EXPLAIN HOW MAGNETIC MATERIALS ARE SEPARATED FROM COAL

The density of the liquid in the drum is 459.184 kg/m³.

To find the density of a liquid, we must know its pressure, the depth to which it is filled, and the gravitational acceleration acting on it. Using the equation for pressure at a depth h below the surface of a liquid in a container of height H, P = ρgh, where P is the pressure, ρ is the density, g is the gravitational acceleration, h is the height of the liquid, and H is the height of the container.Let's substitute the given values in the above formula:P = 9000800 Pa; h = 2m; g = 9.8m/s²Therefore, ρ = P/gh = 9000800/(9.8 × 2) ≈ 459184.

This means that the density of the liquid in the drum is 459.184 kg/m³ (kilograms per cubic meter).

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Explanation:

p = k / v

pv = k

12.86 * 2.52  = k =32.4

p *  0.386  = 32.4

p = 83.95  =   84.0  psi      using 3 Sig Digits

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions ([tex]C_H[/tex]+) from pH is:

[tex]C_H[/tex]+ = [tex]10^(^-^p^H^)[/tex]

Substituting pH = 8 into the formula:

[tex]C_H[/tex]+ = [tex]10^(^-^8^))[/tex]

Using the properties of logarithms, we can calculate the concentration of H+ ions:

[tex]C_H[/tex]+ ≈ 1 x [tex]10^(^-^8^))[/tex] mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions ([tex]C_O_H[/tex]-) is also approximately 1 x [tex]10^(^-^8^))[/tex]mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = [tex]C_H[/tex]+ / [tex]C_O_H[/tex]-

Ratio = (1 x [tex]10^(^-^8^))[/tex] / (1 x [tex]10^(^-^8^))[/tex])

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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Explanation:

To calculate the net force on particle q₂, we need to consider the forces exerted on it by the other two particles. The force between two charged particles can be calculated using Coulomb's law:

F = k * (|q₁| * |q₂|) / r²

Where: F is the force between the particles. k is Coulomb's constant, approximately equal to 8.99 × 10^9 N m²/C². |q₁| and |q₂| are the magnitudes of the charges of the particles. r is the separation distance between the particles.

Let's calculate the forces between q₁ and q₂, and between q₂ and q₃:

Force between q₁ and q₂: F₁₂ = k * (|q₁| * |q₂|) / r₁₂²

Given: q₁ = +18.1 μC (microcoulombs) q₂ = -11.2 μC (microcoulombs) r₁₂ = 0.280 m

Calculating the magnitude of F₁₂:

|F₁₂| = (8.99 × 10^9 N m²/C²) * ((18.1 × 10^-6 C) * (11.2 × 10^-6 C)) / (0.280 m)²

|F₁₂| ≈ 1.839 N

The force between q₁ and q₂ is approximately 1.839 N, and since q₁ is positive and q₂ is negative, the force will point to the left (-F₁₂).

Force between q₂ and q₃: F₂₃ = k * (|q₂| * |q₃|) / r₂₃²

Given: q₂ = -11.2 μC (microcoulombs) q₃ = +5.67 μC (microcoulombs) r₂₃ = 0.350 m

Calculating the magnitude of F₂₃:

|F₂₃| = (8.99 × 10^9 N m²/C²) * ((11.2 × 10^-6 C) * (5.67 × 10^-6 C)) / (0.350 m)²

|F₂₃| ≈ 0.512 N

The force between q₂ and q₃ is approximately 0.512 N, and since both q₂ and q₃ are positive, the force will point to the right (+F₂₃).

To calculate the net force on q₂, we need to consider the vector sum of the forces:

Net force = F₁₂ + F₂₃

Net force ≈ -1.839 N + 0.512 N

Net force ≈ -1.327 N

Therefore, the net force on particle q₂ is approximately -1.327 N, pointing to the left.

A. Identity vs role confusion: Mo's uncertainty about post-graduation plans.

B. Integrity vs despair: Mo's questioning of life accomplishments as an older adult.

C. Sensorimotor stage: Mo's development of motor skills and object permanence.

D. Intimacy vs isolation: Mo's struggle with forming relationships.

E. Concrete operational stage: Mo's ability to think logically and understand conservation.

A. The example matches with the Erikson stage of "identity vs role confusion." During this stage, individuals go through a period of exploration and self-discovery to establish a sense of identity and determine their roles and goals in life. Mo's uncertainty about what he wants to do after graduation reflects the challenges and decision-making processes associated with identity formation.

B. The example matches with the Erikson stage of "integrity vs despair." This stage occurs in late adulthood, where individuals reflect on their life choices, accomplishments, and experiences. Mo, as an older adult questioning his accomplishments, is facing the task of finding a sense of integrity and satisfaction with the life they have lived or experiencing feelings of despair and regret.

C. The example matches with the Piaget stage of "sensorimotor stage." This stage occurs in infancy, where children develop coordination and motor skills and begin to understand object permanence, which is the understanding that objects continue to exist even when they are out of sight. Mo's acquisition of motor skills and developing object permanence aligns with the characteristics of the sensorimotor stage.

D. The example matches with the Erikson stage of "intimacy vs isolation." This stage occurs during early adulthood, where individuals seek to form deep and meaningful relationships with others. Mo's struggle with forming a relationship with a significant other reflects the challenges and conflicts associated with the intimacy vs isolation stage.

E. The example matches with the Piaget stage of "concrete operational stage." This stage occurs in middle childhood, where children develop logical thinking and can grasp the concept of conservation. Mo's ability to think logically and understand the law of conservation aligns with the characteristics of the concrete operational stage.

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The statements that accurately describe sound waves are:

2,3,4,6

1. Sound waves require a medium to transfer energy. Unlike electromagnetic waves, such as light, sound waves cannot propagate through a vacuum. They need a material medium, such as air, water, or solids, to transfer their energy.

2. Sound is heard when a vibration strikes the ear. Sound is a mechanical wave that is produced by vibrations or oscillations of objects. When these vibrations reach our ears, they are detected by the auditory system, which allows us to perceive sound.

3. When particles of a medium interact, part of the wave's energy is lost. Sound waves experience energy losses due to factors like friction, absorption, and scattering. As the wave propagates through a medium, some of its energy is converted into other forms, such as heat, resulting in a decrease in the wave's intensity.

4. A wave's energy can be distinguished from other movements of the medium. Sound waves carry energy in the form of vibrations or oscillations of particles within a medium. These movements are distinct from other random or uncorrelated motions of the medium's particles that do not contribute to the propagation of the sound wave.

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Answer:

(a) To solve for the initial speed of the rock at launch, we can use the kinematic equation:

v = v0 + at

Where:

v = final velocity (15m/s)

v0 = initial velocity (what we're solving for)

a = acceleration due to gravity (-9.8m/s^2)

t = time (2.0s)

Plugging in the values, we get:

15m/s = v0 - 9.8m/s^2 (2.0s)

v0 = 34.6m/s

Therefore, the initial speed of the rock at launch was approximately 34.6m/s.

(b) To solve for the speed of the rock 5.0s after launch, we can use the same kinematic equation:

v = v0 + at

But this time, we need to add the additional time and distance that the rock traveled after the initial 2.0s. To do this, we'll use the equation:

d = v0t + 1/2at^2

Where:

d = distance traveled

v0 = initial velocity (34.6m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (5.0s - 2.0s = 3.0s)

Plugging in the values, we get:

d = (34.6m/s)(3.0s) + 1/2(-9.8m/s^2)(3.0s)^2

d = 103.8m - 44.1m

d = 59.7m

So, the rock traveled 59.7m in the additional 3.0s after the initial 2.0s. Now we can find its speed using the kinematic equation:

v = v0 + at

Where:

v0 = final velocity from before (15m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (3.0s)

Plugging in the values, we get:

v = 15m/s - 9.8m/s^2 (3.0s)

v = -12.6m/s

Note that the velocity is negative because the rock is now moving downward. Therefore, the speed of the rock 5.0s after launch is approximately 12.6m/s.