Find the equation of the linear function represented by the table below in
slope-intercept form.

Answer: 3 ovals and 3 rectangles and an even amount of rectangles and ovals

Therefore , the solution of scatter plot is construct this fence, we multiply the IQR by 1.5, subtract Q1 from this result, and add Q3 to the result.

Taxes calculated in the manner above can be considered regular tax liabilities. tax calculated at 15% of book profit (plus any applicable surcharges and cess) (manner of computation of book profit is discussed in later part). The tax that is calculated by applying 15% (plus any applicable surcharge and cess) to book profit is known as MAT.

Here,

In bivariate data, a scatter plot is helpful for identifying outliers (data with two variables).

Because they will be separated from the majority of points on the scatter plot, the outliers are simple to identify.

We can compare each observation to the minimum and maximum fence posts as a result. Outliers are any observations that fall more than 1.5 IQR outside Q1 or rise more than 1.5 IQR outside Q3.

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Considering the diagram of the bike path crosses the angle measures are calculated to be

x = 21 degrees

< KMH = 96 degrees

According to the diagram, the angle at the intersection of the road shows that

84 degrees = 4x

The angles are equal based on the vertical angle theorem

solving for x

84 degrees = 4x

4x = 84

x = 84 / 4 = 21

x = 21 degrees

solving for < KMH

< KMH and 84 are supplementary angles

< KMH + 84 = 180

< KMH = 180 - 84

< KMH = 96 degrees

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In graph theory, a 2-factor is a subgraph of a given graph that includes every vertex of the original graph and has the property that every vertex has even degree (i.e. degree is a multiple of 2).

The term "2-factor" is used because it is a factor of the original graph that is made up of edges and every vertex has degree 2.

A 2-factor can also be defined as a set of cycles that cover all vertices of the graph. In other words, it is a collection of cycles such that every vertex belongs to exactly one cycle. A 2-factor can also be thought of as a cycle cover of a graph.

A graph that has a 2-factor is called a 2-factorizable graph. Not all graphs are 2-factorizable, for example a graph with an odd number of vertices can't have a 2-factor.

2-factors have many applications in various fields such as scheduling, coding theory, and computer science. They are also used to study the connectivity and robustness of graphs.

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To check if two ratios are equivalent, you can divide both ratios by the same number until you reach the same result. For example, if you divide both 1/2 and 3/6 by 2, you will get the same result of 1/3.

To check if two ratios are equivalent, you can divide both ratios by the same number until you reach the same result. For example, if you divide both 1/2 and 3/6 by 2, you will get the same result of 1/3.

1. Take both ratios, 1/2 and 3/6

2. Divide both ratios by the same number, in this case 2.

3. This will give you the equivalent results of 1/3.

4. Therefore, 1/2 is equivalent to 3/6.

To check if two ratios are equivalent, divide both ratios by the same number until you reach . In this case, 1/2 is equivalent to 3/6.

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Measure wall height from floor to ceiling. Exclude baseboards and moldings. Measure length of each wall including doors and windows.

Walls. Use the basic formula of Length x Width = Area to determine the area of a wall. Then, using the same approach, calculate the individual area of windows and doors. After you’ve taken all of these measurements, deduct the area of the windows and doors from the overall wall area. Methods of longwall and shortwall Long walls are those that run the length of the room, whereas short walls are those that run perpendicular to the length of the room.

Next, consider which unit of measurement is most appropriate for measuring a wall. Very tiny units such as inches, centimeters, and millimeters can be ruled out. We can also eliminate.

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8 feet from the end of the wall is the nearest edge of the picture.

The process of converting phrases into equations and then solving those equations is known as solving algebraic word problems.

We will only need to use one variable and fundamental arithmetic operations to create the equations we require. In a real-world situation, the variable often stands for an unknowable quantity.

We can model and resolve word problems on the test that have two overlapping groups using Venn diagrams.

Let's say that the distance from the picture to the wall is x.

Since that distance will be on both sides of the picture (it's in the exact middle), we can say that:

x+3+x=19

=> 2x+3 = 19

=>2x=16

=>x= 8

Thus, 8 feet from the end of the wall is the nearest edge of the picture.

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Answer: 21 boxes are needed

Step-by-step explanation:

Total area:  length  =  1.5 + 6.25 + 1.5  =  9.25     height  =  1.5 + 6.25  =  7.75

Total Area  =  9.25 x 7.75  =  71.6875

Area of the patio  =  6.25 x 6.25  =  39.0625

Area of the extension  =  Total Area - Area of the patio  =  71.6875 - 39.0625  =  32.625

Area covered by one box of tiles:  25 x 0.25 x 0.25  =  1.5625

Number of boxes needed:  32.625 / 1.5625  =  20.88  =  21 boxes

I hope this helps even though you already figured it out!

