find direction numbers for the line of intersection of the planes x y z = 4 and x z = 0.

Answers

Answer 1

The line of intersection of two planes is found by the cross product of the normal vectors of each plane. Therefore, to find the direction numbers for the line of intersection of the planes x y z = 4 and x z = 0, we must first find the normal vectors of each plane.

The equation x y z = 4 can be rewritten as z = -x - y + 4, which means that the normal vector of this plane is <1, 1, -1>.Similarly, the equation x z = 0 can be rewritten as x = 0 or z = 0, which means that the normal vector of this plane is <0, 1, 0>.Taking the cross product of these two normal vectors, we get:<1, 1, -1> × <0, 1, 0> = <-1, 0, -1>

Therefore, the direction numbers of the line of intersection of the planes x y z = 4 and x z = 0 are -1 and -1.

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Related Questions

The price-earnings (PE) ratios of a sample of stocks have a mean
value of 12.25 and a standard deviation of 2.6. If the PE ratios
have a bell shaped distribution, what percentage of PE ratios that
fal

Answers

If the PE ratios have a bell-shaped distribution, we can assume that they follow a normal distribution. To find the percentage of PE ratios that fall within a certain range, we can use the properties of the normal distribution.

Given that the mean (μ) of the PE ratios is 12.25 and the standard deviation (σ) is 2.6, we can use the properties of the standard normal distribution (with a mean of 0 and a standard deviation of 1) to calculate the desired percentage.

Let's say we want to find the percentage of PE ratios that fall within a range of μ ± nσ, where n is the number of standard deviations away from the mean. For example, if we want to find the percentage of PE ratios that fall within 1 standard deviation of the mean, we can calculate the range as μ ± 1σ.

To find the percentage of values within this range, we can refer to the Z-table, which provides the area under the standard normal distribution curve for different values of Z (standard deviations). We can look up the Z-scores corresponding to the desired range and calculate the percentage accordingly.

For example, if we want to find the percentage of PE ratios that fall within 1 standard deviation of the mean, we can calculate the range as μ ± 1σ = 12.25 ± 1 * 2.6.

To calculate the Z-scores corresponding to these values, we can use the formula:

Z = (x - μ) / σ

For the lower value, x = 12.25 - 1 * 2.6, and for the upper value, x = 12.25 + 1 * 2.6.

Let's perform the calculations:

Lower value:

Z_lower = (12.25 - 1 * 2.6 - 12.25) / 2.6

Upper value:

Z_upper = (12.25 + 1 * 2.6 - 12.25) / 2.6

Once we have the Z-scores, we can look them up in the Z-table to find the corresponding percentages. The difference between the two percentages will give us the percentage of PE ratios that fall within the desired range.

For example, if the Z-scores correspond to 0.1587 and 0.8413 respectively, the percentage of PE ratios that fall within 1 standard deviation of the mean would be:

Percentage = (0.8413 - 0.1587) * 100

You can use this approach to calculate the percentage of PE ratios that fall within any desired range by adjusting the number of standard deviations (n) accordingly.

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You can retry this question below A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 507 randomly selected Americans surveyed, 385 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all Americans who favor the new Green initiative is between and b. If many groups of 507 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group. About 99 percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about 1 percent will not contain the true population proportion.

Answers

a. The 99% confidence interval for the true proportion p of Americans who favor the new Green initiative is: 0.7195 ≤ p ≤ 0.8004.

b.If multiple surveys were conducted, each consisting of 507 randomly selected Americans, approximately 99% of the confidence intervals calculated would include the actual population proportion of Americans who support the Green initiative. Conversely, approximately 1% of these intervals would not encompass the true population proportion.

a. With 99% confidence the proportion of all Americans who favor the new Green initiative is between 0.7195 and 0.8004.Since the point estimate is given by the number of successes divided by the sample size, i.e.

p-hat = 385/507 ≈ 0.7595.

Using this point estimate, the 99% confidence interval for p can be calculated as follows:

Since np and n(1 - p) are both greater than or equal to 10, a normal approximation to the binomial distribution can be used.

The margin of error is given by zα/2 times the standard error:zα/2 is the z-score that gives an area of α/2 in the upper tail of the standard normal distribution, which is 2.58 for α = 0.01 (99% confidence).

So, the 99% confidence interval for the true proportion p of Americans who favor the new Green initiative is: 0.7195 ≤ p ≤ 0.8004.

b. If many groups of 507 randomly selected Americans were surveyed, then about 99% of these confidence intervals would contain the true population proportion of Americans who favor the Green initiative, and about 1% will not contain the true population proportion.

it suggests that if many groups of 507 randomly selected Americans were surveyed, approximately 99% of the confidence intervals constructed for the population proportion of Americans who favor the Green initiative would contain the true population proportion. This indicates a high level of confidence in the accuracy of the estimated proportion.

it states that about 1% of these confidence intervals would not contain the true population proportion. This means that in approximately 1% of the cases, the confidence intervals would fail to capture the true proportion.

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Find the distance between the points using the following methods. (4, 3), (7, 5)
a) The Distance Formula
b) Integration

Answers

a) The distance between the points (4, 3) and (7, 5) using the Distance Formula is √13 units.

b) The distance between the points (4, 3) and (7, 5) using integration is also √13 units.

a) The Distance Formula

To find the distance between the points (4, 3) and (7, 5), we can use the distance formula, which is as follows:

D = sqrt((x₂ - x₁)² + (y₂ - y₁)²), Where (x₁, y₁) and (x₂, y₂) are the coordinates of the two points.

Therefore, substituting the values, we get:

D = sqrt((7 - 4)² + (5 - 3)²)

= sqrt(3² + 2²)

= sqrt(9 + 4)

= sqrt(13)

Hence, the distance between the points using the distance formula is √13 units.

b) Integration

To find the distance between the points (4, 3) and (7, 5) using integration, we need to find the length of the curve between the two points.

The curve is a straight line connecting the two points, so the length of the curve is simply the distance between the points, which we have already found to be √13 units.

Therefore, the distance between the points using integration is also √13 units.

Answer: The distance between the points (4, 3) and (7, 5) using the Distance Formula is √13 units. The distance between the points using integration is also √13 units.

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Solve the given differential equation by separation of variables
dy/dx = xy + 8y - x -8 / xy - 7y + X - 7

Answers

This is the general solution to the given differential equation using separation of variables.

To solve the given differential equation using separation of variables, we'll rearrange the equation and separate the variables:

dy / dx = (xy + 8y - x - 8) / (xy - 7y + x - 7)

First, we'll rewrite the numerator and denominator separately:

dy / dx = [(x - 1)(y + 8)] / [(x - 1)(y - 7)]

Next, we can cancel out the common factor (x - 1) in both the numerator and denominator:

dy / dx = (y + 8) / (y - 7)

Now, we'll separate the variables by multiplying both sides by (y - 7):

(y - 7) dy = (y + 8) dx

To solve the equation, we'll integrate both sides:

∫ (y - 7) dy = ∫ (y + 8) dx

Integrating the left side with respect to y:

(1/2) y^2 - 7y = ∫ (y + 8) dx

Simplifying the right side:

(1/2) y^2 - 7y = xy + 8x + C

where C is the constant of integration.

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The dotplot shows the distribution of passing rates for the bar
ex4m at 185 law schools in the United States in a certain year. The
five number summary is
27​,
77.5​,
86​,
91.5​,
100.
Draw the
Homework: Section 3.5 Homework Question 10, 3.5.72 Part 2 of 2 HW Score: 72.62%, 8.71 of 12 points O Points: 0 of 1 Save The dotplot shows the distribution of passing rates for the bar exam at 185 law

Answers

The dot plot of the distribution of passing rates for the bar exam at 185 law schools in the US for a certain year with five number summary as 27​, 77.5​, 86​, 91.5​, 100 would look like the following:

The minimum value of the passing rates is 27, the lower quartile is 77.5, the median is 86, the upper quartile is 91.5, and the maximum value is 100. The distance between the minimum value and lower quartile is called the interquartile range (IQR).

It is calculated as follows:

IQR = Upper quartile - Lower quartile= 91.5 - 77.5= 14

The range is the difference between the maximum and minimum values. Therefore, Range = Maximum - Minimum= 100 - 27= 73

Hence, the dot plot of the given distribution would look like the above plot.

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If the average daily income for small grocery markets in Riyadh
is 7000 riyals, and the standard deviation is 1000 riyals, in a
sample of 1600 markets find the standard error of the mean
3.75

Answers

The formula to find the standard error of the mean is:Standard error of the mean = Standard deviation / sqrt(n)Where,Standard deviation = 1000 riyalsSample size, n = 1600 markets

Now, let's calculate the standard error of the mean:

Standard error of the mean = Standard deviation / sqrt(n)Standard error of the mean = 1000 / sqrt(1600)Standard error of the mean = 1000 / 40Standard error of the mean = 25

Given, the average daily income for small grocery markets in Riyadh is 7000 riyals, and the standard deviation is 1000 riyals, in a sample of 1600 markets, we need to find the standard error of the mean.

Summary: The standard error of the mean for the given problem is 25.

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determine whether the variable is qualitative or quantitative. model of car driven

Answers

(a) The complex Fourier series of f(t) is given by ∑(n=-∞)^(∞) c_n exp(jnωt), where c_n = { 6j/(7πn) if n is odd, 0 if n is even }.

(b) The trigonometric Fourier series of f(t) is given by ∑(n=0)^(∞) [a_n cos(nωt) + b_n sin(nωt)], where a_n = 0 for all n, and b_n = { 12/(nπ) if n is odd, 0 if n is even }.

(a) To determine the complex Fourier series of f(t), we first need to find the coefficients c_n. The complex Fourier series representation is of the form ∑(n=-∞)^(∞) c_n exp(jnωt), where ω = 2π/T is the fundamental frequency.

For the given function f(t), we have the following recursive relationship:

f(t) = 4t + 6f(t+7)

To find c_n, we need to compute the Fourier coefficients. Multiplying both sides of the recursive relationship by exp(-jmωt) and integrating over one period T, we get:

∫[0]^[T] f(t) exp(-jωnt) dt = ∫[0]^[T] (4t + 6f(t+7)) exp(-jωnt) dt

Expanding the integral on the right-hand side using the linearity property of the integral, we have:

∫[0]^[T] f(t) exp(-jωnt) dt = 4∫[0]^[T] t exp(-jωnt) dt + 6∫[0]^[T] f(t+7) exp(-jωnt) dt

The first integral on the right-hand side can be evaluated using integration by parts. The second integral involves the function f(t+7), which has a periodicity of 7. Thus, we can rewrite it as:

∫[0]^[T] f(t+7) exp(-jωnt) dt = ∫[7]^[T+7] f(t) exp(-jωnt) dt

Substituting these results back into the equation and simplifying, we get:

c_n = 4(∫[0]^[T] t exp(-jωnt) dt) + 6(∫[7]^[T+7] f(t) exp(-jωnt) dt)

Now, we need to evaluate the integrals. The first integral can be computed using integration by parts or by recognizing it as the Fourier coefficient of t. The result is:

∫[0]^[T] t exp(-jωnt) dt = jT/(nω)^2

The second integral can be simplified using the periodicity of f(t+7):

∫[7]^[T+7] f(t) exp(-jωnt) dt = ∫[0]^[T] f(t) exp(-jωn(t+7)) dt = exp(-j7nω) ∫[0]^[T] f(t) exp(-jωnt) dt

Since f(t) has a periodicity of 7, the integral becomes:

∫[7]^[T+7] f(t) exp(-jωnt) dt = exp(-j7nω) ∫[0]^[7] f(t) exp(-jωnt) dt

Substituting these results

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Suppose you are testing the following claim: "Less than 11% of
workers indicate that they are dissatisfied with their job."
Express the null and alternative hypotheses in symbolic form for a
hypothesi

Answers

The null and alternative hypotheses in symbolic form for a hypothesis are as follows: Null Hypothesis: H₀ : p ≥ 0.11; Alternative Hypothesis: H₁ : p < 0.11.

