Find the measure of the arc or angle indicated

Find The Measure Of The Arc Or Angle Indicated

Answers

Answer 1

In the given circle, the measure of arc SM is 106°

Calculating the measure of an arc in the circle

From the question, we are to determine the measure of arc SM.

First, we will determine the measure of angle QSM

m ∠QSM = 37° (Angles in the same segment)

Now,

Let the center of the circle be O

Thus,

OS and OM are radii

Therefore,

m ∠OSM = m ∠OMS

m ∠OSM = 37°

But,

Measure of arc SM = m ∠SOM

Now, we will determine the measure of angle SOM

m ∠SOM = 180° - 37° - 37°

m ∠SOM = 106°

Hence, measure of arc SM is 106°

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Related Questions

Clayton measured a city and made a scale drawing. The scale of the drawing was
7 inches = 1 yard. What is the drawing's scale factor?
Simplify your answer and write it as a fraction.??

Answers

The scale factor of the given scenario is 7/36.

Given that, the scale of the drawing was 7 inches = 1 yard.

We know that, 1 yard = 36 inches

The basic formula to find the scale factor of a figure is expressed as,

Scale factor = Dimensions of the new shape ÷ Dimensions of the original shape.

Here, scale factor = 7/36

Therefore, the scale factor of the given scenario is 7/36.

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Halp me this question

Answers

Answer:

the second equation (59-31-[]=10)

the answer is 18

Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. Focus: (-9,0) Focus: (0, 1/6) Directrix: 2

Answers

The standard form of the equation is 2x^2 + 24y - 35 = 0. To find the standard form of the equation of a parabola with vertex at the origin, we need to use the formula 4p(x^2 + y^2) = (x - h)^2 + (y - k)^2, where (h,k) is the vertex and p is the distance from the vertex to the focus (or directrix, depending on the given information).

For the first characteristic, we have a focus at (-9,0), which is to the left of the vertex at the origin. This means that p = 9 (the distance from the vertex to the focus). Substituting into the formula, we get:
4(9)(x^2 + y^2) = (x - 0)^2 + (y - 0)^2
36x^2 + 36y^2 = x^2 + y^2
35x^2 + 35y^2 = 0
So the standard form of the equation is 35x^2 + 35y^2 = 0. For the second characteristic, we have a focus at (0,1/6), which is above the vertex at the origin. This means that p = 1/6 (the distance from the vertex to the focus). We also know that the directrix is a horizontal line 2 units below the vertex. This means that the equation of the directrix is y = -2. Using the formula and the distance formula between a point and a line, we can write:
4(1/6)(x^2 + y^2) = (y - 0)^2 - 2^2
2x^2 + 24y - 35 = 0

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round 52754.1683 to the nearest ten​

Answers

The answer would be 52750
The answer is 52,750 :)

suppose h and k are subgroups of a group g. if |h| 5 12 and |k| 5 35, find |h > k|. generalize

Answers

The order of the subgroup h ∩ k can be found using Lagrange's theorem, which states that the order of a subgroup of a group G must divide the order of G. Therefore, the order of h ∩ k must divide both |h| and |k|.

In this case, we are given that |h| ≤ 12 and |k| ≤ 35. The largest possible order of h ∩ k occurs when h and k have no elements in common, in which case |h ∩ k| = 1. Therefore, the order of h ∩ k must be a divisor of both |h| and |k| that is less than or equal to 1. Since 1 is the only such divisor, we have |h ∩ k| = 1.

More generally, if |h| = m and |k| = n, then the largest possible order of h ∩ k occurs when h and k have no elements in common, in which case |h ∩ k| = 1. The order of h ∩ k must divide both m and n, so the possible orders of h ∩ k are the divisors of gcd(m, n). Therefore, |h ∩ k| ≤ gcd(m, n).


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A container holds 0.7 liters of oil and vinegar.
3
4
of the mixture is vinegar.

How many liters of oil are in the container? Express your answer as both a fraction and a decimal

Answers

Using the given fraction we can see that there are 0.175 liters of oil in the container.

