The graph of [tex]g(x) = 10^{(x+2)} +3[/tex] will be the graph of [tex]f(x) = 10^x[/tex] shifted left by 2 units and up by 3 units. It will still be an increasing exponential function that passes through the point (-2,4) instead of (0,1).
What is graph?
In mathematics, a graph is a visual representation of the relationships between objects. A graph consists of vertices, which are points or nodes, and edges, which are lines or arcs connecting the vertices.
To understand the transformation of the graph of [tex]g(x) = 10^{(x+2)} +3[/tex], we can first examine the basic graph of [tex]f(x) = 10^x[/tex]. This graph is an increasing exponential function that passes through the point (0,1), and as x gets larger, the y-values grow at an increasingly rapid pace.
Now let's consider the transformations applied to f(x) to obtain g(x):
The "+2" inside the exponent of [tex]10^{(x+2)[/tex] shifts the graph of f(x) to the left by 2 units. This means that the point (0,1) on the graph of f(x) will be moved to the left to the point (-2,1) on the graph of g(x).
The "+3" added outside the exponent of [tex]10^{(x+2)[/tex] shifts the entire graph of f(x) upwards by 3 units. This means that every point on the graph of f(x) will be shifted up by 3 units to obtain the corresponding point on the graph of g(x).
Therefore, the graph of [tex]g(x) = 10^{(x+2)} +3[/tex] will be the graph of [tex]f(x) = 10^x[/tex] shifted left by 2 units and up by 3 units. It will still be an increasing exponential function that passes through the point (-2,4) instead of (0,1).
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NO LINKS!! URGENT HELP PLEASE!!!
Find all points on the x-axis that are a distance 5 from P(-6, 3)
(x, y) = _________ (smaller x-value)
(x,y)= __________ (larger x-value)
Answer:
(x, y) = (-10, 0) and (x, y) = (-2, 0)
Step-by-step explanation:
To find the points on the x-axis that are a distance 5 from P(-6,3), we can use the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Since we want to find the points that are a distance of 5 from P(-6,3) on the x-axis, we know that y = 0 for these points. So we can simplify the distance formula to:
d = √((x - (-6))^2 + (0 - 3)^2)
d = √((x + 6)^2 + 9)
We want to find the values of x that make d = 5. So we can set up the equation:
5 = √((x + 6)^2 + 9)
Squaring both sides, we get:
25 = (x + 6)^2 + 9
Subtracting 9 from both sides, we get:
16 = (x + 6)^2
Taking the square root of both sides (remembering to include both the positive and negative square root), we get:
x + 6 = ±4
Subtracting 6 from both sides, we get:
x = -10 or x = -2
So the two points on the x-axis that are a distance of 5 from P(-6,3) are (-10, 0) and (-2, 0).
Therefore, the two answers are:
(x, y) = (-10, 0) and (x, y) = (-2, 0)
Answer:
(x, y) = (-10, 0) (smaller x-value)
(x, y) = (-2, 0) (larger x-value)
Step-by-step explanation:
To find the all the points on the x-axis that are a distance of 5 from P(-6, 3), we can use the distance formula.
[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Distance Formula}\\\\$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$\\\\\\where:\\ \phantom{ww}$\bullet$ $d$ is the distance between two points. \\\phantom{ww}$\bullet$ $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.\\\end{minipage}}[/tex]
As the distance is 5, d = 5.
Let (x₁, y₁) = (-6, 3).
As the points to be found are on the x-axis, their y-coordinates are zero.
Therefore, let (x₂, y₂) = (a, 0).
Substitute these values into the distance formula:
[tex]\implies \sqrt{(a-(-6))^2+(0-3)^2}=5[/tex]
Simplify and solve for a:
[tex]\implies \left(\sqrt{(a+6)^2+(-3)^2}\right)^2=5^2[/tex]
[tex]\implies (a+6)^2+9=25[/tex]
[tex]\implies (a+6)^2+9-9=25-9[/tex]
[tex]\implies (a+6)^2=16[/tex]
[tex]\implies \sqrt{(a+6)^2}=\sqrt{16}[/tex]
[tex]\implies a+6=\pm 4[/tex]
[tex]\implies a+6-6=-6\pm 4[/tex]
[tex]\implies a=-10, -2[/tex]
Therefore, the points on the x-axis that are a distance of 5 units from P(-6, 3) are:
(x, y) = (-10, 0) (smaller x-value)(x, y) = (-2, 0) (larger x-value)3. Julia has 7 pennies.
