find the standard form of the equation of the ellipse with the given characteristics and center at the origin.

Answers

Answer 1

An ellipse is a geometric shape that looks like a flattened circle, with two focal points. The standard form of the equation of an ellipse with center at the origin is (x^2/a^2) + (y^2/b^2) = 1, where a and b are the lengths of the major and minor axes, respectively.

To find the standard form of the equation of an ellipse with given characteristics and center at the origin, we first need to identify the values of a and b. The major axis is the longer axis of the ellipse, while the minor axis is the shorter axis. If we know the length of the major and minor axes, we can easily find a and b.

Once we have identified a and b, we can plug them into the standard form equation and simplify it to find the equation of the ellipse. For example, if the length of the major axis is 8 and the length of the minor axis is 6, then a = 4 and b = 3. We can plug these values into the equation (x^2/4^2) + (y^2/3^2) = 1 and simplify it to get the standard form of the equation of the ellipse.

In conclusion, finding the standard form of the equation of an ellipse with given characteristics and center at the origin involves identifying the values of a and b, and then plugging them into the standard form equation and simplifying it.

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Related Questions

If H is the circumcenter of triangle BCD find each measure

Answers

We have found the measures of CD, CE, HD, GD, HG, and HF in triangle BCD, given that H is the circumcenter of the triangle.

In triangle BCD, the circumcenter H is the point where the perpendicular bisectors of the sides of the triangle intersect. This point is equidistant from the three vertices of the triangle.

Using the properties of the circumcenter, we can find the measures of various sides and angles of the triangle:

CD = 2FD, where FD is the foot of the perpendicular from H to CD.

CE = BE = 26, since H is equidistant from B and C.

HD = HC = 33, since H is equidistant from D and C.

GD = 1/2BD = 1/2(58) = 29, since H is equidistant from B and D.

HG = √HD² - GD² = √33² - 29² = 2√62 ≈ 15.75, using the Pythagorean theorem.

HF = √HD² - FD² = √33² - 32² = √65 ≈ 8.06, using the Pythagorean theorem.

Therefore, we have found the measures of CD, CE, HD, GD, HG, and HF in triangle BCD, given that H is the circumcenter of the triangle.

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Consider the curve defined by x2 - y2 – 5xy = 25. A. Show that dy – 2x–5y dx 5x+2y b. Find the slope of the line tangent to the curve at each point on the curve when x = 2. C. Find the positive value of x at which the curve has a vertical tangent line. Show the work that leads to your answer. D. Let x and y be functions of time t that are related by the equation x2 - y2 – 5xy = 25. At time t = 3, the value of x is 5, the value of y is 0, and the value of sy is –2. Find the value of at at time t = 3

Answers

A.Hence proved dy/dx = (2x - 5y)/(5x + 2y). B. The slope of the tangent line at any point on the curve when x=2 is given by (4-5y)/(10+2y). C. The curve has a vertical tangent line at x = 5/√29. D. The x-axis is increasing at a rate of 60 square units per unit time at time t=3. D. The value of da/dt at time t=3 is 60.

A. To show that dy/dx = (2x-5y)/(5x+2y), we differentiate the given equation with respect to x using implicit differentiation:

2x - 2y(dy/dx) - 5y - 5x(dy/dx) = 0. Simplifying and solving for dy/dx, we get:

dy/dx = (2x - 5y)/(5x + 2y)

B. To find the slope of the line tangent to the curve at each point when x=2, we substitute x=2 into the expression we derived in part A:

dy/dx = (2(2) - 5y)/(5(2) + 2y) = (4-5y)/(10+2y)

C. To find the positive value of x at which the curve has a vertical tangent line, we need to find where the slope dy/dx becomes infinite. This occurs when the denominator of dy/dx equals zero, which is when: 5x + 2y = 0

Solving for y in terms of x, we get:

y = (-5/2)x

Substituting this into the equation for the curve, we get:

[tex]x^2 - (-5/2)x^2 - 5x(-5/2)x = 25[/tex]

Simplifying and solving for x, we get:

[tex]x = 5/√29[/tex]

or

[tex]x = -5/√29[/tex]

D. To find the value of da/dt at time t=3, we first use the chain rule to get:

2x(dx/dt) - 2y(dy/dt) - 5y(dx/dt) - 5x(dy/dt) = 0. We are given that x=5, y=0, and dy/dt=-2 when t=3. Substituting these values into the equation above and solving for dx/dt, we get:

dx/dt = (5dy/dt)/(2x-5y) = -10/25 = -2/5 Substituting these values into the expression for da/dt, we get:

[tex]da/dt = 2(5)^2 - 2(0)^2 - 5(0)(-2/5) - 5(5)(-2) = 60[/tex]

So the value of da/dt at time t=3 is 60. This means that the area enclosed by the curve.

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I don't understand this problem

Answers

Answer:

1. a

2. a

3. b

Step-by-step explanation:

Q1. The equation is 3x+6=30. b c d are all good answers so it has to be a. If you want more details on why a is wrong, if you expand it becomes 3x+18=30 which is wrong

Q2. This one is 4(x+6) = 40 because you have x+6 4 times and it tells you the total is 40. So the one that matches is a.

Q3.

You have 6 plus 4 x which makes a total of 40.

So 6 + 4x = 40. The equation that matches is b.

Hmu if you need more explanation

Find the length of the diagonal AC in the rectangle below.

Answers

Answer: 26

Step-by-step explanation:

So what its basically asking is for you to find the hypotenuse because you can see that the rectangle splits in half with the green line.

So to find the hypotenuse you would use these steps:

1. formula for hypotenuse  

[tex]\sqrt{a^2+b^2}[/tex]

2. plug in numbers

[tex]\sqrt{10^2+24^2}=26[/tex]

A student in eight grade notices that the current cost of tuition, books, and fees at a 4 year college is $15,000 per year. The family reads that there is an annual increase of $750 per year.

What will the the total cost of tuition, books, and fees for this student when this student attends college for four years, after graduating high school?

Answers

The total cost of tuition, books, and fees for this student when attending college for four years will be $64651

Assuming that the annual increase of $750 per year is compounded each year

we can use the formula for the future value of an annuity to calculate the total cost of tuition, books, and fees for the four years:

[tex]FV = PMT \frac{((1 + r)^n - 1)}{r}[/tex]

In this case, PMT = $15,000, r = 750/15000 = 0.05, and n = 4.

Plugging in these values, we get:

Total cost or FV = $15,000 x ((1 + 0.05)⁴ - 1) / 0.05

FV = $15,000 x(1.2155)-1)/0.05

FV = $15,000 x 0.2155/0.05

FV = $15,000 x4.31

FV = $64651

Hence, the total cost of tuition, books, and fees for this student when attending college for four years will be $64651

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Simplify the following expression. 3x^4+2x^3-5x^2+4x^2+6x-2x-3x^4+7x^5-3x^3

Answers

The simplified form of the expression is [tex]7x^5 - 3x^4 - x^3 - x^2 + 4x.[/tex]

The given expression is a polynomial expression, which can be simplified by combining the like terms. The like terms have the same variable and the same exponent. The given expression can be rearranged and combined as follows:

To simplify the given expression, we need to combine the like terms.

Starting with the x^5 term, we see that there is only one term with [tex]x^5[/tex]which is [tex]7x^5.[/tex]

Moving on to the[tex]x^4[/tex]terms, we have two terms with[tex]x^4,[/tex] namely [tex]3x^4[/tex]and [tex]-3x^4[/tex], which add up to 0. Therefore, we can eliminate the[tex]x^4 t[/tex]erms from the expression.

[tex]7x^5 + 2x^3 - 5x^2 + 4x^2 + 6x - 2x - 3x^4 - 3x^3[/tex]

[tex]= 7x^5 - 3x^4 + 2x^3 - 3x^3 - 5x^2 + 4x^2 + 6x - 2x[/tex] (rearranging the terms)

[tex]= 7x^5 - 3x^4 - x^3 - x^2 + 4x[/tex] (combining the like terms)

Therefore, the simplified form of the expression is [tex]7x^5 - 3x^4 - x^3 - x^2 + 4x.[/tex]

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Previously, 12.1% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 80 workers and finds that 18 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the a= 0.1 level of significance. What are the null and alternative hypotheses?

Answers

The null hypothesis assumes that there is no change in the percentage, while the alternative hypothesis suggests an increase in the proportion of workers with a travel time exceeding 60 minutes.

We have,

The null and alternative hypotheses for testing the economist's belief can be defined as follows:

Null hypothesis (H₀): The percentage of workers with a travel time to work of more than 60 minutes is still 12.1%.

Alternative hypothesis (H₁): The percentage of workers with a travel time to work of more than 60 minutes has increased.

In mathematical notation:

H₀: p = 0.121 (p represents the proportion of workers with a travel time > 60 minutes)

H₁: p > 0.121

Thus,

The null hypothesis assumes that there is no change in the percentage, while the alternative hypothesis suggests an increase in the proportion of workers with a travel time exceeding 60 minutes.

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Suppose x has a distribution with = 30 and = 28.
(a) If a random sample of size n = 31 is drawn, find x, x and P(30 ≤ x ≤ 32). (Round x to two decimal places and the probability to four decimal places.)
x =
x =
P(30 ≤ x ≤ 32) =
(b) If a random sample of size n = 62 is drawn, find x, x and P(30 ≤ x ≤ 32). (Round x to two decimal places and the probability to four decimal places.)
x =
x =
P(30 ≤ x ≤ 32) =
(c) Why should you expect the probability of part (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).)
The standard deviation of part (b) is ---Select--- larger than the same as smaller than part (a) because of the ---Select--- same smaller larger sample size. Therefore, the distribution about x is ---Select--- narrower the same wider .

Answers

a) P(30 ≤ x ≤ 32) = 0.3446.

b) P(30 ≤ x ≤ 32) = 0.2868.

c) The probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).

We have,

(a)

The mean of the distribution is = 30 and the standard deviation is = 28.

For a sample size n = 31, the sample mean x follows a normal distribution with mean = 30 and standard deviation = /√n = 28/√31 = 5.02 (approx.).

Therefore, x ~ N(30, 5.02).

The probability P(30 ≤ x ≤ 32) can be found by standardizing the values using the formula z = (x - ) / , where z is the standard normal variable.

z1 = (30 - 30) / 5.02 = 0

z2 = (32 - 30) / 5.02 = 0.40

P(30 ≤ x ≤ 32) = P(0 ≤ z ≤ 0.40) = 0.3446 (approx.)

Therefore, x = 30, x = 5.02, and P(30 ≤ x ≤ 32) = 0.3446 (approx.).

(b)

For a sample size n = 62, the sample mean x follows a normal distribution with mean = 30 and standard deviation = /√n = 28/√62 = 3.56 (approx.).

Therefore, x ~ N(30, 3.56).

The probability P(30 ≤ x ≤ 32) can be found using the same method as in part (a).

z1 = (30 - 30) / 3.56 = 0

z2 = (32 - 30) / 3.56 = 0.56

P(30 ≤ x ≤ 32) = P(0 ≤ z ≤ 0.56) = 0.2868 (approx.)

Therefore, x = 30, x = 3.56, and P(30 ≤ x ≤ 32) = 0.2868 (approx.).

(c)

The standard deviation of part (b) is smaller than part (a) because of the larger sample size.

Therefore, the distribution about x is narrower in part (b) than in part (a). This means that the sample mean x in part (b) is likely to be closer to the population mean than the sample mean x in part (a).

As a result, the probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).

Thus,

a) P(30 ≤ x ≤ 32) = 0.3446.

b) P(30 ≤ x ≤ 32) = 0.2868.

c) The probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).

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Hello, can someone answer this for me?

Answers

If Amy wants to go to the place that has the highest typical temperature and the least variability, she should visit C. Destin.

Why should she visit Destin?

Destin has one of the highest temperatures as it reaches about 95 degrees. This is the second highest of all the places and so can be one of the places to visit.

Destin has a variability (using range) of :

= 95 - 83

= 12 degrees

Pensacola Beach on the other hand, is:

= 98 - 80

= 18 degrees

Destin has the lower variability.

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Steven cleans his aquarium by replacing 2/3 or the water with new water, but that doesn’t clean the aquarium to his satisfaction. He decides to repeat the process, again replacing 2/3 of the water with new water. How many times will Steven have to do this so that at least 95% of the water is new water?

Help as quickly as possible!!!

Answers

Steven will have to repeat the process three times so that at least 95% of the water is new water

A figure undergoes a translation, reflection, and dilation. Will the image be similar to the original figure? Why or why not?
O A No; a dilation is not a rigid transformation, so the image is not similar to the preimage.
OB. Yes; any number of rigid transformations and dilations will always produce an image similar to the preimage.
OC. No, when more than one transformation is applied, the image is not similar to the preimage.
OD. Yes; since only 3 transformations were applied, the image will be similar to the preimage.

Answers

The image will be similar to the original figure. The correct answer is OB) Yes; any number of rigid transformations and dilations will always produce an image similar to the preimage.

A translation, reflection, and dilation are all examples of rigid transformations, which means that they preserve the shape and size of the figure.

A dilation is also a similarity transformation, which means that it scales the figure uniformly in all directions from a fixed center. The result of applying these three transformations to a figure will be a figure that is similar to the original, but possibly rotated or reflected.

Therefore, the correct option is OB).

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You must study for your test in one of three periods, t = 0, 1, 2. The instantaneous utility cost of studying at t = 0 is 8, at t = 1 is 10, and at t = 2 is 12. You are a naive quasi-hyperbolic discounter with β = 0.75 and δ = 1.
a) In which period will you study? [1 mark]
b) You like to reward yourself with a chocolate cake when you finish study. Your instantaneous utility from eating this cake is equal to 6. Discuss whether binding the unpleasant task to a pleasant task overcome procrastination in this example? [1 mark]
c) After completing this unit you learn about your present bias and become a sophisticated quasi-hyperbolic discounter. Does being sophisticated change the period in which you study? (Assume that there is no cake.)

Answers

Since the utility cost is lowest at t=0, you will conduct your research during period 0 as a quasi-hyperbolic discounter. Procrastination may be beaten if the painful job was linked to an enjoyable task.

a) As a naive quasi-hyperbolic discounter, you must choose the period to study based on your discount factors (β = 0.75, δ = 1) and the utility costs. To determine this, you must compare the present value of the utility costs of studying in each period:

At t = 0: Utility cost = 8 (since you're studying now, no discounting is applied)

At t = 1: Utility cost = 10 x β = 10 x 0.75 = 7.5

At t = 2: Utility cost = 12 x β x δ = 12 x 0.75 x 1 = 9

Since the utility cost is lowest at t=0 (8), you will study during period 0.

b) By binding the unpleasant task (studying) with the pleasant task (eating chocolate cake with utility of 6), it may help overcome procrastination if the combined utility is less than the utility cost of studying in later periods. In this case:

At t = 0: Combined utility cost = 8 - 6 = 2

Since the combined utility cost at t=0 (2) is lower than the utility costs of studying in periods 1 and 2 (7.5 and 9), binding these tasks could help overcome procrastination.

c) As a sophisticated quasi-hyperbolic discounter, you're now aware of your present bias. However, since there is no cake involved, the utility costs remain the same as in part (a):

At t = 0: Utility cost = 8

At t = 1: Utility cost = 7.5

At t = 2: Utility cost = 9

Even though you're now sophisticated, the period in which you study does not change. You will still study during period 0, as it has the lowest utility cost.

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A meteorologist recorded farenheit temperatures in four cities around the world. list these cities in order from coldest to warmest temperature
5 degrees
-6 degrees
-7 degrees
-9 degrees
12 degrees

Answers

The list of the temperature from coldest to warmest temperature includes:

-9 degrees-7 degrees-6 degrees5 degrees12 degrees

What is the order of temperatures in Fahrenheit of the four cities?

The temperatures (Fahrenheit) of the 4 cities from coldest to warmest includes -9 degrees, -7 degrees, -6 degrees, 5 degrees and 12 degrees.

The coldest temperature is -9 degrees, followed by -7 degrees, then -6 degrees. The positive temperature is  5 degrees and 12 degrees.

We must note these temperatures are in Fahrenheit which is not the standard unit of measurement used in all countries, so, we must specify the unit when reporting temperatures.

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ORRELATION
Please complete the following quiz. Use the data set attached. Please upload your Word doc for your submission. Include your SPSS output in this document as part of Step 3.
Test for the significance of the correlation coefficient at the .05 level using a two-tailed test between hours of studying and grade.
Hours of Study Grade
0 80
5 93
8 97
6 100
5 75
3 83
4 98
8 100
6 90
2 78
Sheet 1, Sheet 2, Sheet 3

Answers

We can reject the null hypothesis and conclude that there is a significant correlation between hours of studying and grades at the .05 level.

To test for the significance of the correlation coefficient at the .05 level using a two-tailed test between hours of studying and grade, we can perform a Pearson correlation analysis in SPSS.

Step 1: Open SPSS and import the data set provided.

Step 2: Click on Analyze > Correlate > Bivariate.

Step 3: In the Bivariate Correlations dialog box, select "Hours of Study" and "Grade" as the two variables to be analyzed. Click on Options and select "Two-tailed" under the "Significance" section. Click OK.

Step 4: Click OK again to run the analysis.

The output will provide the Pearson correlation coefficient (r) and the p-value.

In this case, the Pearson correlation coefficient is 0.871, indicating a strong positive correlation between hours of studying and grades. The p-value is 0.002, which is less than the alpha level of 0.05. Therefore, we can reject the null hypothesis and conclude that there is a significant correlation between hours of studying and grades at the .05 level.

In conclusion, the correlation between hours of studying and grades is statistically significant.

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Which graph shows the solution to the inequality shown below?

Answers

The solution to the inequality 15 ≤ 5x + 20 < 35 is -1 ≤ x < 3.

Option C is the correct answer.

We have,

To solve the inequality 15 ≤ 5x + 20 < 35,

We need to isolate the variable x by performing the same operation on all three parts of the inequality.

15 ≤ 5x + 20 < 35

Subtract 20 from all three parts:

-5 ≤ 5x < 15

Divide all three parts by 5:

-1 ≤ x < 3

Therefore,

The solution to the inequality 15 ≤ 5x + 20 < 35 is -1 ≤ x < 3.

This means that any value of x between -1 (inclusive) and 3 (exclusive) will satisfy the inequality

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Which is the area of the rectangle?

A rectangle of length 150 and width 93. Inside the rectangle, there is one segment from one opposite angle of base to the base. The length of that segment is 155.

Answers

The area of the rectangle is 13950.

Can u mark my answer as the Brainlyest if it work Ty

[tex]9x^2 -7 \\-4x^{2} -20x+25[/tex]

Answers

So you would do 9x^2- 4x^2= 5x^2 the 20x would stay the same because nothing else has a single x at the end then you would do -7 + 25= 18 so it would be 5x^2- 20x+18

Show your calculation steps dearly Correct you answer to 4 decimal places and report the measurement unit when applicable. Question 1 (10 marks) A salad shop is selling fruit cups. Each fruit cup consists of two types of fruit, strawberries and blue berries. The weight of strawberries in a fruit cup is normally distributed with mean 160 grams and standard deviation 10 grams. The weight of blue berries in a fruit cup is normally distributed with mean u grams and standard deviation o grams. The weight of strawberries and blue berries are independent, and it is known that the weight of a fruit cup with average of 300 grams and standard deviation of 15 grams. (a) Find the values of u and o (b) The weights of the middle 96.6% of fruit cups are between (300 - K. 300 + K) grams. Find the value of K.
C) The weights of the middle 96.6% of fruit cups are between (L1, L2) grams. Find the values of LI and L2.

Answers

(a) The values of u is 140 g and o is 13.42 g. (b) The value of K in (300 - K. 300 + K) grams is 27.15 g. C) The weights of the middle 96.6% of fruit cups are between (L1, L2) grams. The values of LI is 272.85 g and L2 is 327.15 g.

(a) The mean weight of blueberries is:

300 g - 160 g = 140 g

The standard deviation of the weight is:

Var(X + Y) = Var(X) + Var(Y)

Adding the variances:

15^2 = 10^2 + o^2

Solving for o:

o = sqrt(15^2 - 10^2) = 13.42 g

Therefore, the values of u and o are u = 140 g and o = 13.42 g.

(b) Since the distribution is normal, we can use the standard normal distribution to find K.

The middle 96.6% of a standard normal distribution corresponds to the interval (-1.81, 1.81) (using a table or calculator). Therefore,

K = 1.81 * 15 = 27.15 g

Therefore, the weights of the middle 96.6% of fruit cups are between 300 - 27.15 = 272.85 g and 300 + 27.15 = 327.15 g.

(c) Using the standard normal distribution to find the corresponding interval on the standard normal scale:

(-1.81, 1.81)

We can then scale this interval to the distribution of the weight of fruit cups by dividing by the standard deviation and multiplying by 15 g:

L1 = 300 + (-1.81) * 15 = 272.85 g

L2 = 300 + 1.81 * 15 = 327.15 g

Therefore, the weights of the middle 96.6% of fruit cups are between 272.85 g and 327.15 g.

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Tammie wants to estimate the number of minutes students spend waiting for the bus each morning. She decides to take a random sample of 12 anonymous students. The results are shown below. Determine the mean of the data set.

Answers

The mean of the data set is 9.33 minutes.

How do we find the mean of the data set?

To find mean of the data set, we will add all the values and divide by the total number of values.

In this case, the sum of the values is:

= 0 + 2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22

= 112

There are 12 values in the data set, so the mean is:

= Sum of values / Total number of values

= 112 / 12

= 9.3333

= 9.33 minutes.

Therefore, the mean of the data set is 9.33 minutes.

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Translate the quotient of x and 9 is greater than 27

Answers

The English statement "the quotient of x and 9 is greater than 27" can be represented mathematically as x/9 > 27.

This inequality indicates that the value of x divided by 9 is greater than 27. In other words, x is a number that is more than 27 times 9.

For example, let's say we want to find all the values of x that satisfy this inequality. We can begin by dividing both sides by 9, which gives us:x > 243 So any value of x that is greater than 243 will satisfy the inequality.

For instance, x could be 300 or 500 or any other number larger than 243. Alternatively, we can subtract 27 from both sides to get: x/9 - 27 > 0 This form shows that the difference between x divided by 9 and 27 is positive.

We can then find the range of x that satisfies this inequality by multiplying both sides by 9: x - 243 > 0 This tells us that any value of x that is greater than 243 will satisfy the inequality.

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The average salary of an accountant is $ 71,000 a year. He just finished and his training which will increase his salary by 20%. How much more money he will make in next 10 years as compared to what he was earning without the training?

Answers

Answer:

After 10 years he will make 142 000$ more compared to what was earning without training

A particular fruit's weights are normally distributed, with a mean of 438 grams and a standard deviation of 17 grams. If you pick one fruit at random, what is the probability that it will weigh between 443 grams and 492 grams
_____

Answers

The probability that a fruit picked at random weighs between 443 grams and 492 grams is approximately 0.3695 or 36.95%.

To find the probability that a fruit picked at random weighs between 443 grams and 492 grams, we need to standardize these values using the formula:

z = (x - μ) / σ

where x is the weight of the fruit, μ is the mean weight (438 grams), σ is the standard deviation (17 grams), and z is the standardized score.

For the lower end of the range (443 grams), we have:

z = [tex]\frac{(443 - 438)}{17} = 0.29[/tex]

For the upper end of the range (492 grams), we have:

z = [tex]\frac{(492 - 438)}{17} = 3.18[/tex]

Using a standard normal distribution table or calculator, we can find the probability that a standardized score falls between these values.

The probability of a z-score between 0.29 and 3.18 is approximately 0.3695.

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I'm
curious about why dx/dy becomes -e^-y.
how should I calculate this??

Answers

dx/dy = d/dy(-e^(-y)) = -(-e^(-y)) * 1 = e^(-y). Therefore, dx/dy is equal to e^(-y).

The derivative of a function tells you the rate at which the function is changing with respect to its independent variable. In the case of dx/dy = -e^(-y), x is a function of y, and you're trying to find the derivative of x with respect to y.

To find dx/dy, you need to use the chain rule of differentiation. The chain rule states that if y is a function of t and x is a function of y, then dx/dt = dx/dy * dy/dt.

In this case, you have x as a function of y given by x = -e^(-y). So, you can rewrite dx/dy as d/dy(-e^(-y)).

To differentiate -e^(-y) with respect to y, you can use the chain rule again. The derivative of e^(-y) with respect to y is -e^(-y) (since the derivative of e^u with respect to u is e^u), and then you need to multiply by the derivative of -y with respect to y, which is -1.

So, dx/dy = d/dy(-e^(-y)) = -(-e^(-y)) * 1 = e^(-y). Therefore, dx/dy is equal to e^(-y).

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Participants in a study of a new medication received either medication A or a placebo. Find P(placebo and improvement). You may find it helpful to make a tree diagram of the problem on a separate piece of paper.
Of all those who participated in the study, 70% received medication A.

Of those who received medication A, 56% reported an improvement.

Of those who received the placebo, 52% reported no improvement.

Answers

According to the concept of probability, there is a 48% chance that a participant who received a placebo will report an improvement.

Of those who received medication A, 56% reported an improvement. This means that the probability of a participant receiving medication A and reporting an improvement is 0.56.

On the other hand, of those who received the placebo, 52% reported no improvement. We can use this information to find the probability of a participant receiving a placebo and reporting an improvement.

To do this, we can use the complement rule of probability, which states that the probability of an event happening is equal to 1 minus the probability of the event not happening. In this case, the event we are interested in is a participant receiving a placebo and reporting an improvement. So, the probability of this event happening is equal to 1 minus the probability of a participant receiving a placebo and not reporting an improvement, which is 0.52.

Therefore, the probability of a participant receiving a placebo and reporting an improvement is:

P(placebo and improvement) = 1 - P(placebo and no improvement)

= 1 - 0.52

= 0.48 or 48%.

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Find volume of the solid

Answers

The volume of the cylinder is 803.9 ft².

Given is oblique cylinder, we need to find it volume,

Volume = π × radius² × height

The radius = 8 ft

The height = 4 ft

So,

The volume = 3.14 × 8² × 4

= 803.9 ft²

Hence, the volume of the cylinder is 803.9 ft².

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Find the volume of each rectangular prism from the given parameters.
height: 14; area of the base: 88
best answer get 41 points

Answers

The volume of a rectangular prism is found by multiplying the height by the area of the base.

Since the height is given as 14 and the area of the base is given as 88, we can calculate the volume as follows:

Volume = height * area of the base
Volume = 14 * 88
Volume = 1232

Therefore, the volume of the rectangular prism is 1232 cubic units.

Use the data given in the table below to compute the probability that a randomly chosen voter from the survey will satisfy the following. Round to the nearest hundredth.
The voter is under 50 years old.

Answers

The probability that a randomly chosen voter from the survey  is under 50 years old is 0.75

Computing the probability of randomly chosen a voter

From the question, we have the following parameters that can be used in our computation:

The table of values

Where we have

Voters under 50 years old = 847 + 804 + 773

Total = 3228

So, the required probability is

P = (847 + 804 + 773)/3228

Evaluate

P = 0.75

Hence, the probability is 0.75

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The sum of two numbers is 32 and their difference is 13. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 32. In other words, x plus y equals 32 and can be written as equation A:
x + y = 32
The difference between x and y is 13. In other words, x minus y equals 13 and can be written as equation B:
x - y = 13

Answers

The two numbers are x = 22.5 and y = 9.5. To find the two numbers, x and y, we will solve the given equations (A and B) simultaneously.

Equation A: x + y = 32
Equation B: x - y = 13

Step 1: Add Equation A and Equation B together to eliminate the 'y' variable.
(x + y) + (x - y) = 32 + 13
2x = 45

Step 2: Divide both sides by 2 to isolate 'x'.
2x / 2 = 45 / 2
x = 22.5

Step 3: Substitute the value of 'x' in Equation A to find the value of 'y'.
22.5 + y = 32

Step 4: Subtract 22.5 from both sides to isolate 'y'.
y = 32 - 22.5
y = 9.5

The two numbers are x = 22.5 and y = 9.5.

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A T-shirt stand on the boardwalk recently sold 6 purple shirts and 9 shirts in other colors. What is the experimental probability that the next shirt sold will be purple?
Write your answer as a fraction or whole number.

Answers

The experimental probability that the next shirt sold will be purple is [tex]2/5[/tex].

What is experimental probability on purple shirt?

The experimental probability means ratio of the number of times the event occurs to the total number of trials or observations.

In this case, the event is the sale of a purple shirt and the trials are the total number of shirts sold.

So, total number of shirts sold is:

= 6 purple shirts + 9 other color shirts

= 15 shirts

The number of purple shirts sold is 6.

The experimental probability of selling a purple shirt on the next sale will be:

= Number of purple shirts sold / Total number of shirts sold

= 6 / 15

= 2 / 5.

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A rectangle has a length of 9.6 cm and a width of 6.5 cm. What is the area, in square centimeters, of the rectangle?

Answers

The area of the rectangle is 62.4 square centimeters.

The area of a rectangle is a measure of the amount of space enclosed by the rectangle in two-dimensional (2D) space. It is the product of the length and width of the rectangle, and is usually expressed in square units.

The area of a rectangle will be given by the formula;

Area = Length × Width

where "Length" represents the length of one side of the rectangle, and "Width" represents the length of the other side of the rectangle.

Given that the length of the rectangle is 9.6 cm and the width is 6.5 cm, we can substitute these values into the formula;

Area = 9.6 cm × 6.5 cm

Calculating the area using these values;

Area = 62.4 cm²

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