How many liters of oil are in the container?

We know that 3/4 of the total volume in the container is vinegar, then the remaining fraction must be oil.

The remaining fraction is given by:

1 - 3/4

4/4 - 3/4 = 1/4

Then 1/4 of the total volume is oil (because the mix is only oil and vinegar), and we know that the total volume is 0.7 liters, then the amount of oil is:

(1/4)*0.7 L  =0.175 L

There are 0.175 liters of oil in the mix in the container.

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What is the MEAN of the data set below?(0.2,0.8,0.4,0.3,0.4,0.4,0.4,0.8,1.3)

Answers

Answer:

5/9

Step-by-step explanation:

we add all of the values and divide by the total number in this case 9, all of them add to make 5 so we do 5÷9 to get 5/9

A car factory made 16 cars with a sunroof and 24 cars without a sunroof. What is the ratio of the number of cars without a sunroof to the total number of cars?

Answers

Answer:

3:5

Step-by-step explanation:

24:40

24 cars without sunroof

24+16=40

40 total cars

reduce the ratio of 24:40

12:20

6:10

3:5

the answer is 3:5

if a storage facility charges $1 per cubic yard and the storage space is 32 ft. by 160 ft. by 10 ft. high, how much is the storage charge?

Answers

If a storage facility charges $1 per cubic yard and the storage space is 32 ft. The storage charge is $1999.97.

What is mathematical conversions?

Mathematical conversions refer to the process of changing one unit of measurement to another unit of measurement that is equivalent in value.

First, we need to convert the dimensions from feet to yards, since the rate is given per cubic yard.

32 feet = 10.6667 yards (dividing by 3)

160 feet = 53.3333 yards (dividing by 3)

10 feet = 3.3333 yards (dividing by 3)

Next, we can calculate the volume of the storage space in cubic yards by multiplying the three dimensions:

Volume = 10.6667 yards x 53.3333 yards x 3.3333 yards

Volume = 1999.97 cubic yards (rounded to two decimal places)

Finally, we can calculate the storage charge by multiplying the volume by the rate:

Charge = 1999.97 cubic yards x $1/cubic yard

Charge = $1999.97

Therefore, the storage charge is $1999.97.

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What is the MODE of the data set below (0.2,0.8,0.4,0.3,0.4,0.4,0.4,0.8,1.4)

Answers

The mode of a data set represents the value or values that occur most frequently. In the given data set (0.2, 0.8, 0.4, 0.3, 0.4, 0.4, 0.4, 0.8, 1.4), the value that appears most frequently is 0.4. Therefore, the mode of this data set is 0.4.

Answer: 0.4

Step-by-step explanation:

The number that occurs the most

Find the point P where the function f(x, y, z) = xºy$z? reaches the maximum value for x, y, z > 0 on the unit sphere. (Use symbolic notation and fractions where needed. Give your answer as the coordinates of a point in the form (*,*,*) .) P=

Answers

The point P where the function f(x, y, z) = xºy$z reaches the maximum value for x, y, z > 0 on the unit sphere is (1/√3, 1/√3, 1/√3).

To find the point P where the function f(x, y, z) = [tex]x^y^z[/tex] reaches the maximum value for x, y, z > 0 on the unit sphere, we can use Lagrange multipliers.

Let g(x, y, z) =  x² + y² + z² - 1 be the equation of the unit sphere. We want to maximize f(x, y, z) subject to the constraint g(x, y, z) = 0.

Using Lagrange multipliers, we set up the system of equations

∂f/∂x = λ∂g/∂x

∂f/∂y = λ∂g/∂y

∂f/∂z = λ∂g/∂z

g(x, y, z) = 0

Taking partial derivatives, we get

[tex]y^z * x^{y-1}[/tex]= 2λx

[tex]x^z * y^{z-1}[/tex] = 2λy

[tex]x^y * z^{y-1}[/tex]* ln(z) = 2λz

Simplifying these equations and dividing them by each other, we get:

y ln(x)/x = x ln(y)/y

y ln(z)/z = z ln(y)/y

x ln(z)/z = z ln(x)/x

From the first equation, we get:

y ln(x) = x ln(y)

