DUE SOON! WILL GET 100 POINTS!
I NEED HELP!! SO CONFUSED AND RUNNING OUT OF TIME!!

DUE SOON! WILL GET 100 POINTS!I NEED HELP!! SO CONFUSED AND RUNNING OUT OF TIME!!

Answers

Answer 1

The restrictions on the variables x and y are given as follows:

x ∈ W, y ∈ W.

How to obtain the restrictions to the variables x and y?

The first step in obtaining the restrictions of the variables x and y are identifying them, which is done as follows:

Variable x: number of lower bowl tickets sold.Variable y: number of upper bowl tickets sold.

Then we known that we usually hear it in the news things such as this sentence:

"On the last Buffalo Bills game, 60,000 tickets were sold".

The amount of tickets sold varies, but the type of number doesn't, it is always a positive non-decimal number.

The number of ticket sold cannot assume neither negative nor decimal values, thus the variables x and y belong to the whole number set and the first option is correct.

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Related Questions

How many square tiles of side 40 cm are needed to cover a wall of size 4m by 3.6m?

Answers

Tiles are needed = 90

The number of tiles measuring 40cm by 40cm  that are needed to completely cover a wall 4m by 3.6m is 90.

Squares

Square,  a plane figure with four equal sides and four right (90°) angles. A square is a special kind of rectangle (an equilateral one) and a special kind of parallelogram (an equilateral and equiangular one).

Number of tiles needed

Convert the Meters to Centimeters

4m = 400cm

3.6m = 360 cm

Then

4m by 3.6m = 400 cm × 360 cm

4m by 3.6m = 144000 cm²

Tiles are needed

Number of needed tiles =  144000 cm² / ( 40 cm × 40 cm)

Number of needed tiles =  144,000 cm² /1600 cm²

Number of needed tiles =  90

Tiles are needed = 90

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A survey determines that six out of every ten Niceville residents shop at Walmart: In a group of15, randomly selected Nicevillians, find the prabablllythat at least thirteenof them shop at Walmart.

Answers

From a group of 15 randomly selected residents , the probability that at least thirteen of them shop at Walmart is 0.0271  .

6 out of 10 Niceville residents shop at Walmart

So, the probability of shopping at Walmart (p) is = 6/10 = 0.6

The probability of not shopping at Walmart is (q) = 1 - 0.6 = 0.4 .

The number of members in the group is(n) = 15 ;

We have to find the probability that, at least thirteen of them shop at Walmart

By the Binomial Probability Distribution,

we know that ; P(x = a) = ⁿCₐ×pᵃ×qⁿ⁻ᵃ

So , P(x ≥ 13) = P(x=13) + P(x=14) + P(x=15)

Substituting the values of a , n and p and q ,

We get ;

= ¹⁵C₁₃p¹³q² + ¹⁵C₁₄p¹⁴q¹ + ¹⁵C₁₅p¹⁵q⁰

= ¹⁵C₁₃(0.6)¹³(0.4)² + ¹⁵C₁₄(0.6)¹⁴(0.4)¹ + ¹⁵C₁₅(0.6)¹⁵(0.4)⁰

= 0.0219 + 0.0047 + 0.0004

= 0.0271

Therefore, the required probability is 0.0271

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What are the rules of multiplying decimals?

Answers

To multiply decimals, first multiply as if there is no decimal. Next, count the number of digits after the decimal in each factor. Finally, put the same number of digits behind the decimal in the product.

Answer:

To multiply decimals, first multiply as if there is no decimal. Next, count the number of digits after the decimal in each factor. Finally, put the same number of digits behind the decimal in the product.

Step-by-step explanation:

10. assume that the annual earnings of 23 college students are used in a simple random sample with a mean of $4590 and a standard deviation of $860. construct a confidence interval for the standard deviation if we want a 99% confidence level for our interval

Answers

Using the t-distribution, the 99% confidence intervals for the given standard deviation are given as follows: (5053.39 , 4126.61)

Given that,

Number of college students = 23

A simple random sample with a mean = $4590

A simple random sample with a standard deviation = $860

What is a t-distribution confidence interval?

The t distributions is wide (has thicker tailed) for smaller sample sizes, reflecting that s can be smaller than σ. The thick tails ensure that the 80%, 95%, 99% confidence intervals are wider than those of a standard normal distribution (so are better for capturing the population mean).

The confidence interval is:

= μ ± [tex]t\frac{s}{\sqrt{n} }[/tex]

In which:

μ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 99% confidence interval, with 23 - 1 = 22 df,

Upon using a t -table or a calculator, we see that the critical t -value for this 99% confidence interval is t0.005=2.581

The parameters are:

μ = $4590

n = 23

Hence, with s = 860, the bounds of the interval are:

= μ ± [tex]t\frac{s}{\sqrt{n} }[/tex]

= 4590 ± 2.581 [tex]\frac{860}{\sqrt{23} }[/tex]

= 4590 ± 2.581 [tex]\frac{860}{4.79}[/tex]

= 4590 ± 2.581 (179.54)

= 4590 ± 463.39

Then,

= 4590 + 463.39   ,      4590 - 463.39

= 5053.39              ,       4126.61

Therefore,

Using the t-distribution, the 99% confidence intervals for the given standard deviation are given as follows: (5053.39 , 4126.61)

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Which statements are true about box plots? Check all that apply.
They help describe sets of data.
They include the mean.
They show the data split into four parts.
They show outliers through really short “whiskers.”
Each section of a box plot represents 25% of the data.

Merry Christmas!

Answers

The true statements are they help describe sets of data, they show the data split into four parts and each section of a box plot represents 25% of the data.

What is the box-and-whisker plot?

A box and whisker plot displays a "box" with its left edge at Q₁, right edge at Q₃, "center" at Q₂ (the median), and "whiskers" at the maximum and minimum.

The box plot is also called box-and-whisker plot.

The data is divided into sections by box plots, with each section containing around 25% of the total data.

Box plots are useful as:

They offer a visual overview of the data,

making it simple for researchers to spot skewness,

the dispersion of the data set.

The minimum value, first quartile, median, third quartile, and maximum value are the five values that make up a box plot.

And they don't include mean.

From the above discussion,

we have three statements that are true and those statements are;

they help describe sets of data, they show the data split into four parts and each section of a box plot represents 25% of the data.

Therefore, the correct statements are A, C and E.

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A mining company owns two mines. These mines produce an ore that can be graded into two classes: regular grade and low grade. The company must produce at least 350 tons of regular-grade and 610 tons of low-grade ore per week. The first mine produces 5 tons of regular-grade and 17 tons of low-grade ore per hour. The second mine produces 20 tons of regular-grade and 10 tons of low-grade ore per hour. The operating cost of the first mine is $7000 per hour, and the operating cost of the second mine is $29,000 per hour. The first mine can be operated no more than 54 hours a week, and the second mine can be operated no more than 27 hours a week. How many hours per week should each mine be operated to minimize the cost?

Answers

The number of hours to operate the mines to minimize cost are Mine 1 hour = 30 hours and Mine 2 hour = 10 hours

How to determine the number of hours?

The given parameters can be represented using the following table of values

                             Mine 1 (x)              Mine 2 (y)   Available

Regular grade          5                            20             350

Low grade               17                             10              610

Operating cost      7000                     29000

Time                        54                              27

From the table, we understand that we are to minimize cost

This means that:

Objective function: C = 7000x + 29000y

Subject to:

5x + 20y ≥ 350

17x + 10y ≥ 610

Next, we plot the constraints on a graph (see attachment)

From the graph, we have

(x, y) = (30, 10)

This means that

Mine 1 hour = 30 hours

Mine 2 hour = 10 hours

Hence, the number of hours are 30 and 10 hours

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2. The equation and the graph represent two functions. Use the equation
y 4 and the graph to answer the questions, Besson 5-7)
6 7 8 9 10 11 12
a. When x is 4, is the output of the equation or the graph greater?
b. What value for x produces the same output in both the graph and
the equation?

Answers

The equation y = 4 has a greater output at x = 4

The graph and the equation have the same output at x = 6

The greater output at x = 4

From the question, we have

The linear graph The equation y = 4

From the graph, we can see that

When x = 4, the output is 3

The equation y = 4 implies that, the output is always 4 irrespective of the input value

Hence, the equation has a greater output.

The value of x for same output

Here, we have the same parameters above

From the graph, we can see that

When y = 4, the input is 6

The equation y = 4 implies that, the output is always 4 irrespective of the input value

Hence, they have the same output at x = 6

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HELP ME QUICICICKCKC

Answers

Answer:

A.

Step-by-step explanation:

Multiply the x like terms than multiply the other like terms

What is the circumcenter of a triangle formed by (4,2), (3,-3) and (2,2)?

Answers

The circumcenter of a triangle formed by (4,2), (3,-3) and (2,2) is located at (3, -0.4).

The circumcenter of a triangle is the point of intersection of the three perpendicular bisectors of the sides of a triangle.

Let A = vertex at (4,2)

B = vertex at (3,-3)

C = vertex at (2,2)

Get the midpoint of each side.

midpoint = [(x₂ + x₁)/2 , (y₂ + y₁)/2]

side AB : midpoint = [(3 + 4)/2 , (-3 + 2)/2] = (3.5, -0.5)

side AC : midpoint = [(4 + 2)/2 , (2 + 2)/2] = (3, 2)

side BC : midpoint = [(3 + 2)/2 , (-3 + 2)/2] = (2.5, -0.5)

Get the slope of each side.

slope = (y₂ - y₁) / (x₂ - x₁)

side AB : slope = (-3 - 2) / (3 - 4) = 5

side AC : slope = (2 - 2) / (2 - 4) = 0/-2 = 0

side BC : slope = (2 - -3) / (2 - 3) = -5

Determine the equation of the line of each of the three perpendicular bisectors of the sides of a triangle, that passes through the midpoint and with a slope equal to the negative reciprocal of the slope of the side.

y = mx + b

perpendicular bisector of AB :

-0.5 = -1/5(3.5) + b   ;   b = 0.2   ;   y = -1/5x + 0.2

perpendicular bisector of AC :

since AC is a horizontal line, x = 3

perpendicular bisector of BC :

-0.5 = 1/5(2.5) + b   ;   b = -1   ;   y = 1/5x - 1

Since x is already equal to 3, substitute the value of x in the two other equation and solve for y.

y = -1/5x + 0.2

y = -1/5(3) + 0.2

y = -0.4

y = 1/5x - 1

y = 1/5(3) - 1

y = -0.4

Hence, the circumcenter of the triangle is located at (3, -0.4).

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Can someone help me with this, please?

Answers

π√π÷√π  is an irrational number. So option (a) is required answer.

What is irrational number?

A real number that cannot be stated as a ratio of integers is said to be irrational; an example of this is the number 2. Any irrational number, such as p/q, where p and q are integers, q, cannot be expressed as a ratio. Once more, an irrational number's decimal expansion is neither ending nor recurrent.

Examples of irrational number: √3, ∛2, π

π is an irrational because it is neither ending nor recurrent.

Solving each part of options, we get

π√π÷√π = π

√25 = 5

√π÷π = 1

2√2 ÷ √2 = 2

As most of the option give rational number only one option gives irrational number which is π

We get π from option (a)

So, option (a) is correct option.

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A piñata is a container filled with toys and candy and is broken open by hitting it with a stick. Sophia is trying to break the piñata. The probability that she will break the piñata on the first hit is 0.7. She will continue to hit the piñata until it breaks. If she does not break the piñata on a particular hit, the piñata is weakened and the probability that she will break it on the next hit is 0.1 greater than the probability on the previous hit. For example, if the piñata does not break on the first hit, the probability that it will break on the second hit is 0.8.
(a) Calculate the probability that Sophia docs.not break the piñata on the first hit and does break the piñata on the second hit. Let the random variable X represent the number of hits required for Sophia to break the piñata.
(b) Complete the probability distribution of X in the table below Probability of x 0.7

Answers

The probability that Sophia does not break the piñata on the first hit and does break the piñata on the second hit is of:

0.24 = 24%.

How to calculate the probability?

In the context of a problem, a probability is calculated as the division of the number of desired outcomes divided by the number of total outcomes.

In the context of this problem, these probabilities are given by the percentages/proportions stated in the problem.

The probability that Sophia does not break the piñata on the first hit and does break the piñata on the second hit is calculated considering these two outcomes given as follows:

First outcome -> does not break -> 0.3 probability.Second outcome -> breaks -> 0.8 probability.

The probability is calculated as the multiplication of these outcomes, as follows:

p = 0.3 x 0.8 = 0.24 = 24%.

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Victoria has 1.90 worth of nickels and dimes. She has two more nickels than dimes. Write a system of equation that could be used to determine the number of nickels and the number of dimes that victoria has.

Answers

The system of equations is  0.05n+0.10d=1.90  and n=d+2

What is an equation?

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated.

The calculation is as follows:

We know that

One nickel = $0.05,

So n nickels are worth 0.05n.

One dime = $0.10,

so dd dimes are worth 0.10d.

Now

The total 0.05n+0.10d =  $1.90

i.e.  

0.05n+0.10d=1.90

And,  

n=d+2

Therefore we can conclude that The system of equations is  0.05n+0.10d=1.90  and n=d+2

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. do you need to use sd to estimate the sd of the population? no, we're given the sd of the population, we don't need to estimate it. yes, because with only 20 observations the sample sd is not a great estimate of the true population sd.

Answers

The measure of the spread of scores within a set of data is termed as standard deviation. Usually, we are interested in the standard deviation of a population. since, we are often presented with data from a sample only, we can estimate the population standard deviation from a sample standard deviation.

When to use the sample or population standard deviation ?

Population standard deviation is of great intrest because our population contains all the values we are interested in. Therefore, we would normally calculate the population standard deviation In two cases first when we have the entire population or second we have a sample of a larger population, but we are only interested in this sample and do not wish to generalize our findings to the population. but, in statistics, a sample is presented from which we wish to estimate (generalize to) a population, and the standard deviation is no exception to this.

Thus it can be concluded that, if we have all is a sample, but we wish to make a statement about the population standard deviation from which the sample is drawn, we need to use the sample standard deviation. There a Confusion can often arise as to which standard deviation to use due to the name "sample" standard deviation incorrectly being interpreted and not the estimate of the population standard deviation based on the sample.

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Chelsea has $8.50 in coins. She has only quarters and nickels. If Chelsea has exactly 62 coins, how many nickels does she have?

Answers

Using substitution method, the system of linear equations showed that there 27 and 35 quarters and nickel respectively

System of Linear Equation

System of linear equations is the set of two or more linear equations involving the same variables. Here, linear equations can be defined as the equations of the first order, i.e., the highest power of the variable is 1. Linear equations can have one variable, two variables, or three variables. Thus, we can write linear equations with n number of variables.

To solve this problem, we have to write a system of linear equations which consist of two linear equations.

Let;

x = quartersy = nickel

x + y = 62...eq(i)

0.25x + 0.05y = 8.50 ...eq(ii)

Using substitution method

From equation (i)

x + y = 62

x = 62 - y ...eq(iii)

Put equ(iii) into eq(ii)

0.25( 62 - y) + 0.05y = 8.50

y = 35

Put y = 35 in equation (i)

x + 35 = 62

x = 27

The number of quarters and nickels are 27 and 35 respectively

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I need help with the 1st question please

Answers

When it come to figuring taxes what you have to do is multiply the amount by what percent the tax is then you add or subtract from the amount. If you don't know how to convert a percentage to a decimal divide the percentage by 100. Always remember to round to the nearest hundredths when dealing with money.

SS: $125 x 0.062 = $7.75    Med: $125 x 0.0145 = $1.81

SS: $432 x 0.062 = $26.78    Med: $432 x 0.0145 = $6.26

SS: $241 x 0.062 = $14.94    Med: $241 x 0.0145 = $3.49

SS: $1,562 x 0.062 = $96.84    Med: $1,562 x 0.0145 = $22.65

At the time of her​ grandson's birth, a grandmother deposits 14000 in an account that pays 9.5% compounded monthly. What will be the value of the account at the​ child's twenty-first​ birthday, assuming that no other deposits or withdrawals are made during this​ period?

Answers

The value of the account at the​ child's twenty-first​ birthday is 102125.44

How to determine the value of the account at the​ child's twenty-first​ birthday?

We can use the compound interest formula to determine the value of the account (A) on the​ child's twenty-first​ birthday:

A = P (1 + r/n)^(nt)

Where:

P is the initial amount of money deposited in the account

r is the interest rate

n is the number of times the interest is compounded per year

t is the number of years

Given: P = 14000, r = 9.5% = 0.095, t = 21, n = 12 (i.e. 12 months per year)

Substitututing into A = P (1 + r/n)^(nt):

A = 14000 (1 +  0.095/12)^(12×21)

A = 14000 (1 +  0.095/12)^(252)

A = 102125.44

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Match the equation with its graph

Y=2/5x-1

Answers

Answer:

the second one

Step-by-step explanation:

An element with a mass of 520 grams decays by 25.1% per minute. To the nearest tenth of a minute, how long will it be until there are 60 grams of the element remaining?

Answers

The total time for the mass of the element to be 60 grams is 7.5 minutes

What is exponential growth factor?

The exponential growth or decay formula is given by

x ( t ) = x₀ × ( 1 + r )ⁿ  for growth rate

x ( t ) = x₀ × ( 1 - r )ⁿ   for decay rate

x ( t ) is the value at time t

x₀ is the initial value at time t = 0.

r is the growth rate when r>0 or decay rate when r<0, in percent

t is the time in discrete intervals and selected time units = n

Given data ,

Let the total mass of element be = 520 grams

So , the value of x₀ = 520 grams

Now , the decay rate of element is given by r = 25.1 %

To calculate the time at which the amount of element left is 60 grams = n

where n is the total time = t

So , x ( t ) = 60

The decay rate formula is given by the equation ,

x ( t ) = x₀ × ( 1 - r )ⁿ

Substituting the values in the equation , we get

60 = 520 ( 1 - 25.1/100 )ⁿ

On simplifying the equation , we get

60 = 520 ( 1 - 0.251 )ⁿ

Divide by 520 on both sides of the equation , we get

( 0.749 )ⁿ = 6/52

Taking logarithm on both sides , we get

n × log ( 0.749 ) = log ( 6/52 )

Divide by log ( 0.749 ) on both sides , we get

n = log ( 6/52 ) / log ( 0.749 )

n = -0.9378 / -0.1255

n = 7.47 minutes

Therefore , the value of n time t = 7.5 minutes

Hence ,

The total time for the mass of the element to be 60 grams is 7.5 minutes

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There are 1,295 students attending a small university. There are 714 women enrolled. What percentage of student are women?

Answers

Answer:

55.13 I'm sure is the answer

There are 714 women out of the total 1295 students:

    [tex]\dfrac{714}{1295}\approx0.551351351351351[/tex]

About 55.14% of the students are women.

f(x) = 3x² + 4x - 6
g(x) = 6x³5x² - 2

Find (f - g)(x).

O A. (f-g)(x) = 6x³ - 2x² + 4x - 8
O B. (f-g)(x) = -6x³ - 2x² + 4x - 8
O c. (f - g)(x) = 6x³ - 8x² - 4x + 4
O D. (f - g)(x) = -6x³ + 8x² + 4x - 4

Answers

The difference of the functions, f(x) = 3x² + 4x - 6 and g(x) = 6x³ - 5x² - 2, is: D. (f - g)(x) = -6x³ + 8x² + 4x - 4.

How to Find the Difference of Two Functions?

Finding the difference of two functions involves combining like terms together and then simplify.

Given the functions:

f(x) = 3x² + 4x - 6

g(x) = 6x³ - 5x² - 2

To find (f - g)(x), it implies that we find the difference between f(x) and g(x).

(f - g)(x) = f(x) - g(x)

Substitute

f(x) - g(x) = (3x² + 4x - 6) - (6x³ - 5x² - 2)

Open the parentheses:

f(x) - g(x) = 3x² + 4x - 6 - 6x³ + 5x² + 2

Combine like terms

f(x) - g(x) = - 6x³ + 8x² + 4x - 4

Therefore, the answer is: D. (f - g)(x) = -6x³ + 8x² + 4x - 4

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Complete the fraction to make a true inequality, and explain your reasoning


4 × < 4
3




I know this because the fraction I made

Answers

It is true. Look at the picture
Your welcome
Brainiest and thanks would be nice

Change the circle equation into standard form then answer the following questions:
of the center?
of the vertices?
Coordinates
Coordinates
How long is the radius?
Domain?
Range?
X²+ y²-14X + 8Y+ 40 = 0

Answers

We must transform the current polynomial to circle standard form: (x-h)^2+(y-k)^2=r^2. We will do so by completing the square, which produces a perfect square trinomial that can be factored into a square binomial in the form of the circle standard form.

First, use the commutative property to rearrange and group x and y:

x^2+(-14x)+y^2+8y+40=0

Now, we will subtract 40 from both sides:

x^2+(-14x)+y^2+8y=-40

We can now complete the square for both x and y:

(x^2-14x+(-14/2)^2)+(y^2+8y+(8/2)^2)=-40+(-14/2)^2+(8/2)^2

Simplify:

x^2-14x+49+y^2+8y+16=-40+49+16

Factor and simplify:

(x-7)^2+(y+4)^2=25

Now, factor the 25 to a squared factor:

(x-7)^2+(y+4)^2=5^2

The circle is now in standard form, so let’s identify its features:

Center: (h,k) = (7, -4)

Radius: 5

Vertices: (7, 1), (7, -9), (2, -4), (12, -4)

Domain: [2, 12]

Range: [-9, 1]

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Which of the following statement is true about triangle inequalities?

Answers

The statement which is true about triangle inequalities is that the sum of the lengths of the 2 sides of a triangle is equal than the third side of the triangle.

What are triangle inequalities?

In Euclidean geometry, triangle inequalities are a theorem which states that the sum of any two sides of a triangle is greater than or equal to the third side; in symbols, a + b ≥ c. In shorts, the theorem states that the shortest distance between two points is a straight line.

If the length of a side is equal to the sum of the other two sides, then the vertices have to be colinear, meaning that the three sides form a line segment rather than a triangle. This is called the triangle inequality.

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a researcher was interested in comparing the amount of time spent browsing the internet by men and by women. independent samples of 14 men and 16 women

Answers

The confidence interval limits include 0, which suggests that the two population means might be equal. There does not appear to be a significant difference between the mean amount of time spent watching television for women and the mean amount of time spent watching television for men.

The correct option is (a)

"Information available from the question:"

This is incomplete question:

Complete question is this:

A researcher was interested in comparing the amount of time spent watching television by women and by men. Independent simple random samples of 14 women and 17 men were selected, and each person was asked how many hours he or she had watched television during the previous week. The summary statistics are as follows.

Women             Men

x1 = 11.7hrs x2 = 14.2hrs

s1 = 3.9hrs s2 = 5.2hrs

n1 = 14         n2 = 17

The following 99% confidence interval was obtained for μ1 − μ2, the difference between the mean amount of time spent watching television for women and the mean amount of time spent watching television for men:

-7.43hrs < μ1 − mμ2 < 2.43hrs

What does the confidence interval suggest about the population means?

a. The confidence interval limits include 0 which suggests that the two population means might be equal. There does not appear to be a significant difference between the mean amount of time spent watching television for women and the mean amount of time spent watching television for men.

b. The confidence interval includes only negative values which suggest that the mean amount of time spent watching television for women is smaller than the mean amount of time spent watching television for men.

c. The confidence interval limits include 0 which suggests that the two population means are unlikely to be equal. There appears to be a significant difference between the mean amount of time spent watching television for women and the mean amount of time spent watching television for men.

d. The confidence interval includes only positive values which suggest that the mean amount of time spent watching television for women is larger than the mean amount of time spent watching television for men.

Now, According to the question:

The given confidence interval is:

-7.43hrs < μ1 − mμ2 < 2.43hrs

The interval includes 0 and the populations sampled are small (< 30). Therefore, Option (a) is correct.

Hence, The confidence interval limits include 0, which suggests that the two population means might be equal. There does not appear to be a significant difference between the mean amount of time spent watching television for women and the mean amount of time spent watching television for men.

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A city has a population of 50,000 in 2012. If the population of the city grows at an annual rate of 2%, the year in which the population will reach 100,000 is _____________ and the year it will reach 200,000 is _____________. Show work:

Answers

Doubling time= 70/2=35
2012+35=2047
2047+35=2082

Which is an example of the commutative property of addition?

A. 4+(1+2)=(4+1)+2
B. 2+2=3+1
C. 2+3=2+4
D. 4+3=3+4

Answers

The example of the commutative property of addition is option (D) 4 + 3 = 3 + 4

The commutative property of the addition states that changing the order of the numbers or the variable does not affect the result of sum

The commutative property of addition is

A + B = B + A

Here the position of the variable A and B are changed but still the result is same

From the given option

The example that shows the commutative property of  addition is

4 + 3 = 3 + 4

Here the position of the 3 and 4 changed, but the result will be

7 = 7

Therefore, the correct example is option D) 4 + 3 = 3 + 4

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If I can prove that X is c.e. and ω∖X is c.e. then I can prove that X is computable by the theorem "Let W⊆ω. Then W is computable if both W and ω∖W are c.e". But I'm not able to proceed on how should I do this.

Answers

Proving  X is computable by the theorem "Let W⊆ω. Then W is computable if both W and ω∖W are c.e".

Given :

If I can prove that X is c.e. and ω∖X is c.e. then I can prove that X is computable by the theorem "Let W⊆ω. Then W is computable if both W and ω∖W are c.e". But I'm not able to proceed on how should I do this.

Take a computable surjection :

f : ω → W.

Defined  G = { f ( x ) ∣ x ∈ ω and ∀y < x ( f ( y ) < f ( x ) ) }.

here clearly, G ⊆ W .

And G is infinite. For if f ( x ) ∈ G, take the smallest y such that f ( y ) > f ( x ); then f ( y ) ∈ V.

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5. show that for motion in a straight line with constant acceleration a, initial velocity v0, and initial displacement s0, the displacement after time t is s
s = 1/2 at2 + vOt + sO

Answers

Since the initial displacement is made by s0 and body moves with initial velocity and acceleration after that, the final displacement after time t is

[tex]s= \frac {1}{2} at ^{2} + v_{0}t+s_{0}[/tex]

What is Displacement?

The displacement is only the difference between the locations of the two marks and is unrelated to the route used to get there.

What is formula for acceleration and velocity?

The formula is:

[tex]a= \frac {Velocity}{Time}[/tex] (Acceleration)

[tex]v= \frac {Displacement}{Time}[/tex](Velocity)

Initial Displacement = s0

Displacement from position s0 after time t  = [tex]\frac {1}{2} at ^{2} + v_{0}t[/tex]

Total Final Displacement (s) = [tex]\frac {1}{2} at ^{2} + v_{0}t+s_{0}[/tex]

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solve 2y=3x+12 for y

Answers

Answer: y=[tex]\frac{3x}{2}[/tex]+6

Step-by-step explanation:

isolate y by dividing both sides by 2

y=3x+12/2

y=[tex]\frac{3x+12}{2}[/tex]

y=[tex]\frac{3x}{2}[/tex]+6

In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time college students who earn a​ bachelor's degree in four years or less. Find the sample size needed to estimate that percentage. Use a .03 margin of error and use a confidence level of 90​%. Complete parts​ (a) through​ (c) below.
a. Assume that nothing is known about the percentage to be estimated.
n=
b. Assume prior studies have shown that about 60​% of​ full-time students earn​ bachelor's degrees in four years or less.
n=
c. Does the added knowledge in part​ (b) have much of an effect on the sample​ size?

Answers

The required sample sizes are given as follows:

a) n = 752.

b) n = 722.

c) The added knowledge in item b has an effect, as it decreases the sample size required. The decrease is not huge because the estimate is close to 0.5, but the farther the estimate gets from 0.5, the more the sample size decreases.

What is a confidence interval of proportions?

A confidence interval of proportions has the bounds given by the rule presented as follows:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The margin of error is calculated as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The variables used to calculated these bounds are listed as follows:

[tex]\pi[/tex] is the sample proportion, which is also the estimate of the parameter.z is the critical value.n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

The margin of error in this problem is given as follows:

M = 0.03.

For item a, there is no previous estimate, hence we consider [tex]\pi = 0.5[/tex] and the sample size is obtained as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2[/tex]

n = 752. (rounding up).

For item b, the estimate is [tex]\pi = 0.6[/tex], hence the sample size is obtained as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 1.645\sqrt{\frac{0.6(0.4)}{n}}[/tex]

[tex]0.03\sqrt{n} = 1.645\sqrt{0.6(0.4)}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.6(0.4)}}{0.03}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.6(0.4)}}{0.03}\right)^2[/tex]

n = 722. (rounding up).

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