The hexagon's side length is 4.5 inches whereas the equilateral triangle's side length is 9.

While an exterior angles are equivalent to the sum of the twin interior angles that become not directly adjacent to it, the inside angles necessarily add up to 180°. By lowering the inclination of the target vertex from 180°, one may also get a triangle's exterior angle.

The equilateral triangle's side length is 9 inches.

The hexagon's sides measure 4.5 inches long.

The equilateral triangle's side length is equal to 1.4x plus 2.

Perimeter = 3(1.4x + 2) = 4.2x + 6 as a result.

The hexagon's side length is equal to 0.5x plus 2.

The perimeter is 6(0.5x + 2) = 3x + 12 as a result.

the perimeters being equal.

So,\s4.2x + 6 = 3x + 12

4.2x - 3x = 12-6

1.2x = 6\sx = 5

Hence,

The equilateral triangle's side length is equal to 1.4x + 2 = 1.4(5) + 2 = 9 inches.

The hexagon's side length is equal to 0.5x + 2 (or 0.5(5) + 2; or 4.5 inches).

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The complete question is-

An equilateral triangle has a side length of 1.4x + 2 inches. A regular hexagon has a side length of 0.5x + 2 inches. The perimeters are equal. What is the side length of the triangle? What is the side length of the hexagon? Show your work.

Answer:

7 ≤ x ≤ 25

Step-by-step explanation:

Triangle Inequality Theorem

The sum of any two sides of a triangle is greater than or equal to the third side:

Therefore, the longest side of the triangle is "c".

Let the longest side be "x":

Therefore:

Let the longest side be 16:

Therefore:

As 9 < 16, the longest side cannot be 9.

Therefore, the length of the third side of the triangle, given that the other two sides are 9 ft and 16 ft is greater than or equal to 7, and less than or equal to 25:

The shaded region is made up of the area of a rectangle minus the areas of the semicircles. The semicircles have a diameter of 2 inches, so the radius of each semicircle is 1 inch.

The area of each semicircle can be found using the formula pir^2, where r is the radius. So the area of each semicircle is pi1^2 = pi square inches.

The area of the rectangle is found by multiplying the length by the width: 1 foot * 12 inches/feet = 12 square inches.

The shaded region is the area of the rectangle minus the area of the semicircles. So the area of the shaded region is 12 square inches - 2* pi square inches = 12 - 2* pi square inches.

It's important to note that the length of the shaded region is given in feet (1-foot) but the area of the semicircles and the rectangle is given in square inches.

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Answer: A, [tex]\frac{-6}{17}[/tex]

Step-by-step explanation:

g(3) = 2([tex]3^{2}[/tex]) - 3(3) + 1 = 18 - 9 + 1 =10

f(10) = [tex]\frac{4-10}{7+10}[/tex] = [tex]\frac{-6}{17}[/tex]

Answer:

JF

Step-by-step explanation:

There is a rule where if the angle in a triangle is facing the smallest side, that angle is the smallest of the other 2 angles in the triangle, and vice versa. If the angle in a triangle is facing the biggest side, well, you can see where this is going(the angle is the biggest)

So if we look at this beautiful drawing that I drew :

Angle <JFR is 180 - 115, which is 65.

And the last angle is 180 - 65 - 35 = 80

Angle R is the biggest angle.

So the side that is facing R is the longest side, which is JF

The solution of the trigonometric equation is θ = π/6 radian

Trigonometry is the branch of mathematics that deals with the relationship between ratios of the sides of a right-angled triangle with its angles

2cosθ = √3

Divide both sides by 2:

cosθ = (√3)/2

θ = cos⁻¹[(√3)/2]

θ = 30°

Convert 30° to radian by multiplying it with π/180. That is:

θ = 30 × π/180

θ = π/6 radian

Thus, the solution is θ = π/6 radian

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If the perimeters are the same. Then the dimension of the triangle will be 5, 5, and 6.

The peripheral of a form is defined in mathematics as the entire length of its boundaries. The surrounding of a form is calculated by summing the lengths of all the vertices and edges that surround it. It is measured in linear quantities like cm, meters, inches, and feet.

Let 'x' be the isosceles sides and the 'y' be the third side. Then the equation is given as,

x + x + y = 4 × 4

2x + y = 16

2x + y = 2(5) + 6

Then the dimension of the triangle will be 5, 5, and 6.

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When n is known to be an integer, the formula for m also produces an integer. The assumption is confirmed once the necessary integer m was located.

