Find the pH of the equivalence points when 28.9 mL of 0.0850 M H2SO3 is titrated with0.0392 M NaOH.pH1st =pH2nd =

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Answer 1

pH 1st = [tex][H+] = sqrt(Ka*[HA]) = sqrt(1.5 * 10^{-2} * 0.000565) = 0.00576 M[/tex]. The pH at the equivalence point of the second stage will be higher than that of the first stage due to the excess of NaOH.

The titration of a weak acid with a strong base such as H2SO3 with NaOH involves a neutralization reaction, in which the base reacts with the acidic hydrogen ions of the acid to form water and a salt. In the first stage of the titration, the H2SO3 reacts with the NaOH in a 1:2 stoichiometric ratio, which means that twice as much NaOH is needed to completely neutralize the H2SO3.The balanced chemical equation for the titration reaction is:[tex]H2SO3(aq) + 2NaOH(aq) → Na2SO3(aq) + 2H2O(l)[/tex]To calculate the pH at the equivalence point of the first stage, we can use the equation for the concentration of H+ in a weak acid solution:[H+] = sqrt(Ka*[HA])where Ka is the acid dissociation constant for H2SO3, [HA] is the initial concentration of the acid, and [H+] is the hydrogen ion concentration at the equivalence point.The acid dissociation constant of H2SO3 is [tex]Ka = 1.5 * 10^{-2}[/tex], and the initial concentration of the acid is [HA] = 0.0850 M.At the equivalence point of the first stage, all the H2SO3 will be neutralized by half the amount of NaOH added. The amount of NaOH added can be calculated from the volume and molarity of NaOH:moles of NaOH = volume of NaOH x molarity of NaOH = 0.0392 M x 28.9 mL / 1000 mL = 0.00113 molSince two moles of NaOH are required to neutralize one mole of H2SO3, the amount of H2SO3 at the equivalence point will be:moles of H2SO3 = 0.00113 mol / 2 = 0.000565 molUsing the equation above, we can calculate the hydrogen ion concentration at the equivalence point of the first stage:[tex][H+] = sqrt(Ka*[HA]) = sqrt(1.5 * 10^{-2} * 0.000565) = 0.00576 M[/tex]The pH at the equivalence point can be calculated using the equation:pH = -log[H+] = -log(0.00576) ≈ 2.24For the second stage of the titration, the remaining H2SO3 will react with the remaining NaOH in a 1:1 stoichiometric ratio to form NaHSO3. At the equivalence point of the second stage, the solution will be basic due to the excess of NaOH. The pH at the equivalence point of the second stage can be calculated using a similar approach, but with different stoichiometric ratios and initial concentrations. Since the volume of NaOH added and the concentration of H2SO3 are known, the amount of NaOH remaining after the first stage can be calculated and used to determine the concentration of NaOH at the equivalence point of the second stage. The pH at the equivalence point of the second stage will be higher than that of the first stage due to the excess of NaOH.

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Related Questions

List a few (up to three) that still seem mysterlous to you at this point:

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Scientists are still working to completely comprehend a number of events. Here are a few instances:

A type of stuff known as "dark matter" is invisible to telescopes because it does not emit, absorb, or reflect light. Its gravitational effects on observable matter have implied its existence, but its nature and makeup are still unknown.

Scientists are still working to fully understand the phenomenon of consciousness, or the individual's subjective experience of awareness. There is no commonly accepted theory that explains how subjective experience results from physiological processes in the brain, despite advances in identifying the neurological correlates of consciousness.

Despite being a widely accepted scientific theory, quantum mechanics' consequences and interpretations are still controversial.

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Which factor below does not contribute to the value of the standard reduction potential for the process : Na*(aq) + e- → Na(s) a) Enthalpy change for electron attachment to Na(g) b) Enthalpy change for atomization of Na(s) c) First ionization energy of Na(g) d) Enthalpy change for hydration of Na(g)

Answers

The factor that does not contribute to the value of the standard reduction potential for the process Na×(aq) + e⁻ ⇒ Na(s) is b) Enthalpy change for atomization of Na(s).

The standard reduction potential only takes into account the enthalpy change for electron attachment to Na(g), the first ionization energy of Na(g), and the enthalpy change for hydration

The tendency of a chemical species to become reduced is referred to as standard reduction potential. Volts are measured under typical circumstances.

If a species' reduction potential is negative, it will be simple for it to lose electrons and become oxidised.

Similar to this, if a species has a positive reduction potential, it will be reduced because it will be simple to gain electrons.Compared to zinc ions, the copper ions will be decreased more quickly.

The accurate assertion is therefore that the half-reaction will be reduced more frequently the larger the standard reduction potential.

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Is the formation of ozone (o3(g)) from oxygen (o2(g)) spontaneous at room temperature under standard state conditions?

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The formation of ozone from oxygen is not spontaneous at room temperature under standard state conditions. This is because the standard free energy change for the formation of ozone from oxygen is positive, indicating that it is a non-spontaneous process.

The standard free energy change, ΔG°, for the formation of ozone from oxygen can be calculated using the following equation:

ΔG° = ΔG°f (O3) - ΔG°f (O2)

where ΔG°f (O3) is the standard free energy of formation of ozone and ΔG°f (O2) is the standard free energy of formation of oxygen.

The standard free energy of formation of ozone is positive (+142.7 kJ/mol), while the standard free energy of formation of oxygen is zero (by definition). Therefore, the standard free energy change for the formation of ozone from oxygen is also positive (+142.7 kJ/mol).

Since the standard free energy change is positive, the reaction is non-spontaneous under standard state conditions. However, it is possible for ozone to form from oxygen under certain conditions, such as in the presence of UV radiation or an electrical discharge.

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A balloon has a volume of 4.3 liters at 26.4 C. The balloon is then heated to a temperature of 109.4 C. What is the volume of the balloon after heating?

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The volume of the balloon after heating is 5.47 liters.

To determine the volume of the balloon after heating, we can use Charles's Law, which states that the volume of the gas is directly proportional to its temperature when the pressure and the amount of gas are held constant.

Mathematically, Charles's Law can be expressed as;

V₁ / T₁ = V₂ / T₂

where; V₁ = Initial volume of the gas (before heating)

T₁ = Initial temperature of the gas (before heating)

V₂ = Final volume of the gas (after heating)

T₂ = Final temperature of the gas (after heating)

Given; V₁ = 4.3 liters

T₁ = 26.4°C (which needs to be converted to Kelvin by adding 273.15)

T₂ = 109.4°C (which needs to be converted to Kelvin by adding 273.15)

Converting temperatures to Kelvin;

T₁ = 26.4 + 273.15 = 299.55 K

T₂ = 109.4 + 273.15 = 382.55 K

Plugging the values into Charles's Law equation;

V₁ / T₁ = V₂ / T₂

4.3 / 299.55 = V₂ / 382.55

Solving for V₂ (final volume of the balloon after heating):

V₂ = (4.3 / 299.55) × 382.55

V₂ ≈ 5.47 liters

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What do we call a substance composed of atoms of more than one element that are held together by chemical bonds?
Compound
Crystal
Salt
Ion

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A substance composed of atoms of more than one element that are held together by chemical bonds is called a compound. Therefore the correct option is option A.

A compound is a pure material that is created by chemically combining two or more distinct components in a specific order. Chemical bonds, which can be ionic or covalent, hold the atoms of a substance together.

The characteristics of compounds are distinct from the characteristics of the constituent parts.

For instance, sodium is a soft metal and chlorine is a greenish-yellow gas; nevertheless, when these two elements combine to produce sodium chloride (table salt), they create a white crystalline solid that is far more stable than the constituent parts of each element alone. Therefore the correct option is option A.

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consider these molecules. which is polar? consider these molecules. which is polar? bf3 co2 bh3 bef2 ci4 ch3cl

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The polar molecules are BeF2 and CH3Cl, while the nonpolar molecules are BF3, CO2, BH3, and CI4.

