find the parametric equation for the curve 2 2=36 (use symbolic notation and fractions where needed.)

Answers

Answer 1

The parametric equations [tex]x = 6 cos θ[/tex]and[tex]y = 3 sin θ[/tex] trace out the ellipse [tex]2x^2 + y^2 = 36[/tex].

To find the parametric equation for the curve [tex]2x^2 + y^2 = 36[/tex]., we can use the following steps:

1. Choose a parameter, say t.
2. Express x and y in terms of t using symbolic notation and fractions where needed.
3. Substitute the expressions for x and y into the equation [tex]2x^2 + y^2 = 36[/tex] to verify that the curve is traced out by the parametric equations.

One possible choice for the parameter is t = θ, where θ is the angle measured from the positive x-axis to the point (x, y) on the curve. Using this approach, we can write:
[tex]x = 6 cos θ\\y = 3 sin θ[/tex]

To verify that these equations trace out the curve [tex]2x^2 + y^2 = 36[/tex]., we substitute the expressions for x and y into the equation:
[tex]2(6 cos θ)^2 + (3 sin θ)^2 = 36[/tex]

Simplifying this expression using trigonometric identities, we get:
[tex]72 cos^2 θ + 9 sin^2 θ = 36[/tex]

Dividing both sides by 9 and using the identity [tex]cos^2 θ + sin^2 θ = 1[/tex], we obtain:
[tex]8 cos^2 θ + sin^2 θ = 4[/tex]

Multiplying both sides by 8 and using the identity [tex]cos 2θ = 2 cos^2 θ - 1[/tex]and[tex]sin 2θ = 2 sin θ cos θ[/tex], we get:
[tex]cos 2θ = -3/4\\sin 2θ = ±\sqrt{7}/4[/tex]

These equations represent a curve that has two branches, one in the first and fourth quadrants and the other in the second and third quadrants. Therefore, the parametric equations[tex]x = 6 cos θ[/tex] and [tex]y = 3 sin θ[/tex] trace out the ellipse[tex]2x^2 + y^2 = 36[/tex].


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Related Questions

4n / 2n 3n determine convergence or divergence of the series. if the series converges, find its sum

Answers

The given series 4^n / 2^n 3^n is convergent.

To see why, we can use the ratio test, which states that if the limit of the ratio of consecutive terms is less than 1, then the series converges. Applying the ratio test to the given series, we get:

lim n→∞ |(4^n+1 / 2^n+1 3^n+1) / (4^n / 2^n 3^n)|

= lim n→∞ |4 / 3(1 + 1/2n+1)|

= 4/3

Since the limit is less than 1, the series converges. To find its sum, we can use the formula for the sum of a convergent geometric series:

S = a / (1 - r)

where a is the first term and r is the common ratio. In this case, a = 4/6 = 2/3 and r = 2/3, so we get:

S = (2/3) / (1 - 2/3) = 2

Therefore, the sum of the series is 2.

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find equations for the tangent lines and the normal lines to the hyperbola for the given value of x. (the normal line at a point is perpendicular to the tangent line at the point.)x24− y2 = 1, x = 4

Answers

To find the equations of the tangent and normal lines to the hyperbola x^2/4 − y^2/1 = 1 at the point where x = 4, we need to first find the y-coordinate of the point of tangency. We can do this by substituting x = 4 into the equation of the hyperbola and solving for y:

x^2/4 - y^2/1 = 1

(4)^2/4 - y^2/1 = 1

16/4 - y^2/1 = 1

4 - y^2 = 1

y^2 = 3

y = ±√3

So, the point of tangency is (4, √3).

Now, to find the equation of the tangent line at this point, we need to take the derivative of the equation of the hyperbola implicitly with respect to x:

x^2/4 - y^2/1 = 1

Differentiating both sides with respect to x:

x/2 - 2y(dy/dx) = 0

dy/dx = x/(4y)

At the point (4, √3), we have:

dy/dx = 4/(4√3) = √3/3

So the slope of the tangent line at this point is √3/3. Using the point-slope form of the equation of a line, we can write the equation of the tangent line as:

y - √3 = (√3/3)(x - 4)

Simplifying, we get:

y = (√3/3)x - (√3/3)∙4 + √3

y = (√3/3)x - (√3/3) + √3

y = (√3/3)x + 2√3/3

To find the equation of the normal line, we first need to find its slope, which is the negative reciprocal of the slope of the tangent line. So:

m(normal) = -1/m(tangent) = -1/(√3/3) = -√3

Using the point-slope form again, the equation of the normal line is:

y - √3 = (-√3)(x - 4)

Simplifying, we get:

y = -√3x + 4√3 + √3

y = -√3x + 5√3

So the equations of the tangent and normal lines to the hyperbola x^2/4 − y^2/1 = 1 at the point where x = 4 are:

Tangent line: y = (√3/3)x + 2√3/3

Normal line: y = -√3x + 5√3

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Find the x- and y- intercept in 3x+2y=24

Answers

The x and y intercept of the equation is (8,12)

What is linear equation?

A linear equation is an algebraic equation of the form y=mx+b. It involves only a constant and a first-order term, where m is the slope and b is the y-intercept.

For 3x +2y = 24

we need to put it to the standard form

2y = 24 - 3x

divide both sides by 2

y = 12 - 3/2x

Here b is 12 and m is -3/2

therefore the y intercept is 12

when y = 0

0 = 12 -3/2 x

3/2 x = 12

3x = 24

divide both sides by 3

x = 24/3 = 8

therefore the x intercept is 8

The x and y intercept of the equation is ( 8,12)

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if f(4) = 6 and f '(x) ≥ 3 for 4 ≤ x ≤ 7, how small can f(7) possibly be?

Answers

Using the mean value theorem, we can find an upper bound for f(7) given the information provided. The mean value theorem states that for a differentiable function f(x) on the interval [a,b], there exists at least one point c in the interval such that:

f'(c) = (f(b) - f(a))/(b - a)

If we apply this theorem to the interval [4,7], we get:

f'(c) = (f(7) - f(4))/(7 - 4)

Since f '(x) ≥ 3 for 4 ≤ x ≤ 7, we know that f'(c) ≥ 3. We can use this inequality to find an upper bound for f(7):

3 ≤ (f(7) - 6)/3

9 ≤ f(7) - 6

f(7) ≥ 15

Therefore, the smallest possible value for f(7) is 15. This means that f(x) must be increasing at a rate of at least 3 between x=4 and x=7, and the smallest possible value of f(7) occurs when f(x) is increasing at a constant rate of 3.

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help im on a test and i need to get it right

Answers

The owner of the bookstore sells the used books for $6 each. J.

The price of a used book in the bookstore we need to calculate how much the owner is selling the books for.

The owner of the bookstore buys the used books from customers for $1.50 each.

The owner resells the used books for we need to multiply the cost price by 400%:

$1.50 x 400% = $1.50 x 4

= $6

The markup percentage for the used books is very high.

The owner is reselling the used books for four times the amount he paid for them.

This is a common practice in the used book industry as it allows the owner to make a profit on the books they sell.

It is important for customers to be aware of the markup and shop around for the best prices.

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could you help me please

Answers

Answer:

Angle PRQ = 28 degrees.

Step-by-step explanation:

Angles P and Q are the same! That's bc this is an isosceles triangle.

The total of all 3 angles = 180. So to find R, subtract the other 2 angles from 180.

So 180-76-76 = 28. That's angle R

What is absolute deviation from the mean? ​

Answers

Absolute deviation from the mean is the spread or dispersion of a group of values around their arithmetic mean

What is absolute deviation?

The absolute deviation from the mean is the spread or dispersion of a group of values around their arithmetic mean that is measured statistically.

It is determined by first calculating the average of the absolute deviations between each individual value in the dataset and the mean.

The absolute deviation offers a measurement of how far on average each number deviates from the mean irrespective of its direction.

It is frequently used in descriptive statistics and data analysis and is helpful for comprehending the variability or dispersion of data points.

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50 Points Math Image
Determine the degree of overlap (high, moderate, low, or none).

Answers

Answer:

its none

Step-by-step explanation:

can i get brainliest please

Let f(x,y,z) be a function whose first partial derivatives are continuous for all (x,y,z). Let S be the level surface given by f(x,y,z)=10, and let (a,b,c) be a point on S. For each statement below, circle only one answer (true or false). No work is required. (a) ∇f(a,b,c) must be parallel to the tangent plane to S at (a,b,c). (True) (False) (b) ∇f(a,b,c) must be perpendicular to the tangent plane to S at (a,b,c). (True) (False) (c) If ⟨m,n,q⟩ is a nonzero vector on the tangent plane to S at (a,b,c), then ⟨m,n,q⟩×∇f(a,b,c) must be ⟨0,0,0⟩. (True) (False) (d) If ⟨m,n,q⟩ is a nonzero vector on the tangent plane to S at (a,b,c), then ⟨m,n,q⟩.∇f(a,b,c) must be 0 . (True) (False) (e) ∣∇f(a,b,c)∣=∣−∇f(a,b,c)∣ (True) (False) (f) Let u be a unit vector in R3. Then, −∣∇f(a,b,c)∣≤Duf(a,b,c)≤∣∇f(a,b,c)∣ (True) (False)

Answers

(a) False
(b) True
(c) True
(d) True
(e) True
(f) True
(a) False: ∇f(a,b,c) is not parallel to the tangent plane to S at (a,b,c).

(b) True: ∇f(a,b,c) is perpendicular to the tangent plane to S at (a,b,c).

(c) True: If ⟨m,n,q⟩ is a nonzero vector on the tangent plane to S at (a,b,c), then ⟨m,n,q⟩×∇f(a,b,c) must be ⟨0,0,0⟩.

(d) True: If ⟨m,n,q⟩ is a nonzero derivative vector on the tangent plane to S at (a,b,c), then ⟨m,n,q⟩.∇f(a,b,c) must be 0.

(e) True: ∣∇f(a,b,c)∣=∣−∇f(a,b,c)∣

(f) True: Let u be a unit vector in R3. Then, −∣∇f(a,b,c)∣≤Duf(a,b,c)≤∣∇f(a,b,c)∣

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Mike saves $2000 at a year simple interest rate of 2%. He earns $280 in interest for how many years does he save this money

Answers

Mike saved his money for 7 years to earn $280 in interest at a simple interest rate of 2%.

The simple interest formula:

I = P × r × t

Where:

I is the interest earned

P is the principal (the initial amount of money saved)

r is the interest rate

t is the time (in years)

We know that Mike saves $2000 at a simple interest rate of 2% and he earns $280 in interest.

So we can plug in these values and solve for "t":

280 = 2000 × 0.02 × t

Dividing both sides by (2000 × 0.02):

280 / (2000 × 0.02) = t

t = 7

I = P r t is the formula for calculating interest.

P stands for principle, which is the original sum of money saved and r stands for interest rate.

The date is (in years).

We are aware that Mike gets $280 in interest on his savings of $2000 at a basic interest rate of 2%.

Thus, we may enter these numbers and find the value of "t":

280 = 2000 × 0.02 × t

by (2000 0.02), divide both sides:

280 / (2000 × 0.02)= 7

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At LaGuardia Airport for a certain nightly flight, the probability that it will rain is 0.07 and the probability that the flight will be delayed is 0.12. The probability that it will not rain and the flight will leave on time is 0.87. What is the probability that it is raining if the flight has been delayed? Round your answer to the nearest thousandth.

Answers

Probability of not raining and the flight leaving on time is equals to 0.320 .

