Answer:
[tex]\sigma = 1.8[/tex]
Step-by-step explanation:
Given
[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}[/tex]
Required
The standard deviation
First, calculate the expected value E(x)
[tex]E(x) = \sum x * P(x)[/tex]
So, we have:
[tex]E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5 * 0.2[/tex]
[tex]E(x) = 2.7[/tex]
Next, calculate E(x^2)
[tex]E(x^2) = \sum x^2 * P(x)[/tex]
So, we have:
[tex]E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2 * 0.2[/tex]
[tex]E(x^2) = 10.5[/tex]
The standard deviation is:
[tex]\sigma = \sqrt{E(x^2) - (E(x))^2}[/tex]
[tex]\sigma = \sqrt{10.5 - 2.7^2}[/tex]
[tex]\sigma = \sqrt{10.5 - 7.29}[/tex]
[tex]\sigma = \sqrt{3.21}[/tex]
[tex]\sigma = 1.8[/tex] --- approximated
Please help I’m really stuck this is my last attempt
What is the mode for the set of data?
Ages
Stem Leaves
5 0, 4, 6
6 0, 2, 3, 4, 8, 8, 9
7 0, 2, 3, 4, 4, 4, 8, 9
8 4, 5, 6, 8
5|0 = 50 years old
33
68
4
74
Answer:
I THINK IT IS 74 NOT 4
I HOPE THIS HELPS!!!!!
I really need help please
9514 1404 393
Answer:
60
Step-by-step explanation:
The minimum number required is the least common multiple (LCM) of 15 and 4. The numbers 15 and 4 have no common factors, so their LCM is their product.
15×4 = 60 strands are required
A driver must decide whether to buy a new car for $24,000 or lease the same car over a four-year period. Under the terms of the lease, she can make a down payment
of $3000 and have monthly payments of $150. At the end of the four years, the leased car has a residual value (the amount she pays if she chooses to buy the car at
the end of the lease period) of $11,000. Assume she can sell the new car at the end of the four years at the same residual value. Is it less expensive to buy or
to lease?
Answer:
3000 is the answer this question.
PLEASE HELP! ILL MARK !!
Answer:
c) tan
Step-by-step explanation:
tan = Opposite side / close side
When close side = v and Opposite side = 2,8m
HELP AGAIN sorry
What is the measure of ∠AOB?
The measure of angle ∠AOB is 180°. The correct option from the following is (A).
A turn's angle is quantified using degrees or °. A full turn encompasses 360°. A protractor can be used to determine the size of an angle. The term "acute" refers to an angle smaller than 90°. Obtuse refers to an angle between 90° and 180°. Reflex is an angle larger than 180 degrees. Right angles have an angle of exactly 90 degrees.
A quadrilateral is an enclosed form created by uniting four points, any three of which cannot be collinear. A quadrilateral is a polygon that has four sides, four angles, and four vertices. Let us study more about quadrilaterals' shapes, their characteristics, and the various kinds of quadrilaterals, as well as some examples of quadrilaterals.
For the given quadrilateral, the sum of angles is:
∠A + ∠O + ∠B = ∠AOB
60° + 60° + 60° = 180°
Hence, the correct option is (A).
To learn more about Angle, here:
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change the standard form equation into slope intercept form 13x-7y=23.
Write an equation for staying in Paris, France.
Answer:
[tex]y = 125.00x + 591.00[/tex]
Step-by-step explanation:
Given
See attachment for table
Required
Equation for Paris
From the table, we have:
[tex]flight = 591.00[/tex]
[tex]hotel = 125.00[/tex]
Let the number of nights be x.
So, the equation for the total amount (y) is:
[tex]y = flight + hotel * x[/tex]
[tex]y = 591.00 + 125.00 * x[/tex]
[tex]y = 125.00x + 591.00[/tex]
Classify the following polynomials. Combine any
like terms first.
x^2+3x + 2x - 2x^2
X^3+ 4x - 4x - 4x^2
X^3+2x - X^3- 2x^2+ 3
First simplify all polynomials and rewrite them in descending exponent order.
