Answers
Answer: No this is not a linear function as the y values have different first differences.
Step-by-step explanation:
First we look at the x values. We start off and look at the second x value and subtract the first x value from it (That would be 1-0) and that equals to 1. Then we look at the third x value and subtract the second x value from it (2-1) and that equals to 1. Then we look at the fourth x value and subtract the third x value from it (That would be 3-2) and that is 1. Next we look at the fifth x value and subtract the fourth x value from it (That would be 4-3) and that is 1.
Now we look at the y values and do the same thing as with the x values. We start off and look at the second y value and subtract the first y value from it (That would be 1-0) and that equals to 1. Then we look at the third y value and subtract the second y value from it (4-1) and that equals to 3. Then we look at the fourth y value and subtract the third y value from it (That would be 9-4) and that is 5. Next we look at the fifth y value and subtract the fourth y value from it (That would be 16-9) and that is 7.
Even though the x values all have the same first differences, the y values do not and so this cannot be a linear function.
I hope this helps. Tell me if something doesn't make sense.
Answer:
No, it is a quadratic relation.
Step-by-step explanation:
Work out the first differences between the given y-values:
[tex]0 \underset{+1}{\longrightarrow} 1 \underset{+3}{\longrightarrow} 4 \underset{+5}{\longrightarrow} 9 \underset{+7}{\longrightarrow} 16[/tex]
As the first differences are not the same, this is not a linear relation.
Work out the second differences:
[tex]1 \underset{+2}{\longrightarrow} 3\underset{+2}{\longrightarrow}5\underset{+2}{\longrightarrow}7[/tex]
As the second differences are the same, the relation is quadratic and will contain an x² term. The coefficient of x² is always half of the second difference. As the second difference is 2, the coefficient of x² is one.
[tex]\begin{array}{|c|c|c|c|c|c|}\cline{1-6}x & 0 & 1 & 2 & 3 & 4\\\cline{1-6}x^2 & 0 & 1 & 4 & 9 & 16\\\cline{1-6}\end{array}[/tex]
Comparing x² with the given y-values, we can see that no further operation is needed. Therefore, the relation is quadratic and the equation is [tex]y=x^2[/tex].
Related Questions
If 2 = x3, then x equals
A 05
B 01
C | 1
D 5
Answers
Answer:
D.
Step-by-step explanation:
If p(x,3) Q(7,1) and pQ(15) unit find the possible value of x
Answers
Answer:
Step-by-step explanation: P(x 3), Q(7, -1) and PQ= 5 .
To Find :
The possible value of x.
Solution :
We know, distance between two points in coordinate plane is given by :
Therefore, the possible value of x are 10 and 4.
greatest common factor of 24,36, and 96
Answers
Answer:
12
Step-by-step explanation:
[tex]24=2^{3} \times 3 \\ \\ 36=2^{2} \times 3^{2} \\ \\ 96=2^{5} \times 3[/tex]
Hey there!
What is GCF (Greatest Common Factor)?
Basically, the GCF is the biggest number in a data set that all of your numbers share.
What are the factors of the numbers?
24:1, 2, 3, 4, 6, 8, 12, and 24
36: 1, 2, 3, 4, 6, 9, 12, 18, and 36
96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96
What are the like terms that the numbers share?
1, 2, 3, 4, 6, 8, and 12
What is the biggest number out of the like terms?
12
What is your number?
12
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
When the dollar price of pounds rises, for example, from $1 = 1 pound to $2 = 1 pound, the dollar has ______ relative to the pound.
Answers
The dollar gains depreciated relative to the pound when the price of pounds in dollars increases, for instance, from $1 = 1 pound to $2 = 1 pound.
What is Depreciated relative?Devaluation of a currency can take place in both absolute and relative terms. When the value of one currency declines in relation to the values of other currencies, this is referred to as a relative devaluation. For instance, the British pound sterling may be worth more today than it did yesterday in terms of US dollars.
A currency's value declines when compared to other currencies, which is known as currency depreciation. Political unrest, interest rate differences, weak economic fundamentals, and investor risk aversion are a few examples of the causes of currency devaluation.
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3. Use the image to answer the following questions.
will brainiest if correct. try ur best!
(a) The angle pitch of a roof is safest when measuring between 18° – 27°. According to these guidelines, is the roof pictured in the image safe? (Note:
(b) What is length of the roof line (segment PR)? Round answer to the nearest tenth of a foot and show all your work.
Answer:
Answers
Answer:
Step-by-step explanation:
For missing hypotenuse: [tex]\sqrt({a^{2} + b^{2})[/tex]
Plug in the side lengths that are known to find the hypotenuse.
1. No, the angle is less than 18 degrees (closer to 15), so it is not safe
2. The length rounded to the nearest tenth is approximately 15.5 feet.
how to solve problem in the document
Answers
The number of views on a viral video can be modeled by the function p(t)=590(5)^3t . Write an equivalent function of the form p(t)=ab^t
Answers
Answer:
p(t) = 2950^3t
Step-by-step explanation:
I’m not sure if this is exactly what you wanted or not. Please let me know more info and I’ll write any more answers for this question in the comments. Have a great day!!
Which of the x values are solutions to the inequality 4(2 – x) > –2x – 3(4x 1)? check all that apply.
Answers
The solution for the inequality given exists x > -11/10. The inequality contains an infinite number of solutions as long as it is greater than -11/10.
How to determine the value of x?
Given: 4(2 – x) > –2x – 3(4x + 1)
The inequality can be simplified to
8 - 4x > -14x - 3
subtract 8 from both sides of the equation, and we get
8 - 4x - 8 > -14x - 3 - 8
- 4x > -14x - 11
Add 14x from both sides
- 4x + 14x > -14x - 11 + 14x
10x > - 11
x > - 11/10
The solution for the inequality given exists x > -11/10. This means that any number greater than -11/10 exists as a solution to the inequality given. The inequality contains an infinite number of solutions as long as it is greater than -11/10.
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Answer: C,E
Step-by-step explanation:
you did the work
Find the value of the indicated variable.
Answers
102 degrees
Step-by-step explanation:
Angles in a quadrilateral add to 360 degrees.
y = 360 - (120 + 85 + 53)
y = 360 - 258
y = 102 degrees
Mike wants to find the confidence interval for a set of data. he knows the sample size and the sample proportion. which other piece of information does he need to determine the confidence interval?
Answers
Using the formula for a z-distribution confidence interval of proportions, he also needs to know the confidence level.
What is a confidence interval of proportions?A confidence interval of proportions is given by:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which:
[tex]\pi[/tex] is the sample proportion.z is the critical value.n is the sample size.Of these 3 itens, the problem states that he knows the sample size and the sample proportion, hence he needs to know z to determine the confidence interval. z depends on the confidence level, which is the remaining parameter.
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Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle. y = 2 x , y = 2 x2 , x = 4
Answers
The region enclosed by the given curves are integrated with respect to x and the area is 4.2724 square units.
In this question,
The curves are y = 2/x, y = 2/x^2, x = 4
The diagram below shows the region enclosed by the given curves.
From the diagram, the limit of x is from 1 to 4.
The given curves are integrated with respect to x and the area is calculated as
[tex]A=\int\limits^4_1 {\frac{2}{x} } \, dx -\int\limits^4_1 {\frac{2}{x^{2} } } \, dx[/tex]
⇒ [tex]A=2[\int\limits^4_1 {\frac{1}{x} } \, dx -\int\limits^4_1 {\frac{1}{x^{2} } } \, dx][/tex]
⇒ [tex]A=2[\int\limits^4_1( {\frac{1}{x} } - {\frac{1}{x^{2} } } )\, dx][/tex]
⇒ [tex]A=2[lnx-\frac{1}{x} ] \limits^4_1[/tex]
⇒ [tex]A=2[(ln4-\frac{1}{4} )-(ln1-\frac{1}{1} )][/tex]
⇒ A = 2[(1.3862-0.25) - (0-1)]
⇒ A = 2[1.1362 + 1]
⇒ A = 2[2.1362]
⇒ A = 4.2724 square units.
Hence we can conclude that the region enclosed by the given curves are integrated with respect to x and the area is 4.2724 square units.