Taking the exponential of both sides, we get

[tex]x^y[/tex] = yˣ

Similarly, from the second equation, we get

[tex]y^z[/tex] = [tex]z^y[/tex]

And from the third equation, we get

[tex]x^z[/tex] = zˣ

These equations suggest that x, y, and z should all be equal to each other. To confirm this, we can take the logarithm of both sides of x^y = yˣ to get:

y ln(x) = x ln(y)

ln(x)/x = ln(y)/y

This function has a maximum at x = y, which implies that x = y = z. Furthermore, since we are looking for a point on the unit sphere, we have x² + y² + z² = 1, which gives us:

x = y = z = 1/√3

Therefore, the point P is given by (1/√3, 1/√3, 1/√3).

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According to Newton's Law of Cooling, if a body with temperature T, is placed in surroundings with temperature To. Different from that of T₁, the body will either cool or warm to temperature (t) after

t minutes, where T(t)=To+(T₁-To

A metal pan with temperature 140°F is placed in a freezer with temperature 0°F. After 15 minutes, the temperature of the pan is 41°F. Use Newton's Law of Cooling to find the pan's temperature

after 20 minutes.

After 20 minutes the pan will have a temperature of F.

(Round to the nearest integer)

Answers

After 20 minutes, the temperature of the pan will be approximately 29°F.

Using Newton's Law of Cooling, we can write:

T(t) = To + (T₁ - To)e^(-kt)

where T(t) is the temperature of the pan at time t, To is the temperature of the freezer, T₁ is the initial temperature of the pan, and k is a constant that depends on the properties of the pan and the freezer.

We know that after 15 minutes, the temperature of the pan is 41°F, so we can write: 41 = 0 + (140 - 0)e^(-15k)

Simplifying this expression, we get:

e^(-15k) = 41/140

Taking the natural logarithm of both sides, we get:

-15k = ln(41/140)

Solving for k, we get:

k ≈ 0.056

Now we can use this value of k to find the temperature of the pan after 20 minutes:

T(20) = 0 + (140 - 0)e^(-0.056*20) ≈ 29°F

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After 20 minutes, the temperature of the pan will be approximately 29°F.

Using Newton's Law of Cooling, we can write:

T(t) = To + (T₁ - To)e^(-kt)

where T(t) is the temperature of the pan at time t, To is the temperature of the freezer, T₁ is the initial temperature of the pan, and k is a constant that depends on the properties of the pan and the freezer.

We know that after 15 minutes, the temperature of the pan is 41°F, so we can write: 41 = 0 + (140 - 0)e^(-15k)

Simplifying this expression, we get:

e^(-15k) = 41/140

Taking the natural logarithm of both sides, we get:

-15k = ln(41/140)

Solving for k, we get:

k ≈ 0.056

Now we can use this value of k to find the temperature of the pan after 20 minutes:

T(20) = 0 + (140 - 0)e^(-0.056*20) ≈ 29°F

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find an equation of the tangent plane to the given parametric surface at the specified point. r(u, v) = u cos(v)i u sin(v)j vk; u = 5, v = /3

Answers

Step-by-step explanation:

To find the equation of the tangent plane to the surface at the point (5 cos(π/3), 5 sin(π/3), k), we need to first find the partial derivatives of r with respect to u and v:

ru(u, v) = cos(v) i + sin(v) j

rv(u, v) = -5 sin(v) i + 5 cos(v) j + k k

Then, we can plug in the point (5 cos(π/3), 5 sin(π/3), k) to get the partial derivatives evaluated at that point:

ru(5, π/3) = cos(π/3) i + sin(π/3) j = (1/2) i + (√3/2) j

rv(5, π/3) = -5 sin(π/3) i + 5 cos(π/3) j + k k = -5/2 i + (5√3/2) j + k k

Now we can use the point-normal form of the equation of a plane, where the normal vector is given by the cross product of ru and rv:

⟨ru(5, π/3) × rv(5, π/3)⟩ = ⟨(1/2) i + (√3/2) j, (-5/2) i + (5√3/2) j, k⟩ = (-5/2 - √3/2) i + (-5√3/2 - 1/2) j + k k

Thus the equation of the tangent plane to the surface at (5 cos(π/3), 5 sin(π/3), k) is:

(-5/2 - √3/2)(x - 5 cos(π/3)) + (-5√3/2 - 1/2)(y - 5 sin(π/3)) + (z - k) = 0

Simplifying, we get:

-5√3 x + 5y - 5√3 z + (25/2 + 5/2√3) = 0

So the equation of the tangent plane to the surface at the point (5 cos(π/3), 5 sin(π/3), k) is:

-5√3 x + 5y - 5√3 z + 15.79 = 0.

The annual per capita consumption of milk is 21. 6 gallons. Being from the Midwest, you believe milk consumption is higher and wish to support your opinion. A sample of 16 individuals from the midwestern town of Webster City showed a sample mean annual consumption of 24. 1 gallons with a standard deviation of 4. 8. A. Develop a hypothesis test that can be used to determine whether the mean annual consumption in Webster City is higher than the national mean. B. What is a point estimate of the difference between mean annual consumption in Webster City and the national mean?c. At α = 0. 05, test for a significant difference. What is your conclusion?

Answers

a) Null Hypothesis is μ ≤ 21.6 and Alternative Hypothesis is μ > 21.6.

b) Point estimate of the difference between mean annual consumption in Webster City and the national mean is 2.5.

c) We can conclude that there is sufficient evidence to suggest that the mean annual consumption of milk in Webster City is higher than the national mean.

A. The hypothesis test to determine whether the mean annual consumption in Webster City is higher than the national mean can be set up as follows:

Null Hypothesis: μ ≤ 21.6

Alternative Hypothesis: μ > 21.6

where μ is the true population mean annual consumption of milk in Webster City.

B. The point estimate of the difference between mean annual consumption in Webster City and the national mean is simply the difference between the sample mean and the national mean:

Point Estimate = x' - μ = 24.1 - 21.6 = 2.5

C. To test for a significant difference at α = 0.05, we need to calculate the test statistic and compare it to the critical value.

t = (x' - μ) / (s / √n) = (24.1 - 21.6) / (4.8 / √16) = 2.083

Using a t-table with 15 degrees of freedom and a significance level of 0.05, we find the critical value to be 1.753. Since our test statistic (2.083) is greater than the critical value (1.753), we reject the null hypothesis.

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3/11 multiply 5/7 + 22/6 multiply 14/35

Answers

3/11 * 5/7 + 22/6 * 14/35 = 15/77 + 11/15 = (225 + 508) / (77 * 15) = 733 / 1155.

So the answer is 733/1155

Volume of Prisms. I need help with finding the volume please

Answers

The volume of the prism is 259 units³.

How to find the volume of a prism?

The volume of the prism can be calculated as follows:

volume of a prism = base area × height

The prism is a triangular base prism. The area of the base of the prism is 37 units² and the height of the prism is 7 units.

Therefore,

Base area of the prism = 37 units²

height  = 7 units

Hence,

volume of a prism = 37 × 7

volume of a prism = 259 units³

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Consider the following. f(x, y) = x/y, P(8, 1), u = 3/5 i + 4/5 j(a) Find the gradient of f.∇f(x, y) =(b) Evaluate the gradient at the point P.∇f(8, 1) =(c) Find the rate of change of f at P in the direction of the vector u.Duf(8, 1) =

Answers

We are given a function f(x,y) = x/y and a point P(8,1). We need to find the gradient of the function, evaluate it at the point P, and find the rate of change of the function at P in the direction of the vector u = 3/5 i + 4/5 j.

