + 7)+ 14
We know from the Associative Property
(a+ b)+ c = a + (b+ c )
Here a = 9, b = 7 and c= 14.
Then, using the Associative property
(9 + 7) + 14
= 9 + (7 + 14)
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A zero-seeking device operates as follows: If it is in state m at time n, then at time n+1, its position is uniformly distributed over the states 0,1, . . . ,m−1. Find the expected time until the device first hits zero starting from state m.
Note: This is a highly simplified model for an algorithm that seeks a maximum over a finite set of points.
The expected time until the device first hits zero starting from state m is E[T_m] = m * (1 + E[T_{m-1}])/2
The expected time until the zero-seeking device hits zero starting from state m can be found using the principle of conditional expectation. Let T_m be the time until the device first hits zero starting from state m. We have T_0 = 0 since the device is already at zero. For m > 0, we can condition on the next state of the device at time n+1. Since the device is uniformly distributed over the states 0,1,...,m-1 at time n+1, the expected time until the device hits zero starting from the next state is T_{m-1}. Therefore, we have:
E[T_m] = 1 + (1/m) * [T_0 + T_1 + ... + T_{m-1}]
Using the principle of linearity of expectation and the fact that T_0 = 0, we can simplify this to:
E[T_m] = 1 + (1/m) * (T_1 + T_2 + ... + T_{m-1})
We can continue this process recursively to get:
E[T_m] = 1 + (1/m) * (1 + E[T_{m-1}] + 1 + E[T_{m-2}] + ... + 1 + E[T_1])
Simplifying this expression, we get:
E[T_m] = m * (1 + E[T_{m-1}])/2
Using this recursive formula and the base case E[T_0] = 0, we can calculate E[T_m] for any value of m. This simplified model for an algorithm that seeks a maximum over a finite set of points provides useful insight into the expected behavior of such algorithms.
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#SPJ11
