Find a linear function f, given f(6) = - 4 and f(-3) = - 10. Then find f(0).
f(x)=0
(Type an expression using x as the variable. Simplify your answer.)
f(0) = (Simplify your answer.)

PLZ HELP

the answer is in the picture

Answer:

Step-by-step explanation:

2/a = 1/b - 1/d

2d/a = d/b - 1

2d/a - d/b = -1

d(2/a - 1/b) = -1

d(2b-a)/(ab) = -1

d(a-2b)/(ab) = 1

d = ab/(a-2b)

Answer: Amy is incorrect. The answer is -5 points.

Step-by-step explanation:

From the question, we are informed that Amanda earned 20 points for winning a sprint in the first race but got -25 points in the second race.

Based on the information above, Amanda's total score now will be:

= 20 + (-25)

= 20 - 25

= -5

The answer is -5 points.

Amy is wrong because (+) × (-) = (-)

Answer: a good amount

Step-by-step explanation:

because if you just get a table spoon for all flavour mixtures then wala they are all the same amount -__-------------i is not smart at all srry

Answer:

18

Step-by-step explanation:

Because the diagonals in a parallelogram bisect each other, RS = SP = 18

BRAINLIEST PLEASEEEEE

Answer:

f(x) = [tex]\sqrt{x+5}[/tex] : All real numbers greater than/equal to 5

Explanation: you can't square root negative numbers, and any number less than 5 would give us negative.

f(x) = [tex]\frac{7}{x-8}[/tex] : All real numbers except 8

Explanation: You can't divide by 0, and if we included 8 in the number set, we would get this: [tex]\frac{7}{8-8} =\frac{7}{0}[/tex] (this is impossible).

f(x) = [tex]\sqrt{2}[/tex] : All positive real numbers and 0

Explanation: Again, you can't square root negative numbers.

f(x) = 8x : All real numbers

Not much to explain for this one, any real number makes this equation true.

Answer:

44

Step-by-step explanation:

* means multiply

put 8 where the x is

6 * 8 - 4

48 - 4

44

Answer:

75.4

Step-by-step explanation:

75.4area of cylinder is 2pie r h plus 2 pie * 2^2

Answer:

Step-by-step explanation:

-2y³ +  4 - (-3 - 2y³ - y - 5y²) = -2y³ + 4 + 3 + 2y³ + y + 5y²

                                             = -2y³ + 2y³  +5y² + y   + 4 + 3 {combine like terms}

                                             =  5y² +y + 7

Answer:

$29.69

Step-by-step explanation:

23.52 * 1.1 = $25.872 so this is the marked up price. ----- (1.1 = 110%)

25.872 * 0.1475 = $3.81612  is the sales tax.

Total is 25.872 + 3.81612  ~ $29.69

Answer: 21, 28

Step-by-step explanation:

Use the Pythagorean Theorem [tex]a^{2}+b^{2}=c^{2}[/tex]:

Substitute in the values & solve:

[tex]x^{2}+(x+7)^{2}=35^{2}\\x^{2}+x^{2}+14x+49=1225\\2x^{2}+14x+49-1225=0\\2x^{2}+14x-1176=0\\2(x^{2}+7x-588)=0\\2(x + 28)(x - 21)=0\\x_{1}=-28, x_{2}=21[/tex]

-28 is not a possible solution since you can't have negative inches...

Answer:

3

Step-by-step explanation:

Your answer is 2.98004491789381.

Answer:

1344.

Step-by-step explanation :

.

The speed of the jet will be 166.4. If the jet fly for 12 hours, then the distance cover will be 1996.8.

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

A jet travels 832 km in 5 hours.

Then the speed of the jet will be

Speed = 832 / 5

Speed = 166.4 km per hours

If the jet fly for 12 hours, then the distance cover will be

Distance = Speed x Time

Distance = 166.4 x 12

Distance = 1996.8 km

More about the speed link is given below.

https://brainly.com/question/7359669

#SPJ2

Answer:Vertex at (3, -2)

Step-by-step explanation:

Answer:

Missing angle A = 56.1° (approximately)

Step-by-step explanation:

<A = arcsin(a×sin(C)/c)

= arcsin(5×sin 95/6)

= 56.1154084° ≈ 56.1°

Answered by GAUTHMATH

Answer:

358

Step-by-step explanation:

the step by step is in the photo so look at it

Answer:

80in 2

Step-by-step explanation:

Answer:

a=(d1×d2)÷2

(20×12)÷2

240/2

120

Answer:

<ABD = 42 degrees

<ABC = 84 degrees

Step-by-step explanation:

<ABC = 42 + 42 = 84

Hi there!

We know that the angles ∠B and ∠A are supplementary because they are both interior angles. Therefore:

180 = ∠A + ∠B

Rewrite:

180 = (6x - 48) + (4x + 38)

Combine like terms:

180 = 10x - 10

Solve for x:

190 = 10x

x = 19

Solve for ∠B by plugging in this value of x:

∠B = 4(19) + 38

∠B = 76 + 38

∠B = 114

Answer:

solution

here,

Step-by-step explanation:

f={(2,1/2), ( 3, 1/3) , (4, 1/4)}

Range = { / (\ frac 12\) , \ (\ frac 13\) ,

\( \ frac 14\ )}

Inverse function ( f-^1 ) = {( 1/2, 2) ,( 1/3 ,3) , 1/4, 4 )} is the required answer

Answers:

y intercept = -4

slope = -1

==========================================

Explanation:

The given equation is the same as y = -1x + (-4)

Compare this to y = mx+b form, and we see that

m = -1 is the slope

b = -4 is the y intercept

To graph y = -x-4, you could plot the two points (0,-4) and (1,-5) and draw a straight line through them. Extend the line as far as you can in either direction.

Notice how going from (0,-4) to (1,-5) follows the process "down 1, right 1" which is directly pulled from the slope = -1 =  -1/1.

Answer:

Step-by-step explanation:

cos x=sinx

divide by cos x

1=tan x

tan x=1

[tex]tan x=1=tan \frac{\pi }{4}=tan (n\pi +\frac{\pi }{4})\\x=n\pi +\frac{\pi }{4} ,\\where~n~is~an~integer.[/tex]

Answer:

11. 90

12. 90

13. 90

14. 90

15. 180

16. 135

17. 225

18. 270

Step-by-step explanation:

Answer:

BC=90

AC=90

AE=90

EB=90

ACB=180

AD=135

CBF=225

ADC=270

Step-by-step explanation:

for numbers 11-14 they're all linear pairs which means they're each 90 degrees

and as long as O is the center point, all the arcs are the same value as the degree.

for numbers 16-17 you can assume that line FO and DO bisects the right angles which makes them 45 degrees

and for 18, you just multiply 3 and 90 degrees

Answer:

a)4

Step-by-step explanation:

(a+b)²=43 eqn 1

(a²+b²)=35 eqn 2

solving eqn 2 by putting the value of (a+b)² by eqn 1

hope it helps

Answer:

[tex]10[/tex].

Step-by-step explanation:

See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".

Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:

[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.

Sum of these digits:

[tex]\text{A} + 9\, x= 2021[/tex].

Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].

Therefore:

[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].

[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].

[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].

Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].

Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Proof:

The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".

For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.

Either of the following must be true:

If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.

Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.

let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].

Step-by-step explanation:

hope it helps you.........

Answer:

[tex]here \: is \: your \: solution : - \\ \\ here \: is \: a \: right \: traingle \: with \\ \\ base \: = 52 \: units \\ \\ hypotenuse \: = 65 \: units \\ \\ perpendicular \: = {?} \\ \\ we \: need \: to \: find \: perpendicular \\ \\ by \: using \: pythagorus \: theorem : - \\ \\ perpendicular ^{2} \: = base ^{2} + perpendicular ^{2} \: \\ \\ perpendicular^{2} \: = 65 {}^{2} - 52 {}^{2} \\ \\ perpendicular {}^{2} = (4225 - 2704) \\ \\ perpendicular {}^{2} = 1521 \\ \\ perpendicular = \sqrt{1521} \\ \\ perpendicular = 39 \: units \: \\ \\ hope \: it \: helps \: you \: [/tex]