Positive, negative, and zero are all examples of integers. As a result, integers include numbers like 0, 1, 2, 3, as well as -1, -2, and 3. There are no additional parts, such as fractions or decimals, in integers. As a result, fractional values like 3 1/2 and decimal numbers like -7.5 are NOT integers. All positive counting numbers, zero, and all negative counting numbers that count from negative infinity to positive infinity are included in the category of integers. The fundamental arithmetic operations are included in integer operations (addition, subtraction, multiplication and division). In mathematics, integers are any numbers that are either positive, negative, or zero, with the exception of fractions. As a result, operations on integers are simple.

given

Any whole number that is a multiple of 3 is a type 0 integer. Examples are 3, 6, 9, and 12.

n=1: 3(1)=3

n=2: 3(2)=6

n=3: 3(3)=9

n=4: 3(4)=12

When n is known to be an integer, the formula for m also produces an integer.

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The situations that could be represented by a graph with an y-intercept of 10 is given as follows:

A. Sign up fee of $10.

B. Lilly starts with $10 in her savings account.

E. Tank begins with 10 gallons of water.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which:

Hence options A, B and E are the correct options as they have an initial amount of $10.

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Check the picture below.

AD = 2.6

DB = 4 and DC = 6 , We need to find AD using Euclid's theorem for the right triangle.

Euclid's theorem is a fundamental number theory theorem that asserts that for every two numbers a and b, where b does not equal 0, there exist unique integers q and r such that a = bq + r, where 0 r |b|. To put it another way, a may be divided by b with a remaining of r. Euclid's theorem is a subset of the division method that asserts that for every two integers a and b with b greater than zero, there exist unique numbers q and r such that a = bq + r, where 0 r |b|.

Using Euclid's theorem,

∴ DB² = AD * DC

∴ 4² = AD * 6

∴ 6 AD = 16

∴ AD = 16/6 = 8/3 ≈ 2.67

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A circle chart, often known as a pie chart, is a means to summarize a set of nominal data or a visual depiction of the many values of a particular variable (e.g. percentage distribution).

A circle is created in the plane by each point that is a specific distance from another point (center). Thus, it is a curve made up of points that are separated from one another by a defined distance in the plane. Additionally, it is rotationally symmetric about center at every angle. Every pair of vertices in a circle's closed, two-dimensional plane are evenly spaced apart from the "center." A circular symmetry line is made by drawing a line through the circle. Additionally, it is rotationally symmetric the about center at every angle.

Here,

The pie chart is divided into sectors and segments, and each sector and segment corresponds to a specific amount of the overall (percentage).

The data is a representation of 360°. The pie is always valued at 100% overall.

A pie chart is useful for organising and displaying data by percentage of the total.

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Point D is the center of rotation in the given figure.

A pair of numbers called coordinates are used to locate a point or a form in a two-dimensional plane. The x-coordinate and the y-coordinate are two numbers that define a point's location on a 2D plane.

Triangle A'B'C' rotating about the point d. Observe the Positional relation between ABC and A'B'C' you can get the result. There is no more information given Otherwise i will prove it to you theoretically.

Therefore, Point D can be described as Center of rotation.

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Complete question:

The setup cost for printing the math workbooks, given the printed cost of the books, is $ 1, 800

The setup cost for printing the math workbooks is a fixed cost which means that it will not change regardless of the number of books that are printed.

Since we know that 1, 000 books are printed to be $ 14, 300 and that 5, 000 books cost $ 64, 300, we can find the cost of the books without the setup cost to be :

= Difference in cost of books / ( Difference in number of books )

= ( 64, 300 - 14, 300 ) / ( 5, 000 - 1, 000 )

= 50, 000 / 4, 000

= $ 12. 50

The setup cost is therefore :

= Cost of printing -  (Number of books x cost per book )

= 14, 300 - ( 1, 000 x 12 .5)

= $ 1, 800

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Answer: all are congruent

Step-by-step explanation:

a. The pair of triangles are not congruent.

b. It is impossible to tell about congruency.

c. The pair of triangles are congruent.

Two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure.

These triangles can be slides, rotated, flipped and turned to be looked identical.

a. The given triangles are not congruent.

The triangle has same measures but the side lengths are different.

So the pair of triangles are not congruent.

b. The given pair of triangles are might be congruent if they have side lengths same.

But in the given triangles the side lengths are not measured.

So it is impossible to tell.

c. The given pair of triangles have same measures and same side lengths.

By AAS rule the pair of triangles are congruent.

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So, on solving the provided question we can say that in the function we have m = 500, after 500 miles of driving, the expenses of the 2 plans are equal.

The subject of mathematics includes quantities and their variations, equations and related structures, shapes and their locations, and places where they can be found. The term "function" refers to the relationship between a set of inputs, each of which has an associated output. A connection between inputs and outputs in which each input leads to a single, distinct result is known as a function. Each function is given a domain and a codomain, or scope. Usually, f is used to denote functions (x). input is an x. There are four main types of functions accessible. based on the following factors: on functions, one-to-one functions, many-to-one functions, inside functions, and on functions.

f(m) = .2m + 75

f(m) = .35m

.2m + 75 = ,35m

.15m = 75

m = 500

After 500 miles of driving, the expenses of the 2 plans are equal.