We want to test the following claim: "Less than 11% of workers indicate that they are dissatisfied with their job".

Null Hypothesis: The null hypothesis represents the status quo. It is assumed that the percentage of workers who indicate that they are dissatisfied with their job is equal to or greater than 11%. So, the null hypothesis is expressed in symbolic form as H₀ : p ≥ 0.11 where p represents the proportion of workers who indicate that they are dissatisfied with their job.

Alternative Hypothesis: The alternative hypothesis is the statement that contradicts the null hypothesis and makes the opposite claim. It is assumed that the percentage of workers who indicate that they are dissatisfied with their job is less than 11%. Hence, the alternative hypothesis is expressed in symbolic form as H₁ : p < 0.11. So, the null and alternative hypotheses in symbolic form for a hypothesis are as follows:

Null Hypothesis: H₀ : p ≥ 0.11; Alternative Hypothesis: H₁ : p < 0.11.

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Birth weights in the United States have a distribution that is approximately normal with a mean of 3369 g and a standard deviation of 567 g.
a) One definition of a premature baby is that the birth weight is below 2500 g. Draw the normal distribution (with appropriate labels) and shade in the area that represents birth weights below 2500 g. Convert 2500 g into a standard score. If a baby is randomly selected, find the probability of a birth weight below 2500 g.
b) Another definition of a premature baby is that the birth weight is in the bottom 10%. Find the 10th percentile of birth weights.
c) If 40 babies are randomly selected, find the probability that their mean weight is greater than 3400 g.
A Gallup survey indicated that 72% of 18- to 29-year-olds, if given a choice, would prefer to start their own business rather than work for someone else. A random sample of 400 18- to 29-year-olds is obtained today.
a) Describe the sampling distribution of p, the sample proportion of 18- to 29-year-olds who would prefer to start their own business.
b) In a random sample of 400 18- to 29-year-olds, what is the probability that no more than 70% would prefer to start their own business?
c) Would it be unusual if a random sample of 400 18- to 29-year-olds resulted in 300 or more who would prefer to start their own business? Why?

Answers

This means that ahis means that a sample of 400 18- to 29-year-olds resulting in 300 or more who would prefer to start their own business is not unusual

a) One definition of a premature baby is that the birth weight is below 2500 g. The z-score is given as follows:$z = \frac{2500 - 3369}{567} = -15.3$Using the standard normal distribution table, we find that $P(Z < -15.3)$ is essentially 0. The probability of a birth weight below 2500 g is practically zero.b) Another definition of a premature baby is that the birth weight is in the bottom 10%. To find the birth weight that corresponds to the 10th percentile, we need to find the z-score that corresponds to the 10th percentile using the standard normal distribution table. The z-score is -1.28$z = -1.28 = \frac{x - 3369}{567}$Solve for x to get $x = 2669$ g. Thus, the 10th percentile of birth weights is 2669 g.c) If 40 babies are randomly selected, find the probability that their mean weight is greater than 3400 g. The standard error is $SE = \frac{567}{\sqrt{40}} = 89.4$ g. We can standardize the variable as follows:$z = \frac{3400 - 3369}{89.4} = 0.35$Using the standard normal distribution table, the probability of obtaining a z-score greater than 0.35 is 0.3632. Thus, the probability that their mean weight is greater than 3400 g is 0.3632. This can be interpreted as there is a 36.32% chance that a sample of 40 babies will have a mean birth weight greater than 3400 g.d) For this problem, we are given that $p = 0.72$, the proportion of 18- to 29-year-olds who would prefer to start their own business. Since $n = 400 > 30$, we can use the normal distribution to approximate the sampling distribution of $p$. The mean of the sampling distribution is given by $\mu_{p} = p = 0.72$, and the standard deviation of the sampling distribution is given by $\sigma_{p} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.72(0.28)}{400}} = 0.032$. Thus, the sampling distribution of $p$ is approximately normal with mean 0.72 and standard deviation 0.032.e) To find the probability that no more than 70% of the sample would prefer to start their own business, we need to standardize the variable as follows:$z = \frac{0.70 - 0.72}{0.032} = -0.63$Using the standard normal distribution table, the probability of obtaining a z-score less than -0.63 is 0.2652. Thus, the probability that no more than 70% of the sample would prefer to start their own business is 0.2652.f) To determine whether a sample of 400 18- to 29-year-olds resulting in 300 or more who would prefer to start their own business is unusual, we need to find the z-score:$z = \frac{0.75 - 0.72}{0.032} = 0.9375$Using the standard normal distribution table, the probability of obtaining a z-score greater than 0.9375 is 0.1736.

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find the area of the region enclosed by one loop of the curve: r = 2sin5theta

Answers

This integral can be solved by making use of the trigonometric identity: sin²θ = (1-cos2θ)/2, which will yield an answer in terms of sine and cosine values. The final answer will be 1.26 square units, rounded to two decimal places.

Polar equations represent curves that may have multiple “loops” or closed regions on the plane. The polar equation given is: r = 2 sin 5θ. This equation will yield a curve with 5 “loops” of increasing size, all centred at the origin. One such “loop” can be enclosed by plotting the values of r for θ between 0 and π/5.

This will produce a flower-like shape with five petals. The area of this region can be calculated using the formula for the area enclosed by a polar curve: 1/2 ∫ᵇ_ₐ r² dθ. Using the limits of integration, this equation becomes 1/2 ∫⁺_⁰ 4sin²5θ dθ.

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Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)

an =
4n
1 + 5n
lim n→[infinity] an =

Answers

The given sequence is `an = 4n / (1 + 5n)`.

To determine whether the sequence converges or diverges, we need to find the limit of the sequence.Here,lim n→[infinity] an = lim n→[infinity] 4n / (1 + 5n)

On simplifying the above expression,lim n→[infinity] an = lim n→[infinity] 4 / (5/n + 1)

The limit is of the form `k / ∞`, where k is a finite number.

Therefore,lim n→[infinity] an = 0

Thus, the given sequence converges, and its limit is 0.

Hence, the correct option is A.

