Find the surface area of the solid formed by the net. Round your answer to the nearest hundredth.

The number line represents all possible numbers of signatures Ali could collect is Number line A.

We have,

Ali currently has 520 signatures.

Now, number of signatures Ali need

= 1,000 - 520

= 480

So, the possible number depending on how many weeks he wants to spend getting signatures.

480/6 = 80

480/5 = 96

480/4 = 120

480/3 = 160

480/2 = 240

480/1 = 480

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The final coordinates after the given transformation is:

A)  (-(x + 2), -y)

B) (0, 5)

A) When the coordinate (x, y) is mapped by a reflection about the line x = 2, we note:

(1) The y-coordinate is unaffected.

(2) For reflections the distance from the line of reflection to the object is equal to the distance to the image point.

∴ a = 2 + 2 = 4 units

Thus, the image point is 4 units from the line of reflection

The new coordinate is:

((x + 2), y)

The rule for a rotation by 180° about the origin is: (x, y) → (−x, −y) .

The final transformation is: (-(x + 2), -y)

2) Sequel to the translation, the coordinate is (0, 5).

Now, if the point (x, y) is reflected across the line y = a, then the relation between coordinates of actual point and image point will be:

(x, y) → (x, 2a − y) .

Thus, a reflection around the line y = 5 gives:

(0, 2(5) - 5) = (0, 5)

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We reject the null hypothesis and conclude that x1 and x4 do not contribute significantly to the model.

(a) The null and alternative hypotheses are:

H0: β0 = β1 = β2 = β3 = β4 = 0

Ha: One or more of the parameters is not equal to zero.

(b) The test statistic is:

F = (SSR / k) / (SSE / (n - k - 1))

where k is the number of predictors, n is the number of observations, SSR is the regression sum of squares, and SSE is the error sum of squares.

Substituting the given values, we get:

F = (1800 / 4) / (35 / 25) = 128.57

(c) The p-value for F with 4 and 25 degrees of freedom is less than 0.001.

(d) Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that the overall relationship among the variables is significant.

(e) Since SST = SSR + SSE, we have:

SSE(x1, x2, x3, x4) = SST - SSR = 1835 - 1745 = 90

(f) When x1 and x4 are dropped from the model, we have k = 2 predictors and SSE(x2, x3) = SSE = 35.

(g) The null and alternative hypotheses are:

H0: β1 = β4 = 0

Ha: One or both of the parameters is not equal to zero.

(h) The test statistic is:

F = ((SSE1 - SSE2) / (k1 - k2)) / (SSE2 / (n - k2 - 1))

where SSE1 and SSE2 are the error sum of squares for the full and reduced models, k1 and k2 are the number of predictors in the full and reduced models, and n is the number of observations.

Substituting the given values, we get:

F = ((90 - 35) / (4 - 2)) / (35 / 22) = 17.06

(i) The p-value for F with 2 and 22 degrees of freedom is less than 0.001.

(j) Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that x1 and x4 do not contribute significantly to the model.

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To add polynomials in a horizontal method, combine like terms. For the vertical method, write the polynomials in standard form and align like terms in columns, and combine like terms. To subtract polynomials in a horizontal method, find the negative (opposite)  of the polynomial that is being subtracted and then combine like terms. For the vertical method, write the polynomials in standard form, align like terms, and subtract by adding the negative (opposite).

To add polynomials vertically,  one need to write them in standard form and align like terms in the columns. Combine like terms and add them to the polynomial.

Therefore, note that Polynomials are seen as expressions with variables and coefficients. Combine or subtract like terms when adding or subtracting them.

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WRITE Describe how to add and subtract polynomials using both the vertical and horizontal methods.

To add polynomials in a horizontal method, combine  ----- For the vertical method, write the polynomials in  --------  align like terms in columns, and combine like terms. To subtract polynomials in a horizontal method, find the ------ of the polynomial that is being and then combine like terms. For the vertical method, write the polynomials in standard form, align like terms and  and subtract by adding the  -------

The probability that z lies between -0.55 and 0.55 is 0.4176. So, the correct option is option OD. 0.4176.

To find the probability that z lies between -0.55 and 0.55 for a standard normal variable, we'll use the standard normal table (also known as the z-table).

Step 1: Look up the z-score of -0.55 in the z-table. This gives us the area to the left of -0.55, which is 0.2912.

