Find the number of integral solutions of x+y +z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and
z ≥ 3.

Answers

Answer 1

The total number of integral solutions of x + y + z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and z ≥ 3 is; 59 integer solutions

How to find the number of Integral Solutions?

We are given the condition that;

−3 ≤ x ≤ 4

Thus, we will use x values of -3, -2, -1, 0, 1, 2, 3, 4

When;

x = -3 and y = 2, in x + y + z = 12, solving for z gives z = 13

x = -3 and y = 3,  in x + y + z = 12, solving for z gives z = 12

x = -3 and y = 4,  in x + y + z = 12, solving for z gives z =11

x = -3 and y = 5,  in x + y + z = 12, solving for z gives z = 10

x = -3 and y = 6,  in x + y + z = 12, solving for z gives z = 9

x = -3 and y = 7,  in x + y + z = 12, solving for z gives z = 8

x = -3 and y = 8,  in x + y + z = 12, solving for z gives z = 7

x = -3 and y = 9,  in x + y + z = 12, solving for z gives z = 6

x = -3 and y = 10,  in x + y + z = 12, solving for z gives z = 5

x = -3 and y = 11,  in x + y + z = 12, solving for z gives z = 4

Thus, there are 10 solutions with x =-3

Repeating the above with x = -2, we will have 10 solutions

Similarly, with x = -1, we will have 9 more solutions

Similarly, with x = 0, we will have 8 more solutions.

Similarly, with x = 1, we will have 7 more solutions.

Similarly with x = 2, we will have 6 more solutions.

Similarly with x = 3, we will have 5 more solutions.

Similarly with x = 4, we will have 4 more solutions.

Thus,

Total number of solutions = 4 + 5 + 6 + 7 + 8 + 9 + 10 + 10

= 59 integer solutions

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Related Questions

Hey help mee if you solve it you are intelligent // what number is car park

Answers

Answer: The answer is 87. when you look at the picture each number is one number apart from each other like look at

86, 87, 88, 89, 90, 91

85 + 1  = 86

86 + 1 = 87

87 + 1 = 88

89 + 1 = 90

90 + 1 = 91

Step-by-step explanation:

Which of the
following satisfies
this graph?

Answers

Answer:

C

Step-by-step explanation:

y is greater or equal to 0

x is also greater or equal to 0

you can see that only one answer choice can be the answer

the line is x-y = 2

the upper side is x-y <= 2

proves that c is the answer

x-y ≤ 2

y ≥ 0

x ≥ 0 satisfies this graph. Thus option C is correct.

What is a graph?

A schematic or visual presentation that organizes the depiction of data or quantities is known as a graph. The relationships connecting two or more objects are frequently represented by the spots on a graph. They are employed to arrange data in order to highlight correlations and patterns. This data is presented as a pattern on a graph.

When y is bigger than 0 and x is also.

The equation is 2x-y.

x-y ≤ 2 on the upper side of the graph is represented in this same way.

x-y ≤ 2; y ≥ 0 and x ≥ 0 will be the correct represented points in the graph. Therefore, option C is the correct option.

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What is a31 of the
arithmetic sequence for
which a5 = 12.4 and
ag = : 22.4?

Answers

The value of a₃₁ of the arithmetic sequence exists 77.4.

How to find the value of a₃₁ of the arithmetic sequence?

Given: a₅ = 12.4 and a₉ = : 22.4

For the arithmetic sequence a₁, a₂, a₃, ..., the n-th term exists

where d = common difference

a₅ = 12.4,

a₁ + 4d = 12.4 .........(1)

Because a₉ = 22.4,

a₁ + 8d = 22.4 .........(2)

Subtract (1) from (2), we get

a₁ + 8d - (a₁ + 4d) = 22.4 - 12.4

4d = 10

Dividing throughout by 4, we get

d = 2.5

From (1), we get

a₁ = 12.4 - 4 [tex]*[/tex] 2.5 = 2.4

a₃₁ = 2.4 + 30 [tex]*[/tex] 2.5 = 77.4

Therefore, the correct answer is a₃₁ = 77.4

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Solve each of the following systems of equation.
(b.) 3x + y = 1
6x^2 - y^2 - 2y - 3 = 0