1. [tex]-x^2+2x[/tex]
2. [tex]x^3-4x^2[/tex]
3. [tex]-2x^2+2x+3[/tex]
Now observe the terms with highest exponents in each expression, in particularly focus on their exponent value,
[tex]-x^2[/tex] with value of 2
[tex]x^3[/tex] with value of 3
[tex]-2x^2[/tex] with value of 2
The value is also known as order of polynomial and it is a way to classify polynomials.
Every order creates a family of polynomials determined by the order (which is always greater than -1)
A polynomial such as (1) and (3) have an orders of 2, which is often called quadratic order and thus the polynomials (1), (3) are classified in the same family of quadratic polynomials, these are polynomials with order of 2.
Polynomial (2) however has an order of 3, which is called cubic order. This polynomial (2) is classified in the family of cubic polynomials.
There are of course many other families, in fact, infinitely many of them because you have order 0, 1, 2, 3, and so on there are precisely [tex]\aleph_0+1[/tex] read as "aleph 0 + 1" (the number of natural numbers + 1 (because 0 is not a natural number)) of polynomial families.
The first few have these fancy names, for example:
order 0 => constant polynomial
order 1 => linear polynomial
order 2 => quadratic polynomial
order 3 => cubic polynomial
order 4 => quartic polynomial
and so on.
Hope this helps!
I NEED HELP FAST!!!!!!
Answer:
6.
Step-by-step explanation:
.
Answer:
[tex]C)\:8[/tex]
8 units tiles must be added
--------------------------------------
~HOPE IT HELPS~
~HAVE A GREAT DAY!!~
What is the explicit formula for the geometric sequence with this recursive
formula?
a =
8
2.-1
(
O A... ----(3)
O B.
11
1
6
• (-4)(n-1)
OC. ,- 1.(-6)(n-1)
=
OD. 2, --5•()
160
Answer:
D)
[tex]an = -6 \times {( \frac{1}{4} )}^{n - 1} [/tex]
Step-by-step explanation:
(See the picture)
The explicit formula is given as [tex]T_n=-6(\frac{1}{4} )^{n-1}[/tex]
Geometric and recursive functionsThe general explicit formula for a geometric sequence is expressed as:
[tex]T_n=ar^{n-1}[/tex]Given the following recursive functions:
[tex]a_1=-6\\ a_n=a_{n-1}\cdot\frac{1}{4} [/tex]
Get the next two terms:
[tex]a_2=a_{1}\cdot\frac{1}{4} \\ a_2=-6\cdot\frac{1}{4} \\ a_2=\frac{-3}{2} [/tex]
For the third term:
[tex]a_3=a_{2}\cdot\frac{1}{4} \\ a_3=\frac{-3}{2} \cdot\frac{1}{4} \\ a_3=\frac{-3}{8} [/tex]
The common ratio for the sequence will be [tex]\frac{1}{4} [/tex]
The explicit formula is given as [tex]T_n=-6(\frac{1}{4} )^{n-1}[/tex]
Learn more on explicit functions here: https://brainly.com/question/10308651
Assume that when blood donors are randomly selected, 45% of them have blood that is Group O (based on data from the Greater New York Blood Program).
1. If the number of blood donors is n = 16 equation, find the probability that the number with Group O blood is equation x = 6.
2. If the number of blood donors is n = 8, find the probability that the number with group O is x = 3.
3. if the number of blood donors is n = 20, find the probability that the number with group O blood is x = 16.
4. if the number of blood donors is n = 11, find the probability that the number with group O blood is x = 9.
Answer:
1. 0.1684 = 16.84%.
2. 0.2568 = 25.68%
3. 0.0013 = 0.13%
4. 0.0126 = 1.26%.
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have blood that is Group O, or they do not. The probability of a person having blood that is Group O is independent of any other person, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
45% of them have blood that is Group O
This means that [tex]p = 0.45[/tex]
Question 1:
This is P(X = 6) when n = 16. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 6) = C_{16,6}.(0.45)^{6}.(0.55)^{10} = 0.1684[/tex]
So 0.1684 = 16.84%.
Question 2:
This is P(X = 3) when n = 8. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{8,3}.(0.45)^{3}.(0.55)^{5} = 0.2568[/tex]
So 0.2568 = 25.68%.
Question 3:
This is P(X = 16) when n = 20. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 16) = C_{20,16}.(0.45)^{16}.(0.55)^{4} = 0.0013[/tex]
So 0.0013 = 0.13%.
Question 4:
This is P(X = 9) when n = 11. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 9) = C_{11,9}.(0.45)^{9}.(0.55)^{2} = 0.0126[/tex]
So 0.0126 = 1.26%.
Can someone please answer these?
Answer:
t>-10
31>k
-4>h
f≥6.8
this is the answer
A surveyor is using indirect measurement to find the height of a cliff. He is 4 feet tall and is standing 32 feet away. How tall is the cliff?
Compute the total cost per year of the following pair of expenses. Then complete the sentence: On an annual basis, the first set of expenses is _______% of the second set of expenses.
Vern buys seven lottery tickets each week at a cost of $3 each and spends $900 per year on his textbooks.
Answer:
So 912$ is 58% of 1584 $
Step-by-step explanation:
If Camillo goes with the better buy, how much will he pay for the 25 loaves of bread that he needs for the gourmet peanut butter and jelly sandwiches? Enter your answer to the nearest cent.
Answer:
$49.5
Step-by-step explanation:
* means multiply
at $1.98 per loaf
25 * 1.98 =
49.5
Answer:
48.75
Step-by-step explanation:
It would be the cheapest option
Find the number of integers n that satisfy n^2 < 100.
Answer:
n=-9,-8,-7
Step-by-step explanation:
n<100
but that is the positive square root
\(-10 n is between the negative and positive square root of 100
thus, n=-9,-8,-7
The solution of the inequality n² < 100 will be less than 10.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.
The inequality is given below.
n² < 100
Simplify the equation, then we have
n² < 100
n² < 10²
n < 10
The solution of the inequality n² < 100 will be less than 10.
More about the inequality link is given below.
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How can you use transformations to graph this function?
Answer:
What function?
Step-by-step explanation:
Suppose that the probability distribution for birth weights is normal with a mean of 120 ounces and a standard deviation of 20 ounces. The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is [ Select ] 68%. The probability that a randomly selected infant has a birth weight between 110 and 130 is [ Select ] 68%.
Answer:
The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is 68%.
The probability that a randomly selected infant has a birth weight between 110 and 130 is 38%.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 120 ounces and a standard deviation of 20 ounces.
This means that [tex]\mu = 120, \sigma = 20[/tex]
The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is
p-value of Z when X = 140 subtracted by the p-value of Z when X = 100.
X = 140
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{140 - 120}{20}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a p-value of 0.84
X = 100
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 120}{20}[/tex]
[tex]Z = -1[/tex]
[tex]Z = -1[/tex] has a p-value of 0.16
0.84 - 0.16 = 0.68
The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is 68%.
The probability that a randomly selected infant has a birth weight between 110 and 130
This is the p-value of Z when X = 130 subtracted by the p-value of Z when X = 110.
X = 130
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{130 - 120}{20}[/tex]
[tex]Z = 0.5[/tex]
[tex]Z = 0.5[/tex] has a p-value of 0.69
X = 110
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{110 - 120}{20}[/tex]
[tex]Z = -0.5[/tex]
[tex]Z = -0.5[/tex] has a p-value of 0.31
0.69 - 0.31 = 0.38 = 38%.
The probability that a randomly selected infant has a birth weight between 110 and 130 is 38%.