How many more pennies does she
need in order to have the same value
as I dime?
more pennies
The additional number of pennies needed to complete 1 dime is 3
Calculating the additional number of pennies neededFrom the question, we have the following parameters that can be used in our computation:
Pennies = 7
As a general rule
Ten pennies have the same value as 1 dime.
This means that
7 pennies + x = 1 dimes
So, we have
7 pennies + x = 10 pennies
Where x is the additional pennies needed
When evaluated. we have
x = 3
Hence, the additional number of pennies needed is 3
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Please help ASAP math question
The compound amount after 3 years is $2275.22.
In this case, you are given:
Principle = $2,000
rate = 0.0353
time = 3
You need to find A, the compound amount after 3 years.
To do this, you need to plug in the values of P, r and t into the formula and use a calculator:
A=P×e^rt
A=2000×(e)^0.0353×3
A≈2275.22
Therefore, by the compound interest the answer will be $2275.22.
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For a left-tailed test based on a sample of 18 observations with the test statistic t = 1.9, what is the associated p-value?
The associated p-value for this left-tailed t-test is 0.0359 or 3.59%.
Now, The p-value for a one-tailed t-test with a sample size of 18 and a test statistic of 1.9,
Hence, we need to look up the t-distribution table.
So, Using a one-tailed test with,
df = n - 1
= 18 - 1 = 17 degrees of freedom
We find that the area to the left of 1.9 under the curve is 0.0359.
This means that there is a 3.59% probability of observing a t-statistic less than or equal to 1.9 if the null hypothesis is true.
Therefore, the associated p-value for this left-tailed t-test is 0.0359 or 3.59%.
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CVS is having a sale on vitamins You Purchase 2 bottles of multivitamins at $3.75/bottle 1 bottle of vitamin D
Supplement that costs $4.85 and 2 vitamin C Supplement bottles at $2.95/bottle.How much money wauld be left before tax if you had $20 to spend on this purchase?
You would have $1.75 left before tax after purchasing all the vitamins.
Here is how to solve the word problemLet's calculate the total cost of the vitamins first.
From the question, we can deduce the following:1 bottle of multivitamins = $3.751 bottle of vitamin D = $4.851 bottle of vitamin C = $2.95
Now, let's calculate the cost of what you got:2 bottles of multivitamins = 2 x $3.75 = $7.501 bottle of vitamin D = 1 x $4.85 = $4.852 bottles of vitamin C = 2 x $2.95 = $5.90
Total cost of the vitamins is = $7.50 + $4.85 + $5.90 = $18.25
If you have $20 (total amount) to spend on this purchase, after spending, you would have: balance = total amount - total cost balance = $20 - $18.25 balance = $1.75
So you would have $1.75 left before tax after purchasing all the vitamins.
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Which of the following is considered a service in the U.S. economy?
Diesel fuel for trucks
Housekeeping and cleaning
Milk
Bulk health foods
Housekeeping and cleaning are considered a service in the U.S. economy.
Option B is the correct answer.
We have,
A service is an economic activity where an immaterial exchange of value occurs between a producer and a consumer.
It is intangible and does not result in ownership or possession.
Examples of services include housekeeping and cleaning, healthcare, education, transportation, and entertainment. In contrast, goods are physical objects that can be owned or possessed, such as diesel fuel for trucks, milk, and bulk health foods.
Services play a significant role in the U.S. economy, accounting for a substantial portion of the country's gross domestic product (GDP)
Thus,
Housekeeping and cleaning are considered a service in the U.S. economy.
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use the GCF to factor 12+60 PLEASE!!!!!
Answer:
Step-by-step explanation:
Hello! 12+60 does not need to be factored because it is not division. 12 + 60 = 72.
If you meant 12/60, then I can help you.
The factors of 12 are: 1, 2, 3, 4, 6, 12.
The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
From this, we can see the greatest common factor they share is 12.
12/12 is 1, and 60/12 = 5. So, 12/60 = 1/5.
train A and Train B weigh a total of 241 tons train A is heavier than train B the difference of their weigh is 135 tons what is the weight of each train
Answer:
Step-by-step explanation:
If the train was travelling nonstop for 5.5 hours, it would travel approximately 90 km. This can be estimated by observing the graph and finding the corresponding distance for 5.5 hours on the y-axis.
What is graph?
Graph is a data structure composed of nodes (vertices) and edges. It is a non-linear data structure that is used to represent relationships between objects, events, or ideas. Graphs are widely used in computer science, mathematics, engineering, and other fields for representing various types of data. Graphs can be used to represent a wide variety of data sets, including networks, social relationships, and even biological systems. Graphs can also be used to identify patterns, trends, and correlations in data.
The graph below shows the relation between time (hours) and distance (km) for a train trip that lasted from 0 to 7 hours.
The line of best fit is a linear line with a positive slope, indicating that the distance travelled increases as the time spent travelling increases. Therefore, it can be estimated that if the train was travelling nonstop for 5.5 hours, it would travel approximately 90 km. This can be calculated by observing the graph and finding the corresponding distance for 5.5 hours on the y-axis, which is approximately 90 km.
In conclusion, if the train was travelling nonstop for 5.5 hours, it would travel approximately 90 km. This can be estimated by observing the graph and finding the corresponding distance for 5.5 hours on the y-axis.
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Complete questions as follows-
On the grid below, draw a graph of the relationship between and for a trip that lasted from 0to 7 hours. 8Time (hours) If the train was traveling nonstop, how many would it travel in 5.5 hours?
Train A weighs 174.5 tons and Train B weighs 39.5 tons.
Algebraic equations:
To solve the following problem we use Algebraic equations. An algebraic equation is a mathematical statement that uses algebraic symbols (such as variables, constants, and mathematical operations) to express a relationship between two or more quantities.
Since we don't know the weights of each train represent them with two different variables and form two algebraic equations as per the given condition. Solve both equations for the weights of two trains.
Here we have
Train A and Train B weigh a total of 241 tons train A is heavier than Train B the difference in their weight is 135 tons.
Let x be the weight of Train A and y be the weight of Train B in tons.
According to the given data,
=> x + y = 214 tons ---- (1)
=> x - y = 135 tons ---- (2)
Add (1) and (2)
=> x + y + x - y = 214 + 135
=> 2x = 349
=> x = 174.5 tons
From (1)
=> 174.5 - y = 135
=> y = 174.5 - 135
=> y = 39.5
Therefore,
Train A weighs 174.5 tons and Train B weighs 39.5 tons.
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a person invested $6300 for 1 year part at 8% part at 10% and the remainder at 15%. The total annual income from these investments was $773. The amount of money invested at 15% was $300 more than the amounts invested at 8% and 10% combined. Find the amount invested at each rate.
Answer:
8%: $295
10% : $6005
15%: $595
Step-by-step explanation:
The total invested amount was $6300The total annual income from the investments was $773The amount invested at 15% was $300 more than the amounts invested at 8% and 10% combinedLet's break this down:
Let's call the amounts invested at 8% and 10% combined = x
Then call the amount invested at 15% = x + $300
8% of x = 0.08x
10% of (6300 - x) = 0.1(6300 - x)
15% of (x + $300) = 0.15(x + $300)
0.08x + 0.1(6300 - x) + 0.15(x + $300) = $773
0.18x = $53
x = $53/0.18 = $295
a = amount invested at 8%
how much is 8% of "a"? (8/100) * "a", namely 0.08a.
b = amount invested at 10%
how much is 10% of "b"? (10/100) * "b", namely 0.10b.
c = amount invested at 15%
how much is 15% of "c"? (15/100) * "c", namely 0.15c.
we know the total amount invested is 6300, so whatever "a", "b" and "c" might be, we know that a + b + c = 6300.
we also know that the yielded amount in interest is 773, so if we simply add their interest, that'd be 0.08a + 0.10b + 0.15c = 773.
we also know that the combined amounts of "a + b" plus 300 bucks is "c", so really c = a + b + 300.
