Estimate the answers to the following calculations by carrying out order of magnitude calculations.
a) 0.26 x 890
b) [tex]\frac{1.95}{0.0067}[/tex]
c) 2010 x [tex]10^{-5}[/tex]
d) [tex]\frac{9.98 x 10^{-4} }{9 x 10^{2} }[/tex]

Answer:

y = (1/4)x² - (5/4)x + 1

Step-by-step explanation:

The x-intercepts of the quadratic equation are simply it's roots.

Thus, we have;

(x + 1) = 0 and (x - 4) = 0

Now, formula for quadratic equation is;

y = ax² + bx + c

Where c is the y intercept.

At y-intercept: (0,1), we have;

At (-1,0), thus;

0 = a(1²) + b(1) + 1

a + b = -1 - - - (1)

At (4,0), thus;

0 = a(4²) + b(4) + 1

16a + 4b = -1

Divide both sides by 4 to get;

4a + b = -1/4 - - - (2)

From eq 1, b = -1 - a

Thus;

4a + (-1 - a) = -1/4

4a - 1 - a = -1/4

3a - 1 = -1/4

3a = 1 - 1/4

3a = 3/4

a = 1/4

b = -1 - 1/4

b = -5/4

Thus;

y = (1/4)x² - (5/4)x + 1

Answer:

x = number of students tickets = 1,000

y = number of adults tickets = 250

Step-by-step explanation:

Let

x = number of students tickets

y = number of adults tickets

x + y = 1,250 (1)

2x + 3y = 2,750 (2)

Multiply (1) by 2

x + y = 1,250 (1) * 2

2x + 2y = 2,500 (3)

2x + 3y = 2,750 (2)

Subtract (3) from (2) to eliminate x

3y - 2y = 2,750 - 2,500

y = 250

Substitute y = 250 into (1)

x + y = 1,250

x + 250 = 1,250

x = 1,250 - 250

x = 1,000

x = number of students tickets = 1,000

y = number of adults tickets = 250

Answer:

[tex]{ \tt{sum = \frac{a(r {}^{n - 1} )}{n - 1} }} \\ 27 = \frac{a(r {}^{2 - 1} )}{2 - 1} \\ { \bf{27 = ar - - - (i)}} \\ \\ 54 = \frac{a( {r}^{3 - 1} )}{3 - 1} \\ { \bf{108 = a {r}^{2} - - - (ii) }} \\ { \tt{(ii) \div (i) : }} \\ r = \frac{108}{27} \\ { \bf{common \: ratio = 4}} \\ { \bf{first \: term = \frac{27}{4} }}[/tex]

Answer:

t = D/r

Step-by-step explanation:

you rearrange the equation so that is the subject. when you bring something over the equal sign, it reverses the function so D = r×t becomes t = D/r

Answer:

13

Step-by-step explanation:

i just know

Answer:

,

Step-by-step explanation:

,

Answer:

The 99% confidence interval for the true mean milk production is between 26.33 kg/d and 29.67 kg/d.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{2.25}{\sqrt{12}} = 1.67[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 28 - 1.67 = 26.33 kg/d.

The upper end of the interval is the sample mean added to M. So it is 28 + 1.67 = 29.67 kg/d.

The 99% confidence interval for the true mean milk production is between 26.33 kg/d and 29.67 kg/d.

Answer:

to get the slope. take the change of y axis value divide by the change of x axis value

Answer:

Represent 1/2 by covering 50 squares.

Step-by-step explanation:

There are 100 squares in a 10-by-10 grid.

1/2 of 100 is 50, so you should cover 50 squares out of 100 squares.

Answer:

Step-by-step explanation:

Well lets start with

(3*sqrt 2+ 1)(2*sqrt 3-4)

Lets multiply everything in the second parenthesis by 3*sqrt 2

2 sqrt 3 * 3 sqrt 2 =  6 sqrt 6

-4*3 sqrt 2 =  -12 sqrt 2

Now lets multiply everything by 1

1*2 sqrt 3 = 2 sqrt 3

1*-4 = -4

we have

-4  -12 [tex]\sqrt{2}[/tex]  +  6 [tex]\sqrt{6}[/tex]  + 2 [tex]\sqrt{3}[/tex]  as the awnser to problem A

Now lets do problem b

We can start by multiplying everything in the second parenthesis by 2

2*5=10

2*-1 *sqrt 3 = -2 sqrt 3

Now multiply everything in the second parenthesis by 2sqrt3

2sqrt 3 * 5 = 10 sqrt 3

2 sqrt 3 * -1* sqrt3 =  -6

Our final awnser is

10-6 +10 sqrt 3 -2 sqrt 3 ->  4+ 8 [tex]\sqrt{3}[/tex]