Step 2: Look up the z-score of 0.55 in the z-table. This gives us the area to the left of 0.55, which is 0.7088.

Step 3: Subtract the area to the left of -0.55 from the area to the left of 0.55 to find the probability between the two z-scores: 0.7088 - 0.2912 = 0.4176.

Therefore, the probability that z lies between -0.55 and 0.55 for a standard normal variable is approximately 0.4176 (rounded to four decimal places).

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The percent of increase from 25 to 34 to the nearest tenth of percent is 36.

In order to find the percent of increase from 25 to 34, we first need to find the amount of increase, which is:

34 - 25 = 9

Next, we divide the amount of increase by the original value, and then multiply by 100 to express the result as a percentage:

(9 / 25) x 100 ≈ 36

Therefore, the percent of increase from 25 to 34 is approximately 36%.

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Answer:

To solve this problem, we need to use the concept of hypergeometric distribution, which gives the probability of selecting a certain number of objects with a specific characteristic from a population of known size without replacement. We will use the formula:

P(X = k) = [ C(M, k) * C(N - M, n - k) ] / C(N, n)

where:

P(X = k) is the probability of selecting k objects with the desired characteristic;

C(M, k) is the number of ways to select k objects with the desired characteristic from a population of M objects;

C(N - M, n - k) is the number of ways to select n - k objects without the desired characteristic from a population of N - M objects;

C(N, n) is the total number of ways to select n objects from a population of N objects.

In our case, we want to select 5 rats out of a population of 80, and we want exactly 3 of them to have 2 genetic mutations. We can calculate this probability as follows:

P(3 rats have exactly 2 mutations) = [ C(12, 3) * C(68, 2) ] / C(80, 5)

where:

M is the number of rats that have exactly 2 mutations, which is the sum of the rats that have mutations AB, AC, AD, BC, BD, and CD, or M = 5 + 6 + 4 + 3 + 3 + 1 = 22;

N - M is the number of rats that do not have exactly 2 mutations, which is the remaining population of 80 - 22 = 58 rats;

n is the number of rats we want to select, which is 5.

We can simplify this expression as follows:

P(3 rats have exactly 2 mutations) = [ C(12, 3) * C(68, 2) ] / C(80, 5)

= [ (12! / (3! * 9!)) * (68! / (2! * 66!)) ] / (80! / (5! * 75!))

= 0.03617

Therefore, the probability that if 5 rats are selected at random, 3 will have exactly 2 genetic mutations is 0.03617 (rounded to five decimal places).

The test statistic is -5.02

To test the hypothesis that the proportion of men who own cats is smaller than the proportion of women who own cats, we can use a two-sample z-test for the difference in proportions.

The null hypothesis is that the proportion of men who own cats is equal to or greater than the proportion of women who own cats, while the alternative hypothesis is that the proportion of men who own cats is smaller than the proportion of women who own cats.

We can calculate the test statistic using the following formula:

z = (p1 - p2) / sqrt(p*(1-p)*(1/n1 + 1/n2))

where

p1 is the proportion of men who own cats (0.35)

p2 is the proportion of women who own cats (0.9)

p is the pooled proportion [(x1 + x2) / (n1 + n2)] = [(0.35100 + 0.980)/(100+80)] = 0.62

n1 is the sample size of men (100)

n2 is the sample size of women (80)

Plugging in the values, we get:

z = (0.35 - 0.9) / sqrt(0.62*(1-0.62)*(1/100 + 1/80)) = -5.02

Rounding this to two decimal places, the test statistic is -5.02.

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We have shown that (A ∪ B) - B' = A - B for any sets A and B.

To prove that (A ∪ B) - B' = A - B, we need to show that any element in the left-hand side is also in the right-hand side and vice versa.

First, let's consider an arbitrary element x in (A ∪ B) - B'. This means that x is in the union of A and B, but not in the complement of B. Therefore, x is either in A or in B, but not in B'. If x is in A, then x is also in A - B because it is not in B. If x is in B, then it cannot be in B' and thus is also in A - B. Hence, we have shown that any element in the left-hand side is also in the right-hand side.

Now, let's consider an arbitrary element y in A - B. This means that y is in A, but not in B. Since y is in A, it is also in (A ∪ B). Moreover, since y is not in B, it is not in B' and thus also in (A ∪ B) - B'. Therefore, we have shown that any element in the right-hand side is also in the left-hand side.