Answers

(a) The solution to the given system of equations is x = 1, y = 2, z = -3

(b) The solutions to the system of equations are (3.4142, -9.2426) and (0.5858, -0.7574)

Solving system of equations

From the question, we are to solve the given system of equations

The given system of equation is

x + y + z = 0      ----------- (1)

2x + z = -1         ----------- (2)

x - y - z = 2       ----------- (3)

Add equations (1) and (3)

x + y + z = 0      ----------- (1)

x - y - z = 2       ----------- (3)

__________

2x = 2

x = 2/2

x = 1

Substitute the value of x into equation (2) to find z

2x + z = -1        

2(1) + z = -1

2 + z = -1

z = -1 -2

z = -3

Substitute the values of x and z into equation (1) to determine the value of y

x + y + z = 0    

1 + y + -3 = 0

1 + y - 3 = 0

y = 3 -1

y = 2

Hence, the solution to the given system of equations is x = 1, y = 2, z = -3

b.

The given system of equations is

3x + y = 1                       --------- (1)

6x² - y² - 2y -3 = 0        --------- (2)

From equation (1)

3x + y = 1

y = 1 - 3x -------- (3)

Substitute into equation (2)

6x² - y² - 2y -3 = 0

6x² - (1 -3x)² -2(1 -3x) -3 = 0

6x² - (1 -3x)(1 -3x) -2 + 6x -3 = 0

6x² - (1 -3x -3x +9x²) -2 +6x -3 = 0

6x² - (1 -6x + 9x²) +6x -5 = 0

6x² -1 +6x -9x² +6x -5 = 0

-3x² +12x -6 = 0

3x² -12x +6 = 0

x² -4x + 2 = 0


Solve the quadratic equation by the formula method,

x = [-b±√(b²-4ac)]/2a

a = 1, b = -4 and c = 2

Thus,

x = [-(-4)±√((-4)²-4(1)(2))]/2(1)

x = [4±√(16-8)]/2

x = (4±√8)/2

x = (4+√8)/2 OR (4 - √8)/2

x = 3.4142 OR x = 0.5858

Substitute the values of x into equation (3)

y = 1 - 3x

When x = 3.4142

y = 1 - 3(3.4142)

y = -9.2426

When x = 0.5858

y = 1 - 3(0.5858)

y = -0.7574

Hence, the solutions to the system of equations are (3.4142, -9.2426) and (0.5858, -0.7574)

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What is the equation for the line of best fit on the scatter plot below?

Answers

We've got a negative slope, but it doesn't look steep enough to go through 6 on the y-axis.

So, it's the last option:

y = - 1.25x + 5.75

Hope this helps!

A square field was enlarged by adding 5 feet to the length and width of the original field. if the area of the enlarged field is 576 square feet, what was the side length of the original field?

Answers

The side length of the original field is 19 feet.

What is square?

A square is a special kind of rectangle (an equilateral one) and a special kind of parallelogram (an equilateral and equiangular one). A square has four axes of symmetry, and its two finite diagonals (as with any rectangle) are equal. Bisection of a square by a diagonal results in two right triangles.

Suppose the original square is x feet wide. Since its the length and width are the same,

So, length of side of enlarged field = x+5

Area of new enlarged field =  side²  = ( x + 5 )²

So, the enlarged shape would be = ( x + 5 ) ( x + 5)

  Then ,  ( x + 5 ) ( x + 5) = 576

               ( x + 5 )²= 576

                x + 5 = √576

               x + 5  = 24

                 x = 24 - 5 ⇒ 19

Hence, The side length of the original field is 19 feet.

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Solve each pair of simultaneous equations by elimination method.
a) 2x+3y-1=0
5x+2y+3=0​

Answers

make x the subject
2x = -3y + 1
5x = -2y -3

now times the answers to get the lcd

(2x = -3y + 1) x 5
10x = -15y + 5

(5x = -2y -3) 2
10x = -4y -6

now that they are equal to the same number:
-15y + 5 = -4y -6
-15y + 4y = -6 -5
-11y = -11
y = 1

now to find x we substitute y
2x = -3y + 1
2x = -3(1) + 1
2x = -3 + 1
2x = -2
x = -1


Answer:

x = -1

y = 1

Step-by-step explanation:

PART I: Find the y-value

Given expressions

1) 2x + 3y - 1 = 0

2) 5x + 2y + 3 = 0

Add 1 on both sides of the 1) equation:

2x + 3y - 1 + 1 = 0 + 1

2x + 3y = 1

Subtract 3 on both sides of the 2) equation:

5x + 2y + 3 - 3 = 0 - 3

5x + 2y = -3

Current System

1) 2x + 3y = 1

2) 5x + 2y = -3

Multiply 2.5 on both sides of the 1) equation

(2.5) 2x + (2.5) 3y = (2.5) 1

5x + 7.5y = 2.5

Current System

1) 5x + 7.5y = 2.5

2) 5x + 2y = -3

Subtract 2) equation from 1) equation

(5x + 7.5y) - (5x + 2y) = 2.5 - (-3)

Get rid of the parenthesis

5x + 7.5y - 5x - 2y = 2.5 + 3

Combine like terms

5x - 5x + 7.5y - 2y = 5.5

0 + 5.5y = 5.5

5.5y = 5.5

Divide 5.5 on both sides

5.5y / 5.5 = 5.5 / 5.5

[tex]\boxed{y=1}[/tex]

PART II: Find the x-value

Substitute the y-value back to one of the equations to find the x-value

2x + 3y - 1 = 0

2x + 3(1) - 1 = 0

Combine like terms

2x + 3 - 1 = 0

2x + 2 = 0

Subtract 2 on both sides

2x + 2 - 2 = 0 - 2

2x = -2

Divide 2 on both sides

2x / 2 = -2 / 2

[tex]\boxed{x=-1}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

How do I rewrite 1/4 book 1/3 hour as a unit rate?

Answers

The unit rate of 1/4 book 1/3 hour in books per hour is 3/4 books per hour.

Unit rate

Unit rate is the rate of a quantity in terms of another quantity per unit.

Number of books = 1/4Number of hours = 1/3

Unit rate(books per hour) = Number of books / Number of hours

= 1/4 ÷ 1/3

= 1/4 × 3/1

= (1×3) / (4×1)

= 3/4 books per hour

Therefore, the unit rate of 1/4 book 1/3 hour in books per hour is 3/4 books per hour.

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StartFraction 6 Over 7 EndFraction x + one-half = StartFraction 7 Over 8 EndFraction for x?

Answers

The value of x in 6/7x + 1/2 = 7/8 is 7/16

How to solve for x?

The equation is given as:

6/7x + 1/2 = 7/8

Subtract 1/2 from both sides

6/7x + 1/2 -1/2 = 7/8 -1/2

Evaluate the difference

6/7x = 3/8

Multiply both sides by 7

6x = 21/8

Divides both sides by 6

[tex]x = \frac {7}{16}[/tex]

Hence, the value of x is 7/16

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A set of eight cards were labeled as M, U, L, T, I, P, L, Y. What is the sample space for choosing one card?

S = {I, U, Y}
S = {M, L, T, P}
S = {I, L, M, P, T, U, Y}
S = {I, L, L, M, P, T, U, Y}
Question 2(Multiple Choice Worth 2 points)
(Sample Spaces LC)

A paper bag has five colored marbles. The marbles are red, green, blue, yellow, and orange. List the sample space when choosing one marble.

S = {1, 2, 3, 4, 5}
S = {red, blue, green, yellow}
S = (g, r, b, y, o}
S = (green, blue, yellow, orange}
Question 3(Multiple Choice Worth 2 points)
(Sample Spaces LC)

A four-part spinner is spun once.

spinner with four parts labeled W, X, Y, and Z

List the sample space for the experiment.

S = {X, Y, Z}
S = {W, Z, Z}
S = {W, Y, Y, Z}
S = {W, X, Y, Z}
Question 4(Multiple Choice Worth 2 points)
(Sample Spaces LC)

Which event will have a sample space of S = {h, t}?

