Number of photons emitted = 2167200 photons/second
What are photons emitted?Photons are particles of light that are emitted from atoms. They exist in a wide range of energies and wavelengths and can be emitted from both natural and artificial sources.
Photons are emitted when an electron in an atom moves from a higher energy state to a lower energy state.
1. Number of photons emitted = (Energy conversion efficiency) × (Power in Watts) × (eV/J) × (Avogadro's number) × (1/Energy of band gap)
Number of photons emitted = (0.9) × (50) × (1.6 x 10-19/1) × (6.02 x 1023) × (1/2.0)
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Calculate the surface area in nm2 of a water solution contained in a Petri Dish with a diameter of 9.0 cm. The area of a circle is calculated as A = πr 2 .
The surface area of the water solution contained in a Petri dish with a diameter of 9.0 cm is approximately 6.36 × 10^16 nm^2.
What is area?In geometry, "area" is the measure of the size of a two-dimensional region or shape. It is usually measured in square units, such as square meters (m²) or square feet (ft²) and represents the amount of space that is enclosed by the boundary of the shape. The formula for calculating the area of a shape depends on its type. For example, the area of a rectangle is calculated by multiplying its length by its width, while the area of a circle is calculated by multiplying pi (approximately 3.14159) by the square of its radius. The concept of area is used in many fields, such as architecture, engineering, and physics, to determine the amount of material needed to construct or cover a surface.
According to question:
The surface area of the water solution contained in a Petri dish with a diameter of 9.0 cm can be calculated as follows:
1. First, we need to calculate the radius of the dish. The diameter is given as 9.0 cm, so the radius (r) is half of this value, which is:
r = 9.0 cm / 2 = 4.5 cm
2. Next, we need to convert the radius to nanometers (nm) since the surface area will be in nm^2. We know that 1 cm = 10,000,000 nm (1 cm = 10^7 nm), so we can convert the radius as follows:
r = 4.5 cm × 10,000,000 nm/cm = 45,000,000 nm
3. Finally, we can calculate the surface area of the water solution in the Petri dish using the formula for the area of a circle:
A = πr^2
A = π(45,000,000 nm)^2
A ≈ 6.36 × 10^16 nm^2
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Describe the relationship
between the salinity of water and its surface tension.
Use a primary standard to determine an unknown concentration using an acid–base titration.
Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a primary standard. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP.
If 38.39 mL of a sodium hydroxide solution are needed to neutralize 2.677 grams of KHP, what is the concentration (mol/L) of the sodium hydroxide solution?
? M
The concentration of the sodium hydroxide solution is 0.341 mol/L (or M).
How to calculate the concentration of sodium hydroxide?
We can use the balanced chemical equation for the reaction of sodium hydroxide (NaOH) with potassium hydrogen phthalate (KHP) to determine the number of moles of NaOH that were used in the titration:
NaOH + KHP → NaKP + H2O
From the balanced equation, we see that one mole of NaOH reacts with one mole of KHP. Therefore, the number of moles of NaOH used in the titration is equal to the number of moles of KHP:
moles of KHP = mass of KHP / molar mass of KHP
The molar mass of KHP can be calculated using the atomic weights of the elements in the formula:
molar mass of KHP = (1 x 39.10 g/mol) + (8 x 12.01 g/mol) + (4 x 16.00 g/mol)
molar mass of KHP = 204.22 g/mol
Substituting the values given in the problem, we have:
moles of KHP = 2.677 g / 204.22 g/mol
moles of KHP = 0.0131 mol
Since one mole of NaOH reacts with one mole of KHP, the number of moles of NaOH used in the titration is also 0.0131 mol.
The concentration of the NaOH solution can be calculated using the formula:
concentration of NaOH = moles of NaOH / volume of NaOH solution
Substituting the volume of the NaOH solution given in the problem, we have:
concentration of NaOH = 0.0131 mol / 0.03839 L
concentration of NaOH = 0.341 M
Therefore, the concentration of the sodium hydroxide solution is 0.341 mol/L (or M).
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Calculate the mass of iron(III) oxide that contains a trillion oxygen atoms.
Answer:
7,3g
Explanation:
8.336x10^-13 moles x 88 g/mol =7,3 g
Answer:
0.13 grams.
Explanation:
To calculate the mass of iron(III) oxide that contains a trillion oxygen atoms, we first need to determine the molar mass of iron(III) oxide, also known as ferric oxide or Fe2O3. The molar mass of Fe2O3 is approximately 159.69 g/mol.