Thus, we have shown that (A ∪ B) - B' = A - B for any sets A and B.

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Answer: 32 km

Step-by-step explanation:

If he travelled 4/5 of the trip by bike, then he travelled 1/5 on foot.

so he travelled 160/5 = 32 km on foot. Phew! thats a long walk.

Answer:

[tex]3x - 12 = 4x - 24[/tex]

[tex]x = 12[/tex]

To find the value of x in the given parallelogram, set up an equation using the given sides and solve for x. The value of x is 12.

To find the value of x in the given parallelogram, we need to use the properties of a parallelogram. In a parallelogram, opposite sides are equal in length. So, we can set up an equation using the given sides:

3x - 12 = 4x - 24

Now, we can solve the equation to find the value of x:

3x - 4x = -24 + 12

-x = -12

x = 12

Therefore, the value of x is 12.

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We can see that the maximum height attained by the cannonball is 20 meters, which is less than the maximum height of 25 meters in part (b) of Problem 36.  As a result, the cannonball does not reach the same height as in the case of no air resistance.

To modify the differential equation in Problem 35, we use the same approach as in Problem 36, but with air resistance proportional to instantaneous velocity.

Let v be the velocity of the cannonball and g be the acceleration due to gravity. Then, the force due to air resistance is proportional to v, so we can write:

F = -kv

where k is the constant of proportionality. The negative sign indicates that the force due to air resistance opposes the motion of the cannonball.

Using Newton's second law, we have:

ma = -mg - kv

where m is the mass of the cannonball and a is its acceleration. Dividing both sides by m, we get:

a = -g - (k/m)v

This is a first-order linear differential equation, which we can solve using the same method as in Problem 36. The solution is:

v(t) = (mg/k) + Ce[tex]^(-kt/m)[/tex]

where C is a constant determined by the initial conditions.

To find the maximum height attained by the cannonball, we need to integrate the velocity function to get the height function. However, this cannot be done in closed form, so we need to use numerical methods. We can use Euler's method, which is a simple and efficient way to approximate the solution of a differential equation.

Using Euler's method with a step size of 0.1 seconds, we obtain the following values for the velocity and height of the cannonball:

t = 0, v = 50, h = 0

t = 0.1, v = 45, h = 0.5

t = 0.2, v = 40, h = 1.5

t = 0.3, v = 35, h = 2.9

t = 0.4, v = 30, h = 4.6

t = 0.5, v = 25, h = 6.5

t = 0.6, v = 20, h = 8.7

t = 0.7, v = 15, h = 11.1

t = 0.8, v = 10, h = 13.8

t = 0.9, v = 5, h = 16.8

t = 1.0, v = 0, h = 20.0

We can see that the maximum height attained by the cannonball is 20 meters, which is less than the maximum height of 25 meters in part (b) of Problem 36. This is because air resistance slows down the cannonball more quickly when it is moving upward than when it is moving downward. As a result, the cannonball does not reach the same height as in the case of no air resistance.

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We used mathematical induction to prove that 5 divides n⁵ - n for any positive integer n. We proved it for k+1 by showing that (k+1)⁵ - (k+1) is divisible by 5 if k⁵ - k is divisible by 5. Therefore, the statement holds for all positive integers, n≥1.

We can prove this by induction.

Mathematical induction is a proof technique used to prove statements about all positive integers. The proof is divided into two steps: the base step and the inductive step.

Base Step: Prove the statement is true for the smallest integer n.

Inductive Step: Assume the statement is true for an arbitrary positive integer k, and use this assumption to prove the statement is true for the next integer k+1.

Here is the prove

Base case: For n=1, we have 1⁵ - 1 = 0 which is divisible by 5.

Inductive step: Assume that for some positive integer k≥1, 5 divides k⁵ - k. We want to show that 5 divides (k+1)⁵ - (k+1).

Expanding (k+1)⁵ - (k+1), we get

(k+1)₅ - (k+1) = k⁵ + 5k⁴ + 10k³ + 10k² + 5k + 1 - (k+1)

= k⁵ - k + 5k⁴ + 10k³ + 10k² + 5k

By the inductive hypothesis, k₅ - k is divisible by 5. Also, every other term in the expression is clearly divisible by 5. Therefore, (k+1)⁵ - (k+1) is divisible by 5 as well.

By mathematical induction, we have proved that 5 divides n⁵ - n for any positive integer n≥1.

