The differential equation describing the cell phone sales is given by:dy/dt=(4/300)y(1−y/60)dy/dt=(2/75)y(1−y/60).
(a) We are required to find the constant k, given that the logistic equation is dP/dt=kP(1−P/K). Here, P represents the population of fish and K represents the carrying capacity of the lake. According to the question, the initial population of fish is 500 and the carrying capacity of the lake is 6200. Therefore, K = 6200 and P(0) = 500. The logistic equation is dP/dt=kP(1−P/K) ⇒ dP/dt=kP(1/K−P/K) ⇒ dP/dt=kP(6200−P)/6200 Now we can integrate both sides of this equation using partial fractions:1/P(6200−P)=A/6200+B/P.Now, we will multiply both sides of the equation by 6200P(6200−P):1=AP+B(6200−P).Setting P=0 gives:B=1/6200. Now, setting P=6200 gives:A=−1/6200.Therefore, we have1/P(6200−P)=−1/6200(1/P−1/6200). Substituting this value of 1/P(6200−P) into the previous differential equation, we getdP/dt=k(−1/6200)(1/P−1/6200)PdP/dt=−kP/6200+kP^2/6200.We can rearrange this equation as:dP/dt=kP(6200−P)/6200.The differential equation of the population growth is given by dP/dt=kP(6200−P)/6200.(b) We are required to find how long it will take for the fish population to increase to 3100 (half of the carrying capacity).Using the logistic equation obtained in part (a), we can write this as:3100=6200/(1+5e^(−k(t)))Multiplying both sides of this equation by e^(kt), we get:3100e^(kt)=6200−3100e^(−kt)
Multiplying both sides by e^(kt), we get:3100e^(2kt)=6200e^(kt)−3100Taking logarithms of both sides, we get:2kt+ln 3100=kt+ln 6200−ln 3100kt=ln(2)+ln(3100/3100−6200)e^(kt)=2e^(ln(2)+ln(3100/3100−6200))=2(3100/3100−6200)=0.5Therefore, the fish population will increase to half the carrying capacity in 0.5 years.(c) We are required to find the differential equation describing the cell phone sales, where y(t) is the number of cell phones (in thousands) sold after t months. After 30 thousand cell phones have been sold, sales are increasing by 2 thousand phones per month.The maximum number of cell phones that can be sold is 60,000. The logistic equation is given by:dy/dt=ky(1−y/60).Given that sales are increasing by 2,000 phones per month, we have dy/dt=2000 when y=30,000. Substituting this value into the logistic equation, we get:2000=k(30,000)(1−30,000/60,000)2000=k(0.5)k=4/300
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Find the Laplace transform of the given function:
f(t)=(t−4)u2(t)−(t−2)u4(t),
where uc(t) denotes the Heaviside function, which is 0 for t
Enclose numerators and denominators in parentheses. For example, (a−b)/(1+n).
The Laplace transform of the given function f(t) is L[f(t)] = -6/s³- 72/s³
To find the Laplace transform of the given function f(t) use the linearity property of the Laplace transform and the known Laplace transforms of the Heaviside function u(t) and its powers.
The Laplace transform of (t - 4)u²(t) found as follows:
L[(t - 4)u²(t)] = L[tu²(t) - 4u²(t)]
= L[tu²(t)] - L[4u²(t)]
Now, let's find the Laplace transforms of each term separately.
Using the time-shifting property of the Laplace transform,
L[tu²(t)] = e(-s × 0) × L[u²(t)]' (taking the derivative of u²(t))
= L[u²(t)]'
= -d/ds [L[u(t)]²] (using the Laplace transform of u(t) and the derivative property of the Laplace transform)
The Laplace transform of u(t) is 1/s, so
L[u²(t)]' = -d/ds [(1/s)²]
= -d/ds [1/s²]
= 2/s³
Similarly, for L[4u²(t)],
L[4u²(t)] = 4 × L[u²(t)]
= 4 × 2/s³
= 8/s³
Now, let's combine the results:
L[(t - 4)u²(t)] = -d/ds [L[u(t)]²] - 8/s³
= -d/ds [(1/s)²] - 8/s³
= -d/ds [1/s²] - 8/s³
= 2/s³ - 8/s³
= -6/s³
Next, let's find the Laplace transform of (t - 2)u²(t):
L[(t - 2)u²(t)] = L[tu²(t)] - L[2u²(t)]
Using similar steps as before, we find:
L[tu²(t)] = -d/ds [L[u(t)]²]
= -d/ds [(1/s)²]
= -24/s²
L[2u²(t)] = 2 × L[u²(t)]
= 2 × 24/s²
= 48/s³
Combining the results
L[(t - 2)u²(t)] = -24/s² - 48/s²
= -72/s³
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Find all points (x, y) on the graph of y = x/(x - 2) with tangent lines perpendicular to the line y = 2x + 3.
The point (x, y) on the graph of y = x/(x - 2) with tangent lines perpendicular to the line y = 2x + 3 is (x, y) = (√2 + 2, 1 + √2).
To find the points (x, y) on the graph of y = x/(x - 2) where the tangent lines are perpendicular to the line y = 2x + 3, we need to determine the conditions for perpendicularity between the slopes of the tangent lines and the given line.
The slope of the tangent line to the graph of y = x/(x - 2) can be found using the derivative. Taking the derivative of y with respect to x, we have:
dy/dx = [(x - 2)(1) - x(1)] / [tex](x - 2)^2[/tex]
= -2/ [tex](x - 2)^2[/tex]
The slope of the given line y = 2x + 3 is 2.
For two lines to be perpendicular, the product of their slopes must be -1. So, we have:
(-2/ [tex](x - 2)^2[/tex]) * 2 = -1
Simplifying this equation, we get:
-4 / [tex](x - 2)^2[/tex] = -1
4 = [tex](x - 2)^2[/tex]
2 = x - 2
Taking the square root of both sides, we have:
√2 = x - 2
Solving for x, we get:
x = √2 + 2
Substituting this value of x back into the equation y = x/(x - 2), we can find the corresponding y-value:
y = (√2 + 2) / (√2 + 2 - 2)
= (√2 + 2) / √2
= (√2/√2 + 2/√2)
= 1 + √2
Therefore, the point (x, y) on the graph of y = x/(x - 2) with tangent lines perpendicular to the line y = 2x + 3 is (x, y) = (√2 + 2, 1 + √2).
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1. Consider the matrix A=[3 3 2 8]. (a) Let u=[ 2 3] and v=[ −2 1]. Are u and v eigenvectors of A ? (b) Show that 9 is an eigenvalue of A and find the corresponding eigenvectors.
To determine if u and v are eigenvectors of a matrix A, use the formula Av=λv, where λ is the corresponding eigenvalue. If u=6, v=−3, then u and v are not eigenvectors of A. To find corresponding eigenvectors, substitute λ=9 in the equation (A-λI)X=0.
(a) Let A=[3 3 2 8], u=[ 2 3] and v=[ −2 1].
We can define a vector v to be an eigenvector of a matrix A if the following holds: Av=λv where λ is the corresponding eigenvalue. We will now test if u and v are eigenvectors of A as shown below;
u=[ 2 3]
Au= [3 3 2 8] [2 3]
= [12 18]
= 6[ 2 3]
We can clearly see that Au=6u.
Therefore u is an eigenvector of A corresponding to the eigenvalue 6.
v=[ −2 1]
Av= [3 3 2 8] [−2 1]
= [−6 3]
= −3[ −2 1]
We can clearly see that Av=−3v.
Therefore v is an eigenvector of A corresponding to the eigenvalue −3.No, u and v are not eigenvectors of A.(b) To show that 9 is an eigenvalue of A, we can proceed as shown below:|A-λI| =0 where I is the identity matrix of same size as A.
|A-λI| = |3−λ 3 2 8−λ|
= (3-λ)(8-λ)-2(3)(2)|A-λI|
= λ2 − 11λ + 18
= 0(λ−2)(λ−9)
= 0.
We obtain the eigenvalues λ1=2 and λ2=9.
To find the corresponding eigenvectors we substitute λ=9 in the equation (A-λI)X=0 as shown below:We have;
A−9I = [−6 3 2 −1]X
= [x1x2]
⇒[−6 3 2 −1] [x1x2]
= [0 0].
Solving we obtain x1=−x2/2. Choosing x2=2 we get the eigenvector [−2 4]. Hence the corresponding eigenvectors are given by;v1=[ 2 3] corresponding to eigenvalue λ1=2v2=[ −2 4] corresponding to eigenvalue λ2=9.
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The original 24 m edge length x of a cube decreases at the rate of 3 m/min. a. When x=6 m, at what rate does the cube's surface area change? b. When x=6 m, at what rate does the cube's volume change?
The rate of change of the cube's volume is -216m³/min when x=6m.
a) When x = 6m, the rate of change of the cube's surface area is 54m²/min.b) When x = 6m, the rate of change of the cube's volume is -216m³/min.
Let's derive the formulas for the surface area and volume of a cube in terms of the edge length. Let the edge length of the cube be x.Surface area of a cube A cube has six equal faces. Therefore, the surface area of the cube is given by: Surface area of cube = 6x² Volume of a cubeThe volume of a cube is given by the product of the length, width and height of the cube. In this case, all dimensions of the cube are equal to x.Volume of cube = x³Given that the original edge length of the cube is 24m and is decreasing at the rate of 3 m/min.
Let's differentiate the formula of surface area of a cube with respect to time to obtain the rate of change of surface area with respect to time. Surface area of cube = 6x² Differentiating both sides with respect to time, we get: dS/dt = 12x(dx/dt) Now substitute x = 6m and dx/dt = -3 m/min to obtain the rate of change of surface area when x = 6m.dS/dt = 12x(dx/dt)dS/dt = 12(6²)(-3)dS/dt = -648m²/minTherefore, the rate of change of the cube's surface area is 54m²/min when x=6m. Let's differentiate the formula of volume of a cube with respect to time to obtain the rate of change of volume with respect to time.Volume of cube = x³ Differentiating both sides with respect to time, we get:dV/dt = 3x²(dx/dt)Now substitute x = 6m and dx/dt = -3 m/min to obtain the rate of change of volume when x = 6m.dV/dt = 3x²(dx/dt)dV/dt = 3(6²)(-3)dV/dt = -324m³/min
Therefore, the rate of change of the cube's volume is -216m³/min when x=6m.
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Felicia opens a chequing account that charges a monthly maintenance fee of $10.75. She starts her account by depositing $500 at the start of January. At the end of March, how much money will she have in her account? Assume that she does not make any deposits or withdrawals over this time period.
Answer:
467.65
Step-by-step explanation:
use the guidelines of this section to sketch the curve. y = x /x 2 − 25
Answer:
Step-by-step explanation:
To sketch the curve of the equation y = x / (x^2 - 25), we can start by analyzing the behavior of the function for different values of x.
First, let's identify any vertical asymptotes by finding the values of x that make the denominator equal to zero. In this case, the denominator x^2 - 25 becomes zero when x = ±5. Therefore, we have vertical asymptotes at x = -5 and x = 5.
Next, let's check the behavior of the function near these vertical asymptotes. We can do this by evaluating the function for values of x that approach the asymptotes from both sides.
As x approaches -5 from the left side (x < -5), the function becomes very negative since the numerator (-5) is negative, and the denominator becomes positive but small. As x approaches -5 from the right side (x > -5), the function becomes very positive since the numerator (+5) is positive, and the denominator becomes positive but small. This indicates that there is a vertical asymptote at x = -5.
Similarly, as x approaches 5 from the left side (x < 5), the function becomes very negative since the numerator (-5) is negative, and the denominator becomes positive but small. As x approaches 5 from the right side (x > 5), the function becomes very positive since the numerator (+5) is positive, and the denominator becomes positive but small. This indicates that there is also a vertical asymptote at x = 5.
Next, let's find the x-intercepts of the function. The x-intercepts occur when y = 0. Therefore, we can set the numerator x to zero and solve for x:
0 = x
x = 0
So, we have an x-intercept at x = 0.
Now, let's find the y-intercept of the function. The y-intercept occurs when x = 0. Plugging in x = 0 into the equation, we get:
y = 0 / (0^2 - 25) = 0 / (-25) = 0
So, we have a y-intercept at y = 0.
Based on these observations, we can sketch the curve as follows:
There are vertical asymptotes at x = -5 and x = 5.
There is an x-intercept at x = 0.
There is a y-intercept at y = 0.
The curve approaches the vertical asymptotes as x approaches -5 and 5 from both sides. The function value becomes very large in magnitude as x gets close to the vertical asymptotes.
Please note that without more specific information or additional points, it is challenging to precisely sketch the curve. The given guidelines provide a general idea of the behavior of the function.
Evaluate each integral.
∫
x−y
x+y
ydz=
∫
0
x
∫
x−y
x+y
ydzdy=
Now evaluate ∭
E
ydV, where E={(x,y,z)∣0≤x≤4,0≤y≤x,x−y≤z≤x+y}.
We are given three integrals to evaluate. The first integral is ∫[(x-y)/(x+y)] y dz. The second integral is ∫∫[(x-y)/(x+y)] y dz dy. Lastly, we need to evaluate the triple integral ∭E y dV, where E represents a specific region in three-dimensional space.
1. ∫[(x-y)/(x+y)] y dz:
To evaluate this integral, we treat y as a constant with respect to z. Integrating with respect to z, we obtain [(x-y)/(x+y)] yz + C, where C is the constant of integration.
2. ∫∫[(x-y)/(x+y)] y dz dy:
To evaluate this double integral, we integrate with respect to z first, treating y as a constant. Integrating [(x-y)/(x+y)] yz with respect to z yields [(x-y)/(x+y)] yz^2/2 + C. Next, we integrate this expression with respect to y, resulting in [(x-y)/(x+y)] yz^2/2 + Cy + D, where C and D are constants of integration.
