Find a, b, c, and d such that the cubic function f(x) = ax3 + bx? + cx + d satisfies the given conditions.
Relative maximum: (2,9)
Relative minimum: (4,3)
Inflection point: (3,6)
a =
b =
C=
d =

Answers

Answer 1

Answer:

[tex]\displaystyle f(x)=\frac{3}{2}x^3-\frac{27}{2}x^2+36x-21[/tex]

Where:

[tex]\displaystyle a=\frac{3}{2}, \, b=-\frac{27}{2}, \, c=36, \text{and } d=-21[/tex]

Step-by-step explanation:

We are given a cubic function:

[tex]f(x)=ax^3+bx^2+cx+d[/tex]

And we want to find a, b, c and d such that the  function has a relative maximum at (2, 9); a relative mininum at (4, 3); and an inflection point at (3, 6).

Since the function has a relative maximum at (2, 9), this means that:

[tex]f(2)=9=a(2)^3+b(2)^2+c(2)+d[/tex]

Simplify:

[tex]8a+4b+2c+d=9[/tex]

Likewise, since it has a relative minimum at (4, 3):

[tex]f(4)=3=a(4)^3+b(4)^2+c(4)+d[/tex]

Simplify:

[tex]64a+16b+4c+d=3[/tex]

We can subtract the first equation from the second. So:

[tex](64a+16b+4c+d)-(8a+4b+2c+d)=(3)-(9)[/tex]

Simplify:

[tex]56a+12b+2c=-6[/tex]

Divide both sides by two. Hence:

[tex]28a+6b+c=-3[/tex]

Relative minima occurs only at the critical points of a function. That is, it occurs whenever the first derivative equals zero.

Find the first derivative. We can treat a, b, c and d as constant. Hence:

[tex]f'(x)=3ax^2+2bx+c[/tex]

Since it has a minima at (2, 9), it means that:

[tex]f'(2)=3a(2)^2+2b(2)+c=0[/tex]

Thus:

[tex]12a+4b+c=0[/tex]

(We will only need one of the two points to complete the problem.)

Inflection points occurs whenever the second derivative of a function equals zero. Find the second derivative:

[tex]f''(x)=6ax+2b[/tex]

Since there is a inflection point at (3, 6):

[tex]18a+2b=0\Rightarrow 9a+b=0[/tex]

Solve for b:

[tex]b=-9a[/tex]

Substitute this into the above equation:

[tex]12a+4(-9a)+c=0[/tex]

Solve for c:

[tex]c=24a[/tex]

Substitute b and c into the previously acquired equation:

[tex]28a+6(-9a)+(24a)=-3[/tex]

Solve for a:

[tex]\displaystyle -2a=-3\Rightarrow a=\frac{3}{2}[/tex]

Solve for b and c:

[tex]\displaystyle b=-9\left(\frac{3}{2}\right)=-\frac{27}{2}\text{ and } c=24\left(\frac{3}{2}\right)=36[/tex]

Using either the very first or second equation, solve for d:

[tex]\displaystyle 8\left(\frac{3}{2}\right)+4\left(-\frac{27}{2}\right)+2(36)+d=9[/tex]

Hence:

[tex]d=-21[/tex]

Hence, our function is:

[tex]\displaystyle f(x)=\frac{3}{2}x^3-\frac{27}{2}x^2+36x-21[/tex]


Related Questions

11. Which point is not on the graph of 2x + 3y - Z - 12 = 0?
(6, 0, 0)
(3,3,3)
(0, 4,0)
(1, 1, 7)

Answers

show the graph? i can’t really tell what the answer is without the graph being there.

What is the value of x

Answers

Answer:

52/3

Step-by-step explanation:

Use basic Thales therom,

[tex]\frac{3x}{4x}=\frac{3x+7}{5x-8}\\\\\frac{3}{4}=\frac{3x+7}{5x-8}\\[/tex]

Cross multiply,

3*(5x-8)=4*(3x+7)

3*5x - 3*8 = 4*3x + 4*7

15x - 24 = 12x +28

Add 24 to both sides

15x = 12x + 28 + 24

15x = 12x + 52

Subtract 12x from both sides

15x-12x =52

3x = 52

Divide both sides by 3

x = 52/3

Please answer i will give you brainlest please help me

Answers

have attached the solution, couldn't solve 13 and 17 tho, if it helps, then do mark me the brainliest...

Btw, which class r u in?