Next, we need to convert the number of oxygen atoms to moles using Avogadro's number, which is 6.022 x 10^23 atoms/mol. One mole of Fe2O3 contains two moles of oxygen, so the number of moles of Fe2O3 can be calculated as:
(1 trillion oxygen atoms) / (2 * 6.022 x 10^23 atoms/mol) = 8.37 x 10^-12 moles
Finally, we can calculate the mass of iron(III) oxide as:
(8.37 x 10^-12 moles) * (159.69 g/mol) = approximately 0.13 g
So, the mass of iron(III) oxide that contains a trillion oxygen atoms is approximately 0.13 grams.
Allen i little forget about this Sorry
Calculate the average atomic mass of funnium. One isotopes of funnium has an atomic mass of 78.92 u and a relative abundance of 50.69%. The other major isotope of funnium has an atomic mass of 80.92u
Answer:
89.17 u.
Explanation:
he average atomic mass of funnium can be calculated as follows:
Atomic mass = (Relative abundance of first isotope * atomic mass of first isotope) + (Relative abundance of second isotope * atomic mass of second isotope)
Atomic mass = (50.69% * 78.92 u) + (100% - 50.69% * 80.92 u)
Atomic mass = 39.86 u + (49.31 u)
Atomic mass = 89.17 u
So, the average atomic mass of funnium is 89.17 u.
Continuing from the last question, what is the new pressure inside the container? hint: did we use up all of the reactants?.
The new pressure inside the container is 0.5 atm.
What is new pressure?New pressure is the term used to describe changes in the environment or circumstances that require a person or organization to adapt. This may include changes in technology, competition, customer preferences, and global markets. New pressure can also refer to the external forces that drive a business to continually innovate and adapt to stay competitive. It can be the result of rapid technological advances, a shifting global economy, or changing customer demands.
The pressure inside the container is equal to the partial pressure of the reactants when all of the reactants have been used up. Since the reaction is at equilibrium, this means that the pressure inside the container is equal to the partial pressure of the products, which is 0.5 atm. Therefore, the new pressure inside the container is 0.5 atm.
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What is the new pressure if you expand 103.0 liters of air at 2.00 atm into a cylinder whose volume is 156.0 liters?
a
0.504 atm
b
2.33 atm
c
1.32 atm
d
3.03 atm
Answer:
Explanation:
The new pressure can be calculated using the Ideal Gas Law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant (8.31 J/mol*K), and T is the temperature (assumed to be constant).
Since the number of moles of gas and temperature is constant, we can rearrange the equation to solve for the new pressure:
P = (NRT) / V
Using the initial conditions of P1 = 2.00 atm and V1 = 103.0 liters, we can find the new pressure P2 after the expansion to 156.0 liters:
P2 = (P1 * V1) / V2 = (2.00 atm * 103.0 liters) / 156.0 liters = 1.30 atm
Therefore, the new pressure is 1.30 atm, and the correct answer is (c) 1.32 atm.
Explain why magnesium and aluminium react in a similar way?
Table C: Known Specific Heat Values for Common Materials
Material
Specific Heat
(J/g C)
4.18
Water
Concrete
Wood
Aluminum
Glass
Sand
Steel
Iron
Copper
Lead
Gold
0.88
1.80
0.90
0.84
0.83
0.49
0.44
0.38
0.16
0.13
% Error
(deviation from known)
Water is the best insulator because it has the greatest specific heat capacity and all other substances have low specific heat than the water.
What do you mean by the specific heat capacity?The term specific heat capacity is defined as the amount of heat in joules required to increase the temperature of one gram of a substance by one degree Celsius.
An insulator is a substance which conducts heat to a very miserable extent.
From the definition of specific heat capacity and insulator, we conclude that the higher the value of specific heat capacity, the harder it would be to heat up the material, that is, the more heat would be needed.
All the given substances, only water has the greatest specific heat capacity, therefore, it's the best insulator.
Gold is the best conductor, as it has the lowest specific heat capacity.
Thus, the best insulator is water.
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Your question is incomplete, most probably your question was
Table C: Known Specific Heat Values for Common
Materials
Material Specific Heat (J/g*C)
Water 4.18
Concrete 0.88
Wood 1.80
Aluminum 0.90
Glass 0.84
Sand 0.83
Steel 0.49
Iron 0.44
Copper 0.38
Lead 0.16
Gold 0.13
What is the best insulator and why?
