Different wavelengths of light are reflected or absorbed to cause different objects to appear different colors. When light shines on an object, some wavelengths of light are absorbed by the object, while others are reflected. The wavelengths that are reflected determine the color of the object that we see.
For example, a blue object appears blue because it reflects blue wavelengths of light and absorbs other colors. Similarly, a red object appears red because it reflects red wavelengths of light and absorbs other colors. The main answer to the question of how different wavelengths of light are reflected or absorbed to cause different objects to appear different colors is through selective absorption and reflection of light.Explanation:The way different wavelengths of light are absorbed or reflected by different objects depends on the object's physical and chemical properties, such as its atomic structure and the type of molecules it contains. When light interacts with an object, its energy can be absorbed by electrons in the object's atoms or molecules, causing the electrons to move to higher energy levels. The amount of energy required to move an electron to a higher energy level depends on the wavelength of the light. Therefore, different colors of light can cause electrons in an object to move to different energy levels, depending on their wavelengths.
When an electron in an atom or molecule absorbs energy from light, it becomes excited and unstable. The electron can then release this energy by emitting a photon of light. The wavelength of the emitted photon depends on the energy level difference between the excited state and the ground state. The emitted light can have the same, higher, or lower energy than the absorbed light, depending on the energy level difference.The selective absorption and reflection of light by different objects is what gives them their characteristic colors. For example, a red object appears red because it absorbs blue and green wavelengths of light and reflects red wavelengths. A blue object appears blue because it absorbs red and green wavelengths of light and reflects blue wavelengths. A white object appears white because it reflects all wavelengths of light equally, while a black object appears black because it absorbs all wavelengths of light and reflects none.
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Find the x and y components of a velocity vector that has a magnitude of V =10 m/s and an angle relative to the horizontal 40.0°
Answer:
The x and y components of the velocity vector are 7.66 m/s and 6.43 m/s respectively
Explanation:
Components of a Vector
Given a vector with a magnitude V and angle θ with respect to the positive horizontal direction, the x and y components of the vector are given by:
[tex]x=V\cos\theta[/tex]
[tex]y=V\sin\theta[/tex]
The question gives us the magnitude of the velocity V=10 m/s and the angle relative to the horizontal (assumed to the positive direction), then the components of the velocity vector are:
[tex]x=10\cos40^\circ=7.66\ m/s[/tex]
[tex]y=10\sin40^\circ=6.43\ m/s[/tex]
The x and y components of the velocity vector are 7.66 m/s and 6.43 m/s respectively
A 1.10 mm-diameter ball bearing has excess electrons 2.10 x 10^9. What is the ball bearing's potential?
The potential of the ball bearing is approximately 15.98 volts. The potential of an object can be calculated using the formula V = Q/C, where V is the potential, Q is the charge, and C is the capacitance.
In this case, the excess electrons on the ball bearing can be considered as the charge. The charge Q can be determined using the equation Q = ne, where n is the number of excess electrons and e is the elementary charge (1.6 x 10^-19 coulombs). The capacitance C can be calculated using the formula C = εA/d, where ε is the permittivity of free space (8.85 x 10^-12 F/m), A is the surface area of the ball bearing (πr²), and d is the diameter (1.10 mm = 1.10 x 10^-3 m). Substituting the given values into the formulas, we have Q = (2.10 x 10^9) * (1.6 x 10^-19) and C = (8.85 x 10^-12) * (π * (0.55 x 10^-3)²) / (1.10 x 10^-3). Finally, calculating V = Q/C yields approximately 15.98 volts.
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please help me with this question asap
Answer:
when it's at rest or moving with constant velocity or another word is equilibrium
A 0. 16 kg billiard ball moving to the right at 1. 2 m/s has a head-on elastic collision with another ball of equal mass moving to the left at 0. 85 m/s. The first ball moves to the left at 0. 85 m/s after the collision. Find the velocity of the second ball after the collision, and verify your answer by calculating the total kinetic energy before and after the collision
The velocity of the second ball after the collision is 1.2 m/s. The velocity of the second ball after the collision can be found using the principle of conservation of momentum.
Before the collision, the total momentum of the system is given by the sum of the individual momenta of the two balls. The momentum of an object is calculated by multiplying its mass by its velocity.
Let's assume the initial velocity of the second ball (moving to the left) is v₂.
The initial momentum of the first ball (moving to the right) is (0.16 kg)(1.2 m/s) = 0.192 kg·m/s.
The initial momentum of the second ball is (0.16 kg)(-0.85 m/s) = -0.136 kg·m/s.
The total initial momentum of the system is the sum of these two momenta: 0.192 kg·m/s + (-0.136 kg·m/s)
= 0.056 kg·m/s.
After the collision, the first ball moves to the left at 0.85 m/s. Therefore, its final momentum is (0.16 kg)(-0.85 m/s) = -0.136 kg·m/s.
According to the conservation of momentum, the total final momentum of the system should be equal to the initial total momentum.
Therefore, the final momentum of the second ball (v₂) can be calculated by subtracting the final momentum of the first ball from the total final momentum:
0.056 kg·m/s - (-0.136 kg·m/s) = 0.192 kg·m/s.
Since the second ball has the same mass as the first ball (0.16 kg), we can calculate its velocity by dividing its momentum by its mass:
v₂ = (0.192 kg·m/s) / (0.16 kg)
= 1.2 m/s.
To verify this answer, we can calculate the total kinetic energy before and after the collision.
The initial kinetic energy of the system is the sum of the individual kinetic energies of the two balls. The kinetic energy of an object is given by the equation KE = 0.5 * mass * velocity².
The initial kinetic energy of the first ball is:
KE₁ = 0.5 * (0.16 kg) * (1.2 m/s)²
= 0.1152 J.
The initial kinetic energy of the second ball is:
KE₂ = 0.5 * (0.16 kg) * (0.85 m/s)²
= 0.05768 J.
The total initial kinetic energy of the system is the sum of these two kinetic energies: 0.1152 J + 0.05768 J
= 0.17288 J.
After the collision, the final kinetic energy of the system should still be the same if the collision is perfectly elastic.
The final kinetic energy of the first ball is:
[tex]KE1_final[/tex] = 0.5 * (0.16 kg) * (0.85 m/s)²
= 0.05768 J.
The final kinetic energy of the second ball is:
[tex]KE2_final[/tex] = 0.5 * (0.16 kg) * (1.2 m/s)²
= 0.1152 J.
The total final kinetic energy of the system is the sum of these two kinetic energies: 0.05768 J + 0.1152 J
= 0.17288 J.
Since the total initial kinetic energy is equal to the total final kinetic energy (0.17288 J = 0.17288 J), we can verify that our answer is correct.
In conclusion, the velocity of the second ball after the collision is 1.2 m/s.
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A sea-level pressure of 750 millibars would be:
Question 12 options:
a) A strong high-pressure system
b) Unrealistically low pressure
c) A strong hurricane
d) The same as a pressure of 1013.25 mb at 1.6 km altitude
e) Unrealistically high pressure
A sea-level pressure of 750 millibars indicates an unrealistically high pressure.
A sea-level pressure of 750 millibars is abnormally high and not commonly observed in normal weather conditions. Typically, sea-level pressure ranges between 950 and 1050 millibars.
Therefore, option e) stating that it represents unrealistically high pressure is the correct answer. It is important to note that a pressure of 1013.25 millibars is considered standard atmospheric pressure at sea level, while a pressure of 750 millibars is significantly lower, suggesting an anomalous and extreme situation.
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A 120-g Object is attached to the bottom end of an unstressed spring. The spring is hanging vertically and has a force constant 40.0 N/m. The object is dropped, (a) What is its maximum speed? (b) How far does it drop before coming to rest momentarily?
(a) The maximum speed of the 120 g object is approximately 2.21 m/s when dropped from the unstressed spring.
(b) The object drops a distance of approximately 0.050 m before coming to rest momentarily.
(a) The maximum speed of the object can be determined by considering the conservation of mechanical energy. When the object is released, it converts its gravitational potential energy into kinetic energy. At the maximum speed, all the potential energy is converted into kinetic energy. The formula for kinetic energy is given by:
[tex]KE = (1/2)mv^2,[/tex]
where KE is the kinetic energy, m is the mass of the object (0.120 kg), and v is the velocity. Since the potential energy is converted into kinetic energy, we can equate the two:
[tex]mgh = (1/2)mv^2,[/tex]
where g is the acceleration due to gravity and h is the height of the drop. Solving for v, we find:
[tex]v = \sqrt{2gh} = \sqrt{2(9.8 m/s^2)(0.050 m)} = 2.21 m/s.[/tex]
(b) To determine the distance the object drops before coming to rest momentarily, we can use the equation for gravitational potential energy. When the object comes to rest, all the potential energy is stored in the spring as elastic potential energy. The gravitational potential energy can be calculated using the formula:
PE = mgh,
where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the drop. Equating this to the elastic potential energy of the spring, given by:
[tex]PE = (1/2)kx^2,[/tex]
where k is the force constant of the spring and x is the displacement, we can solve for x:
[tex](1/2)kx^2 = mgh,[/tex]
[tex]x^2 = (2mgh) / k,[/tex]
[tex]x = \sqrt{(2mgh) / k} = \sqrt{(2(0.120 kg)(9.8 m/s^2)(0.050 m)) / (40.0 N/m)} = 0.050 m.[/tex]
Therefore, the object drops a distance of approximately 0.050 m before coming to rest momentarily.
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a capacitor in an rc circuit is initially fully charged to a voltage of 12 v. it is then discharged through a resistor with a resistance of 100 . after 5 seconds, the voltage across the capacitor has decreased to 4 v. what is the time constant r of the circuit?
The time constant R of the circuit is calculated to be approximately 14.43 s. The time constant R of the circuit can be calculated as follows; [tex]V(t) = V(0) * e^(-t / R)[/tex] .
We are given that :A capacitor in an RC circuit is initially fully charged to a voltage of 12 V.A capacitor is then discharged through a resistor with a resistance of 100 Ω.After 5 seconds, the voltage across the capacitor has decreased to 4 V.
The time constant R of the circuit can be calculated as follows; [tex]V(t) = V(0) * e^(-t / R)[/tex] Where, V(0) = 12 V (the initial voltage across the capacitor)V(t) = 4 V (the voltage across the capacitor after 5 seconds)t = 5 sec And, R = time constant
Therefore, substituting the given values in the above formula;
[tex]4 V = 12 V * e^(-5 / R)[/tex]
Dividing both sides of the equation by 12 V, we get; [tex]e^(-5 / R) = (1/3)[/tex]
Take natural logarithm (ln) of both sides of the equation to eliminate e from the equation;
-5 / R = ln(1/3)
Multiplying both sides by R, we get; R * (-5 / R)
= R * ln(1/3)-5
= R * ln(1/3)
Dividing both sides by ln(1/3), we get; R = -5 / ln(1/3)
Therefore, the time constant R of the circuit is approximately 14.43 s.
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is it true or false that even established scientific laws are able to be tested?
please help!!! i need help with this science question!!
Answer:
If the Law has already been est. then the answer should be true .
Explanation:
If the law has already been est. then they can still test the theory of that law. If you test it you might find something new and interesting because the science might have missed something or a factor. It is a good thing to test things,even after establishment.
Paley's Teleological Argument. Know the premises and conclusion of the argument. Paley claims that a watch is like the universe/world. What attributes does he claim are the same for a watch and the universe/world. How does he use this analogy to attempt to prove that God exists? Be able to explain these objections to Paley's argument: a. There is no evidence that we can tell the world has purpose. b. The universe seems to be more chaotic than ordered. c. A watch is a bad analogy for the universe.
Paley's argument compares a watch to the universe/world, claiming that both exhibit similar attributes. He uses this analogy to argue for the existence of God.
Paley's Teleological Argument, often referred to as the argument from design, is based on the idea of purposeful design in the universe. The argument consists of the following premises and conclusion:
Premise 1: Watches are complex and exhibit intricate design, with various parts working together to fulfill a specific purpose.
Premise 2: The universe/world also exhibits complexity and intricate design, with various elements and processes working together.
Premise 3: If something exhibits complexity and design, it must have an intelligent designer.
Conclusion: Therefore, the universe/world must have an intelligent designer, which Paley identifies as God.
Paley argues that the attributes shared by a watch and the universe/world, such as complexity, order, and purposeful design, suggest the existence of an intelligent creator. He believes that just as the intricate design of a watch implies the existence of a watchmaker, the complexity and order observed in the universe imply the existence of a cosmic designer, namely God.
However, objections can be raised against Paley's argument:
a. There is no evidence that we can tell the world has a purpose: Critics argue that Paley's argument assumes the existence of purpose in the world without sufficient evidence. They contend that the appearance of design and order could be explained by natural processes rather than the intentional actions of a designer.
b. The universe seems to be more chaotic than ordered: Some objectors argue that the universe appears to exhibit more chaos and randomness rather than the ordered and purposeful design proposed by Paley. They point to natural disasters, genetic mutations, and other seemingly random events as evidence that the universe is not a well-designed system.
c. A watch is a bad analogy for the universe: Critics also challenge Paley's choice of analogy, asserting that a watch is not a suitable comparison for the universe. They argue that the watch is a human-made object with a known designer, whereas the origins and nature of the universe are fundamentally different and require distinct explanations. Furthermore, the watch is a limited and finite object, while the universe is vast and complex, making the analogy insufficient to support the existence of an omnipotent and infinite God.
These objections challenge the validity of Paley's argument by questioning the assumptions, evidence, and analogies he employs to establish a link between the design observed in the universe and the existence of a divine creator.
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How much force is needed to make a 225 kg object accelerate at a rate of 2.5 m/s²
Answer:
562.5
Explanation:
F=ma
225kg * 2.5m/s square
what percent is the percent difference between the newtonian and relativistic kinetic energies of the muon??
The percent difference between the Newtonian and relativistic kinetic energies of the muon is 61.31%. The difference between the Newtonian and relativistic kinetic energies of the muon is given by: (K - K') / K x 100%.
The percent difference between the Newtonian and relativistic kinetic energies of the muon is given below. Let's say that the velocity of the muon is 0.9c, which is 9/10 of the speed of light, where c is the speed of light.
Then the difference between the Newtonian and relativistic kinetic energies of the muon is given by: (K - K') / K x 100% where K is the relativistic kinetic energy of the muon and K' is the Newtonian kinetic energy of the muon.
Substituting the formula for the relativistic kinetic energy of the muon we get,
(K - K') / K x 100% = [(γ - 1) - (1/2)] / (γ - 1) x 100% where γ is the Lorentz factor, given by:
γ = 1/√[1 - (v/c)²]
So, γ = 1/√[1 - (0.9c/c)²]
= 2.2941
Therefore, [(γ - 1) - (1/2)] / (γ - 1) x 100%
= [1.2941 - 1/2] / 1.2941 x 100%
= 61.31%
Therefore, the percent difference between the Newtonian and relativistic kinetic energies of the muon is 61.31%.
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a string that is under 52.0 n of tension has linear density 5.40 g/m. a sinusoidal wave with amplitude 3.40 cm and wavelength 2.10 m travels along the string. What is the maximum velocity of a particle on the string?
The maximum velocity of a particle on the string is approximately 7.62 m/s.
The velocity of a particle in a sinusoidal wave is given by the equation v = ωA, where v is the velocity, ω is the angular frequency, and A is the amplitude of the wave. In this case, the amplitude of the wave is given as 3.40 cm, which is equal to 0.034 m, and the wavelength is given as 2.10 m.
To find the angular frequency ω, we can use the equation ω = 2πf, where f is the frequency of the wave. The frequency can be calculated using the formula f = v/λ, where v is the velocity of the wave and λ is the wavelength.
The tension in the string is given as 52.0 N, and the linear density of the string is given as 5.40 g/m. To find the velocity of the wave (v), we can use the equation v = √(T/μ), where T is the tension and μ is the linear density.
Substituting the given values into the equations, we can calculate the velocity of the wave. Multiplying the velocity by the amplitude of the wave, we can find the maximum velocity of a particle on the string. The result is approximately 7.62 m/s.
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The rate at which the temperature increases with depth is called the geothermal gradient. What is the geothermal gradient in a tectonically stable region where the temperature is 119° C at a depth of 5.0 km?
(Assume a surface rock temperature of 14° C.)
The geothermal gradient in the tectonically stable region is approximately 21°C/km, indicating that the temperature increases by an average of 21 degrees Celsius per kilometer of depth.
To calculate the geothermal gradient, we need to find the rate at which the temperature increases with depth.
Temperature at the surface (T₁) = 14°C
Temperature at a depth of 5.0 km (T₂) = 119°C
Temperature difference = T₂ - T₁ = 119°C - 14°C = 105°C
Depth difference = 5.0 km - 0 km = 5.0 km
Geothermal gradient = Temperature difference / Depth difference
Geothermal gradient = 105°C / 5.0 km
Calculating this expression, we find:
Geothermal gradient ≈ 21°C/km
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How much energy is stored in a room 3.0 m by 4.0 m by 2.4 m due to the earth's magnetic field with a strength of 5.0 × 10-5 T? (
The energy stored in the room due to the Earth's magnetic field is approximately 1.44 × 10^(-4) joules (J).
The energy stored in a magnetic field can be calculated using the formula:
Energy (E) = (1/2) * magnetic permeability (μ) * magnetic field strength (B)^2 * volume (V),
where the magnetic permeability (μ) is a constant.
Given:
Length of the room (l) = 3.0 m
Width of the room (w) = 4.0 m
Height of the room (h) = 2.4 m
Magnetic field strength (B) = 5.0 × 10^(-5) T (tesla)
The volume of the room (V) can be calculated by multiplying the length, width, and height:
V = l * w * h
= 3.0 m * 4.0 m * 2.4 m
= 28.8 m³
The magnetic permeability of free space (μ₀) is approximately 4π × 10^(-7) T·m/A.
Now we can substitute the given values into the energy formula:
E = (1/2) * μ₀ * B^2 * V
= (1/2) * (4π × 10^(-7) T·m/A) * (5.0 × 10^(-5) T)^2 * 28.8 m³
≈ 1.44 × 10^(-4) J
Therefore, the energy stored in the room due to the Earth's magnetic field is approximately 1.44 × 10^(-4) joules (J).
The energy stored in the room with dimensions 3.0 m by 4.0 m by 2.4 m due to the Earth's magnetic field with a strength of 5.0 × 10^(-5) T is approximately 1.44 × 10^(-4) joules (J). This calculation is based on the formula for magnetic energy, incorporating the volume of the room and the magnetic field strength.
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13. Predict whether each of the following will sink or float:
a pencil lead (graphite) in corn syrup
b. acrylic in water
c. polyethylene in water
A hollow conducting sphere has a charge of -1 C on its outer surface and there is a charge of +1 C fixed at the center of the sphere (not touching the sphere itself). All charges remain stationary. What is the net charge on the hollow sphere (not including the +1 C at the sphere's center)?
Please explain why the net charge isn't zero.
The net charge on the hollow conducting sphere, excluding the +1 C charge at its center, is zero. This is because the electric field inside a conductor in electrostatic equilibrium is zero.
When the positive charge of +1 C is fixed at the center of the sphere, it induces a negative charge on the inner surface of the sphere and an equal positive charge on the outer surface of the sphere. This charge distribution on the inner and outer surfaces creates an electric field that cancels out within the conductor.
The electric field inside the hollow conducting sphere is zero due to the redistribution of charges and the fact that the charges on the inner surface exactly neutralize the charges on the outer surface. As a result, the net charge on the hollow sphere, excluding the +1 C charge at its center, is zero.
Therefore, while there is a charge of +1 C fixed at the center of the sphere, the overall net charge on the hollow conducting sphere is zero due to the redistribution of charges on its inner and outer surfaces.
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Classification of living things is necessary
Classification of living things is necessary to organize and understand the immense diversity of life on Earth.
It allows us to systematically categorize organisms based on their shared characteristics, relationships, and evolutionary history. By classifying living things, we can identify patterns, make predictions, and gain insights into the biological world.
Classification provides a framework for scientists to communicate and exchange information effectively. It enables us to develop a common language and reference system for discussing different species and their traits. It also aids in the identification and discovery of new species, facilitating research, conservation efforts, and the development of medical treatments.
Moreover, classification helps us recognize the interconnectedness and interdependence of various organisms within ecosystems. It highlights the evolutionary relationships between species, revealing shared ancestry and evolutionary patterns.
Overall, classification of living things is crucial for scientific understanding, communication, and management of biodiversity, contributing to our knowledge of the natural world and its complex web of life.
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a stone is vertically thrown upward with the velocity of 72km/hr find the maximum height reached the height
Answer:
40m
Explanation:
v^2=gh
h=v^2/g
h=20^2/10
h=400/10
h=40
1 Which photograph of Lange's is a portrait orientation? Which photograph of Lange's is a landscape orientation? Be sure to support your answer with examples from the two photographs you selected.
2 Select one of Lange's photographs. Identify three photographic techniques in the photograph.
3 Create a photograph in the style of Lange's photographs using one of the photographic techniques you identified. Help will give brainliest
I don't know the answer and I also can't copy and paste the pictures so here is the best I can do for people asking what the picture is so they can help other people.
Picture one
Toward Los Angeles, CA
Two mean walking on a road.
Picture Two
Migrant Mother
A middle age mother with two children.
Picture Three
Cortaro Farms, Pinal County, Arizona.
Three trucks with mean working to stack boxes.
Picture Four
Children in Cotton Picker's Camp
Two young children standing by a shack.
Picture Five
Cotton Pickers
A line of cotton pickers carrying sacks of cotton.
Picture Six
At the Cotton Wagon
Cotton pickers loading trucks with the cotton they have picked.
I'm sorry I wasn't that much helpful but I really hope I helped :)
Which photograph of Lange's is a portrait orientation? Which photograph of Lange's is a landscape orientation? Be sure to support your answer with examples from the two photographs you selected. A photograph that is in portrait orientation is Migrant Mother because it is taller than it is wider. A photograph that is in landscape orientation is Cortaro Farms, Pinal County, Arizona because it is longer that it is taller.
Select one of Lange's photographs. Identify three photographic techniques in the photograph. The photograph Toward Los Angeles, CA the photograph uses lines because the road leads into the distance. It also uses the rule of thirds because the people are centered perfectly. It also uses composition because it draws attention to the subjects.
Create a photograph in the style of Lange's photographs using one of the photographic techniques you identified. This photo use composition because it draws attention to the subject.
Suppose that a Ferrari and a Porsche begin a race with a moving start, and each moves with constant speed. One lap of the track is 2 km. The Ferrari laps the Porsche after the Porsche has completed 9 laps. If the speed of the Ferrari had been 10 km/h less, the Porsche would have traveled 18 laps before being overtaken. What were the speeds of the two cars?
Help is for today
Answer:
The speed of the Porsche = 180 km/h
The speed of the Ferrari = 200 km/h
Explanation:
The distance of one lap = 2 km
The distance the Ferrari laps the Porsche = 9 laps
The distance the Ferrari will lap the Porsche with 10 km/h less speed = 18 laps
Let the speed of the Ferrari = S[tex]_F[/tex], the speed of the Porsche = S[tex]_P[/tex], and the time that lapse before two cars lapped = t
we have;
S[tex]_F[/tex] × t₁ - S[tex]_P[/tex] × t = 2 km
S[tex]_P[/tex] × t₁ = 9 laps × 2 km/lap = 18 km
S[tex]_P[/tex] × t₁ = 18 km
S[tex]_F[/tex] × t₁ = 2 km + S[tex]_P[/tex] × t = 2 km + 18 km = 20 km
S[tex]_F[/tex] × t₁ = 20 km
∴
Similarly, we are given that the following relation;
(S[tex]_F[/tex] - 10) × t₂ - S[tex]_P[/tex] × t₂ = 2 km...(2)
From which we have;
S[tex]_P[/tex] × t₂ = 18 laps × 2 km/lap = 36 km
S[tex]_P[/tex] × t₂ = 36 km
(S[tex]_F[/tex] - 10) × t₂ = 2 km + 36 km = 38 km
(S[tex]_F[/tex] - 10) × t₂ = 38 km
Therefore, given that S[tex]_P[/tex] × t₂ (36 km) = 2 × S[tex]_P[/tex] × t₁ (18 km), we have;
S[tex]_P[/tex] × t₂ = 2 × S[tex]_P[/tex] × t₁
t₂ = 2×t₁
Equation (2) becomes;
(S[tex]_F[/tex] - 10) × 2×t₁ - S[tex]_P[/tex] × 2×t₁ = 2 km...(2)
From which we have;
(S[tex]_F[/tex] - 10) × 2×t₁ = 38 km
(S[tex]_F[/tex] - 10) × 2×t₁ = 38 km
2 × t₁ × S[tex]_F[/tex] - 2 × t₁ × 10 = 38 km
∵ S[tex]_F[/tex] × t₁ = 20 km, we have;
2 × 20 km - 2 × t₁ × 10 = 38 km
2 × t₁ × 10 = 2 × 20 km - 38 km = 2 km
20 × t₁ = 2 km
t₁ = 2/20 = 0.1 hour = 6 minutes
Therefore, we have;
S[tex]_P[/tex] × t₁ = 18 km
S[tex]_P[/tex] × 0.1 h = 18 km
S[tex]_P[/tex] = 18 km/0.1 h = 180 km/h
The speed of the Porsche = S[tex]_P[/tex] = 180 km/h
S[tex]_F[/tex] × t₁ = 20 km
S[tex]_F[/tex] × 0.1 h = 20 km
S[tex]_F[/tex] = 20 km/0.1 h = 200 km/h
The speed of the Ferrari = S[tex]_F[/tex] = 200 km/h
The coefficient of friction on a surface is 0.25. A box requires
100 N to slide it across the surface. What is the weight of the box?
Answer:
Explanation:
Let mass of box = m
weight = mg
limiting friction = μ mg , where μ is coefficient of friction
= .25 x m x 9.8 = 2.45 m
According to problem
2.45 m = 100
m = 40.816 kg
weight = 40.816 x 9.8 = 400 N .
if the mass of a physical pendulum is doubled while its length and mass distribution remain unchanged, its period is
The period of a physical pendulum remains unchanged if the mass of a physical pendulum is doubled while its length and mass distribution remain unchanged.
The time period of a physical pendulum is given by
[tex]T = 2π(l/g)1/2[/tex]
Where l is the distance of the center of mass of the pendulum from the pivot point and g is the acceleration due to gravity.
If the mass of the physical pendulum is doubled while its length and mass distribution remain unchanged, then the value of l and g will remain the sameTherefore, the time period T will remain the same. Hence, the period of a physical pendulum remains unchanged if the mass of a physical pendulum is doubled while its length and mass distribution remain unchanged.
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An object beginning with a negative velocity but undergoing a positive acceleration
i need help
i don’t understand how to do this question and i need it to be done by today
The characteristics of Elements include:
made of one type of atomrepresented by symbolscannot be broken downCompounds:
made of two or more types of atomsrepresented by formulascan be chemically broken downHow to explain the informationElements are substances that consist of only one type of atom. This means that all the atoms within an element are the same. Elements are represented by symbols, which are usually derived from their English or Latin names.
Compounds, on the other hand, are substances that are made up of two or more different types of atoms chemically combined together. Unlike elements, compounds have a definite chemical formula that represents the ratio of the atoms present in the compound. These formulas often use the symbols of the elements involved and indicate the number of atoms of each element present in the compound.
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A.) A student collected 100.00g of moist soil from the field. After heated at 105 C overnight, the soil core decrease its weight to 90.00g. What was the moisture content of the field soil? B.) A student collected 150.00g of moist soil from the field, its moisture content was measured as 9.0%. How much water (in grams) was there in the original moist soil sample?
The moisture content of the field soil was 10%. And The amount of water in the original moist soil sample was 13.50g.
A. The initial weight of the moist soil collected from the field was 100.00g, and after heating it at 105°C overnight, the weight decreased to 90.00g.
To find the moisture content, we can calculate the difference in weight before and after heating:
Initial weight - Final weight = Moisture content
100.00g - 90.00g = 10.00g
The moisture content of the field soil is 10%.
B. The moisture content of the moist soil collected from the field was measured as 9.0%.
To find the amount of water in the original sample, we can calculate it as a percentage of the total weight:
Moisture content (%) = (Weight of water / Total weight) x 100
We know that the moisture content is 9.0% and the total weight of the moist soil sample is 150.00g.
Let's assume the weight of water in the sample is 'x' grams.
Using the formula, we can write the equation as:
9.0 = (x / 150.00) x 100
To solve for 'x', we can rearrange the equation:
x = (9.0 x 150.00) / 100
x = 13.50g
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A horizontal spring-mass system has low friction, spring stiffness 200 N/m, and mass 0.3 kg. The system is released with an initial compression of the spring of 9 cm and an initial speed of the mass of 3 m/s.
a. What is the maximum stretch during the motion?
b. What is the maximum speed during the motion?
c. Now suppose that there is energy dissipation of 0.01 J per cycle of the spring-mass system. What is the average power input in watts required to maintain a steady oscillation?
The maximum stretch during the motion of the spring-mass system is 12 cm. The maximum speed achieved during the motion is approximately 2.3 m/s. When considering energy dissipation of 0.01 J per cycle, the average power input required to maintain steady oscillation is approximately 0.003 W.
During the motion of the spring-mass system, the maximum stretch can be determined by considering the conservation of mechanical energy. Initially, the system has potential energy stored in the compressed spring, which is converted into kinetic energy as the mass moves.
At the maximum stretch, all the initial potential energy is converted into kinetic energy. Using the equation for potential energy in a spring, U = (1/2)kx², where k is the spring stiffness and x is the stretch or compression distance, we can solve for x.
Substituting the given values, we have U = (1/2)(200 N/m)(0.09 m)² = 0.81 J. Since all the potential energy is converted into kinetic energy at maximum stretch, the maximum kinetic energy is also 0.81 J. Using the equation for kinetic energy, K = (1/2)mv², where m is the mass and v is the speed, we can solve for v.
Rearranging the equation, we find that v = sqrt(2K/m) = sqrt((2)(0.81 J)/(0.3 kg)) ≈ 2.3 m/s. Therefore, the maximum stretch during the motion is 12 cm, and the maximum speed achieved is approximately 2.3 m/s.
When energy dissipation occurs in the spring-mass system, the average power input required to maintain a steady oscillation can be calculated by considering the energy dissipated per cycle.
Energy dissipation per cycle is given as 0.01 J. Since the system is in steady oscillation, the energy input per cycle must equal the energy dissipated per cycle.
Therefore, the average power input required is the energy dissipated per cycle divided by the time period of one cycle. The time period of the oscillation can be determined using the formula T = 2π(sqrt(m/k)), where T is the time period, m is the mass, and k is the spring stiffness. Substituting the given values, we have T = 2π(sqrt(0.3 kg/200 N/m)) ≈ 1.74 s.
Dividing the energy dissipated per cycle by the time period, we get the average power input as 0.01 J / 1.74 s ≈ 0.003 W. Hence, the average power input required to maintain steady oscillation in the presence of energy dissipation is approximately 0.003 watts.
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consider the following experimentally measured current outputs at different forward bias voltages applied to a si solar cell irradiated with sunlight: v (v) i (a) 0.75 0 0.6 -0.14 0.5 -0.42 0.4 -0.65 0.3 -1.27 0.1 -2.8 (a) at which applied voltage is the power output of the cell maximized? (b) if you use a different solar cell material with a narrower band gap than si (egsi
a) Power output of the cell is maximized at 0.40 V because this is the voltage at which the highest power output (-0.260 W) is obtained ; b) To increase the power output of the solar cell, one approach is to use a material with a narrower bandgap.
(a) To find the voltage at which the power output of the cell is maximized, the power output at each voltage must first be calculated using the formula P=VI.
Here's the table with the calculated power output:
| P(v) | I(A) | P(W) |
|------|-------|--------|
| 0.75 | 0.00 | 0.00 |
| 0.60 | -0.14 | -0.084 |
| 0.50 | -0.42 | -0.210 |
| 0.40 | -0.65 | -0.260 |
| 0.30 | -1.27 | -0.381 |
| 0.10 | -2.80 | -0.280 |
We can see that the power output of the cell is maximized at 0.40 V because this is the voltage at which the highest power output (-0.260 W) is obtained.
(b) The solar cell's power output is proportional to the product of the current and voltage, which is the point at which the power output is maximized.
To increase the power output of the solar cell, one approach is to use a material with a narrower bandgap. The narrow-bandgap solar cell is expected to have a higher open-circuit voltage (Voc), but a lower short-circuit current (Isc) than the silicon solar cell. As a result, the power output may be improved by changing the cell material.
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What is the density of an object when volume is 80cm3 and mass is 40 g? Group of answer choices
i think its dense
Explanation:
an object with 40 is lifted up by 8 meters with a pulley how much force is needed to overcome friction
The force needed to overcome friction of an object lifted up by 8 meters with a pulley with a mass of 40 kg can be calculated using the following equation;`F = m*g*h`
Where F is the main answer and m, g, and h represents the mass of the object, acceleration due to gravity, and the height respectively.:Mass, `m = 40 kg`Height, `h = 8m`
Acceleration due to gravity, `g = 9.8 m/s^2`Force, `F = ?`Using the above-given equation,F = m*g*h= 40 * 9.8 * 8= 3136 NTherefore, the force needed to overcome friction is 3136 N.
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the magnitude of the electrostatic force getween two identical ions that are seperated by a distance of
The electrostatic force between two identical ions that are separated by a distance of 'r' is expressed by Coulomb's Law, F= (1/4πε) * (q1q2/r²)
where F is the electrostatic force q1 and q2 are the charges on the two ionsr is the distance between the centers of the two ionsε is the permittivity of free space The magnitude of the electrostatic force is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.
herefore, q1=q2=q.
Let's substitute this value of q1 and q2 in
Coulomb's Law. F = (1/4πε) * (q*q/r²)
F = q²/ (4πεr²)
Thus, the magnitude of the electrostatic force between two identical ions that are separated by a distance of 'r' is given by
F = q²/ (4πεr²).
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