A company that wants to send data over the Internet has asked you to write a program that will encrypt it so that it may be transmitted more securely. All the data is transmitted as four-digit integers. Your app should read a four-digit integer entered by the user and encrypt it as follows: Replace each digit with the result of adding 7 to the digit and getting the remainder after dividing the new value by 10. Then swap the first digit with the third, and swap the second digit with the fourth. Then display the encrypted integer. Write a separate app that inputs an encrypted four-digit integer and decrypts it (by reversing the encryption scheme) to form the original number. Use the format specifier D4 to display the encrypted value in case the number starts with a 0
Answer:
The output of the code:
Enter a 4 digit integer : 1 2 3 4
The decrypted number is : 0 1 8 9
The original number is : 1 2 3 4
Explanation:
Okay, the code will be written in Java(programming language) and the file must be saved as "Encryption.java."
Here is the code, you can just copy and paste the code;
import java.util.Scanner;
public class Encryption {
public static String encrypt(String number) {
int arr[] = new int[4];
for(int i=0;i<4;i++) {
char ch = number.charAt(i);
arr[i] = Character.getNumericValue(ch);
}
for(int i=0;i<4;i++) {
int temp = arr[i] ;
temp += 7 ;
temp = temp % 10 ;
arr[i] = temp ;
}
int temp = arr[0];
arr[0] = arr[2];
arr[2]= temp ;
temp = arr[1];
arr[1] =arr[3];
arr[3] = temp ;
int newNumber = 0 ;
for(int i=0;i<4;i++)
newNumber = newNumber * 10 + arr[i];
String output = Integer.toString(newNumber);
if(arr[0]==0)
output = "0"+output;
return output;
}
public static String decrypt(String number) {
int arr[] = new int[4];
for(int i=0;i<4;i++) {
char ch = number.charAt(i);
arr[i] = Character.getNumericValue(ch);
}
int temp = arr[0];
arr[0]=arr[2];
arr[2]=temp;
temp = arr[1];
arr[1]=arr[3];
arr[3]=temp;
for(int i=0;i<4;i++) {
int digit = arr[i];
switch(digit) {
case 0:
arr[i] = 3;
break;
case 1:
arr[i] = 4;
break;
case 2:
arr[i] = 5;
break;
case 3:
arr[i] = 6;
break;
case 4:
arr[i] = 7;
break;
case 5:
arr[i] = 8;
break;
case 6:
arr[i] = 9;
break;
case 7:
arr[i] = 0;
break;
case 8:
arr[i] = 1;
break;
case 9:
arr[i] = 2;
break;
}
}
int newNumber = 0 ;
for(int i=0;i<4;i++)
newNumber = newNumber * 10 + arr[i];
String output = Integer.toString(newNumber);
if(arr[0]==0)
output = "0"+output;
return output;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter a 4 digit integer:");
String number = sc.nextLine();
String encryptedNumber = encrypt(number);
System.out.println("The decrypted number is:"+encryptedNumber);
System.out.println("The original number is:"+decrypt(encryptedNumber));
}
}
Suppose you are given a text file. Design a Python3 program to encrypt/decrypt that text file as follows:
If the character is an upper case character then shift that character forward, s characters forward in the alphabet.
If the character is a lower case character then shift that character backwards, s characters backwards in the alphabet.
If the character is a numeric character then shift that character also backwards, s characters backwards in the 1-digit numbers set {0,1,2,3,4,5,6,7,8,9}.
You must design two functions; one to encrypt. The other one is to decrypt. All white space and punctuation marks must be ignored(cannot be changed). If you reach Z, or A, the shifting may continue as a cycle(A comes after Z, Z comes before A). Both files (original text file and the encrypted text file) must be stored in the working directory of Python.
An example;
Let s=1 and the text file:
11300Hello World
Then encoded text file;
002991dkkn Xnqke
Answer:
Explanation:
Please find attachment for the Python program
Suppose that a program's data and executable code require 1,024 bytes of memory. A new section of code must be added; it will be used with various values 70 times during the execution of a program. When implemented as a macro, the macro code requires 73 bytes of memory. When implemented as a procedure, the procedure code requires 132 bytes (including parameter-passing, etc.), and each procedure call requires 7 bytes. How many bytes of memory will the entire program require if the new code is added as a procedure? 1,646
Answer:
The answer is 1646
Explanation:
The original code requires 1024 bytes and is called 70 times ,it requires 7 byte and its size is 132 bytes
1024 + (70*7) + 132 = 1024 + 490 +132
= 1646
(a) What is the difference between a compare validator and a range validator?