Explanation:

(a) The gradient of a function is a vector that points in the direction of the steepest increase of the function at a point and its magnitude gives the rate of increase. The gradient of the function f(x,y) = x/y can be calculated using partial derivatives as follows:

∇f(x, y) = (∂f/∂x)i + (∂f/∂y)j

= (1/y)i - (x/y^2)j

(b) To evaluate the gradient at the point P(8,1), we substitute x=8 and y=1 in the expression for ∇f(x,y) as follows:

∇f(8, 1) = (1/1)i - (8/1^2)j

= i - 8j

(c) The rate of change of the function f(x,y) at the point P(8,1) in the direction of the vector u = 3/5 i + 4/5 j can be found by taking the dot product of the gradient at P with the unit vector in the direction of u as follows:

Duf(8, 1) = ∇f(8,1) . u/|u|

= (i - 8j) . (3/5 i + 4/5 j)/|(3/5 i + 4/5 j)|

= (3/5) - (32/5)

= -29/5

Therefore, the gradient of f is ∇f(x,y) = (1/y)i - (x/y^2)j, the gradient at P is ∇f(8,1) = i - 8j, and the rate of change of f at P in the direction of u is Duf(8,1) = -29/5.

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find the critical value for testing h 0 : μ = 18.38 versus h a : μ < 18.38 at significance level 0.005 for a sample of size 30. round your final answer to three decimal places.

Answers

Therefore, the critical value for testing the hypothesis at a significance level of 0.005 for a sample of size 30 is -2.756 (rounded to three decimal places).

To find the critical value for testing the hypothesis:

H0: μ = 18.38 (null hypothesis)

Ha: μ < 18.38 (alternative hypothesis)

at a significance level of 0.005 for a sample size of 30, we need to use the t-distribution.

Since the alternative hypothesis is one-tailed (μ < 18.38), we will be looking for the critical value in the left tail of the t-distribution.

The critical value is the value that separates the rejection region from the non-rejection region.

To find the critical value, we can use a t-table or a statistical software. Here, I'll use the t-table.

Since the sample size is 30, the degrees of freedom (df) for this t-test is (n - 1) = (30 - 1) = 29.

Looking up the critical value for a one-tailed test with 29 degrees of freedom and a significance level of 0.005 in the t-table, we find that the critical value is approximately -2.756.

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From exercise 9-15 Find the boundary of the critical region if the type I error probability isa) alpha = 0.01 and n = 10b) alpha = 0.05 and n=10c) alpha = 0.01 and n=16d) alpha = 0.05 and n=16

Answers

a) when alpha = 0.01 and n = 10, the critical region (cr) boundary is at x^- ≤^- - 2.76. b) when alpha = 0.05 and n = 10, the cr boundary is at x^- ≤^- - 1.83. c) when alpha = 0.01 and n = 16, the cr boundary is at x^- ≤^- - 2.60. d) when alpha = 0.05 and n = 16, the cr boundary is at x^- ≤^- - 1.74.

In hypothesis testing, the critical region is the set of values of the test statistic that will lead to the rejection of the null hypothesis. The critical region is determined by the level of significance or alpha and the sample size. The level of significance is the probability of rejecting the null hypothesis when it is true. The critical region is located in the tail of the sampling distribution and is determined by the standard deviation and the mean of the sampling distribution.

For scenario a) where alpha is 0.01 and the sample size is 10, the critical region is located at x^- ≤^- - 2.76. This means that if the sample mean falls below this value, the null hypothesis will be rejected. Similarly, for scenario b) where alpha is 0.05 and the sample size is 10, the critical region is located at x^- ≤^- - 1.83. For scenario c) where alpha is 0.01 and the sample size is 16, the critical region is located at x^- ≤^- - 2.60. Finally, for scenario d) where alpha is 0.05 and the sample size is 16, the critical region is located at x^- ≤^- - 1.74.

In summary, the critical region for hypothesis testing is determined by the level of significance and the sample size. The critical region is located in the tail of the sampling distribution and is determined by the standard deviation and the mean of the sampling distribution. The critical region boundaries for different scenarios of alpha and sample size are provided in the answer above.

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which level of measurement consists of a set of categories that have different names, like eye color?

Answers

Answer: Nominal Scale Level

Step-by-step explanation:

Data that is measured using a nominal scale is qualitative.

colors, names, labels and favorite foods along with yes or no responses are examples of nominal level data.

HELP ME PLEASE I AM GROUNDED AND DONT GET IT

Answers

Answer:

Hi,so since this is a triangle with a right angle and that equals to 90 degrees

so we have found our second number.

The sum of angles in a triangle is 180 degrees

so that would be 27+90+x=180

i.e 117 +x =180

solve equation i.e 180 -117=63

therefore x=63 degrees

hope this was helpful

Answer:

90+27+63=180

so the answer is:

X= 63

I don’t understand this question! Please help me find the answer they are compound shapes

Answers

The area of the shaded region in this problem is given as follows:

995.44 cm².

How to calculate the area of a circle?

The area of a circle of radius r is given by the multiplication of π and the radius squared, as follows:

A = πr²

The radius of a circle represents the distance between the center of the circle and a point on the circumference of the circle, hence it's measure is given as follows:

r = 21 cm.

Then the area of the entire circle is given as follows:

A = π x 21²

A = 1385.44 cm².

The right triangle has two sides of length 39 cm and 20 cm, hence it's area is given as follows:

A = 0.5 x 39 x 10

A = 390 cm².

Then the area of the shaded region is given as follows:

1385.44 - 390 = 995.44 cm².

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a company advertises that food preparation time can be significantly reduced with the handy dandy slicer. a sample of 12 individuals prepared the ingredients for a meal with and without the slicer. you are given the preparation times below. preparation times person with slicer without slicer 1 20 22 2 12 18 3 20 18 4 14 22 5 19 19 6 20 21 7 19 18 8 15 12 9 22 18 10 19 25 11 21 26 12 23 20 to test the null hypothesis, the appropriate probability distribution to use is a . a. normal distribution b. t distribution c. chi-square distribution d. binomial distribution

Answers

The appropriate probability distribution to use to test the null hypothesis in this scenario is the t distribution. This is because the sample size is small (n = 12) and the population standard deviation is unknown. The t distribution allows for estimation of the population mean based on the sample mean and standard deviation.


To test the null hypothesis for this problem, you should use the t-distribution. Here's an explanation of why:
1. You have a small sample size (n = 12), which is less than 30. When you have a small sample size, the t-distribution is more appropriate than the normal distribution.
2. The data consists of paired samples, with each person using the slicer and not using the slicer. This means you are comparing the mean differences within the paired samples.
3. The problem doesn't involve proportions or frequencies, so the chi-square and binomial distributions are not suitable here.

Based on these reasons, the appropriate probability distribution to use for this problem is the t-distribution (option B).

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The perimeter of a rhombus ABCD is 40 cm . Find the area of rhombus of its diagonals BD measures 12 cm.

Answers

Answer:

156cm area of rhombus and 144cm for its diagonal

Step-by-step explanation:

Hope this helps

a professor gives the following scores to her students. (score,frequency) [(35,1) (45,3) (55,6) (65,11) (75,13) (85,10) (95,2) what is the sample standard deviation for the data?

Answers

The sample standard deviation for the given score and frequency is equal to 8.150.

The sample standard deviation for the ,

Calculate the sample mean (X).

X = Σ(x × f) / Σf,

where x = score, f = frequency

Mean X

= (35×1 +45×3 +55×6 + 65×11 +75×13 + 85×10 + 95×2) /(1+3+6+11+13+10+2)

= 35 + 135 + 330 + 715 + 975 + 850 + 190 / 46

= 3230 /46

= 70.2

Calculate the deviation of each score from the mean (x - X).

For 35,  (35 - 70.2) = -35.2

For 45, (45 - 70.2) = -25.2

For 55, (55 - 70.2) = -15.2

For 65, (65 - 70.2) = -5.2

For 75, (75 - 70.2) = 4.8

For 85,(85 - 70.2) = 14.8

For 95, (95 - 70.2) = 24.8

Square each deviation ( (x - X)² ).