Flipping a fair, two-sided coin
Rolling a six-sided die
Spinning a spinner with three sections
Choosing a tile from a pair of tiles, one with the letter A and one with the letter B
Question 5(Multiple Choice Worth 2 points)
(Sample Spaces MC)

Julia had a bag filled with gumballs. There were 2 lemon-lime, 3 watermelon, and 5 grape gumballs. What is the correct sample space for the gumballs in her bag?

Sample space = 2, 3, 5
Sample space = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Sample space = lemon-lime, watermelon, grape
Sample space = lemon-lime, lemon-lime, watermelon, watermelon, watermelon, grape, grape, grape, grape, grape
Question 6 (Essay Worth 4 points)
(Sample Spaces HC)

Part A: Create your own experiment with 5 or more possible outcomes. (2 points)
Part B: Create a sample space for a single experiment and explain how you determined the sample space. (2 points)

Answers

The correct answers to the sample space illustrated will be:

S = {I, L, L, M, P, T, U, Y}.

S = {g, r, b, y, o}.

S = {W, X, Y, Z}.

Flipping a fair, two-sided coin.

Sample space = lemon-lime, lemon-lime, watermelon, watermelon, watermelon, grape, grape, grape, grape, grape.

S = {Joy, Bob, Ben, Peter, John}

How to explain the probability?

A paper bag has five colored marbles. The marbles are red, green, blue, yellow, and orange. The sample space when choosing one marble will be S = {g, r, b, y, o}.

A four-part spinner is spun once and the spinner with four parts labeled W, X, Y, and Z. The sample space for the experiment is S = {W, X, Y, Z}.

The event will have a sample space of S = {h, t} is the flipping a fair, two-sided coin.

The correct sample space for the gumballs in her bag will be sample space = lemon-lime, lemon-lime, watermelon, watermelon, watermelon, grape, grape, grape, grape, grape.

My experiment with 5 or more possible outcomes will be that a teacher wants to randomly give one of his give students a pack of chocolate.

The sample space for the experiment will be based on their names. This will be S = (Joy, Bob, Ben, Peter, John).

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Towns A, B, and C lie on a straight line, as shown below. Jack and Arthur start at Town B and drive for an hour from Town B to Town C, where they stop for an hour to eat lunch. Which of the following graphs could represent their distance from Town A during these two hours?

Answers

The situation described by the distance from Town A is the first graph.

Given that cities A,B and C are on straight line.

We are required to find the graph appropriate the given situation.

Distance is basically the measurement of how far two things,places are located.It can be measurement from one point to another .

On the first hour,they leave town B to town C moving farther from Town A,hence the distance is increasing on the first hour.

On the second hour they stop for lunch,meaning that the distance remains constant at the point, it was at the end of the first hour.

Hence if towns A,B C lie on a straight line and Jack and Arthur start at town B and drive for an hour from Town B to Town C then the distance shown from Town A during these two hours is first graph.

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5x-2y=10
4y+20=10x

Solving systemd

Answers

Answer:

The answer is x=2 and y=0.

Step-by-step explanation:

The given Equations are:

                    5x-2y=10      ----------------- (i)
                    4y+20=10x   ----------------- (ii)

From equation find the value of x, that is:

         5x=10+2y         (Obtained By adding 2y on both side of Equation (i))

Next divide with 5 on both side to get x:

          x=(10+2y)/5           ------------------ (iii)

Put this value of x in equation (ii):

        4y+20=10((10+2y)/5)

Simplifying the above equation:

         4y+20=2(10+2y)

         4y+20=20+4y

From the above equation the solution of y is not possible.

We can make it 0. So,
         y=0

Put this value of y in equation (iii), to get value of x:

        x=(10+2(0))/5

        x=(10+0)/5

        x=10/5

        x=2

Given a triangle ABC at points A = (-6, 3) B=(-4,7) C = (-2, 3), and a first transformation of up 2 and right
3, and a second transformation of down 1 and left 6, what would be the location of the final point B"?
Select one:
O a. (-7,8)
O b. (7,-4)
Oc. (-7,4)
O d. (-1,8)

Answers

Given a triangle ABC at points A = (-6, 3) B=(-4,7) C = (-2, 3), and a first transformation of up 2 and right 3, and a second transformation of down 1 and left 6, the final point B" is located at (-7, 8), which is option (a).

What is transformation?

In mathematics, a transformation refers to a change or mapping of one set of values to another set. In geometry, a transformation involves changing the position, size, or orientation of a geometric object.

To find the location of the final point B", we need to apply the two transformations given to the initial point B (-4, 7).

First transformation: up 2 and right 3

This means we add 2 to the y-coordinate (to move the point up) and add 3 to the x-coordinate (to move the point right).

So, the new location of B after the first transformation is: (-4 + 3, 7 + 2) = (-1, 9)

Second transformation: down 1 and left 6

This means we subtract 1 from the y-coordinate (to move the point down) and subtract 6 from the x-coordinate (to move the point left).

So, the new location of B" after the second transformation is: (-1 - 6, 9 - 1) = (-7, 8)

Therefore, the final point B" is located at (-7, 8), the correct option is a.

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If two cards are drawn from a deck, what is the probability that exactly one of the cards will be a face card?

Answers

The probability of getting exactly one face card is 0.72.

According to the questions two cards are drawn from a deck.

Since, we know that

Total number of cards in a deck = 52

Total number of face cards =  3 × 4 = 12

So, the number of ways of selecting 2 cards from a deck = [tex]^{52} C_{2}[/tex]

And, the total number of ways of  getting exactly one face cards

= [tex]^{12} C_{1} \times ^{40} C_{1}[/tex]  + [tex]^{40} C_{1} \times ^{12} C_{1}[/tex]

= 2[tex]^{40} C_{1} \times ^{12} C_{1}[/tex]

Therefore, the probability of getting exactly one face card

= [tex]\frac{2(^{40} C_{1} \times ^{12} C_{1})}{^{52C_{2} } }[/tex]

[tex]= \frac{2(\frac{40 \times 39!}{1!\times 39!} \frac{12\times 11!}{11!}) }{\frac{52\times 51\times 50!}{2!\times50!} }[/tex]

[tex]= \frac{2(40\times 12)}{26\times 51}[/tex]

[tex]=\frac{2\times 480}{1326}[/tex]

= 0.72

Hence, the probability of getting exactly one face card is 0.72.

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A legend says that a tower of hanoi puzzle with 64 discs is being solved, one move per
second. how long will it take to solve this puzzle? explain how you know.

Answers

It will take 585 billion years to solve the puzzle tower of Hanoi puzzle.

What is hanoi of tower?

The Tower of Hanoi is a mathematical game or puzzle that uses three rods and a number of disks that can slide onto any rod. It is also known as The Problem of the Benares Temple, the Tower of Brahma, Lucas' Tower, or simply the pyramid puzzle. The disks are stacked on one rod at the start of the problem, the smallest at the top and roughly forming a conical shape.

Using the Tower of Hanoi as little as possible

In one version of the problem, 64 golden disks are being used by Brahmin priests to solve it.

Minimum moves required if you had 64 golden disks [tex]=2^{64}-1[/tex]

The problem would take around 585 billion years to solve if every move took a single second.

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Use theorem 9. 11 to determine the convergence or divergence of the p-series. 1 1 6 32 1 6 243 1 6 1024 1 6 3125. .

Answers

The given series is diverges according to the P Test.

According to the statement

we have given that the a series and we have to find that the those series is a converges or diverges.

So, For this purpose, we know that the

P-series test to say whether or not the series converges.

So, The given series is

[tex]1 + 1/\sqrt{32} + 1/\sqrt[3]{243 } + 1/\sqrt[4]{1024} + 1/\sqrt[5]{3125}[/tex]

And then

The value of  P becomes P = 5/6 < 1  when we find it using the p series test.

Hence, the p-series diverges

Because according to the p series test, The series converges if, and only if, the power satisfies p>1.

And diverges if, and only if, the power satisfies p<1.

So, The given series is diverges according to the P Test.

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

Use Theorem 9.11 to determine the convergence or divergence of the p-series. 1 + 1/32 squareroot + 1/243 squareroot 3 + 1/1024 squareroot 4 + 1/3125 squareroot 5.

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Point C is at (-9, -2) and point M is at (-1, 4). Point M
is the midpoint of the line segment whose endpoints
are C and D.
What are the coordinates of endpoint D?

Answers

Answer:

The coordinates of D is (7, 10)

Explanation:

Let the coordinates of endpoint D be (x, y)

Mid-point formula:

[tex]\sf (x_m, y_m) = (\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})[/tex]

Applying formula:

[tex]\sf (-1, \:4) = (\dfrac{-9+ x}{2},\: \dfrac{-2+y}{2} )[/tex]

Comparing found:

[tex]\sf -1 =\dfrac{-9+ x}{2} \quad and \quad \: 4 = \dfrac{-2+y}{2}[/tex]

[tex]\sf 2(-1)+9 =x \quad and \quad \: 2(4)+2 =y[/tex]

[tex]\sf x = 7 \quad and \quad \: y = 10[/tex]

So, coordinates of D is (7, 10)

The answer is (7, 10).

Remember the midpoint formula : [tex]\boxed {M = (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})}[/tex]

Finding the x coordinate of D

x = (x₁ + x₂) ÷ 2-1 = (-9 + x₂) ÷ 2-2 = -9 + x₂x₂ = 7

Finding the y coordinate at D

y = (y₁ + y₂) ÷ 24 = (-2 + y₂) ÷ 28 = -2 + y₂y₂ = 10

What is the annual interest paid on an account that has a $1000 balance if the rate is [tex]7\frac{1}{2}[/tex]%?

Answers

The annual interest paid on the account is $75

How to determine the annual interest

The formula for determining annual interest is given as;

Interest = PRT/100

where;

P is the principal amount = $1000R is the rate = 7. 5%T is the time = 1 year, since it's an annual payment

Substitute the values

Annual Interest = 1000 × 7. 5 × 1/ 100

Annual interest = 7500/ 100

Annual interest = $75

Thus, the annual interest paid on the account is $75

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Assuming brokerage fees of $6000, calculate the amount of cash needed to retire baldwin's 12. 4s2028 bond early

Answers

The amount of cash needed to retire baldwin's bond early based on the brokerage will be $5427896.

How to calculate the cash?

It should be noted that from the information given, we are to calculate the amount of cash needed to retire baldwin's bond early based on the brokerage.

This will be:

= 6000 + (5756951 × 94.18/100)

= 6000 + 5421896.45

= 5427896

Therefore, the amount of cash needed to retire baldwin's bond early based on the brokerage will be $5427896.

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A 3.0-kg ball moving eastward at 4.0 m/s suddenly collides with and sticks to a 5.0-kg ball moving northward at 3.0 m/s. what is the magnitude of the momentum of this system just after the collision?

Answers

Magnitude of the momentum of this system just after the collision = 19.2Kgm/s

What is law of conservation of momentum?

Law of conservation of momentum states that the total momentum after the collision must be equal to the total momentum before the collision.

The momentum of each ball is given by:

p = mv

where m is the mass of the ball and v its velocity.

The momentum of ball 1 is:

p = mv

= (3.0 kg)(4.0 m/s)

= 12.0 kg m/s in the eastward direction

The momentum of ball 2 is:

p = mv

= (5.0 kg)(3.0 m/s)

= 15.0 kg m/s in the northward direction

The two momenta are in perpendicular directions, so the magnitude of the total momentum can be found as:

[tex]p = \sqrt{p1^{2} +p2^{2} }[/tex]

[tex]p = \sqrt{12^{2} +15^{2} }\\p = \sqrt{144 + 225} \\p = \sqrt{369}\\ p = 19.2 kgm/s[/tex]

and due to the law of conservation of the momentum, this is also equal to the total momentum after the collision.

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Consider the exponential function g(x) = 1,296 x .

Find the output values for x-values x = –1.75, –1, –0.25, 0, 0.25, 0.50, 0.75, and 1.

Answers

The values associated to the exponential function are listed below:

g(- 1.75) = 3.572 × 10⁻⁶g(- 1) = 7.716 × 10⁻⁴g(- 0.25) = 0.167g(0) = 1g(0.25) = 6g(0.50) = 36g(0.75) = 216g(1) = 1 296

How to evaluate an exponential function

Herein we have the exponential function [tex]g(x) = 1\,296^{x}[/tex], which has to be evaluated, that is, replacing the variable x by constants and make use of algebra properties until result is found.

g(- 1.75) = 3.572 × 10⁻⁶

g(- 1) = 7.716 × 10⁻⁴

g(- 0.25) = 0.167

g(0) = 1

g(0.25) = 6

g(0.50) = 36

g(0.75) = 216

g(1) = 1 296

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If the store has only 12 red balloons and only 8 blue balloons but at least 29 of each other color of balloon, how many combinations of balloons can be chosen?

Answers

The number of combinations of balloons that can be chosen is 1716.

Selections and combinations are synonyms. Combinations represent the choosing of items from a predetermined group of items. We're not trying to arrange anything here. We're going to pick them.

Utilizing the combinations formula, it is simple to determine how many distinct groups of r objects each may be created from the provided n unique objects.

Number of red balloons = 12

Number of blue balloons = 8

First, we figure out how to choose from 13 red and 9 blue balloons.

There are 7 balloons left out of the 29 total (i.e. 29 - 13 - 9)

So, n = 7+7-1

n = 13

r = 7

Number of combinations of balloons = [tex]_{13} C_{7}[/tex]

                                                               = 13!/(13-7)!7!

                                                               = 13!/6!7!

                                                               = 1716

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Louise, Tammy, Delores, and Sheryl score 78 points total in the tennis matches they play. They score a consecutive number of points from smallest to greatest in respect to the order of the names mentioned. How many points does Louise score?

Answers

[tex]\huge\boxed{18\ \text{points}}[/tex]

We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with [tex]x[/tex], [tex]x+1[/tex], [tex]x+2[/tex], and [tex]x+3[/tex] respectively since each one is 1 point more than the last.

Add all of these values up and set it all equal to [tex]78[/tex].

[tex]x+x+1+x+2+x+3=78[/tex]

Now, simplify.

[tex]4x+6=78[/tex]

Subtract [tex]6[/tex] on both sides.

[tex]\begin{aligned}4x+6-6&=78-6\\4x&=72\end{aligned}[/tex]

Divide both sides by [tex]4[/tex].

[tex]\begin{aligned}\frac{4x}{4}&=\frac{72}{4}\\x&=\boxed{18}\end{aligned}[/tex]

Since Louise's score is [tex]x[/tex], the answer is [tex]18[/tex].

Double-checking

To verify our answer, add the point totals [tex]18[/tex], [tex]19[/tex], [tex]20[/tex], and [tex]21[/tex].

This equals [tex]78[/tex], so we can be sure the answer is correct.

How many different anagrams (including nonsensical words) can be made from the letters in the word statistics, using all the letters?

Answers

50,400 different anagrams can be made from the letters in the word statistics.

Given word : STATISTICS

Anagrams are words formed by jumbling the positions of the letters given in the word.

For such problems we do factorial of number of words and divide by the repeated letters factorials.

Total number of letters = 10

They can be permutated among themselves in 10! ways.

Some letters are repeated in word STATISTICS

Since, there are 3 S's and 3 T's and 2 I's

So, Number of anagrams = [tex]\frac{10!}{3!.3!.2!}[/tex]

= [tex]\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3!}{3! \times 3 \times 2 \times 1 \times 2 \times 1}[/tex]

= [tex]\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4}{3 \times 2 \times 2}[/tex]

= 10 × 9 × 8 × 7 × 2 × 5

= 50,400

50,400 different anagrams can be made from the letters in the word statistics.

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A map has a scale of 1cm:4km the actual distance between the two cities is 52km. What is the distance between the two cities on the map

Answers

Answer:

13cm

Step-by-step explanation:

Given the map scale:

1cm on the map : 4km actual distance

4km actual distance : 1cm on the map

1km actual distance : [tex]\frac{1}{4} =0.25cm[/tex] on the map

Therefore,

52km actual distance = 0.25 * 52 = 13cm

What is the quotient of the rational expression below?
3x+1 x-7
x+8 5x
O A.
O B.
O C.
O D.
3x² + x
x²+x-56
15x² +5x
x² +15x-56
15x² +5x
x²+x-56
15x² +1
x²+x-56

Answers

Answer: C

Step-by-step explanation:

[tex]\frac{3x+1}{x+8} \div \frac{x-7}{5x}\\\\=\frac{3x+1}{x+8} \times \frac{5x}{x-7}\\\\=\frac{5x(3x+1)}{(x+8)(x-7)}\\\\=\frac{15x^2 +5x}{x^2 +x-56}[/tex]

The square below has an area of x2 + 4x + 4 square meters.

What expression represents the length of one side of the square?

Perfect Squares


Write your answer without any spaces. Ex. x+3

Answers

Answer:

The side length of a square is the square root of its area. We know that:

x2 + 4x + 4 = (x + 2)2

Therefore, the side length of the square is x + 2

the side length is x+2

Robert wants to fence a rectangular plot of land of at least $500$ square feet while using the least amount of fencing possible. He wants the width of the plot to be $5$ ft longer than the length. What is the width of the plot

Answers

The area of a rectangle is the amount of space it would cover on a 2-Dimensional plane. The required value of the width is 25 feet.

A rectangle is a plane shape with equal opposite sides. Its area can be determined by;

Area of a rectangle = length x width

Considering the given question, let the length of the plot be represented by l and its width as w. Given that the width of the plot should be longer than its length by 5, then we have;

w = l + 5

But,

Area of the plot = length x width

500 = l x (l + 5)

       = [tex]l^{2}[/tex] + 5l

This implies that,

500 = [tex]l^{2}[/tex] + 5l

[tex]l^{2}[/tex] + 5l - 500 = 0

Applying the quadratic formula, we have;

l = (-b  ± [tex]\sqrt{b^{2} - 4ac}[/tex]) / 2a

a = 1, b = 5, c = -500

= (-5  ±  [tex]\sqrt{5^{2} - (4*1*-500)}[/tex]/ 2

 = (-5  ± 45) / 2

l =   (40) / 2 OR l =  (-50) / 2

l = 20 OR l = - 25.5

So that,

l = 20

Therefore, the length of the plot is 20 feet.

Thus the width of the plot can be determined as;

w = l + 5

   = 20 + 5

w = 25

The width of the plot is 25 feet.

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Suppose we want to choose 5 letters, without replacement, from 16 distinct letters.
(a) If the order of the choices is taken into consideration, how many ways can this be done?
(b) If the order of the choices is not taken into consideration, how many ways can this be done?

Answers

Answer: Your answers are

A. 1, 287 ways

B. 154,440 ways

Hope this helped :D

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Which point is a solution to the system of inequalities graphed here? y ≤ 2x 2 y ≥ -5x 4

Answers

The point that is a solution to the system of inequalities is (5, 0)

How to determine the points on the solution?

The system of inequalities is given as:

y ≤ 2x + 2

y ≥ -5x + 4

Next, we test the given options.


From the list of options, we have

(x, y) = (5, 0)

Substitute (x, y) = (5, 0) in y ≤ 2x + 2 and y ≥ -5x + 4

y ≤ 2x + 2

0 ≤ 2 * 5 + 2

0 ≤ 12 -- this is true

y ≥ -5x + 4

0 ≥ -5 * 5 + 4

0 ≥ -21 -- this is true

Since both results are true, then it means that the point that is a solution to the system of inequalities is (5, 0)

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Complete question

Which point is a solution to the system of inequalities graphed here? y ≤ 2x + 2

y ≥ -5x + 4

A. (1,6)

B. (-6,0)

C. (0,5)

D. (5,0)

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