Find the slope of the line represented by the data below

Answer: -8

Hope this helps :)

Step-by-step explanation:

Adding two negative integers is just like adding two regular numbers

Answer:

negative 8

Step-by-step explanation:

calculator

Therefore , on solving the provided question we can say that inequality will be  x < 2.2727272727 .

An inequality in mathematics is a relationship between two expressions or values that is not equal. Thus, imbalance leads to inequality. An inequality creates the link between two values that are not equal in mathematics. Egality is distinct from inequality. When two variables values are not equal, most commonly use the not equal sign (). Different inequalities are used to contrast values, no matter how little or large. Many simple inequalities may be resolved by modifying the two sides until the variables are all that remain. But a number of things contribute to inequality.

Here,

Given :

the inequality will be

=> 3(2x – 5) < 5(2 – x)

=> 6x - 15 < 10-5x

=> 11x < 25

=> x < 2.2727272727

Thus ,

x < 2.27

Therefore , on solving the provided question we can say that inequality will be  x < 2.2727272727 .

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The complete question is " Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left. "

A bird with a weight greater than 13 ounces lives in the southern region

Z = (x – mean)/standard deviation

Le x be weight for birds

For the northern region  

Z = (13 – 10)/3

Z = 1

For the southern region

Z = (13 – 16)/2.5

Z = -1.2

to find in what region is more likely to find a bird with 13 ounces, we calculate the probability for each z value

For the northern region  

P (x>13) = P(z > 1)

Then we use the z table to find the area under the curve.

P (x>13) = 0.1587

For the southern region

P (x>13) = P(z > 1.2)

Then we use the z table to find the area under the curve.

P (x>13) = 0.8849

Is it more likely that a bird with a weight greater than 13 ounces lives in the southern region

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The probability of drawing exactly three face cards is given as follows:

0.0660 = 6.60%.

The mass probability formula is presented as follows:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

Considering that a standard deck is composed of 52 cards, of which 12 are face cards, and 5 cards are taken, the values of the parameters are given as follows:

N = 52, k = 12, n = 5.

The probability of drawing exactly three face cards is P(X = 3), obtained as follows:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 3) = h(3,52,5,12) = \frac{C_{12,3}C_{40,2}}{C_{52,5}} = 0.0660[/tex]

The problem asks for the probability of drawing exactly three face cards.

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Using a system of equations, Christine's investments in account one were $4,000 and in account two $16,000.

A system of equations refers to simultaneous equations.

Simultaneous equations are two or more equations solved concurrently.

Total investment in two accounts = $20,000

The simple interest rate for account one, x = 8%

The simple interest rate for account two, y = 10%

Total interest for a year = $1,920

Let account one = x and account two = y

x + y = 20,000 ... Equation 1

0.08x + 0.1y = 1,920 ... Equation 2

Multiply Equation 1 by 0.08

0.08x + 0.08y = 1,600 ... Equation 3

Subtract Equation 3 from Equation 2:

0.08x + 0.1y = 1,920

-

0.08x + 0.08y = 1,600

0.02y = 320

y = 16,000

= $16,000

In Equation 1, x + y = 20,000, Substitute y = 16,000:

x + 16,000 = 20,000

x = 4,000

= $4,000

Check:

From Equation 2:

0.08x + 0.1y = 1,920

0.08(4,000) + 0.1(16,000) = 1,920

320 + 1,600 = 1,920

Thus, using simultaneous equations, we can conclude that Christine invested $4,000 in the first account and $16,000 in the second account.

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Last year, Christine had $20,000 to invest. She invested some of it in an account that paid 8% simple interest per year, and she invested the rest in an account that paid 10% simple interest per year. After one year, she received a total of $1920 in interest. How much did she invest in each account?

First account:

Second account:

The function's approximate range will be specified by -∞<y≤12.

The exact same number of elements from Y are assigned to each element of X via a mathematical function from a set X to a set Y.

The function's domain and codomain are respectively referred to as the sets X and Y as a whole.

Functions were first used to describe the idealized relationship between two varying quantities.

Now, drag as follows:

The collection of output values determines a function's range.

The function's indicated range will be -∞ < y ≤ 12.

From the linked graph,

The function's output values (values on the y-axis) range from zero to f(x)=12.

Therefore, the function's approximate range will be specified by -∞<y≤12.

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The values of x, y, and z are 25,15 and, 7 respectively.

An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, whereas B is a constant. 

Given that,

x=y+10................(i)

y=z+8..................(ii)

x+y+z=47............(iii)

Solving these equations to find the values of x,y, and z.

Putting The value of x from the first equation in the third equation:

we get,

y+10+y+z=47

Solving this equation further, we get,

=>2y+z=47 -10=37

=>2(z+8)+z=37

=>2z+16+z=37

=>3z=37-16=21

=>z=21/3=7

=>y=z+8=7+8=15

=>x=y+10=15+10=25

Thus, The values of x, y, and z are 25,15 and, 7 respectively.

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The sum of the first n terms of an arithmetic sequence can be proven using the principle of induction. We assume the formula holds for n = k, and then show it holds for n = k+1, thus showing it holds for all values of n.

The sum of the first n terms of an arithmetic sequence can be determined using the formula S_n = (n/2)(a_1 + a_n), where a_1 is the first term and a_n is the nth term.

We can prove this formula using the principle of induction.

Base Case: Let n = 1. Then S_1 = (1/2)(a_1 + a_1), which simplifies to S_1 = a_1. This is the same result we would get if we added the first term of the sequence.

Inductive Step: Assume that the formula holds for n = k.

Then S_k = (k/2)(a_1 + a_k).

Now consider n = k+1.

S_k+1 = (k+1/2)(a_1 + a_k+1)

= (k/2)(a_1 + a_k) + (1/2)(a_1 + a_k+1)

= S_k + (1/2)(a_k+1 - a_1)

= S_k + (1/2)(a_k+1 - a_k) + (1/2)(a_k - a_1)

= S_k + (1/2)(a_k+1 - a_k) + [S_k - (k/2)(a_1 + a_k)]

= (k+1/2)(a_1 + a_k+1)

= S_k+1

Therefore, we have shown that if the formula holds for n = k, then it also holds for n = k+1. By the principle of induction, the formula holds for all n.

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The given expression 1 2/3+(-8 1/2) is equivalent to -41/6.

what are expressions?

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between. The mathematical operators can be of addition, subtraction, multiplication, or division. For example, x + y is an expression, where x and y are terms having an addition operator in between. In math, there are two types of expressions, numerical expressions - that contain only numbers; and algebraic expressions- that contain both numbers and variables.

e.g. A number is 6 more than half the other number, and the other number is x. This statement is written as x/2 + 6 in a mathematical expression. Mathematical expressions are used to solve complicated puzzles.

Now,

Given expression is 1 2/3+(-8 1/2)

=5/3+(-17/2)

=5/3-17/2

Taking LCM 6

=(10-51)/6

=-41/6

Hence,

        The given expression 1 2/3+(-8 1/2) is equivalent to -41/6.

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Solving for UY. in the figure provided where VX is a midsegment of UWY,  UY is 90

When the comparable triangles' angles are congruent and their respective sides are proportionate, this is referred to as similar triangles in geometry.

In light of this, if the triangle's corresponding angles are congruent, then the side should be proportionate.

For the given figure, the proportionate sides are

WV and VX, WU and UY

Solving for P

WV / VX = WU / UY

1 / (20p - 95) = 2 / (13p - 1)

cross multiplying

13p - 1 = 2(20p - 95)

13p - 1 = 40p - 190

collecting like terms

190 - 1 = 40p - 13p

189 = 27p

p = 7

solving for UY

= 13p - 1

= 13 * 7 - 1

= 90

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Answer:

d. 9 - 2c + 8s

Step-by-step explanation:

we can distribute the two by multiplying it by both 4.50 and -c. our result will be 9 and -2c. simply combine that with the 8s that we already had, and we end up with 9 - 2c + 8s.

Answer:

1/1-mpc and 1-mps

Step-by-step explanation:

to get the multiplier effect you use the formula

M=1/1-MPC

Answer:

D

Step-by-step explanation:

If you folded the figure on the line of symmetry.  The right side would fit perfectly over the left side.

Answer:The temperature dropped 24°F overnight, so the change in temperature would be represented by the expression |-24|, which is the absolute value of -24.

You can also represent it by |38| - |-24| which is equal to 38 - (-24) = 38 + 24 = 62°F.

Step-by-step explanation:

a. The value of h'(3) is 45.

b. The value of H'(1) is 36.

The complete table is in the attachment. h' and H are derivates from function h(x) and H(x). Using the Chain Rules to derivate the function.

Calculate the h'(x) function

h(x) = f(g(x))

h'(x) = d/dx {f(g(x))}

h'(x) = f' (g(x)) × g'(x)

h'(3) = f' (g(3)) × g'(3)

h'(3) = f'(2) × 9

h'(3) = 5 × 9

h'(3) = 45

Calculate the H'(x) function

H(x) = g(f(x))

H'(x) = d/dx {g(f(x))}

H'(x) = g' (f(x)) × f'(x)

H'(1) = g' (f(1)) × f'(1)

H'(1) = g'(3) × 4

H'(1) = 9 × 4

H'(1) = 36

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The general solution of  dy over dx equals x times y plus 3 times x question is [tex]y=e^{\frac{x^{2} }{2} +c_{1}} -3[/tex]

A differential equation is an equation that contains one or more functions with its derivatives.

The given differential equation is  dy over dx equals x times y plus 3 times x question

dy/dx=xy+3x

dy/dx=x(y+3)

dy/dx-x(y+3)=0

Solve seperable ODE

[tex]y=e^{\frac{x^{2} }{2} +c_{1}} -3[/tex]

Hence, the general solution of dy over dx equals x times y plus 3 times x question is [tex]y=e^{\frac{x^{2} }{2} +c_{1}} -3[/tex]

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These two points on the number line describe that she descended by 70 units.

A number line is defined as the number marked on the line calibrated into an equal number of units. For example -1, 0, 1, and so on.

Here,
She started at –5 and descended to –75.
On the number line, the difference between  -75 and -5 is given as
= -5 - (-75)
= 70

Thus, these two points on the number line describe that she descended by 70 units.

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Answer: [tex]y-1=\frac{1}{4}(x-5)[/tex]

Step-by-step explanation:

The median from vertex [tex]A[/tex] passes through [tex]A[/tex] and the midpoint of [tex]\overline{BC}[/tex].

Using the midpoint formula, the midpoint of [tex]\overline{BC}[/tex] has coordinates [tex]\left(\frac{3+7}{2}, \frac{5-3}{2} \right)=(5, 1)[/tex].

Therefore, we need the equation of the line passing through [tex](-3,-1)[/tex] and [tex](5,1)[/tex].

The slope of this line is [tex]\frac{-1-1}{-3-5}=\frac{1}{4}[/tex].

Using point-slope form, the equation is y[tex]y-1=\frac{1}{4}(x-5)[/tex].

If for her party, Carla bought a 5-pound bag of candy to give as party treats. She invited 15 people. The amount of candy that each of the 15 people get is: A) 15 ÷ 5 = 15/5 = 3 pounds.

Given data:

Candy bought = 5

Number of people invited = 15

Now let find the amount of candy to gives as party treats

Number of candy = Number of people invited / Candy bought

Number of candy = 15/5

Number of candy = 3 pounds

Therefore we can conclude that the correct option is A.

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The value of upper quartile is, 300.

The value of 7th decile is, 250.2.

The value of 35th percentile is, 100.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

The donations are as follows,

⇒ 50, 50, 50, 100, 100, 100, 150, 150, 200, 250, 250, 300, 300, 400, 500.

Now, We find the values as;

a) The upper quartile is,

⇒ Qₐ = a/4 (n + 1)

Here, n = 15

So, We get;

⇒ Q₃ = 3/4 (15 + 1)

        = 3/4 × 16

        = 12

So, Q₃ is in 12th position.

So, The value of Q₃ = 300

The value of 7th decile is,

⇒ D₇ = 7/10 (15 + 1)

        = 7/10 × 16

        = 11.2

Here, 11.2 is between the position 11th and 12th position which are 250 and 300 respectively.

Then, We get;

⇒ 300 - 250 = 50

Hence, The value of D₇ = 250 + 0.2

                                     = 250.2

Now, The value of 35th percentile is,

⇒ Pₐ = a/100 (n + 1)

⇒ P₃₅ = 35/100 (15 + 1)

         = 35/100 × 16

         = 5.6

Here, 5.6 is between the 5th and 6th position which are 100 and 200 respectively.

Hence,  P₃₅ = 100

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Let ww represent the number of hours washing cars, and tt represent the number of hours tutoring.

The inequality representing the total number of hours Arianna must work between both jobs is:

ww + tt ≥ 10

This inequality states that the number of hours spent washing cars plus the number of hours spent tutoring must be greater than or equal to 10 hours. This represents all possible combinations of hours washing cars and hours tutoring that Arianna can work in a given week while meeting the requirement that she must work no less than 10 hours altogether between both jobs.

Answer is c. 2.5, 4, 5

Step-by-step explanation:

To find the dimensions of the new triangle,

we need to apply the scale factor of 0.5 to the original triangle's dimensions.

This means we need to multiply each dimension by 0.5.

Original Dimensions: 5, 8, 10

New Dimensions:

5 x 0.5 = 2.5,

8 x 0.5 = 4

10 x 0.5 = 5

Therefore, the dimensions of the new triangle are 2.5, 4, 5.

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So on solving provided question we can say that given angle is m/ABD (7q-46) (3q+6)°​ = m/ABD = 98

An angle is a form in Euclidean geometry made composed of two rays, called the angle's sides, that meet at a point in the middle known as the angle's vertex. In the plane where the rays are placed, two rays can produce an angle. An angle is also produced when two planes intersect. They're known as dihedral angles. In plane geometry, an angle is the form that two rays or lines with a common termination might take. The Latin word "angulus," which means "horn," is where the English word "angle" comes from. The two rays, also known as the sides of the angle, have a common termination known as the vertex.

here,

the given angle is m/ABD (7q-46) (3q+6)°​

m/ABD = 98

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According to the vector rule, the values of the 2u, -3v, u + v, and 3u + 4v are (-4, 18), (-18, 6), (4, 7) and (18, 19) respectively.

Here we have given the following two vector such as

u = (-2, 9)

v = (6, -2)

Then as per the following vector rule, t

=> ku = (ka , kb)

where k refers the constant in vector.

Then the value of 2u is calculated as,

=> 2u = ((-2 x 2), (9 x 2)) = (-4, 18)

And the value of -3v is calculated as ,

=> -3v = ((-3 x 6), (-3 x- 2)) = (-18, 6)

Here we have to use the following rule, that is written as,

=>  (u ± v) = (a ± c, b ± d)

Then the value of u + v is calculated as,

=> (u + v) = ((-2 + 6),  (9 + (-2)) = (4, 7)

Then the value of 3u + 4v is calculated as,

=> 3u = ((3 x -2), (3 x 9)) = (-6, 27)

And the value of

=> 4v = ((4 x 6), (4 x- 2)) = (24, -8)

Then the value of

=> 3u + 4v = (-6, 27) + (24, -8)

=>  3u + 4v = ((-6+24) , (27 + (-8))

Therefore, the resulting value is (18, 19).

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The percentage of the total deliveries made by the Mary is equal to 95%.

As given in the question,

Total number of deliveries need to be delivered by the Mary this week = 40

Total number of deliveries completed by Mary is equal to 38

Percentage formula =  [( Number obtained ) / (Total number ) ] × 100

Substitute the value in the formula we get,

The percentage of the completed deliveries made by Mary is

= ( 38 / 40 ) × 100

= 3800 / 40

= 95%

Therefore, the total percentage of the completed delivery made by Mary is equal to 95%.

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In the given question, none of the function exhibits an end behavior

The end behavior of a polynomial is the way the graph of the polynomial behaves as the input values become very large or very small. Generally, the end behavior of a polynomial is either up, down, or a combination of both. If the highest degree term has a positive coefficient, the end behavior is up; if the highest degree term has a negative coefficient, the end behavior is down. If the highest degree term has a coefficient of zero, the end behavior is a combination of up and down.

In the functions given, we can find the end behavior of each of these functions.

1)

y = √x

The leading coefficient test requires a polynomial and this function is not a polynomial.

2)

y = √(x - 5) - 6

The leading coefficient test requires a polynomial and this function is not a polynomial.

3)

y = -3√(x + 3) + 7

The leading coefficient test requires a polynomial and this function is not a polynomial

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The volume of the new box is 30 units^3.

We can infer the roots are rational integers from the response options, thus this polynomial ought to be simple to factor. The coefficients of x must multiply by 10, hence they must be in some sequence of 5,2,1 or 10,1. Since we can try each one separately, we can express the factored form as follows:

                                       (5x-p)(2x-q)(x-r)

Due to the fact that p, q, and r must multiply to 6, they must be either 3,2,1 or 6,1,1 in some sequence. Once more, we may test each one in a different place to determine if they multiply properly.

When we multiply the x-terms and attempt (5x-2)(2x-1)(x-3), the answer is 29. Try adding the x^2 terms together; they equal -39. Consequently, the roots are [tex]\frac{2}{5} , \frac{1}{2} and 3.[/tex] Now if you add 2 to each root, you get the volume is

=> [tex]\frac{12}{5} X \frac{5}{2} X 5 =30[/tex]

Therefore, The volume of the new box is 30 units^3.

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Given ,

[tex]\bold\red{zeroes \: of \: a \: cubic \: polynomial \: are \: - 2 \:, \: 0 \: and \: 7} \\ [/tex]

[tex]let \:, \\ \boxed{\alpha \: = - 2} \\ \boxed{\beta \: = 0} \\ \boxed{\gamma \: = 7} [/tex]

Now ,

[tex]sum \: of \: zeroes \: = \alpha \: + \: \beta \: + \: \gamma \: \\ \dashrightarrow \: sum = - 2 + 0 + 7 = \underline{5} \\ \\ sum \: of \: product \: of \: zeroes \: taken \: two \: at \: a \: time \: = \alpha\beta \: + \beta\gamma \: + \: \alpha\gamma \\ \dashrightarrow \: ( - 2)(0) \: + \: (0)(7) \: + \: (7)( - 2) \: = \: \underline{ - 14} \\ \\ product \: of \: zeroes \: = \: \alpha\beta\gamma \\ \dashrightarrow \: ( - 2)(0)(7) = \underline{0}[/tex]

We know that ,

[tex] \boxed{cubic \: polynomial \: = {x}^{3} - (\alpha \: + \: \beta \: + \: \gamma \:) \:{x}^{2} + (\alpha\beta \: + \: \beta\gamma \: + \: \alpha\gamma) \:x \: - \: \alpha\beta\gamma} [/tex]

Plugging in the values , we get

[tex]\boxed{f(x) = {x}^{3} - 5 {x}^{2} - 14x + 0}[/tex]

since this polynomial has degree 3 , it is called a cubic polynomial.

hope helpful! :)

The equation is y = 3x/5 - 1/5.

Based on the position of two lines: m = 3/5

Write the equation of linear function

Substitute: 1 = 3/5 * 2 + b

Rearrange unknown terms to the left side of the equation: -b = 3/5 * 2 -1

Write as a single fraction:

Find common denominator and write the numerators above common denominator: -b = (3*2)/5 - 1

Calculate the sum or difference: -b = (6 - 5 )/5

Divide both sides of the equation by the coefficient of variable: b = -1/5

Substitute: y = 3x/5 - 1/5

Find the required form: y = 3x/5 - 1/5.

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