Now, By De Morgan's law;

P( A'∩ B')  = P (A∪B)'

P (A∪B)' = 1 -  P (A∪B)

P(A∪B) = P(A) + P(B) - P(A∩B)

According to the question,

Let Probability of rain = P(A)

                                   = 0.07

Probability of flight delay =P(B) = 0.12

Therefore ,

Probability of rain and flight delay = P (A∩B)

                                                        = 0.87

Probability of not raining and flight on time = P( A'∩ B')

Substitute the values in the formula

P( A'∩ B') = 1 - [ 0.07 + 0.12 -0.87]

              = 1- 0.68

              = 0.32

              = 0.320 ( nearest thousandth)    

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A quadrilateral is shown.


If the value of y is 2.7 feet, what is the area of the quadrilateral?

Answers

The area of the trapezoid is 25. 8 ft²

How to determine the area

We can see from information given that the shape is a trapezoid.

Hence, the formula for calculating the area of a trapezoid is expressed as;

A = a + b/2 h

Such that the parameters of the given equation are;

A is the area of the trapezoida is the length of the parallel sideb is the length of the parallel sideh is the height of the trapezoid

Substitute the value, we have that;

Area = 2.7 + 5.9)/2 × 6

add the values, we have;

Area = 8. 6/2 ×6

Divide the values, we have;

Area = 25. 8 ft²

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Amstat News (December 2004) lists median salaries for associate professors of statistics at research institutions and at liberal arts and other institutions in the United States. Assume a sample of 200 associate professors from research institutions having an average salary of $70,750 per year with a standard deviation of $6000. Assume also a sample of 200 associate professors from other types of institutions having an average salary of $65,200 with a standard deviation of $5000. Required:

Test the hypothesis that the mean salary for associate professors in research institutions is $2000 higher than for those in other institutions

Answers

To test the hypothesis that the mean salary for associate professors in research institutions is $2000 higher than for those in other institutions, we can perform a two-sample t-test.

The null hypothesis is that the difference in means is not significantly different from $2000, while the alternative hypothesis is that the difference is greater than $2000.

Using the given information, we can calculate the t-statistic as (70750 - 65200 - 2000) / sqrt((6000^2/200) + (5000^2/200)) = 5.39. With 398 degrees of freedom (n1 + n2 - 2), the p-value for this one-sided test is less than 0.0001.

Since this p-value is much smaller than any reasonable level of significance, we reject the null hypothesis and conclude that there is strong evidence that the mean salary for associate professors in research institutions is significantly higher than for those in other institutions by $2000.

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To test the hypothesis that the mean salary for associate professors in research institutions is $2000 higher than for those in other institutions, we can perform a two-sample t-test.

The null hypothesis is that the difference in means is not significantly different from $2000, while the alternative hypothesis is that the difference is greater than $2000.

Using the given information, we can calculate the t-statistic as (70750 - 65200 - 2000) / sqrt((6000^2/200) + (5000^2/200)) = 5.39. With 398 degrees of freedom (n1 + n2 - 2), the p-value for this one-sided test is less than 0.0001.

Since this p-value is much smaller than any reasonable level of significance, we reject the null hypothesis and conclude that there is strong evidence that the mean salary for associate professors in research institutions is significantly higher than for those in other institutions by $2000.

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How long will it take money to quadruple if it is invested at 6% compounded daily? 6. 9% compounded continuously?

It will take about years at 6% compounded daily.

Answers

If money is invested at 6% compounded daily, the interest rate per day is 6%/365 = 0.01644%.

To find the number of days it takes to quadruple the money, we can use the formula A = P(1 + r/n)^(nt), where A is the final amount, P is the initial amount, r is the annual interest rate, n is the number of times compounded per year, and t is the time in years. In this case, we want A/P = 4, so we have:

4 = (1 + 0.0001644/1)^(1t)

ln(4) = tln(1 + 0.0001644/1)

t = ln(4)/ln(1 + 0.0001644/1) ≈ 123.73 days

Therefore, it will take about 123.73 days or approximately 4 months to quadruple the money at 6% compounded daily.

If money is invested at 6.9% compounded continuously, we can use the formula A = Pe^(rt) to find the time it takes to quadruple the money. Again, we want A/P = 4, so we have:

4 = e^(0.069t)

ln(4) = 0.069t

t = ln(4)/0.069 ≈ 10.04 years

Therefore, it will take about 10.04 years to quadruple the money at 6.9% compounded continuously.

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NEED HELP ASAP
Which of the following tables represents a linear relationship that is also proportional?


x −4 −2 0
y 0 2 4

x 3 1 −1
y −2 0 2

x 0 1 2
y −1 0 1

x 6 3 0
y −2 −1 0

Answers

Answer:

x −4 −2 0

y 0 2 4

Step-by-step explanation:

:)

for which positive integers n is dn, the number of de rangements of n objects, even?

Answers

A derangement of n objects is a permutation of the objects such that no object is in its original position. The number of derangements of n objects, dn, is given by the formula dn = n!(1/0! - 1/1! + 1/2! - 1/3! + ... + (-1)^n/n!).

For n = 1 or 2, there is only one possible derangement, which is not even. For n = 3, there are 2 possible derangements, which are both even. For n = 4, there are 9 possible derangements, which are all odd. For n = 5, there are 44 possible derangements, which are all even.

In general, integer for n > 2, dn is even if and only if n is odd.
Hello! For positive integers n, the number of derangements (dn) is even when n is odd. A derangement is a permutation where no object is in its original position. The formula for finding the number of derangements is given by dn = n! * (1 - 1/1! + 1/2! - 1/3! + ... + (-1)^n/n!). When n is odd, the last term in the series has a positive sign, causing the result to be even.

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for the following factored polynomial, find all of the zeros and their multiplicities. f(x)=(x−5)5(x 1)7

Answers

the question is that the zeros of the polynomial f(x)=(x−5)5(x+1)7 are x=5 and x=-1, and their multiplicities are 5 and 7, respectively.

the zeros and their multiplicities is as follows:

To find the zeros of the polynomial, we set each factor equal to zero and solve for x.

For the factor (x−5)5, we get x=5 as the only zero.

For the factor (x+1)7, we get x=-1 as the only zero.

To determine the multiplicities of the zeros, we count the number of times each zero appears as a factor.

Since (x−5)5 is a factor of the polynomial, the zero x=5 has a multiplicity of 5.

Similarly, since (x+1)7 is a factor of the polynomial, the zero x=-1 has a multiplicity of 7.

the zeros of the polynomial f(x)=(x−5)5(x+1)7 are x=5 and x=-1, and their multiplicities are 5 and 7, respectively.

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What is the area on the object above

A.102
B.166
C.204
D.126

Answers

Answer

D. 126 inches squared

Step-by-step explanation:

8 x 17 = 136

2 x 5 = 10

136-10= 126

D. 126, the reason is because of multiplying all the sides with each other which equal 126.

Find value of x round to the nearest tenth.

Answers

Answer:

8√3

Step-by-step explanation:

method 1

180°-(30°+90°)= 60°

8=sin 30° × chord

sin 30°=1/2

chord=16

x^2 + 8^2 = 16^2

x=√256 - 64

x= √192 = 8√3

method 2:

use arcsin & arccos

method 3:

...

The heights, in feet, of the trees for sale at two nurseries are shown below.

Yard Works: 7, 9, 7, 12, 5
The Grow Station: 9, 11, 6, 12, 7

Which statements are true regarding the measures of center and variability of these data sets? Select three choices.
The mean of the tree heights at Yard Works is less than the mean of the tree heights at The Grow Station.
The median of the tree heights at Yard Works is greater than the median of the tree heights at The Grow Station.
The range of the tree heights at Yard Works is greater than the range of the tree heights at The Grow Station.
The mean absolute deviation of the tree heights at Yard Works is greater than the mean absolute deviation of the tree heights at The Grow Station.
The mean absolute deviation of the tree heights at Yard Works is equal to the mean absolute deviation of the tree heights at The Grow Station.

Answers

The true statements regarding the measures of center and variability of these data sets are: statements A, C and E.

How to Find the Measures of center and Variability of a Data Set?

To analyze the statements regarding the measures of center and variability, let's calculate the required measures for each data set.