In order to determine whether a molecule is polar or nonpolar, we need to consider the electronegativity difference between the atoms in the molecule and the molecule's geometry.BF3 (boron trifluoride) has a trigonal planar geometry with three fluorine atoms arranged symmetrically around a central boron atom. Since the electronegativity of boron is lower than that of fluorine, the bond dipoles cancel each other out, resulting in a nonpolar molecule.CO2 (carbon dioxide) has a linear geometry with two oxygen atoms arranged symmetrically around a central carbon atom. Since the electronegativity of oxygen is higher than that of carbon, the bond dipoles point towards the oxygen atoms, but they cancel each other out, resulting in a nonpolar molecule.BH3 (boron trihydride) has a trigonal planar geometry with three hydrogen atoms arranged around a central boron atom. Since boron has a lower electronegativity than hydrogen, the bond dipoles point towards boron, but since the molecule is symmetric, they cancel each other out, resulting in a nonpolar molecule.BeF2 (beryllium difluoride) has a linear geometry with two fluorine atoms arranged symmetrically around a central beryllium atom. Since beryllium has a low electronegativity compared to fluorine, the bond dipoles point towards fluorine, and the molecule is polar.CI4 (carbon tetrachloride) has a tetrahedral geometry with four chlorine atoms arranged symmetrically around a central carbon atom. Since the bond dipoles are pointing in opposite directions and cancel each other out, the molecule is nonpolar.CH3Cl (chloromethane) has a tetrahedral geometry with a chlorine atom and three hydrogen atoms arranged around a central carbon atom. Since the bond dipoles are pointing towards the chlorine atom, the molecule is polar.In summary, the polar molecules are BeF2 and CH3Cl, while the nonpolar molecules are BF3, CO2, BH3, and CI4.

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What two categories of materials require special engineering for chemical hoods?
Radioactive substances and perchloric acid
Radioactive substances and blood-born pathogens
Toxic gases and radioactive gases
Toxic gases and blood-born pathogens

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Toxic gases and radioactive gases are the two categories of materials that require special engineering for chemical hoods.

The design and construction of the hoods must take into consideration the potential hazards of these materials to ensure the safety of workers and prevent any release of harmful substances into the surrounding environment. Chemical hoods are a critical component of laboratory safety and must be carefully designed and maintained to protect workers and the surrounding area from exposure to hazardous materials. Special engineering is needed to ensure that the hood is properly vented and that any radiation that is emitted is contained and not released into the environment.

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You have 800,000 atoms of a radioactive substance. After 3 half-lives have past, how
many atoms remain?

Remember that you cannot have a fraction of an atom, so round the answer to the
nearest whole number.

Answers

The half life of a radioactive material is inversely proportional to the decay constant and it is completely independent of the amount of it present initially. Here the number of atoms which remain after the decay of radioactive material is

The half-life period of a radionuclide is the time required for the decay of the one half of the amount of the species. The half life period is a characteristic of a radionuclide. The half-lives of different radionuclides vary from fractions of seconds to billions of years.

The amount remaining after 3 half-lives can be obtained as:

N = N₀ / 2ⁿ

N = 800000 / 2³

N = 800000 / 8

N = 100,000

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Question 5
Marks: 1
Neutrons are charged, high-energy particles.
Choose one answer.

a. True

b. False

Answers

Neutrons are not charged particles, they have no electrical charge, unlike protons that are positively charged and electrons that are negatively charged. Neutrons have a neutral charge, and they do not interact with charged particles like electrons and protons, but they can interact with other particles through the strong nuclear force.

Regarding the term "high-energy," neutrons can indeed be high-energy particles in certain situations. For example, when they are emitted during a nuclear reaction, they can have a lot of kinetic energy. However, in general, neutrons have a much lower energy than other subatomic particles like protons and electrons.
In summary, neutrons are not charged particles, but they can be high-energy particles in certain contexts.

The correct answer to the question is false.

Neutrons are not charged, high-energy particles. Instead, they are neutral particles found in the nucleus of an atom, along with protons. Neutrons have no charge, meaning they are not charged particles. Protons, on the other hand, are positively charged particles found in the nucleus.

While neutrons can be involved in high-energy reactions, such as nuclear fission and fusion, they themselves are not inherently high-energy particles. High-energy particles, such as cosmic rays or particles accelerated in particle accelerators, often carry a charge and exhibit high kinetic energies.

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H(g)+Cl(g)→HCl(g)The formation of HCl(g) from its atoms is represented by the equation above. Which of the following best explains why the reaction is thermodynamically favored?

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The reaction is thermodynamically favored because it releases energy, which is indicated by the negative value of the change in enthalpy (∆H) of the reaction. This means that the products have a lower enthalpy than the reactants, making the reaction spontaneous and energetically favorable.

Additionally, the decrease in the disorder or randomness of the system (negative ∆S) is outweighed by the decrease in enthalpy, resulting in a negative change in Gibbs free energy (∆G) and indicating that the reaction will proceed in the forward direction.

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when a strong acid is titrated with a weak base, the ph of the solution at the equivalence point is _____ than 7

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When a strong acid is titrated with a weak base, the pH of the solution at the equivalence point is less than 7.

This is because the weak base has a limited ability to accept protons, and so at the equivalence point, some of the strong acid will remain unreacted.During the titration, the strong acid will be neutralized by the weak base until the point where all the acid has been consumed and an equal number of moles of the weak base have been added. At this point, the solution will contain only the salt of the weak base and the strong acid. If the weak base is a weak enough base such that its salt with the strong acid undergoes hydrolysis, then the pH of the solution will be less than 7.For example, if acetic acid (a weak acid) is titrated with sodium hydroxide (a strong base), the pH of the solution at the equivalence point will be slightly acidic (pH around 5) due to the hydrolysis of the acetate ion.

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PART OF WRITTEN EXAMINATION:
Breaks in the coating of the pipe are called
A) vacations
B) holidays
C) naps
D) tours

Answers



The answer is B) holidays. Breaks in the coating of a pipe are called holidays. These are small areas where the protective coating has not properly adhered to the pipe's surface, leaving it exposed and potentially vulnerable to corrosion or damage.

The ensure the integrity and longevity of the pipe, it is essential to identify and repair any holidays promptly. Here is a brief step-by-step explanation of the process Inspect the pipe's coating for any visible breaks or irregularities. Use a holiday detector to identify any holidays in the coating. This device sends an electric current through the coating and alerts you when it detects a break in the circuit, indicating a holiday. Mark the location of any identified holidays for repair. Clean the area around the holiday to remove any dirt or debris and ensure proper adhesion of the repair material. Apply a patch or repair material to the holiday, following the manufacturer's recommendations for the specific coating and application method. Allow the repair material to cure according to the manufacturer's instructions. Re-inspect the repaired area with the holiday detector to ensure the repair has fully covered and sealed the holiday. By following these steps, you can effectively repair holidays in the coating of a pipe and maintain the pipe's structural integrity.

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What makes a substance a strong acid?
Less hydroxide ions in solution
Less hydrogen ions in solution.
More hydroxide ions in solution.
More hydrogen ions in solution.

Answers

Answer:

A strong acid is characterized by the fact that it ionizes completely in water to produce a large number of hydrogen ions (H+), resulting in a low pH value. Therefore, the correct answer is "More hydrogen ions in solution."

Calculate the volume of oxygen that was in excess. if 150cm³ of carbon(11) oxide burns in 80cm³of oxygen according to the following equation 2CO + O2 =2CO.​

Answers

If 150cm³ of carbon(11) oxide burns in 80cm³of oxygen according to the given equation the volume of oxygen that was in excess is 5.6 cm³.

From the balanced equation, we can see that 2 moles of CO react with 1 mole of O2. Therefore, we need to determine how much O2 is required to react with 150 cm³ of CO.

Let's start by calculating the number of moles of CO:

n(CO) = V(CO) / molar volume at STP

= 150 cm³ / 22.4 L/mol

= 0.006696 mol

Since the stoichiometric ratio of equation of CO to O2 is 2:1, we need half as many moles of O2 as CO. Therefore, the number of moles of O2 required is:

n(O2) = 1/2 * n(CO)

= 1/2 * 0.006696 mol

= 0.003348 mol

Now we can calculate the volume of oxygen required using the ideal gas law:

PV = nRT

Assuming the temperature and pressure are constant, we can simplify this to:

V = n(RT/P)

where V is the volume of gas in liters, n is the number of moles of gas, R is the ideal gas constant, T is the temperature in Kelvin, and P is the pressure in atmospheres.

At STP, the temperature is 273 K and the pressure is 1 atm. Therefore:

V(O2) = n(O2)(RT/P)

= 0.003348 mol * (0.0821 L·atm/mol·K * 273 K / 1 atm)

= 0.0744 L

= 74.4 cm³

So the volume of oxygen required to react with 150 cm³ of CO is 74.4 cm³. Since the initial volume of O2 was 80 cm³, the volume of O2 in excess is:

V(excess) = V(initial) - V(required)

= 80 cm³ - 74.4 cm³

= 5.6 cm³

Therefore, the volume of oxygen that was in excess is 5.6 cm³.

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Based on the percentages of components in Alka-Seltzer and the balanced equation below, determine the limiting reactant assuming 1 gram of Alka-Seltzer. 3NaHCO3(aq)+C6H8O7(aq)\rightarrow3CO2(gas)+Na3C6H5O7(aq)+3H2O(L) A. acetylsalicylic acid (C9H8O4) B. other ingredients C. sodium bicarbonate (NaHCO3) D. citric acid (C6H8O7)

Answers

Alka-Seltzer contains three main components: sodium bicarbonate (NaHCO3), citric acid (C6H8O7), and acetylsalicylic acid (C9H8O4). .

According to the manufacturer, Alka-Seltzer contains about 325 mg of sodium bicarbonate, 1000 mg of citric acid, and 325 mg of acetylsalicylic acid per tablet. Assuming that 1 gram of Alka-Seltzer is equivalent to one tablet, we can calculate the approximate percentage of each component as follows:

- Sodium bicarbonate: (325 mg / 1000 mg) x 100% = 32.5%
- Citric acid: (1000 mg / 1000 mg) x 100% = 100%
- Acetylsalicylic acid: (325 mg / 1000 mg) x 100% = 32.5%

Using these percentages, we can make an educated guess about the limiting reactant. Since there is an equal amount of sodium bicarbonate and acetylsalicylic acid in Alka-Seltzer (both at 32.5%), and since citric acid is present in a larger amount (at 100%), it is possible that citric acid could be the limiting reactant.

However, without more precise information about the percentages of each component in Alka-Seltzer, we cannot determine the limiting reactant with certainty.

It's worth noting that even if we did know the exact percentages of each component in Alka-Seltzer, there could be other factors that affect the limiting reactant, such as the temperature and pressure of the reaction. Additionally, the reaction may not proceed according to the balanced equation in a real-world scenario.

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4) 96,500C is required to produce 0.5moles of a certain metal at the cathode. What is the charge on the metal ion?

5) A current of 15A, flowing for 965s, produces 0.05 moles of element Q. Find the valency of Q.​

Answers

1) The charge on the metal is + 2

2) The valency of the element Q is 3

What is electrochemical cell?

We know that the kind of cell that we dealing with here is electrochemical cell.

In this problem, I = 15A and t = 965s, so:

Q = 15A x 965s = 14475 C

Then;

The amount of substance produced n is given by:

n = Q / (F x z)

where F is the Faraday constant (96500 C/mol), and z is the valency of the ion.

In this problem, n = 0.05 moles, so:

0.05 = 14475 C / (96500 C/mol x z)

Solving for z, we get:

z = 3

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1. What is the activation energy for this reaction?
2. What letter represents activation energy?
3. What is the change in energy?
4. Is it exothermic or endothermic?
5. What is the activation energy after the catalyst was added to the reaction?
5. What letter represents the activation energy after the catalyst was added?

Answer all the questions

Answers

The energy hump corresponds to the energy barrier existing between the reactants and products. The reactants must first acquire a certain amount of energy to reach the level of threshold energy.

The minimum excess energy that the reactants must acquire so as to have energy equals to the threshold energy is the activation energy.

Activation energy =  Peak energy - Energy of reactant

1. 80 - 0 = 80 kJ

2. Here letter 'E' represents activation energy

3. Change in energy = Energy of product - energy of reactant

20 - 0 = 20 kJ

4. The reaction is endothermic

5. A catalyst does not change the activation energy, it is 80 kJ

6. The letter is also E.

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Calculate the pH at the following points in a titration of 40 mL of 0.100 M barbituric acid (Ka=9.8×10−5) with 0.100 M KOH.(a) no KOH added(b) 20 mL of KOH solution added(c) 39 mL of KOH solution added(b) 40 mL of KOH solution added(b) 41 mL of KOH solution added

Answers

The pH values at different points in the titration of barbituric acid with KOH were calculated. The pH was initially acidic and decreased as KOH was added until the equivalence point was reached. After the equivalence point, the pH became basic and increased rapidly as excess KOH was added.

a) Before any KOH is added, the solution contains only barbituric acid. Therefore, the pH can be calculated using the dissociation constant (Ka) of the acid.pH = 1/2(pKa - log[C]) where pKa = -log(Ka) and [C] is the concentration of the acid.[tex]pH = 1/2(-log(9.8×10−5) - log(0.1)) = 2.15[/tex]b) At 20 mL of added KOH solution, half of the barbituric acid has been neutralized. This means that the amount of barbituric acid remaining is half of the original concentration and the amount of OH- is equal to the original concentration of the acid. Therefore, we can use the expression for the Kb of the conjugate base, to calculate the pH.[tex]pOH = -log[OH-] = -log(0.05) = 1.30\\Kb = Kw/Ka = 1.0E-14/9.8E-5 = 1.02E-10\\pKb = -log(Kb) = 9.99\\pH = 14.00 - pOH = 12.70[/tex]c) At 39 mL of added KOH solution, the amount of barbituric acid remaining is 1/10 of the original concentration and the amount of OH- is 10 times the original concentration of the acid. Therefore, we can use the expression for the Kb of the conjugate base to calculate the pH.[tex]pOH = -log[OH-] = -log(0.4) = 0.40\\Kb = Kw/Ka = 1.0E-14/9.8E-5 = 1.02E-10\\pKb = -log(Kb) = 9.99\\pH = 14.00 - pOH = 13.60[/tex]d) At 40 mL of added KOH solution, the solution contains only the conjugate base of the acid. Therefore, we can use the Kb of the conjugate base to calculate the pH.[tex]pOH = -log[OH-] = -log(0.5) = 0.30\\Kb = Kw/Ka = 1.0E-14/9.8E-5 = 1.02E-10\\pKb = -log(Kb) = 9.99\\pH = 14.00 - pOH = 13.70[/tex]e) At 41 mL of added KOH solution, the amount of OH- is in excess and can be calculated as follows:OH- = (mol of KOH added) - (mol of barbituric acid initially present)[tex]OH- = (0.041 L)(0.100 M) - (0.040 L)(0.100 M) = 4.1E-4 mol\\pOH = -log[OH-] = -log(4.1E-4) = 3.39\\pH = 14.00 - pOH = 10.61[/tex]In summary, the pH values at different points in the titration of barbituric acid with KOH were calculated. The pH was initially acidic and decreased as KOH was added until the equivalence point was reached. After the equivalence point, the pH became basic and increased rapidly as excess KOH was added.

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A compound that is added in small amounts to make a polymer more soft and pliable is called a(n) _____.

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The compound that is added in small amounts to make a polymer more soft and pliable is called a plasticizer. A polymer is a large molecule made up of repeating units.

Plasticizer is a low molecular weight substance that is added to the polymer to improve its flexibility and moldability. Plasticizers work by increasing the free volume in the polymer, which allows the polymer chains to move more easily and become more pliable.

Plasticizers are commonly used in the production of a wide range of products, including vinyl flooring, automotive parts, and medical devices. However, it's important to note that plasticizers can also have negative environmental and health effects, and there is ongoing research into developing safer alternatives.

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How many mL of 1.81 M CaCl2 have 18.4 g of CaCl2 in them?

Answers

It is crucial to understand that when a specific solution is described in terms of molarity or molar concentration (M).

Thus, The unit of concentration actually refers to the number of moles of solute that are present per litre of the solution.

The concentration of the calcium chloride solution in the given problem is 0.80 M, meaning that 0.80 moles of calcium chloride are present in one litre.

The molarity, M, is the number of moles of a pure substance present in a litre of a solution, whereas the molar mass, M, is the mass of a mole of a pure material.

Thus, It is crucial to understand that when a specific solution is described in terms of molarity or molar concentration (M).

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If a weak diprotic acid deprotonates, the resulting species will be which of the following? Choose the best description below.Select the correct answer below.an acida baseLast updated: 8/6both an acid and a basedepends on the substance

Answers

The resulting species when a weak diprotic acid deprotonates will depend on the specific substance. It could be both an acid and a base or only an acid or a base. Therefore, Option C is correct.

When a weak diprotic acid deprotonates, it can form different species depending on the specific acid. A diprotic acid is capable of donating two protons (H+) per molecule.

If the first proton is completely removed from the diprotic acid, it will form a monoprotic base. In this case, the resulting species will act as a base because it can accept a proton (H+). This species can be described as a base.

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Which of the following are correct for first-order reactions? Select all that apply?
a. The reaction slows down as the reaction proceeds. ?
b. A higher concentration of reactants will speed up the reaction. ?
c. The concentration of the reactants changes nonlinearly.
d. The half-life of the reaction stays constant as the reaction proceeds The units for the rate constant and the rate of reaction are the same.

Answers

The reaction slows down as the reaction proceeds and The half-life of the reaction stays constant as the reaction proceeds. Therefore the correct option is option A and D.

The rate of a first-order reaction is inversely proportional to the reactant concentration. The concentration of the reactant falls over the course of the reaction, which slows down the rate of the reaction.

However, the reaction's half-life is constant, which means that no matter where in the reaction it occurs, the length of time needed for half of the reactant's starting concentration to be consumed is the same.

The units of the rate constant for a first-order reaction are the same as the units for the reaction's rate, such as s-1 or min-1.

Reactant concentration changes linearly rather than nonlinearly. Therefore the correct option is option A and D.

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what are the ways to Absorb and remove unwanted surface oil

Answers

There are several ways to absorb and remove unwanted surface oil. One way is to use oil-absorbing sheets or blotting paper, which can easily soak up excess oil from the skin. Another way is to apply a clay mask, which can absorb oil and impurities from the skin.

There are several ways to absorb and remove unwanted surface oil. One way is to use oil-absorbing sheets or blotting paper, which can easily soak up excess oil from the skin. Another way is to apply a clay mask, which can absorb oil and impurities from the skin. Additionally, using a toner that contains ingredients like witch hazel or salicylic acid can help to remove surface oil and keep pores clear. It's important to avoid harsh products or over-washing the skin, as this can actually stimulate the production of more oil. Instead, focus on gentle, non-drying methods to keep skin balanced and healthy.

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What must be done with the rectifier before the entire rectifier can be safe to work on?
A) measure the AC input in the back
B) DC disconnect must be OFF
C) AC disconnect must be OFF
D) fuse out of circuit board

Answers

The AC disconnect must be turned OFF before the entire rectifier can be safe to work on. This will prevent any live AC voltage from reaching the rectifier, reducing the risk of electric shock or electrocution.

Additionally, it is important to ensure that the DC disconnect is also turned OFF to prevent any residual DC voltage from lingering in the system. Once both disconnect switches are OFF, the fuse on the circuit board should also be removed to ensure that there is no current flowing through the circuit. This will allow technicians to work on the rectifier without any danger to themselves or others nearby.In summary, before working on a rectifier, it is essential to turn off both the AC and DC disconnect switches and remove the fuse on the circuit board to ensure that there is no live current flowing through the system.

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An atom has the following chemical symbol: N-14
How many protons, neutrons and elecrons does this atom have?

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The chemical symbol N-14 indicates that this atom is nitrogen-14, which means it has a mass number of 14. the N-14 atom has 7 protons, 7 neutrons, and 7 electrons

The mass number is the sum of the number of protons and neutrons in the nucleus of an atom. Since nitrogen has an atomic number of 7, it also has 7 protons in its nucleus. This means that the number of neutrons in the nucleus must be 14-7=7.
As for electrons, the number of electrons in an atom is equal to the number of protons. This is because an atom is electrically neutral, meaning it has an equal number of positive charges (protons) and negative charges (electrons). Therefore, nitrogen-14 has 7 electrons orbiting around its nucleus.
In summary, nitrogen-14 has 7 protons, 7 neutrons, and 7 electrons. The number of protons and electrons determine the chemical properties of an element, while the number of neutrons affects its nuclear stability and isotopic properties.

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Some parts of the electromagnetic spectrum can cause changes in biological cells due to the energy of each photon: For the wavelengths given for different bands, determine the energy of a single photon, indicate if it can break the atomic bond of water (4.7 eV), ionize hydrogen (13.6 eV), and ionize calcium (6.11 eV): For those that can break bonds, how many molecules/atoms can one photon change? Show all of your work, not just vour answers in the table: Band Microwave Infrared Green Ultraviolet X-ray Break HzO lonize H lonize Ca 5 cm 50 um 500 nm 10 nm 50 pm

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One UV photon can break the atomic bond of almost one water molecule. However, it is important to note that the actual number of molecules/atoms that can be changed by one photon depends on several factors, such as the intensity and duration of the exposure.

The energy of a single photon can be calculated using the equation E = hv, where E is energy, h is Planck's constant, and v is frequency.For the given bands, the energy and other properties of a single photon are:Microwave: [tex]2.42 * 10^{-23} J[/tex], cannot break the atomic bond of water or ionize hydrogen or calcium.Infrared: [tex]1.98 * 10^{-19} J[/tex], cannot break the atomic bond of water or ionize hydrogen or calcium.Green: [tex]3.95 * 10^{-19} J[/tex], cannot break the atomic bond of water or ionize hydrogen or calcium.Ultraviolet: [tex]7.86 * 10^{-19} J[/tex], can break the atomic bond of water, cannot ionize hydrogen or calcium.X-ray: [tex]3.98 * 10^{-15} J[/tex], can break the atomic bond of water and ionize both hydrogen and calcium.To calculate the number of molecules/atoms that one photon can change, we can divide the energy required to break a bond/ionize an atom by the energy of one photon. For example, for water:Energy required to break atomic bond: [tex]4.7 eV = 7.54 * 10^{-19} J[/tex]Energy of one UV photon: [tex]7.86 * 10^{-19} J[/tex]Number of water molecules changed per photon: [tex]7.54 * 10^{-19} J / 7.86 * 10^{-19} J = 0.96[/tex]Therefore, one UV photon can break the atomic bond of almost one water molecule. However, it is important to note that the actual number of molecules/atoms that can be changed by one photon depends on several factors, such as the intensity and duration of the exposure.

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If you are given 36 moles of HCI (hydrochloric acid), how many moles of magnesium chloride
will be produced?

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2HCl + Mg -> MgCl2 + H2

The balanced chemical equation shows that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of magnesium chloride and 1 mole of hydrogen gas.

Therefore, if you have 36 moles of hydrochloric acid, you would need 18 moles of magnesium to react with all of it, and this would produce 18 moles of magnesium chloride.

How many moles of NH3 would form from the complete reaction of 14. 0 g N2

Answers

The total number of moles NH3 is 1.00 mole, under the condition that the reaction is of 14. 0 g N2.

The given balanced chemical equation for the reaction of nitrogen gas (N2) and hydrogen gas (H2) to form ammonia gas (NH₃) is
N₂(g) + 3H₂(g) → 2NH₃(g)

The molar mass of N₂ is 28.01 g/mol. To evaluate the number of moles of N₂ in 14.0 g of N₂ we divide the mass by the molar mass
Number of moles of N₂ = Mass of N₂ / Molar mass of N₂
Number of moles of N₂ = 14.0 g / 28.01 g/mol
Number of moles of N₂ = 0.4998 mol

Then, the number of moles of NH3 that would form from the complete reaction of 14.0 g N2 can be evaluated
Number of moles of NH₃ = Number of moles of N₂ × (2 moles NH₃ / 1 mole N₂)
Number of moles of NH₃ = 0.4998 mol × (2 mol NH₃ / 1 mol N₂)
Number of moles of NH₃ = 0.9996 mol

Hence, approximately 1.00 mole of NH₃ would form from the complete reaction of 14.0 g N₂.

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What presents as acute febrile illness often followed by chills and rigors, then fever spikes (up to 40C/104F) and sweating?

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The symptoms you are describing are commonly associated with an acute febrile illness, typically caused by an infection.

The patient may experience chills and rigors, followed by a fever spike that can reach up to 40C/104F. Sweating often follows the fever. It is important to seek medical attention if these symptoms persist or worsen. This type of fever is often caused by a bacterial or viral infection and is usually accompanied by other symptoms such as headache, fatigue, body aches and pains, and nausea. If left untreated, this type of fever can lead to more serious health complications. It is important to seek medical attention if any of these symptoms are present.

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1)how many red blood cells could you line up across the grain of sand?


2) How many red blood cells could you line up across the diameter of a penny (0. 02 m)?


Please I need helpppppp

Answers

Penny #2439
Sand grain #244

Hope this helps :)

Brainlist pls

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