find the solution of the differential equation that satisfies the given initial = 2pt, p(1) = 2

Answer: r

=

v

2

a

Step-by-step explanation:

The trigonometric ratios for angle x in the given right triangle are:

[tex]sin(x) = a/c\\\\cos(x) = b/c\\\\tan(x) = a/b[/tex]

To find the trigonometric ratios for angle x in a right triangle with side lengths a, b, and c, we need to use the definitions of the trigonometric functions:

sin(x) = opposite/hypotenuse

cos(x) = adjacent/hypotenuse

tan(x) = opposite/adjacent

In a right triangle, the side lengths are related as follows:

a: opposite side to angle x

b: adjacent side to angle x

c: hypotenuse

Using these lengths, we can find the trigonometric ratios:

sin(x) = a/c

cos(x) = b/c

tan(x) = a/b

Therefore, the trigonometric ratios for angle x in the given right triangle are:

sin(x) = a/c

cos(x) = b/c

tan(x) = a/b

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Answer: 19/36

Step-by-step explanation:

the mass moment of inertia about the x-axis is ixx = (2/7)[tex]mr^{2}[/tex] and about the y-axis is iyy = (1/7)[tex]mr^{2}[/tex] + (2/3)[tex]mh^{2}[/tex]

To find the mass moment of inertia, we consider the solid of revolution as a collection of infinitesimally thin disks or cylinders stacked together along the axis of revolution. Each disk or cylinder has a mass element dm.

For the mass moment of inertia about the x-axis (ixx), we integrate the contribution of each mass element along the axis of revolution:

ixx = ∫ [tex]r^{2}[/tex] dm

Since the solid is homogeneous, dm = ρ dV, where ρ is the density and dV is the volume element. For a solid of revolution, dV = πr^2 dh, where h is the height of the solid.

Substituting the expressions and performing the integration, we get:

ixx = ∫ [tex]r^{2}[/tex] ρπr^2 dh

= ρπ ∫ [tex]r^{4}[/tex] dh

= [tex](1/5)\beta \pi r^{4}[/tex] h

Since the solid is homogeneous, the mass m = [tex]\beta \pi r^{2}[/tex] h. Substituting this in the equation above, we get:

ixx = (1/5)m [tex]r^{2}[/tex]

Similarly, for the mass moment of inertia about the y-axis (iyy), we integrate along the radius r:

iyy = ∫[tex]r^{2}[/tex]  dm

= ∫ [tex]r^{2}[/tex] [tex]\beta \pi r^{2}[/tex] dh

= ρπ ∫ [tex]r^{4}[/tex] dh

= (1/5)[tex]\beta \pi r^{4}[/tex] h

Since the height of the solid is h, substituting [tex]\beta \pi r^{2}[/tex] h = m, we get:

iyy = (1/5)m [tex]r^{2}[/tex] + [tex](2/3)mh^{2}[/tex]

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The equation you provided is:

x² + 4x + 4 + y² - 6y + 9 = 5 + 4 + 9

Simplifying both sides of the equation, we have:

x² + 4x + y² - 6y + 13 = 18

Combining like terms, we get:

x² + 4x + y² - 6y - 5 = 0

This is the simplified form of the equation.

Answer:

Step-by-step explanation:

[tex]\int\limits^a_b {x} \, dx i \lim_{n \to \infty} a_n \\\\\\.......\\..\\\\solving:\\\\x^{2}+y^{2} + 4x-6y = 5[/tex]

Given that the average value of the function f on the interval [2, 6] is 3, the value of the integral ∫2,6 dx is 120.

The average value of a function f on an interval [a, b] is given by the formula:

average value = (1/(b-a)) × ∫[a, b]f(x)dx

In this case, we are given that the average value of f on the interval [2, 6] is 3. Therefore, we have:

3 = (1/(6-2)) × ∫[2, 6]f(x)dx

3 = (1/4) × ∫[2, 6]f(x)dx

To find the value of the integral ∫2, 6dx, we can utilize the relationship between the average value and the integral. We can rewrite the integral as follows:

∫2, 6dx = 5 × ∫2, 6dx

Since the average value of f on the interval [2, 6] is 3, we can substitute this value into the equation:

∫2, 6dx = 5 × ∫2, 6dx

∫2, 6dx = 5 × 9 × ∫[2, 6]dx

∫2, 6dx = 45 × [x] from 2 to 6

∫2, 6dx = 45 × (6 - 2)

∫2, 6dx = 45 × 4

∫2, 6dx = 180

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(a) The probability that a randomly selected package weighs between 48 and 50 grams is 0.5596.

(b) The probability that a randomly selected package weighs more than 51 grams is 0.1587.

(c) we can solve for k using the formula z = (k - μ) / σ: 1.645 = (k - 49.8) / 1.2

What is probability?

Probability is a measure of the likelihood of an event occurring.

a. To find the probability that a randomly selected package weighs between 48 and 50 grams, we need to calculate the area under the normal curve between these two values.

We can standardize the values using the formula z = (x - μ) / σ, where x is the value we are interested in, μ is the mean, and σ is the standard deviation.

For x = 48, z = (48 - 49.8) / 1.2 = -1.5

For x = 50, z = (50 - 49.8) / 1.2 = 0.1667

Using a standard normal distribution table or a calculator, we can find the area under the curve between z = -1.5 and z = 0.1667 to be approximately 0.5596.

Therefore, the probability that a randomly selected package weighs between 48 and 50 grams is 0.5596.

b. To find the probability that a randomly selected package weighs more than 51 grams, we need to calculate the area under the normal curve to the right of 51.

Again, we can standardize using z = (x - μ) / σ, where x = 51, μ = 49.8, and σ = 1.2.

z = (51 - 49.8) / 1.2 = 1

Using a standard normal distribution table or a calculator, we can find the area under the curve to the right of z = 1 to be approximately 0.1587.

Therefore, the probability that a randomly selected package weighs more than 51 grams is 0.1587.

c. To find the value of k for which the probability that a randomly selected package weighs more than k grams is 0.05, we need to find the z-score that corresponds to the area to the right of k being 0.05.

Using a standard normal distribution table or a calculator, we can find that the z-score for an area of 0.05 to the right of it is approximately 1.645.

Therefore, we can solve for k using the formula z = (k - μ) / σ:

1.645 = (k - 49.8) / 1.2

Solving for k, we get:

k = 1.645(1.2) + 49.8 ≈ 51.02

So the value of k for which the probability that a randomly selected package weighs more than k grams is 0.05 is approximately 51.02 grams.

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Answer:

x = 2

Step-by-step explanation:

2x + 15 = 27 - 4x

add 4x to both sides:

2x + 15 + 4x = 27 -4x + 4x

that is 6x + 15 = 27

subtract 15 from both sides:

6x + 15 - 15 = 27 - 15

that is 6x = 12

divide both sides by 6:

x = 2

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathtt{2x + 15 = 27 - 4x }[/tex]

[tex]\mathtt{2x + 15 = -4x + 27}[/tex]

[tex]\large\text{ADD 4x to BOTH SIDES}[/tex]

[tex]\mathtt{2x + 15 - 4x = -4x + 27 + 4x}[/tex]

[tex]\large\text{SIMPLIFY it}[/tex]

[tex]\mathtt{2x + 4x + 15 = 27}[/tex]

[tex]\mathtt{6x + 15 = 27}[/tex]

[tex]\large\text{SUBTRACT 15 to BOTH SIDES}[/tex]

[tex]\mathtt{6x + 15 - 15 = 27 - 15}[/tex]

[tex]\large\text{SIMPLIFY it}[/tex]

[tex]\mathtt{6x = 27 - 15}[/tex]

[tex]\mathtt{6x = 12}[/tex]

[tex]\large\text{DIVIDE 6 to BOTH SIDES}[/tex]

[tex]\mathtt{\dfrac{6x}{6} = \dfrac{12}{6}}[/tex]

[tex]\mathtt{x= \dfrac{12}{6}}[/tex]

[tex]\mathtt{x= 2}[/tex]

[tex]\huge\text{Therefore your answer should be:}\\\\\huge\boxed{\mathtt{x = 2}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Given statement solution is :- The correct inequality that matches the given graph is:

D) 3x − 2y < 7 , because if we plug in the point (1, -2), we get: 3(1) − 2(-2) < 7, which simplifies to 3 + 4 < 7, which is not true.

To determine which inequality matches the given graph, we can analyze the slope and the points that the line passes through.

The given line has a positive slope and passes through the points (-3, -8) and (1, -2) on the negative side of the graph, and (9, 10) and (10, 10) on the positive side of the graph.

Let's check each answer choice:

A) −2x + 3y > 7:

If we plug in the point (-3, -8) into this inequality, we get: −2(-3) + 3(-8) > 7, which simplifies to 6 - 24 > 7, which is false. So, this inequality does not match the graph.

B) 2x + 3y < 7:

If we plug in the point (-3, -8) into this inequality, we get: 2(-3) + 3(-8) < 7, which simplifies to -6 - 24 < 7, which is true. Additionally, if we plug in the point (1, -2), we get: 2(1) + 3(-2) < 7, which simplifies to 2 - 6 < 7, which is also true. Therefore, this inequality matches the graph.

C) −3x + 2y > 7:

If we plug in the point (-3, -8) into this inequality, we get: −3(-3) + 2(-8) > 7, which simplifies to 9 - 16 > 7, which is false. So, this inequality does not match the graph.

D) 3x − 2y < 7:

If we plug in the point (-3, -8) into this inequality, we get: 3(-3) − 2(-8) < 7, which simplifies to -9 + 16 < 7, which is true. Additionally, if we plug in the point (1, -2), we get: 3(1) − 2(-2) < 7, which simplifies to 3 + 4 < 7, which is also true. Therefore, this inequality matches the graph.

After analyzing all the answer choices, we can conclude that the correct inequality that matches the given graph is:

D) 3x − 2y < 7.

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The volume of the orange whose circumference has been given would be = 1117.6cm³

To calculate the volume of the circle, the formula for the circumference of a circle is used to determine the radius of the circle. That is;

Circumference of circle = 2πr

radius = ?

circumference = 49.2 cm

that is ;

49.2 = 2× 3.14 × r

r = 49.2/2×3.14

= 49.2/6.28

= 7.8

Volume of a shere;

= 3/4×πr³

= 3/4×3.14×474.552

= 4470.27984/4

= 1117.6cm³

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The company has 70 employees in human resource department, 240 employees in accounting department and 480 employees in the marketing department.

Assume that the number of employees in the human resources department is x.

Given that the total number of employees in the company is 790.

The number of employees in the accounting department is 30 more than three times the number of employees in the human resources department. Therefore, the number of the employees in the accounting department is 3x+30.

The number of employees in the marketing department is twice the number of employees in the accounting department. Thus, the number of employees in the marketing department is 2(3x+30) = 6x+60.

Sum of the employees in all the three departments is equal to total number of  employees in the company is 790.

x + (3x+30) + (6x+60) = 790.

By combining the like terms gives,

(3x + x + 6x) + (30+60) = 790.

By adding like terms gives,

10x + 90 = 790.

By subtracting [tex]90[/tex] from both sides gives,

10x = 700.

On dividing by [tex]10[/tex] on both sides gives,

x = 70.

To find the number of employees in each department by substituting the value of [tex]x[/tex].

The number of the employees in the human resources department is

x = 70employees.

The number of the employees in the accounting department is

3x+30 = 3(70)+30 = 210+30 = 300employees.

The number of employees in the marketing department is  

6x+60 = 6(70)+60 = 420+60 = 480employees.

Hence, the company has 70 employees in human resource department, 240 employees in accounting department and 480 employees in the marketing department.

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For the linear equations provided by the coordinates in the table;

The first equation of this system is y = -2x.

The second equation of this system is y = x - 3.

The solution to the system is (1, -2).

We have four points (-5,10), (-1,2), (0,0), and (11,-22) for first equation, and four points (-8,-11), (-2,-5), (1,-2), and (7,4) the second equation.

The slope (m) is given by the formula (y2 - y1) / (x2 - x1).

For the first line, we can use the points (-5,10) and (-1,2)

m1 = (2 - 10) / (-1 - (-5)) = -8/4 = -2.

the first equation is y = -2x

the second line, we can use the points (-8,-11) and (-2,-5)

m2 = (-5 - -11) / (-2 - -8) = 6/6 = 1.

the second line has a slope of 1,

the equation should have the form y = x + c.

To find c, we can use one of the points, for instance (-2,-5):

-5 = -2 + c => c = -5 + 2 = -3.

So, the second equation is y = x - 3.

the solution to the system, we need to find where the two lines intersect.

y = -2x

y = x - 3

Setting both equation equally

-2x = x - 3

=> 3x = 3

=> x = 1.

Substituting x = 1 into the first equation

y = -2(1) = -2.

the solution to the system of linear equation would be (1, -2).

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Answer:

total ribbon collected is 147.5 meters.

Step-by-step explanation:

Total students = 50

3/5 are girls

girls = 3/5*50 = 30

boys= 50-30 = 20

length of ribbon brought by girls = 30*2.75 = 82.5

length of ribbon brought by boys = 20*3.25 = 65

total length of ribbon = 82.5+65 = 147.5 metres

Thus, a sample size of 615 is necessary in order to have a 95% confidence interval for the population mean that is within +/- 0.1 of the sample mean, given a normal random variable x with mean 36 and variance 16.

Use the formula for the standard error of the mean:

SE = σ / sqrt(n)

where σ is the standard deviation of the population, which is the square root of the variance (in this case, σ = sqrt(16) = 4), and n is the sample size.

We want to find the sample size n that will give us a 95% confidence interval for the population mean that is within +/- 0.1 of the sample mean. This means we need to find the z-score for a 95% confidence interval, which is 1.96 (from a standard normal distribution table).

So we have:
0.1 = 1.96 * SE
0.1 = 1.96 * (4 / sqrt(n))
0.1 = 7.84 / sqrt(n)
sqrt(n) = 78.4
n = 614.2

Rounding up to the nearest integer, we get a sample size of n = 615.

Therefore, a sample size of 615 is necessary in order to have a 95% confidence interval for the population mean that is within +/- 0.1 of the sample mean, given a normal random variable x with mean 36 and variance 16.

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A median in a right triangle joining the right angle to the hypothenuse has the same length as the segment connecting the midpoints of the legs.

The median equals half the hypotenuse

In triangle ABC where ∠B = 90° BD is median

AD = DC median divides into two equal part

DX ⊥ BC

BX = XC = BC/2

DX = AB/2

By Pythagorean theorem

BD² = DX² + BX²

BD² = BC²/4 + AB²/4

BD² = AC²/4

BD = AC/2

Now in triangles BXD and DXC

DX = DX ( common )

AB║ DX

∠BXD = ∠DXC (as corresponding angles )

BX = XC (corresponding side)

By SAS congruency

ΔBXD ≅ ΔDXC

BD = DC

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The simplified expression is [tex]-9z^32 + 3x^7y^4 / (z^5y^2).[/tex]

To simplify the expression [tex](36z^6^7 - 12x^7y^4) / (-4z^5y^2),[/tex] we can apply the rules of exponents and divide each term in the numerator by the denominator:

[tex](36z^6^7 - 12x^7y^4) / (-4z^5y^2)[/tex]

First, let's simplify the numerator: [tex]36z^6^7 - 12x^7y^4.[/tex]

Using the power of a power rule, we can simplify [tex]z^6^7 to z^(6*7) = z^42[/tex].

Therefore, the numerator becomes: [tex]36z^42 - 12x^7y^4.[/tex]

Now, we can divide each term in the numerator by the denominator:

[tex](36z^42 - 12x^7y^4) / (-4z^5y^2)[/tex]

= [tex]-36z^(42-5) / (4z^5) + 12x^7y^4 / (4z^5y^2)[/tex]

=[tex]-9z^37 / z^5 + 3x^7y^4 / (z^5y^2)[/tex]

Using the quotient rule of exponents, we subtract the exponents when dividing like bases:

= [tex]-9z^(37-5) + 3x^7y^4 / (z^5y^2)[/tex]

= -9z^32 + 3x^7y^4 / (z^5y^2)

Therefore, the simplified expression is [tex]-9z^32 + 3x^7y^4 / (z^5y^2).[/tex]

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Christa sliced the pyramid perpendicular to its base through one edge. The Option A .

A cross section means the view that shows what the inside of something looks like after a cut has been made across it. To determine how Christa sliced the cross section, let's consider the properties of a rectangular pyramid.

The rectangular pyramid has a rectangular base and triangular faces that converge at a single point called the apex. Since Christa sliced the pyramid through one edge perpendicular to its base, the resulting cross section would have the same shape as the base which is a rectangle.

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The volume of the solid bounded below by the circular cone z=1.5√(x^2+y^2) and above by the sphere x^2+y^2+z^2=2.75 is (1/6)π(2.75)^3 - (1/6)π(1.5)^3.

To find the volume, we need to determine the limits of integration. The cone equation suggests that we should integrate over the region defined by z=1.5√(x^2+y^2). The sphere equation defines the upper boundary.

Using spherical coordinates, we have the following limits:

ρ: from 0 to √2.75 (radius of the sphere)

θ: from 0 to 2π (full revolution)

φ: from 0 to π/3 (the cone angle)

The volume element in spherical coordinates is ρ^2sin(φ)dρdθdφ. Substituting the given equations into the volume element, we get (ρ^2sin(φ))(ρ^2sin(φ))dρdθdφ.

Integrating with respect to ρ first, we have ∫[0 to π/3] ∫[0 to 2π] ∫[0 to √2.75] (ρ^4sin^2(φ))dρdθdφ.

Simplifying further, we obtain ∫[0 to π/3] ∫[0 to 2π] (1/5)(√2.75)^5sin^2(φ)dθdφ.

Integrating with respect to θ, we have ∫[0 to π/3] (2π)(1/5)(√2.75)^5sin^2(φ)dφ.

Now integrating with respect to φ, we get (2π)(1/5)(√2.75)^5(φ - (1/2)sin(2φ)) evaluated from 0 to π/3.

Substituting the limits and simplifying, we find the volume of the solid to be (1/6)π(2.75)^3 - (1/6)π(1.5)^3.

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"The given statement is incorrect", consider the case where P(x) is "x is even" and Q(x) is "x is odd". Then, ∀x(P(x) ∨ Q(x)) is clearly true, since every integer is either even or odd. However, neither ∀xP(x) nor ∀xQ(x) is true, since there are even and odd numbers. The conclusion in step 7 is incorrect, and the argument is not valid.

The error in the argument is step 7. It is not valid to conclude that ∀x(P (x) ∨ ∀xQ(x)) is true based on the previous steps.

Step 4 only shows that P(c) is true for a specific value of x (namely, c), and it does not necessarily follow that P(x) is true for all values of x. Similarly, step 6 only shows that Q(c) is true for a specific value of x, and it does not necessarily follow that Q(x) is true for all values of x.

Therefore, the conjunction of ∀xP(x) and ∀xQ(x) is not justified by the previous steps. The original statement, ∀x(P (x) ∨ Q(x)), does not imply that the disjunction of ∀xP(x) and ∀xQ(x)) is true.

In fact, a counter example can be constructed where ∀x(P (x) ∨ Q(x)) is true but ∀xP (x) ∨ ∀xQ(x) is false. For example, suppose P(x) is "x is a dog" and Q(x) is "x is a cat". Then, ∀x(P (x) ∨ Q(x)) is true (since everything is either a dog or a cat), but ∀xP (x) ∨ ∀xQ(x) is false (since there exist animals that are neither dogs nor cats).

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The decision for the main effect of Rows using an alpha of 0.05 would be to REJECT THE NULL HYPOTHESIS.

The decision for the main effect of Columns using an alpha of 0.05 would be to REJECT THE NULL HYPOTHESIS.

The decision for the interaction effect using an alpha of 0.05 would be to FAIL TO REJECT THE NULL HYPOTHESIS

To make a decision about the main effect of Rows, we compare the mean squares (MS) for Rows with the critical F-value at a significance level of 0.05. Since the MS for Rows is 7.632 and the degrees of freedom (df) for Rows is not provided in the table, we cannot directly compare it to the critical F-value. However, if the MS for Rows is significantly larger than the MS within groups, it suggests that the main effect of Rows is significant, leading to the decision to REJECT THE NULL HYPOTHESIS.

Similar to the main effect of Rows, we compare the MS for Columns with the critical F-value at a significance level of 0.05. With an MS of 22.15 and an unspecified df for Columns, we cannot directly compare it to the critical F-value. However, if the MS for Columns is significantly larger than the MS within groups, it indicates a significant main effect of Columns, resulting in the decision to REJECT THE NULL HYPOTHESIS.

To evaluate the interaction effect, we compare the MS for the interaction with the MS within groups. With an MS of 7.884 for the interaction effect, we would compare it to the MS within groups (272.42244). If the MS for the interaction is significantly larger than the MS within groups, it suggests a significant interaction effect, leading to the decision to FAIL TO REJECT THE NULL HYPOTHESIS, indicating that there is evidence of an interaction effect.

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(a) For case a, the 95% confidence interval for β1 is (-48.25, -13.75) and the 90% confidence interval is (-46.37, -15.63).

(b) For case b, the 95% confidence interval for β1 is (-101.15, -28.85) and the 90% confidence interval is (-96.32, -33.68).

(c) For case c, the 95% confidence interval for β1 is (-17.35, 0.15) and the 90% confidence interval is (-15.92, 1.52).

To construct confidence intervals for β1, we need the values of β1, s (standard error of β1), SSxx (sum of squares of x), and n (sample size). The formula for the confidence interval is β1 ± tα/2 × (s / sqrt(SSxx)), where tα/2 is the critical value from the t-distribution for the desired confidence level.

(a) For case a, with β1 = -31, s = -4, SSxx = 35, and n = 10, we calculate the standard error as s / sqrt(SSxx) = -4 / sqrt(35) ≈ -0.676. With a sample size of 10, the critical value for a 95% confidence interval is t0.025,8 = 2.306, and for a 90% confidence interval is t0.05,8 = 1.860. Plugging the values into the formula, we get the 95% confidence interval as -31 ± 2.306 × (-0.676), which gives us (-48.25, -13.75), and the 90% confidence interval as -31 ± 1.860 × (-0.676), which gives us (-46.37, -15.63).

(b) For case b, with β1 = -65, SSE = 1,860, SSxx = 20, and n = 14, we calculate the standard error as sqrt(SSE / (n-2)) / [tex]\sqrt{ SSxx}[/tex]≈ 20.00 / [tex]\sqrt{20}[/tex]≈ 4.472. With a sample size of 14, the critical value for a 95% confidence interval is t0.025,12 = 2.179, and for a 90% confidence interval is t0.05,12 = 1.782. Plugging the values into the formula, we get the 95% confidence interval as -65 ± 2.179 ×4.472, which gives us (-101.15, -28.85), and the 90% confidence interval as -65 ± 1.782 × 4.472, which gives us (-96.32, -33.68).

(c) For case c, with β1 = -8.6, SSE = 135, SSxx = 64, and n = 18, we calculate the standard error as [tex]\sqrt{(SSE / (n-2) }[/tex] / [tex]\sqrt{ SSxx}[/tex] ≈ 135 / [tex]\sqrt{64}[/tex] ≈ 2.813. With a sample size of 18, the critical value for a 95% confidence interval is t

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The solution is: B. the initial number of elk, best describes the coefficient, 1,300.

Here, we have,

An equation is made up of two expressions connected by an equal sign. For example, 2x – 5 = 16 is an equation.

Given,

Biologists are studying elk population in a national park. After their initial count, the scientists observed that the number of elk living in the park is increasing every 4 years.

The approximate number of elk in the park t years after the initial count was taken is shown by this function:

f(t) = 1300 (1.08)^t/4

now, we know that,

the equation of exponential function of any growth of population is:

P(t) = P₀ (r)ˣⁿ

where, P₀ denotes the the initial number.

so, comparing with the given equation we get,

P₀ = 1300

i.e. we have,

the initial number of elk , best describes the coefficient, 1,300.

Therefore, B. the initial number of elk, best describes the coefficient, 1,300.

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The expression as given above: "−c f(x, y) ds = − c f(x, y) ds" seems to be true.

Both expressions, the left-hand side, −c f(x, y) ds and the right-hand side, − c f(x, y) ds:

represent the same mathematical operation. The mathematical equation represented here is obtained by multiplying the function f(x, y) by a constant -c and integrating it with respect to the variable ds. The placement of the constant -c does not affect the result, so the two expressions are equivalent.

Thus, both expressions (right-hand and left-hand sides) are the same. Hence, the statement is true.

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The volume of the cylinder is 164.85 ft³.

We have the dimension of cylinder

Radius = 15/2 =7 .5 ft

Height = 7 ft

Now, the formula for Volume of Cylinder is

= 2πrh

Plugging the value of height and radius we get

Volume of Cylinder is

= 2πrh

= 2 x 3.14 x 7.5/2 x 7

=  3.14 x 7.5 x 7

= 164.85 ft³

Thus, the volume of the cylinder is 164.85 ft³.

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Answer:

[tex][-1,7][/tex]

Step-by-step explanation:

From the figure, we observe that the y-coordinate of the circle's center is [tex]y_{c}=3[/tex] units while its radius is [tex]r=4[/tex] units.

So, the range of the circle is [tex][y_{c}-r, y_{c}+r]=[3-4,3+4]=[-1,7][/tex]

The given differential equation xy'' 2y'-xy=0 can be transformed into a recurrence relation by assuming a solution of the form y=x^r. Substituting this into the equation yields a characteristic equation of r(r-1)+2r-1=0, which simplifies to r^2+r-1=0.

Solving for the roots of this equation gives r=(-1±√5)/2. Therefore, the general solution for the differential equation is y=c1x^((-1+√5)/2)+c2x^((-1-√5)/2).

To find the recurrence relation, we first multiply the equation by x^2 and rearrange to get x^2y''-xy'+(x^2)y=0. Then, we substitute y=x^r into this equation to obtain r(r-1)x^r- rx^r+ x^r = 0. Factoring out x^r and simplifying gives r(r-1)- r + 1 = 0, which can be rewritten as r^2 = r-1.

We can now express r(n) in terms of r(n-1) using the recurrence relation r(n) = r(n-1) + (r(n-1)-1). Letting k=r-1, we can rewrite this recurrence relation as k(n) = k(n-1) + k(n-2). Therefore, the recurrence relation for the differential equation is cz(k+r)(k+r-1) + Ck-1 = 0, where c and C are constants.

In summary, the recurrence relation for the differential equation xy'' 2y'-xy=0 is cz(k+r)(k+r-1) + Ck-1 = 0, which can be derived by substituting y=x^r into the differential equation and solving for the roots of the characteristic equation. The recurrence relation allows us to express the solution to the differential equation in terms of a sequence of constants, which can be determined using initial conditions.

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Aaron sprints 0.45 kilometers, which is equivalent to 450 meters. By repeating this sprint 12 times, he will have sprinted a total distance of 5400 meters by the end of practice.

To find out how many meters Aaron will have sprinted by the end of practice, we need to convert the distance of 0.45 kilometers to meters and then multiply it by the number of times he repeats the sprint.

1 kilometer is equal to 1000 meters. Therefore, 0.45 kilometers can be converted to meters by multiplying it by 1000:

0.45 kilometers * 1000 = 450 meters.

So, each time Aaron sprints, he covers a distance of 450 meters.

To find the total distance he will have sprinted by the end of practice, we multiply the distance covered in each sprint by the number of sprints:

450 meters * 12 = 5400 meters.

Therefore, by the end of practice, Aaron will have sprinted a total distance of 5400 meters.

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The limit can be expressed as the definite integral ∫[tex]2^3[/tex] x cos(x) dx over the interval [2, 3].

To express the given limit as a definite integral, we can first rewrite the expression inside the limit using the definition of a Riemann sum:

n cos(xi) xi δx = Σi=1n cos(xi) xi Δx

where Δx = (3 - 2)/n = 1/n is the width of each subinterval, and xi is the midpoint of the i-th subinterval [xi-1, xi].

We can then express the limit as the definite integral of the function f(x) = x cos(x) over the interval [2, 3]:

lim n→∞ Σi=1n cos(xi) xi Δx = ∫[tex]2^3[/tex] x cos(x) dx

Therefore, the limit can be expressed as the definite integral ∫[tex]2^3[/tex] x cos(x) dx over the interval [2, 3].

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To express the limit as a definite integral on the given interval [2,3], we first need to rewrite the expression using the definition of a Riemann sum. Recall that a Riemann sum is an approximation of the area under a curve using rectangular approximations.

Given the limit:

lim (n→∞) Σ [n * cos(x_i) * x_i * Δx], i=1 to n, with interval [2, 3]

We can express this limit as a definite integral by recognizing that it's a Riemann sum, which represents the sum of the areas of the rectangles under the curve of the function in the given interval. In this case, the function is f(x) = x * cos(x). The limit of the Riemann sum as n approaches infinity converges to the definite integral of the function over the interval [2, 3]. Therefore, we can write:

lim (n→∞) Σ [n * cos(x_i) * x_i * Δx] = ∫[2, 3] x * cos(x) dx

So, the limit can be expressed as the definite integral of the function x * cos(x) on the interval [2, 3].

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