(b) When would you choose to use one versus the other?
Answer:
Check the explanation
Explanation:
a) A compare validator: A compare validator can be described as a particular method that is utilized to control and also enabled to perform different types of validation tasks. It is being used to carry out as well as to execute a correct data type that determines the entered value is proper value into a form field or not. For instance when in an application registration it makes use of the confirm password after the first-password.
(b) Whenever it is compulsory to determine if the value that has been entered is the correct value into the form field then the usage of compare validator will be needed whereas a range validator is used to confirm the entered value is in a specific range.
Explanation:
a) A compare validator: A compare validator can be described as a particular method that is utilized to control and also enabled to perform different types of validation tasks. It is being used to carry out as well as to execute a correct data type that determines the entered value is proper value into a form field or not. For instance when in an application registration it makes use of the confirm password after the first-password.
(b) Whenever it is compulsory to determine if the value that has been entered is the correct value into the form field then the usage of compare validator will be needed whereas a range validator is used to confirm the entered value is in a specific range.
An attacker compromises the Washington Post's web server and proceeds to modify the homepage slightly by inserting a 1x1 pixel iframe that directs all website visitors to a webpage of his choosing that then installs malware on the visitors' computers. The attacker did this explicitly because he knows that US policymakers frequent the website. This would be an example of a ___________ attack.
Answer:
Water holing is the correct answer to this question.
Explanation:
Waterholing:-
It is a kind of attack in which the attacker detects the sites that the targets of the group frequently access and then afflicts the sites with the ransomware. Which afflicts selected representatives of the target group.
The watering hole assault is a data breach wherein the individual attempts to infiltrate a particular demographic of end-users by harming sites reported to be visited by team members. The aim is to compromise a specific target data and gain network access at the perpetrator's place of work.
Caches are important to providing a high-performance memory hierarchy to processors. Below is a list of 32-bits memory address references given as word addresses. 0x03, 0xb4, 0x2b, 0x02, 0xbf, 0x58, 0xbe, 0x0e, 0xb5, 0x2c, 0xba, 0xfd For each of these references identify the binary word address, the tag, and the index given a direct mapped cache with 16 one-word blocks. Also list whether each reference is a hit or a miss, assuming the cache is initially empty.
Answer:
See explaination
Explanation:
please kindly see attachment for the step by step solution of the given problem.
what should i name my slideshow if its about intellectual property, fair use, and copyright
Answer:
You should name it honest and sincere intention
Explanation:
That is a good name for what you are going to talk about in your slideshow.
4. Write an interface ObjectWithTwoParameters which has a method specification: double area (double d1, double d2) which returns the area of a particular object. Write three classes RectangleClass, TriangleClass, and CylinderClass which implement the interface you created. Also, write a demo class which creates objects of RectangleClass, TriangleClass, and CylinderClass and call the corresponding methods
Answer:
The java program for the given scenario is as follows.
import java.util.*;
//interface with method area
interface ObjectWithTwoParameters
{
double area (double d1, double d2);
}
class RectangleClass implements ObjectWithTwoParameters
{
//overriding area()
public double area (double d1, double d2)
{
return d1*d2;
}
}
class TriangleClass implements ObjectWithTwoParameters
{
//overriding area()
public double area (double d1, double d2)
{
return (d1*d2)/2;
}
}
class CylinderClass implements ObjectWithTwoParameters
{
public double area (double d1, double d2)
{
return ( 2*3.14*d1*d1 + d2*(2*3.14*d1) );
}
}
public class Test
{
public static void main(String[] args)
{
//area displayed for all three shapes
ObjectWithTwoParameters r = new RectangleClass();
double arear = r.area(2, 3);
System.out.println("Area of rectangle: "+arear);
ObjectWithTwoParameters t = new TriangleClass();
double areat = t.area(4,5);
System.out.println("Area of triangle: "+areat);
ObjectWithTwoParameters c = new CylinderClass();
double areac = c.area(6,7);
System.out.println("Area of cylinder: "+areac);
}
}
OUTPUT
Area of rectangle: 6.0
Area of triangle: 10.0
Area of cylinder: 489.84
Explanation:
1. The program fulfils all the mentioned requirements.
2. The program contains one interface, ObjectWithTwoParameters, three classes which implement that interface, RectangleClass, TriangleClass and CylinderClass, and one demo class, Test, containing the main method.