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99 students at a college were asked whether they had completed their required English 101 course, and 76 students said "yes". Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is ( Submit Question

Answers

(0.691, 0.844) is  the 90% confidence interval for the proportion of students at the college who have completed their required English 101 course.

Given that a survey was conducted on 99 students at a college to find out whether they had completed their required English 101 course, out of which 76 students said "yes". We are supposed to construct the 90% confidence interval for the proportion of students at the college who have completed their required English 101 course.

Confidence Interval:

It is an interval that contains the true population parameter with a certain degree of confidence. It is expressed in terms of a lower limit and an upper limit, which is calculated using the sample data. The confidence interval formula is given by:

Confidence Interval = \bar{x} ± z_{\frac{\alpha}{2}}\left(\frac{s}{\sqrt{n}}\right)

where \bar{x} is the sample mean, z_{\frac{\alpha}{2}} is the critical value, s is the sample standard deviation, \alpha is the significance level, and n is the sample size.

Here, the sample proportion \hat{p} = \frac{x}{n} = \frac{76}{99}

Confidence Level = 90%, which means that \alpha = 0.10 (10% significance level)

The sample size, n = 99

Now, to calculate the critical value, we need to use the z-table, which gives the area under the standard normal distribution corresponding to a given z-score. The z-score corresponding to a 90% confidence level is 1.645.

Using the formula,

Confidence Interval = \hat{p} ± z_{\frac{\alpha}{2}}\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

Confidence Interval = 0.768 ± 1.645\sqrt{\frac{0.768(0.232)}{99}}

Confidence Interval = (0.691 , 0.844)

Therefore, the 90% confidence interval for the proportion of students at the college who have completed their required English 101 course is (0.691, 0.844).

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Score on last try: 0 of 1 pts. See Details for more. > Next question x + 5 x + 10 Let f(x) = 5(2x-1) f-¹ (-5) = 1-z Question Help: Video Submit Question = Get a similar question You can retry this qu

Answers

Given function is f(x) = 5(2x - 1) and we need to find f-¹(-5).

To find the inverse of a function, follow the steps given below:Replace f(x) with y interchange x and y i.e x = f-¹(y) Solve the above equation for y and replace y with f-¹(x) The resulting equation represents the inverse function of f(x)

Solving f-¹(-5)Replace y with -5 and f-¹(y) with x5(2x - 1) = -5Simplify the above equation by dividing both sides by 5 to get

2x - 1 = -12x

= -1 + 2x

= 1/2

Therefore, the value of f-¹(-5) is 1/2.

Inverse functions help us to find the original value of the function by using the output value.

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Calculate the percent increase in population between year 1 and year 2, year 2 and year 3, and year 3 and year 4. Round up or down to the nearest whole percentage. Show your work. //// Percent increase between years 1 and 2:

(5,780 – 3,845) ÷ 3,845 = 0.50 = 50% increase

Percent increase between years 2 and 3:

(15,804 – 5,780) ÷ 5,780 = 1.73 = 173% increase

Percent increase between years 3 and 4:

(52,350 – 15,804) ÷ 15,804 = 2.31 = 231% increase

Answers

The percent increase in population between year 1 and year 2 is 50%.

Between year 2 and year 3, the percent increase is 173%

Between year 3 and year 4, the percent increaseis 231%.

What are the percent increases in population?

Calculation of percent increase between years 1 and 2:

Population increase = 5,780 - 3,845

Population increase = 1,935

Percent increase = (1,935 / 3,845) * 100

Percent increase = 50%

Calculation of percent increase between years 2 and 3:

Population increase = 15,804 - 5,780

Population increase = 10,024

Percent increase = (10,024 / 5,780) * 100

Percent increase = 173%

Calculation of percent increase between years 3 and 4:

Population increase = 52,350 - 15,804

Population increase = 36,546

Percent increase = (36,546 / 15,804) * 100

Percent increase = 231%

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The distribution of the number of customers a server has this
shift, Y, is
Value of Y
0
1
2
3
P(Y=y)
0.18
0.1
0.27
0.45
i) Find P(X≤1)
ii) Find μ, (is the expected number of customers).
iii

Answers

P(X ≤ 1) is 0.28 and the expected number of customers ≈ 1.99.

To calculate P(X ≤ 1), we sum the probabilities of Y being 0 or 1:

P(X ≤ 1) = P(Y = 0) + P(Y = 1)

P(Y = 0) = 0.18

P(Y = 1) = 0.1

P(X ≤ 1) = 0.18 + 0.1 = 0.28

Therefore, P(X ≤ 1) is 0.28.

To find the expected number of customers, μ, we multiply each value of Y by its corresponding probability and sum them up:

μ = 0 * P(Y = 0) + 1 * P(Y = 1) + 2 * P(Y = 2) + 3 * P(Y = 3)

μ = 0 * 0.18 + 1 * 0.1 + 2 * 0.27 + 3 * 0.45

μ = 0 + 0.1 + 0.54 + 1.35

μ = 1.99

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Please find the mean, variance, and standard deviation
Internet Purchases Twenty-four percent of adult Internet users have purchased products or services online. For a random sample of 200 adult Internet users, find the mean, variance, and standard deviat

Answers

Hence, the mean, variance, and standard deviation for the given data set is 48, 36.48, and 6.03 respectively.

The term variance refers to a statistical measurement of the spread between numbers in a data set. More specifically, variance measures how far each number in the set is from the mean (average), and thus from every other number in the set. Variance is often depicted by this symbol: σ2.

Given information:Twenty-four percent of adult Internet users have purchased products or services online. For a random sample of 200 adult Internet users, find the mean, variance, and standard deviation.

Mean of the given data set is:

μ = npμ = 200 × 0.24

μ = 48

Variance of the given data set is:σ² = npqσ² = 200 × 0.24 × 0.76σ² = 36.48

Standard deviation of the given data set is:σ = √σ²σ = √36.48σ = 6.03

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which function has an axis of symmetry of x = −2?f(x) = (x − 1)2 2f(x) = (x 1)2 − 2f(x) = (x − 2)2 − 1f(x) = (x 2)2 − 1

Answers

The function that has an axis of symmetry of x = −2 is  f(x) = (x + 2)² - 1. To determine the function that has an axis of symmetry of x = −2, you will need to identify the vertex of the function. To do this, the function has to be in the vertex form, which is f(x) = a(x - h)² + k, where (h, k) is the vertex.