Write an equation for the formation of each compound from its elements in their standard states, and find AH for each in Appen- dix IIB. MISSED THIS?
a. NH3(g
b. CO2(8)
c. Fe203(s)
d. CH4(g)
The equation for the formation of each compounds are given below:
N₂ (g) + 3 H₂ (g) --> 2 NH₃ (g)
C (s) + O₂ (g) --> CO₂ (g)
4 Fe (s) + 3 O₂ (g) --> 2 Fe₂O₃ (s)
C (s) + 2 H₂ (g) --> CH₄ (g)
The standard enthalpy of formation of a substance is defined as the enthalpy change that occurs when 1 mole of the substance is formed from its constituent elements in their standard states.
Hf for NH₃ is -46.0 kJ/mol.
Hf for CO₂ is -393.5 kJ/mol
Hf for solid Fe₂O₃ is -826.0 kJ/mol.
Hf for methane gas is -74.9 kJ/mol.
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Using tabulated ∆° values in the text, determine the enthalpy change (in kJ) that occurs during the formation of water from its elements.
32 ()+2 ()→22(l) ∆=?
The enthalpy of formation of H₂ and O₂ are zero. Then , the enthalpy of formation of water is 285 kJ.
What is enthalpy of formation ?Enthalpy change of a chemical reaction of physical change is the change in heat energy absorbed or evolved during the change or reaction. It is represented as ΔHf⁰.
The enthalpy of formation of elements in molecular state is zero. Hence the enthalpy of formation of H₂ and O₂ are zero.
The enthalpy of formation of water = -285 kJ.
enthalpy of reaction = enthalpy of products - enthalpy of reactants.
ΔHr = -285 kJ - 0+0 = - 285 kJ.
Therefore, the enthalpy change during the formation of water from its elements is - 285 kJ.
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Your complete question is as follows:
Using tabulated ∆Hf° values in the text, determine the enthalpy change (in kJ) that occurs during the formation of water from its elements:
2 H2 (g) + O2 (g) → 2 H2O (l) ∆H = ?
What’s the velocity of the sound wave at a temperature of 38 C
Answer:
The velocity of sound in air is dependent on several factors, including temperature, pressure, and humidity. At a temperature of 38°C (100.4°F), the average velocity of sound in air is approximately 343 meters per second (m/s). However, it is important to note that this is just an approximation and the actual velocity can vary depending on the specific conditions. To get a more precise value, you may need to consider the effect of pressure, humidity, and other factors.
Analysis of a 5.68-g sample of ZnS contains 3.80 g of Zn. Calculate the mass of Zn that can be obtained from 7.53 kg of Zns.
a.5.65 kg
b.5.04 kg
c.3.73 kg
d.2.87 kg
If a 5.68-g sample of ZnS contains 3.80 g of Zn then the mass of Zn that can be obtained from 7.53 kg of Zns. is 5.04kg so correct option is
(b) 5.04kg.
With the provided data, we can first determine the mass percent content of zinc in ZnS:
(Mass of Zn / Mass of ZnS) times 100% Equals mass percent of Zn
3.80 g / 5.68 g x 100%, where mass percent of Zn
Zn mass percentage is 66.9%.
This indicates that zinc accounts for 66.9% of the mass of ZnS. This number can be used to determine how much Zn can be extracted from 7.53 kg of ZnS:
mass of Zn from 7.53 kg of ZnS is equal to (66.9 / 100) × 7.53 kg, or 5.04 kg.
As a result, 5.04 kg of Zn can be extracted from 7.53 kg of ZnS. 5.04 kg is the correct answer (b).
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The acid ionization constant, Ka, for propanoic acid, C2H5COOH, is 1.3x10-5.(a) Calculate the hydrogen ion concentration, [H+], in a 0.20-molar solution of propanoic acid.(b) Calculate the percentage of propanoic acid molecules that are ionized in the solution in (a).(c) What is the ratio of the concentration of propanoate ion, C2H5COO-, to that of propanoic acid in a buffer solution with a pH of 5.20?(d) In a 100.-milliliter sample of a different buffer solution, the propanoic acid concentration is0.35-molar and the sodium propanoate concentration is 0.50-molar. To this buffer solution,0.0040 mole of solid NaOH is added. Calculate the pH of the resulting solution
(a) The hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M. (b) 0.57%. (c) The ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(a) The balanced equation for the ionization of propanoic acid is:
C2H5COOH + H2O ⇌ C2H5COO- + H3O+
The equilibrium expression for this reaction is:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
At equilibrium, the concentration of propanoic acid that has ionized to form propanoate ion and hydronium ion is equal to the concentration of propanoic acid that has not ionized, so we can assume that [C2H5COO-] ≈ [H3O+]. Let x be the concentration of hydronium ion in the solution. Then the equilibrium expression becomes:
Ka = x^2 / (0.20 - x)
Solving for x, we get:
x = sqrt(Ka * (0.20 - x)) = sqrt(1.3x10^-5 * 0.20) = 1.14x10^-3 M
Therefore, the hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M.
(b) The percentage of propanoic acid molecules that are ionized in the solution is given by:
% ionization = [H3O+] / [C2H5COOH] x 100%
% ionization = (1.14x10^-3 / 0.20) x 100% = 0.57%
(c) The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:
pH = pKa + log([C2H5COO-] / [C2H5COOH])
At pH 5.20, the hydronium ion concentration is 10^-5.20
= 6.31x10^-6 M.
Using the equilibrium expression for propanoic acid and the fact that [C2H5COO-] + [C2H5COOH] = total buffer concentration,
we can solve for the ratio of the concentrations of propanoate ion to propanoic acid:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
[C2H5COO-] = Ka[C2H5COOH] / [H3O+]
[C2H5COO-] = (1.3x10^-5)([C2H5COOH]) / (6.31x10^-6)
[C2H5COO-] / [C2H5COOH]
= 2.68
Therefore, the ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(d) When solid NaOH is added to the buffer solution, it reacts with the propanoic acid to form propanoate ion and water:
C2H5COOH + NaOH → C2H5COO- + H2O + Na+
The number of moles of propanoic acid that react with NaOH is equal to the number of moles of NaOH that were added. The new concentration of propanoic acid is:
0.35 M - (0.0040 mol / 0.100 L) = 0.346 M
The new concentration of propanoate ion is:
0.50 M + (0.0040 mol / 0.100 L) = 0.54 M
The new concentration of hydronium ion can be calculated using the equilibrium expression.
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For the reaction below, Kc = 1.10 × 10⁻⁴. Note Kc is sometimes called K.
What is the equilibrium concentration of C if the reaction begins with 0.200 M A and 0.300 M B?
2 A (aq) + B (aq) ⇌ C (aq)
Kc = 1.10 104 for the reaction detailed below. If the reaction starts with 0.200 M A with 0.150 M B, how much is the equilibrium level of C
What does the word reaction mean?
Chemical reaction is the transformation of one or more substances—the reactants—into one or more additional substances—the products. Chemical elements or chemical compounds make up substances.
Where do reaction take place?
The Earth's geology, the atmosphere, the oceans, and a wide variety of intricate processes that take place in all life processes are rife with chemical reactions. Physical changes and chemical must be differentiated.
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the town in the video stressed using locally made goods instead of imported goods. how could using locally made goods lover CO2 emissions
The way that using locally made goods can lower CO2 emissions is by reducing the emissions from the transport needed to take foreign made goods to a place.
How do locally made good usage lower CO2 emissions ?The use of locally made goods can lower CO2 emissions by reducing the transportation distance needed to transport goods. When goods are manufactured and consumed locally, they do not need to be transported over long distances, which can greatly reduce the carbon emissions associated with transportation.
Transportation is a significant source of greenhouse gas emissions, particularly emissions from the burning of fossil fuels like gasoline and diesel. By reducing the amount of transportation needed, the use of locally made goods can help to lower the overall carbon footprint of an economy.
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Give the two conversion factors you can construct using each pair of units. a. meters and kilometers b. liters and microliters c. seconds and milliseconds.
The conversion factors are, a. 1 kilometer = 1000 meters, 1 meter = 0.001 kilometers b. 1 liter = 1,000,000 microliters, 1 microliter = 0.000001 liters c. 1 second = 1000 milliseconds, 1 millisecond = 0.001 seconds
Here are the conversion factors for each pair of units:
a. Meters and kilometers:
1 kilometer = 1000 meters
1 meter = 0.001 kilometers
b. Liters and microliters:
1 liter = 1,000,000 microliters
1 microliter = 0.000001 liters
c. Seconds and milliseconds:
1 second = 1000 milliseconds
1 millisecond = 0.001 seconds
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An organic chemist measures the temperature T of a solution in a reaction flask. Here is the result.
T= 128. °C
Convert T to SI units. Be sure your answer has the correct number of significant digits.
The final answer is: T = 401 K
What is celsius temperature?
Celsius temperature scale is a metric temperature scale that is commonly used in most countries around the world. It is based on the Celsius temperature scale, which is defined by the melting and boiling points of water at standard atmospheric pressure.
How to convert the temperature from Celsius to Kelvin (the SI unit of temperature)
First we simply add 273.15 to the Celsius temperature:
T(K) = T(°C) + 273.15
In this case, T = 128. °C. Substituting this into the above equation, we get:
T(K) = 128. °C + 273.15 = 401.15 K
Therefore, the temperature in SI units is 401.15 K.
Since the given temperature has three significant digits, the converted temperature should also have three significant digits.
Therefore, the final answer is: T = 401 K
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Classify each of the events based on whether the solubility of the gas will increase, decrease, or stay the same.
Increased gas solubility Reduced gas solubility As a body of water's temperature rises, Oz's gas solubility remains unchanged. Air enters the blood when the diver drops 10 meters; an atm of pressure rises.
Gas molecules can more easily leave the solution phase at higher temperatures due to their higher kinetic energy. As a result, solubility declines. A measurement of the concentration of dissolved gas particles in a liquid, solubility is a function of gas pressure. A gas's solubility rises as pressure is increased, but it falls as pressure is decreased due to an increase in collision frequency. The solubility of gases rises with pressure, as one might anticipate. According to Henry's Law, a gas's solubility in a liquid is directly inversely proportionate to the gas's pressure above the surface of the solution. thus this will most effectively release the pressure that has been imposed.
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5. There are two types of bond cleavage: homolytic and heterolytic. In homolytic cleavage,
the two electrons in the bond are divided equally between the products. In heterolytic
cleavage, one atom gets both of the shared electrons. Show how the electrons in the
C-X bond in the compound L below are distributed in the bond cleavage to form:
a) Free radical
b) Carbocation
c) Carbanion
[6 marks]
C-X bond in the compound L below are distributed in the bond cleavage to form free radical.
How do bonds break?
When a bond is broken through heterolytic cleavage, also known as heterolysis, one of the fragments still has the shared pair of electrons from the original connection. Because it has both bonding electrons, one fragment acquires an electron while the other loses one. Another name for this procedure is ionic fission.
Any molecular species that has an unpaired electron in an atomic orbital and is capable of independent existence is referred to as a free radical. Most radicals exhibit certain similar characteristics when an unpaired electron is present. Many radicals are highly reactive and inherently unstable.
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What is the metabolism during high intensity interval training? Describe the most important processes and name the regulatory enzyme. Describe the regulation of metabolism during exercise. What modification of enzyme activity is involved in this case - covalent or allosteric? Which metabolic products affect fatigue and how? Why are we tired in the sarcoplasmic reticulum after exercise?
During high-intensity interval training, the body's metabolism shifts to meet the increased energy demands of the workout. The most important metabolic processes during high-intensity interval training include:
1. Glycolysis: The breakdown of glucose to produce energy in the form of ATP (adenosine triphosphate).
2. Lipolysis: The breakdown of fats to release fatty acids into the bloodstream, which can then be used as fuel.
3. Oxidative phosphorylation: The production of ATP through the process of cellular respiration, in which glucose and fatty acids are oxidized to produce energy.
The regulatory enzyme involved in these metabolic processes is AMPK (AMP-activated protein kinase), which increases in activity during exercise to stimulate the breakdown of glucose and fatty acids and the production of ATP.
The regulation of metabolism during exercise involves changes in enzyme activity, which can be either covalent or allosteric. In the case of high-intensity interval training, enzyme activity is increased through allosteric regulation, which involves the binding of regulatory molecules to the enzyme to alter its activity.
Metabolic products such as lactic acid and hydrogen ions can affect fatigue during high-intensity interval training. Lactic acid buildup in the muscles can cause fatigue and muscle pain, while the accumulation of hydrogen ions can disrupt muscle function and lead to fatigue.
We are tired in the sarcoplasmic reticulum after exercise because it has been depleted of its energy stores (ATP and glycogen) during the workout. Additionally, the increased levels of metabolic by-products such as lactic acid and hydrogen ions can cause fatigue and disrupt muscle function. The sarcoplasmic reticulum is responsible for storing and releasing calcium ions, which are necessary for muscle contraction. When it is depleted of energy, it can no longer perform this function effectively, leading to fatigue.
Answer:
During high-intensity interval training (HIIT), the body undergoes a number of metabolic processes to provide energy for the muscles. The most important processes are anaerobic glycolysis, which involves the breakdown of glucose to produce energy, and aerobic respiration, which involves the breakdown of glucose and fatty acids in the presence of oxygen.
The regulatory enzyme involved in metabolism during exercise is AMP-activated protein kinase (AMPK). AMPK helps to regulate energy balance in the cells by increasing glucose uptake and fatty acid oxidation, while decreasing glucose production and lipid synthesis.
Metabolism during exercise is regulated through a combination of covalent and allosteric modifications of enzyme activity. Covalent modifications involve the phosphorylation of enzymes, which changes their activity. Allosteric modifications involve the binding of regulatory molecules to enzymes, which changes their conformation and activity.
During exercise, a number of metabolic products can affect fatigue, including lactic acid and hydrogen ions, which can disrupt the acid-base balance in the muscles and lead to fatigue. Another important factor is the depletion of glycogen stores, which can lead to a reduction in energy production.
In the sarcoplasmic reticulum, the accumulation of calcium ions can lead to fatigue after exercise. This is because the increased levels of calcium ions can disrupt the normal functioning of the sarcoplasmic reticulum, which is responsible for regulating muscle contractions. The accumulation of calcium ions can also lead to the activation of proteolytic enzymes, which can break down proteins and contribute to muscle fatigue.
Explanation:
A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C. Use the chart to complete the multiple steps required to arive at the final answer. Type in your answers below using 3 digits.
q1 = kJ
q2 = kJ
q3 = kJ
qtot = kJ
Total heat required for all steps: Q1 + Q2 + Q3 + Q4 + Q5 = 309261 J.
How to calculate heat for the samples?
To calculate the amount of heat required to change the sample of water from ice at -45.0°C to liquid water at 75.0°C, we need to consider the heat required for the following steps:
Heat to bring the ice from -45.0°C to 0°C and melt itHeat to bring the liquid water from 0°C to 100°C and boil itHeat to bring the steam from 100°C to 75.0°CFor each of these steps, we can use the formula:Q = m × C × ΔT
where Q is the amount of heat required (in joules), m is the mass of the sample (in grams), C is the specific heat capacity (in joules/gram°C) and ΔT is the change in temperature (in °C).
Heat to bring the ice from -45.0°C to 0°C and melt it
To bring the ice from -45.0°C to 0°C, we need to add heat:
Q1 = m × Cice × ΔT1
where Cice is the specific heat capacity of ice (2.108 J/g°C), ΔT1 is the change in temperature (0°C - (-45.0°C) = 45.0°C).
Q1 = 100.0 g × 2.108 J/g°C × 45.0°C
Q1 = 9456 J
To melt the ice, we need to add heat:
Q2 = m × Lfus
where Lfus is the heat of fusion of water (333.55 J/g).
Q2 = 100.0 g × 333.55 J/g
Q2 = 33355 J
Total heat for step 1: Q1 + Q2 = 42711 J
Heat to bring the liquid water from 0°C to 100°C and boil it
To bring the liquid water from 0°C to 100°C, we need to add heat:
Q3 = m × Cwater × ΔT2
where Cwater is the specific heat capacity of liquid water (4.184 J/g°C), ΔT2 is the change in temperature (100°C - 0°C = 100°C).
Q3 = 100.0 g × 4.184 J/g°C × 100.0°C
Q3 = 41840 J
To boil the water, we need to add heat:
Q4 = m × Lvap
where Lvap is the heat of vaporization of water (2257 J/g).
Q4 = 100.0 g × 2257 J/g
Q4 = 225700 J
Total heat for step 2: Q3 + Q4 = 267540 J
Heat to bring the steam from 100°C to 75.0°C
To bring the steam from 100°C to 75.0°C, we need to remove heat:
Q5 = m × Csteam × ΔT3
where Csteam is the specific heat capacity of steam (1.996 J/g°C), ΔT3 is the change in temperature (75.0°C - 100.0°C = -25.0°C).
Q5 = 100.0 g × 1.996 J/g°C × (-25.0°C)
Q5 = -4990 J
Total heat for step 3: Q5 = -4990 J (since heat is being removed)
Total heat required for all steps: Q1 + Q2 + Q3 + Q4 + Q5 = 309261 J
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Answer:
q1 = ⇒ 9.42 kJ
q2 = ⇒ 226 kJ
q3 = ⇒ 31.4 kJ
qtot = ⇒ 267 kJ
Explanation:
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What type of reaction is shown below:Ca(OH)2(aq) + HCl(aq)—>CaCl₂ + H₂O
Answer The reaction shown below is a chemical reaction between aqueous calcium hydroxide (Ca(OH)2) and aqueous hydrochloric acid (HCl):
Explanation:
Ca(OH)2(aq) + HCl(aq) -> CaCl2 + H2O
This reaction is an example of a neutralization reaction. Neutralization reactions occur when an acid reacts with a base to produce a salt and water. In this reaction, the hydrogen ions from the hydrochloric acid react with the hydroxide ions from the calcium hydroxide to produce calcium chloride (CaCl2) and water (H2O). The reaction results in the neutralization of both the acid and the base, hence the name "neutralization reaction."
How does temperature affect the rate of a chemical reaction?
Answer:
Temperature affects the rate of a chemical reaction because it affects the rate of motion of the reacting particles. Higher temperatures increase the kinetic energy of particles, which increases their rate of collision and reaction.
Explanation:
Tutored Practice Problem 4.5.1COUNTS TOWARDS GRADE
Calculate solution concentration in molarity units.
A student weighs out 5.96 g of Zn(CH3COO)2, transfers it to a 250. mL volumetric flask, adds enough water to dissolve the solid and then adds water to the 250 mL mark on the neck of the flask.
Calculate the concentration (in molarity units) of zinc acetate in the resulting solution?
M=?
The number of moles of 5.96 g of zinc acetate is 00324 . The volume of the solution is 0.25 L. Then the molarity of the solution is 0.16 M.
What is molarity ?Molarity of a solution is a common term used to express the concentration of a solution. It is the the ratio of number of moles of the solute to the volume of solution in liters.
Given that the solution contains 5.965 g of ammonia.
molar mass of zinc acetate = 183.4 g/mol.
no.of moles in 75 g = 75/17 = 4.411 moles.
volume of solution = 250 ml = 0.25 L.
molarity = no.of moles of solute/volume of solution in L.
= 0.032 mole/ 0.25 L= 0.16 M.
Therefore, the molarity of the solution is 0.16 M.
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PLEASE HELP
Calculate the number of oxygen atoms in a 120.0 g sample of forsterite (Mg2SiO4).
Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.
Answer:
The molar mass of Mg2SiO4 can be calculated by adding the atomic masses of each element:
Mg: 2 x 24.31 g/mol = 48.62 g/mol
Si: 1 x 28.09 g/mol = 28.09 g/mol
O: 4 x 16.00 g/mol = 64.00 g/mol
Molar mass of Mg2SiO4 = 48.62 + 28.09 + 64.00 = 140.71 g/mol
To calculate the number of oxygen atoms in a 120.0 g sample of forsterite, we first need to calculate the number of moles of Mg2SiO4 in the sample:
n = mass / molar mass = 120.0 g / 140.71 g/mol = 0.853 mol
Next, we can use the molecular formula to determine the number of oxygen atoms in one mole of Mg2SiO4:
Mg2SiO4 has 4 oxygen atoms per molecule, so one mole of Mg2SiO4 has 4 moles of oxygen atoms.
Therefore, the number of oxygen atoms in 0.853 mol of Mg2SiO4 is:
0.853 mol Mg2SiO4 x 4 mol O / 1 mol Mg2SiO4 = 3.412 mol O
Finally, we can convert the number of oxygen atoms to a more convenient unit, such as atoms. One mole of oxygen atoms contains 6.022 x 10^23 atoms, so the total number of oxygen atoms in 0.853 mol of Mg2SiO4 is:
3.412 mol O x 6.022 x 10^23 atoms/mol = 2.055 x 10^24 atoms of oxygen
Rounding this result to 4 significant digits, we get:
2.055 x 10^24 atoms of oxygen (to 4 significant digits)
Explanation:
2NOBr(g)> 2NO(g) + Br2(g). if the initial pressure was 400 torrs, calculate the pressure when this reaction is complete
If the initial pressure was 400 torrs, the pressure when this reaction is complete is 1000 torrs.
How to find the pressure when this reaction is complete?The given equation is 2NOBr(g) -> 2NO(g) + Br2(g)
This is a decomposition reaction, which means that the total number of moles of gas will increase.
From the balanced chemical equation, we can see that 2 moles of gas are produced for every 2 moles of NOBr consumed. Therefore, the number of moles of gas will double when the reaction is complete.
Let x be the final pressure of the gas mixture in torrs.
Initially, the pressure of NOBr is 400 torrs, and the initial pressure of NO and Br2 is 0 torrs.
When the reaction is complete, 2 moles of gas will be present for every 1 mole of NOBr initially present. Therefore, the final pressure of the gas mixture is:
x = (2 moles of NO + 1 mole of Br2) / (2 moles of NOBr) x 400 torrs
x = (2 + 1/2) x 400 torrs
x = 1000 torrs
Therefore, the pressure of the gas mixture when the reaction is complete is 1000 torrs.
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1. How many atoms of nitrogen are there in 0. 50 mol of (NH4)2CO3?
A. 1
B. 2
C. 3. 01 × 1023
D. 6. 02 × 1023
There are[tex]6.02*10^{23}[/tex] atoms of nitrogen in 0.50 mol of (NH4)2CO3. The correct answer is D. [tex]6.02*10^{23}[/tex]
How to determine the number of atoms present in nitrogen?To determine the number of atoms of nitrogen in 0.50 mol of (NH4)2CO3, we first need to find the total number of moles of nitrogen in the compound.
(NH4)2CO3 contains two nitrogen atoms in each molecule, so the total number of moles of nitrogen is:
2 nitrogen atoms/molecule x 0.50 mol = 1.00 mol of nitrogen
We know that one mole of nitrogen contains Avogadro's number[tex](6.02 * 10^{23})[/tex] atoms of nitrogen. Therefore, 1.00 mol of nitrogen also contains [tex](6.02 * 10^{23})[/tex]atoms of nitrogen.
Therefore, there are [tex](6.02 * 10^{23})[/tex]atoms of nitrogen in 0.50 mol of [tex](NH4)2CO3.[/tex]
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A chemist is performing a chemical reaction under a fume hood. The chemist has a set of beakers, flasks, and tubes set up under the fume hood, with various liquids being combined inside the glass containers. The fume hood is turned on in order to withdraw any toxic gases and expel them outside the building.
The part that js designated as the surrounding here is Inside the famous hood
How to get the surrounding in the chemical reactionIn this scenario, the system is the chemical reaction being performed by the chemist with the various glass containers and liquids. The surroundings are everything else outside of this system, including the fume hood and the outside of the building.
The correct answer that is the designated surrounding here would be the fume hood.
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A chemist is performing a chemical reaction under a fume hood. The chemist has a set of beakers, flasks, and tubes set up under the fume hood, with various liquids being combined inside the glass containers. The fume hood is turned on in order to withdraw any toxic gases and expel them outside the building.
Which part of this system is designated as the surroundings
A. Outside of the building
B. Liquid contents of the glass containers
C. Inside the famous hood
D. The glass containers
Once we factor in the stoichiometric coefficients in the balanced equation for a process, calculation of the standard entropy change for the process will involve: Select the correct answer below: O adding the sum of the standard entropy changes of the reactants to the sum of the standard entropy changes of the products O subtracting the sum of the standard entropy changes of the reactants from the sum of the standard entropy changes of the products O multiplying the sum of the standard entropy changes of the reactants by the sum of the standard entropy changes of the products O dividing the sum of the standard entropy changes of the reactants by the sum of the standard entropy changes of the products
The right response is option B, which involves subtracting the total of the standard entropy changes of the reactants from the total of the standard entropy changes of the products.
Calculating the standard entropy change for a process requires subtracting the sum of the standard entropy changes of the reactants from the sum of the standard entropy changes of the products after the stoichiometric coefficients are taken into account in the balanced equation for the process.
The formula S° = S°(products) - S°(reactants), where S° is the sum of the standard entropy changes of the reactants and products, may be used to determine the standard entropy change for a process. The stoichiometric coefficients in the balanced equation are automatically taken into account throughout the computation since the standard entropy change of the reactants is subtracted from the standard entropy change of the products.
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