The awnser to question B is 4+ 8 [tex]\sqrt{3}[/tex]

pls give brainliest

Answer:

AC is greater than BC

Step-by-step explanation:

First, we know that the angle of a straight line is 180°, so angle B as a whole is equal to 180 degrees. Therefore, angle YBC + angle ABC = 180 degrees. As angle YBC is a right angle, signified by the small square on the angle, it is 90 degrees. Therefore,

90 degrees + angle ABC = 180 degrees

subtract 90 degrees from both sides to isolate angle ABC

angle ABC = 90 degrees

Therefore, as angle ABC is equal to 90 degrees, and a right angle is 90 degrees, triangle ABC has a right angle, making it a right triangle.

In a right triangle, using the Pythagorean Theorem, the square of the side opposite the right angle is equal to the sum of the squares of the other side. Since side AC is opposite the right angle, we can say that

AC² = AB² + BC²

As the length of a side has to be greater than 0, we can say that

AC² = AB² + BC²

AB² > 0

AC² > BC²

square root both sides

AC > BC

Therefore, AC is greater than BC

Answer:

(12/39) * (12/39) or 16/169

Step-by-step explanation:

Answer:

1/2

8

Step-by-step explanation:

When its talking about the result or output, look at the range, and then follow the line(s) back to the number(s) in the domain. Do the opposite when it's talking about the function of a certain number, e.g. f(4).

Answer:

[tex] a_n = 2n^2 + n + 1 [/tex]

Step-by-step explanation:

4, 11, 22, 37, 56

11 - 4 = 7

22 - 11 = 11

37 - 22 = 15

56 - 37 = 19

After the first difference, 11 - 4 = 7, each difference is 4 more than the previous difference.

Difference of differences:

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

Since we need the difference of differences to find a constant, this must be a second degree function.

[tex] a_1 = 4 = 2^2 + 1(0)[/tex]

[tex] a_2 = 11 = 3^2 + 2 = 3^2 + 2(1) [/tex]

[tex] a_3 = 22 = 4^2 + 6 = 4^2 + 3(2) [/tex]

[tex] a_4 = 37 = 5^2 + 12 = 5^2 + 4(3) [/tex]

[tex]a_5 = 56 = 6^2 + 20 = 6^2 + 5(4)[/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = n^2 + 2n + 1 + n^2 - n [/tex]

[tex] a_n = 2n^2 + n + 1 [/tex]

Answer:

8(X^2+1)

Step-by-step explanation:

(X²+3)²-(X²-1)

(X²+3)(X²+3)-(X²-1)(X²-1)

X⁴+3X²+3X²+9-(X⁴-X²-X²+1)

X⁴+6X²+9-(X⁴-2X²+1)

X⁴+6X²+9-X⁴+2X²-1

8X²+8

Answer:

223.6 square units. or 223.569 square units

Answer:A

Step-by-step explanation:I took the test

The question is not complete as the scatter plot is missing.

Thus, I have attached the complete question showing the scatter plot.

Answer:

D: On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

Step-by-step explanation:

From the attached image showing the question and scatter plot, we can see that the scatter plot is modeled by the line; y = -5.9x + 850

Where;

x is the high temperature in °F

y is the amount of fluid ounces sold

Let's try x = 0°F

Thus;

y = 0 + 850

y = 850 fluid ounces

Let's try x = 10°F

Thus;

y = -5.9(10) + 850

y = 850 - 59

y = 791

This means for every increase in temperature of 10°F, the amount sold is approximately 60 fluid ounces lesser.

Looking at the options in the attached file, the only correct one that corresponds to our answer is option D where it says;. On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

Answer:

-x²-2x+3

Step-by-step explanation:

The first thing I noticed is that the first and second point has the same y intercept despite being only 2 x coordiantes away. This must mean that the vertex's x coordiante is probably (-1,4)

Because the vertex is probably (-1,4) the graph must also be concave down because the point (-4,-5) is below it

writing this in vertex form we get

-a(x+1)²+4

Where a is some constant

solve for a by plugging in (0,3)

3= -a(0+1)²+4

3= -a+4

-1= -a

a=1

therefore the equation looks like

-(x+1)²+4

expanding this so that it's in stantard form...