Once the vertex is identified, the x-coordinate of the vertex is the axis of symmetry. To obtain the vertex form of the given functions, you will need to complete the square. The vertex form of the function is f(x) = (x + 2)² - 1The function f(x) = (x - 1)² does not have an axis of symmetry of x = -2. Completing the square gives f(x) = (x - 1)² + 0. The vertex is (1, 0), so the axis of symmetry is x = 1.The function f(x) = (x + 1)² - 2 does not have an axis of symmetry of x = -2.

Completing the square gives f(x) = (x + 1)² - 3. The vertex is (-1, -3), so the axis of symmetry is x = -1.The function f(x) = (x - 2)² - 1 does not have an axis of symmetry of x = -2. Completing the square gives f(x) = (x - 2)² - 1. The vertex is (2, -1), so the axis of symmetry is x = 2.The function f(x) = (x + 2)² - 1 has a vertex of (-2, -1), so the axis of symmetry is x = -2. Therefore, the function that has an axis of symmetry of x = −2 is f(x) = (x + 2)² - 1.

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Find the exact values below. If applicable, click on "Undefined". 4t √ Undefined √3 3 5 4t 3 tan CSC = 2√√3 3 X

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The square root of a negative number cannot be computed, it's undefined. Therefore, the answer is "Undefined".Answer: Undefined.

The given expressions are given below:

4t √ Undefined√3/35/4t 3 tanCSC = 2√√3/3 X

The following is the method to find the exact value of the given expression:To solve this problem, let's first find the missing information from the data given.Let's first solve for tan, which is the ratio of the opposite side to the adjacent side. tan = opposite side/adjacent side

= 3/4t = 3/(4t)

Let's next solve for CSC, which is the ratio of the hypotenuse side to the opposite side. CSC = hypotenuse side/opposite side = 2√√3/3 Therefore, since tan is the opposite side and CSC is the hypotenuse side, we can use the Pythagorean Theorem to find the adjacent side. Adjacent side

= √(hypotenuse^2 - opposite^2) = √[(2√√3/3)^2 - (3/4t)^2] = √[(4*3/3^2) - (9/16t^2)] = √(12/9 - 9/16t^2) = √[(48 - 81)/(16*9t^2)] = √[-33/(16*9t^2)]

Since the square root of a negative number cannot be computed, it's undefined. Therefore, the answer is "Undefined".Answer: Undefined.

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Which of the following is not one of the Counting Rules. O a. The Range Rule O b. The Combination Rule O c. The Permutation Rule O d. Fundamental Counting Rule

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The Range Rule is not one of the Counting Rules.

The following are the Counting Rules: Permutation Rule: Used to calculate the number of arrangements of a set in a particular order. Combination Rule: Used to calculate the number of ways to pick objects from a larger set, without regards to order. Fundamental Counting Rule: Used to calculate the number of possible outcomes in an event by multiplying the number of outcomes in each category together .Range Rule: The range rule is used to calculate the variation of a data set by subtracting the minimum value from the maximum value. It is not a counting rule, but a statistical tool.

The Fundamental Counting Principle is a technique used in mathematics, more specifically in probability theory and combinatorics, to determine how many combinations of options, items, or outcomes are possible. The Rule of Multiplication, the Product Rule, the Multiplication Rule, and the Fundamental Counting Rule are some of its alternate names.

It has a connection to the Sum method, often known as the Rule of Sum, which is a fundamental counting method used to calculate probabilities.

According to the Fundamental Counting Principle, if a decision or event has a possible outcome or set of options, and a different decision or event has b possible outcomes or choices, then the sum of all the unique combinations of outcomes for the two is ab.

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In the competitive market represented by the graph provided, which of the following is true at a price of $20?
A. There is a surplus of 60 units.
B.There is a surplus of 35 units.
C.There is a shortage of 60 units.
D.There is a shortage of 35 units.
F. The quantity sold equals 60 units

Answers

Option B.There is a surplus of 35 units.

The competitive market represented by the graph provided, which is also called a supply and demand diagram, can help us determine the quantity of goods that will be sold at a given price.

The graph is used to show how the quantity of a good demanded by consumers varies with the price of that good, and how the quantity of a good supplied by producers varies with the price of that good. The intersection of the supply and demand curves represents the market equilibrium, which is the point where the quantity of a good supplied equals the quantity of that good demanded.

In the given graph, the price is $20, and we can see that the quantity supplied is 95 units, while the quantity demanded is 60 units. Thus, at a price of $20, there is a surplus of 35 units. This means that the quantity supplied is more than the quantity demanded.

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The three right triangles below are similar. The acute angles LL, ZR, and ZZ are all approximately measured to be 61.2º. The side lengths for each triangle are as follows. Note that the triangles are

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The ratio of corresponding sides of similar triangles is called the scale factor. If the scale factor of two similar triangles is k, then the ratio of their perimeters is also k, and the ratio of their areas is k².

Given:The three right triangles are similar. The acute angles LL, ZR, and ZZ are all approximately measured to be 61.2º. The side lengths for each triangle are as follows. Note that the triangles are...The three right triangles below are similar. The acute angles LL, ZR, and ZZ are all approximately measured to be 61.2º. The side lengths for each triangle are as follows. Note that the triangles are similar because they have the same angle measures.•

Triangle 1: LK = 5 cm, KL = 10 cm, LL = 11.55 cm•

Triangle 2: ZS = 15 cm, ZR = 7.75 cm, ZZ = 16.90 cm•

Triangle 3: XY = 20 cm, XZ = 10.32 cm, ZZ = 22.5 cm

The triangles are similar because they have the same angle measures and the ratio of their side lengths is the same. The ratio of corresponding sides of similar triangles is called the scale factor. If the scale factor of two similar triangles is k, then the ratio of their perimeters is also k, and the ratio of their areas is k².

