You have the following expression:
8.1p + 7.5r
if p=6 and r=7, you obtain for the previous expression:
8.1(6) + 7.5(7) = 48.6 + 52.5 = 101.1
Hence, the result is 101.1
When we ride a bike, do we actually move the earth, but not enough for the human eye to see?
Answer: Yes, we do move the earth
Explanation: When we ride a bike, we exert a force on the earth, and the earth in turn pushes us forward, which is what propels us. The force that we exert on the earth does move the earth by a very small amount. Newton's third law of motion states exactly this.
A 100 watt lamp has a resistance of 120 Ω. Find the current in the lamp.Group of answer choices2.15 A1.20 A0.913 A0.833 A
0.913 A
Explanation
the poweris given by
[tex]P=I^2R[/tex]so
Step 1
Let
[tex]\begin{gathered} I=I \\ P=100\text{ watts} \\ \text{resistance}=120\text{ ohm} \end{gathered}[/tex]b) now replace
[tex]\begin{gathered} P=I^2R \\ 100=I^2\cdot120 \\ \text{divide boths sides by 120} \\ \frac{100}{120}=\frac{I^2\cdot120}{120} \\ 0.8333=I^2 \\ \text{square root in both sides} \\ \sqrt{0.8333}=\sqrt{I^2} \\ 0.91287=I \\ \text{rounded} \\ I=0.913\text{ Amperes} \end{gathered}[/tex]therefore, the answeris
0.913 A
I hope this helps you
You have an unknown substance with a mass of
40 g and a volume of 100 cm³.
What is its density?
Will it sink or float in water?
Which THREE statements are TRUE about mechanical and electromagnetic waves? A In all mechanical waves, the amplitude is the distance from the medium to the crest of the wave. B Particles in mechanical waves can travel perpendicular or parallel to the medium they are traveling throughCSome mechanical waves lack a crest because the particles move parallel to the medium they are traveling through D In electromagnetic waves, a wavelength is determined by measuring the distance between two consecutive cresis EIn electromagnetic waves, a wavelength is determined by measuring the distance between two consecutive compressions
The statements that are true are, Statement B, statement C and statement D.
Not all mechanical waves have crests. Transverse waves have crests and troughs and longitudinal waves have compression and rarefactions. Thus statement A is not true.
Mechanical waves have two main types. In transverse waves, the particles of the wave travel perpendicularly and in longitudinal waves, they travel parallelly. Therefore, statement B is true.
A student tries to unscrew a bolt with a spanner with 25 cm long. Thelargest force that he is able to apply is 100 N, while the minimummoment required to unscrew the nut is 30 N m. Can he unscrew the nut?
ANSWER
No, he cannot
EXPLANATION
First, let us draw a sketch of the problem:
For him to be able to unscrew the nut, the moment of the largest force he can apply must be greater than the minimum moment required to unscrew the nut.
To find the moment of the force, we apply the formula:
[tex]M=F\cdot d[/tex]where F = force applied = 100 N;
d = distance between effort and bolt i.e. the length of the spanner = 25 cm = 0.25 m
Therefore, we have that the moment of the force is:
[tex]\begin{gathered} M=100\cdot0.25 \\ M=25Nm \end{gathered}[/tex]Since the largest moment is 25Nm, and the minimum moment required to unscrew the nut is 30Nm, he cannot unscrew the nut.
The answer is NO.
An airplane flies on a level path. There is a pressure difference of 587 Pa between the lower and upper surfaces of the wings. The area of each wing surface is about 100 m2. The air moves below the wings at a speed of 80.5 m/s. Estimate the weight of the plane.
ANSWER:
117400 N
STEP-BY-STEP EXPLANATION:
Given:
Pressure difference = 587 Pa
Surface area of the wing = 100 m^2
Speed of the sir below the wing = 80.5 m/s
The weight of the plane is the force due to the pressure difference of upper and lower side of both wings. Therefore:
[tex]\begin{gathered} F=\Delta P\cdot2A \\ F=587\cdot2\cdot100 \\ F=117400\text{ N} \end{gathered}[/tex]The weight is a force of 117400 N.
Converting the number0.700 to Scientific Notation7.00 x 10-17.00 x 101O 7x 1010 7x10-1
Explanation
Step 1
Place a decimal by counting the steps to the left until the coefficient of the number is between 1 and 9.
so
[tex]0.700\rightarrow move\text{ the decimal place 1 position 7.000}[/tex]Step 2
Count the number of steps moved. This will be the power of the base 10.
Moving the decimal point to the right gives a negative exponent, whereas moving the decimal point to the left makes a positive exponent.
1 place to the rigth so the exponent is -1
Step 3
In this case, the coefficient is 7 and the 1 steps are moved
so, Multiply the coeeffcient by 10 exp(1), the (1) we got from the previous step
so, the number is scientific notation is
[tex]\begin{gathered} 0.700\rightarrow7\cdot10^{-1} \\ 7\cdot10^{-1} \end{gathered}[/tex]I hope this helps you
Find the acceleration of a toy place whose velocity as a function of time is given by the graph belowat a) t = 4.00 s b) t = 9.00 s and c) t = 11.0 s.
ANSWER:
a) 1 m/s^2
b) -4 m/s^2
c) 0 m/s^2
STEP-BY-STEP EXPLANATION:
The acceleration is given by the following equation:
[tex]a=\frac{\Delta v}{\Delta t}=\frac{v_f-v_i}{t_f-t_i}[/tex]Therefore:
a) t = 4 s
[tex]a=\frac{3-(-3)}{6}=\frac{3+3}{6}=\frac{6}{6}=1[/tex]b) t = 9 s
[tex]a=\frac{-5-3}{10-8}=\frac{-8}{2}=-4[/tex]c) t = 11 s
[tex]a=\frac{-5-(-5)}{12-10}=\frac{-5+5}{2}=\frac{0}{2}=0[/tex]An object moving with uniform acceleration has a velocity of 13.0 cm/s in the positive x-direction when its x-coordinate is 3.18 cm. If its x-coordinate 2.95 s later is −5.00 cm, what is its acceleration? cm/s2
Given:
The initial velocity of the object is: u = 13 cm/s
The time taken by an object to change the position coordinate is: t = 2.95 s
The change in the position (displacenent) is: Δx = -5 cm - 3.18 cm = - 1.82 cm
To find:
The acceleration of an object.
Explanation:
The acceleration of an object can be determined by using following kinematical equation,
[tex]\Delta x=ut+\frac{1}{2}at^2[/tex]Rearranging the above equation, we get:
[tex]a=\frac{2(\Delta x-ut)}{t^2}[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} a=\frac{2\times(1.82\text{ cm}-13\text{ m/s}\times2.95\text{ s\rparen}}{(2.95\text{ s\rparen}^2} \\ \\ a=\frac{2\times(-36.53^\text{ cm})}{8.7025\text{ s}} \\ \\ a=-8.9351\text{ cm/s}^2 \end{gathered}[/tex]Final answer:
The acceleration of an object is -8.9351 cm/s^2.
Which two forces will cause the same rate of change in the stick's angular momentum as each other.
Given:
The stick is attached to a pivot at the right end.
The four forces are,
[tex]40\text{ N, 60 N, 30 N, 150 N}[/tex]Any one of the forces can act on that stick at a time.
To find:
Which two forces will cause the same rate of change in the stick's angular momentum
Explanation:
Let the length of each space be x.
To produce the same rate of change in angular momentum, the forces should produce the same torque.
The torque produces by the force,
[tex]40\text{ N}[/tex]is,
[tex]\begin{gathered} 40\times4x\text{ \lparen the distance of this force from the right end is 4x\rparen} \\ =160x \end{gathered}[/tex]Similarly, the torque by 60 N force is,
[tex]\begin{gathered} 60\times3x \\ =180x \end{gathered}[/tex]by 30 N force is,
[tex]\begin{gathered} 30\times2x \\ =60x \end{gathered}[/tex]by 150 N force is,
[tex]150x[/tex]Here, we see all the torques are different from each other.
Hence, they all are different.
The Moon has a mass of 7.35 × 1022 kg and a radius of 1.74 × 106 m. It orbits around the Earth at a distance of 3.84 × 108 m, completing a full rotation every 27.3 days. It also spins on its axis at a speed such that the same side of the moon is always facing the Earth. calculate the angular momentum of the moon in its orbit around the earth, b,calculate the angular momentum of the moon in its rotation around its axis, c,how many times larger is the angular momentum than the rotational angular momentum for the moon?
Givens.
• Mass of the Moon = 7.35x10^22 kg.
,• The radius of the orbit = 3.84x10^8 m.
First, find the tangential velocity.
[tex]v=\frac{2\pi r}{T}=\frac{2\pi\cdot3.84\times10^8m}{2.36\times10^6s}=1022.35\cdot\frac{m}{s}[/tex]Observe that we use the period in seconds, not in days. The transformation we performed is
[tex]T=27.3\text{days}\cdot\frac{86400\sec}{1day}=2.36\times10^6\sec [/tex]Once we have the tangential velocity, we can find the angular momentum of the Moon around the Earth.
[tex]\begin{gathered} L=mvr=7.35\times10^{22}\operatorname{kg}\cdot1022.35\cdot\frac{m}{s}\cdot3.84\times10^8m \\ L=2.9\times10^{34}\operatorname{kg}\cdot\frac{m^2}{s} \end{gathered}[/tex]Therefore, the angular momentum around the Earth is 2.9x10^34.
The angular momentum of the moon can be found using the following formula.
[tex]L=I\cdot w[/tex]Where I is the moment of inertia of the moon and w is the angular velocity.
The moment of inertia of a spherical solid is
[tex]I=\frac{2}{5}mr^2[/tex]The mass of the moon is 7.35 × 10^22 kg and its radius is 1.74 × 10^6 m. So, the inertia is
[tex]\begin{gathered} I=\frac{2}{5}\cdot7.35\times10^{22}\operatorname{kg}\cdot(1.74\times10^6m)^2 \\ I=8.9\times10^{34}\operatorname{kg}\cdot m^2 \end{gathered}[/tex]Using its angular velocity of 2.7x10^-6 rad/s, we find its angular momentum.
[tex]\begin{gathered} L=2.7\times10^{-6}rad/s\cdot8.9\times10^{34}\operatorname{kg}\cdot m^2 \\ L=2.4\times10^{29}\operatorname{kg}\cdot\frac{m^2}{s^{}} \end{gathered}[/tex]The angular momentum of the moon onto itself is 2.4x10^29.
At last, divide both momentums to compare them.
[tex]\frac{L_{\text{earth}}}{L_{\text{moon}}}=\frac{2.9\times10^{34}\operatorname{kg}\cdot\frac{m^2}{s}}{2.4\times10^{29}\operatorname{kg}\cdot\frac{m^2}{s^{}}}=1.2\times10^5[/tex]Therefore, the angular momentum around the Earth is 1.2x10^5 times greater than the angular momentum of the Moon onto itself.
A voice that is audible cannot be easily heard. True or false
Given
A voice that is audible cannot be easily heard.
To find
Whether the given statement is true or false
Explanation
The sounds which a person can hear is known as audible. So the voice that is audible is easily heard.
Conclusion
The given statement is false
order the colors of the darts to show the size of the acceleration each dart will have as it is being thrown
silver
green
red
gold
blue
Explanation:Relationship between force (F), mass (M), and acceleration (a) is:
F = ma
a = F/m
The larger the value of a, the smaller the value of m. The smaller the value of a, the larger the value of m.
Therefore, if the force applied is equal, to arrange the acceleration from the largest to the smallest, we will arrange the mass from the smallest to the largest
silver
green
red
gold
blue
in which ecosystem would a lion hunt a zebra? freshwater
savanna
desert
Answer:
Savanna
Explanation:
lions are in Africa right? Hot deserty climat so the answer would be Savanna.
Answer:
Savanna
Explanation:
Lions are predators in African savanna. They hunt on large herbivore populations of buffalos, impalas, zebras, and even elephants and giraffes.
A penny is dropped from a building and it takes 7.00 seconds to hit the ground.
What was the penny’s final velocity as it hit the ground?
The final velocity of the pen as it hits the ground is 68.6 meters per seconds.
What is the velocity of the pen as it hits the ground?Velocity is simply the speed at which an object moves in a particular direction.
From the first equation of motion
v = u + gt
Where v is final velocity, u is initial velocity, t is time elapsed and g is acceleration due to gravity ( g = 9.8m/s² )
Given the data in the question;
The pen was initially at rest before the drop, Initial velocity u = 0Elapsed time t = 7.00sFinal velocity v = ?To determine the velocity just before the pen hits the ground, plug the values into the formula and solve for v.
v = u + gt
v = 0 + ( 9.8m/s² × 7.00s )
v = 9.8m/s² × 7.00s
v = 68.6m/s
Therefore, the final velocity is 68.6 meters per seconds.
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Q5. Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), will it ever swing higher than it's starting point? Explain your answer in terms of kinetic and potential energy.
Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), it will never swing higher than it's starting point.
In a pendulum, the total energy of the system always remains constant.
Total energy = Potential Energy + Kinetic Energy
When a bob of a pendulum is raised to hang in the string it gains potential energy because work is done to raise the bob. In a pendulum motion, at the starting point potential energy is at its maximum, meaning kinetic energy is zero.
As it starts to swing the potential energy is converted into kinetic energy. So potential energy decreases and kinetic energy increases. At the lowest point of the swing the kinetic energy is maximum and potential energy is zero. As the motion continues when it reaches the top most point potential energy will be maximum and Kinetic energy will be zero again. Throughout the entire motion total energy remains constant. Only when you push it initially, it will gain extra energy to go higher than the starting point.
Therefore, unless you push a pendulum at the start of it's swing (doing work to give it extra energy), it will never swing higher than it's starting point.
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The amount of potential energy possessed by an object elevated is equal toThe power used to lift itThe work done in liftingThe distance liftedForce needed to lift it
To find:
The amount of potential energy possessed by an object is equal to which of the given quantities?
Explanation:
The potential energy of an object is the energy possessed by the object due to its position.
To lift an object to a certain height, a certain amount of work needs to be done. This work done on the object to lift it will be stored in the object as theopotential energy.
Final answer:
Thus the correct answer is option B, 'the work done in lifting.'
You walk exactly 250 steps North, turn around, and then walk exactly 400 steps South. How far are you from your starting point?
150 steps
Explanation
to find the final position, we need to add the vectors of displacement
Step 1
Diagram:
Step 2
now, we need to add the vectors
a)let the vectors
U= vector from the start point to the place where he turns around
v= vector from point B to end point
[tex]\begin{gathered} U=\langle0i+250j\rangle \\ v=\langle0i-400j) \end{gathered}[/tex]so, to find the final position we need to add the vectors, component to component
so
[tex]\begin{gathered} U+v=(0i+0i,250j-400j) \\ U+v=\langle0,-150\rangle \end{gathered}[/tex]so, the final position is -150, the negative sign indicates the direction (south) and the magnitud indicates the distance
so, you are 150 steps from your starting point
I hope this helps you
A point charge of −3μC is locatedat the center of a sphere with a radius r=5cm. What is the net electric flux through the surface?short answer pls asap
Given:
The total charge enclosed by the surface of the sphere, q=-3 μC
The radius of the sphere, r=5 cm=5×10⁻² m
To find:
The net electric flux through the surface of the sphere.
Explanation:
From Gauss's law, the net electric flux through the surface of the sphere is given by,
[tex]\phi=\frac{Q}{\epsilon_0}[/tex]Where ε₀ is the permittivity of free space.
On substituting the known values,
[tex]\begin{gathered} \phi=-\frac{3\times10^{-6}}{8.85\times10^{-12}} \\ =339\times10^3\text{ Nm}^2\text{/C} \end{gathered}[/tex]Final answer:
The net flux through the surface of the sphere is 339×10³ Nm²/C
A particle’s position along the x-axis is described byx(t) = A t + B t2,where t is in seconds, x is in meters, and the constants A and B are given below.Randomized VariablesA = -3.15 m/sB = 2.4 m/s21 what is the position of the particle when the velocity is zero.
Given data:
Position of the particle along the x-axis;
[tex]x(t)=At+Bt^2[/tex]Here, A and B are constants with A=-3.15 m/s and B=2.4 m/s².
Therefore,
[tex]x(t)=-3.15t+2.4t^2[/tex]The velocity of the particle is given as,
[tex]v(t)=\frac{dx(t)}{dt}[/tex]Substituting x(t),
[tex]\begin{gathered} v(t)=\frac{d}{dt}(-3.15t+2.4t^2) \\ =\frac{d}{dt}(-3.15t)+\frac{d}{dt}(2.4t^2) \\ =-3.15+2\times2.4t \\ =-3.15+4.8t \end{gathered}[/tex]The time when the velocity will be zero is calculated by substituting v(t)=0 in the above expresion,
[tex]\begin{gathered} 0=-3.15+4.8t \\ 4.8t=3.15 \\ t=\frac{3.15}{4.8} \\ \approx0.66\text{ s} \end{gathered}[/tex]Therefore, the position of the particle when the velocity is zero is calculated by substituting t=0.66 s in the equation for the position of the particle,
[tex]\begin{gathered} x(0.66\text{ s})=-3.15\times0.66+2.4\times(0.66)^2 \\ \approx-1.03\text{ m} \end{gathered}[/tex]Therefore, the position of the particle when the velocity is zero is -1.03 m (1.03 m to the left of its initial position).
A light wave has a frequency of 6 x 10^8. What is the wavelength of the light wave? (Assume the speed of light to be 3 x 10^8.)
ANSWER
[tex]\begin{equation*} 0.5\text{ }m \end{equation*}[/tex]EXPLANATION
Parameters given:
Frequency of light wave, f = 6 * 10⁸ Hz
Speed of light, c = 3 * 10⁸ m/s
To find the wavelength of the light wave, apply the relationship between speed of light and wavelength:
[tex]\begin{gathered} c=\lambda f \\ \lambda=\frac{c}{f} \end{gathered}[/tex]Hence, the wavelength of the light wave is:
[tex]\begin{gathered} \lambda=\frac{3*10^8}{6*10^8} \\ \lambda=0.5\text{ }m \end{gathered}[/tex]That is the answer.
A position versus time graph is shown below.
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. A line connects points 0, 0 and 1, 4. A horizontal line connects points 1, 4 and 4, 4. A line connects points 4, 4 and 6, 10. A horizontal line connects points 6, 10 and 8, 10. A line connects 8, 10 and 9, 14, and then 10, 15.
Use the graph to determine the instantaneous velocity in m/s of the object at 7 seconds.
0 m/s north
1.4 m/s north
7 m/s north
10 m/s north
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. The instantaneous velocity in m/s of the object at 7 seconds is 0 m/s north.
What is instantaneous velocity?
Instantaneous velocity, often known as the time derivative of position, is the rate of change (slope) of the position function.
[tex]v=\dot{s}=\frac{ds}{dt}[/tex]
The limit of the average velocity as time approaches 0, or the derivative of x with respect to t, is the instantaneous velocity of an object.
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. A line connects points 0, 0 and 1, 4. A horizontal line connects points 1, 4 and 4, 4. A line connects points 4, 4 and 6, 10. A horizontal line connects points 6, 10 and 8, 10. A line connects 8, 10 and 9, 14, and then 10, 15.
Use the graph we determine the instantaneous velocity in m/s of the object at 7 seconds is 0 m/s .
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Answer:
the answer is 7m/s north
Explanation:
I took the quiz
A motorcycle moving at 18 m/s decelerates at a rate of 3.6 m/s². What is the car's
velocity 4 seconds later?
Answer:
V = 3.6 m/s
Explanation:
Given:
V₀ = 18 m/s
a = - 3,6 m/s² (The motorcycle is slowing down!)
t = 4 s
____________
V - ?
Motorcycle speed:
V = V₀ + a·t
V = 18 + (-3.6)·4 = 3.6 m/s
A circus van moves 50 km [E] in the first hour, 40 km [W] in the second hour, and 30 km [N] in the next half hour. Calculate the average velocity of the travelling circus van?
The average velocity of the travelling circus van is 12.64km/h.
As we already know, the directions east[E] and west[W] are opposite to each other, north[N] perpendicular to both of them.
We know, average velocity V,
V = total displacement/total time taken
Let us assume the situation on a coordinate plane, and say that the van started from origin,
The circus van first goes to the east direction and travels 50Km. After that, it travels 40Km back,
So, he travels straight 50Km and then return back 40Km, so now, his current position is 10Km in the east direction,
Now, from the point in 10km east, he travels 30km north,
Now, his current and final position is 10km east and 30km north,
His initial position was 0km in east and 0km in north,
So, his total displacement D is,
D² = (10)²+(30)²
D² = 100+900
D² = 1000
D = 10√10 Km.
Total time T taken by him is,
T = 1+1+.05
T = 2.5 hours,
Putting the values, the average velocity V is,
V = D/T
V = 10√10/2.5
V= 12.64 km/h
So, the average velocity is 12.64km/h.
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The main characteristics used to classify stars include all of the following EXCEPT:A. shape.B. brightnessC. colorD. temperature
From the given list of choices, let's select the characteristic that cannot be used to classify stars.
Stars can be said to be self-luminous bodies of gas which shines by radiation gotten from its internal energy sources.
Stars can be classified using five properties:
0. Color
,1. Temperature
,2. Size
,3. Composition
,4. Nature of brightness
Therefore, the characteristic that cannot be used to classify a star is its shape.
All stars look spherical due to their gravitational properties.
ANSWER:
A. Shape
Doubling the frequency of a sound wave within a uniform (unchanging) medium will _________. Select all that apply.a- halve the amplitude of the waveb- halve the wavelength of the wavec- double the speed of the waved- halve the speed of the wavee- double the amplitude of the wavef- double the wavelength of the wave
ANSWER:
b- halve the wavelength of the wave
STEP-BY-STEP EXPLANATION:
We have that the speed of a wave is dependent upon the properties of the medium through which the wave is moving. An alteration in the properties of the medium will result in a change in the speed at which the wave moves through that medium.
That is to say that when changing frequency, what changes is the wavelength.
They are inverse, so when the frequency doubles, the wavelength is divided in half.
Therefore, the correct answer is:
b- halve the wavelength of the wave
The force exerted by gravity on a whole brick is greater than the force exerted bygravity on half a brick. Why, then, doesn't a whole brick fall faster than half a brick?
The force exerted by gravity on a whole brick is greater than the force exerted by gravity on half a brick.
They hit the ground at the same time because they fall at -9.81m/s^2.
What is force ?The definition of force is: The push or pull on a mass object causes it to change velocity. Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.The term "force" has a specific meaning. At this level, it is perfectly acceptable to refer to a force as a push or a pull. A force is not something that an object 'has in it.' Another object applies a force to another. The concept of a force is not limited to living or nonliving things.According to Newton's Law F = ma. where m is mass of the object, a is acceleration.
so,
The force exerted by gravity on a whole brick is greater than the force exerted by gravity on half a brick.
They hit the ground at the same time because they fall at -9.81m/s^2.
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A solid cube is submerged in a container of water of density p,. The cube has mass M, volume Vc, and density ½pw. The water exerts an upward buoyant force on the cube of magnitude PwVcg. Which of the diagrams is the best representation of the forces exerted by the water on the cube?
ANSWER:
STEP-BY-STEP EXPLANATION:
We have that the density of the cube is less than the density of water.
Which means that naturally the cube will float, so if it is immersed in water, the upward force will be greater than the downward push.
The diagram that represents a greater force upwards than downwards is the diagram for option C, so the correct option is option C.
Anyone, help me plss
The acceleration of the given car is 4 m/s² on the Right hand side.
What is meant by velocity?Velocity can be defined as the rate at which something moves in a specific direction.
As the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.
Based on the information, one could use the following formula to compute the magnitude of acceleration in this case:
[tex]$a=\frac{V_f-V_i}{t}$$[/tex]
Given:
initial velocity (u): 2m/s
Final velocity (v): 12m/s
Time taken : 2.5 second
we know that,
V = u + at
after putting all the values, we get
a = 4 m/s²
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Equilibrium Attained Net Force = 0 NewtonsDraw a free body diagram with a 10 N force and a 25 Newton force acting on an object in the opposite directions. Describe the additional force needed to be applied to achieve equilibrium.
Explanation:
There are two forces acting on the object in opposite directions.
The sketch of the two forces is
since the force acting towards the left is greater than the force acting on the right, the object will accelerate towards the left.
Now, how much force is required to counter 25 N acting on the left?
The answer is, if we apply an additional 15 N towards the right, the total force acting in this direction is 10 + 15 = 25 N, which is enough to counter 25 N acting towards the left.
Therefore, we need to apply an additional 15 N in the direction of the 10 N force.