For Yard Works:

Tree heights: 7, 9, 7, 12, 5

Mean: (7 + 9 + 7 + 12 + 5) / 5 = 40 / 5 = 8

Median: 7, 7, 9, 12, 5 → Median = 7

Range: 12 - 5 = 7

Mean absolute deviation (MAD): Calculate the absolute difference of each value from the mean, then find the average of those differences.

|7 - 8| + |9 - 8| + |7 - 8| + |12 - 8| + |5 - 8| = 1 + 1 + 1 + 4 + 3 = 10 / 5 = 2

For The Grow Station:

Tree heights: 9, 11, 6, 12, 7

Mean: (9 + 11 + 6 + 12 + 7) / 5 = 45 / 5 = 9

Median: 6, 7, 9, 11, 12 → Median = 9

Range: 12 - 6 = 6

Mean absolute deviation (MAD):

|9 - 9| + |11 - 9| + |6 - 9| + |12 - 9| + |7 - 9| = 0 + 2 + 3 + 3 + 2 = 10 / 5 = 2

Analyzing the statements:

A. The mean of the tree heights at Yard Works is less than the mean of the tree heights at The Grow Station.

True. Mean Yard Works < Mean The Grow Station (8 < 9)

B. The median of the tree heights at Yard Works is greater than the median of the tree heights at The Grow Station.

False. Median Yard Works = Median The Grow Station (7 = 9)

C. The range of the tree heights at Yard Works is greater than the range of the tree heights at The Grow Station.

True. Range Yard Works > Range The Grow Station (7 > 6)

D. The mean absolute deviation of the tree heights at Yard Works is greater than the mean absolute deviation of the tree heights at The Grow Station.

False. MAD Yard Works = MAD The Grow Station (2 = 2)

E. The mean absolute deviation of the tree heights at Yard Works is equal to the mean absolute deviation of the tree heights at The Grow Station.

True. MAD Yard Works = MAD The Grow Station (2 = 2)

In summary, the true statements are: A, C, and E.

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Each chair that is added to this stack makes it 8cm taller. One chair is 55cm tall. Use your knowledge of patterns to find how high a stack of chairs will be that has 8 chairs in it. 1.5.1 Write down the constant difference 1.5.2 Using the general rule, determine how many chairs would there be if the stack was 127cm high?​

Answers

Answer:

1.5.1 : constant difference is 8

1.5.2: When there are 10 chairs stacked, it's 127 cm tall.

Step-by-step explanation:

There is a linear relationship between the height of the stack and the number of chairs.

1 chair = 55 cm + 0 extra cm = 55cm

2 chairs = 55cm + 8cm = 63 cm

3 chairs = 55cm + 8(2)cm = 71 cm

4 chairs = 55cm + 8(3)cm = 79 cm

1.5.1 the constant difference between all the underlined numbers above is 8.

1.5.2 You could just keep calculating above until you get 127 cm. (Your teacher might not like that, but it's an option!)

You can find the equation & either solve for the number of chairs OR graph it.

So if we let C = the number of stacked chairs, our equation for H (height) would be:

H = 55 + 8(C-1)

If we substitute H = 127, solve for C.

127 = 55+ 8(c-1)

127 = 55+ 8c-8

127 = 47 + 8c

127 -47 = 8c

80 = 8c

10=c

When there are 10 chairs stacked, it's 127 cm tall.

Check that the answer works:

55 cm (1st chair) + 8*9 (8cm for each additional chair) = 55+ 72 = 127 cm


Marco has a bag of red, blue, and green tiles. Which set of events would be considered independent? A tile is drawn and replaced, and then a second tile is drawn. A tile is drawn and removed, and then a second tile is drawn. A red or blue or green tile is drawn. Two tiles are drawn at the same time.

Answers

A tile is drawn and replaced, and then a second tile is drawn. Therefore, option A and B are correct answers.