[tex]c = a + b + 300 \\\\[-0.35em] ~\dotfill\\\\ a+b+c=6300\implies c=6300-a-b\implies \stackrel{\textit{substituting from the equation above}}{a+b+300=6300-a-b} \\\\\\ 2a+2b+300=6300\implies 2a+2b=6000\implies 2(a+b)=6000[/tex]
[tex]a+b=\cfrac{6000}{2}\implies a+b=3000\implies \boxed{b=3000-a} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that}}{c = a + b + 300}\implies \stackrel{\textit{substituting from above}}{c=a+(3000-a)+300}\implies {\Large \begin{array}{llll} c=3300 \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \textit{we also know that} }{0.08a+0.10b+0.15c=773}\implies \stackrel{\textit{now, substituting "b" and "c"}}{0.08a+0.10(3000-a)+0.15(3300)=773}[/tex]
[tex]0.08a+300-0.10a+495=773\implies -0.02a+300+495=773 \\\\\\ -0.02a+795=773\implies -0.02a=-22\implies a=\cfrac{-22}{-0.02}\implies {\Large \begin{array}{llll} a=1100 \end{array}} \\\\\\ \stackrel{\textit{now, we know that}}{b=3000-a}\implies {\Large \begin{array}{llll} b=1900 \end{array}}[/tex]
Mathematics-Session 2
29. The numbers of gallons of gas used by a car and a truck are proportional to the
numbers of miles driven. When 2.5 gallons of gas are used, the car has driven
84.5 miles. The relationship between the number of gallons of gas used and the
number of miles driven for the truck is shown in the table.
Truck
A.
Gallons
of Gas
B.
C.
D.
E.
F.
5.8
6.5
11.0
14.5
Miles
Which statements about the car and the truck are correct?
Select the two correct statements.
The car travels 3.3 more miles per gallon of gas than the truck.
The car travels 5.8 more miles per gallon of gas than the truck.
The car travels 7.1 more miles per gallon of gas than the truck.
To travel 495 miles, the car uses about 2.5 fewer gallons of gas than the truck.
To travel 495 miles, the car uses about 3.3 fewer gallons of gas than the truck.
To travel 495 miles, the car uses about 3.9 fewer gallons of gas than the truck.
154.86
173.55
293.70
387.15
convert 70 degrees to radians
Answer:
This is the formula:
1 degree = π/180 radians
To convert 70 degrees to radians, we can multiply by the conversion factor:
70 degrees × π/180 = 7π/18 radians
So 70 degrees is equal to 7π/18 radians.:)
NO LINKS!! URGENT HELP PLEASE!!!
Part 2b^2
Describe the set of all points P(x, y) in a coordinate plane that satisfy the given condition.
Answer: B, D, A
Step-by-step explanation:
1. In order to be greater than 0 when multiplying 2 numbers they must be the same sign so that happens in quadrant 1 an 3. B
2. y is negative in quadrant 3 and 4 which are below the x-axis. D
3. since x=0 is a line that goes up and down. It' along the y-axis. A
Answer:
(d) Option 2 - The set of all points in quadrants I and III {x and y have the same sign}.
(e) Option 4 - The set of all points below the x-axis.
(f) Option 1 - The set of all points on the y-axis.
Step-by-step explanation:
Question (d)xy > 0 means that the product of x and y is positive.
This is true if both x and y have the same sign (either both positive or both negative).
In quadrant I all points have both a positive x and y coordinate.
In quadrant III all points have both a negative x and y coordinate.
Therefore, the correct answer is:
Option 2 - The set of all points in quadrants I and III {x and y have the same sign}.[tex]\hrulefill[/tex]
Question (e)y < 0 means that y is negative.
All points above the x-axis have a positive y-coordinate.
All points below the x-axis have a negative y-coordinate.
The y-coordinate of all points on the x-axis is equal to zero.
Therefore, the correct answer is:
Option 4 - The set of all points below the x-axis.[tex]\hrulefill[/tex]
Question (f)x = 0 means that x is equal to zero.
All points on the x-axis have:
An x-coordinate of all real values.A y-coordinate of y = 0.All points on the y-axis have:
An x-coordinate of x = 0.A y-coordinate of all real values.The coordinates of the origin are (0, 0).
Therefore, the correct answer is:
Option 1 - The set of all points on the y-axis.What is the explicit equation for the nth term of the arithmetic sequence 7.2, 3.8, 0.4, −3, −6.4, ...?
an = 7.2 − 3.4n
an = 7.2 + 3.4n
an = 7.2 − 3.4(n − 1)
an = 7.2 + 3.4(n + 1)
Answer:
To find the explicit equation for the nth term of an arithmetic sequence, we use the formula:
an = a1 + (n-1)d
where:
an represents the nth term of the sequence
a1 represents the first term of the sequence
d represents the common difference between consecutive terms in the sequence
In this case, we can see that the first term of the sequence is 7.2, and the common difference between consecutive terms is -3.4 (we subtract 3.4 from each term to get to the next term). Therefore, we have:
an = 7.2 + (n-1)(-3.4)
Simplifying this expression gives:
an = 7.2 - 3.4n + 3.4
which can be further simplified to:
an = 10.6 - 3.4n
So the explicit equation for the nth term of the arithmetic sequence 7.2, 3.8, 0.4, −3, −6.4, ... is an = 10.6 - 3.4n.
Step-by-step explanation:
Find the equation of the linear function represented by the table below in slope-intercept form. x y -1 5 2 2 5 -1 8 -4
An equation of the linear function represented by the table below in slope-intercept form is y = -x + 4.
How to determine an equation of this line?In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical expression:
y - y₁ = m(x - x₁)
Where:
x and y represent the data points.m represent the slope.First of all, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (2 - 5)/(2 + 1)
Slope (m) = -3/3
Slope (m) = -1
At data point (2, 2) and a slope of -1, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 2 = -1(x - 2)
y = -x + 2 + 2
y = -x + 4
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greg the trainer has two solo workout plans that he offers his clients: plan a and plan b. each client does either one or the other (not both). on friday there were 3 clients who did plan a and 5 who did plan b. on saturday there were 6 clients who did plan a and 2 who did plan b. greg trained his friday clients for a total of 10 hours and his saturday clients for a total of 10 hours. how long does each of the workout plans last?
The length of time that each workout plan lasts, given the total time that Greg took to train is :
Plan A - 1. 25 hours Plan B - 1. 25 hours How to find the duration ?Assuming the time taken for Plan A is x and the time taken for Plan B is y, the system of equations to represent the time taken per workout is:
3x + 5y = 10
6x + 2y = 10
Using elimination, we can solve for x:
(30 x + 10 y) - ( 6x + 10y ) = 50 - 20
24 x = 30
x = 30 / 24
x = 1.25
Then we can find y to be :
3x + 5y = 10
3 (1. 25 ) + 5 y = 10
y = 6. 25 / 5 = 1.25
In conclusion, both Plan A and Plan B lasts for 1.25 hours.
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An initial sample of 555 g of a radioactive substance decays according to the function
where A(t)=555e^-0.029t
where t is given in years.
(a) How many grams of the substance will remain after 28 years? Round your answer to one decimal place.
Answer=246.40292776
(b) What is the half-life of the substance? Round your answer to one decimal place.
I Dont know how to solve (b) can anyone help me
Answer: 23.9
Step-by-step explanation:
It's asking: after how many years will there be half of the sample remaining?
555e^-0.029t=555/2
Solving this gives you 23.9
1)
A grocer fixed the price of his goods. 25% above the cost price. if he sold a box of noodles allowing 5% discount, find his profit percent.
Let's say the cost price of the box of noodles is x.
The grocer fixed the selling price at 25% above the cost price, which means he sold it for 1.25x.
But he allowed a 5% discount, so the selling price becomes 0.95(1.25x) = 1.1875x.
Now, the profit is the difference between the selling price and the cost price: 1.1875x - x = 0.1875x.
The profit percent is calculated as (profit/cost price) x 100.
So, the profit percent is (0.1875x/x) x 100 = 18.75%.
Therefore, the grocer's profit percent is 18.75%.
PLEASE HURRY DUE TONIGHT
Mary is babysitting a 4-year-old. The little boy wants to play in the kiddie pool in the backyard. Mary knows that using the hose that is near the kiddie pool will take 30 minutes to fill up. The little boy has already asked 17 times if the pool is ready but she hasn't even turned on the water yet. Mary also knows that the hose from the front yard works faster and can fill the pool in 1/2 the time as the hose in the back yard. If she can use both hoses at the same time, how long will it take for the pool to fill up?
(PLEASE SHOW YOUR WORK)(I saw other people get 7.5 min and 75 min but those answers are incorrect.)
A. 5 minutes
B. 10 minutes
C. 22.5 minutes
Using both hoses will take 10 minutes to fill up the kiddie pool. Mary can fill up 1/3 of the pool using the front yard hose in 10 minutes and 1/6 of the pool using the backyard hose in 10 minutes.
To solve this problem, we need to use the concept of rates. Let's assume the rate of the hose in the backyard is x, so the rate of the hose in the front yard is 2x (because it is twice as fast as the other hose).
The combined rate of the two hoses is x + 2x = 3x, which means they can fill the pool in 30/3x = 10/x minutes.
We know that the area of the pool is 600 square feet and each small rock covers 20 square feet, so we need a total of 600/20 = 30 small rocks to cover the pool.
Since the mass of each rock is 20 grams, the total mass of all 30 rocks is 30 x 20 = 600 grams.
To find the density, we divide the total mass (600 grams) by the total volume of the rocks (30 x 20 cubic feet = 600 cubic feet)
Density = 600g / 600 cubic feet = 1g/cubic foot
Therefore, the answer is B. 10 minutes for the pool to fill up, and the density of the rocks is 1 gram per cubic foot.
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Need help in Qa, Qc, Qe and Qf.
With workings for each of the following please, Thank you!!
The expression in the form (x +a)² + b is shown below.
We have to expression given expression in the form (x +a)² + b.
1. x² + 12x
x² + 12x + 36 - 36
= (x +6)² - 36
2. x² + 3x - 2
x² + 2 . 3x /2 - 9/4 + 9/4 -2
(x+ 3/2)² - 17/4
3. x²+ 1/2 x
x² + 2 . 1/4 x + (1/2)² - (1/2)²
= (x+ 1/2)² - 1/4
4. x² - 2/9 x
= x² + 2 . 2/20 x + 4/400 - 4/400
= (x+ 2/200)² - 1/100
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find the product 19.48x0.189 (Don’t round the answer)
[tex]\dfrac{x}{19.48} =0.189[/tex]
[tex]x=0189\times19.48[/tex]
[tex]\boxed{\bold{x=3.68172}}[/tex]
Can someone help me with this please thank you
The areas of the composite figures are:
Case 1: 21 m²
Case 2: 217.5 m²
Case 3: 42 m²
Case 4: 168 cm²
Case 5: 252 m²
Case 6: 27 in²
Case 7: 39 cm²
Case 8: 44 cm²
Case 9: 558
Case 10: 70
Case 11: 78 cm²
Case 12: 21 ft²
How to determine the areas of composite figures
In this problem we need to determine the areas of triangles, rectangles and composite figures formed by adding triangles and rectangles. The area formulas are introduced below:
Triangle
A = 0.5 · b · h
Rectangle
A = b · h
Where:
b - Baseh - HeightThe areas are now determined below:
Case 1:
A = 0.5 · (7 m) · (6 m)
A = 21 m²
Case 2:
A = (9 m) · (15 m) + 0.5 · (11 m) · (15 m)
A = 217.5 m²
Case 3:
A = 0.5 · (7 m) · (12 m)
A = 42 m²
Case 4:
A = 2 · 0.5 · (6 cm) · (8 cm) + 2 · 0.5 · (15 cm) · (8 cm)
A = 168 cm²
Case 5:
A = 2 · 0.5 · (7 m) · (9 m) + 2 · 0.5 · (21 m) · (9 m)
A = 252 m²
Case 6:
A = (9 in) · (2 in) + (3 in)²
A = 27 in²
Case 7:
A = (9 cm) · (3 cm) + (6 cm) · (2 cm)
A = 39 cm²
Case 8:
A = (4 cm) · (5 cm) + (2 cm) · (3 cm) + (3 cm) · (6 cm)
A = 44 cm²
Case 9:
A = 2 · 0.5 · 10 · 18 + 18 · 21
A = 558
Case 10:
A = 14 · 5
A = 70
Case 11:
A = (12 cm) · (6.5 cm)
A = 78 cm²
Case 12:
A = (3 ft) · (5 ft) + (3 ft) · (2 ft)
A = 21 ft²
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The attendance for the last
years at a county fair is shown in the table.
This year, the first
of people attending the fair will receive a raffle ticket. Of the people who receive raffle tickets,
will receive a small prize.
• Based on the data in the table, determine a reasonable estimate of the number of people who will attend this year's fair. Explain how you found your estimate.
• Use your estimate to find the approximate number of people who will receive a small prize at this year's fair.
• Show your work or provide an explanation of how you found the approximate number of people who will receive a small prize at this year's fair.
Enter your answers and your work or explanations in the box provided.
The approximate number of people who will receive a small prize at this year's fair is 12,000.
What is number?
A number is a mathematical concept used to represent a quantity or value. It can be represented by numerals, symbols, or words.
To estimate the number of people who will attend this year's fair, we can calculate the average attendance of the last 5 years:
Average attendance = (270,000 + 280,000 + 300,000 + 320,000 + 330,000) / 5
= 300,000
Therefore, a reasonable estimate of the number of people who will attend this year's fair is 300,000.
To find the approximate number of people who will receive a small prize at this year's fair, we need to multiply the number of people who receive raffle tickets by the proportion of those who will receive a small prize:
Number of people who will receive a small prize = 60,000 x 0.2
= 12,000
Therefore, the approximate number of people who will receive a small prize at this year's fair is 12,000.
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The student council consists of 10 juniors and 12 seniors. If two members are voted to be officers, what is the probability they are both seniors? Round to two decimal places
The probability that both officers will be seniors is 0.29 or 29%.
There are a total of 22 council members.
To find the probability that both officers are seniors, we need to find the probability of selecting a senior for the first officer and then a senior for the second officer.
The probability of selecting a senior for the first officer is 12/22 since there are 12 seniors out of 22 total members.
After one senior has been selected, there are only 11 seniors left out of a total of 21 remaining members.
Therefore, the probability of selecting another senior for the second officer is 11/21.
To find the probability of both events occurring together, we multiply the probabilities:
P(selecting 2 senior officers) = (12/22) x (11/21) = 0.287 or 0.29 (rounded to two decimal places).
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Find the equation of the linear relationship.
The equation of the linear relationship is y = 232x
We know that the general equation of the linear function is y = mx + c.
m is the slope of the line
x₁ = 2, y₁ = 464
x₂ = 15, y₂ = 3,480
The formula for Slope of the line = (y₂ - y₁)/(x₂ - x₁)
= (3480 - 464)/(15 - 2)
= 3016/13
= 232
The equation of a line
(y - y₁) = m(x - x₁)
(y - 464) = 232(x - 2)
y - 464 = 232x - 464
y = 232x
Therefore, the equation of the linear relationship is y = 232x
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2x - 4y = 6
2x+4y=-10
The system when solved is:
(-1,-4).
(-1,-2).
(2,4).
(1,-2).
Answer:
The correct answer is the second option: (-1,-2).
Step-by-step explanation:
To solve the system of equations:
2x - 4y = 6
2x + 4y = -10
We can use the method of elimination to eliminate one of the variables. Adding the two equations, we get:
4x = -4
Solving for x, we get:
x = -1
Substituting x = -1 in the first equation, we get:
2(-1) - 4y = 6
Simplifying, we get:
-2 - 4y = 6
Subtracting 2 from both sides, we get:
-4y = 8
Dividing by -4 on both sides, we get:
y = -2
Therefore, the solution to the system of equations is (-1, -2). So, the correct answer is (2nd option): (-1, -2).
En casa de la profesora Mary son muy aficionados a la lectura. Tienen un total de 300 libros de crecimiento personal, 90 novelas clásicas, 6 libros de terror y 180 novelas románticas. Mary ha pensado en hacer montones iguales de libros con los cuatro estilos para colocarlos en estanterías distintas. ¿Cuál es el mayor número de montones que puede hacer y de cuántos libros?
The total number of books in all the piles is 4 x 72 = 288.
What is the prime factor about?For one to be able to create the equal stacks of books in all of the four styles, one need to look at the greatest common divisor (GCD) .
Hence the GCD of 300, 90, 6, and 180:
300 = 2² x 3 x 5²
90 = 2 x 3² x 5
6 = 2 x 3
180 = 2² * 3² *x 5
The GCD is 2² x 3² = 36.
In terms of the number of piles, we have to divide the total number of books in all of the style by the GCD: Hence:
300 ÷ 36 = 8.33...
90 ÷ 36 = 2.5
6 ÷ 36 = 0.17...
180 / ÷ 36 = 5
For one to be able to find the total number of books in all of pile, we need to multiply the GCD by the number of piles:
36 x 2 = 72
Hence, each pile will need to contain 72 books. The total number of books in all the piles is 4 x 72 = 288.
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what is the slope of the line that passes through (-2,5) and (3,-5)
Answer:
slope = - 2
Step-by-step explanation:
calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (3, - 5 )
m = [tex]\frac{-5-5}{3-(-2)}[/tex] = [tex]\frac{-10}{3+2}[/tex] = [tex]\frac{-10}{5}[/tex] = - 2
mDE
Q D E
8.73 in
10 in
The measure of the arc angle DE is derived to be 46.5055° using the arc length of the sector.
How to evaluate for the measure of the the arc angle DEThe arc measure DE and the angle it subtends at the center of the circle are directly proportional.
so arc DE = m∠DQE {central angle}
Arc length of the sector = (central angle / 360) x (2 x π x radius)
8.73 in = (m∠DQE / 360) x (2 x 22/7 x 10 in)
m∠DQE = (8.13 in × 360 × 7)/(2 × 22 × 10) {cross multiplication}
m∠DQE = 46.5055° = arc DE
Therefore, the measure of the arc angle DE is derived to be 46.5055° using the arc length of the sector.
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I need help with this problem if do thank you a lot
The first circle have the values of x = 89° and y = 8.49. The second circle have values of x = 132° and y = 15.72. And the third circle have the value of a = 8.67.
What are circle theoremsCircle theorems are a set of rules that apply to circles and their constituent parts, such as chords, tangents, and arcs. These rules describe the relationships between the different parts of a circle and can be used to solve problems involving circles.
For the first circle:
28° = x - 61° {secant tangent angle}
x = 28° + 61°
x = 89°
y² = 4 × 18
y = √72
y = 8.4853
For the second circle:
triangles formed by intersecting tangents are congruent so;
x = 2 × [180 - (24 + 90)]
x = 2 × 66°
x = 132°
tan 24 = 7/y {opposite/adjacent}
y = 7/tan 24
y = 15. 7223
For the third circle:
9(9 + a) = 21 × 8 {secant secant}
81 + 9a = 168
9a = 168 - 81
9a = 87
a = 87/9
a = 9.6667.
Therefore, the first circle have the values of x = 89° and y = 8.49. The second circle have values of x = 132° and y = 15.72. And the third circle have the value of a = 8.67.
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trapezoid is shown.
4m
4 m
3 m
What is the area of the trapezoid?
O 11 m²
O 12 m²
O 14 m²
O16 m²
Answer:
The area of a trapezoid can be calculated as:
Area = (1/2) × (sum of bases) × (height)
In this case, the sum of the bases is 4m + 3m = 7m, and the height is 4m. Therefore:
Area = (1/2) × 7m × 4m = 14m²
So the area of the trapezoid is 14 m². The answer is O 14 m².