Step-by-step explanation:

Please help! I feel like I'm drowning :(

Answers

Answer:

1d = -3

2b = 2

2c = 1

3a = 3

3d = 4

Step-by-step explanation:

Polynomial 1: [tex]x^2-8x+15[/tex]

Multiply the leading coefficient, 1, and the last term, 15. You get: 15.

Then, list out the factors of 15 and the addends of -8 until you get two of numbers that are the same:

Factors of 15: -5 * -3

Addends of -8: -5 + -3

Replace the -8x with -5x - 3x:

[tex]x^2-5x-3x+15[/tex]

Put parentheses around the first 2 terms & last 2 terms and factor like so:

[tex](x^2-5x)-(3x+15)[/tex]

[tex]x(x-5)-3(x-5)[/tex]

[tex](x-5)(x-3)[/tex]

Looking at the answer (ax + b)(cx + d), d would correspond with -3.

Polynomial 2: [tex]2x^3-8x^2-24x[/tex]

First factor out the x:

[tex]x(2x^{2}-8x-24)[/tex]

Divide the polynomial inside by 2 and place the 2 outside with the x:

[tex]2x(x^2-4x-12)[/tex]

Then find the factors of 1*-12 and the addends of -4 and see which two numbers match:

Factors of -12: -6 * 2

Addends of -4: -6 + 2

Replace the -8x with -6x + 2x:

[tex]2x(x^2-6x+2x-12)[/tex]

Put parentheses around the first 2 terms & last 2 terms and factor like so:

[tex]2x((x^2-6x)+(2x-12))[/tex]

[tex]2x(x(x-6)+2(x-6))[/tex]

[tex]2x((x+2)(x-6))[/tex]

[tex]2x(x+2)(x-6)[/tex]

Looking at the answer (2x)(ax + b)(cx + d), b & c would correspond with 2 & 1.

Polynomial 3: [tex]6x^2+14x+4[/tex]

Divide the polynomial by 2:

[tex](2)(3x^2+7x+2)[/tex]

Find the factors of 3*2 and the addends of 7 and see which two numbers match:

Factors of 6: 6 * 1

Addends of 7: 6 + 1

Replace the 7x with 6x + x:

[tex](2)(3x^2+6x+x+2)[/tex]

Put parentheses around the first 2 terms & last 2 terms and factor like so:

[tex](2)((3x^2+6x)+(x+2))[/tex]

[tex](2)(3x(x+2)+(x+2))[/tex]

[tex](2)((3x+1)(x+2))[/tex]

[tex](2)(3x+1)(x+2)[/tex]

Then multiply the 2 with the (x+2) and here's your final answer:

[tex](3x+1)(2x+4))[/tex]

Looking at the answer (ax + b)(cx + d), a & d correspond with 3 & 4.

Hope that helps (●'◡'●)

(This took a while to write, sorry about that)

PLEASE HELP!!! I have been adding and multiplying many different ways however my answer are wrong. How do I go about solving the perimeter then?

Answers

Answer:

66 m

Step-by-step explanation:

First, lets add up the numbers you know. It should be:

16, 8, 17, and 7.

Add them all up, and you will get:

48.

For the last two sides, subtract 7 from 16 to get 9.

For the last slide, subtract 8 from 17 to get 9.

Add them all up, and get 66.

What is the approximate percent change in temperature that went down from 120 degrees to 100 degrees?

Answers

The answer would be approximately 17%.

Answer:

17%

Step-by-step explanation:

change in temprature=100-120=-20

% chsnge in temp.=-20/120 ×100=-50/3 %=-16.66666...≈-17%

negative sign shows temperature is coming down.

Frans paid R9600 as interest on a loan he took 5 years ago at 16% rate. What's was the amount he took as loan?

Answers

Step-by-step explanation:

Interest (I)=R9600

Rate(R)=16%

Time (T)=5years

Principal (P)=?

P=100×I÷R×T

P=100×R9600÷16×5

P=R960000÷80

P=R12, 000

Answer:

      The amount he took as loan = R12,000

Step-by-step explanation:

Simple Interest

Let loan amount be = P

R = 16%

T = 5years

I = 9600

Find P

  [tex]I = \frac{PRT}{100}\\\\9600 = \frac{P \times 16 \times 5}{100}\\\\P = \frac{9600 \times 100}{16 \times 5} = 12,000[/tex]

Here is the general information about the Learn by Doing discussion board exercises (directions, grading, feedback). Prompt
1) Give an example of a research question that involves estimating a characteristic about the population of part-time students at your college.
2) Improve this poorly stated research question: Do students work a lot of hours

Answers

Answer:

Step-by-step explanation:

Answer to question 1:

On average do part-time students spend less than 20 hours per work on academic work and assignments ?