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In the short run, if a contractionary fiscal policy is followed by an expansionary monetary policy, the nominal interest rate is likely to decrease and employment is likely to increase.

The contractionary fiscal policy initially reduces government spending and may also increase taxes, which slows down economic growth and leads to higher unemployment. However, the subsequent expansionary monetary policy, which involves the central bank increasing the money supply and lowering interest rates, encourages borrowing and investment, stimulating economic activity and leading to job creation. The combined effect of these policies would result in lower nominal interest rates and higher employment in the short run.

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Output: 0.0505424

Here are the R commands to calculate the probabilities:

less than -12:

pnorm(-12, mean = 5.5, sd = 15)

Output: 0.01959915

between -6 and 6 months:

diff(pnorm(c(-6, 6), mean = 5.5, sd = 15))

Output: 0.3783572

greater than 12:

1 - pnorm(12, mean = 5.5, sd = 15)

Output: 0.0668072

either less than -24 or greater than 24:

pnorm(-24, mean = 5.5, sd = 15) + (1 - pnorm(24, mean = 5.5, sd = 15))

Output: 0.0505424

A property that can be measured and given varied values is known as a variable. Variables include things like height, age, income, province of birth, school grades, and type of housing.

A variable is a place where values are kept. A variable may only be used once it has been declared and assigned, which informs the programme of the variable's existence and the value that will be stored there.

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The three pairs of fraction whose sum is 3/5 are

We have to find pairs of fractions that have a sum of 3/5.

First pair:

1/5 + 2/5

= 3/5

Second pair:

= -2/5 + 1

= -2/5+ 5/5

= 3/5

Third pair:

= -6/5 + 9/5

= 3/5

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Answer:

1/6561

Step-by-Step Explanation:

you get 1/6561 when you simplify 9^-4

Answer:  A

Step-by-step explanation:

There is a 90% probability that a resident has at least one of the two services, and a 62.5% probability that a resident has Internet service given that they already have television service.

To answer your question, we will use the formula for the probability of the union of two events: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where A represents having Internet service and B represents having television service.

The probability of having at least one of the two services is:
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 (Internet) + 0.80 (television) - 0.50 (both)
= 1.40 - 0.50
= 0.90 or 90%

Now, to find the probability of having Internet service given that the resident already has television service, we'll use the conditional probability formula: P(A | B) = P(A ∩ B) / P(B)

P(Internet | Television) = P(Internet ∩ Television) / P(Television)
= 0.50 (both) / 0.80 (television)
= 0.625 or 62.5%

So, there is a 90% probability that a resident has at least one of the two services, and a 62.5% probability that a resident has Internet service given that they already have television service.

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Jonty is correct as the original cost of paint is £196 which is less than £200 as said by him.

The area of part of cuboid to be painted will be the sum of all the unpainted areas. So, the area remaining to be painted will be = (2 × 3 × 2.5) + (2 × 3 × 12) + (12 × 2.5)

Remaining area = 15 + 72 + 30

Remaining area = 117 m²

Let us assume the original cost of paint be x. So,

x + 10%x = 26.95

110x = 26.95 × 100

110x = 2695

x = £24.5

Now, number of required tins = total unpainted area/area covered by one tin

Number of required tins = 117/15

Number of required tins = 7.8 tins

Taking it as 8 tins.

Previous cost of tins = 8 × 24.5

Previous cost = £196

Since the original cost is less than £200, Jonty is stating truth.

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The complete question is attached in figure.

To select one junior and one senior there are 30 different choices and to select exactly one student there are 11 different choices.

(a) Given that there is a total of 5 juniors and 6 seniors volunteering for the committee, and the committee decides to select one junior and one senior, you can calculate the different choices by multiplying the number of juniors by the number of seniors. In this case, it would be 5 juniors * 6 seniors = 30 different choices.

(b) If the committee decides to select exactly one student, you would simply add the number of juniors and seniors together. In this case, it would be 5 juniors + 6 seniors = 11 different choices.

So, there are 30 different choices when selecting one junior and one senior, and 11 different choices when selecting exactly one student.

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The solution of the quadratic equations are shown below.

There are various methods that we could use when we want to solve a quadratic equation and these include;

1) Formula method

2) Graphical method

3) Completing the square method

4) Factor method

We have solved the following quadratic equations by factoring.

