Solution of integral [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].
We have to evaluate [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex]
By using partial fractions, evaluate the integral
Let [tex]\frac{1}{s^{2}(s-1)^{2} } =\frac{A}{s} +\frac{B}{s^{2}} +\frac{c}{s-1} +\frac{D}{(s-1)^{2} }[/tex]
[tex]1=As(s-1)^{2} +B(s-1)^{2} +Cs^{2}(s-1)+Ds^{2}[/tex]
Put s = 0, 1 = B.1 ⇒ B = 1
Put s= 1, 1 = D ⇒ D = 1
Put s = -1, [tex]1=A(-1)(-2)^{2} +B(-2)^{2} +C(-1)^{2} (-2)+D(-1)^{2}[/tex]
1 = -4A + 4B -2C + D
1 = -4A + 4 -2C + 1
-4 = -4A -2C
2 = 2A + C----------------(1)
Put s = 2, 1 = A(2) + B +C(4) +D(4)
1 = 2A + 1 + 4C +4
-4 = 2A + 4C
-2 = A + 2C---------------(2)
From(1),
C = 2 -2A ---------------(3)
From (2),
⇒ -2 = A + 4 -4A
⇒ -6 = -3A ⇒ A = 2
From (3)
C = 2 - 2(2)
⇒ C = -2
Thus [tex]\int \frac{ds}{s^{2}(s-1)^{2} }= \int (\frac{2}{s} +\frac{1}{s^{2} }- \frac{2}{s-1} +\frac{1}{(s-1)^{2} } )ds[/tex]
= [tex]2 ln|s|-\frac{1}{s} -2ln|s-1|-\frac{1}{s-1}+c[/tex]
= [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex]
Thus,
Solution of integral [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].
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The degrees of freedom for a chi-square test applied to a cross-tabulation with 5 rows and 2 columns is equal to:
The degrees of freedom for a chi-square test applied to a cross-tabulation with 5 rows and 2 columns is equal to 6
How to determine the degrees of freedom applied to a cross-tabulation ?The given parameters are:
Rows = 5
Column = 2
The degrees of freedom is then calculated as:
df = Rows + Column - 1
Substitute the known values in the above equation
df = 5 + 2 - 1
Evaluate the expression
df = 6
Hence, the degrees of freedom for a chi-square test applied to a cross-tabulation with 5 rows and 2 columns is equal to 6
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Let a and b be 3 by 3 matrices with det (a) = 3 and det (b) = 5. find the value of det(ab).
If the value of determinant a is 3, determinant b is 5 then the value of determinant ab is 15.
Given that the value of determinant a is 3, determinant b is 5.
We are required to find the value of determinant ab.
Determinant of a matrix is the scalar value computed for a given square matrix.It means the matrix which is not square does not have a determinant value. It is denoted by IAI.
We know that,
IaI*IbI=IabI
So we have to just put the values in the above formula to get the determinant of ab.
IabI=3*5
=15
Hence if the value of determinant a is 3, determinant b is 5 then the value of determinant ab is 15.
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Sumalee and Julio are selling cheesecakes for a school fundraiser. Customers can buy pecan
cheesecakes and apple cheesecakes. Sumalee sold 6 pecan cheesecakes and 12 apple
cheesecakes for a total of $270. Julio sold 12 pecan cheesecakes and 9 apple cheesecakes for a
total of $285. Find the cost each of one pecan cheesecake and one apple cheesecake.
The cost of the pecan cheesecake and one apple cheesecake are $11 and $17.
According to the statement
we have given that the Sumalee sold 6 pecan cheesecakes and 12 apple
cheesecakes for a total of $270. Julio sold 12 pecan cheesecakes and 9 apple cheesecakes for a
total of $285.
And we have to find that the cost each of one pecan cheesecake and one apple cheesecake.
So, for this purpose,
Let x be the cost of each pecan cheesecake.
and y be the cost of each one apple cheesecake.
Then The equation become
6x + 12y = 270 -(1)
12x + 9y = 285 -(2)
From elimination method
multiply (1) by 12 and (2) by 6 then
72x + 144y = 3240
72x + 54y = 1710
Now eliminate x from them then the equation become
90y = 1530
here y = 17
then the x become
6x + 12y = 270
6x + 12(17) = 270
6x = 270-204
6x = 66
and x become 11.
So, The cost of the pecan cheesecake and one apple cheesecake are $11 and $17.
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guys help me please
Answer:
(x + 6, y + 1)
Step-by-step explanation:
Just look at 1 point of ABCD. For example, look at point D.
Point D must become point F.
When you reflect ABCD over the x-axis, point D will end up at (-1, -2).
Now it has to be translated to (5, -1).
For x to go from -1 to 5, you need to add 6.
For y to go from -2 to -1, you need to add 1.
Answer: (x + 6, y + 1)
A zookeeper is monitoring the population of penguins. the group needs to have exactly two times more males than females for the population to thrive. the zoo only has room for a maximum of 10 female penguins. let x represent the number of female penguins and y represent the number of male penguins. write the constraints that represent the possible number of male and female penguins that can live in a thriving population at the zoo. 0 < x ≤ 10 and 0 < y ≤ 20 x > 0 and y > 0 0 < x ≤ 10 and y > 20 x > 0 and y < 10
Answer:
0 < x ≤ 10 and 0 < y ≤ 20.
Step-by-step explanation:
I did the test and got it right ma bois.
Answer: Its A
Step-by-step explanation:
if you rolled two dice what is the probability that you would roll a 4 or a 5
subtract 2/9-2/15. enter your answer below as a fraction in lowest terms, using the slash (/) as the fraction bar.
Answer:
2/9 - 2/15
Solution
LCM = 45
45 ÷9 ×2 = 10
45÷ 15 ×2 = 6
10 - 6 = 4
ANSWER = 4/45
Answer:
l
Step-by-step explanation:
take the lcm of 9 and 15. it will be 45 . than continue
If you are choosing a single card from a standard deck of playing cards, what is
the probability that you draw a face card or a heart?
Your answer should be in the form of a fraction. Type it like this: 15/52.
Just to review:
• There are 52 cards in a deck.
• There are 4 suits with 13 cards each.
o 2 red suits - hearts and diamonds
o 2 black suites - clubs (look like clovers) and spades
• Each suit has an Ace, numbered cards 2-10, and 3 "face" cards--a Jack, Queen, and King.
Step-by-step explanation:
there are 4 suit with 13 cards each
Use 3.14 for pi. ROUND YOUR FINAL ANSWER TO THE NEAREST TENTHS PLACE!
Answer:
379.94
Step-by-step explanation:
3.14 x 11^2 = 379.94
The area of the given circle is 95 square ft.
Calculation for the Area of the Circle:
It is given in the diagram that,
The diameter of the circle, d = 11 ft.
Now, we know that the radius of a circle is equal to half of the diameter.
Therefore, radius of the given circle, r = 11/2 ft.
The formula for the area of the circle is given as follows,
A = π × r²
Substituting the values, π = 3.1, and r = 11/2, we get,
A = (3.14) × (11/2)²
A = (3.14) × 30.25
A = 94.985
A ≈ 95
Hence, the area of the given circle with diameter 11 ft. comes out to be 95 ft².
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trevor takes up a test at school and completes it in an hour. the test has two sections. if he takes 35 minutes to complete the first section, how much time does he have left to complete the second section? which equation would you use to answer this problem?
a) x + 2 = 35
b) 2x + 30 = 35
c) 2x + 30 + 60
d) x + 35 = 60
Answer:
I would use equation d
Step-by-step explanation:
because need to find out X which is the second section so you would do 60 subtract 35 which gives 25 so X would be 25 .
I hope this helped . if you need any more help pls ask :)
pls give brainliest if you like my answer :)
Will has twice as many stamps in his collection as Carlton and Ashley do in their collections combined. If Ashley has 30 stamps and she has a third as many as Carlton has, how many stamps are in Will’s collection?
Taking into account the definition of a system of linear equations, 240 stamps are in Will’s collection.
System of linear equationsA system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.
Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is to say, the values of the unknowns must be sought, with which when replacing, they must give the solution proposed in both equations.
Number of stamps that are in Will’s collectionIn this case, a system of linear equations must be proposed taking into account that:
W: Number of stamps that are in Will’s collectionC: Number of stamps that are in Carlton’s collectionA: Number of stamps that are in Ashley’s collectionOn the other hand, you know that:
Ashley has 30 stamps and she has a third as many as Carlton has → A= [tex]\frac{1}{3}[/tex]C → 30= [tex]\frac{1}{3}[/tex]CWill has twice as many stamps in his collection as Carlton and Ashley do in their collections combined. → W= 2(C + A)So, the system of equations to be solved is
[tex]\left \{ {{30=\frac{1}{3}C } \atop {W=2(C+30)}} \right.[/tex]
There are several methods to solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.
Solving the first equation:
30= [tex]\frac{1}{3}[/tex]C
30÷[tex]\frac{1}{3}[/tex]= C
90= C
Substituting the value in the second equation:
W= 2(90 + 30)
W= 2×120
W=240
Finally, 240 stamps are in Will’s collection.
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G.CO.5 △ABC undergoes a series of transformations to create △A'B'C'. Which of the following series of transformations will carry △ABC onto △A'B'C'?
Triangle ABC was reflected over the y axis and translated 3 units down to form triangle A'B'C'.
What is transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, translation, rotation and dilation.
Rigid transformation preserves the shape and size of the figure. Reflection, translation, rotation are rigid transformations.
Triangle ABC was reflected over the y axis and translated 3 units down to form triangle A'B'C'.
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Solve this system of equations by using the elimination method. x+4y=9 2x-4y=-6
Answer:
[tex]x=6[/tex]
[tex]y=\frac{3}{4}[/tex]
Step-by-step explanation:
Given the following question:
[tex]x+4y=9[/tex]
[tex]2x-4y=9[/tex]
To solve using the elimination method we will add the two equations together to find the two individual values.
[tex]x+2x=3x[/tex]
[tex]4y-4y=0[/tex]
[tex]9+9=18[/tex]
[tex]3x=18[/tex]
[tex]\frac{3x}{3} =x[/tex]
[tex]18\div3=6[/tex]
[tex]x=6[/tex]
[tex]x+4y=9[/tex]
Substitute six in for x:
[tex]x=6[/tex]
[tex]6+4y=9[/tex]
Solve for y:
[tex]6-6=0[/tex]
[tex]9-6=3[/tex]
[tex]\frac{4y}{4} =y[/tex]
[tex]3=\frac{3}{4}[/tex]
[tex]y=\frac{3}{4}[/tex]
x is equal to 6, and y is equal to 3/4.
Hope this helps.
algebra 2: help please
a scuba diver enters the water 1m away from her boat. She dives down and then resurfaces 12m away from her boat. Her diving path id in the shape of a quadratic function, where x is the distance away from the boat and y is the distance away from the surface of the water, and negative values of y are below the water. She reaches a maximum depth of 30.25m below the surface of the water.
Her diving partner wants to estimate the diver’s depths at different points away from the boat. What is the diver’s depth when she is 4m away from the boat?
Answer:
24 m depth
Step-by-step explanation:
The quadratic function modeling depth will have zeros at x=1 and x=12, the distances in meters from the boat where the diver is at the surface.
Quadratic functionThe factored form of a quadratic function can be written as ...
y = a(x -p)(x -q)
where p and q are zeros of the function. The value 'a' is a vertical scale factor.
Here, we are given y=0 at the surface, at points where x=1 and x=12. This means the function can be written as ...
y = a(x -1)(x -12)
Scale factorTo find the value of 'a', we can use the maximum depth value. That depth will be halfway between the function zeros, at x = (1+12)/2 = 6.5
-30.25 = a(6.5 -1)(6.5 -12)
30.25 = 5.5²·a = 30.25a ⇒ a=1
Model of depthThen the function modeling the diver's depth in meters is ...
y = (x -1)(x -12)
And the depth at x=4 will be ...
y = (4 -1)(4 -12) = 3(-8) = -24 . . . . meters
The diver's depth is 24 meters when she is 4 m away from the boat.
Towns A, B, and C lie on a straight line, as shown below. Jack and Arthur start at Town B and drive for an hour from Town B to Town C, where they stop for an hour to eat lunch. Which of the following graphs could represent their distance from Town A during these two hours?
Considering the situation described, it can be graphed by the first function.
Which graph models the situation?Cities A, B and C are on a straight line.
On the first hour, they leave town B to town C, moving farther from Town A, hence the distance is increasing on the first hour.On the second hour, they stop for lunch, meaning that the distance remains constant at the point it was at the end of the first hour.Hence, the first graph is the correct one for this problem.
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Can anyone help me solve these linear systems using substitution?
1. 3x-y=4
x+2y=6
2. 2x-y= -39
x+y= -21
3. 2x+y =11
6x-5y =9
Each question should demonstrate step by step on how to do it, as well as each step should show the final given points of each solution (x,y)
Answer:
1. (2,2)
2. (-20, -1)
3. (4,3)
Step-by-step explanation:
See attached images
Answer:
The solutions to the sets of equations may be found by either a substitution process or by graphing and looking for the point that the two lines formed by the quations intersect. Both approaches are described.
The "solution" to these sets of equations is the point at which the two lines intersect each other.
Step-by-step explanation:
1. 3x-y=4 and x+2y=6
x+2y=6
6x-2y=8 We can simply add these two equations since y will disappear, leaving just x.
7x = 14 [result of addition]
x = 2 [Solve]
Since x = 2, [Then use the solution for x to find y]
x+2y=6
(2)+2y=6
2y = 4
y = 2
(2,2) is the solution (where the lines intersect). See attached graph.
2. 2x-y= -39 and x+y= -21
2x-y= -39
x+y= -21 Add the two equations (since the y will be eliminated)
3x = -60
x = -20
Find y:
x+y= -21
(-20)+y= -21
y = -1
Solution is (-20,-1)
3. 2x+y =11 and 6x-5y =9
2x+y =11
-6x+-3y = -33 [Multiply by -3 and then add to other equation. This allows us to eliminate x]
6x - 5y = 9
-8y = - 24
y = 3
2x+y =11
2x+(3) =11
2x = 8
x = 4
Solution is (4,3)
==================
See attached graph for all the graphed solutions.
==================
The substitution process also works if we isolate one of the 2 variables in one equation and then use the resulting value in the second eqaution. For example, in problem 1:
3x-y=4
x+2y=6
Pick either equation and isolate the x or y. I'll pick the second equation and isolate for x:
x = 6-2y
Now use this value of x (6-2y) in the other equation:
3x-y=4
3(6-2y)-y=4
18 - 6y - y = 4
-7y = -14
y = 2
Then use y=2 to fiond x, using either equation:
x+2y=6
x+2(2)=6
x = 2
The solution is (2,2).
This same approach can be used on all these problems. It avoids trying to visualize what can be done to an entire equation to eliminate one of the variables, but it takes a bit more paper.
All solutions are graphed in the attachment.
What is the probability that a five-card poker hand contains the two of diamonds and the three of spades?.
Answer:
1/311875200.
There is exactly 1 way to have all 5 of these cards. For the first card, there are 52 total cards to be had; for the second, 51; for the third, 50; for the fourth, 49; and for the fifth, 48:
(1/52)(1/51)(1/50)(1/49)(1/48) = 1/311875200.
Step-by-step explanation:
A local baseball team is struggling this season, and many fans of the team believe it may be time to replace the head coach. to estimate support for firing the current head coach, a television news station provides a link on its website where fans of the team can respond to the question: "do you feel the current head coach should be fired?" after 2,367 votes on the website, 79% of those who responded felt the coach should be fired. which of these describes the type of bias in this survey and a likely direction of the bias in estimating overall support for firing the coach?
This is voluntary response bias. The result overestimates true support for firing the coach.
What is voluntary response bias? When sample participants are self-selected volunteers, as in voluntary samples, voluntary response bias emerges.An illustration would be call-in radio programs that invite listeners to participate in polls on contentious issues (abortion, affirmative action, gun control, etc.).The sample that results tends to overrepresent people with strong opinions. In a random sampling technique, every component of the population has a known, non-zero probability of being chosen, and the selection of the sample unit is dependent only on chance.By removing voluntary response bias and protecting against undercoverage bias, random sampling aids in the production of representative samples.Random sampling underpins all probability sampling techniques.To know more about voluntary response bias with the given link
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What is the period of y = 2cos(3x - 2п)?
Answer:
Periodicity of 2cos(3x-2π)=
[tex] \frac{2\pi}{3} [/tex]
Step-by-step explanation:
Greetings![tex]periodicity \: of \: 2 \cos(3x - 2\pi) \\ periodicity \: of \: a. \cos(bx + c) + d = \\ \frac{periodicity \: of \: \cos(x) }{|b|} \\ periodicity \: of \: \cos(x) \: is \: 2\pi = \frac{2\pi}{|3|} \\ simplify = \frac{2\pi}{3} [/tex]
Answer:
[tex]\sf Period=\dfrac{2}{3} \pi[/tex]
Step-by-step explanation:
The cosine function is periodic, meaning it repeats forever.
Standard form of a cosine function
f(x) = A cos(B(x + C)) + D
where:
A = amplitude (height from the mid-line to the peak)2π/B = period (horizontal distance between consecutive peaks)C = phase shift (horizontal shift - positive is to the left)D = vertical shiftGiven function:
y = 2 cos (3x - 2π)
Therefore:
A = 2B = 3C = 2/3D = 0Period of given function:
[tex]\sf \implies Period=\dfrac{2 \pi}{B} = \dfrac{2 \pi}{3}[/tex]
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what is - 4x +7 > x -13
Answer:
[tex]\huge\boxed{\sf x < 4}[/tex]
Step-by-step explanation:
Given inequality:-4x + 7 > x - 13
Subtract x to both sides
-4x - x + 7 > -13
-5x + 7 > -13
Subtract 7 to both sides
-5x > -13 - 7
-5x > -20
Divide -5 to both sides
x < -20/-5
x < 4[tex]\rule[225]{225}{2}[/tex]
Answer:
[tex]x < \bf 4[/tex]
Step-by-step explanation:
[tex]-4x + 7 > x -13[/tex]
We have to make [tex]x[/tex] the subject of the equation:
• Subtract [tex]x[/tex] from both sides:
[tex]-4x - x + 7 > -13[/tex]
⇒ [tex]-5x + 7 > -13[/tex]
• Now subtract 7 from both sides:
[tex]-5x > -13 - 7[/tex]
⇒ [tex]-5x > -20[/tex]
• Next divide both sides by -5, and remember that dividing an inequality by a negative number reverses the inequality symbol:
[tex]x < \frac{-20}{-5}[/tex]
⇒ [tex]x < \frac{20}{5}[/tex]
⇒ [tex]x < \bf 4[/tex]
By selling 20 oranges for#1.35 a trader makes a profit of 8% what is the percentage gain or loss if he sells the same 20 oranges for#1.10?
Answer:
12% loss
Step-by-step explanation:
The selling price is the sum of the cost price and the markup. Here, the markup (profit) is expressed as a percentage of the cost price.
Cost priceThe relation between selling price and cost price is ...
selling price = cost price + cost price × markup fraction
selling price = cost price × (1 + markup fraction)
Then the original cost price is ...
cost price = (selling price) / (1 + markup fraction)
cost price = #1.35 / (1 +8%) = #1.25
ProfitAfter the change in selling price, we can find the markup fraction (profit rate) to be ...
1 + markup fraction = (selling price)/(cost price)
markup fraction = (selling price)/(cost price) -1
markup fraction = #1.10/1.25 -1 = 0.88 -1 = -0.12
The trader has a 12% loss when selling the oranges at #1.10.
Find the missing length indicated.
The missing length of given right triangle is equal to 1500.
RIGHT TRIANGLEA triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.
The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.
The Pythagorean Theorem says: [tex]hypotenuse^2=(leg_1)^2+(leg_2)^2[/tex] . And the main trigonometric ratios are: sin (x), cos (x) and tan (x) , where:
[tex]sin(x)=\frac{opposite\ side}{hypotenuse} \\ \\ cos(x)=\frac{adjacent\ side}{hypotenuse} \\ \\ tan (x)= \frac{opposite\ side}{adjacent\ side}[/tex]
There is another important property, where h²=m*n. See the attached image.
From the previous informations presented, you can solve the given question.
Thus, if h²=m*n. You can write:
h²=900*1600
[tex]h=\sqrt{1440000}\\ \\ h=1200[/tex]
If h=1200, you can find x from Pythagorean Theorem.
x²=1200²+900²
x²=1440000+810000
x²=2250000
x=[tex]\sqrt{2250000}[/tex]
x=1500
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PLease helppppppppp!!!
Answer:
437.068 28.019
Step-by-step explanation:
Not sure how to explain this one....it is what it is
7 ones = 7
3 tens = 30
4 hundreds = 400 added = 437
No tenths = 0
6 hudredths = .06
8 thousandths = .008 added to = 437.068
280 tenths = 280 * 1/10 = 28
19 thousandths = .019 summed = 28.019
In a scale drawing of a painting, 2 centimeters represents 7 inches.
The height of the real painting is 35 inches. What is the height of the painting in the scale drawing?
The height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches. This can be obtained by using the ratio of scale drawing to the real drawing.
Find the height of the painting in the scale drawing:Here in the question it is given that,
In a scale drawing of a painting, 2 centimeters represents 7 inchesThe height of the real painting is 35 inchesThus we can say that, scale of the painting is 2 cm : 7 in
Ratio of scale drawing and real painting is 2 : 7
⇒ Similarly here height of the painting in the scale drawing to the height of the painting in the real drawing will be in the ratio 2 : 7.
We can say that,
2 cm/7 in = x cm/35 in
where x is the height of the painting in the scale drawing
2 cm × 35 in /7 in = x cm
x = 2 × 5 cm
x = 10 cm
Hence the height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches.
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The actual length of Lake Superior is 350 miles and the width is 160 miles. What's the length and width of the lake on a map if the scale is "1 cm = 25 miles"?
Answer:
length = 14 cm; width = 6.4 cm
Step-by-step explanation:
We can use proportions to find the length and width.
Thus, for length, l, we have:
[tex]\frac{1}{25}=\frac{l}{350} \\25l=350\\l=14[/tex]
For width, w, we have:
[tex]\frac{1}{25}=\frac{w}{160}\\ 25w=160\\ w=6.4[/tex]
The local gym is offering this new promotion: An enrollment fee of $40 and a monthly fee of $30. Which of the following expressions represents the cost of the gym membership for m months?
40+30m=c40 plus 30 m is equal to c
30+40m=c30 plus 40 m is equal to c
40+30m40 plus 30 m
30+40m
The expression 40 + 30m = c represents the cost of the gym membership for m months option (A) 40 + 30m = c is correct.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
It is given that:
The local gym is offering this new promotion:
An enrollment fee of $40 and a monthly fee of $30.
Let m be the total number of months
Total monthly fee = 30m
Total cost(including the enrollment fee of $40) = 40 + 30m
Let the total cost is c:
c = 40 + 30m
If in the linear expression, one variable is present, then the bis known as the linear expression in one variable.
Thus, the expression 40 + 30m = c represents the cost of the gym membership for m months option (A) 40 + 30m = c is correct.
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4x+10=-2x + 4
y - 4 (2y - 5) = -4
Solve the 2 equations
(ignore image)
The solutions to the equations are x = 7/3 and y = 24/7
What are linear equations?Linear equations are equations that have constant average rates of change, slope or gradient
How to determine the solution to the system?A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
4x + 10 = -2x + 4
y - 4(2y - 5) = -4
Considering the first equation
4x + 10 = -2x + 4
Collect the like terms
4x + 2x = 10 + 4
Evaluate the like terms, by adding them
6x = 14
Divide both sides of the equation by 6
x = 7/3
Considering the second equation
y - 4(2y - 5) = -4
Expand the bracket in the above equation
y - 8y + 20 = -4
Collect the like terms
y - 8y = -20 -4
Evaluate the like terms, by adding them
-7y = -24
Divide both sides of the equation by -7
y = 24/7
Hence, the solutions to the equations are x = 7/3 and y = 24/7
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DIVINE TOK A MATH TEST AND GOT 36 CORRCET AND 9 INCORRECT WHAT WAS THE PERCANTHGE OF CORRECT ANSWERS
Answer: 80% correct
Step-by-step explanation:
If Divine got 36 correct and 9 incorrect, then we can find the total number of questions.
36 + 9 = 45 questions
Now, we will divide the number of questions answered correctly by the total number of questions.
[tex]\displaystyle \frac{36}{45} =0.8[/tex]
Lastly, we will multiply it by 100 to find the percentage.
0.8 * 100 = 80%
Answer:
80% was correct.
Step-by-step explanation:
The total number of questions is 45 (36 + 9). The percentage is the part correct over the total.
36/45 = .8. The answer is given in the decimal form. To change a decimal to a percent, move the decimal two places to the right.
The drama club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $8.50, and bags of cookies cost $4.50, and sales equaled $79.00 in total. There were 6 more bags of cookies than candy sold.
Find the number of bags of candy and cookies sold by the drama club. Show your work.
The bags of candy that was sold is 6
The bags of cookies that was sold is 10.
What are the linear equations that represent the question?$8.50c + $4.50o = 79 equation 1
o - c = 6
o = 6 + c equation 2
Where:
o = bags of cookies soldc = bags of candies sold How many bags of candy and cookies were sold?Substitute for o in equation 1 using equation 2
$8.50c + $4.50(6 + c) = 79
$8.50c + 27 + 4.50c = 79
$8.50c + 4.50c = 79 - 27
$13c = 52
c = 52 / 13
c = 4
Substitute for c in equation 2
0 = 6 + 4 = 10
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Find the most general antiderivative of the function. (check your answer by differentiation. use c for the constant of the antiderivative. ) f(x) = x(18x 4)
Answer:
Below in bold.
Step-by-step explanation:
f(x) = x(18x + 4)
f(x) = 18x^2 + 4x
Antiderivative = 18 * (x^2+1)/(2 + 1) -+4x(1+1) / (1+1) + C
= 18x^3 / 3 + 4x^2 / 2 + C
= 6x^3 + 2x^2 + C.
Checking by differentiating:
f'(x) = 6*3 x^(3-1) + 2*2x^(2-1)
= 18x^2 + 4x
= x(18 -+4)