3. ∭E y dV:
Here, E represents the region in three-dimensional space defined by E={(x,y,z)|0≤x≤4,0≤y≤x,x−y≤z≤x+y}. To evaluate this triple integral, we integrate the function y over the region E. We can rewrite the integral as ∭E y dV = ∫∫∫E y dV, where we integrate over the region E in the order dz, dy, dx.
Since the region E is defined by the constraints 0≤x≤4, 0≤y≤x, x−y≤z≤x+y, the limits of integration for the triple integral will be:
x: 0 to 4
y: 0 to x
z: x-y to x+y
Evaluating the integral ∭E y dV with these limits will give us the final result.
Hence, the first two integrals have been evaluated, and the triple integral over the region E has been set up. To complete the evaluation, the specific expression for y within the region E needs to be determined and integrated over the defined limits of integration.
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Q1. Consider an array having elements: 10 2 66 71 12 34 8 52 Sort the elements of the array in an ascending order using selection sort algorithm. Q2. Write an algorithm that defines a two-dimensional array. Q3. You are given an one dimensional array. Write an algorithm that finds the smallest element in the array. Q4. Consider an array having elements: 10 2 66 71 12 34 8 52 Sort the elements of the array in an ascending order using insertion sort algorithm. Q5. Write an algorithm that reads 2 integer numbers from data medium and finds the sum of them
The given array is 10 2 66 71 12 34 8 52. Selection sort is a simple algorithm that is used to sort an array in ascending or descending order.
Selection sort is performed by selecting the smallest (or largest) element from the unsorted subarray and placing it at the beginning of the array. Then, repeat this process until the entire array is sorted. Here's how to use selection sort to sort the given array in ascending order: Step 1: Initialize the minimum value as the first element of the array. Step 2: Compare this value with all of the other values in the array. If any value is less than the minimum value, assign that value to the minimum value. Step 3: Swap the minimum value with the first element of the unsorted subarray. Step 4: Repeat steps 1-3 for the remainder of the array until the entire array is sorted. The sorted array is 2 8 10 12 34 52 66 71. The selection sort algorithm is a simple, easy-to-understand algorithm that sorts an array in ascending or descending order. This algorithm works by repeatedly selecting the smallest (or largest) element from the unsorted subarray and placing it at the beginning of the array. Then, the algorithm moves on to the next element of the unsorted subarray and repeats the process. This process is repeated until the entire array is sorted. One of the benefits of the selection sort algorithm is that it is easy to understand and implement. However, it is not very efficient, particularly for large arrays. This is because the algorithm has to scan the entire unsorted subarray for every element in the sorted subarray. As a result, the algorithm has a time complexity of O(n^2). Selection sort is not the best choice for sorting large arrays, but it can be useful for sorting small arrays or for educational purposes. The selection sort algorithm is a simple, easy-to-understand algorithm that can be used to sort an array in ascending or descending order. However, it is not very efficient for large arrays and has a time complexity of O(n^2). The algorithm that defines a two-dimensional array: Step 1: Start Step 2: Declare a two-dimensional array of m rows and n columns, where m and n are integers. Step 3: Initialize the array by assigning values to its elements. This can be done using nested loops that iterate over the rows and columns of the array. Step 4: Display the elements of the array. This can be done using nested loops that iterate over the rows and columns of the array. Step 5: End The algorithm that finds the smallest element in a one-dimensional array: Step 1: Start Step 2: Declare an array of n elements, where n is an integer. Step 3: Initialize the array by assigning values to its elements. This can be done using a loop that iterates over the array and reads in values from the user. Step 4: Set the minimum value to the first element of the array. Step 5: Compare the minimum value with each of the other elements in the array. If any element is less than the minimum value, assign that element to the minimum value. Step 6: Display the minimum value. Step 7: End The given array is: 10 2 66 71 12 34 8 52 Insertion sort is a simple algorithm that is used to sort an array in ascending or descending order. Insertion sort is performed by iterating over the array and inserting each element into its proper position in the sorted subarray. Here's how to use insertion sort to sort the given array in ascending order: Step 1: Iterate over the array starting from the second element. This is because the first element is already considered sorted. Step 2: Compare the current element with the elements in the sorted subarray. If any element is greater than the current element, move that element to the right to make room for the current element. Step 3: Insert the current element into its proper position in the sorted subarray. Step 4: Repeat steps 1-3 for the remainder of the array until the entire array is sorted. The sorted array is 2 8 10 12 34 52 66 71Q5. The algorithm reads 2 integer numbers and finds their sum. Step 1: Start Step 2: Read the first integer number from the data medium and assign it to variable a. Step 3: Read the second integer number from the data medium and assign it to variable b. Step 4: Add the values of a and b and assign the result to variable c. c = a + b Step 5: Display the value of c. Step 6: End
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given ln 2 = .6931, ln 5 = 1.6094 , find ln√ e^7
Given \( \ln 2=.6931 \) \( \ln 5=1.6094 \), Find \( \ln \sqrt{e^{\pi}} \) ?
For \( \ln 2=.6931 \) \( \ln 5=1.6094 \) , \( \ln \sqrt{e^{\pi}} \) = \pi/2 \).
To find \( \ln \sqrt{e^{\pi}} \), we can break it down as:
Simplify the expression \( \sqrt{e^{\pi}} \)
The square root of \( e^{\pi} \) is equal to \( (e^{\pi})^{1/2} \). And according to the rules of exponents, \( (e^{\pi})^{1/2} = e^{\pi/2} \).
Take the natural logarithm of \( e^{\pi/2} \)
Since \( \ln \) is the natural logarithm, we can find \( \ln e^{\pi/2} \) which simplifies to \( \pi/2 \).
Therefore, \( \ln \sqrt{e^{\pi}} = \pi/2 \).
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when performing a test of a control with respect to control over cash receipts, an auditor may use a systematic sampling technique with a start at any randomly selected item. the biggest disadvantage of this type of sampling is that the items in the populationgroup of answer choicesa. must be systematically replaced in the population after sampling.b. may systematically occur more than once in the sample.c. must be recorded in a systematic pattern before the sample can be drawn.d. may occur in a systematic pattern, thus destroying the sample randomness.
Systematic sampling is a statistical sampling technique that is widely used by auditors when performing tests of controls with respect to control over cash receipts. This technique is popular because of its ease of use, and the results obtained from it are reliable.
Like any other statistical sampling technique, it has its advantages and disadvantages. One of the biggest disadvantages of using systematic sampling is that it may systematically occur more than once in the sample. When performing a systematic sampling technique with a start at any randomly selected item, auditors may select an item more than once in the sample, which may result in biased results that do not reflect the true state of the population.
This is particularly true when the population is not homogenous, and some items in the population are more likely to be selected than others. When using systematic sampling, auditors should take care to ensure that the sample is truly random, and that each item in the population has an equal chance of being selected.
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What is the solution (using back substitution method) to the following system of congruences? 3x≡4(mod5) 2x≡2(mod4) a
nd x≡1(mod3) a.Since 2 does not admit a multiplicative inverse inZ4 this system does not have any solution. b.The set of all x of the form x=60t+13 for an integer t. c.The set of all x of the form x=30t+13 for an integer t. d.None of these is correct. e.The set of all x of the form x=30t+43 for an integer t.
Using the back substitution method, the correct answer is (c), the set of all x of the form x=3t+1 for an integer t.
[tex]$$3x \equiv 4\pmod{5}$$[/tex]
The value of x will be equal to the first value in the last row of the table.
[tex]$$2x \equiv 2\pmod{4}$$[/tex]
The value of x will be equal to the first value in the last row of the table.
[tex]$$x \equiv 1\pmod{3}$$[/tex]
The value of x will be equal to the first value in the last row of the table.The possible values of x are the same in all the three equations.
Thus, x can be equal to either 5t+2 or 4t+1 or 3t+1.
To obtain x for each of these equations, substitute the value of x in other equations to find the t values.The first two equations will result in contradiction, so the third one will be used to find the solutions.
[tex]$$x \equiv 3t+1\pmod{3}$$[/tex]
Therefore, x will have the form x=3t+1, for some integer t.The required solution (using back substitution method) to the given system of congruences is the set of all x of the form x=3t+1 for an integer t.
To solve the given system of congruences using the back substitution method, we need to first simplify each equation so that the value of x can be easily determined. Once the value of x is found for each equation, we can then find the possible values of x that satisfy all three equations.
Using the first equation, 3x≡4(mod5), we can write x=5t+2, where t is an integer.
Similarly, using the second equation, 2x≡2(mod4), we can write x=2t+1, where t is an integer.
However, the value of x obtained from these two equations does not satisfy the third equation, x≡1(mod3).
Therefore, we need to use the third equation to find the possible values of x.
Using this equation, x≡1(mod3), we can write x=3t+1, where t is an integer.
Now, we can substitute this value of x in the first two equations to find the value of t.Substituting x=3t+1 in the first equation, 3x≡4(mod5), we get 9t+3≡4(mod5), which gives t≡3(mod5). Substituting x=3t+1 in the second equation, 2x≡2(mod4), we get 6t+2≡2(mod4), which gives t≡0(mod2).
Therefore, t can be written as t=2k, where k is an integer.Substituting t=2k in x=3t+1, we get x=6k+1.
Therefore, the possible values of x that satisfy all three equations are of the form x=6k+1, where k is an integer.
To summarize, the solution to the given system of congruences (using back substitution method) is the set of all x of the form x=6k+1 for an integer k.
Using the back substitution method, we found that the solution to the given system of congruences is the set of all x of the form x=3t+1 for an integer t. The other options are not correct. Option (a) is incorrect because this system does have a solution. Option (b) is incorrect because the values of x do not satisfy all three equations. Option (c) is the correct answer. Option (d) is incorrect because there is a solution to this system of congruences. Option (e) is incorrect because the values of x do not satisfy all three equations. Therefore, the correct answer is (c), the set of all x of the form x=3t+1 for an integer t.
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find the standard deviation for the given sample data. round your answer to one more decimal place than is present in the original data.184 169 120 271 230 114 163 241 110
The standard deviation of the given sample data is 55.7, the standard deviation is a measure of how spread out the values in a data set are.
It is calculated by taking the square root of the variance. The variance is calculated by taking the average of the squared differences between each value in the data set and the mean.
In this case, the mean of the data set is 177.67. The variance is 3123.53. The standard deviation is the square root of 3123.53, which is 55.7.
Here is a step-by-step calculation of the standard deviation:
Calculate the mean:
mean = (184 + 169 + 120 + 271 + 230 + 114 + 163 + 241 + 110) / 9 = 177.67
Calculate the squared differences between each value in the data set and the mean:
(184 - 177.67)^2 = 32.49
(169 - 177.67)^2 = 4.84
(120 - 177.67)^2 = 240.96
(271 - 177.67)^2 = 554.89
(230 - 177.67)^2 = 190.49
(114 - 177.67)^2 = 343.69
(163 - 177.67)^2 = 23.04
(241 - 177.67)^2 = 242.25
(110 - 177.67)^2 = 359.29
Calculate the variance:
variance = (32.49 + 4.84 + 240.96 + 554.89 + 190.49 + 343.69 + 23.04 + 242.25 + 359.29) / 9 = 3123.53
Calculate the standard deviation:
standard deviation = sqrt(3123.53) = 55.7
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A dishonest shopkeeper marks his goods 40% above the cost price and gives a 25% discount to customers. at time of selling the goods uses a false 1kg of weight which actually weighs 800gm find his profit
The dishonest shopkeeper marks his goods with a 40% markup and offers a 25% discount to customers. The profit earned by the shopkeeper on this particular item is $105 - $100 = $5.
Let's consider the cost price of an item to be $100. The shopkeeper marks it up by 40%, which results in a selling price of $140. However, the shopkeeper then offers a 25% discount on this inflated price, bringing the price down to $105.
Now, regarding the weight manipulation, the shopkeeper falsely claims that the weight of the item is 1kg. However, in reality, it weighs only 800g. Since the selling price is determined based on weight, the customer is paying the price of 1kg while receiving only 800g of the item.
To calculate the profit, we need to subtract the cost price from the selling price. The selling price, taking into account the discount and weight manipulation, is $105. The cost price is $100. Hence, the profit earned by the shopkeeper on this particular item is $105 - $100 = $5.
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Find the point on curve where the point is horizontal or vertical. If you have a graphic device, graph the curve to checkyour work
x=2t^3+3t^2−36t,y=2t^3+3t^2+5
horizontal tangent (x,y)=
vertical tangent (x,y)=
The horizontal tangent is (0, 5) and (81, 98). The vertical tangent is (-135, -32) and (60, 23).Graph of the curve: Please refer to the attachment.
The given curve is x=2t³+3t²−36t and
y=2t³+3t²+5.
We need to find the points on the curve where the point is horizontal or vertical, and if we have a graphic device, we can graph the curve to check our work.
Given: x=2t³+3t²−36t,
y=2t³+3t²+5
We know that for a curve, if the point is horizontal, then its derivative should be zero.
We will find the derivative of y with respect to x using the Chain Rule of Differentiation.
dy/dx = dy/dt ÷ dx/dt(dy/dx)
= (dy/dt) / (dx/dt)
We are given two equations x=2t³+3t²−36t and
y=2t³+3t²+5We need to find the derivative of y with respect to x and equate it to zero to find the points where the point is horizontal. Let's do it:
dx/dt = 6t² + 6t - 36x
= 0x - 2t³ - 3t² + 36t
= 0t
= 0, 3
We have found two values of t, i.e. t = 0 and
t = 3.
Let's find the corresponding points on the curve:
For t = 0,
x = 0 and
y = 5.
So, the point is (0, 5).
For t = 3,
x = 81
and y = 98.
So, the point is (81, 98).
Now, we need to find the derivative of x with respect to y to find the points where the point is vertical. dy/dt = 6t² + 6tdx/dt
= 6t² + 6t - 36
We need to find the values of t for which the derivative of x with respect to y is zero. dx/dt = 6t² + 6t - 36 = 0t² + t - 6
= 0t = -3, 2
We have found two values of t, i.e. t = -3 and t = 2.
Let's find the corresponding points on the curve:
For t = -3,
x = -135 and
y = -32.
So, the point is (-135, -32).For t = 2,
x = 60 and
y = 23.
So, the point is (60, 23).
Therefore, the horizontal tangent is (0, 5) and (81, 98). The vertical tangent is (-135, -32) and (60, 23).Graph of the curve: Please refer to the attachment.
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how would increases in tolerable misstatement and the assessed level of control risk affect the sample size in a substantive test of details? group of answer choices a. increases in both tolerable misstatement and the assessed level of control risk would increase the sample size. b. an increase in tolerable misstatement would increase the sample size while an increase in the assessed level of control risk would decrease the sample size. c. an increase in tolerable misstatement would decrease the sample size while an increase in the assessed level of control risk would increase the sample size. d. increases in both the tolerable misstatement and the assessed level of control risk would decrease the sample size.
The increases in tolerable misstatement and the assessed level of control risk affect the sample size in a substantive test of details is b. an increase in tolerable misstatement would increase the sample size while an increase in the assessed level of control risk would decrease the sample size.
There are various factors that affect the sample size in a substantive test of details, including tolerable misstatement and the assessed level of control risk. The tolerable misstatement is the maximum amount of error that the auditor is prepared to accept in the financial statements. It is based on materiality, which is influenced by the size of the financial statements and the risk of misstatement. As the tolerable misstatement increases, the sample size decreases since the auditor can tolerate more error in the financial statements.
The assessed level of control risk reflects the degree of reliance that the auditor can place on the client's internal controls. As the assessed level of control risk increases, the sample size also increases since the auditor will need to perform more substantive procedures to obtain sufficient and appropriate audit evidence. Therefore, the correct answer is "b. an increase in tolerable misstatement would increase the sample size while an increase in the assessed level of control risk would decrease the sample size."
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3. Solve the system of equations algebraically, in exact values. ( 3 marks) y=2x 2−10x+12 and 2x+ 1/3 y=x^2
The exact values of the solutions for the system of equations are given by:
x = 3 + (1/2)√(6(18 + y))
y = 6 + √(6(18 + y))
and
x = 3 - (1/2)√(6(18 + y))
y = 6 - √(6(18 + y))
To solve the system of equations algebraically, we'll start by setting the two equations equal to each other:
2x^2 - 10x + 12 = 2x + (1/3)y
Next, let's rearrange the equation to bring all terms to one side:
2x^2 - 10x + 12 - 2x - (1/3)y = 0
Combining like terms, we have:
2x^2 - 12x + 12 - (1/3)y = 0
To simplify the equation further, we can multiply through by 3 to eliminate the fraction:
6x^2 - 36x + 36 - y = 0
Now we have a quadratic equation in terms of x and y. However, this equation is not easily factorable. To find the exact values of x and y, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 6, b = -36, and c = 36 - y. Substituting these values into the quadratic formula, we have:
x = (-(-36) ± √((-36)^2 - 4(6)(36 - y))) / (2(6))
= (36 ± √(1296 - 864 + 24y)) / 12
= (36 ± √(432 + 24y)) / 12
= (36 ± √(24(18 + y))) / 12
= (36 ± 2√(6(18 + y))) / 12
= (6 ± √(6(18 + y))) / 2
= 3 ± (1/2)√(6(18 + y))
Thus, the exact values of x are given by x = 3 ± (1/2)√(6(18 + y)).
To find the corresponding values of y, we can substitute the x-values back into one of the original equations. Let's use the equation y = 2x:
For x = 3 + (1/2)√(6(18 + y)):
y = 2(3 + (1/2)√(6(18 + y)))
= 6 + √(6(18 + y))
For x = 3 - (1/2)√(6(18 + y)):
y = 2(3 - (1/2)√(6(18 + y)))
= 6 - √(6(18 + y))
Therefore, the exact values of the solutions for the system of equations are given by:
x = 3 + (1/2)√(6(18 + y))
y = 6 + √(6(18 + y))
and
x = 3 - (1/2)√(6(18 + y))
y = 6 - √(6(18 + y))
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Eliminate the parameter to velate the \( x \) and \( y \) variables directly C) \( x=5+\cos t, \quad y=3 \sin t, \quad 0 \leq t \leq \pi \)
The parameterization in terms of (x) and (y) is:
[y = 3\sin^{-1}(x-5)]
where (-1 \leq \sin^{-1}(x-5) \leq 1).
To eliminate the parameter (t), we can use the trigonometric identity (\cos^2 t + \sin^2 t = 1) to express (\cos t) in terms of (\sin t):
[\cos t = \sqrt{1 - \sin^2 t}]
Substituting this into the equation for (x), we get:
[x = 5 + \sqrt{1 - \sin^2 t}]
Simplifying this expression requires a bit of algebraic manipulation. We can start by multiplying the numerator and denominator of the radical by (\cos^2 t + \sin^2 t = 1):
[x = 5 + \sqrt{1 - \sin^2 t} \cdot \frac{\cos^2 t + \sin^2 t}{\cos^2 t + \sin^2 t}]
[x = 5 + \sqrt{\frac{\cos^2 t}{\cos^2 t + \sin^2 t}}]
[x = 5 + \sqrt{\frac{\cos^2 t}{1}}]
[x = 5 + \left|\cos t\right|]
Note that we take the absolute value of (\cos t) because it can be negative depending on the value of (t).
Now we can substitute the expression we found for (x) into the equation for (y) to get:
[y = 3\sin t]
So the parameterization in terms of (x) and (y) is:
[y = 3\sin^{-1}(x-5)]
where (-1 \leq \sin^{-1}(x-5) \leq 1).
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Find the length of the curve given by
a) r(t)=ti+ln(sect)j+3k from t=0 to t=pi/4
b) r(t)=(tsint+cost)i+(sint-tcost)j+(sqrt(3)/2)t^2k
The length of the curve given by
a) `r(t)=ti+ln(sect)j+3k from
t=0 to
t=pi/4` is `ln(√2+1)`.
b) `r(t)=(tsint+cost)i+(sint-tcost)j+(sqrt(3)/2)t^2k` is approximately `1.4817`.
a) We can find the length of the curve as shown below: The curve is defined as `r(t)=ti+ln(sect)j+3k
from t=0 to
t=pi/4`.
To find the length, we use the formula:
s=∫ab|v(t)|dt
where `v(t)=dr/dt` and
a=0` and
b=π/4
First, we find `v(t)`:
`v(t)=dr/dt
=i+d/dt[ln(sec t)]j+0`
Let's simplify `d/dt[ln(sec t)]`:
`d/dt[ln(sec t)]=d/dt[ln(1/cos t)]
=-d/dt[ln(cos t)]
=-tan t`
Thus, `v(t)=i-tan t j`.
Now, let's find `|v(t)|`:`|v(t)|
=√(i-tan t j)·(i-tan t j)
=√(1+tan^2 t)
=√sec^2 t
=sec t`
Thus, `s=∫ab|v(t)|dt
=∫0^(π/4) sec t dt
=ln(sec t+tan t)|_0^(π/4)
=ln(√2+1)-ln(1)
=ln(√2+1)`.
Therefore, the length of the curve is `ln(√2+1)`.
b) We can find the length of the curve as shown below:
The curve is defined as `r(t)=(tsint+cost)i+(sint-tcost)j+(sqrt(3)/2)t^2k`.
To find the length, we use the formula:
s=∫ab|v(t)|dt`
where `v(t)=dr/dt` and
a=0` and
b=1`.
First, we find `v(t)`:
v(t)=dr/dt
=cos t i+(cos t-sin t)j+sqrt(3)t k`
Now, let's find `|v(t)|`:
|v(t)|=√(cos t i+(cos t-sin t)j+sqrt(3)t k)·(cos t i+(cos t-sin t)j+sqrt(3)t k)
=√(cos^2 t+(cos t-sin t)^2+3t^2)
=√(2-2sin t+4t^2)
Thus, `s=∫ab|v(t)|dt
=∫0^1 √(2-2sin t+4t^2) dt
≈1.4817
Therefore, the length of the curve is approximately `1.4817`.
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2.9x10 to the power 5 x 8.7x10 to the power 3
[tex]2.9\times 10^{5} ~~ \times ~~ 8.7\times 10^{3}\implies (2.9)(8.7)\times 10^5\cdot 10^3 \\\\\\ (25.23)\times 10^{5+3}\implies 25.23\times 10^8\implies 2.523 \times 10^9[/tex]
Use the Chain Rule to find dQ/dt, where Q= sq rt x^2 + y^2 + 5z^2 , x=sint, y=cost, and z=sint.
Find the following
partial Q/partial x =
dx/dt=
partial Q/partial y =
dy/dt=
partial Q/partial z =
dz/dt =
dQ/dt =
This expression gives: dQ/dt = (5sintcost)/sqrt(1+4sin^2t)
Using the Chain Rule, we have:
dQ/dt = (partial Q/partial x)(dx/dt) + (partial Q/partial y)(dy/dt) + (partial Q/partial z)(dz/dt)
To find partial Q/partial x, we differentiate Q with respect to x while holding y and z constant:
partial Q/partial x = x/sqrt(x^2 + y^2 + 5z^2) = sint/sqrt(sin^2t + cos^2t + 5sin^2t) = sint/sqrt(1+4sin^2t)
To find dx/dt, we differentiate x with respect to t:
dx/dt = cost
Similarly, we can find partial Q/partial y, dy/dt, partial Q/partial z, and dz/dt:
partial Q/partial y = y/sqrt(x^2 + y^2 + 5z^2) = cost/sqrt(sin^2t + cos^2t + 5sin^2t) = cost/sqrt(1+4sin^2t)
dy/dt = -sint
partial Q/partial z = 5z/sqrt(x^2 + y^2 + 5z^2) = 5sint/sqrt(sin^2t + cos^2t + 5sin^2t) = 5sint/sqrt(1+4sin^2t)
dz/dt = cost
Substituting these values into the chain rule formula gives:
[tex]dQ/dt = (sint/sqrt(1+4sin^2t))(cost) + (cost/sqrt(1+4sin^2t))(-sint) + (5sint/sqrt(1+4sin^2t))(cost)[/tex]
Simplifying this expression gives:
dQ/dt = (5sintcost)/sqrt(1+4sin^2t)
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A survey in one country,as reported by the Los Angeles times,Found that 66% of young people feel themselves to be under heavy pressure. If a sample of 8 young people in China is selected, what is the probability that at least one will report being under heavy pressure?
the probability that at least one person out of 8 will report being under heavy pressure is approximately 0.990428, or 99.04%.
To find the probability that at least one person out of 8 will report being under heavy pressure, we can use the complement rule.
The probability that none of the 8 people will report being under heavy pressure is given by:
P(none under heavy pressure) = (1 - 0.66)⁸ = 0.009572
The complement of this probability (i.e., the probability that at least one person will report being under heavy pressure) is:
P(at least one under heavy pressure) = 1 - P(none under heavy pressure) = 1 - 0.009572 = 0.990428
Therefore, the probability that at least one person out of 8 will report being under heavy pressure is approximately 0.990428, or 99.04%.
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Let S be the following set of ordered pairs of integers: Base case: (1, 1) ES Recursive step: If (m, n) e S, then (m + 2, n) e S and (m, n+4) € S. . . Use structural induction to prove that the product mn is odd for all (m, n) e S.
By satisfying the recursive step, we have shown that if (m, n) has an odd product mn, then both (m + 2, n) and (m, n + 4) also have odd products.
To prove that the product mn is odd for all (m, n) in the set S using structural induction, we need to establish two conditions: Base case: Show that the product of (1, 1) is odd. Recursive step: Assume that for any (m, n) in S, if (m, n) has an odd product, then (m + 2, n) and (m, n + 4) also have odd products. Let's proceed with the proof:
Base case: For the ordered pair (1, 1), the product mn = 1 * 1 = 1, which is indeed an odd number.
Recursive step: Assume that for any (m, n) in S, if (m, n) has an odd product mn, then (m + 2, n) and (m, n + 4) also have odd products.
Now, consider an arbitrary ordered pair (m, n) in S with an odd product mn. According to the recursive step, we need to show that (m + 2, n) and (m, n + 4) also have odd products. For (m + 2, n): The product is (m + 2) * n = mn + 2n. Since mn is odd (as assumed), and 2n is always even (since n is an integer), the sum mn + 2n will remain odd. For (m, n + 4): The product is m * (n + 4) = mn + 4m. Again, since mn is odd (as assumed), and 4m is always even (since m is an integer), the sum mn + 4m will remain odd.
By satisfying the recursive step, we have shown that if (m, n) has an odd product mn, then both (m + 2, n) and (m, n + 4) also have odd products. Based on the base case and the recursive step, we have established that the product mn is odd for all (m, n) in the set S using structural induction.
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Let \( f(x, y)=x e^{x y} . \) Find the maximum rate of change of \( f \) at the point \( (3,-2) \)
The maximum rate of change of f at the point (3,-2) is equal to √(10e⁻⁶ - 6e⁻¹²).
Given that f(x,y) = xe^(xy), we need to find the maximum rate of change of f at the point (3,-2).
To find the maximum rate of change of f, we can use the partial derivatives of f with respect to x and y.
Let's begin with finding the partial derivative of f with respect to x:
∂f/∂x = e^(xy) + xye^(xy)
Next, we find the partial derivative of f with respect to y:
∂f/∂y = x²e^(xy)
Now we can find the maximum rate of change of f using the partial derivatives we just found:
Rate of change of f = √((∂f/∂x)² + (∂f/∂y)²)
Substituting the given values x = 3 and y = -2 into the above equation, we get:
Rate of change of f = √((e^(-6) - 6)² + 9e⁻⁶)
To simplify the expression, we can use the exponential formula (a - b)^2 = a^2 - 2ab + b^2. Using this, we get:
Rate of change of f = √(e^(-12) - 12e⁻⁶ + 36e⁻¹² + 9e⁻⁶)
Further simplifying, we have:
Rate of change of f = √((10e⁻⁶ - 6e⁻¹²))
In summary, the maximum rate of change of f at the point (3,-2) is equal to √(10e⁻⁶ - 6e⁻¹²).
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Determine the following for the set of coupled first order differential equation shown:
x 1'=(0)x1+(1)x2
x'2=-(36)x'-(20)x2
a) Express using matrices, labelling each matrix. b) The characteristic equation. c) The 2 Eigen values. d) The 2 Eigen vectors. e) The general solution.
The given set of coupled first-order differential equations can be expressed using matrices, where each matrix represents a part of the system. The characteristic equation is obtained by finding the determinant of the matrix and setting it equal to zero.
(a) Let's define the vectors \(x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix}\) and \(A\) as the coefficient matrix:
\[A = \begin{bmatrix} 0 & 1 \\ -36 & -20 \end{bmatrix}\]
The given set of coupled first-order differential equations can be written as \(x' = Ax\), where \(x' = \begin{bmatrix} x_1' \\ x_2' \end{bmatrix}\).
(b) To find the characteristic equation, we need to calculate the determinant of the matrix \(A\) and set it equal to zero:
\(\text{det}(A - \lambda I) = 0\)
where \(\lambda\) is the eigenvalue and \(I\) is the identity matrix.
(c) By solving the characteristic equation, we find the eigenvalues. These eigenvalues are the roots of the characteristic equation and provide information about the stability and behavior of the system.
(d) The eigenvectors can be obtained by substituting each eigenvalue into the matrix equation \((A - \lambda I)v = 0\), where \(v\) represents the eigenvector corresponding to the eigenvalue.
(e) The general solution can be expressed as \(x(t) = c_1e^{\lambda_1t}v_1 + c_2e^{\lambda_2t}v_2\), where \(c_1\) and \(c_2\) are constants, \(\lambda_1\) and \(\lambda_2\) are the eigenvalues, and \(v_1\) and \(v_2\) are the corresponding eigenvectors. This general solution represents the solution to the system of differential equations.
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Find the local extrema of f(x)=x
3
−48x on the closed interval [−5,6]. Solution. Let f(x)=2x
2
+2x−5.Show that f satisfies the hypotheses of Rolle's Theorem on the interval [−3,2], and find all real numbers c in (−3,2) such that f
′
(c)=0.
We have proved that if ∫(a to b) f(x) dx = 0 and f(x) ≥ 0 for all x ∈ [a, b], then f(x) = 0 for all x ∈ [a, b].
To prove that f(x) = 0 for all x ∈ [a, b] given ∫(a to b) f(x) dx = 0, we can follow the hint and use the fact that the integral of a non-negative function over an interval is zero if and only if the function is identically zero on that interval.
Let's define F(x) = ∫(a to x) f(t) dt for all x ∈ [a, b]. We want to show that F(x) is a constant function, which will imply that f(x) = F'(x) = 0 for all x ∈ [a, b].
First, we need to prove that F(x) is well-defined and continuous on [a, b]. Since f(x) is continuous on [a, b], by the Fundamental Theorem of Calculus, F(x) is differentiable on (a, b) and continuous on [a, b]. We also have F(a) = ∫(a to a) f(t) dt = 0. Now, we need to prove that F(x) is constant for all x ∈ [a, b].
Suppose, by contradiction, that there exist two points c and d in [a, b] such that F(c) ≠ F(d). Without loss of generality, assume F(c) > F(d).
Consider the interval [c, d]. Since F(x) is continuous on [a, b], it is also continuous on [c, d] (since [c, d] ⊆ [a, b]). By the Mean Value Theorem, there exists a point ξ in (c, d) such that:
F'(ξ) = (F(d) - F(c))/(d - c)
Since F(x) = ∫(a to x) f(t) dt, we can rewrite F'(ξ) as:
F'(ξ) = f(ξ)
Now, since f(x) ≥ 0 for all x ∈ [a, b], we have f(ξ) ≥ 0. However, this
contradicts the assumption that F'(ξ) = f(ξ) ≠ 0, as F(x) is assumed to be non-constant.
Hence, our assumption that F(c) ≠ F(d) leads to a contradiction. Therefore, F(x) must be constant for all x ∈ [a, b].
Since F(x) is a constant function, we have F(x) = F(a) = 0 for all x ∈ [a, b]. This implies that f(x) = F'(x) = 0 for all x ∈ [a, b].
Therefore, we have proved that if ∫(a to b) f(x) dx = 0 and f(x) ≥ 0 for all x ∈ [a, b], then f(x) = 0 for all x ∈ [a, b].
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Using the method of undetermined coefficients, Determine the following for the second order linear homogeneous differential equation and initial conditions. d^2y/dx^2+8dy/dx+12y=5,y(0)=3,dy(0)/dt=9 a) The characteristic equation. b) The type of solution and roots. c) The complementary function solution. d) The particular integral solution. e) The particular solution.
We have to solve this equation using the method of undetermined coefficients. Given differential equation:
[tex]$d^2y/dx^2+8dy/dx+12y=5,y(0)=3,dy(0)/dt=9$[/tex]
Let's solve this equation part by part:
Solution:
a) The characteristic equation is $m^2+8m+12=0.$
To solve this equation, we use the quadratic formula. The roots are:
[tex]$$\begin{aligned} m=\frac{-b±\sqrt{b^2-4ac}}{2a}\end{aligned}$$[/tex]
[tex]$$\begin{aligned}m=\frac{-8±\sqrt{8^2-4(1)(12)}}{2(1)}\end{aligned}$$[/tex]
[tex]$$\begin{aligned}m=-6,-2\end{aligned}$$[/tex]
Therefore, the roots are [tex]$-6$[/tex] and[tex]$-2$.[/tex]
b) The roots are negative and distinct, so the type of solution is
[tex]$$\begin{aligned}y(t)=C_1e^{-2t}+C_2e^{-6t}\end{aligned}$$[/tex]
c) The complementary function solution is
[tex]$$\begin{aligned}y_c(t)=C_1e^{-2t}+C_2e^{-6t}\end{aligned}$$[/tex]
d) The particular integral solution is
[tex]$$\begin{aligned}y_p(t)=A\end{aligned}$$[/tex]
where [tex]$A$[/tex] is the particular constant.
e) The general solution is
[tex]$$\begin{aligned}y(t)=y_c(t)+y_p(t)\end{aligned}$$[/tex]
Substituting the given initial conditions in the general solution, we get
[tex]$$\begin{aligned}3=C_1+C_2+A\\ 9=-2C_1-6C_2\end{aligned}$$[/tex]
Solving these equations, we get
[tex]$$\begin{aligned}C_1=0,C_2=-\frac{3}{4},A=\frac{15}{4}\end{aligned}$$[/tex]
Therefore, the particular solution is
[tex]$$\begin{aligned}y(t)=\frac{15}{4}-\frac{3}{4}e^{-6t}\end{aligned}$$[/tex]
Hence, the solution of the given differential equation is
[tex]$$\begin{aligned}y(t)=C_1e^{-2t}+C_2e^{-6t}+\frac{15}{4}-\frac{3}{4}e^{-6t}\end{aligned}$$[/tex]
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each member of a random sample of 15 business economists was asked to predict the rate of in??ation for the coming year. assume that the predictions for the whole population of business economists follow a normal distribution with standard deviation 1.8%. a) (4pts) the probability is 0.01 that the sample standard deviation is bigger than what number? 0:01
The number for which the sample standard deviation is exceeded with a probability of 0.01 is approximately 29.143.
What is the number for which the sample standard deviation will exceed the probability of 0.01?To find the probability that the sample standard deviation is bigger than a certain number, we can use the chi-square distribution.
Given:
Sample size (n) = 15
Standard deviation of the population (σ) = 1.8%
Significance level (α) = 0.01 (1%)
To find the critical chi-square value, we need to determine the degrees of freedom. For a sample standard deviation, the degrees of freedom are (n - 1).
Degrees of freedom (df) = 15 - 1 = 14
Using a chi-square distribution table or calculator with 14 degrees of freedom and a significance level of 0.01, we find the critical chi-square value to be approximately 29.143.
The probability that the sample standard deviation is bigger than a certain number can be interpreted as the probability of having a chi-square value greater than that number.
Therefore, the probability that the sample standard deviation is bigger than the critical chi-square value of 29.143 is 0.01 or 1%.
In summary, the probability is 0.01 that the sample standard deviation is bigger than 29.143.
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Power companies severely trim trees growing near their lines to avoid power failures due to falling limbs in storms. Applying a chemical to slow the growth of the trees is cheaper than trimming, but the chemical kills some of the trees. Suppose that one such chemical would kill 20% of sycamore trees. The power company tests the chemical on 250 sycamores. Consider these an SRS from the population of all sycamore trees. What is the probability that 24% or more of the trees in the sample are killed? Step #2: Calculate the mean and standard deviation of the sampling distribution. Use appropriate notation. Mean of the Sampling Distribution: Symbol = 1 Formula = Answer: Standard Deviation of the Sampling Distribution: Symbol = Formula = ! Answer: p(1-0) :: :: p :: P "Mo OpMp =p p :: Oộ= V p(1-P) n Op= V n :: 0.24(0.76) 250 = 0.027 0.20 (0.80) 250 0.025 - Up :: = 0.20 * Mô = 0.24
the mean of the sampling distribution is 0.20, and the standard deviation is approximately 0.0253.
To calculate the mean and standard deviation of the sampling distribution, we need to use the following formulas:
Mean of the Sampling Distribution (μ):
μ = p
Standard Deviation of the Sampling Distribution (σ):
σ = √[(p(1 - p)) / n]
where p is the probability of an event (in this case, the probability of a tree being killed), and n is the sample size.
Given that the chemical kills 20% of sycamore trees, we have p = 0.20. The sample size is 250, so n = 250.
Now let's calculate the mean and standard deviation:
Mean of the Sampling Distribution:
μ = p = 0.20
Standard Deviation of the Sampling Distribution:
σ = √[(p(1 - p)) / n]
= √[(0.20(1 - 0.20)) / 250]
= √[(0.16) / 250]
≈ √[0.00064]
≈ 0.0253
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Evaluate the following integral TT S SS y $ cos(x + y + z) dz dx dy 0 o
The value of the given integral is 0.
To evaluate the integral ∫[0,π] ∫[0,y] ∫[0,x] cos(x + y + z) dz dx dy, we can integrate it step by step.
First, let's integrate with respect to z:
∫[0,x] cos(x + y + z) dz = sin(x + y + z) ∣[0,x] = sin(x + y + x) - sin(x + y)
Simplifying, we have:
= sin(2x + y) - sin(x + y)
Next, we integrate with respect to x:
∫[0,y] [sin(2x + y) - sin(x + y)] dx
Using the antiderivative of sin(ax) which is -cos(ax)/a, we have:
= [-cos(2x + y)/2 - (-cos(x + y))/1] ∣[0,y]
= [-cos(2y + y)/2 + cos(y + y)] - [-cos(0 + y)/2 + cos(0 + y)]
= [-cos(3y)/2 + cos(2y)] - [-cos(y)/2 + cos(y)]
= -cos(3y)/2 + cos(2y) + cos(y)/2 - cos(y)
Simplifying, we have:
= cos(y) + cos(2y) - cos(3y)/2
Finally, we integrate with respect to y:
∫[0,π] [cos(y) + cos(2y) - cos(3y)/2] dy
Using the antiderivative of cos(ax) which is sin(ax)/a, we have:
= [sin(y) + sin(2y)/2 - sin(3y)/(2*3)] ∣[0,π]
= [sin(π) + sin(2π)/2 - sin(3π)/(23)] - [sin(0) + sin(0)/2 - sin(0)/(23)]
= [0 + 0 - 0] - [0 + 0 - 0]
= 0
Therefore, the value of the given integral is 0.
Correct Question :
Evaluate the following integral ∫0 to π∫0 to y∫0 to x cos(x+y+z)dz dx dy.
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Use a right triangle to write the expression as an algebraic expression. Assume that
x is positive and in the domain of the given inverse trigonometric function.
sin(sin-1
Ox√3
O
√x²+3
x²+3
3)
xvx²-3
x²-3
x√√3
The algebraic expression for sin(sin^(-1)(x/√3)) using a right triangle is x / (√(3 - x^2/3)).
To write the expression sin(sin^(-1)(x/√3)) as an algebraic expression using a right triangle, we can use the properties of inverse trigonometric functions.
Let's consider a right triangle where the angle opposite to the side of length x/√3 is θ. Since sin(θ) = (x/√3), we can label the side opposite to θ as x and the hypotenuse as √3.
Using the Pythagorean theorem, we can find the length of the adjacent side:
(x/√3)^2 + adjacent side^2 = (√3)^2
x^2/3 + adjacent side^2 = 3
adjacent side^2 = 3 - x^2/3
adjacent side = √(3 - x^2/3)
Now, we can express the expression sin(sin^(-1)(x/√3)) in terms of the adjacent side:
sin(sin^(-1)(x/√3)) = sin(θ) = opposite side / hypotenuse
= x / (√(3 - x^2/3))
Therefore, the algebraic expression for sin(sin^(-1)(x/√3)) using a right triangle is x / (√(3 - x^2/3)).
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