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(3x^{4} +3x^{3}+5x^{2})-(x^{4}-6x^{3}+5x^{2} )
Answers
Answer: x^{3}(2x+9)
Step-by-step explanation:
Eliminate redundant parentheses:
(3x^{4}+3x^{3}+5x^{2})-1(x^{4}-6x^{3}+5x^{2})
3x^{4}+3x^{3}+5x^{2}-1(x^{4}-6x^{3}+5x^{2})
Distribute:
^{4}+3x^{3}+5x^{2}{-1(x^{4}-6x^{3}+5x^{2})}
3x^{4}+3x^{3}+5x^{2}
Combine like terms UNTIL YOU FIND ONE FACTOR
Please help me
Prove the following identity. Include a complete proof in proper form
1/1-sin x-1/1+sin x=2 tan x/COS X
Answers
By using algebra properties and trigonometric formulas we find that the trigonometric expression [tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex] is equivalent to the trigonometric expression [tex]\frac{2\cdot \tan x}{\cos x}[/tex].
How to prove a trigonometric equivalence by algebraic and trigonometric proceduresIn this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:
[tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex] Given.
[tex]\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}[/tex] Subtraction between fractions with different denominator / (- 1) · a = - a.
[tex]\frac{2\cdot \sin x}{\cos^{2}x}[/tex] Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)
[tex]\frac{2\cdot \tan x}{\cos x}[/tex] Definition of tangent / Result
By using algebra properties and trigonometric formulas we conclude that the trigonometric expression [tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex] is equal to the trigonometric expression [tex]\frac{2\cdot \tan x}{\cos x}[/tex]. Hence, the former expression is equivalent to the latter one.
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To gain a pass a student needs to achieve a mean of at least 60% in eight tests. In the first seven
tests the student achieved a mean of 54%. What percentage must the student achieve in test eight
if they are to pass the course?
Answers
Step-by-step explanation:
the mean value is the sum of all data points divided by the number of data points.
first we have 7 tests and their mean value :
(t1 + t2 + t3 + t4 + t5 + t6 + t7) / 7 = 54
that means
(t1 + t2 + t3 + t4 + t5 + t6 + t7) = 54 × 7 = 378
in order for the mean value to be at least 60% after 8 tests, we need to add a t8, so that
(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) = 60 × 8 = 480
because only then we have
(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) / 8 = 60
and the student passes.
so,
(t1 + t2 + t3 + t4 + t5 + t6 + t7) + t8 = 480
378 + t8 = 480
t8 = 480 - 378 = 102%
the student would have to achieve 102% on the 8th test.
which would be normally impossible, but maybe the tests involve some bonus points.
The floor of a rectangular room measures 5m by 4m and the ceiling is 3m from the floor. An ant is at the top of a corner of the room and crawls to the opposite bottom corner of the room. Find the shortest distance it can travel. (Cannot do its diagonal distance)
Answers
Answer:
12 m
Step-by-step explanation:
Well, imagine you got this nice room. How can it reach the other corner? It has to go along the 3 dimensions. So the shortest path would be: 5 + 4 + 3 12m
Answer:
3 + √(41) = 9.4 m (nearest tenth)
Step-by-step explanation:
The room can be modeled as a rectangular prism with:
width = 4 mlength = 5 mheight = 3 mIf the ant is at the top of a corner of a room and crawls to the opposite bottom corner of the room, the shortest distance will be to travel down one vertical edge of the room then to travel the diagonal of the floor of the room (or to travel the diagonal of the ceiling and then one vertical edge).
Vertical edge = height of room = 3m
The diagonal of the floor (or ceiling) is the hypotenuse of a right triangle with legs of the width and length. Therefore, to find the diagonal, use Pythagoras Theorem.
Pythagoras Theorem
[tex]a^2+b^2=c^2[/tex]
where:
a and b are the legs of the right trianglec is the hypotenuse (longest side) of the right triangleGiven:
a = width = 4 mb = length = 5 mc = diagonalSubstitute the given values into the formula and solve for c:
[tex]\implies 4^2+5^2=c^2[/tex]
[tex]\implies c^2=41[/tex]
[tex]\implies c=\sqrt{41}[/tex]
Therefore, the shortest distance the ant can travel is:
⇒ 3 + √(41) = 9.4 m (nearest tenth)
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Ann and Tom want to establish a fund for their grandson's college education. What lump sum must they deposit at 12 % annual interest rate, compounded quarterly , in order to have 20,000$ in the fund at the end of 10 years?
Answers
The principal amount that must be deposited as a lump sum amount is = $16,666.7
Calculation of principal amountThe simple interest amount = $20,000
The interest rate = 12%
The time that is given= 10 years
Therefore the principle amount =?
Using the simple interest formula;
SI= P×T×R/100
Make P the subject of formula,
P = SI ×100/T×R
P= 20,000×100/10×12
P= 2,000,000/120
P= $16,666.7
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Use the ratio test to determine whether the series is convergent or divergent. 2 4/2^2 8/3^2 16/4^2 ......
Answers
I assume the given series is
[tex]\displaystyle 2 + \frac4{2^2} + \frac8{3^2} + \frac{16}{4^2} + \cdots = \frac{2^1}{1^2} + \frac{2^2}{2^2} + \frac{2^3}{3^2} + \frac{2^4}{4^2} + \cdots = \sum_{n=1}^\infty \frac{2^n}{n^2}[/tex]
By the ratio test, the series diverges, since
[tex]\displaystyle \lim_{n\to\infty} \left|\frac{2^{n+1}}{(n+1)^2} \cdot \frac{n^2}{2^n}\right| = 2 \lim_{n\to\infty} \frac{n^2}{(n+1)^2} = 2 > 1[/tex]
Find the smallest evan number that contains every digit once
Answers
Answer:
The smallest even number that contains every digit once is 1023456798.============================
Conditions we need to meet:
Use every digit once,Even number,Smallest possible number.To get the smallest number we'd use all 10 digits in the ascending order:
0123456789Here we can't have zero in the beginning as the number becomes 9-digit.
So swapping zero with the closest digit, 1.
Our number should be even, so we should swap 9 with one even digit.
Again it should be the closest one to 9, so it is 8.
We get the following number as a result:
1023456798To test you may swap digits, any number you get will be greater than this number.
3. Bob has 8 pieces of square index cards that each measures 8 inches per side. Using a pair of scissors, he cuts each piece in half (so the resulting size is 8” x 4”) and then places all the resulting card pieces in a new stack. If he repeats this procedure 4 more times, how many pieces of card stock will he have and what will be the measure of each piece? (Note: All cuts will be made along the longer edge of the piece if the piece of index card is not square.)
Answers
The number of pieces of card stock which would result upon the process repetition is; 256 pieces.
What is the number of card stock pieces resulting from the cutting process?According to the task content, it follows that since, there are 8 pieces of the 8 inches per side cards initially, the resulting number of cards after carrying out the process of cutting cards into half five, 5 times is;
No of cards = 8 (2)⁵
No. of cards = 256 pieces.
The size of each of the cards in discuss provided that all cuts will be made along and not across the longer edge is; 8 by 1/4 inches.
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The length of the diagonal of a wooden cube is 24 cm. The cube is cut into the cylinder of the
biggest volume possible. The volume of the cylinder is:
Answers
The volume of the cylinder is [tex]384\pi \sqrt{3cm }^{2}[/tex].
What is the diagonal of the cube?The diagonal that runs through the middle of a cube is it's main diagonal; the diagonal that runs along one of its faces is not. Any cube's major diagonal can be calculated by multiplying one side's length by the square root of three.Cos-1(2/3) is the angle formed between a cube's diagonal and the diagonal of one of its faces.Body of the diagonal=24cm.
Assume the length of the side= a.
[tex]a^{2} +(a^{2} +a^{2} )=24^{2}[/tex]
[tex]a=\sqrt[8]{3} cm[/tex]
The area of the cylinder base=[tex]\pi R^{2}[/tex]
=[tex]\pi (\frac{1}{2} \sqrt[8]{3} )^{2}[/tex]
=[tex]48cm^{2}[/tex]
The high of the cylinder is[tex]\sqrt[8]{3}cm[/tex]
The volume of the cylinder:
=s*h
=[tex]48\pi *\sqrt[8]{3}[/tex]
=[tex]384\pi \sqrt{3} cm^{3}[/tex]
The volume of the cylinder is [tex]384\pi \sqrt{3cm }^{2}[/tex].
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The biggest possible volume of the cylinder will be [tex]2089.497\hspace{1mm}\text{cm}^3[/tex].
What will be the diameter and height of the cylinder obtained from a cube and what are the formulas for the diagonal of a cube and the volume of a cylinder?If a cylinder with the biggest possible volume is cut inside the cube, the height of the cylinder and the diameter of the cylinder will be equal to the side length of the cube.For example, consider the following figure in which the cylinder is cut inside of the cube and since the side length of the cube is [tex]x[/tex], the diameter and the height of the cylinder are also [tex]x[/tex]If the side length of a cube is [tex]x[/tex] unit, then its diagonal will be [tex]x\sqrt{3}[/tex] unit.The formula for the volume of a cylinder is [tex]V=\pi r^2h[/tex], where [tex]r[/tex] is the radius and [tex]h[/tex] is the height of the cylinder. If [tex]d[/tex] is the diameter, then [tex]r=\frac{d}{2}[/tex].Now, given that the diagonal of the cube is [tex]24[/tex] cm. So, if the side length of the cube is [tex]x[/tex] cm, then we must have
[tex]x\sqrt{3}=24\\\Longrightarrow x=\frac{24}{\sqrt{3}}\\\Longrightarrow x=8\sqrt{3}[/tex]
Thus, the side length of the cube is [tex]8\sqrt{3}[/tex] cm.
So, the height of the cylinder with maximum volume will be [tex]h=8\sqrt{3}[/tex] cm and the diameter will be [tex]d=8\sqrt{3}[/tex]cm i.e. the radius will be [tex]r=\frac{d}{2}=\frac{8\sqrt{3}}{2}=4\sqrt{3}[/tex] cm.
So, using the above formula for the volume of a cylinder, we get
[tex]V=\pi r^{2}h=\pi\times (4\sqrt{3})^2\times 8\sqrt{3}=2089.497\hspace{1mm}\text{cm}^3[/tex].
Therefore, the biggest possible volume of the cylinder will be [tex]2089.497\hspace{1mm}\text{cm}^3[/tex].
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List the sides in order from the smallest to the largest.
L
K
27°
OA. LJ, KL, JK
OB. LJ, JK, KL
OC. KL, LJ, JK
D. JK, LJ, KL
Reset Selection
78°
75°
Answers
Answer:
A
Step-by-step explanation:
the side opposite of the angle is related to the size of this angle. Smaller angles have less space for the line to "spread out," so it will be shorter. Vice versa, bigger angles will have opposite sides longer because of more space.
Please gimme a hand I appreciate it in advance!!!
Answers
Answer:
30 degrees
Step-by-step explanation:
They are corresponding angles.
Answer: 30 degrees
Step-by-step explanation:
mangle8 and mangle 4 are corresponding angles meaning the angles are both the same.
Find the value of x
a. 13 b. 14/5 c. 5 d. 8
Answers
Using the chord theorem, option C is the best solution since x = 5.
The four line segments that are created by two intersecting chords inside of a circle are explained by the chord theorem, sometimes referred to as the intersecting chords theorem, a statement in fundamental geometry. The products of the line segment lengths on each chord are equal, according to this assertion.
The value of x must be determined in order to answer the question.
We may determine the following using the chord property:
8*x = 4*10,
or, 8x = 40,
or, x = 40/8,
or x = 5.
Given that x = 5, option C is the best option according to the chord theorem.
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For the first 150 miles of a trip, an car drives at v mph. For the next 200 miles, the car drives at (v
+25) mph. The average speed of the whole trip is 35 mph. Find the value of v.
(A) 20
(B) 25
(C) 30
(D) 35
Answers
If for the first 150 miles of a trip, an car drives at v mph, for the next 200 miles, the car drives at (v+25) mph and the average speed of the whole trip is 35 mph, then the value of v will be 20mph (A).
Given Information:
Average speed = 35 mph
Total distance = 150 + 200 = 350 miles
For the first 150 miles of a trip, an car drives at v mph speed
⇒ Time, t1 = 150/v hrs
For the next 200 miles, the car drives at (v+25) mph speed
⇒ Time, t1 = 200 / (v+25) hrs
Now, the formula for average speed is given as,
Total distance / Total time
= [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex]
⇒ [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex] = 35 mph
[tex]\frac{350 v (v+25)}{150(v+25) + 200v}[/tex] = 35
[tex]\frac{350v^{2} + 8750v}{150v +3750 + 200v}[/tex] = 35
350v² + 8750v = 35 (350v + 3750)
v² + 25v = 35v + 375
v² - 10v = 375
v² - 10v - 375 = 0
Now, the above equation for speed can be written as,
v² - 20v + 15v - 375 = 0
v(v-20) + 15(v-20) = 0
(v-20) (v+15) = 0
v = 20
or v = -15
Since, speed is a scalar quantity, it can't be negative. Thus, v = 20 mph
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a. How many feet is [tex]\frac{1}{5}[/tex] of a mile? ______
b. How many feet is [tex]\frac{1}{100}[/tex] of a mile? ______
Answers
Answer:
a. 1056 ft
b. 52.8 ft
Step-by-step explanation:
1 mile = 5280 feet
a.
[tex]\frac{1}{5} *5280 = 1056[/tex]
Therefore 1/5 of a mile is 1056 feet.
b.
[tex]\frac{1}{100} *5280=52.8[/tex]
Therefore 1/100 of a mile is 52.8 feet
Help for a brianlest at show your work
Answers
First we substitute the variables for their known values and get
2^2-2(2-(-2))-(-3)^3
Simplify
4 + (-4+4) -(-27)
4+-27= -23
That’s your answer
A soccer team won only 10 of their first 30 games. How many of their remaining 20 games will they have to win to have a .500 record??
Answers
Answer: 5 games
Step-by-step explanation: A .500 record means that the soccer team won half of their games ( that's how I interpret it). Since they are going to play 30 games, they need to win half of 30 or 15 games to have that record. 15-10 = 5. So, they need to win 5 more games to have a .500 record.
50 points!!!
Someone help pls, I can’t understand it and it’s due tomorrow :c
Answers
[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 1 :}}}}}}[/tex]
[tex]\star\:{\underline{\underline{\sf{\purple{Solution:}}}}}[/tex]
❍ Arrange the given data in order either in ascending order or descending order.
2, 3, 4, 7, 9, 11
❍ Number of terms in data [n] = 6 which is even.
As we know,
[tex]\star \: \sf Median_{(when \: n \: is \: even)} = {\underline{\boxed{\sf{\purple{ \dfrac{ { \bigg (\dfrac{n}{2} \bigg)}^{th}term +{ \bigg( \dfrac{n}{2} + 1 \bigg)}^{th} term } {2} }}}}}[/tex]
[tex]\\[/tex]
[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ { \bigg (\dfrac{6}{2} \bigg)}^{th}term +{ \bigg( \dfrac{6}{2} + 1 \bigg)}^{th} term } {2} }[/tex]
[tex]\\[/tex]
[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \dfrac{6 + 2}{2} \bigg)}^{th} term } {2} }[/tex]
[tex]\\[/tex]
[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \cancel{ \dfrac{8}{2}} \bigg)}^{th} term } {2} }[/tex]
[tex]\\[/tex]
[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ 4}^{th} term } {2} }[/tex]
• Putting,
3rd term as 4 and the 4th term as 7.
[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 4 + 7 } {2} }[/tex]
[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 11} {2} }[/tex]
[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} = \purple{5.5}[/tex]
[tex]\\[/tex]
[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 2 :}}}}}}[/tex]
[tex]\star\:{\underline{\underline{\sf{\red{Solution:}}}}}[/tex]
❍ Arrange the given data in order either in ascending order or descending order.
1, 2, 3, 4, 5, 6, 7
❍ Number of terms in data [n] = 7 which is odd.
As we know,
[tex]\star \: \sf Median_{(when \: n \: is \: odd)} = {\underline{\boxed{\sf{\red{ { \bigg( \frac{n + 1}{2} \bigg)}^{th} term}}}}}[/tex]
[tex]\\[/tex]
[tex] \sf Median_{(when \: n \: is \: odd)} = {{ \bigg(\dfrac{ 7 + 1 } {2} \bigg) }}^{th} term[/tex]
[tex]\\[/tex]
[tex] \sf Median_{(when \: n \: is \: odd)} = { \bigg(\cancel{\dfrac{8}{2}} \bigg)}^{th} term[/tex]
[tex]\\[/tex]
[tex] \sf Median_{(when \: n \: is \: odd)} ={ 4}^{th} term[/tex]
• Putting,
4th term as 4.