-(x²+x+x+1)+4

-x²-2x+3

which is the final answer

Answer:

[tex]\frac{y^8}{x^{10}}[/tex]

Step-by-step explanation:

Given

[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

Required

The equivalent

Apply law of indices to the inner bracket

[tex](x^{-4--9}y^{1 -5})^{-2}[/tex]

[tex](x^{5}y^{-4})^{-2}[/tex]

Rewrite as:

[tex]\frac{1}{(x^{5}y^{-4})^2}[/tex]

Expand

[tex]\frac{1}{(x^{5*2}y^{-4*2})}[/tex]

[tex]\frac{1}{(x^{10}y^{-8})}[/tex]

Apply law of indices

[tex]\frac{y^8}{x^{10}}[/tex]

Answer:

P [ X ≤  9.8 ]  = 0.1335

Step-by-step explanation:

P [ X ≤  9.8 ]  =  [ ( 9.8  - 10.2 )/1.8√25 ]

P [ X ≤  9.8 ]  =  - 0.4*5/1.8

P [ X ≤  9.8 ]  = - 2 / 1.8

P [ X ≤  9.8 ]  =  - 1.11

From z- table we get:  α  =  0.1335

P [ X ≤  9.8 ]  = 0.1335   or   P [ X ≤  9.8 ]  = 0.1335

Answer:

-6 -b

Step-by-step explanation:

I have attached the explanation above. hopefully this will help you

Answer:

The one with 6.4 ounces or multiple that are equivalent to that

Step-by-step explanation:

4/10 of a pound is equivalent to 2/5 of a pound. 2/5 of a pound is 6.4 ounces.

Answer:

2x-25<89

x<57

Step-by-step explanation:

2x-25<89

2x<89+25

2x<114

Divide by 2...

x<57

Hope this helped! Please mark brainliest :)

Answer:

14 units is the answer

Step-by-step explanation:

^_^^_^^_^^_^^_^

Answer:

1 day=10outfits

5days=10outfits×5

=50outfits

Step-by-step explanation:

hope this is helpful

Based on the calculation, you can wear the 10 outfits in 50 different ways throughout the week.

To calculate the number of ways you can wear 10 outfits to school each day in a 5-day week, you need to consider the total number of outfits across all days. Since there are 10 outfits and 5 days, the total number of outfit combinations can be calculated by multiplying the number of outfits per day by the number of days:

10 outfits/day × 5 days = 50 outfit combinations

Therefore, you can wear the 10 outfits in 50 different ways throughout the week.

Learn more about permutations

https://brainly.com/question/4658834

#SPJ2

the way to do these recurring decimals is by firstly separating the repeating part or recurring part and then multiply it by some power of 10 so we move it to the left, lemme show

[tex]3.5\overline{41}\implies \cfrac{35.\overline{41}}{10}\qquad \stackrel{\textit{say that the repe}\textit{ating part is }~\hfill }{x = \overline{0.41}\qquad \qquad \textit{so that }35.\overline{41}=35+\overline{0.41}=35+x}[/tex]

now, let's multiply that repeating part by some power of 10 that moves the 41 to the left, well, we have two repeating decimals, 4 and 1, so let's use two zeros, namely 100 or 10², thus

[tex]100\cdot x = 41.\overline{41}\implies 100x - 41+\overline{0.41}\implies 100x = 41+x\implies 99x=41 \\\\\\ \boxed{x =\cfrac{41}{99}}\qquad \qquad \textit{so then we can say that}~~\cfrac{35.\overline{41}}{10}\implies \cfrac{35+\frac{41}{99}}{10} \\\\\\ \cfrac{~~\frac{3506}{99}~~}{10}\implies \cfrac{~~\frac{3506}{99}~~}{\frac{10}{1}}\implies \cfrac{3506}{99}\cdot \cfrac{1}{10}\implies \cfrac{3506}{990}\implies \blacktriangleright \stackrel{\textit{which simplifies to}}{\cfrac{1753}{495}} \blacktriangleleft[/tex]

Step-by-step explanation:

went to a calculator

it said

Angle ∠A = 55.543°

Angle ∠B = 78.28°

Angle ∠C = 46.177

Answer:

radical is sqrt we find 180 sqrt root

Step-by-step explanation:

first we write sqrt 180

sqrt 180 = ?

we can choose first two letters

18 are two letters

4^2 + 2 = 18

so first + third number choose

4 , 2 are number choose

4 + 2 sqrt (4+2-1)

6 sqrt 5

sqrt 180 = 6sqrt 5

Answer:

9

Step-by-step explanation:

First you would need to subtract all the irrelevant students.

So, subtract 4 from 36, which is 34.

34 - (10 + 15) =

34 - 25 =

9

The answer is 9 pupils.