Answer to question 2:

On average do students work greater than 50 hours a week ?

87,521 rounded to the nearest hundred

Answers

Answer:

87,500

Step-by-step explanation:

Since the last 2 digits arent 5 or greater than 5 it can not be rounded to the next hundred.

Answer:

875

Step-by-step explanation:

th t h t u

8 7 5 2 1

the hundred is 5 so the next digit after that is 2 remember 0 to 4 round down 5 to 9 round up

so 875

If 128x is a perfect square number what is the least value of x

Please answer the question fast​

Answers

Answer:

in a square all sides are equal so x has to equal

128

Hope This Helps!!!

You need
1
1
4
feet of string to make 20 holiday ornaments.

To make 14 holiday ornaments, you will need
feet of string.

Answers

Answer:

79.8

Step-by-step explanation:

math

Enunciate demerits of classical probability.

Answers

Answer:

Some demerits of classical probability are provided throughout the following portion.

Step-by-step explanation:

This could only be utilized if somehow the occurrences are fairly probable as well as predictable. Such supposition is established far in advance of the investigation or testing.This only applies whereas if an overall number of occurrences seems to be limited, one such term has quite a restricted scope, such as coins tossing, picking card numbers, etc.

please help i guess on a

Answers

Answer:

A = (2, 2)

B = (3, -1)

C = (-1, 0)

Step-by-step explanation:

To translate a point, you have to translate each individual point. At the bottom it shows <-2,3>, therefore you have to translate x 2 units to the left (because it's negative meaning the number is going away from 0, and 3 units to the right because 3 is a positive number.)

First Point A:

x: 4 - 2 = 2; y: -1 + 3 = 2

Second Point B:

x: 5 - 2 = 3; y: -4 + 3 = -1

Lastly, Point C:

x: 1 - 2 = -1, y: -3 + 3 = 0

I hope this helps!

Which of the following rational functions is graphed below?

Answers

Answer:

the answer is d

Step-by-step explanation:

because when we put-1 from x the equation hasn't any value

determine the 2nd and 3rd terms of a geometric sequence of which T1 =5 and T4=40​

Answers

Answer:

Second term of this sequence: [tex]10[/tex].

Third term of this sequence: [tex]20[/tex].

Step-by-step explanation:

The first step is to find the common ratio of this sequence.

In a geometric sequence, multiply one term by the common ratio to find an expression for the next term. Let [tex]r[/tex] denote the common ratio of this sequence. For this sequence:

The first term of this sequence is [tex]5[/tex]. Multiply the first term by the common ratio to find an expression for the third term: [tex]5\, r[/tex].Multiply the second term by the common ratio to find an expression for the fourth term: [tex]5\, r^{2}[/tex].Similarly, an expression for the the fourth term would be: [tex]5\, r^{3}[/tex].

However, the question states that the value of the fourth term is [tex]40[/tex]. In other words, [tex]5\, r^{3} = 40[/tex].

Solve this equation for [tex]r[/tex]:

[tex]r^{3} = 8[/tex].

[tex]r = 2[/tex].

(Since the power of [tex]r[/tex] is non-even in the equation, there's no need to consider the sign of [tex]r\![/tex] when taking the cube root.)

Substitute [tex]r = 2[/tex] into the expression for the second term and the third term to find their values:

Second term: [tex]5\, r = 10[/tex].Third term: [tex]5\, r^{2} = 20[/tex].

The graph of f(x)=x^2 is shown. Compare the graph of f(x) with the graph of g(x)=x^2+8

Answers

Answer:

D

Step-by-step explanation:

Number 8 is not related to the x, but is related to the the function. so g(x) is 8 units above f (x)

Answer:

D. 8 units above the graph

Step-by-step explanation:

y = mx + b

this formula is basically y = x^2 + 8

+8 part means where it is on the y axis

if it were y = (x+6)^2 + 8

it would also be on 6 places to the left on the x axis

Please look at the included picture, show me your work and please include a good explanation. It would really help me out here.

Answers

These are indeed equivalent, and this identity is one of DeMorgan's laws.

The 6th column is the negation of the 5th column. For example, the first row says

not p or q

is true (T), so the negation would be false (F). The 5th column reads {T, F, T, T}, so the next column should be {F, T, F, F}.