The first two events would be considered independent because the drawing and replacing/removing of one tile does not affect the outcome of the next tile. The third event would not be considered independent because how the first tile is drawn will affect the second one being drawn (since only one of each color is available). The fourth event would also not be considered independent because the outcome of the first tile drawn will affect the second one.

Therefore, option A and B are correct answers.

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Angle ABC and angle CBD are complementary. What is the value of x?

Answers

Answer:

x = 26

Step-by-step explanation:

complementary angles sum to 90° , that is

∠ ABC + ∠ CBD = 90

2x + 38 = 90 ( subtract 38 from both sides )

2x = 52 ( divide both sides by 2 )

x = 26

Work out the bearing of D from A.
D
155
zt
15%
B
A
166°
Not drawn accurate

Answers

The bearing form D from A, according to the figure is

205 degrees

How to find the bearing of D from A

Bearings are measured form the North and in the clockwise direction

Examining the figure and applying the clockwise direction to measure the angles, we have the bearing as

bearing form D from A = angle N to B + angle B to C + angle C to D

angle C to D is not given and solved using sum of angles in a point

angle C to D = 360 - 155 - 15 - 166

angle C to D = 24 degrees

plugging in the values

bearing form D from A = 15 + 166 + 24

bearing form D from A = 205 degrees

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Bookwork code: P67
Line AB below is 12 cm long.
Line AC is 18 cm long.
Line BE is 10 cm long.
Calculate the length of line CD.
Give your answer as an integer or as a fraction in its simplest form.
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Answers

The length of line CD is 15 cm.

To calculate the length of line CD, we can use the property of similar triangles.

In triangle ABC, we can see that triangle ABE is similar to triangle ACD.

Using the property of similar triangles, we can set up the following proportion:

AB/AC = BE/CD

Substituting the given values:

12/18 = 10/CD

To solve for CD, we can cross-multiply and solve the resulting equation:

12 × CD = 18 × 10

CD = (18 × 10) / 12

CD = 180 / 12

CD = 15

Therefore, the length of line CD is 15 cm.

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Find the area of the surface obtained by rotating the curve about the x-axis:y=[(x^3)/6]+[1/(2x)] from 1/2 to 1

Answers

The area of the surface obtained by rotating the curve y = (x³/6) + (1/2x) from 1/2 to 1 about the x-axis is given by the above expression is 2π (1/6 x √(1+ 9x² - 3x⁴/4)).

Calculate the arc length of the curve

We first need to calculate the arc length of the curve, which can be done using the formula:

L = ∫aᵇ √(1+ (dy/dx)²) dx

where,

dy/dx = (3x² - 1/2x²)/6

Therefore, the arc length of the curve is given by:

L = ∫1/2¹√(1+ (3x² - 1/2x² )/6)dx

Calculate the area of the surface

Once we have the arc length of the curve, we can calculate the area of the surface obtained by rotating the curve about the x-axis. This can be done using the formula:

A = 2π × L

Substituting the arc length of the curve in the formula, we get:

A = 2π × ∫1/2¹√(1+ (3x² - 1/2x²)/6)dx

Evaluate the integral

Finally, we need to evaluate the integral in order to calculate the area of the surface. We can do this using integration by parts, which gives us:

A = 2π × ∫1/2¹√(1+ (3x² - 1/2x²)/6)dx

= 2π (1/6 x √(1+ 9x² - 3x⁴/4) - (1/6) ∫1/2¹ (9x² - 3x⁴/4)/√(1+ 9x² - 3x⁴4) dx)

Therefore, the area of  the surface is 2π (1/6 x √(1+ 9x² - 3x⁴/4)).

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Find the volume of the square pyramid shown. Round to the nearest tenth as necessary.

a 70 cm
b. 229.7 cm
c. 1575 cm
d. 1050 cm³

Answers

The volume of the square pyramid that has sides of length 15 cm and height of 14 cm is: D. 1050 cm³

How to Find the Volume of a Square Pyramid?

To find the volume of a square pyramid, you can use the formula: Volume = (1/3) * Base Area * Height.

Since the base of the square pyramid has sides of length 15 cm, the base area can be calculated as:

Base area = 15 cm * 15 cm

= 225 cm².

Plugging the values into the formula, the volume of the pyramid:

= (1/3) * 225 * 14 cm

= 1050 cm³.

Therefore, the volume of the square pyramid is 1050 cm³.

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WILL GIVE BRAINLIEST AND 100 POINTS PLS HELP A small tree that is 6 feet tall casts a 4-foot shadow, while a building that is 27 feet tall casts a shadow in the same direction. Determine the length of the building's shadow.


12 feet

14 feet

15 feet

18 feet

Answers

We can use proportions to solve this problem.

Since the ratio of the height of the tree to its shadow is 6:4 or 3:2, we can write:

Height of the tree / Length of its shadow = 3 / 2

Using cross-multiplication, we can find the length of the shadow of the tree:

Length of the shadow of the tree = (2 / 3) * Height of the tree
= (2 / 3) * 6 feet
= 4 feet

Now, we can use the length of the shadow of the tree and the ratio of the height of the building to its shadow to find the length of the shadow of the building:

Height of the building / Length of its shadow = 27 / x (where x is the length of the shadow of the building)

We know that the ratio of the height of the tree to its shadow is the same as the ratio of the height of the building to its shadow, so we can write:

Height of the building / Length of its shadow = Height of the tree / Length of its shadow

Substituting the values we know, we get:

27 / x = 3 / 2

Cross-multiplying, we get:

2 * 27 = 3 * x

Simplifying, we get:

x = 18 feet

Therefore, the length of the building's shadow is 18 feet.

So the answer is (D) 18 feet.

Answer:

should be 18 ft

Step-by-step explanation:

6÷4= 1.5

27÷1.5= 18

At the beginning of an experiment, a scientist has 132 grams of radioactive goo. After 75 minutes, her sample has decayed to 2. 0625 grams. What is the half-life of the goo in minutes? find a formula for g(t), the amount of goo remaining at time t. G(t)

Answers

The half-life of the goo is approximately 18.75 minutes. The formula for g(t), the amount of goo remaining at time t, is g(t) = 132 * (1/2)^(t/18.75).

To find the half-life of the goo, we can use the formula for exponential decay: A(t) = A0 * (1/2)^(t/h), where A(t) is the amount of radioactive substance at time t, A0 is the initial amount, h is the half-life, and t is time. We are given A0 = 132 grams, A(75) = 2.0625 grams, and we need to solve for h. Plugging in these values, we get:

2.0625 = 132 * (1/2)^(75/h)

Solving for h, we get h ≈ 18.75 minutes.

The formula for g(t) is g(t) = A0 * (1/2)^(t/h). Plugging in A0 = 132 and h = 18.75, we get g(t) = 132 * (1/2)^(t/18.75). This formula gives us the amount of goo remaining at time t, where t is measured in minutes.

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find the exact length of the curve y = x^4/16 1/2x^2

Answers

The exact length of  curve y = (x^4/16) + (1/2)x^2 is obtained by integrating the arc length formula.

How we find the exact length of the curve defined by the equation y = (x[tex]^4[/tex]/16) + (1/2)x[tex]^2[/tex].

To find the exact length of the curve defined by the equation y = (x[tex]^4[/tex]/16) + (1/2)x[tex]^2[/tex], we can use the arc length formula. This formula calculates the length of a curve over a given interval by integrating the square root of the sum of the squares of the derivatives of x and y with respect to a parameter.

In this case, we need to find the derivative of y with respect to x, which is given by (4x[tex]^3[/tex]/16) + x.

Using this derivative, we substitute it into the arc length formula, which becomes an integral of √(1 + ((4x[tex]^3/16[/tex]) + x)[tex]^2[/tex]) dx over the desired interval.

By evaluating this integral, we can obtain the exact length of the curve. The result will be a numerical value that represents the length of the curve in the given interval.

It is important to note that the specific interval over which we calculate the length will affect the final result.

The arc length formula allows us to find the precise length of the curve, taking into account its shape and path.

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