Find the product of the complex numbers. Express your answer in trigonometry form. Z1= 7cos(15) + isin(15)) z2= 2(cos(110)+ isin(110))

Answer:

(0, 8/3) = y-intercept

Step-by-step explanation:

I chose to find the y-intercept since it is easy to find with the given information.

The equation for a line is y = mx + b

To find the y-intercept, we must plug in the info we have and solve for b:

4 = -1/3 (-4) + b

4 = -4/3 + b

8/3 = b

To find a point on the line, you also could have added -1 to 4 and 3 to -4 since slope means rise/run or change in y/change in x:

(y - 1) / (x + 3) = (4 - 1) / (-4 + 3) = (3, -1) (flip since it's the y and x coordinate) = (-1, 3)

The computation shows that:

G n M = Anael and Max

G u S = Acel, Action, Anael, Max, Carl, Dario, Catlin, Kai, and Barek.

From the information, ten students from a school appear in one or more subjects for an inter school quiz competition as shown in the table.

The subjects include general Knowledge Math Science.

Therefore, G represents the set of students appearing for General Knowledge, M represents the set of students appearing for Math, and S represents the set of students appearing for Science. The intersection is illustrated above.

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[tex]\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & 80\\ P=\textit{initial amount}\dotfill &40\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years \end{cases} \\\\\\ 80=40(1 + 0.05)^{t}\implies \cfrac{80}{40}=1.05^t\implies 2=1.05^t\implies \log(2)=\log(1.05^t) \\\\\\ \log(2)=t\log(1.05)\implies \cfrac{\log(2)}{\log(1.05)}=t\implies 14.2\approx t[/tex]

Answer:

I think that I am right.  One train is traveling at 75 mph and the other train is traveling at 91 mph

Step-by-step explanation:

The correct proportion that can be used to find the actual distance  represented by 5 inches on the map is start fraction over 50 end fraction=start fraction 50 over 5 end fraction which is 3/50=5/x.

Given that 3 inches on a map represents 50 miles.

We are told to find the proportion which can be used to represent 5 inches.

Multiplication is basically finding the product of two numbers but it can be used to convert the units also.

If 3 inches represents 50 miles then,

1 mile=50/3

Multiply both sides by 5.

5 miles=5*50/3

If we see the options then we will get that the most appropriate and correct option which represents 5 inches is that start fraction over 50 end fraction=start fraction 50 over 5 end fraction which is 3/50=5/x.

Hence the correct proportion that can be used to find the actual distance represented by 5 inches on the map is start fraction over 50 end fraction=start fraction 50 over 5 end fraction which is 3/50=5/x.

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Answer:

B

Step-by-step explanation:

3/50 = 5/x

Answer: 8  units

Step-by-step explanation:

Answer:

-24 would be the temperature

Answer:

-24 BECAUSE I did all the math.

Answer:

  c = 2.25

Step-by-step explanation:

The normal distribution function is symmetrical, so the area not in the central zone is split evenly between the lower and upper tails.

We can find -c from ...

  P(x < -c) = (1 - 0.9756)/2 . . . . .  the area in the lower tail

The calculator tells us -c = -2.25.

  c = 2.25

Answer:

the third one

Step-by-step explanation:

it is function that contain four domain

Answer:

f(-5) = 30

f(0) = 5

f(3) = 14

Step-by-step explanation:

=> f(x) = x²+5

for , f(-5) = (-5)² +5

=> 25 +5

=> 30

for , f(0) = (0)² +5

=> 5

for , f(3) = (3)² + 5

=> 9 + 5

=> 14

The derivative of y= sin x sin 3x​ is [tex]$=3 \cos x-3 \cos 3 x$[/tex]

To find the derivative of y= sin x sin 3x​:

[tex]$y=3 \sin (x)-\sin (3 x)$[/tex]

[tex]$y^{\prime}=3 \cos x-[\cos (3 x) \cdot 3]$[/tex]

[tex]$y^{\prime}=3(\cos x-\cos 3 x)$[/tex]

[tex]\frac{dx}{dy} =3 cosx - 3 cos x[/tex]

Differentiate [tex]sin 3x[/tex] using the chain rule

Given [tex]y=f^{'} (g(x))*g^{'}[/tex]←chain rule

y=[tex]y=3 sin x-sin 3x[/tex]

[tex]\frac{dx}{dy} =3 cos x - cos 3x*\frac{d}{dx} (3x)[/tex]

[tex]=3cosx-3cos3x[/tex]

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If you do in fact mean [tex]f(1)=f(6)=0[/tex] (as opposed to one of these being the derivative of [tex]f[/tex] at some point), then integrating twice gives

[tex]f''(x) = -\dfrac1{x^2}[/tex]

[tex]f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1[/tex]

[tex]f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2[/tex]

From the initial conditions, we find

[tex]f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0[/tex]

[tex]f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)[/tex]

Eliminating [tex]C_2[/tex], we get

[tex](C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))[/tex]

[tex]-5C_1 = \ln(6)[/tex]

[tex]C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)[/tex]

Then

[tex]\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}[/tex]

Answer: one

Step-by-step explanation:

parallel faces are the ones that are opposite to each other.

Answer:

one

Step-by-step explanation:

there is only one pair of parallel faces.

Answer:

Step-by-step explanation: Hey for the second one I got y = -3/4x -0.5 I'm not sure if its correct though sorry if not
ill try my best to explain my solution though
1. From the parallel equation (3x + 4y = 12) all we need to do is find the slope

So the easiest way to do so is to put the said equation in y-intercept form

y=mx +b
m= slope

b= y intercept

so 1. 3x + 4y = 12

=

4y = 12-3x

divide that by 4 to get only y

y=3-3/4x

-3/4 is our slope

y=-3/4x+b

than we have a point -2, -2

if we put -2 for y

-2=-3/4x+b

and then we put our -2 for x
-2 = -3/4 * -2 + b

=

-2  = -1.5 +b
b=-0.5

Answer : y=-3/4x-0.5

The aim of factorization to obtain the common factors that are present in the expression.

When we factorize an expression, the aim is to obtain the common factors that are present in the expression.

Now we have trinomials numbered 1 - 15. Trinomial is an expression that is made up of three terms. Quadratic expressions are mostly found to appear as trinomial

The binomial factors that are associated with each are shown in the factorized expressions below. The binomials contain two terms in each bracket.

Given the trinomials, the correct binomial factors are;

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Answer:

21%

Step-by-step explanation:

($63*100%) / $300 = 21%

The minimum surface area that such a box can have is 380 square

Represent the base length with x and the bwith h.

So, the volume is

V = x^2h

This gives

x^2h = 500

Make h the subject

h = 500/x^2

The surface area is

S = 2(x^2 + 2xh)

Expand

S = 2x^2 + 4xh

Substitute h = 500/x^2

S = 2x^2 + 4x * 500/x^2

Evaluate

S = 2x^2 + 2000/x

Differentiate

S' = 4x - 2000/x^2

Set the equation to 0

4x - 2000/x^2 = 0

Multiply through by x^2

4x^3 - 2000 = 0

This gives

4x^3= 2000

Divide by 4

x^3 = 500

Take the cube root

x = 7.94

Substitute x = 7.94 in S = 2x^2 + 2000/x

S = 2 * 7.94^2 + 2000/7.94

Evaluate

S = 380

Hence, the minimum surface area that such a box can have is 380 square

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There is convincing evidence the new type of tire tread improves mileage of the tire.

The given parameter is:

Average = 50000 miles

New average = 51500 miles

The dot plot is added as an attachment

From the dot plot, we can see that the mean value of 51500 or more occurred 14 times out of the 200 samples

So, the conclusion is that: (a) Yes, because a mean mileage of 51,500 or more occurred only 14 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.

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The value of 'y' is 32. 5 degrees . Option B

It is important to note that If two chords intersect inside a circle,

The measure of the angle formed is half the sum of the measure of the arcs intercepted by the angle and its vertical angle

From the diagram, it is shown that the both the chords at 'y' and the angle '65' intersect in the circle

We then have that;

[tex]y = 65[/tex] × [tex]\frac{1}{2}[/tex]

[tex]y = 65[/tex] × [tex]0. 5[/tex]

y = 32. 5 degrees

We can see that the value of 'y' in the given figure is 32. 5 degrees which is half the angle at the vertex of the intersecting chords.

Thus, the value of 'y' is 32. 5 degrees . Option B

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The material-handling cost per wall mirror under activity-based costing is $280

What is activity-based costing?

Activity-based costing involves absorbing overheads based on cost drivers which directly impact the incurrence of the overhead, in this case, material moves determine the amount of material-handling costs to be incurred, hence, material-handing overheads would be absorbed into the two products based on material moves, which is the appropriate cost driver.

There 25 materials move in both divisions (i.e. 7+18=25)

Material-handling cost per material move=Budgeted material-handling costs /total material moves

Budgeted material-handling costs =$30,000

Material-handling cost per material move=$30,000/25

Material-handling cost per material move=$1,200

Total material-handing costs for wall mirror=number of material moves for wall mirror*Material-handling cost per material move

Total material-handing costs for wall mirror=7*$120

Total material-handing costs for wall mirror=$8,400

material-handling cost per wall mirror=Total material-handing costs for wall mirror/number of wall mirrors

material-handling cost per wall mirror=$8,400/30

material-handling cost per wall mirror=$280

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Answer:

[tex]-8c+6[/tex]

Step-by-step explanation:

[tex]2(-6c+3)+4c=-12c+6+4c=\boxed{-8c+6}[/tex]

Answer:

-8c + 6 and 3(-4c+2) + 4c

Step-by-step explanation:

khan

Answer:

C. Subtract 4 from both sides.

Step-by-step explanation:

You need the equation in the form x² + ax + b = 0 to then either try factoring or use the quadratic formula.

In order to achieve that, you need to first:

Subtract 4 from both sides.

Considering the asymptotes of the function, the equation that represents the graph is:

[tex]y = \frac{1}{x + 2} + 3[/tex]

This function, from the graph, has a vertical asymptote at x = -2, hence the denominator is given by:[tex]y = \frac{1}{x + 2} + 3[/tex]

x + 2, as x + 2 = 0 -> x = -2.

The horizontal asymptote is of y = 3, hence:

[tex]\lim_{x \rightarrow \infty} f(x) = 3[/tex]

Which means that the function is described by the following rule:

[tex]y = \frac{1}{x + 2} + 3[/tex]

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The preparation of the Cost of Goods Sold Budget for MingWare Ceramics Inc. in September is as follows:

Beginning inventory of finished goods $11,850

Cost of goods manufactured                485,310

Ending inventory of finished goods      (12,670)

Cost of Goods Sold                          $484,490

The cost of goods sold budget sums the costs of the beginning inventory of finished goods with the cost of goods manufactured and subtracts the ending inventory of finished goods.

The cost of goods sold budget is based on the cost of goods manufactured budget.

Direct materials:                            Enamel        Paint     Porcelain      Total    

Total direct materials purchases

budgeted for September            $35,870    $7,530    $139,890  $183,290

Estimated inventory, September 1   1,730        4,150          6,920      12,800 Desired inventory, September 30 (2,980)      (2,710)         (7,150)    (12,840)

Materials used in production                                                          $183,250

Direct labor cost:           Kiln Department    Decorating Department   Total

Total direct labor cost

 budgeted for September    $51,550                   $149,500        $201,050

Finished goods inventories:             Dish       Bowl     Figurine             Total

Estimated inventory, September 1  $5,810   $3,310     $2,730        $11,850

Desired inventory, September 30    3,720    4,590       4,360         12,670

Work in process inventories:

 Estimated inventory, September 1      $3,540

Direct materials used in production $183,250

Direct labor costs                              $201,050

Total factory overhead costs             $99,450

 Desired inventory, September 30       (1,980)

Cost of goods manufactured           $485,310

Indirect factory wages $80,400

Depreciation of plant and equipment 10,550

Power and light 5,110

Indirect materials 3,390

Total 99,450

Thus, to prepare the cost of goods sold, as above, MingWare Ceramics, requires to determine the cost of goods manufactured for September.

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The subsets of the set of novels is given as follows:

{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.

Suppose we have a set with cardinality n, that is, with n elements. This set will have 2^n subsets, which are all the possible combinations with the elements of the set, including the empty set.

In this problem, the novels are given as follows:

Light, Zami, and Money.

Hence the possible subsets are given as follows:

{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.

With is the list that is asked for this problem, which are the subsets of the set of novels.

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Answer:

-8 5/12

Step-by-step explanation: