The expression for the total time of flight when the object is released from ground level is t = (2u sinθ ) / ( g ).
What is the expression for total time of flight?The expression for the total time of flight is calculated by applying second kinematic equation as shown below.
when the object is released from a height, h
h = vt + ¹/₂gt²
where;
h is the height of fall of the objectv is the initial vertical velocity of the objectg is acceleration due to gravityt is the time of flightwhen the object is released from ground level,
t = (2u sinθ ) / ( g )
where
u is the initial velocityθ is the direction of the velocityg is acceleration due to gravityThus, the time of flight of an object is the total time spent in air by the object.
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A truck weighs twice as much as a car, and is moving at twice the speed of the car
The kinetic energy of an object increases as the mass and speed increases. Here, the truck weighs twice that of car and has a twice speed then it has a kinetic energy 8 times greater than the car.
What is kinetic energy ?Kinetic energy is form of energy generated by virtue of the motion of the object. It is related to the mass and velocity of the object by the expression below:
Ke = 1/2 mv²
Let the mass and velocity of the car be m and v. Then its kinetic energy is 1/2 mv²
The mass and velocity of the truck are being 2m and 2v.
Then, kinetic energy of the truck = 1/2 2m (2v)²
Ke = 1/2 8 m v²
Therefore, the truck has 8 times the kinetic energy of the car. Hence, option d is correct.
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Your question is incomplete. But your complete question probably was:
A truck weighs twice as much as a car, and is moving at twice the speed of the car. Which statement is true about the truck's kinetic energy compared to that of the car?
a. All that can be said is that the truck has more kinetic energy.
b. The truck has twice the kinetic energy of the car.
c. The truck has 4 times the kinetic energy of the car.
d. The truck has 8 times the kinetic energy of the car.
Which of the following is a longitudinal wave? which of the following is a longitudinal wave?A.sound waveB.water waveC.light wave
Of the choices shown, sound wave is classified as a longitudinal wave (A)
A longitudinal wave is a type of wave that travels in a direction that is perpendicular to the motion of the particles that make up the medium in which the wave is traveling. Similar to light waves, sound waves oscillate in a direction parallel to the direction in which they propagate, producing compressions and rarefactions. Because of this, we refer to sound waves as longitudinal waves.
The particles that make up the wave do not move in the same direction as the wave; rather, they merely move back and forth in relation to their own equilibrium. Additional examples of longitudinal waves are the sound wave, the principal waves that are produced by an earthquake, ultrasound, the vibration of a spring, the fluctuation in gas, and the waves that are produced by a tsunami.
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use the climber's tea problem to calculate the mass of butane (in g) needed to fuel the stove to heat the water for tea.
the mass of butane (in g)needed to fuel the stove to heat the water for tea. is 1.32g
Butane is a colorless gas with a little aroma of petroleum. It might smell so it can be transported. It is transported under its vapor pressure as a liquefied gas. Ingestion of the liquid can result in frostbite. It is quickly set ablaze. Its fumes weigh more than the air. Any leak could be a liquid or a vapor one. The canisters may violently burst and shoot into the air when exposed to fire or extreme heat for an extended period of time. It is employed in the manufacture of various compounds as well as as a fuel and an aerosol propellant.
The thermochemical equation for the combustion of butane is:
[tex]2C_4H_10(g) \:+13O_2\rightarrow8CO_2(g)\:+10H_2O(l)[/tex]
[tex]\delta H=[/tex]-5748 KJ [tex](mol)^-1[/tex]
So far, calculated the heat released by water as follows:
[tex]Q = m\times c\times \Delta v[/tex]= 0.724g x 4.18 x 43.2
Q = 130.7 (kJ)/(mol)
it can be seen that burning 1 mole of butane releases 5748 kJ of energy
( ΔH<0)
[tex]nbutane=\frac{130.9 kJ}{5748 kJ} =0.023 mol[/tex]
[tex]m_(butane)=0.023 mol \times 58.12 g (mol)^-1=1.32 g[/tex]
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a 550 g squirrel with a surface area of 860 cm2 falls from a 4.8-m tree to the ground. estimate its terminal velocity. (use the drag coefficient for a horizontal skydiver. assume that the squirrel can be approximated as a rectanglar prism with cross-sectional area of width 11.1 cm and length 22.2 cm. note, the squirrel may not reach terminal velocity by the time it hits the ground. give the squirrel's terminal velocity, not it's velocity as it hits the ground.)
The terminal velocity of the squirrel is approximately 29.5 m/s.
The terminal velocity of an object can be calculated using the equation:
[tex]V_t = \sqrt{(2mg / (C_d \times A \times p))[/tex]
where V_t is the terminal velocity,
m is the mass of the object (550 g = 0.550 kg),
g is the acceleration due to gravity ([tex]9.8 m/s^2[/tex]),
[tex]C_d[/tex] is the drag coefficient for a horizontal skydiver (approximately 0.75),
A is the surface area of the object, and p is the density of air (approximately 1.225 kg/m^3 at sea level).
Since the squirrel can be approximated as a rectangular prism with a cross-sectional area of width 11.1 cm and length 22.2 cm,
We can calculate A as follows:
A = [tex]2 \times (11.1 cm) \times (22.2 cm)[/tex]
= [tex]484 cm^2[/tex]
Converting the surface area to square meters:
A = [tex]484 cm^2 \times (10^-4 m^2/cm^2)[/tex]
= [tex]0.0484 m^2[/tex]
Finally, calculate the terminal velocity:
[tex]V_t = \sqrt((2 \times 0.550 kg \times 9.8 m/s^2) / (0.75 \times 0.0484 m^2 \times 1.225 kg/m^3))[/tex]
= 29.5 m/s
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Determine the direction of the force on each charge. Enter your answers numerically separated by commas_ AZd 01, 02 , 03, 04 ________ counterclockwise from the +x axis
The direction of the force on a charge due to an electric field depends on the sign of the charge and the direction of the electric field. The direction of the electric field is determined by the direction of the gradient of the electric potential.
In general, the direction of the electric field can be found using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. The direction of the force is given by the direction of the vector connecting the two charges.
Given the information provided in the prompt, it is not possible to determine the direction of the force on each charge without additional information. Please provide more details.
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A person stands on a scale in a elevator at rest. The scale reads 900N. 1) what is the persons mass 2) the elevator accelerates up at 2.5m/s^2. What does the scale read now ? 3)The elevator then continues to move upwards with a steady speed of 4m/s for 5 seconds. What does the scale read during this period 4)the elevator now decelerates at 1.8m/s^2 until it reaches zero velocity. What does the scale read during this period[/B]
1. Mass of the person is 91.84 kg
2. The scale reads 917.4 N
3. The scale reads 917.4 N
4. The scale reads 905 N
Since the gravity acceleration (g) is not stated, assume it is 9.8 m/s^2
1. To calculate their mass, the formula m = F/g (where m is mass, F is weight (or force), and g is the acceleration due to gravity) would need to be used with the known weight and acceleration due to gravity (9.8 m/s^2). So, m = 900 N / 9.8 m/s^2 = 91.84 kg.
2. When the elevator accelerates upward at 2.5 m/s^2, the scale reading will increase. This is because the apparent weight of the person will be greater than their actual weight due to the upward acceleration of the elevator. The formula for apparent weight is Fapparent = m * g + ma (where m is mass, g is the acceleration due to gravity, and a is the acceleration of the elevator). So, Fapparent = 91.84 kg * 9.8 m/s^2 + 91.84 kg * 2.5 m/s^2 = 917.42 N.
3. During the steady speed of 4m/s, the scale will still read 917.42 N because the apparent weight does not change with constant velocity.
4. When the elevator decelerates at 1.8 m/s^2, the scale reading will decrease. The apparent weight will be less than the person's actual weight due to the downward acceleration of the elevator. The formula for apparent weight will be the same as in step 2, using the negative value of the deceleration of the elevator. So, Fapparent = 91.84 kg * 9.8 m/s^2 - 91.84 kg * 1.8 m/s^2 = 905.00 N.
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why is gamma ray dangerous
Answer:
They can go through humans damaging their tissue.
Explanation:
Gamma rays are very dangerous in comparison to other rays such as radio waves as gamma rays have a higher frequency. This higher frequency gives them an immense about of energy in comparison to other waves. They have more penetrating power and are able to damage human tissue... which is dangerous.
to increase the range of the water, isabella places her thumb on the hose hole and partially covers it. assuming that the flow remains steady, what fraction f of the cross-sectional area of the hose hole does she have to cover to be able to spray her friend? assume that the cross section of the hose opening is circular with a radius of 1.5 centimeters g
Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to 0.50 to be able to spray her friend.
What is fraction?The fraction f of the cross-sectional area of the hose hole that Isabella needs to cover depends on the desired range of the water. The range is determined by the speed of the water, which is related to the pressure of the water. Pressure is determined by the amount of water flowing through the hose, which is determined by the size of the hose opening.
To increase the range of the water, Isabella needs to decrease the size of the hose opening. This can be done by partially covering the hose hole with her thumb. The fraction f of the cross-sectional area of the hose hole that she needs to cover can be calculated using the following equation:
f = 1 - (A/A₀)
where A is the area of the partially covered hose hole and A₀ is the area of the fully opened hose hole.
For a circular hose hole with a radius of 1.5 centimeters (A₀ = 7.07 cm²), the area of the partially covered hose hole (A) can be calculated using the following equation:
A = πr²(1 - f)
where r is the radius of the hose hole (1.5 cm) and f is the fraction of the cross-sectional area of the hose hole that Isabella needs to cover.
Substituting the equation for A into the equation for f, we get:
f = 1 - (πr²(1 - f))/A₀
Solving for f, we get:
f = 1 - (πr²/A₀)
Therefore, for a circular hose hole with a radius of 1.5 centimeters, Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to:
f = 1 - (π × (1.5 cm)²)/(7.07 cm²)
f = 0.50
Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to 0.50 to be able to spray her friend.
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When you perpendicular-park you should, when possible, select a space that lets you drive into the facing space so that when you leave you will:
a. Not have to back out
b. Be able to back out of your space and the one behind you giving you more practice
c. Already have your wheels straight
d. None of the above is correct
Answer:
a. Not have to back out
When you perpendicular-park, if possible, you should select a space that lets you drive into the facing space so that when you leave, you will not have to back out. This will make it easier and safer for you to exit the parking spot and get back on the road.
all access doors to interior transmitting stations for radio equipment shall be provided with ? , which disconnect all voltages above 350 volts when the door is opened.
Equipment for radio and television – Article 810. For five different system kinds, Article 800 lists general requirements.
Which chapter 8 section details the specifications for radio and television gear? Six articles, including those on radio and television equipment [810], network-powered broadband [830], and premises-powered broadband [840], are included in Chapter 8 of the National Electrical Code (NEC) that deal with communications systems.For five different system kinds, Article 800 lists general requirements.There must be a minimum voltage rating of 300 volts for communication wires and cables.A coaxial cable's individual conductors' insulation, excluding the outside conductor, must be rated for a minimum of 300 volts.If communication cables are not marked with a tag for future use or terminated at both ends with a connector or other device, they will be regarded as abandoned.To learn more about television equipment refer
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22 4 points
What is the mechanical advantage of a hydraulic system that has a small piston diameter of 6.5 inches and a large piston diameter of 20 inches?
A.8.84
B.15.35
C.9.47
D.3.7
This is 20 plus 6.5 squared, which equals.Nearly nine 478 is what this equates to.This system therefore has a 9.47 mechanical advantage.
What mechanical benefit does this hydraulic system offer? This is 20 plus 6.5 squared, which equals.Nearly nine 478 is what this equates to.This system therefore has a 9.47 mechanical advantage.In a hydraulic system, the fluid's capacity to convey pressure evenly accounts for the significant mechanical advantage.It enables you to apply a tiny amount of force to the small piston in order to generate a bigger amount of force on the large piston.The output force minus the input force is equal to the mechanical advantage.The ratio of the large piston area to the tiny piston area is the mechanical advantage of a hydraulic lift that is optimal.
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10. Which of the following can be used to distinguish a solid ball from a hollow sphere of the same radius and mass?
(A) Measurements of the orbit of a test mass around the object.
(B) Measurements of the time it takes the object to roll down an inclined plane.
(C) Measurements of the tidal forces applied by the object to a liquid body.
(D) Measurements of the behavior of the object as it floats in water.
(E) Measurements of the force applied to the object by a uniform gravitational field
You should discover that, regardless of their exact mass or diameter, a solid object will always roll down the ramp quicker than a hollow object of the same shape (sphere or cylinder).
Do solid or hollow balls roll more quickly?You should discover that, regardless of their exact mass or diameter, a solid object will always roll down the ramp quicker than a hollow object of the same shape (sphere or cylinder).Yes, since Force=MassxAcceleration (F=MA), more force is required to move items with greater mass, and the more mass an object has, the faster it can move.Gravity is what causes a slope's change in speed. Things move more quickly when moving downhill and more slowly when moving upwards (slow down). If there is little friction on a flat surface, they will then keep moving at the same speed.To learn more about mass refer to:
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Three horizontal ropes pull on a large engine block, producing the vector forces A, B and
C as shown below. Find the magnitude and direction of a fourth force on the engine that
will make the vector sum of the forces equal zero.
Use the method of components to calculate the magnitude and represent the direction
in degrees from the positive x or from the negative x axis. Marks will be taken off if
you use other methods.
Σ Φ
= 0
Fand = P
P
sin a b
Cosa
B (80.0 N)
30.0°
X
30.0°
53.0⁰
(40.0 N)
A (100.0 N)
·x
The magnitude and direction of a fourth force on the engine that will make the vector sum of the forces equal zero is 193.1 N with direction is 57.7° counter-clockwise from the positive x axis.
What is magnitude?The magnitude or size of a mathematical object is a property which determines whether the object is larger or smaller than other objects of the same kind.
We find the x and y components of each force:
A = 100 N, θ = 53.0° => Ax = 100 N * cos (53.0°) = 70.7 N; Ay = 100 N * sin (53.0°) = 50.0 N
B = 40.0 N, θ = 30.0° => Bx = 40.0 N * cos (30.0°) = 34.0 N; By = 40.0 N * sin (30.0°) = 20.0 N
C = 80.0 N, θ = 30.0° => Cx = 80.0 N * cos (30.0°) = 68.0 N; Cy = 80.0 N * sin (30.0°) = 40.0 N
We will find the total x and y components:
Net x = Ax + Bx + Cx = 70.7 N + 34.0 N + 68.0 N = 172.7 N
Net y = Ay + By + Cy = 50.0 N + 20.0 N + 40.0 N = 110.0 N
Finally, let's find the magnitude and direction of the fourth force, P:
P = sqrt (Net x^2 + Net y^2) = sqrt (172.7 N^2 + 110.0 N^2) = 193.1 N
θ = tan^-1 (Net y / Net x) = tan^-1 (110.0 N / 172.7 N) = 57.7°
In conclusion, if the angle is negative, the direction is clockwise from the negative x axis. In this example, the angle is positive, so the direction is 57.7° counter-clockwise from the positive x axis.
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An astronaut who weights 700 N on the surface of the earth lifts off from planet Zuton in a space ship. The free-fall acceleration on Zuton is 3 m/s². At the moment of lift off the space ship experiences an acceleration of 5 m/s². The acceleration of gravity is 10 m/s². What is the magnitude of the force that the space ship exerts on the astronaut?
Answer:
Explanation:
The magnitude of the force that the space ship exerts on the astronaut is 1300 N.
This can be calculated by using the formula: force = mass x acceleration.
The astronaut's mass is 700 N / 10 m/s² = 70 kg
The acceleration of the ship is 5 m/s².
So the force on the astronaut is 70 kg x 5 m/s² = 350 N.
Additionally, the astronaut also experiences the force of gravity on Zuton, which is 700 N - (70 kg x 3 m/s²) = 630 N.
So the total force on the astronaut is 630 N + 350 N = 980 N.
550 Hz sound is emitted from a megaphone into symmetrical tubes of one top path and one bottom path. The top and bottom paths are initially identical, but the top path can be lengthened. a. Why is the interference initially constructive? b. How far do you have to raise the top part of the tube to achieve destructive interference in m?
Initially the sound waves are in phase and they overlap to form the constructive interference pattern. The length that we have to raise the top part will be equal to the wavelength of the waves in meter.
What is interference ?A wave of greater, lower, or the same amplitude is created when two waves merge through interference by combining their displacements at all points in space and time.
The interaction of waves that are coherent or correlated with one another, either because they originate from the same source or because their frequencies are similar or almost identical, leads to both constructive and destructive interference.
All sorts of waves, including light, radio, acoustic, surface water waves, gravity waves, and matter waves, can exhibit interference effects. In constructive interference, the waves are in single phase forms a resultant wave with higher amplitude.
When waves from in phase phase meets, the resultant wave will have an amplitude less than the individual amplitudes. Here
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23.
The escape velocity from the surface of the Moon is 2.4 x 10³ ms ¹.
(a)
An object is projected from the surface of the Moon with a speed
of 2.0 x 10³ ms'..
Calculate the maximum height reached above the Moon's surface.
_____ involves relying on assumptions and beliefs about the world, whereas _____ involves making direct observations of the world.
Intuition involves relying on assumptions and beliefs about the world, whereas empirical observation involves making direct observations of the world.
Intuition refers to the process of using past experiences, beliefs, and assumptions to make quick, unconscious judgments or decisions about the world.
It is often associated with feelings or gut reactions and can be influenced by factors such as emotions, biases, and prior knowledge.
Empirical observation, on the other hand, refers to the process of gathering information about the world through direct sensory experience, such as seeing, hearing, touching, and measuring.
Empirical observations are the foundation of scientific inquiry as they provide the raw data that can be used to test and refine hypotheses and theories.
Unlike intuition, empirical observations are objective and uninfluenced by personal biases or assumptions.
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Cheetahs can accelerate to a speed of 20.0 m/s s and can continue to accelerate to reach a top speed of 29.8 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter. Let the +x-direction point in the direction the cheetah runs.
Express the cheetah's top speed in miles per hour
The final speed of the Cheetah is 66.6607 miles per hour.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
If a body changes its velocity or direction of velocity, the physical quantity "acceleration" comes into play.
Initial speed of the Cheetah is = 20.0 m/s
Final speed of the Cheetah is = 29.8 m/s
Now 1 meter per second = 2.237 miles per hour
Hence, Final speed of the Cheetah is = 29.8 × 2.237 miles per hour
= 66.6607 miles per hour.
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1)A ball with an initial velocity of 9.6 m/s rolls up a hill without slipping. a)Treating the ball as a spherical shell, calculate the vertical height it reaches in meters. b) Repeat the calculation for the same ball if it slides up the hill without rolling in m.
2) Suppose we want to calculate the moment of inertia of a 56.5 kg skater, relative to a vertical axis through their center of mass. Calculate the moment of inertia in (kg*m^2) when the skater has their arms pulled inward assuming they are cylinder of radius 0.125m
1 (a) The vertical height upto which the ball reaches will be 4.608 meters
a) We may use the theory of conservation of energy to compute the vertical height reached by the ball.
The ball's original total mechanical energy equals its ultimate potential energy.
The potential energy formula is mgh,
where m is the ball's mass,
g is the acceleration due to gravity (9.8 m/s2), and
h is the height.
The initial total mechanical energy equals the initial kinetic energy, which may be computed using the formula 1/2 * m * v2,
where v represents the beginning velocity.
By equating the two, we get:
1/2 * m * v^2 = mgh
Rearranging and solving for h:
h = v^2 / (2g)
= (9.6 m/s)^2 / (2 * 9.8 m/s^2)
= 4.608 m
b) If the ball glides up the hill without rolling, its final height will be lower than if it rolls.
As the ball slows down, part of its original kinetic energy is converted into frictional warmth, sound, and other types of internal energy.
To calculate the moment of inertia, we must first know the skater's mass distribution and the axis along which the moment of inertia is being computed.
Assuming the skater's arms are dragged inward and may be considered as cylinders with radius 0.125 m and mass m_a, the moment of inertia can be calculated as follows:
I = I_cm + m_a * r^2
where I_cm is the moment of inertia of the skater's body (assuming it can be treated as a point mass),
r is the distance from the axis of rotation to the center of mass of the cylinder (0.125 m), and
m_a is the mass of the cylinder (unknown).
To calculate I_cm, we need to know the skater's body's mass and shape. Without more information, we cannot calculate the moment of inertia.
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Use Gauss's theorem to prove that at the surface of a curved charged conductor, the normal derivative of the electric field is given by 譜--(1+1) 1 dE R1 R2 where Ri and R2 are the principal radii of curvature of the surface.
The normal derivative of the electric field is given by [tex]\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )[/tex].
The Gauss law is really applied in integral form, E da = 0.
then there is no contained charge. prior to thinking about the three-dimensional issue. Think about the similar circumstance in two dimensions.
Gauss laws therefore state that if you place a curve Gaussian box adjacent to the charged conductor's surface at a position where the radius of curvature is R.
[tex]0=\int {E.x} \, da=E_{top}\triangle a_{top} -E_{bottom}\triangle a_{bottom}[/tex]
[tex]\triangle a_{top}[/tex] and [tex]\triangle a_{bottom}[/tex] are the top and bottom portions of the box, respectively.
using [tex]\triangle a_{top}[/tex] =(R+E)d∅× dz and,
[tex]\triangle a_{bottom}[/tex]=Rd∅× dz gives
[tex]E_{bottom}=E_{top}(1+\frac{E}{R})[/tex]
This enables us to compute.
[tex]\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(\frac{-E_{top}}{R})= \frac{-E_{top}}{R}[/tex]
Taking into consideration that Flop is the same as E ,this may be written as
[tex]\frac{1}{E}\times\frac{dE}{dn}=-\frac{1}{R}[/tex]
This is a two-dimensional expression analogue.
Returning to the 3D issue, we will use the aforementioned methods. However, this time around, the top and bottom
[tex]\triangle a_{top}[/tex]=[tex](R_{1}+E)\times(R_{2}+E)\times[/tex]dФ
[tex]\triangle a_{bottom}[/tex]=[tex]R_{1}R_{2}[/tex]dФ
Now putting these in equation
[tex]E_{bottom}=E_{top}(1+\frac{E}{R_{1} })(1+\frac{E}{R_{2} })[/tex]
which gives,
[tex]\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} }+\frac{E}{R_{1} R_{2} })=-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} })[/tex]
Rearranging the equation gives,
[tex]\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )[/tex]
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Exercise 18: Veanna is in Las Vegas waiting for her number to be called at the roulette
wheel, a large 3.0-kg disk of radius 0.60 m. What is the moment of inertia of the wheel?
The wheel's moment of inertia is a sizable 3.0-kg disk with a radius of 0.60 m and a mass of 0.54 kg/m².
Explain the moment of inertia.In physics, a body's inertial moment is a numerical representation of its resistance to having overall speed of its movement about an axis changed by that of the deployment of a torque. The axis could be local or exterior, fixed or not.
Forces of inertia: What are they?All materials share the attribute of force of inertia, which keeps them in their states—whether they are at rest and in motion an outside force is applied to cause them to change. Except when someone changes their state, bodies do not exhibit this force.
Moment of inertia,
solid disc of mass = M
radius = R
I = 1/2 MR²
= 1/2 * 3 * 0.60²
= 0.54 kg.m²
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A 4kg ball moving 8m/s to the right collides with a 2kg ball at rest. After the
collision, the 4kg ball moves with a new velocity of 4.8m/s to the right. Assuming
that the collision is elastic, how fast is the 2kg ball moving?
We can see that the new velocity of the 2 Kg ball is 6.4 m/s.
What is the momentum?Momentum is a measure of an object's motion. It is defined as the product of an object's mass and velocity. In physics, momentum is a vector quantity, meaning it has both magnitude and direction.
The law of conservation of momentum states that in an isolated system, the total momentum of the system remains constant if no external forces are acting upon it.
Given that we know that;
Momentum before collision = Momentum after collision
(4 * 8) + (2 * 0) = (4 * 4.8) + (2 * v)
Let v be the new velocity
32 = 19.2 + 2v
v = 32 - 19.2/2
v = 6.4 m/s
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the force shown on a force time diagram acts on a 3.7 kg object. find the impulse of the force
The impulse on the mass is equal to the area under the force -time graph. The area under the plot in the graph is 6 N.s thus the impulse is 6 Ns.
What is impulse ?Impulse of a moving object is its change in momentum. It is equal to the product of force and time. The force- time plot of a moving object can be used to determine the impulse.
From the given force- time graph, the area under the curve is :
area = area of the two triangles + area of the rectangle.
area of the triangle = 1/2 (2 N × 2s )= 2N s
area of the rectangle = 2 N × 1s = 2N s.
The second triangle have the area equal to the first one that is 2 N s.
then the total area of the curve = 2 Ns × 3 = 6 Ns.
Therefore, the impulse on the mass is 6 Ns.
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Define 1meter, 1second and 1kilogram
Answer:
Explanation:
1meter equals 100cm mt and cm are measure the distance.
1second, 60seconds equals 1minute second minute and hour meansures time.
1kg is equals 1000g and measures weight.
A 7.18 x10³ kg space vehicle and its empty 6.32 x10² kg booster unit are moving together through space at a speed of 369.66 m/s. An explosion lasting 2.81 s is used to separate the two parts. If the speed of the space vehicle after the separation increased to 444.57 m/s what is the magnitude force on the booster unit?
The magnitude of the force on the booster unit can be calculated using the principle of conservation of momentum. According to this principle, the momentum of a system is conserved before and after an interaction, as long as no external forces act on the system.
Before the separation, the total momentum of the system is:
m_total * v_initial = (7.18 x 10^3 kg) * (369.66 m/s)
After the separation, the momentum of the space vehicle is:
m_vehicle * v_final = (7.18 x 10^3 kg) * (444.57 m/s)
And the momentum of the booster unit is:
m_booster * v_final = (6.32 x 10^2 kg) * v_final
Since the total momentum is conserved, the initial momentum must equal the final momentum:
m_total * v_initial = m_vehicle * v_final + m_booster * v_final
Solving for v_final, we find:
v_final = (m_total * v_initial - m_vehicle * v_final) / m_booster
Now we can find the magnitude of the force on the booster unit using Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:
F = m_booster * a = m_booster * (dv/dt)
where dv/dt is the change in velocity over time, which can be approximated as (v_final - v_initial) / time.
Substituting the values we have found into this equation, we find:
F = (6.32 x 10^2 kg) * ((v_final - v_initial) / (2.81 s))
This equation can be evaluated to find the magnitude of the force on the booster unit.
A basketball player grabbing a rebound jumps 80 cm vertically. How much total time (ascent and descent) does the player spend (a) in the top 10 cm of this jump and (b) in the bottom 10 cm? Do your results explain why such players seem to hang in the air at the top of a jump?
(a) The time spent by the player in the top of 10 cm of this jump is 0.14 second.
(b) The time spent by the player in the bottom 10 cm of this jump is 0.38 second.
(c) The result shows that the player spends more time during ascent and decent because of greater distance.
What is the time of motion of the player?
The time taken for the player to jump 80 cm and back to ground is calculated as follows;
t = 2 ( √ ( 2h / g ) )
where;
h is the vertical height travelled by the playerg is acceleration due to due to gravityt = 2 ( √ ( 2 x 0.8 / 9.8 ) )
t = 0.4 s
t = 0.8 second
The time spent by the player in 10 cm jump is calculated as follows;
t = √ ( 2h / g )
t = √ ( 2 x 0.1 / 9.8 )
t = 0.14 s
From 10 cm at the bottom, the player has travelled 70 cm, and the time of motion of this player is calculated as follows;
t = √ ( 2 x 0.7 / 9.8 )
t = 0.38 second
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Metamorphism occurs when a rock ________.
a. experiences conditions that include high pressures
b. experiences conditions that include high temperatures
c. experiences conditions that are similar to those that formed the rock
d. experiences conditions that are significantly different from those that formed the rock
Metamorphism occurs when rocks experience conditions significantly different from those under which they were formed.
Metamorphism is the process by which existing rocks are transformed into new forms by temperature, pressure, and chemically active fluids. There are three types of metamorphism: contact metamorphism, regional metamorphism, and dynamic metamorphism. Contact metamorphism occurs when magma comes into contact with existing rock masses. When this happens, the temperature of the existing rock increases and liquids from the magma seeps in. The word metamorphosis is of Greek origin and means "change of shape". Metamorphic rocks are derived from igneous or sedimentary rocks that have changed shape (recrystallized) due to changes in the physical environment.
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The spectrum of a continuous cool source located behind a hot cloud of gas will show group of answer choices O emission lines O absorption lines O emission and absorption lines O no spectral lines
The spectrum of a continuous cool source located behind a hot cloud of gas will show a combination of emission lines and absorption lines.
The emission lines will be from the continuous cool source, while the absorption lines will be from the hot cloud of gas. Absorption lines are dark lines in the spectrum caused by the hot gas absorbing light from the cool source. Emission lines are bright lines in the spectrum caused by the hot gas emitting light.
Emission lines are bright lines in the spectrum caused by the hot gas emitting light. They are produced when electrons in an atom or molecule make a transition from a higher energy state to a lower energy state, releasing energy as a photon of light that has a specific wavelength.
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A ball is thrown upwards. Its acceleration is: A. upward during both ascent and descent B. upward during ascent and downward during descent C. downward during both ascent and descent D. downward during ascent and upward during descent E. downward at all times except at the very top, when it is zero
A ball is thrown upwards. Its acceleration is: C. downward during both ascent and descent
What is vertical launch upwards?In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.
In the vertical launch upwards movements, the acceleration due to the gravity is always acting downward, this is because of attraction that the earth exerts on all bodies pulling them toward its center
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a student standing on the ground throws a ball straight up. the ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground.you may want to review (page) .for help with math skills, you may want to review:quadratic equationsfor general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of time in the air for a tossed ball.
Before the ball hits the ground, it is 2.8 seconds in the air. The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionThe equations apply in uniformly accelerated straight motion in vertical dimension are
v₁ = v₀ + gt
v₁² = v₀² + 2gh
h = v₀t + ½ gt²
Where
v₀ = initial velocityv₁ = final velocityg = acceleration due to gravityt = timeh = height of objectA student standing on the ground throws a ball straight up with
Initial height, h₁ = 2.5 mSpeed of the ball at h₁, v₀ = 13.0 m/sFind the time it takes for the ball to reach the ground!
We use g = 9.8 m/s². See the illustration picture in the attachment!
The ball will go upward and stop at a certain height with v₁ = 0. The time needed is
v₁ = v₀ - gt₁
0 = 13.0 - 9.8t
13.0 = 9.8t
t₁ = 13.0/9.8
t₁ = 1.3 s
The height above the hand when the ball stops is
v₁² = v₀² - 2gh₂
0 = 13.0² - 2(9.8)h₂
13.0² = 2(9.8)h₂
169 = 19.6h₂
h₂ = 8,62 m
The ball stops at a height of
h₃ = h₁ + h₂
h₃ = 2.50 + 8.62
h₃ = 11.12 m
The ball goes downward and reach the ground. Initial velocity in this condition is v₁ = 0. The time needed is
h₃ = v₁t + ½ gt₂²
11.12 = 0 + ½ (9.8)t₂²
11.12 = 4.9t²
t₂² = 2.27
t₂ ≈ 1.5 s
The time that the ball in the air is
t = t₁ + t₂
t = 1.3 + 1.5
t = 2.8 s
Hence, the ball is in the air for 2.8 seconds.
Your question is incomplete, but most probably your full question was
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground. How long is the ball in the air before it hits the ground? (The student moves her hand out of the way).
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