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im
not getting the same answers when i calculate i might be missing a
step can u redo
and further explain #4
rect! In the early 1900s, Lucien Cuénot studied the genetic basis of yellow coat color in mice (discussed on p. 114). He carried out a number of crosses between two yellow mice and obtained what he t

Answers

Lucien Cuénot was a geneticist who conducted experiments on the genetic basis of yellow coat color in mice in the early 1900s. He carried out a series of crosses between two yellow mice and obtained what he termed the "third color," which is now known as the agouti color.

His work paved the way for modern-day genetic research. Lucien Cuénot used monohybrid crosses to study yellow coat color in mice. In such crosses, a single trait is considered. He crossed two yellow mice and obtained all yellow offspring. Then he took two of the yellow offspring and crossed them to produce the third color, which was found to be agouti. Agouti is a term used to describe a coat color pattern that is distinguished by bands of color on each individual hair.

Lucien Cuénot's experiments showed that the yellow coat color trait is controlled by a single gene. The dominant allele Y causes yellow coat color, while the recessive allele y produces agouti color. When two yellow mice are crossed, they only produce yellow offspring because they are both homozygous dominant (YY).

However, when two yellow offspring are crossed, they produce yellow, agouti, and white offspring in a ratio of 2:1:1. This is because the yellow offspring are heterozygous (Yy) and can produce either yellow or agouti offspring when they are crossed with each other.

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what is the eqquation for the line that passes through points (10,-6) and (6,6)

Answers

The point-slope form of the equation of a line is given by: y - y1 = m(x - x1)

where (x1, y1) is a point on the line, and m is the slope of the line. To find the slope of a line, we use the slope formula given by: m = (y2 - y1) / (x2 - x1)where (x1, y1) and (x2, y2) are two points on the line.

To find the equation of a line that passes through two given points, we will use the point-slope form of the equation of a line. The point-slope form of the equation of a line is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line, and m is the slope of the line. To find the slope of a line, we use the slope formula given by:m = (y2 - y1) / (x2 - x1)where (x1, y1) and (x2, y2) are two points on the line. Now we can find the equation of the line that passes through the points (10,-6) and (6,6) using the following steps:

Step 1: Find the slope of the line.The slope of the line is given by: m = (y2 - y1) / (x2 - x1)

Where (x1, y1) = (10, -6) and (x2, y2) = (6, 6)m = (6 - (-6)) / (6 - 10)= 12 / (-4)= -3

Therefore, the slope of the line is -3.

Step 2: Choose one of the two points to use in the equation. `Since we have two points, we can use either of them to find the equation of the line. For simplicity, let's use (10, -6).

Step 3: Substitute the slope and the point into the point-slope form of the equation of a line and solve for y.y - y1 = m(x - x1)y - (-6) = -3(x - 10)y + 6 = -3x + 30y = -3x + 24Therefore, the equation of the line that passes through the points (10, -6) and (6, 6) is:y = -3x + 24

To find the equation of a line that passes through two given points, we can use the point-slope form of the equation of a line. The point-slope form of the equation of a line is given by:y - y1 = m(x - x1)where (x1, y1) is a point on the line, and m is the slope of the line. To find the slope of a line, we use the slope formula given by:m = (y2 - y1) / (x2 - x1)where (x1, y1) and (x2, y2) are two points on the line. Once we have found the slope of the line, we can choose one of the two points and substitute the slope and the point into the point-slope form of the equation of a line and solve for y. This will give us the equation of the line. In this problem, we were given the points (10, -6) and (6, 6) and asked to find the equation of the line that passes through them. Using the slope formula, we found that the slope of the line is -3. We then chose the point (10, -6) and substituted the slope and the point into the point-slope form of the equation of a line and solved for y. This gave us the equation of the line:y = -3x + 24.

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QUESTION 25 You are testing the null hypothesis that there is no linear relationship between two variables, X and Y. From your sample of n=22. At the a=0.05 level of significance, what are the upper a

Answers

The null hypothesis is rejected if the test statistic is greater than 2.074 or less than -2.074.

You are testing the null hypothesis that there is no linear relationship between two variables, X and Y.

From your sample of n = 22. At the a = 0.05 level of significance,

what are the upper and lower critical values for the appropriate test of hypothesis?

:Upper and Lower critical values of the test of hypothesis at the a=0.05 level of significance are +/- 2.074.

The null hypothesis of a linear relationship between two variables, X and Y can be tested by finding the appropriate correlation coefficient and using this test statistic to find the p-value.

This test statistic follows a t-distribution with n-2 degrees of freedom. In this question, n=22.

Therefore, the critical values can be found using the t-distribution table for n-2 degrees of freedom and an alpha level of 0.05 (two-tailed).

From the table, we find the t-value at the 0.025 level of significance with 20 degrees of freedom is 2.074. So the upper and lower critical values of the test are ±2.074.

Thus, the upper and lower critical values of the test of hypothesis at the a=0.05 level of significance are +/- 2.074.

This implies that the null hypothesis is rejected if the test statistic is greater than 2.074 or less than -2.074.

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The central limit theorem states that if the population is normally distributed, then the a) standard error of the mean will not vary from the population mean. b) sampling distribution of the mean will also be normal for any sample size c) mean of the population can be calculated without using samples d) sampling distribution of the mean will vary from the sample to sample

Answers

The central limit theorem states that if the population is normally distributed, then the sampling distribution of the mean will also be normal for any sample size.

According to the theorem, the mean and the standard deviation of the sampling distribution are given as: μ = μX and σM = σX /√n, where μX is the population mean, σX is the population standard deviation, n is the sample size, μ is the sample mean, and  σM is the standard error of the mean .The central limit theorem does not state that the mean of the population can be calculated without using samples. In fact, the sample mean is used to estimate the population mean. This theorem is significant in statistics because it establishes that regardless of the population distribution,  This makes it possible to estimate population parameters, even when the population distribution is unknown, using the sample statistics.

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Suppose that you have 8 cards. 5 are green and 3 are yellow. The cards are well shuffled. Suppose that you randomly draw two cards, one at a time, with replacement. • G1 = first card is green • G2 = second card is green Part (a) Draw a tree diagram of the situation. (Enter your answers as fractions.) 5/ 3/ 51 5 31 20 15 GG GY, 1564 YE 9 > Part (b) Enter the probability as a fraction. PIG, AND G2) 25/64 Part (c) Enter the probability as a fraction. Plat least one green) = 80/64

Answers

The probability of getting at least one green card is 55/64.

Part (a)A tree diagram can help to keep track of the possibilities when drawing two cards with replacement from a deck of eight cards.

In this case, we have two events: G1 = first card is green G2 = second card is green The tree diagram for the given problem is as shown below: 5/8 G 3/8 Y 5/8 G 3/8 Y 5/8 G 3/8 Y G1 G1 Y G1 G2 G2 G2 G2

Part (b) Probability of first card being green P(G1) = 5/8 Probability of second card being green given that the first card was green P(G2|G1) = 5/8

So, P(G1 and G2) = P(G1) x P(G2|G1) = 5/8 x 5/8 = 25/64

Therefore, P(G1 and G2) = 25/64

Part (c)Probability of getting at least one green card means the probability of getting one green card and the probability of getting two green cards.

P(at least one green) = P(G1 and Y2) + P(Y1 and G2) + P(G1 and G2) P(at least one green)

= P(G1) x P(Y2) + P(Y1) x P(G2) + P(G1) x P(G2|G1) P(at least one green)

= (5/8) x (3/8) + (3/8) x (5/8) + (5/8) x (5/8)

= 15/64 + 15/64 + 25/64

= 55/64

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Let A be a factorial ring and
p a prime element. Show that the local ring
A(p) is principal.

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It can be shown that A(p) is a local ring with a unique maximal ideal generated by pA(p), which is the set of all fractions a/b where a is an element of A and b is not divisible by p. since A(p) is a local ring with a unique maximal ideal, A(p) is a principal ideal ring.

Let A be a factorial ring and p a prime element. The local ring A(p) is principal.In order to show that the local ring A(p) is principal, we first need to define what a factorial ring and a local ring is.A factorial ring is defined as an integral domain where every non-zero, non-unit element can be expressed as a product of irreducible elements and this factorization is unique up to order and associates.A local ring is defined as a commutative ring with a unique maximal ideal, which is a proper ideal that is not contained in any other proper ideal of the ring.A as a factorial ring and p as a prime element, A(p) is the localization of A at the multiplicative set S = {1, p, p², ...}.The local ring A(p) can be seen as the ring of fractions of A where we have "localized" the denominators by inverting all elements outside the prime ideal generated by p. More formally, A(p) is the set of all fractions a/b, where a is an element of A and b is an element of S. It can be shown that A(p) is a local ring with a unique maximal ideal generated by pA(p), which is the set of all fractions a/b where a is an element of A and b is not divisible by p.Hence, since A(p) is a local ring with a unique maximal ideal, it follows that A(p) is a principal ideal ring.

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17. The prevalence of a disease is 12% in population X (n = 10,000). Two screening tests have been developed for this disease. Individuals first undergo screening test 1, which has a sensitivity of 85

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Therefore, the positive predictive value of screening test 1 is 27.87%.

The prevalence of a disease is 12% in population X (n = 10,000). Two screening tests have been developed for this disease. Individuals first undergo screening test 1, which has a sensitivity of 85% and a specificity of 70%. Those who test positive on screening test 1 undergo screening test 2, which has a sensitivity of 90% and a specificity of 80%.What is the positive predictive value of screening test 1?A screening test is a medical test given to large groups of people to identify those who have a disease. It is a statistical measure that helps to identify those who have a disease from those who do not. Sensitivity and specificity are two major measures used to determine the effectiveness of a screening test. Sensitivity refers to the percentage of people with the disease who test positive on the screening test. The formula for sensitivity is: Sensitivity = True Positive / (True Positive + False Negative) × 100%The sensitivity of screening test 1 is 85%, which means that of the people with the disease, 85% will test positive on screening test 1.Specificity refers to the percentage of people without the disease who test negative on the screening test. The formula for specificity is: Specificity = True Negative / (True Negative + False Positive) × 100%The specificity of screening test 1 is 70%, which means that of the people without the disease, 70% will test negative on screening test 1.The positive predictive value (PPV) is the probability that a person who tests positive on the screening test actually has the disease. The formula for PPV is :PPV = True Positive / (True Positive + False Positive) × 100%To calculate the PPV of screening test 1, we need to know the prevalence of the disease and the number of people who test positive on screening test 1. The prevalence of the disease in population X is 12%, which means that 1200 people have the disease in a population of 10,000 people. Using the sensitivity and specificity of screening test 1, we can calculate the number of true positive and false positive cases as follows :True Positive = Sensitivity × Prevalence × Total population= 0.85 × 0.12 × 10,000= 1020False Positive = (1 - Specificity) × (1 - Prevalence) × Total population= 0.3 × 0.88 × 10,000= 2640Now that we know the number of true positive and false positive cases, we can calculate the PPV of screening test 1 as follows :PPV = True Positive / (True Positive + False Positive) × 100%PPV = 1020 / (1020 + 2640) × 100%PPV = 27.87%.

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Kevin was asked to solve the following system of inequali-
ties using graphing and then identify a point in the solution
set.

Answers

Kevin's mistake was that he included the line itself in the solution set, instead of shading the region above the line.To fix this, he should represent the solution set as the region above the line y = 2x - 1.

Kevin's mistake can be identified by examining his graph and comparing it to the given inequality. The inequality y > 2x - 1 represents a line with a slope of 2 and a y-intercept of -1. This line has a positive slope, indicating that it should be slanting upwards from left to right.

If we plot the point (2, 5) on Kevin's graph, we can see that it lies on the line y = 2x - 1. However, the original inequality is y > 2x - 1, which means that the solution set should include all points above the line.

To fix Kevin's mistake, he needs to recognize that the solution set consists of all points above the line y = 2x - 1. Therefore, he should have shaded the region above the line, not including the line itself.

By shading the region above the line, Kevin would correctly represent the solution set of the inequality. The point (2, 5) does not lie in this shaded region, so it is not a point in the solution set.

In summary, Kevin's mistake was that he included the line itself in the solution set, instead of shading the region above the line. To fix this, he should represent the solution set as the region above the line y = 2x - 1.

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an insurance provider claims that 80% of cars owners have no
accident in 2021. you randomly selected 6 car owners and asked
whether they had any accidents in 2021. 1. let X denote the number
of car ow

Answers

The probability of having exactly 4 car owners with no accidents in 2021 out of a random sample of 6 car owners is 0.2765.

We can solve this problem by using the binomial distribution formula since we are interested in the number of successes (car owners with no accidents) out of a fixed number of trials (the 6 randomly selected car owners).

The formula for the binomial distribution is P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where n is the number of trials, k is the number of successes, p is the probability of success on any given trial, and (n choose k) is the binomial coefficient calculated as n!/((n-k)!*k!).

In this case, n=6, p=0.8 (the probability of a car owner having no accident), and we want to find P(X=4). Plugging these values into the formula, we get:

P(X=4) = (6 choose 4) * 0.8^4 * (1-0.8)^(6-4)

= 15 * 0.4096 * 0.04096

= 0.2765

Therefore, the probability of having exactly 4 car owners with no accidents in 2021 out of a random sample of 6 car owners is 0.2765.

It's worth noting that this calculation assumes that the insurance provider's claim of 80% is accurate and representative of the population as a whole. If the claim is not accurate or there are other factors that affect the likelihood of car accidents, then the results of this calculation may not accurately reflect the actual probability of having 4 car owners with no accidents in 2021.

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what feature is uniquely associated with cervical vertebrae? Applying the Charter John Nesbitt is an accounting clerk, employed by the municipality of Anytown, Alberta, in the town's financial services department. Like all municipalities, the town has an elected group of councilors and a mayor, who meet to set policy and enact bylaws under the authority of the Municipal Government Act of the province. A bylaw is a type of subordinate legislation. The town employs a large group of employees, from those who work out of doors maintaining streets and roads, to those who work in the town hall itself, serving the public and managing the complex business affairs of the municipality. Following a recent election, the newly elected mayor and councilors embark on a plan that, in their view, will improve the organizational culture of the staff and managers employed by the town. Two new complimentary bylaws are introduced and passed: the first bylaw makes it a requirement that all full-time, permanent employees of the municipality are required to reside within town limits. The motive for this bylaw is to demonstrate that the town is a good place to live, and employees who earn a living working for the town should be expected to live in the town. The second bylaw states that no full-time, permanent employee of the town is permitted to publicly criticize the decisions of town council. John Nesbitt lives with his family on an acreage sometres outside of the town corporate limits. He is a full-time, permanent employee who has worked for Anytown in the finances department for more than seven years, and he has no desire to move his residence or to seek new employment. Nesbitt writes a letter to the editor of the local newspaper; the letter is published, and is critical of the new residency requirement bylaw governing employees of the municipality. 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Joseph Moore, the firm's marketing director, has completed the following sales forecast.Month Sales Month Sales January$920.000July$1.170.000february$1.020.000August$1.500.000March$920.000September$1.600.000April$1.020.000October$1.600.000May$870.000November$1.500.000Juni $970.000Desember $1.700.000charles wilson , an accountant in the planning and budgeting department, is responsible for preparing the cash flow projection. he has gathered the following information .1. all sales are made on credit. what is the correct assignment of the names of the functional groups in the following nitrogen-containing compounds? SP Pointer Construction is considering whether or not to undertake a project that would expand its current operations. Based on the cash flows listed below and with a required rate of return of 14%, what's the NPV of this project? Round your answer to the nearest dollar. 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Suppose the Chinese government imposes an export tax on metal ores due to concerns about the negative impact of mining on the environment. Assume that China is a price taker to the market of metal ores, analyse the changes in welfare after the imposition of export tax. Be sure to fully label the diagram [6 marks] b. An economist determines the demand and supply of metal ores in Chinese market without trade as below Demand: P = 300 - 40 Supply: P = 20 + 0.10 where P is dollar per kg and Q is quantity in kg. Suppose the marginal external cost of producing metal ores is represented by MEC 10+ 0.2Q The world price of metal ores is $90. The export tax is $2/kg Does the imposition of export tax increase or decrease welfare? By how much? [9 marks] how many grams of sodium are required to produce 3.95 grams of sodium hydroxide? assume water is in excess. puritan communities in the first half of the seventeenth century could be characterized by Based on the following data, is there any arbitrage opportunities? Please detail theaction plan to generate arbitrage profit/loss.Spot rate CAD/EUR180 day - Forward rate CAD/EUR0.7322-440.7330-58CAD'S APR5%-6%EUR'S APR7%-8% A price ceiling imposed by the government ALWAYS leads to an excess demand or shortage for a commodity or service. The statement is:Select one:TrueFalse exposure to environmental pollution is most highly correlated with which of the following factors? 1)social class2)race3)income The following data is available for a risky portfolio managed byyou:Expected rate of return = 17%Standard deviation of portfolio = 27%T-bill rate = 7%RequiredCalculate the expected return and standard deviation of a clients portfolio who wishes to invest 70% in the risky portfolio and 30% in T-Bill money market.Calculate the beta of a portfolio, given the following details:E(rp) = 20%rf = 5%E(rm) = 15% Which of the following mechanisms can cause two different proteins to be produced from the same gene? Group of answer choices mRNA splicing alteration by a protease posttranslational modifications NONE OF THESE are good answers RNA editing ALL OF THESE are good answers Assume you won a $10M lottery but it pays in 10 equal installments of $1m each, the first installment is now and the rest 9 payments will continue over the next 9 years. At 10% discount rate, what is the present value (cash value) of this lottery of 10 payments? Hint Find the PV of 9 payments of $1m each discounted at 10% and then add the initial $1m to the PV you just found. The result would be the cash value of the 10 payments Be careful with the signs your calculator displays. Another method is to set your calculator's mode to "Beginning, BGN mode" and just plug N=10 A. 6.759m B.6.156 C.10m D.16.245m the vectors v1 = (1, 2, 3) and v2 = (0, 5, 3) are linearly independent. enlarge {v1 , v2 } to a basis for 3 .