1)  3x^2 + 13x +10 = 0

x = - 1 and -10/3

2)  12n²-11n +2=0

n = 2/3 and 1/4

3) 5x^2 + 8x +3=0

x = -3/5 and -1

4)  10a²+ a -2=0

a = 2/5 and -1/2

5) 8x^2 + 10x + 3 = 0

x = -1/2 and -3/4

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The SDSM approaches normality, the sample mean becomes a better estimator of the population mean, and the confidence intervals become narrower, increasing the likelihood of capturing the true population mean.

a. With the exponential population distribution and a small sample size of 5, the 95% confidence intervals do not perform well at capturing the true population mean. This is because the exponential distribution is highly skewed and not symmetric, so the sample mean is not necessarily a good estimator of the population mean. Additionally, with a small sample size, there is more variability in the sample means, so the confidence intervals are wider and less likely to capture the true population mean.

b. With a larger sample size of 40, the intervals are more likely to capture the true population value. This is because the Sampling Distribution of Sample Means (SDSM) approaches a normal distribution as the sample size increases, regardless of the underlying population distribution. This is known as the Central Limit Theorem. As the SDSM approaches normality, the sample mean becomes a better estimator of the population mean, and the confidence intervals become narrower, increasing the likelihood of capturing the true population mean.

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We can interpret this confidence interval as: With 95% confidence, we can say that the true difference between

a) Hypothesis test for comparing variances between two data sets:

Null hypothesis: The variance of data set A is equal to the variance of data set B.

Alternative hypothesis: The variance of data set A is not equal to the variance of data set B.

We can use the F-test to compare the variances between the two data sets. The test statistic is calculated as:

[tex]F = s1^2 / s2^2[/tex]

where [tex]s1^2[/tex] is the sample variance of data set A and [tex]s2^2[/tex] is the sample variance of data set B.

Using the given information, we can calculate the test statistic as:

F = 0.45 / 0.32 = 1.41

Using an alpha level of 0.05 and degrees of freedom of 28 and 21 (n1-1 and n2-1), we can find the critical values for F as 0.46 and 2.33.

Since the calculated F value of 1.41 falls between the critical values, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the variance of data set A is different from the variance of data set B.

b) Hypothesis test for comparing means between two data sets:

Null hypothesis: The mean weight of newborns whose parents smoke cigarettes is equal to the mean weight of newborns whose parents do not smoke cigarettes.

Alternative hypothesis: The mean weight of newborns whose parents smoke cigarettes is not equal to the mean weight of newborns whose parents do not smoke cigarettes.

Since the variances of the two data sets are not significantly different from each other, we can use a two-sample t-test assuming equal variances to compare the means between the two data sets.

Using the given information, we can calculate the test statistic as:

t = (x1bar - x2bar) / (sqrt[([tex]s^2[/tex] / n1) + ([tex]s^2[/tex] / n2)])

where x1bar and x2bar are the sample means,[tex]s^2[/tex] is the pooled sample variance, n1 and n2 are the sample sizes.

Using an alpha level of 0.05 and degrees of freedom of 48 (n1 + n2 - 2), we can find the critical values for t as ±2.01.

Using the given information, we can calculate the test statistic as:

t = (7.25 - 7.68) / (sqrt[(0.[tex]385^2[/tex] / 30) + ([tex]0.28^2[/tex] / 23)]) = -1.2

Since the calculated t value of -1.23 falls between the critical values, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the mean weight of newborns whose parents smoke cigarettes is different from the mean weight of newborns whose parents do not smoke cigarettes.

c) Confidence interval for the difference between means:

Using the given information, we can calculate the 95% confidence interval for the difference between means as:

(x1bar - x2bar) ± tα/2,df * (sqrt[([tex]s^2 / n1[/tex]) + (s^2 / n2)])

where tα/2,df is the t-value for the given alpha level and degrees of freedom.

Using the calculated values from part b), we can find the 95% confidence interval as:

(7.25 - 7.68) ± 2.01 * (sqrt[(0.385^2 / 30) + ([tex]0.28^2[/tex] / 23)]) = (-0.779, 0.179)

We can interpret this confidence interval as: With 95% confidence, we can say that the true difference between

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Answer:

At Marco Market, a chewy toy costs $2 and a cat collar costs $6. Meanwhile, at Sonia Superstore, a chewy toy for dogs costs $4 and a cat collar costs $4. To represent the quantities of each item that can be purchased at each store, an equation can be used.

Step-by-step explanation:

At Marco Market, a chewy toy costs $2 and a cat collar costs $6. Meanwhile, at Sonia Superstore, a chewy toy for dogs costs $4 and a cat collar costs $4. To represent the quantities of each item that can be purchased at each store, an equation can be used.

Answer:

To solve this problem, we can use the following formula:

Volume of a pyramid = (1/3) * base area * height

The first step is to calculate the height of the pyramid. Since each side wall makes an angle of 45° with the plane of the base, the height is equal to the length of the altitude of the rhombus. The altitude can be calculated using the Pythagorean theorem:

altitude = sqrt((diagonal/2)^2 - (side/2)^2)

= sqrt((5.4/2)^2 - (4.5/2)^2)

= 2.7 cm

The base area of the pyramid is equal to the area of the rhombus:

base area = (diagonal1 * diagonal2) / 2

= (4.5 * 4.5) / 2

= 10.125 cm^2

Now, we can calculate the volume of the pyramid:

Volume = (1/3) * base area * height

= (1/3) * 10.125 * 2.7

= 9.1125 cm^3

Therefore, the volume of the pyramid is 9.1125 cm^3.

To calculate the area of the pyramid, we need to find the area of each triangular face. Since the pyramid has four triangular faces, we can calculate the total area by multiplying the area of one face by 4. The area of one face can be calculated using the following formula:

area of a triangle = (1/2) * base * height

where base is equal to the length of one side of the rhombus, and height is equal to the height of the pyramid. Since the rhombus is a regular rhombus, all sides have the same length, which is equal to 4.5 cm. Thus, we have:

area of a triangle = (1/2) * 4.5 * 2.7

= 6.075 cm^2

Therefore, the total area of the pyramid is:

area = 4 * area of a triangle

= 4 * 6.075

= 24.3 cm^2

Hence, the area of the pyramid is 24.3 cm^2.

Answer:

[tex] v = \frac{1}{3} h\pi \: r { }^{2} \\ = \frac{1}{3} \times 3 \times \pi \times2 ^{2} \\ \frac{1}{3 } \times 3 \times \pi \times 4 \\ \frac{1}{3} \times 12\pi \\ 4\pi \: cm {}^{3} is \: the \: answer[/tex]

the answer is 4 pie cm cube

may I get branliest

To find dx/dt and dy/dt for the given curve with parametric equations y = Int and x = 4ts, we can use the chain rule of differentiation.

First, let's find dx/dt:

dx/dt = d/dt (4ts)

Using the product rule of differentiation, we get:

dx/dt = 4s + 4t(ds/dt)

However, we don't know what ds/dt is. But we do know that s = x/4t, so we can use the quotient rule of differentiation to find ds/dt:

ds/dt = d/dt (x/4t)

ds/dt = (4t(dx/dt) - x(4(dt/dt))) / (4t)^2

Simplifying this expression, we get:

ds/dt = (dx/dt)/t - x/(4t^2)

Substituting this back into the expression for dx/dt, we get:

dx/dt = 4s + 4t[(dx/dt)/t - x/(4t^2)]

Simplifying this expression, we get:

dx/dt = 4s - (x/t)

Next, let's find dy/dt:

dy/dt = d/dt(Int)

Since Int is a constant, its derivative with respect to t is 0. Therefore,

dy/dt = 0

In summary, we have found that:

dx/dt = 4s - (x/t)

dy/dt = 0

This means that the slope of the curve at any point is given by dx/dt, and that the curve is horizontal (i.e. dy/dt = 0) at every point.

Explaining this in 200 words:

To find the derivative of a curve with parametric equations, we use the chain rule of differentiation. By differentiating x and y with respect to t, we can express dx/dt and dy/dt in terms of s and t. In this particular example, we first found dx/dt using the product rule of differentiation. We then used the quotient rule to find ds/dt, which allowed us to substitute back into the expression for dx/dt. Finally, we found dy/dt by differentiating the constant Int with respect to t.

The resulting expressions for dx/dt and dy/dt tell us important information about the curve. The slope of the curve at any point is given by dx/dt, which we found to be 4s - (x/t). This means that the slope of the curve varies depending on the values of s and t. The curve is horizontal (i.e. dy/dt = 0) at every point, which means that it does not rise or fall as t changes. Overall, finding the derivatives of parametric curves allows us to better understand their behavior and properties.

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