f space is expanding, that tell us something about how the universe began. what would happen if wind the clock backwards? how would the distance between objects today compare with the distances in the early universe?

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Answer 1

If we wind the clock backwards to the early universe, the distances between objects would be significantly smaller than they are today.

The expansion of space is a result of the Big Bang, which took place around 13.8 billion years ago. As time progresses, space continues to expand, causing galaxies and other celestial objects to move away from each other. By rewinding time and going back to the early universe, we would observe that the distances between objects were much smaller, as everything was closer together and concentrated in a smaller region of space.

In the early universe, the distances between objects were much smaller compared to today due to the ongoing expansion of space since the Big Bang.

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Related Questions

Determine the quantity and type of charge on an object that has 3.62 x 1012 more protons than electrons.
(static electricity)

Answers

The object has an overall positive charge, since it has 3.62 x 1012 more protons than electrons.

What is electrons?

Electrons are subatomic particles with a negative electric charge. They are found in all atoms and are responsible for chemical bonding between atoms and molecules. Electrons have a very small mass in comparison to protons and neutrons, which make up the nucleus of an atom. Electrons are found in various energy levels around the nucleus, and each of these energy levels can contain a certain number of electrons. Electrons can also move from one energy level to another, which is what happens when an atom absorbs or emits light. Electrons are essential for life, as they give atoms the ability to form molecules, which are the building blocks of life.

This means that it has a net charge of 3.62 x 1012 protons, or 3.62 x 1012 units of positive charge. This type of charge is known as static electricity, since it is a type of electric charge that accumulates and remains on an object until it is neutralized.

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a laser beam is normally incident on a single slit with width 0.650 mm. a diffraction pattern forms on a screen a distance 1.20 m beyond the slit. the distance between the positions of zero intensity on both sides of the central maximum is 2.28 mm. calculate the wavelength of the light (in nm).

Answers

We can use the formula for the distance between the positions of zero intensity on both sides of the central maximum in a single-slit diffraction pattern.The wavelength of the light is 546 nm.

To solve this proble, we can use the formula for the distance between the positions of zero intensity on both sides of the central maximum in a single-slit diffraction pattern:   sin(θ) = λ/d

In this case, we are given the width of the slit (d = 0.650 mm), the distance between the slit and the screen (L = 1.20 m), and the distance between the positions of zero intensity on both sides of the central maximum (2θ = 2.28 mm).

We can use trigonometry to find the value of sin(θ):  sin(θ) = (2θ)/(L) Substituting in the given values, we find:  sin(θ) = (2 × 2.28 mm)/(1.20 m) = 0.0038

Finally, we can use the formula we derived earlier to find the wavelength of the light:  λ = (0.650 mm) × sin(θ) = 546 nm.

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ch 7 #24
Two billiard balls of equal mass undergo a perfectly elastic head-on collision. If one ball's initial speed was 2.0 m/s. and the other's was 3.00 m/s in the opposite direction, what will be their speeds after the collision?

Answers

After the collision, the ball that was initially moving at 2.0 m/s will be moving at 3.00 m/s in the opposite direction, while the ball that was initially moving at 3.00 m/s will be moving at 2.0 m/s in the opposite direction.

This result can be obtained by applying the principle of conservation of momentum and the principle of conservation of kinetic energy. Since the collision is perfectly elastic, the total kinetic energy of the system is conserved. The initial momentum of the system is zero, since the balls are moving in opposite directions with equal and opposite momenta. Therefore, the final momentum of the system must also be zero.

Using these principles, we can solve for the final velocities of the balls using the following equations:

m1v1i + m2v2i = m1v1f + m2v2f    (conservation of momentum)

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2  (conservation of kinetic energy)

Plugging in the given values, we get:

m1v1i + m2v2i = m1v1f + m2v2f

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Substituting m1 = m2 and solving for v1f and v2f, we get:

v1f = v2i

v2f = v1i

Plugging in the given values, we get:

v1f = 3.00 m/s

v2f = 2.0 m/s

Therefore, after the collision, the ball that was initially moving at 2.0 m/s will be moving at 3.00 m/s in the opposite direction, while the ball that was initially moving at 3.00 m/s will be moving at 2.0 m/s in the opposite direction.

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When you blow some air above the upper face of a paper strip, the paper rises. This occurs because:.

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When you blow air above the upper face of a paper strip, the paper rises due to a phenomenon known as Bernoulli's principle.

According to this principle, as the speed of a fluid (in this case, air) increases, its pressure decreases. When you blow air above the paper, the air moves faster than the air below the paper. This creates a region of lower pressure above the paper and higher pressure below the paper.

The difference in pressure creates an upward force on the paper, causing it to rise. This effect is also what allows airplanes to fly and explains why flags flutter in the wind.

When you blow air above the upper face of a paper strip, the paper rises due to a principle called Bernoulli's principle. As you blow air, the air pressure above the paper decreases due to the increased air velocity. Since the air below the paper is relatively still, it has a higher pressure.

This difference in air pressure causes the paper to rise, as the higher pressure beneath the paper pushes it upward. In summary, the paper rises because the fast-moving air above the paper creates a lower pressure, and the still air below the paper exerts a higher pressure, lifting the paper.

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hal makes an electromagnet with a 9-volt battery, wire, and a steel rod. what is the function of electric current in his electromagnet?

Answers

Answer:

Electric current creates a magnetic field that charges the rod.

Explanation:

A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Who has greater linear speed?
A. the boy
B. both have zero speed
C. the girl has greater linear speed
D. both the girl and the boy have non zero linear speed

Answers

C. The girl has greater linear speed.

The merry-go-round is turning at a constant rate, which means the angular velocity (ω) of the girl and the boy is the same. However, since the girl is nearer to the outer edge of the merry-go-round, she has to travel a greater distance along the circumference of the circle than the boy does in the same amount of time. Therefore, the girl has a greater linear speed than the boy.

Linear speed, also known as tangential speed, is the rate at which an object travels along a straight line path. It is the magnitude of the velocity vector of an object in uniform circular motion.

The formula for linear speed is:

v = rω

where v is the linear speed, r is the radius of the circle, and ω (omega) is the angular velocity, or the rate at which the object is rotating.

Linear speed is measured in units of distance per unit time, such as meters per second (m/s) or kilometers per hour (km/h).

In the case of the merry-go-round, the girl, who is closer to the outer edge of the circle, travels a greater distance in the same amount of time than the boy, who is closer to the center. Therefore, the girl has a greater linear speed than the boy.

Linear speed is an important concept in physics, especially in the study of circular motion and the motion of rotating objects. It is also used in many practical applications, such as determining the speed of vehicles, machinery, and other moving objects.

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oes a particle in a 1-d box gain more, less, or the same amount of energy by going from the 1st to the 2nd level or from the 2nd to the 3rd level?

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The particle gains the same amount of energy when it goes from the 1st to the 2nd level or from the 2nd to the 3rd level.

In a particle in a 1-d box, the energy levels are given by the equation:

[tex]E = (n^2 * h^2)/(8mL^2)[/tex]

where

n is the quantum number,

h is Planck's constant,

m is the mass of the particle, and

L is the length of the box.

As we can see, the energy levels are proportional to the square of the quantum number.

Therefore, the difference in energy between two adjacent levels is given by:

Δ [tex]E = E_n+1 - E_n[/tex]

       [tex]= [(n+1)^2 - n^2] * (h^2)/(8mL^2)[/tex]

Simplifying this expression, we get:

Δ [tex]E = (2n+1) * (h^2)/(8mL^2)[/tex]

We can see that the difference in energy between two adjacent levels depends on the value of n. For a given n, the difference in energy between two adjacent levels is constant.

Therefore, the particle gains the same amount of energy when it goes from the 1st to the 2nd level or from the 2nd to the 3rd level.

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a time-dependent but otherwise uniform magnetic field of magnitude b0(t) is confined in a cylindrical region of radius 7.5 cm. initially the magnetic field in the region is pointed out of the page and has a magnitude of 4.5 t, but it is decreasing at a rate of 8.5 g/s. due to the changing magnetic field, an electric field will be induced in this space which causes the acceleration of charges in the region.

Answers

When a magnetic field changes with time, it induces an electric field in the space around it. This is known as electromagnetic induction and is the basis for many technologies, including generators and transformers.

In this case, a uniform magnetic field of magnitude b0(t) is confined in a cylindrical region of radius 7.5 cm. Initially, the magnetic field is pointed out of the page and has a magnitude of 4.5 t, but it is decreasing at a rate of 8.5 g/s. As a result of the changing magnetic field, an electric field is induced in this space, which causes the acceleration of charges in the region.

The induced electric field is given by Faraday's law of electromagnetic induction, which states that the induced electric field is proportional to the rate of change of magnetic flux. In this case, the magnetic flux is changing due to the decreasing magnetic field, which leads to the induction of an electric field.

The electric field causes charges in the region to accelerate, which can lead to the production of current. The strength of the induced electric field and the resulting current depend on the rate of change of the magnetic field, the size of the region, and the properties of the materials in the region.

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When approaching a frozen dessert truck with its red lights flashing you must do what?

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When approaching a frozen dessert truck with its red lights flashing, you must slow down and come to a complete stop. This is because the red lights indicate that the truck is stopped and children may be approaching it to buy ice cream or other frozen treats.

The driver of the truck is required to activate the red lights whenever they are stopped to alert other drivers and pedestrians of their presence.

It is important to be cautious and watchful when approaching a frozen dessert truck as children may dart out from behind it or cross the street without looking. In some states, there are laws that require drivers to stop at a safe distance from the truck and remain stopped until the red lights are turned off or the truck has moved on.

Overall, the key is to be aware and follow the laws of your state when approaching a frozen dessert truck with flashing red lights to ensure the safety of everyone involved.

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What could have caused the planets to migrate through the solar system?.

Answers

Answer:

Explanation:

The orbit of a planet can change due to gravitational encounters with a large number of planetesimals.

what is the potential difference across the rod if it moves parallel to ab?

Answers

If a rod moves parallel to line AB, the potential difference across the rod will be zero. This is because the electric field lines are perpendicular to the equipotential surfaces, and when the rod moves parallel to AB, it remains on the same equipotential surface. Since there is no change in electric potential, the potential difference is zero.

A rod's potential difference will be zero if it moves parallel to line AB. This is so because when a rod moves parallel to AB, it stays on the same equipotential surface because the electric field lines are perpendicular to those surfaces. Electric potential is unchanged, hence there is no potential difference.

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The speed of all electromagnetic waves is 3. 00 × 108 meters per second. What is the wavelength of an x-ray with a frequency of 1. 18 × 1018 hz?.

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The wavelength of an x-ray with a frequency of 1.18 × 10¹⁸ Hz is approximately 0.253 nm.

Electromagnetic waves are characterized by their wavelength, frequency, and speed. The speed of electromagnetic waves, including x-rays, is a constant value in a vacuum, equal to 3.00 × 10⁸ meters per second.

In this case, we are given a frequency of 1.18 × 10¹⁸ Hz. Plugging this value into the formula, we get a wavelength of approximately 0.253 nm. The wavelength of an x-ray with a given frequency can be determined using the formula λ = c/f, where λ is the wavelength, c is the speed of light, and f is the frequency.

The relationship between wavelength (λ), frequency (f), and the speed of light (c) is given by the formula λ = c/f. Plugging in the values given, we get: λ = c/f = (3.00 × 10⁸ m/s)/(1.18 × 10¹⁸ Hz) ≈ 0.253 nm

This is a very short wavelength, which is characteristic of x-rays, and is why they are able to penetrate solid objects.

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A 60 kg skier starts from rest from the top of a 50 m high slope. What is the speed of the skier on reaching the bottom of the slope? (Neglect friction.)

A) 9.8 m/s

B) 31 m/s

C) 41 m/s

D) 22 m/s

Answers

The speed of the skier on reaching the bottom of the slope. The answer is B) 31 m/s.

To solve this problem, we can use the conservation of energy principle. Initially, the skier has only potential energy, which is given by mgh, where m is the mass of the skier, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the slope (50 m). When the skier reaches the bottom of the slope, all of this potential energy is converted to kinetic energy, which is given by (1/2)mv^2, where v is the velocity of the skier.

Setting these two equations equal to each other, we have:

mgh = (1/2)mv^2

Simplifying, we get:

v = sqrt(2gh)

Substituting the given values, we have:

v = sqrt(2 x 9.8 m/s^2 x 50 m) = 31 m/s

Therefore, the answer is B) 31 m/s.

It's important to note that neglecting friction is an idealized assumption, as frictional forces are present in most real-world situations. However, this assumption is often made in physics problems to simplify the calculations and focus on the main concepts.

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A transverse and longitudinal wave combine to form what kind of wave?.

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When a transverse wave and a longitudinal wave combine, they form a type of wave known as a surface wave. Surface waves travel along the boundary between two different materials, such as air and water, or rock and soil.

This type of wave has characteristics of both transverse and longitudinal waves, with particles moving both perpendicular and parallel to the direction of wave propagation. Surface waves can be very destructive, as they tend to cause shaking and damage to structures at the surface. They are also important for seismologists studying earthquakes, as they can provide information about the Earth's interior.

When a transverse wave and a longitudinal wave combine, they form a complex wave known as a "surface wave." Surface waves are a combination of both transverse and longitudinal wave motions, and they typically occur at the interface between two different media, such as air and water. In a surface wave, particles move in both parallel and perpendicular directions to the direction of the wave's energy propagation, which is a combination of the characteristics of both transverse and longitudinal waves.

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a toy plane with a mass of 1.10 kg is tied to a string and made to travel at a speed of 25.0 m/s in a horizontal circle with a 16.0-m radius. the person holding the string pulls the plane in, increasing the tension in the string, increasing the speed of the plane and decreasing the radius of the plane's orbit. what is the net work done on the plane if the tension in the string increases by a factor of four and the radius decreases to 8.00 m.

Answers

The net work done on the toy plane is 343.75 joules.

Given,

mass of the toy plane = 1.10 kg.

speed of the toy train = 25 m/s.

The radius of the circular path = 16m.

Now,

the energy of the toy plane = Kinetic energy of the plane

                                              = 1/2 × mass × velocity²

                                              = 1/2 × 1.10 × 25²

                                              = 343.75 joules.

∵ The toy plane is moving at a constant speed,

the net force on the toy plane = 0

centrifugal force = centripetal force

Now the centripetal force acting on the toy plane is the tension in the string.

Tension in the string = centrifugal force

But the centrifugal force = mass × velocity²/radius

                                         = 1.10 × 25²/16

                                         = 42.96 N

∴ Tension in the string = 42.96 N

Now, after the string is pulled,

New tension in the string becomes 4 times. ( according to question)

∴ New tension = 42.96 × 4

                         = 171.87 N

Again,

The toy moves at a constant speed,

∴ Centripetal force = centrifugal force

But the centripetal force is the new tension in the string.

∴ New tension in the string = centrifugal force

                                             = mass × velocity²/radius

But the radius has changed to 8m.

Let the changed velocity be "v".

∴ New tension in the string = 1.1 × v²/8

⇒ 171.87 = 1.1 × v²/8

⇒ v² = 171.87 × 8/1.1

        = 1250

Or, v = 35.35 m/s

Now,

the energy of the plane = the kinetic energy of the plane

                                       = 1/2 × mass × velocity²

                                       = 1/2 × 1.1 × 35.35²

                                       = 687.5 J

We know that,

Net work done = Change in the energy of the object.

Now, a change in the energy of the plane = Change in the kinetic energy

                                                                   = 687.5 - 343.75

                                                                   = 343.75 J

Hence, the net work done on the toy plane is 343.75 joules.

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When water vapor condenses to a liquid a. it transfers heat to the surroundings. b.it absorbs energy from the surroundings c. its temperature drops sharply. d. its temperature rises slightly.

Answers

a. When water vapor condenses to a liquid, it transfers heat to the surroundings.

This is because the process of condensation involves the release of heat energy, which is transferred from the water vapor to the surroundings. This heat transfer causes the temperature of the surroundings to increase slightly, and it is why you may feel warm and humid in a room with a lot of condensing water vapor, such as in a bathroom after a hot shower. The release of heat energy during condensation is also what causes clouds to form in the atmosphere, as water vapor condenses around particles in the air, releasing heat energy and forming droplets of liquid water.

Condensation is a physical process in which a gas or vapor transitions into a liquid or solid state. This occurs when the temperature of the gas or vapor is lowered below its dew point, which is the temperature at which the gas or vapor begins to condense.

When a gas or vapor condenses, it releases heat energy to its surroundings, as the energy that was previously holding the gas or vapor in a gaseous state is released. This heat energy transfer can cause the surrounding environment to warm up slightly.

Condensation is an important process in the water cycle, where it plays a major role in the formation of clouds, rain, and other forms of precipitation. When water vapor in the atmosphere cools and reaches its dew point, it condenses into tiny droplets, forming clouds. These droplets can then grow and combine until they become heavy enough to fall to the ground as precipitation, such as rain or snow.

Condensation is also an important process in various industrial and scientific applications, such as in refrigeration, where the compression and expansion of gases leads to their condensation and evaporation, respectively.

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at one point in the pipe the radius is 0.245 m . what is the speed of the water at this point if water is flowing into this pipe at a steady rate of 1.20 m3/s ?

Answers

The speed of water at the point where the radius of the pipe is 0.245 m is approximately 5.38 m/s. We can use the equation of continuity, which states that the mass flow rate of a fluid is constant throughout a pipe of varying cross-sectional area.

This means that the product of the fluid density, cross-sectional area, and velocity of the fluid is constant at any point in the pipe.

Mathematically, we can express this as:

ρ₁A₁v₁ = ρ₂A₂v₂

where ρ is the density of water, A is the cross-sectional area of the pipe, and v is the velocity of water.

We know that the water is flowing into the pipe at a steady rate of 1.20 m3/s, which means that the cross-sectional area of the pipe at any point must be equal to this volume flow rate divided by the velocity of the water:

A₁v₁ = A₂v₂ = 1.20 m3/s

At the point where the radius of the pipe is 0.245 m, the cross-sectional area can be calculated as:

A₂ = πr² = π(0.245 m)² = 0.189 m²

Substituting this into the equation of continuity, we can solve for v₂:

v₂ = A₁v₁/A₂ = (1.20 m³/s)/(0.189 m²) ≈ 6.35 m/s

Therefore, the speed of the water at the point where the radius of the pipe is 0.245 m is approximately 5.38 m/s (rounded to two decimal places).

The velocity of water flowing through a pipe of varying cross-sectional area can be calculated using the equation of continuity, which relates the mass flow rate of the fluid to its density, cross-sectional area, and velocity. In this particular case, we found that the speed of the water at the point where the radius of the pipe is 0.245 m is approximately 5.38 m/s, given a steady rate of water flow of 1.20 m³/s.

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light with an intensity of 1.0 kw/m2 falls normally on a surface with an area of 2.0 cm2 and is completely absorbed. the force of the radiation on the surface is

Answers

The force of radiation on the surface is 5.0 × 10⁷ N.

The given problem involves calculating the force of radiation on a surface, which can be determined using the formula: force = power/area.

To begin with, the given surface area of 2.0 cm² needs to be converted into square meters. Since 1 cm² is equal to 10⁻⁴ m², 2.0 cm² can be converted into square meters as follows:

2.0 cm² = 2.0 × 10⁻⁴ m²

Next, the intensity of radiation given in the problem is in kW/m², but the formula requires the intensity to be in watts per square meter (W/m²).

So, the intensity of 1.0 kW/m² can be converted to W/m² as follows:

1.0 kW/m² = 1000 W/m²

Now, we can substitute the values into the formula:

force = 1000 W/m² ÷ 2.0 × 10⁻⁴ m²

Simplifying this expression, we get:

force = 5.0 × 10⁷ N

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What are the basic si units for the frequency of light?.

Answers

The basic SI unit for the frequency of light is Hertz (Hz), which equals to [tex]s^{-1}[/tex].

The number of cycles of the constant waveform per second is expressed by the frequency of wave-like patterns such as sound, electromagnetic waves (such as radio or light), electrical impulses, or other waves. The quantity of full oscillations made by any wave element in a unit of time is known as the frequency of a sinusoidal wave.

A parameter that describes the rate of oscillation and vibration is called frequency. The result of the experiment is expressed in Hertz (Hz), which equals to [tex]s^{-1}[/tex], a unit of measure in SI that holds the name Heinrich Rudolf Hertz, a German physicist. One complete oscillation per second equals one hertz (Hz).

Therefore, the basic SI unit for the frequency of light is Hertz (Hz), which equals to [tex]s^{-1}[/tex].

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A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the amplitude of the motion is 0.090m , it takes the block 2.90s to travel from x= 0.090m tox= -0.090m .
a) If the amplitude is doubled, to 0.180m , how long does it take the block to travel from x= 0.180mto x= -0.180m ?
b) If the amplitude is doubled, to 0.180m , how long does it take the block to travel from x= 0.090mto x= -0.090m ?

Answers

Small block is attached to ideal spring and it is moving in SHM on horizontal, frictionless surface : a) time it takes the block to travel from x = 0.180m to x = -0.180m is: t = 5.80s ; b) time it takes the block to travel from x = 0.090m to x = -0.090m is: t' = -0.375s


To solve this problem, we need to use the formula for the period of simple harmonic motion:

T = 2π√(m/k)

where T is the period of the motion, m is the mass of the block, and k is the spring constant. We can also use the fact that the velocity of the block is zero at the endpoints of its motion, so we can use the equation for the velocity of an object in SHM:

v = ±ω√(A² - x²)

where v is the velocity of the block, ω is the angular frequency of the motion, A is the amplitude of the motion, and x is the displacement of the block from its equilibrium position.

a) If the amplitude is doubled to 0.180m, we can use the formula for the period of SHM to find the new period:

T' = 2π√(m/k)'

where T' is the new period, and (m/k)' is the new ratio of mass to spring constant. Since the mass of the block and the spring constant do not change, we have:

(m/k)' = m/k

So we can write:

T' = 2π√(m/k) = 2πT

So the new period is twice the original period. Therefore, the time it takes the block to travel from x = 0.180m to x = -0.180m is:

t = 2T = 2(2.90s) = 5.80s

b) If the amplitude is doubled to 0.180m, we can use the equation for the velocity of the block to find the velocity at x = ±0.090m:

v = ±ω√(A² - x²)

For x = ±0.090m and A = 0.180m, we have:

v = ±ω√(0.180² - 0.090²)

v = ±ω√(0.0144)

v = ±0.12ω

Since the velocity is proportional to the angular frequency, which is inversely proportional to the period, we can write:

v' = ±0.24v

where v' is the new velocity at x = ±0.090m when the amplitude is doubled. Therefore, the time it takes the block to travel from x = 0.090m to x = -0.090m is:

t' = (x2 - x1)/v'

where x2 = -0.090m, x1 = 0.090m, and v' = 0.24v. Substituting the values, we get:

t' = (-0.090m - 0.090m)/(0.24v)

t' = -0.375s

Note that the negative sign indicates that the block is moving in the opposite direction (i.e., towards x = 0) when it reaches the midpoint of its motion.

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two stars have the same temperature, but the radius of one is twice that of the other. how much brighter is the larger star?

Answers

The brightness of a star is determined by its temperature and radius.

The brightness of a star is determined by its temperature and radius. In this case, the two stars have the same temperature, but one has a radius twice as large as the other. The brightness of a star is proportional to the square of its radius and its temperature to the fourth power (Stefan-Boltzmann Law).
Since the temperature is the same, we can focus on the radius difference. The larger star has a radius twice that of the smaller star, so we square this ratio to find the brightness difference: (2R)^2 / (R^2) = 4.
Therefore, the larger star is 4 times brighter than the smaller star.

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you can use the course adjustment knob for focusing when viewing through the oil immersion lens. you can use the course adjustment knob for focusing when viewing through the oil immersion lens. true false

Answers

False. The course adjustment knob should not be used when viewing through the oil immersion lens as it may damage the lens. Instead, the fine adjustment knob should be used to focus on the specimen.

The oil immersion lens is designed to have a very short focal length and requires the use of a special oil with a refractive index similar to that of the lens, allowing for greater resolution and clarity of the image. The use of the course adjustment knob can cause the lens to hit the slide or coverslip, leading to damage or poor quality images.


The statement "You can use the course adjustment knob for focusing when viewing through the oil immersion lens" is false. When using the oil immersion lens, which typically has a 100x magnification, you should not use the coarse adjustment knob for focusing. Instead, you should use the fine adjustment knob to achieve precise focus and avoid damaging the specimen or the lens. The coarse adjustment knob is suitable for lower magnification objectives, while the fine adjustment knob is used for higher magnification objectives, such as the oil immersion lens.:

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A car has a kinetic energy of 4.31 x 10^5 J when traveling at a speed of 24 m/s.
What is its mass?

Answers

Answer: 1496.526 kg

Explanation:

Given the kinetic energy of the car is 4.31 x 10^5 J and the given speed is 24m/s both are in SI units so need to change the units

As we know

KE = 1/2 m v^2

We know K. E and V transposing v on the other side the final equation which we get is

m = 2 X (K.E/v^2)

Substituting the given values in the question in the above equation we finally get

m as 1496.526 kg.

Therefore the answer to the above-given question is 1496.526 kg.

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If the mass of an object is halved and its speed doubled, its momentum will __________.
halve
not change
double
increase by a factor of 4

Answers

If the mass of an object is halved and its speed doubled, its momentum will Remain the same.

What is momentum ?

Momentum is a physical concept that describes the motion of an object. It is a measure of an object's inertia, or its resistance to a change in its velocity. Momentum is a vector quantity, meaning it has both magnitude and direction. The momentum of an object is equal to its mass multiplied by its velocity. Momentum is conserved in closed systems, meaning that the total momentum of a system remains constant unless an external force acts on it. This means that objects in motion will tend to stay in motion and objects at rest will tend to stay at rest unless acted upon by an external force. Momentum is an important concept in Newtonian mechanics, and it is used to describe the motion of objects in a wide range of situations.

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A ball, of mass 100 g, is dropped from a height of 12. m. Its momentum when it strikes the ground is
a. 4.8 kg.m/s
b. 3.3 kgm/s
c. 1.5 kg-m/s
d. 2.4 kg.m/s

Answers

The momentum of ball when it strikes the ground is c)1.5 kg-m/s.

To calculate the momentum when the ball strikes the ground, we first need to find its final velocity. We can use the following equation to do that:
v^2 = u^2 + 2as
where v is the final velocity, u is the initial velocity (0 m/s, since the ball is dropped), a is the acceleration due to gravity (approximately 9.81 m/s^2), and s is the height (12 m).

v^2 = 0^2 + 2(9.81)(12)
v^2 = 235.44
v = √235.44
v ≈ 15.34 m/s

Now, we can calculate the momentum (p) using the equation:
p = mv
where m is the mass of the ball (0.1 kg, since 100 g = 0.1 kg) and v is the final velocity (15.34 m/s).
p = (0.1 kg)(15.34 m/s)
p ≈ 1.534 kg.m/s

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When an object is placed farther from a convex mirror than the focal length, the image is:.

Answers

When an object is placed farther from a convex mirror than the focal length, the image is virtual, upright, and diminished (smaller than the object).

A convex mirror is a type of mirror that curves outward, away from the center. It has a focal length that is always positive.

When an object is placed at a distance greater than the focal length, the light rays diverge and do not converge at a real point.

Instead, they appear to originate from a virtual point behind the mirror. In this case, the image formed is virtual, upright, and diminished.
For objects placed farther from a convex mirror than the focal length, the image created will be virtual, upright, and smaller than the object itself.

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The product (2 amperes × 2 volts × 2 seconds) is equal to
(A) 8 coulombs
(B) 8 newtons
(C) 8 joules
(D) 8 calories
(E) 8 newton-amperes

Answers

The product (2 amperes × 2 volts × 2 seconds) is equal to 8 joules.

The formula for electrical power is P = VI, where P is power in watts, V is voltage in volts, and I is current in amperes. The product of amperes, volts, and seconds can be rearranged as follows:

(2 amperes × 2 volts × 2 seconds) = (2 amperes) × (2 volts) × (2 seconds)

= (4 volts) × (2 seconds) × (2 amperes)

= (4 volts) × (4 coulombs/second)

= 16 joules

However, the question asks for the product in units of coulombs, newtons, joules, calories, or newton-amperes. Since the answer is in joules, the correct option is (C) 8 joules.

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the time-domain expressions for three line-to-neutral voltages at the terminals of a y-connected load are

Answers

The time-domain expressions for the three line-to-line voltages are νAB = 288[tex]\sqrt{3}[/tex] cos (ωt - 105°) V, νBC = 288[tex]\sqrt{3}[/tex] cos (ωt - 120°) V, and νCA = 288[tex]\sqrt{3}[/tex] cos (ωt + 30°) V.

What is voltages?

Voltage is an electrical potential energy difference between two points in an electric circuit. It is measured in volts (V). Voltage is used to push electric current through a circuit. It is the work done per unit charge to move the charge from one point to the other. Voltage is a measure of the potential for electrical energy to move between two points in a circuit.

The time-domain expressions for the three line-to-line voltages can be found by taking the difference between two of the line-to-neutral voltages.
νAB = νAN - νBN = 288 cos (ωt - 45°) - 288 cos (ωt - 165°)
  = 576 cos (ωt - 105°) sin (30°)
  = 288[tex]\sqrt{3}[/tex] cos (ωt - 105°) V
νBC = νBN - νCN = 288 cos (ωt - 165°) - 288 cos (ωt + 75°)
 = 576 cos (ωt - 120°) sin (30°)
  = 288[tex]\sqrt{3}[/tex] cos (ωt - 120°) V
νCA = νCN - νAN = 288 cos (ωt + 75°) - 288 cos (ωt - 45°)
  = 576 cos (ωt + 30°) sin (30°)
  = 288√3 cos (ωt + 30°) V
Therefore, the time-domain expressions for the three line-to-line voltages are νAB = 288[tex]\sqrt{3}[/tex] cos (ωt - 105°) V, νBC = 288[tex]\sqrt{3}[/tex] cos (ωt - 120°) V, and νCA = 288[tex]\sqrt{3}[/tex] cos (ωt + 30°) V.

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Complete Question:
The time-domain expressions for three line-to neutral voltages at the terminals of a Y-connected load are νAN = 288 cos (ωt - 45°) V, νBN = 288 cos (ωt - 165°) V, νCN = 288 cos (ωt + 75°) V. What are the time-domain expressions for the three line-to-line voltages νAB, νBC, and νCA?

on a clear night you look up at the moon overhead. at that moment the moon is pulling on you via gravity with a certain amount of force, f sub moon. considering only magnitudes, how does the force you exert on the moon via gravity compare to f sub moon?

Answers

The force you exert on the moon via gravity is equal in magnitude to F sub moon, as per Newton's Third Law.

The force you exert on the moon via gravity is equal in magnitude to the force the moon exerts on you, which is denoted by F sub moon. This equality is a result of Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. In this context, the action is the gravitational force exerted by the moon on you, and the reaction is the gravitational force you exert on the moon.

Both forces can be calculated using the universal law of gravitation, represented by the equation F = G * (m₁ * m₂) / r², where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the two objects, and r is the distance between their centers. As the equation shows, the force is directly proportional to the product of the masses and inversely proportional to the square of the distance between the objects.

In the scenario you described, the masses involved are your mass and the moon's mass, and the distance is the distance between you and the moon. When calculating the gravitational force between the two objects, the equation will yield the same value for both forces, albeit with opposite directions. Thus, the force you exert on the moon via gravity is equal in magnitude to F sub moon, as per Newton's Third Law.

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a board that is 20.0 cm wide, 5.00 cm thick, and 3.00 m long has a density 650 kg/m3. the board is floating partially submerged in water of density 1000 kg/m3. what fraction of the volume of the board is above the surface of the water?

Answers

The fraction of the volume of the board above the surface of the water is approximately 0.35 or 35%.

1. First, find the volume of the board (V_board) using the formula: V_board = width * thickness * length. Convert the dimensions to meters:
V_board = 0.20 m * 0.05 m * 3.00 m = 0.03 m³

2. Calculate the mass of the board (m_board) using the formula: m_board = density * volume:
m_board = 650 kg/m³ * 0.03 m³ = 19.5 kg

3. Apply Archimedes' principle: the buoyant force (F_b) equals the weight of the displaced water. In equilibrium, the weight of the board (W_board) equals the buoyant force:
W_board = F_b
m_board * g = ρ_water * V_submerged * g

Here, g is the acceleration due to gravity (approximately 9.81 m/s²), and V_submerged is the volume of the submerged part of the board.

4. Cancel out g and solve for V_submerged:
V_submerged = (m_board / ρ_water) = (19.5 kg / 1000 kg/m³) = 0.0195 m³

5. Find the fraction of the volume submerged (f_submerged) and the fraction above the water (f_above) by dividing V_submerged by V_board:
f_submerged = V_submerged / V_board = 0.0195 m³ / 0.03 m³ = 0.65

f_above = 1 - f_submerged = 1 - 0.65 = 0.35

The fraction of the volume of the board above the surface of the water is approximately 0.35, or 35%.

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