Ellason wants to solve the following system using the elimination method:

5x + 2y = 30
x + y = 8

What number should the equation x + y = 8 be multiplied by to eliminate y?

2
−2
5
−5

a) The mean of the data-set is of 2 hours.

b) The mean absolute deviation of the data-set means that the measures vary by an average amount of 0.93 hours from the mean.

The dot plot gives a dot to each measure for each time that it appears, hence it says the same thing as a table, in a different format.

The sum of the fifteen observations in this problem is given as follows:

0 x 1 + 1 x 5 + 2 x 3 + 3 x 5 + 4 x 1 = 30.

The mean of the data-set is given as the sum of all the observations divided by the number of values, hence:

30/15 = 2.

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The homeowner should put aside $375.30 each month in order to save up for these expenses. Rounded to the nearest cent, this is $375.31.

The question asks us to determine how much a homeowner should put aside each month in order to save up for property taxes, homeowner's insurance, and car insurance expenses that come up every six months and annually.

To solve this problem, we can add up the total cost of all these expenses and divide by the number of months in a year, then round to the nearest cent.
Let's begin by finding the total cost of all these expenses. The homeowner pays property taxes twice a year, so that's a total cost of $1470 x 2 = $2940. The homeowner's insurance is paid once per year, with a cost of $918. The car insurance is paid twice a year, with costs of $285.78 + $359.79 = $645.57.
Adding up all these costs, we get: $2940 + $918 + $645.57 = $4503.57.
To determine how much to put aside each month, we divide this total by 12 (the number of months in a year): $4503.57 ÷ 12 = $375.30.

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Answer:

x = 13

Step-by-step explanation:

Since [tex]\angle M\cong \angle Y[/tex], then we set the angles equal to each other:

[tex]m\angle M=m\angle Y\\52^\circ=(4x)^\circ\\52=4x\\13=x[/tex]

Therefore, x=13

Answer:

  40.45°

Step-by-step explanation:

You want the angle opposite the side of length 13 ft in a triangle with the other sides being 16 ft and 20 ft.

The law of cosines tells you ...

  c² = a² +b² -2ab·cos(C)

Then angle C is ...

  C = arccos((a² +b² -c²)/(2ab))

In the given triangle, this is ...

  C = arccos((16² +20² -13²)/(2·16·20)) = arccos(487/640) ≈ 40.453°

The measure of angle θ is about 40.45°.

<95141404393>

Answer:

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

it's a property of powers, when the base is the same (-5) , you need to

sum the powers when both terms are multiplyng

subtract the powers when both terms are dividing (numerator power minus denominator power, in that order)

The variance of the data-set in this problem is given as follows:

σ² = 366.3.

The variance of a data-set is calculated as the sum of the differences squared between each observation and the mean, divided by the number of values.

The mean for this problem is given as follows:

205.

Hence the sum of the differences squared is given as follows:

SS = (198 - 205)² + (190 - 205)² + (245 - 205)² + (211 - 205)² + (193 - 205)² + (193 - 205)²

SS = 2198.

There are six values, hence the variance is given as follows:

σ² = 2198/6

σ² = 366.3

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The equation of the line perpendicular to  y = 2 / 3 x - 4 and passes through (6, -2) is y = - 3 / 2x + 7.

The equation of a line can be represented in slope intercept form as follows:

y = mx + b

where

The slopes of perpendicular lines are negative reciprocals of one another.

Therefore, the slope of the line perpendicular to y = 2 / 3 x - 4 is - 3 / 2.

Hence, let's find the line as its passes through (6, -2).

Therefore,

y = - 3 / 2 x + b

-2 = - 3 / 2(6) + b

-2  = -9 + b

b = -2 + 9

b = 7

Therefore, the equation of the line is y = - 3 / 2x + 7.

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Answer:

Let's denote the amount of the short-term note as x and the amount of the long-term note as y. We know that:

1. The total amount of the property is $145,000, so x + y = $145,000.

2. The total annual interest is $11,650, which is the sum of the interest from the short-term note (9% of x) and the long-term note (7% of y). So, 0.09x + 0.07y = $11,650.

We now have a system of two equations that we can solve to find the values of x and y.

Let's solve this system of equations:

1. Multiply the first equation by 0.07: 0.07x + 0.07y = $10,150.

2. Subtract this from the second equation: 0.02x = $1,500.

3. Solve for x: x = $1,500 / 0.02 = $75,000.

Substitute x = $75,000 into the first equation to find y:

$75,000 + y = $145,000

y = $145,000 - $75,000 = $70,000.

So, the short-term note is $75,000, and the long-term note is $70,000.

The output when the input is 8 in the given number machine is 1.

The given number machine input is - x5 - -2 - output. Now, we have to find the output when the input is 8. Let's understand how we can solve this problem.

What is a number machine? The numbering machine is an imaginary box or machine that takes in a number and does a specific task on it to produce an output.

This concept is usually taught to children in primary grades. It is a fun way to introduce basic mathematical operations such as addition, subtraction, multiplication, and division.

The machine we are dealing with here subtracts the input by 5 and then subtracts 2 from the result to get the output. We can write this as output = (input - 5) - 2 Now we have to find out what the output would be when the input is 8. We can substitute 8 into the formula to get: output = (8 - 5) - 2 Simplifying this, we get: output = 3 - 2output = 1

Therefore, the output when the input is 8 in the given number machine is 1.

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The graph of h(x) = (x-1)^2 - 9 is a U-shaped parabola that opens upwards, with the vertex at (1, -9), and it extends indefinitely in both directions.

The function h(x) = (x-1)^2 - 9 represents a quadratic equation. Let's analyze the different components of the equation to understand the behavior of the graph.

The term (x-1)^2 represents a quadratic term. It indicates that the graph will have a parabolic shape. The coefficient in front of the quadratic term (1) implies that the parabola opens upwards.

The constant term -9 shifts the graph downward by 9 units. This means the vertex of the parabola will be at the point (1, -9).

Based on this information, we can draw the following conclusions:

The graph will be a U-shaped curve with the vertex at (1, -9).

The vertex represents the minimum point of the parabola since it opens upward.

The parabola will be symmetric with respect to the vertical line x = 1 since the coefficient of the quadratic term is positive.

The graph will extend indefinitely in both directions.

To accurately plot the graph, you can choose several x-values, substitute them into the equation to find the corresponding y-values, and then plot the points on the graph. Alternatively, you can use graphing software or calculators that can plot the graph of the equation for you.

Remember to label the axes and indicate the vertex at (1, -9) to provide a complete representation of the graph of h(x) = (x-1)^2 - 9.

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The errors in the proposed statement to prove by contradiction that 3·√2 - 7 is an irrational number, is the option;

Proving by contradiction is an indirect method of proving a fact or a reductio ad absurdum, which is a method of proving a statement by the assumption that the opposite of the statement is true, then showing that a contradiction is obtained from the assumption.

The definition of rational numbers are numbers that can be expressed in the form a/b, where a and b are integers

The assumption that 3·√2 - 7 is a rational number indicates that we get;

3·√2 - 7 = a/b, where a and b are integers

Therefore, the error in the method used to prove that 3·√2 - 7 is an irrational number is the option; To apply the definition of rational, a and b must be integers. This is so as the value 3·√2 - 7 is a real number, which is also an irrational number, thereby contradicting the supposition.

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There are infinitely many solutions for a and b that satisfy the given conditions, as long as they satisfy the above equations.

To solve this problem, we need to use the concepts of tangent and normal lines to a circle.

First, we find the equation of the given circle[tex]x^2+y^2-2x=5/3[/tex]. Completing the square, we get [tex](x-1)^2+y^2=8/3[/tex].

To find the tangent line to this circle that is also normal to the circle [tex]x^2+y^2+2x-4y+1=0[/tex], we need to first find the point of intersection between the two circles.

By solving the simultaneous equations of the two circles we obtain the point of intersection [tex](-1/2, y=\sqrt(11/12))[/tex].

We then find the gradient of the tangent at this point by differentiating the equation of the circle x^2+y^2-2x=5/3. At the point (-1/2, √(11/12)), the gradient of the tangent is m = 1/√(33/4).

Since the tangent line is also normal to the circle x^2+y^2+2x-4y+1=0, its gradient is the negative reciprocal of the gradient of the tangent at the point of intersection, which is m'= -√(33/4).

Using the point-gradient form of a straight line, we can then write the equation of the tangent line as y-√(11/12) = (-√(33/4))(x+1/2).

To find the values of a and b that satisfy this equation of the tangent line and also the equation ax+by+c=0, we substitute the expression for y in terms of x into the second equation:

a(x)-b(√(33/4))(x+1/2)+c= 0 (ax-b(√33/4)x)+(-b(√33/4)/2+a)+c=0

We now compare the coefficients of x and constants in each equation

ax-b(√33/4)x = 0 -b(√33/4)/2+a+c = 0

We now have a system of two equations in two unknowns (a and b). Solving this system of equations we get a = (b√33/4) - 2c and plugging this into the second equation we get b = c/√(33/4).

Therefore, there are infinitely many solutions for a and b that satisfy the given conditions, as long as they satisfy the above equations.

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a) The particle is farthest to the left at t = 0.

b) The speed of the particle is decreasing at t = π.

c) The value of k is 2π.

a) To find the time at which the particle is farthest to the left, we need to determine when the particle's position is at its minimum on the x-axis. The position function x(t) = [tex]e^t^2 cos(t^2)[/tex] represents the particle's position at time t.

To find the minimum, we can take the derivative of x(t) with respect to t and set it equal to zero. Let's differentiate x(t) to find the velocity function v(t):

v(t) = [tex](1/2)e^t^2 (cos(t^2) - sin(t^2))[/tex]

Next, we solve the equation v(t) = 0 to find the critical points:

0 = [tex](1/2)e^t^2 (cos(t^2) - sin(t^2))[/tex]

Since [tex]e^t^2[/tex] is always positive, the critical points occur when cos([tex]t^2[/tex]) - sin([tex]t^2[/tex]) = 0. By solving this equation, we find that it is true for t = 0 and t = π/2.

Now, to determine which critical point corresponds to the particle being farthest to the left, we evaluate the positions at t = 0 and t = π/2:

x(0) = [tex]e^0^2 cos(0^2)[/tex]= 1 * 1 = 1

x(π/2) = e(π/[tex]2)^2[/tex] cos((π/[tex]2)^2[/tex]) = [tex]e^{(\pi ^{2/4)[/tex] * 0 = 0

The particle is farthest to the left when x(0) = 1. Therefore, the particle is farthest to the left at t = 0.

b) To determine if the speed of the particle is increasing or decreasing at t = π, we need to analyze the velocity function v(t).

Let's calculate the derivative of v(t) with respect to t to find the acceleration function a(t):

a(t) = [tex]d(v(t))/dt[/tex] = [tex]d^2x(t)/dt^2[/tex] = [tex]e^t^2 * (-2t^2[/tex] - 2) * [tex]sin(t^2)[/tex]

To determine if the speed is increasing or decreasing, we need to evaluate a(t) at t = π. Plugging in t = π into the acceleration function, we have:

a(π) = [tex]e^\pi ^2 * (-2\pi ^2[/tex] - 2) * si[tex]n(\pi ^2[/tex]) = [tex]e^\pi ^2 * (-2\pi ^2[/tex] - 2) * 0 = 0

Since the acceleration at t = π is zero, the speed of the particle is neither increasing nor decreasing at that time.

c) The total distance traveled by the particle can be calculated by integrating the absolute value of the velocity function v(t) with respect to t over the interval [0, 2π]. The expression given is:

∫ v(t) dt from 0 to k − ∫ v(t) dt from 0 to 2π

To find the value of k, we can evaluate the integral on the right side:

∫ v(t) dt from 0 to 2π = ∫ [(1/[tex]2)e^t^2[/tex] (co[tex]s(t^2[/tex]) - [tex]sin(t^2[/tex]))] dt from 0 to 2π

Evaluating this integral gives us the total distance traveled by the particle over the interval [0, 2π]. Since k represents a different upper limit, the integral from

0 to k will give us the distance traveled up to the time t = k.

To find the value of k, we need to find the total distance traveled. Since the integral from 0 to 2π represents the total distance, we have k = 2π.

Therefore, the value of k is 2π.

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From the first equation you can get that -2x = 36 + 2t; and after adding those equations to each other we get that y - 2x = 3 - 2t + 36 + 2t = 39; y = 2x + 39.

The answer is 2x + 39.

Answer:

Step-by-step explanation:

Answer:

10[tex]\sqrt{2}[/tex]

Step-by-step explanation:

√200 = √(2 × 2 × 2 × 5 × 5)

√200 = (√2)2× (√5)2× √2

√200 = 10√2

Answer:

The square root of 200 in its simplest form is 10√2 is the answer.

This can be done if we know the prime factorization of a number we can right the radical form of the square root of that number.

As a result the prime factorization of 200 is 2×2×2×5×5 so in that way the simplest form of square root of 200 is 10√2.

Step-by-step explanation:

Answer:

B, No solution

Step-by-step explanation:

If two lines are graphed, the point they intersect is the solution. However, if the slope is the same, they will never intersect

In the first and second equation, the slopes are both 3 so they will never intersect.

The given statement "There is no tax jump from 0.33E − 15,207.50 to 0.35E − 21,346.50" is false.

The tax jump from 0.33E − 15,207.50 to 0.35E − 21,346.50 is not zero. Let us look at how this is not true.

Firstly, 0.33E − 15,207.50 and 0.35E − 21,346.50 are both amounts of tax that need to be paid. E here stands for exponential notation of the number 10.

For example, 0.33E − 15,207.50 = 0.33 x 10 ^ -15,207.50.

This means that 0.33E − 15,207.50 is 0.33 multiplied by 10 raised to the power of -15,207.50.

Similarly, 0.35E − 21,346.50 = 0.35 x 10 ^ -21,346.50 which means 0.35E − 21,346.50 is 0.35 multiplied by 10 raised to the power of -21,346.50.

It is important to note that the power of E in 0.35E − 21,346.50 is higher than that of 0.33E − 15,207.50. This means that the second tax amount is lower than the first.

However, the tax jump from 0.33E − 15,207.50 to 0.35E − 21,346.50 is still not zero. A tax jump is the difference in the amount of tax paid between two different amounts.

Therefore, the difference between the two taxes is:

= 0.35 x 10 ^ -21,346.50 - 0.33 x 10 ^ -15,207.50

= 0.002E-2134650 - 0.0033E-1520750

= 0.00000167 - 0.000033 = -0.00003133

The tax jump is equal to 0.00003133 which is not zero.

Therefore, the given statement is false.

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A tessellation is a pattern made by repeating geometric shapes without any gaps or overlaps. These shapes, called tiles or polygons, fit together perfectly to cover a plane or a surface. Tessellations can be found in various forms of art, architecture, and design. They are used to create visually appealing patterns and decorations, as well as to explore mathematical concepts.

Tessellations are utilized in various practical applications, such as tiling floors, walls, and pavements, designing mosaics and quilts, and creating computer graphics and textile patterns. They are also studied in mathematics to understand concepts like symmetry, geometry, and transformations.

For polygons to tessellate, certain conditions must be met at their vertices. At each vertex, the angles formed by the polygons must add up to a whole number of degrees, typically 360 degrees. In other words, the sum of the interior angles of each polygon meeting at a vertex must be a multiple of 360 degrees.

This ensures that the polygons can fit together seamlessly without leaving any gaps or overlaps. Examples of polygons that tessellate include equilateral triangles, squares, and hexagons, as their angles add up to 360 degrees at each vertex.

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Test for Proportion Hypothesis Conclusion: There is not sufficient evidence to conclude that more than 1.6% of this drug's users experience flulike symptoms as a side effect at the 0.05 level of significance.

To determine if there is sufficient evidence to conclude that more than 1.6% of this drug's users experience flulike symptoms as a side effect, we can perform a hypothesis test.

Let's define the null and alternative hypotheses:

Null hypothesis (H₀): The proportion of this drug's users experiencing flulike symptoms is 1.6% or less.

Alternative hypothesis (H₁): The proportion of this drug's users experiencing flulike symptoms is greater than 1.6%.

We can use the normal approximation to the binomial distribution since the sample size is large (846 patients) and the expected number of successes (flulike symptoms) is greater than 5.

First, let's calculate the expected number of patients experiencing flulike symptoms if the proportion is 1.6%:

Expected number = (proportion) * sample size = 0.016 * 846 = 13.536

Now, let's calculate the test statistic (Z-score):

Z = (observed number of successes - expected number of successes) / sqrt(expected number of successes * (1 - proportion))

Z = (17 - 13.536) / sqrt(13.536 * (1 - 0.016))

Z = 3.464 / sqrt(13.536 * 0.984) ≈ 3.464 / sqrt(13.316)

Z ≈ 3.464 / 3.648 ≈ 0.950

The test statistic (Z) is approximately 0.950.

Next, we need to find the p-value associated with this test statistic. Since the alternative hypothesis is one-tailed (we're testing if the proportion is greater than 1.6%), we'll find the p-value corresponding to the area to the right of the observed test statistic.

Using a standard normal distribution table or a calculator, we find that the area to the right of Z = 0.950 is approximately 0.1711.

Therefore, the p-value is approximately 0.1711.

Finally, let's compare the p-value with the significance level (α = 0.05). Since the p-value (0.1711) is greater than the significance level (0.05), we do not have sufficient evidence to conclude that more than 1.6% of this drug's users experience flulike symptoms as a side effect at the 0.05 level of significance.

In summary:

Test statistic (Z) ≈ 0.950

P-value ≈ 0.1711

Test for Proportion Hypothesis Conclusion: There is not sufficient evidence to conclude that more than 1.6% of this drug's users experience flulike symptoms as a side effect at the 0.05 level of significance.

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The values into the slope-intercept form, we have y = -5x - 6

The slope-intercept form of a linear equation is given by:

y = mx + b

where 'm' represents the slope of the line, and 'b' represents the y-intercept.

In this case, the y-intercept is (0, -6), which means that the line crosses the y-axis at the point (0, -6).

The slope is given as -5.

Therefore, substituting the values into the slope-intercept form, we have:

y = -5x - 6

This equation represents the line with a y-intercept of (0, -6) and a slope of -5.

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The 95% confidence interval for the effectiveness of the blood-pressure drug is given as follows:

[tex]22.6 < \mu < 24.4[/tex]

The mean, the standard deviation and the sample size for this problem, which are the three parameters, are given as follows:

[tex]\overline{x} = 23.5, \sigma = 12.2, n = 775[/tex]

Looking at the z-table, the critical value for a 95% confidence interval is given as follows:

z = 1.96.

The lower bound of the interval is then given as follows:

[tex]23.5 - 1.96 \times \frac{12.2}{\sqrt{775}} = 22.6[/tex]

The upper bound of the interval is then given as follows:

[tex]23.5 + 1.96 \times \frac{12.2}{\sqrt{775}} = 24.4[/tex]

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Answer:

169

Step-by-step explanation:

360-[36+160]-36

360-160-72

169

The yield to maturity for the ABC Inc. bonds is 4.95%.

The yield to maturity (YTM) represents the effective interest rate that an investor would earn if they hold the bond until its maturity date.

To calculate the YTM for the ABC Inc. bonds, we need to find the interest rate that equates the present value of the bond's cash flows (coupon payments and par value) to its current price.

Given that the bond has a $1,000 par value and an 8.40% coupon rate, it pays a coupon of $42 (8.40% × $1,000 / 2) semi-annually for 18 years, totaling 36 coupon payments. At maturity, the bond will also repay the par value of $1,000.

To calculate the YTM, we can use a financial calculator or a spreadsheet software. By inputting the cash flows and solving for the interest rate, we find that the YTM is approximately 4.95% (rounding to two decimal points).

Therefore, the yield to maturity for the ABC Inc. bonds is 4.95%.

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Answer:

  (d)  5/8 in

Step-by-step explanation:

You want the measure indicated by the compass points in the figure.

The largest mark between the end of the ruler and the mark labeled 1 is at the 1/2 inch point. The compass is to the right of that.

The mark halfway between the 1/2 inch mark and the 1 inch mark is 3/4 inches. The compass is to the left of that.

The mark halfway between 1/2 inch and 3/4 inch is 5/8 inch. The compass seems to be nearer this mark than it is to the 1/2 inch mark.

The measure of the distance between compass points is about 5/8 inch.

<95141404393>

There is no solution in the system

From the question, we have the following parameters that can be used in our computation:

The augmented matrix

In the augmented matrix, we have

Rows = 2

Columns = 4

This means that

there are 2 equations in the system and there are 3 variables

The general rule is that

The number of variables must be equal to or less than the number of equations

Hence, there is no solution in the system

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The amount of money in your account after 4 years would be $541.22.

We might utilize the accompanying recipe to work out how much money will be in your ledger following four years with a 2% yearly funding cost:

A = P(1 + r)ᵗ

Where:

A is the final amount.

P is the principal amount(initial deposit).

r means the interest rate (in decimal structure).

t is the number of years

Given:

P = $500

r = 2% = 0.02 (expressed as a decimal)

t = four years

Associating these qualities to the situation:

A = $500(1 + 0.02)⁴

Making the condition:

A = $500(1.02)⁴

A = $500(1.082432)

A ≈ $541.22

Subsequently, following four years, the cash in your ledger would be around $541.22.

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Answer:

[tex]\text{Midpoint of $AC$}=\left(-2,2\right)[/tex]

[tex]\text{Midpoint of $AB$}=\left(\dfrac{5}{2},3\right)[/tex]

[tex]\text{Slope of midsegment}=\dfrac{2}{9}[/tex]

[tex]\text{Slope of $AC$}=3[/tex]

[tex]\text{Slope of $BC$}=\dfrac{2}{9}[/tex]

[tex]\text{Length of midsegment}=\dfrac{\sqrt{85}}2[/tex]

[tex]\text{Length of $BC$}=\sqrt{85}[/tex]

Step-by-step explanation:

Given points:

To determine the midpoints of AC and AB, substitute the given points into the midpoint formula.

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Midpoint between two points}\\\\Midpoint $=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the endpoints.\\\end{minipage}}[/tex]

[tex]\begin{aligned}\text{Midpoint of $AC$}&=\left(\dfrac{x_C+x_A}{2},\dfrac{y_C+y_A}{2}\right)\\\\&=\left(\dfrac{-3-1}{2},\dfrac{-1+5}{2}\right)\\\\&=\left(\dfrac{-4}{2},\dfrac{4}{2}\right)\\\\&=\left(-2,2\right)\end{aligned}[/tex]

[tex]\begin{aligned}\text{Midpoint of $AB$}&=\left(\dfrac{x_B+x_A}{2},\dfrac{y_B+y_A}{2}\right)\\\\&=\left(\dfrac{6-1}{2},\dfrac{1+5}{2}\right)\\\\&=\left(\dfrac{5}{2},\dfrac{6}{2}\right)\\\\&=\left(\dfrac{5}{2},3\right)\end{aligned}[/tex]

[tex]\hrulefill[/tex]

[tex]\boxed{\begin{minipage}{8cm}\underline{Slope Formula}\\\\Slope $(m)=\dfrac{y_2-y_1}{x_2-x_1}$\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.\\\end{minipage}}[/tex]

To determine the slope of the midsegment, substitute the midpoints of AC and AB into the slope formula:

[tex]\begin{aligned}\text{Slope of midsegment}&=\dfrac{y_{AB}-y_{AC}}{x_{AB}-x_{AC}}\\\\&=\dfrac{2-3}{-2-\frac{5}{2}}\\\\&=\dfrac{-1}{-\frac{9}{2}}\\\\&=\dfrac{2}{9}\end{aligned}[/tex]

Therefore, the slope of the midsegment is 2/9.

To find the slope of AC, substitute the points A and C into the slope formula:

[tex]\begin{aligned}\text{Slope of $AC$}&=\dfrac{y_{C}-y_{A}}{x_{C}-x_{A}}\\\\&=\dfrac{-1-5}{-3-(-1)}\\\\&=\dfrac{-6}{-2}\\\\&=3\end{aligned}[/tex]

Therefore, the slope of the AC is 3.

**Note** There may be an error in the question. I think you are supposed to find the slope of BC (not AC) since there is no relationship between the slopes of the midsegment and AC, but there is a relationship between the slopes of the midsegment and BC.  

[tex]\begin{aligned}\text{Slope of $BC$}&=\dfrac{y_{C}-y_{B}}{x_{C}-x_{B}}\\\\&=\dfrac{-1-1}{-3-6}\\\\&=\dfrac{-2}{-9}\\\\&=\dfrac{2}{9}\end{aligned}[/tex]

The slope of BC is 2/9, so the slopes of the midsegment and BC are the same. This implies that the midsegment and BC are parallel.

[tex]\hrulefill[/tex]

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Distance Formula}\\\\$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$\\\\\\where:\\ \phantom{ww}$\bullet$ $d$ is the distance between two points. \\\phantom{ww}$\bullet$ $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.\\\end{minipage}}[/tex]

To find the length of the midsegment, substitute the endpoints (-2, 2) and (5/2, 3) into the distance formula:

[tex]\begin{aligned}\text{Length of midsegment}&=\sqrt{\left(\frac{5}{2}-(-2)\right)^2+(3-2)^2}\\\\&=\sqrt{\left(\frac{9}{2}\right)^2+(1)^2}\\\\&=\sqrt{\frac{81}{4}+1}\\\\&=\sqrt{\frac{85}{4}}\\\\&=\dfrac{\sqrt{85}}2\end{aligned}[/tex]

To find the length of the BC, substitute points B and C into the distance formula:

[tex]\begin{aligned}\text{Length of $BC$}&=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\&=\sqrt{(-3-6)^2+(-1-1)^2}\\&=\sqrt{(-9)^2+(-2)^2}\\&=\sqrt{81+4}\\&=\sqrt{85}\end{aligned}[/tex]

Therefore, the length of BC is twice the length of the midsegment.

Answer:

X=20

Step-by-step explanation:

20 On one side and the other side are mirror so

is 40

120-40=80

Both the top and lower triangles are similar which will be half divided

40 each scare now divide again for 2 parts of x

x=20

Answer:

a rectangle, because it has 2 pairs of parallel sides

Step-by-step explanation:

A parallelogram is a two-dimensional figure with two sets of parallel lines and equal opposite-interior angles. A hexagon has too many sides to qualify, trapezoids only have one set of parallel lines, and quadrilaterals can have anywhere from 0 to 2 sets of parallel sides. Because of this, these three other options are eliminated

A rectangle is always a parallelogram because, by definition, a parallelogram is a four-sided plane rectilinear figure with opposite sides parallel which fits the description of a rectangle.

The correct answer to which shape is always a parallelogram is a rectangle, because it has 2 pairs of parallel sides. By definition, a parallelogram is a four-sided plane rectilinear figure with opposite sides parallel. This means that a quadrilateral with two sets of parallel sides is a parallelogram, which fits the description of a rectangle. Other options like hexagon and trapezoid do not always adhere to this definition and hence can't be considered as a parallelogram.

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