[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: odd)} = \red{ 4}[/tex]
[tex]\\[/tex]
[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 3 :}}}}}}[/tex]
[tex]\star\:{\underline{\underline{\sf{\green{Solution:}}}}}[/tex]
The frequency distribution table for calculations of mean :
[tex]\begin{gathered}\begin{array}{|c|c|c|c|c|c|c|} \hline \rm x_{i} &\rm 3&\rm 1&\rm 7&\rm 4&\rm 6&\rm 2 \rm \\ \hline\rm f_{i} &\rm 4&\rm 6&\rm 2&\rm 2 & \rm 1&\rm 1 \\ \hline \rm f_{i}x_{i} &\rm 12&\rm 6&\rm 14&\rm 8&\rm 6&\rm \rm 2 \\ \hline \end{array} \\ \end{gathered} [/tex]
☆ Calculating the [tex]\sum f_{i}[/tex]
[tex] \implies 4 + 6 + 2 + 2 + 1 + 1[/tex]
[tex] \implies 16[/tex]
☆ Calculating the [tex]\sum f_{i}x_{i}[/tex]
[tex] \implies 12 + 6 + 14 + 8 + 6 + 2[/tex]
[tex]\implies 48[/tex]
As we know,
Mean by direct method :
[tex] \: \: \boxed{\green{{ { \overline{x} \: = \sf \dfrac{ \sum \: f_{i}x_{i}}{ \sum \: f_{i}}}}}}[/tex]
here,
• [tex]\sum f_{i}[/tex] = 16
• [tex]\sum f_{i}x_{i}[/tex] = 48
By putting the values we get,
[tex]\sf \longrightarrow \overline{x} \: = \: \dfrac{48}{16}[/tex]
[tex]\sf \longrightarrow \overline{x} \: = \green{3}[/tex]
[tex]{\large{\textsf{\textbf{\underline{\underline{Note\: :}}}}}}[/tex]
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[tex]\begin{gathered} {\underline{\rule{290pt}{3pt}}} \end{gathered}[/tex]
Which of these expressions demonstrates the identity property? 25(0) = 25 25(1) = 25 25 + 0 = 25 25 + 1 = 25
Answers
The expressions which demonstrates the identity property of multiplication is; 25(1) = 25 option B
Identity Property
Identity Property of Multiplication states that any number multiplied by 1 does not change, that is, it is constant or remains the same
Check all options
25(0) = 25
0 = 25
Not true
25(1) = 25
25 = 25
True (identity property of multiplication holds)
25 + 0 = 25
25 = 25
True (Not identity property of multiplication)
25 + 1 = 25
26 = 25
Not true
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Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table below.
Low Temperatures during the School Day This Week and Last Week
Low Temperatures
This Week (Degrees Fahrenheit)
42
38
45
46
39
Low Temperatures
Last Week (Degrees Fahrenheit)
56
58
52
62
62
Daniela used the steps below to find a relationship between the difference in the mean temperatures and the mean absolute deviations of the data sets.
This Week Last Week
Step 1
Find the mean.
StartFraction 42 + 38 + 45 + 46 + 39 over 5 EndFraction = 42
Find the mean.
StartFraction 56 + 58 + 52 + 62 + 62 over 5 EndFraction = 58
Step 2
Find the mean absolute deviation.
StartFraction StartAbsoluteValue 42 minus 42 EndAbsoluteValue + StartAbsoluteValue 38 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 45 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 46 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 39 minus 42 EndAbsoluteValue over 5 EndFraction = 2.8
Find the mean absolute deviation.
StartFraction StartAbsoluteValue 56 minus 58 EndAbsoluteValue + StartAbsoluteValue 58 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 52 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 62 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 62 minus 58 EndAbsoluteValue over 5 EndFraction = 3.2
Step 3 Find the ratio of the differences of the means compared to the mean absolute deviation.
StartFraction 42 over 2.8 EndFraction = 15 Find the ratio of the differences of the means compared to the mean absolute deviation.
StartFraction 58 over 3.2 EndFraction = 18.125
Step 4 The difference in the means is about StartFraction 15 + 18 over 2 EndFraction = 16.5 times the mean absolute deviations.
In which step did Daniela make the first error?
Answers
Based on the information given about the temperature, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation.
How to illustrate the error?From the information given, it van be seen that Daniela recorded the low temperatures during the school day last week and this week and her results are shown in the table.
Here, she didn't find the difference between the today and last week means. She just put the mean as a whole.
Therefore, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation. This was the error.
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