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Answer:$10

Step-by-step explanation:

Assume 20% = 0.20

50 x 0.20 = 10

OR

Move the decimal one place to the left for 10 percent, and double it to get 20 percent.

Answer:

Suppose 20% Equals 0.20.

50 x 0.20 = 10

To acquire 10%, move the decimal one position to the left, and to reach 20%, double it.

Step-by-step explanation:

5-card hands have at least one club  2023203

5-card hands have at least two cards with the same rank 916,272

N[at least one club] = N[total ways] - N'[at least one club]

                               = N[total ways] - N[no clubs]

There are 39 cards without a club. So there are 39 choose 5 = 575757 ways to not get a club.

There are 2598960 possible hands, leaving us with 2598960-575757 ways.

Which is 2023203 hands.

How many 5 card hands will have (at least) two of the same number?

This is a standard deck. Take 2–10 to be what I mean by numbers.

N=∑k=24(91)(4k)⋅(125−k)(41)5−k+[(92)+(91)(41)](42)2⋅(111)(41)

+(91)(42)⋅(121)(43)+(91)(43)⋅(41)(42)

=(760,320+38,016+432)+114,048+2,592+864

=916,272

A standard deck of playing cards contains 13 unique ranks, each with 4 distinct suits. Since we are interested in only pairs from ranks 2 to 10, we shall define A be the collection of the 9 relevant ranks and B be the collection of the 4 ranks (ace, jack, queen, king) where pairs are not a consideration. Collection C is the union of A and B, which contains all 13 ranks.

When computing probabilities we need to select the ranks(s) from a collection and then choose a number of suits (cards). When ranks are chosen from either A or B they are also chosen from C. This is important since we might choose twice from the same collection. For example, we might choose a rank from A for a pair (9 choose 1) and later choose 3 ranks from C for singletons (12 choose 3).

To hopefully make understanding the logic easier, I have first chosen the ranks either from A, B, or C, and immediately following I have chosen the number of cards, which is always choosing from 4 suits. I have inserted a dot between different card selections.

We begin by computing the number of combinations with exactly 2, 3, and 4 of a kind from A. The singletons come from C.

N1=∑k=24(91)(4k)⋅(125−k)(41)5−k=760,320+38,016+432=798,768

We add the case of either two pairs from A or a pair from each of A and B. The singleton comes from C.

N2=[(92)+(91)(41)](42)2⋅(111)(41)=114,048

We add the case of a pair from A and 3 of a kind from C.

N3=(91)(42)⋅(121)(43)=2,592

Finally, we add the case of 3 of a kind from A and a pair from B. Note that the case of both 3 of a kind and a pair from A is the same as the case of both a pair and 3 of a kind from A, which has already been included.

N4=(91)(43)⋅(41)(42)=864

N=N1+N2+N3+N4=916,272

5-card hands have at least one club  2023203

5-card hands have at least two cards with the same rank 916,272

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Answer:

[tex]26u + 14v[/tex]

Step-by-step explanation:

[tex]2(8u - 2v) + 2(5u + 9v) \\ 16u - 4v + 10u + 18v \: \: \\ 26u + 14v \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

The three methods to solve a 3 variable linear system of equations are substitution, elimination, and matrix inversion.

1. Substitution: This method involves isolating one of the variables in one of the equations, then substituting it into the other equations to solve for the other two variables.

2. Elimination: In this method, the coefficients of two of the variables in one of the equations are multiplied by constant values, so that when the two equations are added together, one of the variables is eliminated. The remaining variable can then be solved for, and the other two variables can be found using substitution.

3. Matrix Inversion: This method involves writing the system of equations in matrix form, then inverting the matrix using matrix algebra to solve for the three variables.

The three methods to solve a 3 variable linear system of equations are substitution, elimination, and matrix inversion. Substitution involves isolating one of the variables and substituting it into the other equations, elimination involves multiplying coefficients of two of the variables and adding the equations together to eliminate one of the variables, and matrix inversion involves writing the system of equations in matrix form and inverting the matrix to solve for the three variables.

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3 hours, but must submit the exam no later than the closing time.

The browser displays a notification banner for tests that have a due date to inform students when the test will be marked as incomplete (30 minutes prior, 5 minutes prior, and 1 minute prior).

The browser displays a notification banner for quizzes that are about to auto-submit (using an Until date or the natural course finish date) to inform students of this (30 minutes prior, 5 minutes prior, 1 minute prior, and 10 seconds prior).3 hours, but must submit the exam no later than the closing time.

If students are unable to finish a timed quiz in the full permitted time, the browser will display a notification banner.

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