Find the area of the figure
Please help :)
9514 1404 393
Answer:
372 m²
Step-by-step explanation:
A vertical line down the center of the figure will divide it into two congruent trapezoids, each with bases 13 and 18, and height 12.
The area of one of them is ...
A = 1/2(b1 +b2)h
So, the area of the two of them together is ...
A = (2)(1/2)(b1 +b2)h = (b1 +b2)h
A = (13 m + 18 m)(12 m) = 372 m²
The life of light bulbs is distributed normally. The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 520 hours. Find the probability of a bulb lasting for at most 528 hours. Round your answer to four decimal places.
Answer:
0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 520 hours.
This means that [tex]\sigma = 15, \mu = 520[/tex]
Find the probability of a bulb lasting for at most 528 hours.
This is the p-value of Z when X = 528. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{528 - 520}{15}[/tex]
[tex]Z = 0.533[/tex]
[tex]Z = 0.533[/tex] has a p-value of 0.7031
0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.
Keith used the following steps to find the inverse of f, but he thinks he made an error.
2. The prices, in dollars per unit, of the three commodities X, Y and Z are x, y and z,
respectively
Person A purchases 4 units of Z and sells 3 units of X and 3 units of Y.
Person B purchases 3 units of Y and sells 2 units of X and 1 unit of Z.
Person C purchases 1 unit of X and sells 4 units of Y and 6 units of Z.
In the process, A, B and C earn $40, $50, and $130, respectively.
a) Find the prices of the commodities X, Y, and Z by solving a system of linear
equations (note that selling the units is positive earning and buying the units is
negative earning).
Answer:
Price of X is $24.81
Price of Y is $3.66
Price of Z is $11.36
Step-by-step explanation:
for person A, we know that earns $40, then we can write the equation:
-4*z + 3*x + 3*y = $40
For person B, we know that earns $50, then:
1*z + 2*x - 3*y = $50
For person C, we know that earns $130, then:
6*z - 1*x + 4*y = $130
Then we have a system of equations:
-4*z + 3*x + 3*y = $40
1*z + 2*x - 3*y = $50
6*z - 1*x + 4*y = $130
To solve the system, we need to isolate one of the variables in one of the equations.
Let's isolate z in the second equation:
z = $50 - 2*x + 3*y
now we can replace this in the other two equations:
-4*z + 3*x + 3*y = $40
6*z - 1*x + 4*y = $130
So we get:
-4*($50 - 2*x + 3*y) + 3*x + 3*y = $40
6*($50 - 2*x + 3*y) - 1*x + 4*y = $130
Now we need to simplify both of these, so we get:
-$200 + 11x - 9y = $40
$350 - 13*x + 28*y = $130
Now again, we need to isolate one of the variables in one of the equations.
Let's isolate x in the first one:
-$200 + 11x - 9y = $40
11x - 9y = $40 + $200 = $240
11x = $240 + 9y
x = ($240 + 9y)/11
Now we can replace this in the other equation:
$350 - 13*x + 28*y = $130
$350 - 13*($240 + 9y)/11 + 28*y = $130
Now we can solve this for y.
- 13*($240 + 9y)/11 + 28*y = $130 - $350 = -$220
-13*$240 - (13/11)*9y + 28y = - $220
y*(28 - (9*13/1) ) = -$220 + (13/11)*$240
y = ( (13/11)*$240 - $220)/(28 - (9*13/1) ) = $3.66
We know that:
x = ($240 + 9y)/11
Replacing the value of y, we get:
x = ($240 + 9*$3.66)/11 = $24.81
And the equation of z is:
z = $50 - 2*x + 3*y = $50 - 2* $24.81 + 3*$3.66 = $11.36
Then:
Price of X is $24.81
Price of Y is $3.66
Price of Z is $11.36
(2x4−7x3−6x2+23x−12)÷(x−4)
Answer:
[tex]\frac{23x-37}{x-4}[/tex]
Step-by-step explanation:
Solve by graphing. Round each answer to the nearest tenth.
