explain how the energy/velocity of water/wind controls the size of the particles in clastic/detrital) rocks

The ability to view living cells in their normal form without first killing, fixing, and staining them is one of the primary advantages of phase contrast microscopy in an interference microscope.

It is possible to view and record the dynamics of current biological processes in great clarity and strong contrast with minuscule specimen detail. Phase contrast and differential interference contrast (DIC) microscopy are complementary methods for obtaining highly contrasted pictures of transparent biological phases that often have no impact on the amplitude of visible light waves flowing through the material.

In both situations, the contrast in the DIC pictures is heavily influenced by the orientation of the specimen, but the characteristics of the phase contrast images are unaffected by the rotation of the specimen around the microscope's optical axis.

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It is to be noted that the total displacement is 0cm. Note that displacement is different from distance traveled.

Displacement is described as the total change in an object's location as well as the direction of motion.

The formula is given as:

Displacement = Final position – initial position = change in position.

Given that the caterpillar falls back to the ground, it means that the total displacement is zero.

Final Position = 0

Initial position = 0

Displacement, thus = 0-0 =0

When distinguishing between displacement and distance, we know that distance is the total length of the path between any two places.

Displacement is defined as the direct length between any two places measured via the shortest path between them.

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The wire must be cut at a length of l/5 along its length so that the resistance of one piece is four times the resistance of other.

The relation between the resistance the resistivity the area and the length of the wire is given by,

R = pl/A

p is resistivity,

A is the area,

l is the length of the wire.

Let us say that the peace of length X is cut from the wire,

So, length of one piece is x and of the other is (l-x)

The resistance of the bigger price has to be four times of the other.

So, we can write,

px/A = 4p(l-x)/A

x = 4l-4x

5x = l

x = l/5.

So, the wire should be cut at a point l/5 from one of the ends of the wire.

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The average rotational latency of a hard drive rotating at 7,200 rpm or 120 revolutions per second is 4.16 ms.

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Bernoulli's equation formula is a relation between pressure, kinetic energy, and gravitational potential energy of a fluid in a container. The formula for Bernoulli's principle is given as follows: p + 1 2 ρ v 2 + ρ g h = c o n s t a n t.

An object's kinetic energy is the energy it has as a result of motion. Applying force is necessary if we want to accelerate an object. We have to put in work to apply a force. After the work is finished, the object will be moving at a new, constant speed because energy has been transferred to it. The science of fluid mechanics examines how fluids—including liquids, gases, blood, and plasma—behave both at rest and while moving. There are numerous uses for fluid mechanics in astrophysics, chemical and mechanical engineering, and biological systems.

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The answer is  2.416 m/s^2.

Solution:

friction force on the upper block = umg

= 0.13*2*9.81

= 2.5506 N

so writing the equation of motion for the upper block

T - f = ma

or T-2.5506 = 2a

writing the equation of motion for the lower block

mg-T=ma

or 9.8-T=a

Hence, we get a  = 2.416 m/s^2.

Since the top block slides to the right, the frictional force acting on it acts to the left. His reaction wall acts on the forward-acting lower block. The frictional force absorbs x mechanical energy from the upper block, but transfers only y mechanical energy to the lower block. To find the acceleration of the body in terms of angle and coefficient of friction.

A material modulus value of 1 means that the friction force is equal to the normal force. This means that the force required to move an object is equal to its weight. An object may have a friction value greater than 1. There are two types of friction coefficients: static friction coefficient and dynamic friction coefficient. The former is sometimes called the initial friction coefficient and the latter is sometimes called the dynamic or sliding friction coefficient.

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Plumb-line method By hanging an item from several places and marking the vertical line with a plumb line, you can empirically determine where an object's center of gravity is located.

The object's center of gravity is where two or more vertical lines converge at a point on the plumb line.

A plumb line is a string that hangs perpendicular to the earth's surface with a large weight attached to it. The center of mass of the object will be traversed by a line drawn parallel to the plumb line. Draw a line along the second plumb line after repeating the process with a different attachment point.

Rub a rope through colored chalk to create a plumb line, then tack it to the top of the wall. Then secure the loose end with a plumb bob (or other tiny weight). Pull the cord taut while maintaining the bob's natural position of falling.

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The time rate of change of the electric field between the

is 1.43x [tex]10^{14}[/tex]N C [tex]s^{1[/tex] .

The  radius is   2.7 cm = 0.027m

The distance of separation is   1.1 mm = 0.0011m

The  current is  7A

Generally the electric field generated is mathematically represented as

            E = [tex]\frac{q}{\pi r^{2}E_{0} }[/tex]

                =

Where [tex]E_{O}[/tex] is the permittivity of free space with a value

   [tex]E_{0} = 8.85\times 10^{-12} m^{-3} kg^{-1} s^{4} A^{2}[/tex]

So the time rate of change of the electric field between the plates is mathematically represented as

[tex]\frac{E}{t} = \frac{q}{t} \times \frac{1}{\pi r^{2} E_{o} }[/tex]

[tex]\frac{q}{t} = I[/tex]

[tex]\frac{E}{t} = \Ifra \times \frac{I}{\pi r^{2} E_{o} }[/tex]

substituting values

[tex]\frac{E}{t} = \Ifra \times \frac{7}{3.142 (0.027)^{2} 8.85\times 10^{-12} }[/tex]

   = 1.43x [tex]10^{14}[/tex]N C [tex]s^{1[/tex]

"Electric charge is a property of a subatomic particle that causes a force when placed in an electric and magnetic field." There are two types of electrical charges: positive and negative, which are usually carried by the charge-carrying protons and electrons.  Examples of charge types are subatomic particles or particles of matter: Protons are positively charged. Electrons are negatively charged. neutrons have zero charge.  Electric charge is a scalar quantity. In addition to magnitude and direction, a quantity called a vector should also obey the laws of vector addition, such as the triangular law of vector addition and the line law of vector addition; only then is the quantity said to be a vector quantity.

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Answer:

Work = 196 Joules (1 kg*m^2/sec^2 is 1 Joule)

Explanation:

Work, W, is defined as force. F, times displacement, d.  

  W = Force*displacement

In the worker's case, the force he/she is struggling against is Earth's gravity's acceleration, g, (9.8 m/sec^2) times the mass, m.

Force = mg

Force = (10kg)*(9.8 m/sec^2) = 98 kg*m/sec^2

Use this force in the work calculation.

W = Force*displacement

The displacement is 2 meters.

Work = (98 kg*m/sec^2)*(2 meters) = 196 kg*m^2/sec^2

1 kg*m^2/sec^2 is 1 Joule

Work = 196 Joules

According to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs

To identify individual conductors in a telecommunications twisted pair cable the 25-pair color code is used. These colours are marked on the conductor's insulation. The primary colours are white, red, black, yellow and violet. The secondary colours are blue, orange, green, brown and slate.

The primary colours are called as tip which is positive and the secondary colours are called as ring which is negative. In the pair only one colour from each group should be used. So the possible combinations are 25 pairs.

Therefore, according to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs

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The number of elements pictured in the above image is 3 (option C).

Element are any one of the simplest chemical substances that cannot be decomposed in a chemical reaction or by any chemical means and made up of atoms all having the same number of protons.

There are about 118 chemical elements, each with its own type of atom. Everything in the universe contains the atoms of at least one or more elements. The periodic table lists all the known elements, grouping together those with similar properties.

According to this question, elements are represented by different colours. Each colour represents each element.

The three colours are as follows:

This means that there are three elements in the above image.

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A cylindrical resistor of radius 4.5 mm and length 2.0 cm is made of material that has a resistivity then current density J is  1.12 × [tex]10^{5}[/tex]

Since P = i^2 r = (J^2) (A^2) R

J = 1/A [tex]\sqrt{P/R}[/tex]

Current density (J)  = 1.12 × [tex]10^{5}[/tex]

A material's electrical resistivity, also known as specific electrical resistance or volume resistivity, is a key characteristic that quantifies how effectively it resists electric current. A substance that permits electric current to flow easily has a low resistance. The Greek letter is often used to signify resistivity (rho). Ohm-meters (m) are the metric unit for electrical resistivity.  For instance, the resistivity of a material is 1 m if it has sheet contacts on two of its opposing faces and has a 1 resistance between them.

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anticlockwise = clockwise (Force*distance)

1 * 20 = 2 * x

x = 10

The energy that powers radio galaxies, quasars, and other active galactic nuclei is thought to be produced by accreting matter onto a supermassive black hole. This process is called active galactic nucleus (AGN) fueling.

The gas that surrounds the black hole is heated to millions of degrees as it falls into the black hole. Because the gas is so hot, it emits a great deal of radiation in many different wavelengths.

This radiation can be seen across the electromagnetic spectrum, from low-energy gamma rays to high-energy X-rays. In some cases, jets of charged particles are ejected at nearly the speed of light along magnetic field lines; these jets can create shock waves in the surrounding medium that emit radio waves.

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Since (r ) equal to A plus Br, the mass per unit area of a circular disc with radius a depends on the distance r from its center.

Mass is obtained by multiplying density by volume.The volume of a disk is equal to its area times thickness, or r2 times thickness.Simply multiply this volume by the disk density, and there you have it!a disk's bulk.

F= 50 N

r= 0.12 m

α = 110 rad/s²

The moment of inertia of disk about center

I= 0.5 m r²

m=mass   , r=radius

The moment of inertia of disk about O

I' = 0.5 m r²+ m r²

I'=1.5 m r²

The torque produce by force F about O

τ = F x 2r

τ =2 F r

= 2 x 50 x 0.12 N.m

τ =12 N.m

We know that

τ = I' α

12 = 1.5 x m x  0.12² x 110

m=2.37 Kg

Mass of the disk m= 2.377 kg

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The force needed to bring a car to rest from a speed is 2,541 Newton.

The formula in non-uniform motion

v = u + at

v² = u² + 2ad

[tex]d = u \times t + \frac{1}{2} \times a \times t^2[/tex]

Because the final speed is km/h, we must convert it into m/s

v = 85.0 km/h

v = [tex]85.0 \times \frac{1 \: km}{1 \: hour}[/tex]

v = [tex]85.0 \times \frac{1,000 \: m}{3,600 \: s}[/tex]

v = [tex]\frac{850}{36}[/tex]

v = 23.6 m/s

Calculate the acceleration

v² = u² + 2ad

23.6² = 0² + (2×a×15)

556.96 = 230a

[tex]a = \frac{556.96}{230}[/tex]

a = 2.42 m/s

Formula to find the force F=ma

F = ma

F = 1,050×2.42

F = 2541 Newton

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The key observation was observing individual Cepheid variable stars in Andromeda and applying the period-luminosity relation.

Edwin Powell Hubble was an American astronomer. He played a crucial role in establishing the fields of extragalactic astronomy and observational cosmology.

In 1924, Edwin Hubble proved that the Andromeda Galaxy lay far beyond the bounds of the Milky Way, thus putting to rest the idea that it might have been a cloud within our own galaxy. This all he has done by observing individual Cepheid variable stars in Andromeda and applying the period-luminosity relation.

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The hottest part of the atmosphere is called the thermosphere.

This region is the hottest because UV rays cause ionization, and because solar radiation is absorbed here, temperature rises with altitude.

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The reading on the scale is 96.31 N.

The Reading Scale describes how people progress through the difficult process of learning to read. It provides teachers with methods for viewing and analyzing their observations of children's developing reading skills, knowledge, and comprehension.

When the elevator stops, its speed decreases from 4 m/s to 0 m/s.

This suggests a slowing down. The amount of force being applied to the

F= mass times acceleration

Assuming the deceleration is constant, we have the following equation:

V = U + at

Where V = Final speed = 0

U = initial speed = 4

a = acceleration

t = time

Solving, we get:

0 = 4 + 2a

a = -2 m/s^2

Solving, we get:

0 = 4 + 2a

a = -2 m/s^2

Thus the object decelerates at 2 m/s^2

The mass of the person = 80 / 9.81 =  8.155 kg

F = 8.155 * 2

F = 16.31 N

Weight in total: 80 + 16.31 = 96.31 N (This is the reading on the scale).

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The sudden cessation of energy generation causes the core to collapse and the star's outer layers to collapse onto the core.

What is core collapse?

Core-collapse supernovae are spectacular explosions that occur at the end of a big star's thermonuclear evolution, giving rise to neutron stars and black holes. They are among the most intense occurrences in the universe, play an important role in the synthesis and distribution of chemical elements, drive the development of new stars, and are closely tied to an enigmatic subclass of gamma-ray bursts. As a result, astro-physicists are keen to learn which stars burst as supernovae, what physical mechanisms produce the explosion, and what observable effects result from these cataclysmic events.

When the explosion wave generated in the optically obscured stellar centre eventually reaches the surface layers of the star, the visual supernova outburst begins.

The fire ceases because iron does not work as a fuel. The sudden cessation of energy output leads the core to collapse and the star's outer layers to collapse onto the core. The infalling layers compress so quickly that they 'bounce' off the iron core at near-lightspeed.

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It is accurate to say that the Mercalli, Richter, and magnitude scales are the three main scales used to measure earthquakes. These three scales were used to gauge the earthquake's seismic waves.

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The direction of net force at all points in the projectile's path is downwards towards the ground.

F = m a

F = Force

m = Mass

a = Acceleration

F ∝ a

The direction of net force is influenced by the direction of acceleration.

In a projectile motion, if the air resistance is considered negligible, there will be no acceleration in horizontal direction. Because, there will be no forces acting in horizontal direction. The only force acting on the projectile is the force of gravity. Gravity pulls the object downwards throughout its motion. So the direction of net force will be downwards at all points in the projectile's path.

Therefore, the direction of net force at all points in the projectile's path is downwards towards the ground.

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The flow rate and the volume that passes through the artery in a period of 20 s is Q= 4.1448cm³/s and V= 82.896cm³.

We must define both the volume V and the instant in time it is flowing past represented by t in order to determine the Flow Rate denoted by Q, which is equal to V/t. In addition, the relationship between flow rate and velocity can be seen in the equation Q = Av, where A is the flow's cross-sectional area and v is its average velocity.

We must utilize the equation Q=V x A, where Q is the flow rate, V is the velocity, and A is the area, to determine the flow rate.

We must apply this formula to determine the volume. V = Q x t, where Q is the flow rate, t is the time, and V is the volume.

Converting 2mm to cm is the first thing we must accomplish.

2mm x 0.1= 0.2 cm

Currently, we utilize the calculation Q=V x A, but we must keep in mind that the area of an artery is circular, therefore we swap out A with the formula π r2.

Q= 33 cm/s x 3,14x (0.2cm)²

Q= 33cm/s x 0.1256cm²/s

Q= 4.1448cm³/s.

There is a flow at 4.1448cm³/s.

Now, using the flow rate (Q), we may

V=  4.1448 cm³/s x 20s

V= 82.896cm³.

82.896cm3 of fluid travels through the artery every 20 seconds.

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The speed of each wave is identical. The only factor that affects how fast sound travels is the property of the medium.

An example of an energy type that propagates through a medium using adiabatic loading and unloading is acoustic waves. Acoustic pressure, particle velocity, particle displacement, and acoustic intensity are crucial parameters for defining acoustic waves. Because the air molecules oscillate back and forth as the sound travels, we refer to sound as a wave. The way the air behaves is similar to a compression or longitudinal wave on a spring.

A sound wave is a pressure wave, which can be conceptualized as variations in pressure over time. Transverse waves include sound waves. The tines of a tuning fork must transfer air from the fork to one's ear in order for one to hear the sound of the fork.

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Answer:

50 m/s

Explanation:

Half of its Potential Energy (mgh) will have been converted to Kinetic Energy  ( 1/2 mv^2)

1/2 mgh = 1/2 mv^2

gh = v^2

10(250) = v ^2      v = 50 m/s

The velocity of the stone halfway through the fall will be approximately 50.0 m/s.

To calculate the velocity of the stone halfway through its fall, we can use the kinematic equation for free fall

v² = u² + 2as

Where:

v is the final velocity,

u is the initial velocity,

a is the acceleration due to gravity (g),

and s is the distance fallen.

Given that the stone falls freely, the initial velocity u is 0 since it starts from rest.

The distance fallen halfway through the fall can be calculated by dividing the total distance fallen by 2.

s = 250.0 m / 2 = 125.0 m

Plugging these values into equation, now we solve for v:

v² = 0² + 2 × 10.0 m/s² × 125.0 m

v² = 0 + 2500 m²/s²

Taking the square root of both sides to find v:

v ≈ √2500 m²/s²

v ≈ 50.0 m/s

Therefore, the velocity of the stone halfway through the fall is approximately 50.0 m/s.

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The frictional force applied on the object if a horizontal force of 50N is applied on the object is 19.6 N

N = m g

N = Normal force

m = Mass

g = Acceleration dur to gravity

m = 10 kg

g = 9.8 m / s²

N = 10 * 9.8

N = 98 N

f = μ N

f = Frictional force

μ = Co-efficient of friction

For static friction,

μ = 0.4

f = 0.4 * 98

f = 39.2 N

For kinetic friction,

μ = 0.2

f = 0.2 * 98

f = 19.6 N

Since Applied force of 50 N is greater than the static frictional force of 39.2 N, the frictional force acting on the object is frictional force.

Therefore, the frictional force applied on the object is 19.6 N

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Answer:

Explanation:

Work:

A = m·g·h = 32·9.8·0.1 = 31.36 L

Power:

N = A / t = 31.36 / 0.83 ≈ 38 W

Answer:The correct statement regarding single convicts made A is false if we don't choose the correct statement. Okay, which is not true. The image is always a virtual coma, erect and small in size, for the single mirror. Real objects regardless of traditions are small. Is it okay? The enemy's position needs to be smaller than the object position if the image is virtual erect. The third option will become the false statement that it will be the answer and the fourth option will give us a virtual object that will give us a real image. We can use a virtual object to give us a real image. It is a real image. The answer to the problem is the option three. Thank you for taking the time to thank me.

Explanation:

If a block of material has a mass of 16 grams and a volume of 8 cubic centimeters, then density is 2 grams per cubic centimeter.

Density = mass / volume

Density = 16/8 = 2 grams per cubic centimeter.

The substance's mass per unit of volume is its density (also known as specific mass or volumetric mass density). The Latin letter D can also be used to represent density, however the most common symbol is (the lower case Greek letter rho). According to mathematics, density is determined by dividing mass by volume, where denotes the density, m denotes the mass, and V denotes the volume. Although it is incorrect scientifically - this amount is more precisely known as specific weight – in some circumstances (for example, in the US oil and gas business), density is roughly described as its weight per unit volume.

Density and mass concentration have the same numerical value for a pure substance. Varied materials often have different densities, therefore purity and buoyancy may both be affected by density.

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A network of metal wires that allows the simultaneous transport of several bits of data Serial cables, which transport data one bit at a time, have mostly replaced parallel wires.

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