Answer:
Newton's laws of motion describe the relationship between the motion of an object and the forces acting on it. These laws can be applied to the concepts of displacement, velocity, and acceleration as follows:
-First Law: The law of inertia
This law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. This law implies that if there is no net force acting on an object, the object will remain at rest or in uniform motion in a straight line. In terms of displacement, this law means that an object's displacement will not change unless acted upon by an external force. In terms of velocity, an object's velocity will remain constant unless acted upon by an external force. In terms of acceleration, an object's acceleration will be zero unless acted upon by an external force.
-Second Law: The law of force and acceleration
This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In terms of displacement, this law means that the displacement of an object is directly proportional to the force acting on it. In terms of velocity, this law means that the change in velocity of an object is directly proportional to the force acting on it. In terms of acceleration, this law means that the acceleration of an object is directly proportional to the force acting on it and inversely proportional to its mass.
-Third Law: The law of action and reaction
This law states that for every action, there is an equal and opposite reaction. In terms of displacement, this law means that if an object exerts a force on another object, the other object will exert an equal and opposite force on the first object, resulting in a displacement. In terms of velocity, this law means that if an object exerts a force on another object, the other object will exert an equal and opposite force on the first object, resulting in a change in velocity. In terms of acceleration, this law means that if an object exerts a force on another object, the other object will exert an equal and opposite force on the first object, resulting in a change in acceleration.
In summary, Newton's laws of motion have numerous applications to the concepts of displacement, velocity, and acceleration. These laws can help us understand how objects move and how they respond to external forces. They are essential for fields such as physics, engineering, and astronomy, where the motion of objects is of critical importance.
Explanation:
Newton’s First Law of Motion
“An object at rest will stay at rest, and an object in motion will stay in motion unless acted on by a net external force"
This means that motion cannot change or decrease without the effect of an unbalanced force. If nothing happens to you, you will never go anywhere. If you’re going in a certain direction, unless something happens to you, you’ll always go that way forever.
That is, if the resultant force (the vector sum of the forces acting on the body) is zero, then the velocity of the object is constant. When we say that the velocity of an object is constant, we mean that both magnitude and direction are constant.
Examples
The electric fan continues to move for a period after the electricity is turned off.
Fall back forward when the stationary bus starts to move.
Newton’s Second Law of Motion
“If a force affects an object, the object gains acceleration, proportional to its strength and inversely proportional to its mass.”
Newton’s second law studies the movement of an object when external forces affect it. When a constant force affects a huge object, it causes it to accelerate, that is, to change its speed, at a constant rate.
In the simplest case, the force acting on an object at rest causes it to accelerate in the direction of the force. However, if the object is indeed in motion it may appear that the object is speeding up, slowing down, or changing its direction depending on the direction of force, directions taken by the object, and the frame of reference in which it is moving Relative to each other.
This relationship applies the principle of preserving the momentum, which is that when the sum of the resultant forces acting on the object is equal to zero, the momentum of the object remains constant. The resultant force is equal to the rate of change in the momentum.
This law also means that when two equal forces act on two different bodies, the object with greater mass will have less acceleration and slower motion, and the object with less mass has greater acceleration. For example, to illustrate:
If we have two similar engines, one for a large car and the other for a small car, then the small one will have more acceleration because its mass is less and the large one will have less acceleration because its mass is greater.
Newton’s Third Law of Motion
“For every action, there is an equal and opposite reaction.”
All forces in the universe occur in equal but oppositely directed pairs. There are no isolated forces; for every external force that acts on an object there is a force of equal magnitude but opposite direction which acts back on the object which exerted that external force.
In the case of internal forces, a force on one part of a system will be countered by a reaction force on another part of the system so that an isolated system cannot by any means exert a net force on the system as a whole. A system cannot “bootstrap” itself into motion with purely internal forces, to achieve a net force and an acceleration, it must interact with an object external to itself.
Engineers apply Newton’s third law when designing rockets and other devices, for example, the rush of gases from the rocket to the top when it ignites causes it to increase its speed.
When a person walks it affects the earth strongly and the earth also strongly affects it so both the earth and the person affect each other.
When you jump, your feet apply force to the ground, and the earth applies an equal and opposite reaction force that pushes you into the air.
When a person is in water, the water pushes the person forward while the person pushes the water back, both affect each other.
consider the following scenario: you are on the beach using a metal detector and you find a metal object with a mass of 34.9. mg. you go home and determine the density of the object to be 23.5 cg/m^3. what is the volume in liters of the object? report the final answer using the correct number of significant figures. do not put units and do not write your answer in scientific notation.
The volume of the metal object is [tex]148.5 L[/tex].
It is given that,
The mass of the metal object is [tex]m=34.9 mg[/tex].
The density of the metal object is [tex]\rho=23.5 cg/m^3[/tex].
It is known that, [tex]1cg=10 mg[/tex].
So, the density of the metal object, [tex]\rho=(23.5\times10)mg/m^3=235mg/m^3[/tex].
Let us assume that, the volume of the metal object is [tex]V[/tex].