For 35, (-35.2)² = 1239.04

For 45, (-25.2)²= 635.04

For 55, (-15.2)² = 231.04

For 65,(-5.2)² = 27.04

For 75,(4.8)² = 23.04

For 85, (14.8)² = 219.04

For 95, (24.8)² = 615.04

Calculate the sum of squared deviations.

Σ(x - X)²

= 1239.04 + 635.04 + 231.04 + 27.04+ 23.04 + 219.04 + 615.04

= 2989.28

Calculate the variance (s²).

s² = Σ(x - X)² / (n - 1)

⇒s²  = 2989.28 / 46 -1

⇒s²  =66.428

Calculate the sample standard deviation (s).

s = √(s²)

⇒s = √(66.428)

⇒ s = 8.150 (rounded to three decimal places)

Therefore, the sample standard deviation for the given data is 8.150.

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solve this please.!!!!!!

Answers

Answer:

(m-4)(m+4)

Step-by-step explanation:

If you multiply both and open up it becomes [tex]m^2-4m+4m-16[/tex], simplify to [tex]m^2-16[/tex]

Write an equation that shows the relationship 30%of 105 is x

Answers

The equation that shows the given relationship is:

105*0.3 = x

How to write the equation for the given relationship?

We want to write an equation that shows the relationship.

30% of 105 is x.

First, remember that if we take a percentage X of a number N, the expression is:

N*(X/100%).

In this case we are taking the 30% of 105, then the expression is:

105*(30%/100%)

105*0.3

And that must be equal to x, then the equation that we want is:

105*0.3 = x

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If R= [0,3] x [0, 4] then use the mid point rule with m = 3 and n = 2 subdivisions to estimate || sin(ay?)da, where m is the number of z-axis subdivisions and n is the number of y-axis subdivisions. You need not simplify your answer.

Answers

Using the midpoint rule with m = 3 and n = 2 subdivisions, the estimate of || sin(ay?)da over the rectangle R = [0,3] x [0,4] is approximately 16.219.

The midpoint rule is a numerical integration method that approximates the value of a definite integral by dividing the integration region into smaller subintervals and approximating the integrand by its value at the midpoint of each subinterval. In this case, we are integrating sin(ay?) over the rectangle R = [0,3] x [0,4], which means that we need to divide the rectangle into m*n subrectangles, each with width 3/m and height 4/n. Then, we can approximate the integral by summing up the contributions of the midpoints of each subrectangle.

In this case, we have m = 3 and n = 2, which means that we need to divide the rectangle into 6 subrectangles, each with width 1 and height 2. The midpoints of the subrectangles are then (0.5,1), (1.5,1), (2.5,1), (0.5,3), (1.5,3), and (2.5,3). Evaluating the integrand at each midpoint, we get the values sin(a*0.5)2, sin(a1.5)2, sin(a2.5)2, sin(a0.5)2, sin(a1.5)2, and sin(a2.5)*2. Summing up these values and multiplying by the area of each subrectangle (2), we get the estimate of 16.219.

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Marine has a 6-inch-wide rectangular photograph. She wants to enlarge the photograph using the scale 1:5. What is the width of the enlarged photograph?

Answers

The enlarged photograph will be 30 inches in width and a proportional length.

Marine has a rectangular photograph that measures 6 inches in width. If she wants to enlarge the photograph using a scale of 1:5, this means that the size of the photograph will be increased by a factor of 5 in both width and height.

To determine the new width of the photograph, we can multiply the original width of 6 inches by 5, which gives us a width of 30 inches for the enlarged photograph.

It's important to note that while the width of the photograph will increase, the aspect ratio of the photograph will remain the same.

This means that the length of the photograph will also be increased by the same factor of 5.

Therefore, the enlarged photograph will be 30 inches in width and a proportional length.

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what is 13/24 as a decimal rounded to the nearest tenth

Answers

Answer: 0.54

Step-by-step explanation:

13/24 is 0.54166.....

So if you round that by a tenth, it would be 0.54 because 1 is ower than five is its the same

Answer:

0.5

Step-by-step explanation:

13/24 = 0.541666...

by rounding it to the nearest tenth, it will be 0.5 since the succeeding number from the tenth is lower than 5

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