3. The method in the interface has no access specifier.
4. The overridden methods in the three classes have public access specifier.
5. No additional variables have been declared.
6. The test class having the main() method is declared public.
7. The area of the rectangle, triangle and the cylinder have been computed as per the respective formulae.
8. The interface is similar to a class which can have only declarations of both, variables and methods. No method can be defined inside an interface.
9. The other classes use the methods of the interface by implementing the interface using the keyword, implements.
10. The object is created using the name of the interface as shown.
ObjectWithTwoParameters r = new RectangleClass();
Trace the complete execution of the MergeSort algorithm when called on the array of integers, numbers, below. Show the resulting sub-arrays formed after each call to merge by enclosing them in { }. For example, if you originally had an array of 5 elements, a = {5,2,8,3,7}, the first call to merge would result with: {2, 5} 8, 3, 7 ← Note after the first call to merge, two arrays of size 1 have been merged into the sorted subarray {2,5} and the values 2 and 5 are sorted in array a You are to do this trace for the array, numbers, below. Be sure to show the resulting sub-arrays after each call to MergeSort. int[] numbers = {23, 14, 3, 56, 17, 8, 42, 18, 5};
Answer:
public class Main {
public static void merge(int[] arr, int l, int m, int r) {
int n1 = m - l + 1;
int n2 = r - m;
int[] L = new int[n1];
int[] R = new int[n2];
for (int i = 0; i < n1; ++i)
L[i] = arr[l + i];
for (int j = 0; j < n2; ++j)
R[j] = arr[m + 1 + j];
int i = 0, j = 0;
int k = l;
while (i < n1 && j < n2) {
if (L[i] <= R[j]) {
arr[k] = L[i];
i++;
} else {
arr[k] = R[j];
j++;
}
k++;
}
while (i < n1) {
arr[k] = L[i];
i++;
k++;
}
while (j < n2) {
arr[k] = R[j];
j++;
k++;
}
printArray(arr, l, r);
}
public static void sort(int[] arr, int l, int r) {
if (l < r) {
int m = (l + r) / 2;
sort(arr, l, m);
sort(arr, m + 1, r);
merge(arr, l, m, r);
}
}
static void printArray(int[] arr, int l, int r) {
System.out.print("{");
for (int i = l; i <= r; ++i)
System.out.print(arr[i] + " ");
System.out.println("}");
}
public static void main(String[] args) {
int[] arr = {23, 14, 3, 56, 17, 8, 42, 18, 5};
sort(arr, 0, arr.length - 1);
}
}
Explanation:
See answer
Evaluati urmatoarele expresii
5+2*(x+4)/3, unde x are valoare 18
7/ 2*2+4*(5+7*3)>18
2<=x AND x<=7 , unde x are valoare 23
50 %10*5=
31250/ 5/5*2=
Answer:
A) 22 ⅓
B) 111>18
C) There is an error in the expression
D) 25
E) 62500
Question:
Evaluate the following expressions
A) 5 + 2 * (x + 4) / 3, where x has a value of 18
B) 7/2 * 2 + 4 * (5 + 7 * 3) & gt; 18
C) 2 <= x AND x<= 7, where x has value 23
D) 50% 10 * 5 =
F) 31250/5/5 * 2 =
Explanation:
A) 5 + 2 * (x + 4) / 3
x = 18
First we would insert the value of x
5 + 2 * (x + 4) / 3
5 + 2(18 + 8) / 3
Then we would evaluate the expression by applying BODMAS : This stands for Bracket, Of, Division, Multiplication, addition and subtraction.
= 5 + 2(26) / 3
= 5 + 52/3
= 5 + 17 ⅓
= 22 ⅓
B) 7/2 * 2 + 4 * (5 + 7 * 3) > 18
we would evaluate the expression by applying BODMAS : This stands for Bracket, Of, Division, Multiplication, addition and subtraction.
7/2 * 2 + 4 * (5 + 7 * 3) >18
= 7/2 × 2 + 4× (5 + 7 × 3)>18
= (7×2)/2 + 4× (5+21) >18
= 14/2 + 4(26) >18
= 7 + 104 >18
= 111>18
C) 2 <= x AND x<= 7, where x has value 23
There is an error in the expression
D) 50% of 10 * 5
we would evaluate the expression by applying BODMAS : This stands for Bracket, Of, Division, Multiplication, addition and subtraction.
The 'of' expression means multiplication
= 50% × 10×5
= 50% × 50
50% = 50/100
=50/100 × 50
= 1/2 × 50
= 25
F) 31250/5/5 * 2
The expression has no demarcation. Depending on how it is broken up, we would arrive at different answers. Let's consider:
31250/(5/5 × 2)
Apply BODMAS
= 31250/[5/(5 × 2)]
= 31250/(5/10)
= 31250/(1/2)
Multiply by the inverse of 1/2 = 2/1
= 31250 × (2/1)
= 62500
Use a vector to solve the following problem. Read in 20 numbers, each of which is between 10 and 100, inclusive. As each number is read, validate it and store it in the vector only if it isn't a duplicate of a number already read. After reading all the values, display only the unique values that the user entered. Begin with an empty vector and use its push_back function to add each unique value to the vector.
Answer:
The following are the program in the C++ Programming Language.
//header files
#include <iostream>
#include <vector>
//using namespace
using namespace std;
//define a function
int find(vector<int> &vec, int n)
{
//set the for loop
for(int i = 0; i < vec.size(); ++i)
{
//check the elements of v is in the num
if(vec[i] == n)
{
//then, return the values of i
return i;
}
}
return -1;
}
//define the main method
int main()
{
//declare a integer vector type variable
vector<int> vec;
//print message
cout << "Enter numbers: ";
//declare integer type variable
int n;
//set the for loop
for(int i = 0; i < 20; ++i)
{
//get input in the 'num' from the user
cin >> n;
//check the following conditions
if(n >= 10 && n <= 100 && find(vec, n) == -1)
{
//then, assign the values of 'num' in the vector
vec.push_back(n);
}
}
//print the message
cout << "User entered: ";
//set the for loop
for(int i = 0; i < vec.size(); ++i)
{
//print the output
cout << vec[i] << " ";
}
cout << "\n";
return 0;
}
Output:
Enter numbers: 14 18 96 75 23 65 47 12 58 74 76 92 34 32 65 48 46 28 75 56
User entered: 14 18 96 75 23 65 47 12 58 74 76 92 34 32 48 46 28 56
Explanation:
The following are the description of the program:
Firstly, set the required header files and required namespace.Define an integer data type function 'find()' and pass two arguments that is integer vector type argument 'vec' and integer data type argument 'n'.Then, set the for loop that iterates according to the size of the vector variable 'vec' inside the function, after that set the if conditional statement to check the following condition and return the variable 'i'.Define the main method that gets the input from the user then, check that the following inputs are greater than 10 and smaller than 100 then assign these variables in the vector type variable 'vec' and print all the elements.4. What are the ethical issues of using password cracker and recovery tools? Are there any limitations, policies, or regulations in their use on local machines, home networks, or small business networks? Where might customer data be stored? Discuss any legal issues in using these tools on home networks in the United States, which has anti-wiretap communications regulations. Who must know about the tools being used in your household?
Answer:
There are no limitation, policies or regulations that limit these tools for use on privately owned machines or home networks. In most businesses networks, intranets or internets the use of them is illegal if used for malicious intent. Penetration testing teams sign rules of engagement before using these tools.
Explanation:
There are no limitation, limitations, policies, or regulations in their use on local machines, privately owned machines or home networks, or small business networks.
In most businesses networks, intranets or internets the use of them is often and mostly illegal especially in a situation where they are been used for malicious intent.
Penetration testing teams would often or always make sure that they sign rules of engagement before using these tools.
Double any element's value that is less than minValue. Ex: If minValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}.
import java.util.Scanner;
public class StudentScores {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_Points = 4;
int[] dataPoints = new int[NUM_POINTS];
int minValue;
int i;
minValue = scnr.nextInt();
for (i = 0; i < dataPoints.length; ++i) {
dataPoints[i] = scnr.nextInt();
}
/* Your solution goes here */
for (i = 0; i < dataPoints.length; ++i) {
System.out.print(dataPoints[i] + " ");
}
System.out.println();
}
}
Answer:
Following are the code to this question:
for(i=0;i<dataPoints.length;++i) //define loop to count array element
{
if(dataPoints[i]<minValue) // define condition that checks array element is less then minValue
{
dataPoints[i] = dataPoints[i]*2; //double the value
}
}
Explanation:
Description of the code as follows:
In the given code, a for loop is declared, that uses a variable "i", which counts all array element, that is input by the user. Inside the loop and if block statement is used, that check array element value is less then "minValue", if this condition is true. So, inside the loop, we multiply the value by 2.For dinner, a restaurant allows you to choose either Menu Option A: five appetizers and three main dishes or Menu Option B: three appetizers and four main dishes. There are six kinds of appetizer on the menu and five kinds of main dish.
How many ways are there to select your menu, if...
a. You may not select the same kind of appetizer or main dish more than once.
b. You may select the same kind of appetizer and/or main dish more than once.
c. You may select the same kind of appetizer or main dish more than once, but not for all your choices, For example in Menu Option A, it would be OK to select four portions of 'oysters' and one portion of 'pot stickers', but not to select all five portions of 'oysters'.)
In each case show which formula or method you used to derive the result.
Answer:
The formula used in this question is called the probability of combinations or combination formula.
Explanation:
Solution
Given that:
Formula applied is stated as follows:
nCr = no of ways to choose r objects from n objects
= n!/(r!*(n-r)!)
The Data given :
Menu A : 5 appetizers and 3 main dishes
Menu B : 3 appetizers and 4 main dishes
Total appetizers - 6
Total main dishes - 5
Now,
Part A :
Total ways = No of ways to select menu A + no of ways to select menu B
= (no of ways to select appetizers in A)*(no of ways to select main dish in A) + (no of ways to select appetizers in B)*(no of ways to select main dish in B)
= 6C5*5C3 + 6C3*5C4
= 6*10 + 20*5
= 160
Part B :
Since, we can select the same number of appetizers/main dish again so the number of ways to select appetizers/main dishes will be = (total appetizers/main dishes)^(no of appetizers/main dishes to be selected)
Total ways = No of ways to select menu A + no of ways to select menu B
= (no of ways to select appetizers in A)*(no of ways to select main dish in A) + (no of ways to select appetizers in B)*(no of ways to select main dish in B)
= (6^5)*(5^3) + (6^3)*(5^4)
= 7776*125 + 216*625
= 1107000
Part C :
No of ways to select same appetizers and main dish for all the options
= No of ways to select menu A + no of ways to select menu B
= (no of ways to select appetizers in A)*(no of ways to select main dish in A) + (no of ways to select appetizers in B)*(no of ways to select main dish in B)
=(6*5) + (6*5)
= 60
Total ways = Part B - (same appetizers and main dish selected)
= 1107000 - 60
= 1106940
#define DIRECTN 100
#define INDIRECT1 20
#define INDIRECT2 5
#define PTRBLOCKS 200
typedef struct {
filename[MAXFILELEN];
attributesType attributes; // file attributes
uint32 reference_count; // Number of hard links
uint64 size; // size of file
uint64 direct[DIRECTN]; // direct data blocks
uint64 indirect[INDIRECT1]; // single indirect blocks
uint64 indirect2[INDIRECT2]; // double indirect
} InodeType;
Single and double indirect inodes have the following structure:
typedef struct
{
uint64 block_ptr[PTRBLOCKS];
}
IndirectNodeType;
Required:
Assuming a block size of 0x1000 bytes, write pseudocode to return the block number associated with an offset of N bytes into the file.
Answer:
WOW! that does not look easy!
Explanation:
I wish i could help but i have no idea how to do that lol
write the steps to insert picture water mark
Answer:
Is there a picture of the question?
Explanation:
