Find m angle LKJif m angle LKD=60^ and m angle DKJ=55^

Answer:

D) x = e - 1

General Formulas and Concepts:

Pre-Algebra

Algebra II

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle ln(x + 1) = 1[/tex]

Step 2: Solve for x

Answer:

Area of a trapezoid= (big base+small base)/2 x height

A=(67+54)/2 x 18

A=60.5 x 18

A=1089  

Answer:

options aren't given but the correct answer will be [tex]\frac{27x^6y^9}{z^9}[/tex]

Step-by-step explanation:

The simplified form of (3x²y³/z³)³ is 27x⁶y⁹/z⁹.

To simplify the expression (3x²y³/z³)³, we apply the rules of exponents. When we raise a power to another power, we multiply the exponents.

First, let's apply the exponent of 3 to each term inside the parentheses:

(3x²y³/z³)³ = 3³ × (x²)³ × (y³)³ / (z³)³

Simplifying further:

= 27 × x⁶ × y⁹ / z⁹

Therefore, the simplified form of (3x²y³/z³)³ is 27x⁶y⁹/z⁹.

This means that each term inside the parentheses is raised to the power of 3, resulting in the expression 27x⁶y⁹/z⁹.

The final expression represents the cube of the original expression, where each term is cubed individually. The exponents are multiplied by 3 to reflect this operation.

In summary, the simplified form is 27x⁶y⁹/z⁹.

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Answer:

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

Step-by-step explanation:

We are given the following function:

[tex]f(x) = \frac{x+1}{x^2-6x+8}[/tex]

It's a fraction, so the domain is all the real values except those in which the denominator is 0.

Denominator:

Quadratic equation with [tex]a = 1, b = -6, c = 8[/tex]

Using bhaskara, the denominator is 0 for these following values of x:

[tex]\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4[/tex]

[tex]x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]

[tex]x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

Answer:

467 voters

Step-by-step explanation:

Given

See attachment for complete question

Required

Sample size at 95% confidence interval

From the attachment, we have:

[tex]p = 65\% = 0.65[/tex]

[tex]E = 4.33\% = 0.0433[/tex]

[tex]CL = 0.95[/tex]

[tex]\alpha = 0.05[/tex] i.e. 1 - CL

First, we calculate the critical level

At [tex]CL = 0.95[/tex] and [tex]\frac{\alpha}{2}[/tex]

[tex]z^* = 1.96[/tex] --- the critical level

So, we have:

[tex]n = p * (1 - p) * (\frac{z^*}{E})^2[/tex]

[tex]n = 0.65 * (1 - 0.65) * (\frac{1.96}{0.0433})^2[/tex]

[tex]n = 0.65 * (1 - 0.65) * (45.3)^2[/tex]

[tex]n = 0.65 * 0.35 * 2052.1[/tex]

[tex]n = 466.9[/tex]

[tex]n = 467[/tex] --- approximated

Answer:

14

Step-by-step explanation:

2+2+82-72

86 - 72 = 14

Answer:

Price of X is $24.81

Price of Y is $3.66

Price of Z is $11.36

Step-by-step explanation:

for person A, we know that earns $40, then we can write the equation:

-4*z + 3*x + 3*y = $40

For person B, we know that earns $50, then:

1*z + 2*x - 3*y = $50

For person C, we know that earns $130, then:

6*z - 1*x + 4*y = $130

Then we have a system of equations:

-4*z + 3*x + 3*y = $40

1*z + 2*x - 3*y = $50

6*z - 1*x + 4*y = $130

To solve the system, we need to isolate one of the variables in one of the equations.

Let's isolate z in the second equation:

z = $50 - 2*x + 3*y

now we can replace this in the other two equations:

-4*z + 3*x + 3*y = $40

6*z - 1*x + 4*y = $130

So we get:

-4*($50 - 2*x + 3*y) + 3*x + 3*y = $40

6*($50 - 2*x + 3*y) - 1*x + 4*y = $130

Now we need to simplify both of these, so we get:

-$200 + 11x - 9y = $40

$350 - 13*x + 28*y = $130

Now again, we need to isolate one of the variables in one of the equations.

Let's isolate x in the first one:

-$200 + 11x - 9y = $40

11x - 9y = $40 + $200 = $240

11x = $240 + 9y

x = ($240 + 9y)/11

Now we can replace this in the other equation:

$350 - 13*x + 28*y = $130

$350 - 13*($240 + 9y)/11 + 28*y = $130

Now we can solve this for y.

- 13*($240 + 9y)/11 + 28*y  = $130 - $350 = -$220

-13*$240  - (13/11)*9y + 28y = - $220

y*(28 - (9*13/1) ) = -$220 + (13/11)*$240

y = ( (13/11)*$240 - $220)/(28 - (9*13/1) ) = $3.66

We know that:

x = ($240 + 9y)/11

Replacing the value of y, we get:

x = ($240 + 9*$3.66)/11  = $24.81

And the equation of z is:

z = $50 - 2*x + 3*y = $50 - 2* $24.81 + 3*$3.66 = $11.36

Then:

Price of X is $24.81

Price of Y is $3.66

Price of Z is $11.36

Answer:

Below

Step-by-step explanation:

It is 5 1/4 PERCENT not just 5 1/4.

5 1/4 % = 5.25%

= 5.25/100

= 0.0525.

The median of the following set of values is equals to 17.

Median represents the middle value of the given data when arranged in a particular order. The mean is the average value which can be calculated by dividing the sum of observations by the number of observations

We are given that the median of the following set of values

7, 21, 19, 15, 19, 14, 15, 19

Line them up in order first.

7, 14, 15, 15, 19, 19, 19, 21

Here the middle value are 15 and 19.

The median is 15 and 19. OR 17,

Therefore, 15 + 19 = 34/2 which equals to 17.

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Explanation:

There are 8 different flavors and 3 types of cones. This means there are 8*3 = 24 different combos possible.

Imagine a table with 8 rows and 3 columns. Each row is a different flavor and each column is a different cone type. The table formed has 24 inner cells to represent a different combination of flavor + cone type. So that's why we multiplied those values earlier.

Note: This only works if you're only able to select one type of flavor.

Answer:

Step-by-step explanation:

As shown in the graph,

A, B, C and D are the vertices of a square, all sides of the square will be equal in measure.

Coordinates of A → (0, 0)

Coordinates of B → (0, m)

Distance between point D and point A = m

Therefore, coordinates of point D → (m, 0)

Now point C will be equally distant from the points B and D.

Coordinates of C → (m, m)

Answer:

I THINK IT IS 74 NOT 4

I HOPE THIS HELPS!!!!!

Answer:

x=7

Step-by-step explanation:

The directrix of a parabola is the vertical line found by subtracting

p from the x-coordinate h

of the vertex if the parabola opens left or right.

x=h-p

Substitute the known values of

p and h

into the formula and simplify.

x=7

Answer:

Step-by-step explanation:

Given right triangle with:

Use Pythagorean and solve for s:

Answer:

c....................

Answer:

3x3x13 and 2 x 2 x 2 x 2 x 2 x 5 x 5

Step-by-step explanation:

Answer:

[tex]ac - bd[/tex]

Step-by-step explanation:

[tex]ac - bd [/tex]

carry on learning

Answer:

- 850

3

Step-by-step explanation:

650 - 700 - 800

650 - 1500

- 850

25 - 45 + 23

- 20 + 23

3

Answer:

1) any number that is greater than ten is considered an integer bigger than ten: for example, 11, 12, 100, 1000000, etc.

2) any number that is smaller than ten is considered an integer smaller than ten: for example, 9, 8, 7, -100, -100000, etc.

3) any number that is bigger than zero is considered an integer bigger than ten: for example, 1, 2, 10, 100, 100000, etc.

4) any number that is smaller than zero is considered an integer smaller than zero: for example, -1, -2, -3, -10, -100000, etc.

Step-by-step explanation:

An integer is any whole number

Answer:

Step-by-step explanation:

integer bigger than 10 is 11

integer smaller than 10 is 9

integer greater than 0 is 1.

integer smaller than 0 is -1.

Answer:

c

Step-by-step explanation:

Answer:

(–1,4)

Step-by-step explanation:

x – y = –5

3x + y = 1

You omit Ys due to their positive and negative signs and you got

4x = –4===> x= –1

and now place –1 inside the upper linear equation and there you have the Y, look

–1 – Y= –5===> –Y= –4===> Y = 4

(–1,4)

Answer:

[tex]\boxed{\sf x- intercepts = 0 , 5 \ and \ -4}[/tex]

Step-by-step explanation:

A function is given to us and we need to find the x Intercepts of the graph of the given function . The function is ,

[tex]\sf \implies f(x) = 2x( x - 5 ) ^2(x+4)^3 [/tex]

For finding the x intercept , equate the given function with 0, we have ;

[tex]\sf \implies 2x ( x - 5 )^2(x+4)^3= 0 [/tex]

Equate each factor with 0 ,

[tex]\sf \implies 2x = 0[/tex]

Divide both sides by 2 ,

[tex]\sf \implies\bf x = 0[/tex]

Again ,

[tex]\sf \implies ( x - 5)^2=0 [/tex]

Taking squareroot on both sides,

[tex]\sf \implies x - 5 = 0 [/tex]

Add 5 to both sides,

[tex]\sf \implies \bf x = 5[/tex]

Similarly ,

[tex]\sf \implies \bf x = -4 [/tex]

Hence the x Intercepts are -4 , 0 and 5 .

{ See attachment also for graph } .

Answer:

2 kilometers

Step-by-step explanation:

every 1 kilometer is a 1/2 hour. double that and you get 2

Answer:

2 < x < 6

Step-by-step explanation:

x/10

1/5 = 2/10

.6 = 6/10

2 < x < 6

Answer:

last one

Step-by-step explanation:

x = width

x+6 = length

Area = length times width

x(x + 6) = [tex]x^{2}[/tex] + 6x

[tex]x^{2}[/tex] + 6x = 114   (subtract 114 from both sides)

[tex]x^{2}[/tex] + 6x -114 = 0

Answer:

Not sure if this is right, but I hope it helps. Please see attached pic

Step-by-step explanation:

9514 1404 393

Answer:

  (a) one parallelogram

  (b) opposite sides are 3 inches and 4 inches. Opposite angles are 45° and 135°

  (c) yes, all side lengths can be determined, see (b)

Step-by-step explanation:

Opposite sides of a parallelogram are the same length, so if one side is 3 inches, so is the opposite side. Similarly, if one side is 4 inches, so is the opposite side. If sides have different lengths, they must be adjacent sides. The given numbers tell us the lengths of all of the sides.

The 4 inch sides are adjacent to the 3 inch sides. Thus the angle between a 4 inch side and a 3 inch side must be 45°. Opposite angles are congruent, and adjacent angles are supplementary, so specifying one angle specifies them all.

Only one parallelogram can be formed with these sides and angles. (The acute angle can be at the left end or the right end of the long side. This gives rise to two possible congruent orientations of the parallelogram. Because these are congruent, we claim only one parallelogram is possible. Each is a reflection of the other.)

Answer:

[tex](a)\ P(White) = \frac{1}{2}[/tex]

(b) 10 additional white balls

(c) 10 additional black balls

Step-by-step explanation:

Given

[tex]White = 5[/tex]

[tex]Black =3[/tex]

[tex]Red = 2[/tex]

Solving (a): P(White)

This is calculated as:

[tex]P(White) = \frac{White}{Total}[/tex]

[tex]P(White) = \frac{5}{5+3+2}[/tex]

[tex]P(White) = \frac{5}{10}[/tex]

[tex]P(White) = \frac{1}{2}[/tex]

Solving (b): Additional white balls, if [tex]P(White) = \frac{3}{4}[/tex]

Let the additional white balls be x

So:

[tex]P(White) = \frac{White+x}{Total+x}[/tex]

This gives:

[tex]\frac{3}{4} = \frac{5+x}{10+x}[/tex]

Cross multiply

[tex]30+3x = 20 + 4x[/tex]

Collect like terms

[tex]4x - 3x = 30 - 20[/tex]

[tex]x = 10[/tex]

Hence, 10 additional white balls must be added

Solving (c): Additional black balls, if [tex]P(White) = \frac{1}{4}[/tex]

Let the additional black balls be x

So:

[tex]P(White) = \frac{White}{Total+x}[/tex]

So, we have:

[tex]\frac{1}{4} = \frac{5}{10+x}[/tex]

Cross multiply

[tex]10+x = 5 * 4[/tex]

[tex]10+x = 20[/tex]

Collect like terms

[tex]x = 20 -10[/tex]

[tex]x = 10[/tex]

Hence, 10 additional black balls must be added