Then in the 7th/last column, you are checking the truth value of the statement

p and not q

For example, in the first row, both p and q are true (T). This means (not q) is false, so (p and not q) is false (F). The last column should end up reading {F, T, F, F}, same as the previous column.

A plane flying horizontally at an altitude of 2 miles and a speed of 410 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 5 miles away from the station.

Answers

Answer:

[tex]82\sqrt{21}\text{ or approximately 375.77 miles per hour}[/tex]

Step-by-step explanation:

Please refer to the diagram below. R is the radar station and x is the distance from the station to the plane.

We are given that the plane is flying horizontally at an altitude of two miles and at a speed of 410 mph. And we want to find the rate at which the distance from the plane to the station is increasing when it is five miles away from the station.

In other words, given da/dt = 410 and x = 5, find dx/dt.

From the Pythagorean Theorem:

[tex]a^2+4=x^2[/tex]

Implicitly differentiate both sides with respect to time t. Both a and x are functions of t. Hence:

[tex]\displaystyle 2a\frac{da}{dt}=2x\frac{dx}{dt}[/tex]

Simplify:

[tex]\displaystyle a\frac{da}{dt}=x\frac{dx}{dt}[/tex]

Find a when x = 5:

[tex]a=\sqrt{5^2-2^2}=\sqrt{21}[/tex]

Therefore, dx/dt when da/dt = 410, x = 5, and a = √(21) is:

[tex]\displaystyle \frac{dx}{dt}=\frac{(\sqrt{21})(410)}{5}=82\sqrt{21}\approx 375.77\text{ mph}[/tex]

The rate at which is distance from the plane to the radar station is increasing at a rate of approximately 375.77 miles per hour.

What is the probability that this spinner will stop on blue or white when it is spun?

1/4 is white
1/4 is purple
1/4 is blue
1/4 is black

Answers

Answer:

1/2 or 50-50

Step-by-step explanation:

1/4 +1/4 = 1/2 or 50-50

Cho hàm số f(x, y) = ln(x
2 + y
2
).
a) Tính f

x
, f′
y
;
b) Tính f

x
(2; 1), f′
y
(2; 1).

Answers

Answer:

Sorry, I can't understand in which language you have written......

Step-by-step explanation:

So if you tell me the question in English then I can answer

suppose y varies inversely with X, and y = 48 when x = 3. What is the value of x when y = 24?
NO LINKS OR ANSWERING YOU DON'T KNOW.

a. 3
b. 12
c. 6
d. 24​

Answers

Answer:

C. 6

Step-by-step explanation:

Recall that inverse variation is given by:

[tex]\displaystyle y=\frac{k}{x}[/tex]

Where k is the constant of variation.

We know that y = 48 when x = 3. Substitute:

[tex]\displaystyle (48)=\frac{k}{(3)}[/tex]

Solve for k:

[tex]k=3(48)=144[/tex]

Hence, our equation is:

[tex]\displaystyle y=\frac{144}{x}[/tex]

We want to find x when y = 24. Substitute:

[tex]\displaystyle \frac{24}{1}=\frac{144}{x}[/tex]

Cross-multiply:

[tex]24x=144[/tex]

Divide both sides by 24. Hence:

[tex]x=6[/tex]

Our answer is C.

A projectile is fired from ground level with an initial velocity of 35 m/s at an angle of 35° with the horizontal. How long
will it take for the projectile to reach the ground?

Answers

Answer:

Step-by-step explanation:

We will work in the y-dimension only here. What we need to remember is that acceleration in this dimension is -9.8 m/s/s and that when the projectile reaches its max height, it is here that the final velocity = 0. Another thing we have to remember is that an object reaches its max height exactly halfway through its travels. Putting all of that together, we will solve for t using the following equation.

[tex]v=v_0+at[/tex]

BUT we do not have the upwards velocity of the projectile, we only have the "blanket" velocity. Initial velocity is different in both the x and y dimension. We have formulas to find the initial velocity having been given the "blanket" (or generic) velocity and the angle of inclination. Since we are only working in the y dimension, the formula is

[tex]v_{0y}=V_0sin\theta[/tex] so solving for this initial velocity specific to the y dimension:

[tex]v_{0y}=35sin(35)[/tex] so

[tex]v_{0y}=[/tex] 2.0 × 10¹ m/s

NOW we can fill in our equation from above:

0 = 2.0 × 10¹ + (-9.8)t and

-2.0 × 10¹ = -9.8t so

t = 2.0 seconds

This is how long it takes for the projectile to reach its max height. It will then fall back down to the ground for a total time of 4.0 seconds.

If the rectangle were translated three units down, then reflected across the y-axis, what would be the coordinates of point D ?

Answers

Answer

all y values change sign that is reflection over x axis SKETCH IT !!!!

More

How many fixed-requirement constraints does a transportation problem with 5 factories and 6 customers have?a. 30.b. 11.c. 6.d. 5.

Answers

Answer:

Option B

Step-by-step explanation:

From the question we are told that:

Demand point [tex]m=5[/tex]

Supply Point [tex]n=6[/tex]

Generally the equation for fixed-requirement constraints is mathematically given by

 [tex]X=m+n[/tex]

 [tex]X=5+6[/tex]

 [tex]X=11[/tex]

Therefore the correct option is

Option B

Triangle A'B'C' is formed using the translation (x + 2 y + 0) and the dilation by a scale factor of 1/2 from the origin. Which equation explains the relationship between
AB and A"B"?

Answers

Answer:

[tex]A"B" = \frac{AB}{2}[/tex]

Step-by-step explanation:

Given

[tex]k = \frac{1}{2}[/tex] --- scale factor

Required

Relationship between AB and A"B"

[tex]k = \frac{1}{2}[/tex] implies that the sides of A"B"C" are smaller than ABC

i.e.

[tex]A"B" = k * AB[/tex]

[tex]A"B" = \frac{1}{2} * AB[/tex]

This gives:

[tex]A"B" = \frac{AB}{2}[/tex]

one story with author and summary please​

Answers

Answer:

The story tells of a plain-looking little bird (the Ugly Duckling) born in a barnyard. His brothers and sisters as well as the other birds and animals on the farm tease him for being plain and ugly, so he runs off to live with a flock of wild ducks and geese until hunters shoot down the flock. Alone again, the Ugly Duckling finds a home with an old woman, but her cat and hen also tease him, so he doesn't stay there long.

In his wanderings, the Ugly Duckling comes across a flock of migrating swans, and he wishes to join them but can't because he's too young and can't fly well enough. When winter sets in, a farmer rescues the Ugly Duckling, but the farmer's children and other animals frighten him with their noise and teasing, so again, he flees. He spends a cold and lonely winter hiding in a cave until springtime, when the flock of swans comes to the lake near his hiding place.

When the Ugly Duckling approaches the swans, he's delighted to find that they accept him and treat him like one of them. When he looks at his reflection in the lake, he realizes, to his astonishment, that he's matured into a beautiful swan himself. When the swans fly off from the lake, he spreads his wings and joins them, finally having found a family who accepts him.

A particular network service provider charges 50 Kobo per second to make a call. How many minutes will a caller with 300 naira airtime last.​

Answers

9514 1404 393

Answer:

  10 minutes

Step-by-step explanation:

The current legal tender conversion rate is 50 kobo = 0.50 naira. Then the airtime balance is ...

  (300 NGN)/(0.50 NGN/s) × (1 min)/(60 s) = 300/(0.50×60) min = 10 min

Amy types at an average speed of 38 words per rinute. She has already typed 1,450 words of her final paper, which will be more than 4,000
words. Which inequality can be used to solve for x, the number of minutes it will take Amy to finish typing her paper?
ОА.
38x-1,450 > 76
OB.
38[X+1,450) > 4,000
Ос. .
38x> 4,000
OD.
38x + 1,450 > 4,000
Reset
Next
ntum. All rights reserved.
o
74°F Mostly cloudy
I
о
m
De here to search

Answers

Answer: D. 38x + 1,450 > 4,000

Step-by-step explanation:

It has to be greater than 4,000 so A makes no sense

The parentheses are in the wrong place completely changing the meaning for B

C disregards the info we have about how she's already typed 1,450 words

The answer has to be D

Write an algebraic expression for the
following
I start with x, add 4, square the answer
and then multiply it by 3​

Answers

Answer

(x+4)^2x3

Step-by-step explanation:

so x add 4 is obviously x add 4 but since you want to square it you have to put x add 4 in brackets like this

(x+4)

you put the square symbol next to the brackets because you only want to square whats inside the brackets

(x+4)^2

and then you put times 3 so you can multiply everything by it so now its

(x+4)^2x3

If s(x)= 2 -x^2 and f(x)=3x, which value is equivalent to (s°f)(-7)

Answers

I got ((sof)-7) = -439
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