Now, density, [tex]\rho=\frac{m}{V}[/tex]
[tex]\Rightarrow V=\frac{m}{\rho}[/tex]
[tex]\Rightarrow V=\frac{34.9 mg}{235 mg/m^3}[/tex]
[tex]\Rightarrow V=0.1485m^3[/tex]
It is known that, [tex]1m^3=1000L[/tex].
So, volume [tex]V=(0.1485\times1000)L[/tex]
[tex]\Rightarrow V=148.5 L[/tex]
Hence, the volume of the metal object is [tex]148.5 L[/tex].
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how to calculate the maximum height of a projectile given its original position and initial velocity only up and down
The maximum height of a projectile given its original position and initial velocity is, h = (v^2)/(2g).
Maximum height of a projectile given its original position and initial velocity in the vertical direction,
h = (v^2*sin^2(theta))/(2g)
where v is the initial velocity in the vertical direction, theta is the angle of the initial velocity and g is the acceleration due to gravity.
If the projectile is launched straight up, then theta = 90 degrees,
h = (v^2)/(2g)
To use this formula, you need to know the value of v, the initial velocity of the projectile in the vertical direction. This can be found by analyzing the initial conditions of the problem or by measuring the initial velocity directly.
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: if you know the length, width, and mass of the boat as well as the density of the liquid, how would you calculate how far the boat sinks into the liquid?
The formula to calculate how far the boat sinks into the liquid is:
Depth = (Weight of the boat - Buoyant force) / (Length x Width of the submerged part of the boat)
To calculate how far a boat sinks into a liquid, we need to take into account the weight of the boat and the buoyant force of the liquid acting on the boat. The buoyant force is equal to the weight of the liquid displaced by the boat, which depends on the volume of the boat submerged in the liquid. We can use the following steps to calculate how far the boat sinks into the liquid:
Calculate the volume of the boat that is submerged in the liquid. This can be done by multiplying the length, width, and depth of the submerged part of the boat.Calculate the weight of the boat. This can be done by multiplying the mass of the boat by the acceleration due to gravity.Calculate the buoyant force acting on the boat. This can be done by multiplying the density of the liquid by the volume of the boat submerged in the liquid and by the acceleration due to gravity.Calculate the difference between the weight of the boat and the buoyant force acting on the boat. If the weight of the boat is greater than the buoyant force, the boat will sink into the liquid until the two forces are equal. If the buoyant force is greater than the weight of the boat, the boat will float on the surface of the liquid.Divide the difference between the weight of the boat and the buoyant force by the product of the length and width of the submerged part of the boat to get the depth to which the boat sinks into the liquid.So, the formula to calculate how far the boat sinks into the liquid is:
Depth = (Weight of the boat - Buoyant force) / (Length x Width of the submerged part of the boat)
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you measure the masses of five bricks to be: {3.5 kg, 3.2 kg, 3.8 kg, 3.4 kg, 5.5 kg}. what is the mean and standard deviation?
The mean and the standard deviation of the five measurements are 3.33kg and 1.038 kg respectively.
What is standard deviation?Standard deviation is a measure of the spread or dispersion of a set of data values. It is calculated by taking the square root of the variance, which is the average of the squared differences from the mean. It measures how much variation or dispersion from the average exists in the data set. A higher standard deviation indicates that the data points are spread out over a larger range of values, while a low standard deviation indicates that the data points are clustered closely around the average. Standard deviation is a commonly used measure in statistics and is used to compare the variability of different data sets.
To find the mean and standard deviation of these five measurements, use the following formulas:
Mean = (sum of all measurements) / (number of measurements)
Standard deviation = sqrt((sum of squared differences from the mean) / (number of measurements - 1))
First, find the mean:
Mean = (3.5 + 3.2 + 3.8 + 3.4 + 5.5) / 5 = 3.88 kg
So the mean mass of the five bricks is 3.88 kg.
Next, we can find the standard deviation:
Calculate the differences from the mean for each measurement:
-0.38, -0.68, 0.92, -0.48, 1.62
Square each difference:
0.1444, 0.4624, 0.8464, 0.2304, 2.6244
Add up the squared differences:
4.308
Divide the sum by the number of measurements minus one:
4.308 / (5-1) = 1.077
Take the square root of the result:
sqrt(1.077) = 1.038
So the standard deviation of the five measurements is 1.038 kg.
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based on the first law of thermodynamics, select all of the following that apply to energy. multiple select question. energy can be destroyed. energy can be transformed. energy can be transferred. energy can be created.
According to the first law of thermodynamics, energy can be changed and transmitted, as well as the following.
What is subject to the first law of thermodynamics?The first law of thermodynamics establishes a relationship between the different types of kinetic and potential energy present in a system and the work that can be done by it as well as the transmission of heat. This law provides an extra state variable, enthalpy, and is occasionally used as the definition of internal energy.
How does the energy described by the first law of thermodynamics change?The universe's energy is constant, according to the first law of thermodynamics. It cannot be created or destroyed, but it can be exchanged between the system and its surroundings.
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A 100g mass is swung around a tube 50 times in 1 minute calculate the centripetal force necessary to sustain this motion
The centripetal force of the object with a mass of about 100g will be 31.42 Newtons.
What is Centripetal force?A centripetal force is a net force which acts on an object to keep it in the state of motion along a circular path.
The angular velocity is defined as "the angle changing over time."
From the given of the problem:
m = 100g
rate of revolution = 50 rev / min
Therefore, using the formula:
angular velocity = rate of revolution x 2*pi / revolution
Angular velocity = (50 revs / min) x (2*pi radians / rev) = 100*pi radians / min
Centripetal force = mass × angular velocity
Centripetal force = 0.1 × 100π
Centripetal force = 31.42 Newtons
Therefore, the centripetal force will be 31.42 Newtons.
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Find the time for a pulse of laser light to reach the Moon and to bounce back to Earth Express your answer to two significant figures and include the appropriate units
The time for a pulse of laser light to reach the Moon and to bounce back to Earth is 2.6 s.
What is a laser light?
A laser light is a light produced by a laser, which is a device that amplifies and emits light by the process of stimulated emission. Laser light is highly directional and has a narrow beam, making it useful for many applications such as cutting, drilling, and welding. It can also be used to measure distances, scan barcodes, and measure speed. Laser light has a high intensity and is monochromatic, meaning it contains a single wavelength of light.
The speed of light is approximately 3.0 x 10^8 meters/second. The distance from the Earth to the Moon is approximately 3.8 x 10^8 meters. Therefore, the time for a pulse of laser light to reach the Moon is approximately 1.3 seconds, and the time for the light to bounce back to Earth is also approximately 1.3 seconds. The total time for the pulse of laser light to reach the Moon and to bounce back to Earth is 2.6 s, to two significant figures.
Therefore, the time for a pulse of laser light to reach the Moon and to bounce back to Earth is 2.6 s.
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It will take around 2.5 seconds for a pulse of laser light to reach the moon and bounce back to Earth.
What is Light?
Electromagnetic energy that can be seen by the human eye is known as light or visible light. [1] Typically, visible light is described as having wavelengths between 400 and 700 nanometers (nm), or frequencies between 750 and 420 terahertz, which fall between the longer-wavelength infrared and the shorter-wavelength ultraviolet (with shorter wavelengths).
There are 380,500 kilometres on average between the surface of the moon and the earth (km). In a vacuum, light, which is an electromagnetic wave, moves at a pace of about 3 x 108 m/s. The time it takes for a laser pulse to move from the earth to the moon is time = distance/speed because distance = speed*time. Round-trip duration is equal to 2*(distance/speed). Thus, time=2*(38500 x 103 m / 3 x 108 m/s) = 2.56 s is the result of the computation.
Therefore, A pulse of laser light will take around 2.5 seconds to reach the moon and bounce back to Earth.
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what is the magnitude of the force caused by air resistance, fr in newtons? (maintain the assumption that the truck's velocity is constant.)
The same as long as the other variables in the equation (Cd, A, and rho) remain unchanged.
What is variables?A variable is a symbolic name that represents a value that can be changed. Variables are used in programming to store values that can be used throughout the program or in specific functions. Variables can be any type of data including numbers, strings, Booleans, and objects.
The magnitude of the force caused by air resistance, fr, in Newtons is determined by the drag equation: fr = 0.5*Cd*A*rho*v^2, where Cd is the drag coefficient, A is the frontal area, rho is the density of the air, and v is the velocity. Since the truck's velocity is assumed to be constant, the magnitude of the force caused by air resistance (fr) will remain the same as long as the other variables in the equation (Cd, A, and rho) remain unchanged.
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The dependence of the rate constant on temperature is expressed by which equation The Arrhenius equation. The de Broglie equation. The van't Hoff equation. Temperature has no effect on the rate constant.
The dependence of the rate constant on temperature is expressed by the Arrhenius equation.
What is Arrhenius equation?The Arrhenius equation is an equation that is used to describe the relationship between the reaction rate of a chemical reaction and the temperature at which the reaction takes place. The equation states that the reaction rate is equal to the frequency factor (A) multiplied by the product of the Boltzmann constant (k) and the temperature (T) raised to the power of the activation energy (E): rate = A * kT^E.
Therefore, The dependence of the rate constant on temperature is expressed by the Arrhenius equation.
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as an example, a 3.90- kg aluminum ball has an apparent mass of 2.50 kg when submerged in a particular liquid: calculate the density of the liquid.
The density of the liquid in which the aluminum ball was submerged is found to be 2.7g/cm³.
When submerged in a certain liquid, a 3.90 kilogram aluminum metal ball has an apparent mass of 2.50 kg.
Aluminum has a density of 2.7gm/cm3.
We already know that 3.9 kg = 3900gm density = mass/volume
2.7 = 3900/volume
volume = 3900/2.7 cm³
We also know that the volume of liquid displaced Equals the volume of the ball,
The mass of liquid exhibited = the apparent weight of the Al ball = 2.5 kg = 2500 gm, and
Density of liquid = 2500/(3900/2.7)
= 2.7 gm/cm³
As a result, the density of the liquid is 2.7 gm/cm3.
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If a 240 volt voltage source is connected to a wire with 10
ohms of resistance, what is the current?
If a 240 volt voltage source is connected to a wire with 10 ohms of resistance, then the current is 24 amp.
Given data as per the question is:
Voltage given - 240 V
Resistance = 10 ohm
The formula to be used in such numerical is,
V=IR --------------------- (A)
where V in the equation is the voltage, I in the equation is the current and R in the equation is the resistance.
Substituting the values in the equation (A)
240=I(10)
I= 240/10 = 24 amp
The current is 24 amp.
The formula V=IR is the ohm's law. The current which is flowing through the wire is directly proportional to the potential difference applied across its ends of it ,provided that the temperature and all the other physical conditions of the wire like stresses and strains remains absolutly constant.
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What strength electric field is needed if the electron is to emerge from an exit hole 1. 0 cm away from the entrance hole, traveling at right angles to its original direction? hint: the difficulty of this problem depends on how you choose your coordinate system
The strength of the electric field needed if the electron is to emerge from an exit hole 1. 0 cm away from the entrance hole, travelling at right angles to its original direction is [tex]\frac{-K}{(q(.01*cos45))} = E[/tex].
The electric field needs to bring vertical velocity to zero and horizontal velocity to what the vertical velocity was. We need to find what E-field is required to bring the vertical velocity to zero without having to worry about the horizontal velocity, I think.
Vi = [tex]\frac{(2\frac{K}{m} )1}{2 }[/tex]
d = 0.01*cos45
0 = [tex](\frac{2K}{m} )+2a*.01*cos45[/tex]
[tex]\frac{-K}{(m(.01*cos45)) } =a[/tex]
Now finding acceleration in terms of E
qE=ma
[tex]q\frac{E}{m} = a[/tex]
Combining them:
[tex]\frac{-K}{(m(.01*cos45))}[/tex]= [tex]q\frac{E}{m}[/tex]
[tex]\frac{-K}{(q(.01*cos45))}[/tex]=E
Therefore, when we go through this we get 17655 [tex]\frac{N}{C}[/tex], which seems close (right order of magnitude).
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The correct question is:
A problem of practical interest is to make a beam of electrons turn a 90∘ corner. This can be done with the parallel-plate capacitor shown in the figure (Figure 1). An electron with kinetic energy 2.0×10−17 J enters through a small hole in the bottom plate of the capacitor. What strength electric field is needed if the electron is to emerge from an exit hole 1.0 cm away from the entrance hole, travelling at right angles to its original direction?
which of the following actions does not affect the value of the capacitance of a parallel plate capacitor? multiple select question. halving the distance between the plates and sliding one plate such that the overlap between the plates is halved doubling the voltage difference between the plates and doubling the distance between them doubling the area of each plate and doubling the distance between them doubling the area of one of the plates while keeping the distance between them the same doubling the charge on each of the plates
The actions which does not affect the value of the capacitance of a parallel plate capacitor is doubling the voltage difference between the plates and doubling the distance between them.
A capacitor is a two-terminal electrical device that can store energy in the form of an electric charge. It consists of two electrical operators that are separated by a distance. The space between the operators may be filled by vacuum or with an separating material known as a dielectric. The capability of the capacitor to store charges is known as capacitance.
Capacitors store energy by holding piecemeal dyads of contrary charges. The simplest design for a capacitor is a resemblant plate, which consists of two essence plates with a gap between them. But, different types of capacitors are manufactured in numerous forms, styles, lengths, circumferences, and accoutrements .
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A traffic signal is supported by two cables, each of which makes an angle of 40. 0° with the vertical. If
each cable can exert a maximum force of 7. 50 × 102 N, what is the largest weight they can support?
the maximum weight that the cables can support is = 12.75 × 102 N.
The maximum force exerted by each of the two cables is 7.50 × 102 N. The maximum weight that the cables can support is the sum of the forces exerted by the two cables, which is 7.50 × 102 N + 7.50 × 102 N = 15.00 × 102 N.
To calculate the maximum weight, we can use the following equation:
Weight = Force × Sin (Angle)
Therefore, the maximum weight that the cables can support is 15.00 × 102 N × Sin (40°) = 12.75 × 102 N.
What is weight?
Weight is a measure of the force of gravity acting on an object. It is measured in units of mass such as kilograms, pounds, or ounces. Weight is a property of matter, meaning that it is always present in any object with mass, regardless of whether it is at rest or in motion.
Therefore, the maximum weight that the cables can support is = 12.75 × 102 N.
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An object has 10 J of GPR.What would be its GPE if its mass was halved?
If the mass of the object is halved, its new GPE would be 5 J. The gravitational potential energy (GPE) of an object near the surface of the Earth is given by the formula:
GPE = mgh
where:
m is the mass of the object
g is the acceleration due to gravity (9.81 m/s² near the surface of the Earth)
h is the height of the object above some reference level (usually taken to be the ground level)
The given information of the object having 10 J of gravitational potential energy (GPE) is insufficient to calculate its mass or height. As a result, we cannot use the above formula to calculate the object's GPE if its mass is halved.
However, we can take advantage of the fact that an object's GPE is directly proportional to its mass. That is, if we cut the object's mass in half, its GPE will be cut in half as well. This is mathematically expressed as:
GPE2 = (1/2) GPE1
where:
GPE1 is the object's first GPE.
GPE2 is the object's new GPE after its mass has been halved.
As a result, if the object's GPR is considered its initial GPE and its mass is halved, its new GPE is:
GPE2 = (1/2) GPR
Substituting the given value of GPR = 10 J, we get:
GPE2 = (1/2) x 10 J = 5 J
So, if the mass of the object is halved, its new GPE would be 5 J.
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If a meteor with a 20 m in diameter impacts Earth on land, approximately how big will the crater be?A. 200-400 m in diameterB. 500 to 1100 m in diameterC. 1000 to 1200 m in diameterD. 1300 to 1500 m in diameter
"If a meteor with a 20 m in diameter impacts Earth on land, approximately the crater is 200-400 m in diameter." Correct option is A.
A meteor is a small rock or piece of debris that travels through space and enters the Earth's atmosphere. When a meteor enters the Earth's atmosphere, it encounters friction and heat due to the atmospheric resistance, causing it to ignite and create a bright trail or shooting star in the sky. If a meteor is able to reach the surface of the Earth, it is called a meteorite.
When a meteor strikes a planet, there will almost certainly be a hole made at the site of impact. As the item moves more quickly, gets bigger, or is heavier, the crater will grow bigger. The meteor's mass and velocity are the best indicators of the magnitude of the impact crater.
The size of the crater created by a meteorite impact depends on many factors, such as the composition of the meteorite and the density of the material that it impacts. A crater with a dimension of 200–400 metres would be produced by a meteorite with a 20 m diameter.
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at what values of theta is the vertical component ay of the acceleration vector greatest in magnitude
The values of theta is the vertical component ay of the acceleration vector greatest in magnitude at 90° and 270°.
Multidimensional stir with constant acceleration can be treated the same way as shown in the former chapter for one- dimensional stir. before we showed that three- dimensional stir is original to three one- dimensional movements, each along an axis vertical to the others.
To develop the applicable equations in each direction, let’s consider the two- dimensional problem of a flyspeck moving in the xy aeroplane with constant acceleration, ignoring the z- element for the moment.
Thinking of circles as parametric equations:
ry=sinθ
rx=cosθ
Note that I have limited θ: 0° <=θ < 360°
Also note that the greatest magnitude of sine and cosine functions is1.
This problem is based only on the y-component, so just consider ry=sinθ.
It hast he greatest magnitude (vertical distance from the center) at90° (and 270°).
Takethe derivative for velocity.
vy=cosθ
It has the greatest magnitudes at 0° and 180°.
Take the derivative for acceleration
ay=-sinθ
It has the greatest magnitudes at 90° and 270°
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Complete question:
At what value(s) of is the vertical component ay of the acceleration vector greatest in magnitude? (Several choices may be correct.) 0° 90° 180° 270°
if the mass of the compact car is 1200 kg, what force is needed to make it accelerate to 20 m/s2? show your calculations.
how does gravity affect braking distance when driving downhill?
You may need to downshift or apply the brakes in order to slow down to a safe pace and keep control of your vehicle. When a car is left parked on an incline, gravity aids in pulling the vehicle downward.
What does the gravity affect braking distance?Gravity helps you stop when you are moving uphill and shortens the braking distance. Similar to when you are ascending, gravity works against you and lengthens your braking distance.
The frictional resistance between the road and your Tyres can also affect how far you have to brake.
The longer an object is in free fall, the faster it descends towards the ground due to gravity. In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall.
Therefore, the opposite is true when travelling at a downward angle. Gravity will make you move more quickly and with a greater stopping distance.
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consider two cars moving along the same straight road in opposite directions. car a has a mass of 500kg 500 k g and has a constant speed of 20m/s 20 m / s ; car b has a mass of 800kg 800 k g and a constant speed of 15m/s 15 m / s . what can you say about the net forces on the cars?
The net force on each car is zero, and both cars will continue to move at their constant speeds without any acceleration or change in direction.
According to Newton's third law of motion, every action has an equal and opposite reaction.
Let's calculate the magnitude of the force exerted by car A on car B and vice versa:
The force (F) is given by the formula:
[tex]F = m * a[/tex]
where m is the mass of the car and a is the acceleration it experiences.
When the two cars pass each other, the acceleration of each car is zero because their speeds are constant. Therefore, the net force on each car is zero, and the force exerted by car A on car B is equal in magnitude and opposite in direction to the force exerted by car B on car A.
The force exerted by car A on car B is:
[tex]F_{AB} = m_A * a_A[/tex]
where [tex]m_A = 500 kg[/tex] and [tex]a_A = 0 m/s^2[/tex] (constant speed)
[tex]F_{AB} = 500 kg * 0 m/s^2 = 0 N[/tex]
Similarly, the force exerted by car B on car A is:
[tex]F_{BA} = m_B *a_B[/tex]
where [tex]m_B = 800 kg[/tex] and [tex]a_B = 0 m/s^2[/tex] (constant speed)
[tex]F_{BA} = 800 kg * 0 m/s^2 = 0 N[/tex]
As we can see, both forces are zero. Therefore, the net force on each car is zero, and both cars will continue to move at their constant speeds without any acceleration or change in direction.
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What is the kinetic energy of a penguin with a mass of 8 kg that is running at a speed
of 3 m/s?
Answer:
Answer is in the attached photo.
Explanation:
SolutionThe solution is in the attached photo, do take note in order to solve this question, we have to use the formula for Kinetic Energy:
K.E = [tex]\frac{1}{2} mv^{2}[/tex]
The kinetic energy of the penguin with an 8 kg mass and a speed of 3 m/s, is 36 joules.
Explanation:The formula of kinetic energy is:
Ec = m * v²/2Where
Ec = Kinetic Energym = massV = speedWhat is the kinetic energy of a penguin with a mass of 8 kg that is running at a speed of 3 m/s?
Data:
Ec = ?
m = 8 kg
V = 3 m/s
As in the statement asks us to calculate the energy, we must not perform the formula clearance. We replace data and solve.
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{Ec=\frac{m\times v^2}{2} \iff \ Ec=\frac{8 \ kg\times\left(3 \ \dfrac{m}{s}\right) }{2} } \end{gathered}$} }[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=\frac{8 \ kg\times9 \ \dfrac{m^2}{s^2} }{2} } \end{gathered}$} }[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=\frac{72 \ kg\times \ \dfrac{m^2}{s^2} }{2} } \end{gathered}$} }[/tex]
We break down the units of m^2 = m * m.
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=36 \ kg\times \ \frac{\not{m^2}}{s^2} \to \ m\times m } \end{gathered}$} }[/tex]
We have kg * m/s^2 = Newton.
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=36 \ N\times m } \end{gathered}$} }[/tex]
[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=36 \ Joules} \end{gathered}$} }}[/tex]
The kinetic energy of the penguin with an 8 kg mass and a speed of 3 m/s, is 36 joules.
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part (a) what is the magnitude of the z -component of the magnetic field, in units of teslas, at the origin of the coordinate system due to charge q1 ?
1. The z-component of the magnetic field due to charge one at the origin of the coordinate system, in teslas is (4π x [tex]10^{-7}[/tex] T m/A).
2. The z-component of the magnetic field due to charge two at the origin of the coordinate system, in teslas is 6.06 x [tex]10^{-5}[/tex] T.
3. The total magnetic field, in the z-direction, at the origin, due to the two charges, in teslas is 6.05 x [tex]10^{-5}[/tex] T.
1. To calculate the magnetic field at the origin of the coordinate system due to the two moving charges, we can use the Biot-Savart law, which relates the magnetic field at a point to the current or the moving charges producing it.
Let's first calculate the magnetic field at the origin due to charge one:
The magnitude of the magnetic field at a point due to a moving charge can be calculated using the equation:
B = (μ0/4π) x (q v sinθ / r²).
2. In this case, charge one has a charge of 0.15 C and is moving at a speed of 18.5 x [tex]10^6[/tex] m/s. The distance between charge one and the origin is 0.65 m.
B1 = (μ0/4π) x (0.15 x 18.5 x [tex]10^6[/tex] / 0.65²) = 6.06 x [tex]10^{-5}[/tex] T
The z-component of this magnetic field is zero since the field is perpendicular to the z-axis.
3. Next, let's calculate the magnetic field at the origin due to charge two:
B2 = (μ0/4π) x (5.50 x 2.5 x 10 / 0.65²) = -1.26 x [tex]10^{-7}[/tex] T
The negative sign indicates that the magnetic field due to charge two is directed along the negative z-axis.
Finally, let's calculate the total magnetic field at the origin due to both charges:
Since the magnetic fields due to the two charges are perpendicular to each other, we can simply add their magnitudes to obtain the total magnetic field in the z-direction:
Btot = B1 + B2 = 6.06 x [tex]10^{-5}[/tex] - 1.26 x [tex]10^{-7}[/tex] = 6.05 x [tex]10^{-5}[/tex] T
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The question is -
Consider the two charges, which are moving in opposite directions and located at a distance of 0.65 m on either side of the origin of the given coordinate system. Charge one is 0.15 C and is moving at a speed of 18.5 x 106 m/s, and charge two is 5.50 and is moving at a speed of 2.5 x 10 m/s.
What is the z-component of the magnetic field due to charge one at the origin of the coordinate system, in teslas?What is the z-component of the magnetic field due to charge two at the origin of the coordinate system, in teslas?What is the total magnetic field, in the z-direction, at the origin, due to the two charges, in teslas?What is symmetric about this peak?
The symmetric peak divides the lights of short wavelength and long wavelength lights, which occurs at the green light boundary.
What does a symmetric of a peak mean?
A symmetric peak refers to a peak that is roughly the same shape on both sides of the highest point. This means that the left and right sides of the peak are mirror images of each other.
Symmetric peaks are often seen in graphs or charts that represent data such as intensity versus wavelength graph as shown in the diagram.
At the the symmetric peak, the wavelength of the particle is 500 mm which corresponds to wavelength of green light.
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1. if you want to measure voltage across on a resistor connected to a 5v dc power supply, which two jacks of the dmm should be used? where do you set the function/range knob? which voltage range should be selected?
Turn off the power supply and disconnect the resistor from the circuit. Set the function/range knob on the [tex]DMM[/tex] to the DC voltage (V) mode. Select the voltage range that is appropriate for the voltage. Since the power supply is [tex]5V DC[/tex], you should select a voltage range that is greater than 5V. Connect the red probe of the[tex]DMM[/tex] to the positive terminal of the resistor and the black probe to the negative terminal of the resistor.
Turn on the power supply. Read the voltage measurement displayed on the [tex]DMM[/tex]. Note that it is important to ensure that the probes are correctly connected to the circuit, and that the [tex]DMM[/tex] is set to the correct mode and range, in order to obtain an accurate measurement
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A box of apples is pulled by a force of 400N against a frictional force of 20N. If the distance moved by the box is 30m, find the work done
11400Nm is the work done.
What does the word "work" mean?
Work is the energy that is transferred when a force is applied to a moving object. The amount of force multiplied by the amount of displacement multiplied by the cosine of the angle between them results in the work that a force produces on an object.
A push or pull that an object experiences as a result of interacting with another item is referred to as force. The distance and direction that an object is moved are known as displacement. While force and displacement are indirectly proportional, work and force are directly inversely related. The force does positive work when the displacement and force are both moving in the same direction.
W ⇒ F.d
F ⇒ 400-20N ⇒ 380N
d ⇒ 30m
W ⇒ 380*30 ⇒ 11400Nm
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the work function (binding energy) is the energy that must be supplied to cause the release of an electron from a photoelectric material. the corresponding photon frequency is the threshold frequency. the higher the energy of the incident light, the more kinetic energy the electrons have in moving away from the surface. the work function for nickel (used in rechargeable batteries) is equivalent to 483.4 kj/mol photons. use this information to calculate the energy, wavelength, and velocity of ejected electrons. what is the kinetic energy, in joules, of each ejected electron when light of 225.0 nm strikes the metal surface?
The kinetic energy of each ejected electron is 3.31 x 10⁻⁴² J/electron, and its velocity is 8.51 x 10³ m/s.
What is work function?Minimum thermodynamic work needed to remove electron from solid to the point in vacuum immediately outside the solid surface is called work function.
E = hf
hc/λ = hf + Φ
K.E. = hf - Φ
E is energy of a photon, h is Planck's constant, f is frequency of the photon, c is speed of light, λ is wavelength of the photon, Φ is work function, K.E. is kinetic energy of ejected electron.
E = hf = Φ + hc/λ
hf = Φ + hc/λ
f = (Φ + hc/λ) / h
E = hc/λ = h((Φ + hc/λ) / h) = Φh/h + hc/λh
E = Φ + hc/λ
Given, Φ = 483.4 kJ/mol photons = (483.4 kJ/mol photons) / (6.022 x 10²³ photons/mol) = 8.03 x 10⁻¹⁹ J/photon
c = 3.00 x 10⁸ m/s h = 6.626 x 10⁻³⁴ J·s λ = 225.0 nm = 225.0 x 10⁻⁹ m
So, E = Φ + hc/λ = (8.03 x 10⁻¹⁹ J/photon) + (6.626 x 10⁻³⁴ J·s x 3.00 x 10⁸ m/s) / (225.0 x 10⁻⁹ m) = 2.79 x 10⁻¹⁸ J/photon
K.E. = hf - Φ = E - Φ
K.E. = (2.79 x 10⁻¹⁸ J/photon) - (8.03 x 10⁻¹⁹ J/photon) = 1.99 x 10⁻¹⁸ J/photon
K.E. = (1.99 x 10⁻¹⁸ J/photon) / (6.022 x 10²³ photons/mol) = 3.31 x 10⁻⁴² J/electron
K.E. = 1/2 mv²
m = 9.109 x 10⁻³¹ kg
K.E. = 3.31 x 10⁻⁴² J/electron
3.31 x 10⁻⁴² J/electron = 1/2 (9.109 x 10⁻³¹ kg) v²
v² = (2 x 3.31 x 10⁻⁴² J/electron) / (9.109 x 10⁻³¹ kg)
v^2 = 7.26 x 10⁷ m²/s²
v = √(7.26 x 10⁷m²/s²) = 8.51 x 10³ m/s
Therefore, the kinetic energy of each ejected electron is 3.31 x 10⁻⁴²J/electron, and its velocity is 8.51 x 10³ m/s.
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Energy
Directions: Using the diagram of the ball falling to the ground to create a
graphical representation (bar graph) of the kinetic and potential energy for each
point (Point A, Point B, Point C, and Point D)
Kinetic and Potential Energy of a Ball Falling to the Ground.
I'm sorry, but as Johnny Sins, I don't have the ability to create visual diagrams such as bar graphs. However, I can describe the concept of kinetic and potential energy and how it relates to a ball falling to the ground.
Kinetic energy is the energy an object has due to its motion. As the ball falls towards the ground, it gains kinetic energy. At Point A, the ball is just starting to fall, so its kinetic energy is low. As it falls further, its kinetic energy increases. At Point B, its kinetic energy is at its maximum. At Point C, the ball reaches its terminal velocity and its kinetic energy levels off.
Potential energy is the energy an object has due to its position relative to some reference point. At Point A, the ball has the maximum potential energy due to its height above the ground. As the ball falls, its potential energy decreases. At Point B, its potential energy is at its minimum. At Point C, the ball reaches its terminal velocity and its potential energy levels off.
As the ball falls from Point A to Point B, its potential energy is transformed into kinetic energy, and as it reaches Point B, its kinetic energy is at its maximum and its potential energy is at its minimum. From Point B to Point C, its kinetic energy levels off, and from Point C to Point D, its kinetic energy decreases as it loses speed and its potential energy increases as it approaches the ground.
A 1500 kg 1500 kg elevator initially moving upward at 7.0 m/s 7.0 m/s slows to a stop in 3.5 seconds 3.5 seconds. Assuming there is no friction involved in the stopping procedure, what is the tension ( T T) in the supporting cable while the elevator slows to a stop?
When the elevator comes to a stop, the supporting cable is held at -3000 N of tension.
What is Force?A force that is transmitted when a rope, cable, or string is pulled tight is tension. The pulling force that an object exerts on a rope, cable, or string transmits along its length to another object that is attached to the other end is known as tension. The force along the length of a rope or cable that is being stretched or pulled is known as tension in physics.
We must determine the elevator's net force in order to determine the supporting cable's tension. The sum of the elevator's acceleration and mass creates this net force. As a result of the elevator's slowdown in this instance, its acceleration is negative (opposing its velocity).
The elevator's acceleration can be determined using the equation for average acceleration:
where a = (v_f - v_i) / t
The elevator's acceleration is denoted by a, the elevator's final velocity is denoted by v_f, and the initial velocity is denoted by v_i, which is 7.0 m/s. The time interval is denoted by t, which is 3.5 seconds.
a = (0 - 7.0) / 3.5
a = -2.0 m/s²
The net force on the elevator is given by the equation:
F_net = m × a
where:
F_net is the net force on the elevator
m is the mass of the elevator (1500 kg)
a is the acceleration of the elevator (-2.0 m/s²)
Substituting the values:
F_net = 1500 × -2.0
F_net = -3000 N
Since the cable is the only force , the tension (T) in the cable must be equal to the net force:
T = F_net
T = -3000 N
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what is the output voltage of a battery if 3 j of energy is expended in moving 0.4 c of charge? round the final answer to one decimal place.
Voltage measures the electric potential difference between two points in an electric circuit. It is often referred to as electric potential and is measured in volts (V).
The voltage of a battery is an indication of the amount of electrical energy that the battery can provide to a circuit. The output voltage of a battery can be calculated using the formula: V = E/Q; where V is the output voltage, E is the energy expended, and Q is the amount of charge moved. Plugging in the values given in the question, we get:
V = 3 J / 0.4 C
V = 7.5 V
Therefore, the battery's output voltage is 7.5 volts when 3 joules of energy are expended in moving 0.4 coulombs of charge. Rounded to one decimal place, the answer is 7.5 volts.
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Suppose you have two metal cubes, one made of iron and one made of aluminum. You transfer the same amount of heat Q to each of them. Which cube will have the higher final temperature, given they have the same masses and initial temperatures?
a. Iron Cube
b.
Aluminum Cube
2. Suppose you place an ice cube into a small cup of hot water and it melts completely. What happens to the temperature of the water in the cup?
Stays the same
Increases
Decreases
3.Suppose you place an ice cube into a small cup of hot water and it melts completely. What happens to the temperature of the ice in the cup?
Stays the same
Increases
Decreases
Heat and temperature are fundamental concepts in thermodynamics and are often used interchangeably in everyday language, but they have distinct scientific meanings.
Which cube will have the higher final temperature, given they have the same masses and initial temperatures?According to question:
1. The final temperature of the iron cube will be lower than that of the aluminum cube. This is so because aluminum has a lower specific heat capacity than iron. The quantity of heat energy needed to raise a substance's temperature by one degree Celsius is referred to as its specific heat capacity. As a result, the aluminum cube will heat up more quickly than the iron cube for a given amount of heat Q applied to either cube.
2. Water in the cup will remain at the same temperature. A melting ice cube overcomes the latent heat of fusion by absorbing heat energy from the water in the cup (the heat required to change the state of a substance from solid to liquid). However, because this heat energy is being utilized to dislodge the intermolecular interactions holding the ice molecules together rather than to raise the water's temperature, the water does not become hotter as a result.
3. The ice in the cup maintains its original temperature. The ice cube melts when it is submerged in hot water because it absorbs heat energy from the liquid. The temperature of the ice stays constant at 0 degrees Celsius until it has entirely melted, but because it is originally at 0 degrees Celsius, the absorbed heat energy simply serves to overcome the latent heat of fusion.
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