6x2 = −19x − 15
a: −2, 1.7
b: −1.7, −1.5
c: −1.5, 1.5
d: −1.5, 1.7
9514 1404 393
Answer:
b: -1.7, -1.5
Step-by-step explanation:
The graph is shown below. We have annotated the x-intercepts for the equivalent equation ...
6x^2 +19x +15 = 0
PLEASE HELP THIS IS MY LAST QUESTIONNNN
- The electric company charges Dalton a monthly service fee of $30 plus $0.15 per kilowatt-hour of electricity used. This month, Dalton's bill is $105.
- How many kilowatt-hours of electricity did Dalton use?
500 kwh
$105 - $30 = $75
$75 / $0.15 = 500
Answer:
$105-$30 service fee, this leaves only the electricity used. $75. now to find how many kilowatt hours used you divide $75/.15=500 answer 500 kilowatt hours.
Step-by-step explanation:
see above
answer plz pix inside plz find both answers
Answer:
pixxer
Step-by-step explanation:
please pick inside please
Answer:
I dont now
Step-by-step explanation:
plz conprendation
Find the prime factorisation of each of the following numbers, leaving your answer in index notation..
(e) 117 800
plzz answer quick
Answer:
3x3x13 and 2 x 2 x 2 x 2 x 2 x 5 x 5
Step-by-step explanation:
What is the domain of the function f(x) =x+1/
X^2-6x+8?
Answer:
The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]
Step-by-step explanation:
We are given the following function:
[tex]f(x) = \frac{x+1}{x^2-6x+8}[/tex]
It's a fraction, so the domain is all the real values except those in which the denominator is 0.
Denominator:
Quadratic equation with [tex]a = 1, b = -6, c = 8[/tex]
Using bhaskara, the denominator is 0 for these following values of x:
[tex]\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4[/tex]
[tex]x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]
[tex]x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]
The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]
Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five events 25% of the time, four events 30% of the time, three events 20% of the time, two events 15% of the time, one event 5% of the time, and no events 5% of the time. Find the probability that Javier volunteers for less than three events each month. P (x < 3) = 2 Find the expected number of events Javier volunteers in a month. 3.6 It is given that x must be below a certain value, which limits the rows to use in the PDF table. What is the sum of the probabilities of those rows?
Answer:
[tex]P(x < 3) = 25\%[/tex]
[tex]E(x) = 3[/tex]
Step-by-step explanation:
The given parameters can be represented as:
[tex]\begin{array}{ccccccc}x & {5} & {4} & {3} & {2} & {1}& {0} & P(x) & {25\%} & {30\%} & {20\%} & {15\%} & {5\%} & {5\%} \ \end{array}[/tex]
Solving (a): P(x < 3)
This is calculated as:
[tex]P(x < 3) = P(x = 0) + P(x = 1) + P(x =2)[/tex] ----- i.e. all probabilities less than 3
So, we have:
[tex]P(x < 3) = 5\% + 5\% + 15\%[/tex]
[tex]P(x < 3) = 25\%[/tex]
Solving (b): Expected number of events
This is calculated as:
[tex]E(x) = \sum x * P(x)[/tex]
So, we have:
[tex]E(x) = 5 * 25\% + 4 * 30\% + 3 * 20\% + 2 * 15\% + 1 * 5\% + 0 * 5\%[/tex]
[tex]E(x) = 125\% + 120\% + 60\% + 30\% + 5\% + 0\%[/tex]
[tex]E(x) = 340\%[/tex]
Express as decimal
[tex]E(x) = 3.40[/tex]
Approximate to the nearest integer
[tex]E(x) = 3[/tex]
Ray is constructing a flower bed
Answer:
41 feet
Step-by-step explanation:
12 +12 + [tex]\sqrt{144+144}[/tex]
Answer:
Perfilar. Comienza por delimitar la forma y dimensión del macizo. ...
Cavar y abonar. ...
Enmarcar y rastrillar. ...
Distribuir y plantar.
Step-by-step explanation: