find the unknown angles .......... please answer number wise .................................... please help!!!!!!!!!!!!!!!!!!!!!!!!!!!

Find The Unknown Angles .......... Please Answer Number Wise .................................... Please

Answers

Answer 1

Answer:

x=

a.60

b.25

c.45

d.30

e.53

f.is a right angle so 90

g.15

h.is a right angle so 90.we have to divide it so it's 45.equal to both sides.

Step-by-step explanation:

by looking at the angles we know

first one is 180.so simply just subtract from the number given.like that we do..

as you can see H ,there the symbol means both sides are equal so the amount will be same.


Related Questions

a ball is thrown upward with an initial height of 3 feet with an initial upward velocity 37 ft/s the balls heigh in feet after t second is given by h=3=+37t-16t^2

Answers

Answer:

[tex]t = 1.45[/tex] or [tex]t = 0.86[/tex]

Step-by-step explanation:

Given

[tex]h=3+37t-16t^2[/tex]

Required

Find all values of t when height is 23 feet

To solve this, we simply substitute 23 for h

[tex]23=3+37t-16t^2[/tex]

Collect  like terms

[tex]16t^2 - 37t - 3 + 23=0[/tex]

[tex]16t^2 - 37t +20=0[/tex]

Solve t using quadratic formula;

[tex]t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

Where a = 16, b =-37 and c = 20

[tex]t = \frac{-(-37)\±\sqrt{(-37)^2 - 4*16*20}}{2*16}[/tex]

[tex]t = \frac{37\±\sqrt{(-37)^2 - 4*16*20}}{2*16}[/tex]

[tex]t = \frac{37\±\sqrt{1369 - 1280}}{32}[/tex]

[tex]t = \frac{37\±\sqrt{89}}{32}[/tex]

[tex]t = \frac{37\±9.43}{32}[/tex]

[tex]t = \frac{37+9.43}{32}[/tex] or [tex]t = \frac{37-9.43}{32}[/tex]

[tex]t = \frac{46.43}{32}[/tex] or [tex]t = \frac{27.57}{32}[/tex]

[tex]t = \frac{46.43}{32}[/tex] or [tex]t = \frac{27.57}{32}[/tex]

[tex]t = 1.45[/tex] or [tex]t = 0.86[/tex]

PLEASE PLEASE PLEASE HELP ME ANSWER THIS QUESTION QUICK!! The picture of the question is down below. The answer choices are increased or decreased.

Answers

Answer:

NEGATIVE; DECREASED.

Step-by-step explanation:

A correlation coefficient of -0.76 indicates that there is a "fairly" strong negative relationship between the daily temperature and the number of people who visit the store.

This implies that, as the daily temperature increases, number of customers who come to the store decreases.

Therefore, the interpretation of the situation is:

"There is a NEGATIVE association between x and y. As the high temperature of the day increases across days, the number of customers who come to the store DECREASED.

Using the constant of proportionality, determine how much water will be in the bathtub after 2.5 minutes.

Answers

Answer:

[tex]\boxed{41.25}[/tex]

Step-by-step explanation:

Hey there!

Well we know the constant of proportionality is 16.5 because on the table it states 1 minute is 16.5 gallons.

So we can set up the following,

W = 2.5*16.5

W = 41.25

Hope this helps :)

Answer:

The amount of water in the bathtub after 1 minute is 16.5 gallons. So, the amount of water in the tub after 2.5 minutes of filling will be

2.5 minutes × 16.5 gallons per minute = 41.25 gallons.

There will be 41.25 gallons of water in the bathtub after 2.5 minutes.

Step-by-step explanation:

Given the equations, which of the following represents z1 * z2? Using the same values in #6, which of the following represents z1/z2 in standard form?

The selected answers are incorrect.

Answers

Answer:

First Attachment : Option A,

Second Attachment : Option C

Step-by-step explanation:

We are given that,

z₁ = [tex]3(\cos ((\pi )/(6))+i\sin ((\pi )/(6)))[/tex] and z₂ = [tex]4(\cos ((\pi )/(3))+i\sin ((\pi )/(3)))[/tex]

Therefore if we want to determine z₁( z₂ ), we would have to find the trigonometric form of the following expression,

[tex]3(\cos ((\pi )/(6))+i\sin ((\pi )/(6)))*4(\cos ((\pi )/(3))+i\sin ((\pi )/(3)))[/tex]

( Combine expressions )

= [tex]12(\cos ( \pi /6+\pi / 3 ) + i\sin (\pi /6 +\pi / 3 )[/tex]

( Let's now add [tex]\pi / 6 + \pi / 3[/tex], further simplifying this expression )

[tex]\frac{\pi }{6}+\frac{\pi }{3} = \frac{\pi }{6}+\frac{\pi 2}{6} = \frac{\pi +\pi 2}{6} = \frac{3\pi }{6} = \pi / 2[/tex]

( Substitute )

[tex]12(\cos ( \pi /2 ) + i\sin ( \pi /2 ) )[/tex]

And therefore the correct solution would be option a, for the first attachment.

______________________________________________

For this second attachment, we would have to solve for the following expression,

[tex]\frac{3\left(\cos \left(\frac{\pi \:}{6}\right)+i\sin \left(\frac{\pi \:}{6}\right)\right)}{4\left(\cos \left(\frac{\pi \:}{3}\right)+i\sin \left(\frac{\pi \:}{3}\right)\right)}[/tex]

From which we know that cos(π/6) = √3 / 2, sin(π/6) = 1 / 2, cos(π/3) = 1 / 2, and sin(π/3) = √3 / 2. Therefore,

[tex]\:\frac{3\left(\cos \left(\frac{\pi }{6}\right)+i\sin \left(\frac{\pi }{6}\right)\right)}{4\left(\cos \left(\frac{\pi }{3}\right)+i\sin \left(\frac{\pi }{3}\right)\right)}:\quad \frac{3\sqrt{3}}{8}-i\frac{3}{8}[/tex]

[tex]\frac{3\sqrt{3}}{8}-i\frac{3}{8} = \frac{3\sqrt{3}}{8}-\frac{3}{8}i[/tex]

Our solution for the second attachment will be option c.

A cola-dispensing machine is set to dispense 11 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer of the machine would like to set the control limit in such a way that, for samples of 35, 5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.Required:a. At what value should the control limit be set?b. If the population mean shifts to 10.7, what is the probability that the change will be detected?c. If the population mean shifts to 11.7, what is the probability that the change will be detected?

Answers

Answer:

a.  the control limits should be set at (10.72, 11.28)

b. [tex]\mathbf{P(10.72<x<11.28) = 0.4526}[/tex]

c. [tex]\mathbf{P(10.72<x<11.28) = 0.0065}[/tex]

Step-by-step explanation:

Given that:

population mean μ = 11

standard deviation [tex]\sigma[/tex] = 1.0

sample size n = 35

5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.

Therefore, level of significance ∝ = 0.05+0.05 = 0.10

Critical value for [tex]z_{1-\alpha/2} =z_{1-0.10 /2}[/tex]

[tex]\implies z_{1-0.05} = z_{0.95}[/tex]

Using the EXCEL FORMULA: = NORMSINV (0.95)

z = 1.64

The lower control limit and the upper control limit can be determined by using the respective formulas:

Lower control limit = [tex]\mathtt{\mu - z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}[/tex]

Upper control limit = [tex]\mathtt{\mu + z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}[/tex]

For the lower control limit = [tex]11-1.64 \times \dfrac{1.0}{\sqrt{35}}[/tex]

For the lower control limit = [tex]11-0.27721[/tex]

For the lower control limit = 10.72279

For the lower control limit [tex]\simeq[/tex] 10.72

For the upper control limit = [tex]11+1.64 \times \dfrac{1.0}{\sqrt{35}}[/tex]

For the upper control limit = 11 + 0.27721

For the upper control limit = 11.27721

For the upper control limit  [tex]\simeq[/tex]  11.28

Therefore , the control limits should be set at (10.72, 11.28)

b. If the population mean shifts to 10.7, what is the probability that the change will be detected?

i.e

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 10.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 10.7}{\dfrac{1.0}{\sqrt{35}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{0.02}{\dfrac{1.0}{5.916}}<z < \dfrac{0.58}{\dfrac{1.0}{5.916}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(0.1183<z < 3.4313})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(z< 3.4313) - P(z< 0.1183) }[/tex]

Using the EXCEL FORMULA: = NORMSDIST (3.4313) - NORMSDIST (0.118 ); we have:

[tex]\mathbf{P(10.72<x<11.28) = 0.4526}[/tex]

c If the population mean shifts to 11.7, what is the probability that the change will be detected?

i.e

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 11.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 11.7}{\dfrac{1.0}{\sqrt{35}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{-0.98}{\dfrac{1.0}{5.916}}<z < \dfrac{-0.42}{\dfrac{1.0}{5.916}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(-5.7978<z < -2.48472})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(z< -2.48472) - P(z< -5.7978) }[/tex]

Using the EXCEL FORMULA: = NORMSDIST (-2.48472) - NORMSDIST (-5.7978); we have:

[tex]\mathbf{P(10.72<x<11.28) = 0.0065}[/tex]

Please help. I’ll mark you as brainliest if correct!

Answers

Answer:

Children = 150

Students = 98

Adults = 75

Step-by-step explanation:

C + S + A = 323

5C + 7S + 12A = 2336

A = 1/2C

C = 150

S = 98

A = 75

c. What is f (-5)?
When the function is f(x) =-3x+7

Answers

Answer:

f(-5) = 22

Step-by-step explanation:

f(x) =-3x+7

Let x = -5

f(-5) =-3*-5+7

      = 15 +7

       =22

Question 2 (1 point)
Saved
A year ago, Rebecca purchased 100 shares of Havad stock for $20 per share.
Yesterday, she placed a limit order to sell her stock at a price of $33 per share before
the market opened. The stock's price opened at $23 and slowly increased to $26 in
the middle of the day, before declining to $22 by the end of the day. The stock did
not pay any dividends over the period in which Rebecca held it. Given Rebecca's
initial investment of $ 20 per share, her return is

Answers

Answer:

Rebecca does not have a return yet because the stock was not sold since there was a limit order at $33.

However, the value of her investment can be put around $2,400 (100 x $24 average price).

Step-by-step explanation:

Price of Havad Stock bought a year ago = $20

No. of shares = 100

Limit order selling price = $33

Stock prices during the limit order day = $23, $26, and $22

The stock cannot be sold, since its price did not reach $33.

Rebecca's limit order is an order to buy or sell her stock in Havad at $33 or better. Since her order is a sell limit order, it can only be executed at the limit price of $33 or higher.  Unfortunately, the price of the stock did not reach the limit order on that particular day.  This implies that her limit order is not guaranteed to execute.

A survey of 500 randomly selected adults found that 57% say that they would take a ride in a fully self-driving car. The 95% confidence interval for the true proportion of all adults who would take a ride in a full self-driving car is found to be (0.5266, 0.6134). Can we conclude that the majority of all adults would take a ride in a fully self-driving car?

Yes; Since the confidence interval limits are both greater than 50%, we can reasonably conclude that more than half of all adults would take a ride in a fully self-driving car.

No; The data does not include all adults, so we cannot make a conclusion about the population.

No; The confidence interval limits are not large enough to determine that a majority rely only on cellular phones. The proportion would need to be much greater than 50%, and the one above is only slightly larger.

Yes; Since the proportion of adults who said yes is 57%, and this is higher than 50%, we can conclude that a majority would take a ride in a fully self-driving car.

Answers

Answer:

Yes; Since the confidence interval limits are both greater than 50%, we can reasonably conclude that more than half of all adults would take a ride in a fully self-driving car.

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  500

     The sample proportion is  [tex]\r p = 0.57[/tex]

     The  95% confidence interval is (0.5266, 0.6134)

Looking at the 95% confidence level interval we see that the sample proportion is within the interval and given that the confidence interval limits are both greater than 50%, we can reasonably conclude that more than half of all adults would take a ride in a fully self-driving car.

In determining your group’s estimate, what mathematical model of a tennis ball did you use? What model of the classroom did you use? Did you make other simplification or assumptions?

Answers

Answer:

bro ur question is not understandable

The company charges $5 per sq ft, AND has a minimum charge of 3 sq ft per order (meaning if a customer orders something SMALLER than 3 sq ft they still are charged as if they ordered 3 sq ft, never less - but if they order something larger than 3 sq ft they just pay regularly by the sq ft). What would you charge someone who orders a piece of glass 12in X 12in

Using the same sq ft charge ($5 per sq ft) and remembering the rule about when to use the minimum charge, what would you charge someone ordering a piece of glass 48in X 48in? *

Answers

Answer:

12 inches by 12 inches = 15 dollars

48 inches by 48 inches = 80 dollars

Step-by-step explanation:

12 inches = 1 ft

so 12 inch by 12 inches  is 1 ft * 1 ft

1 ft* 1 ft

1 ft^2

This is smaller than 3 ft^2 so they will get charged for 3 ft^2

3 ft^2 = 3 ft^2 * $5 / ft^2 = 15 dollars

48 inches = 48/12 = 4 ft

4ft * 4 ft = 16 ft^2

16 ft^2 = 16 ft^2 * $5 / ft^2 = 80 dollars

What are the polar coordinates of the rectangular coordinates
(V3,-1)?
o (2,5)
O (2,11)
(4, 15)

Answers

Answer:

1)

[tex] \sqrt{( \sqrt{} 3 {}^{2} } + 1 {}^{2} )[/tex]

[tex] \sqrt{4} = 2[/tex]

then the angle,

[tex] \tan( \alpha ) = - 1 \div \sqrt{3} = 330[/tex]

in radians,

[tex]11\pi \div 6[/tex]

hope this helps for the next questions

PLEASE HELP ASAP RN!!!!!!

Answers

Answer:

3sqrt(2)

Step-by-step explanation:

sqrt(32) - sqrt(2)

rewriting sqrt(32)

sqrt(16*2) - sqrt(2)

sqrt(16) * sqrt(2)  - sqrt(2)

4 sqrt(2) - sqrt(2)

3sqrt(2)

Plz answer quick will give good rate and thanksss
h(x) = (x - 3)^2 determine which x-value whether it is in the domain of h or not

In domain not in domain
0
3
4

Answers

Answer:

Hey there!

All of the values: 0, 3, and 4 are in the domain.

This is because h(x) = (x - 3)^2 is a parabola, or a quadratic. By definition, the domain, or the possible x values of a parabola are infinite.

Hope this helps :)

Please help. I’ll mark you as brainliest if correct

Answers

Answer:

32  20  17  -57  13

-24  15  -31  31  -28

27  10  -7  18  22

Step-by-step explanation:

There are $400$ pages in Sheila's favorite book. The average number of words per page in the book is $300$. If she types at an average rate of $40$ words per minute, how many hours will it take to type the $400$ pages of the book?

Answers

Answer:

50hours

Step-by-step explanation:

Given that there are 400 pages in Sheila's favorite book.

The average number of words per page in the book is 300

She types an average rate of 40words per minute.

So to type 400pages of the book

Total number of words in the pages = 400×300 = 120000 words

Typing rate : 40words ------- 1minute

120000 words ----------- x minutes

Hence we have 40 × X mins = 120000 × 1min

Make X the subject

40X = 120000minutes

X = 120000/40

X = 3000minutes

Since 60minutes = 1hour

3000minutes = 3000minutes/60

= 50hours

Hence it took her 50hours to type 400pages

Solution:

The total number of words in the book is 400 x 300. Sheila types at a rate of 40 words per minute, or 40 x 60 words per hour. The number of hours it takes her is equal to the number of words divided by her rate of typing, or 400x300/40x60 = 50 hours.

Fill in the blanks and explain the pattern.
1, 4, 9, 16, 25,__,__,__,__,100


Fill in the blanks and explain the pattern.
1/2, 1/6, 1/18, 1/54,__,__,__

Answers

37, 47 ,57, 67,77

hope this help you

Answer:

1. 36, 49, 64, 81

The pattern is going up by squares.  

2. 1/162, 1/486, 1/1458

The pattern is 1/3n.

Step-by-step explanation:

1. Before the blank spaces started we were at 5^2, or 25.  Now, we have to find 6^2, 7^2, 8^2, and 9^2.  That would be 36, 49, 64, and 81. It goes up by squares.

2. As the pattern continues, each number in the sequence is multiplied by 1/3 create the next number in the sequence.


8.What side of the road will you see speed, yield, and guide signs on ?

Answers

Answer:

we see it in our left side of the road

you will be able to spot these signs on your left hand side :)

Recall the formula V = four-thirds pi r cubed.

Answers

Answer:

1308.33

Step-by-step explanation:

In the pic

Find the length of AB¯¯¯¯¯¯¯¯ A. 19.56 B. 51.86 C. 42.99 D. 34.98

Answers

Answer:

Apllying cos on the triangle

cos(angle)= Base/ Hyp

cos(34)= 29/ AB

AB= 29/0.8290

AB=34.98

Step-by-step explanation:

The length of AB is 34.98 units which the correct answer would be an option (D).

What is the right triangle?

A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.

What are Trigonometric functions?

Trigonometric functions are defined as the functions which show the relationship between the angle and sides of a right-angled triangle.

Given that ΔABC

∠C = 90°

Here base = BC = 29 units and hypotenuse = AB

To determine the length of AB

Apply the cosine on the given right triangle

⇒ cos(θ) = Base/hypotenuse

⇒ cos(34) = 29/ AB

∴ cos(34°) = 0.8290

⇒ 0.8290 = 29/ AB

⇒ AB= 29/0.8290

⇒ AB = 34.98 units

Hence, the length of AB is  34.98 units

Learn more about Trigonometric functions here:

https://brainly.com/question/6904750

#SPJ2

can someone help me please

Answers

Answer:

[tex] {x}^{4} = 2880[/tex]

Step-by-step explanation:

[tex] {y}^{2} = 20 \: (eq . \: 1)[/tex]

[tex] {x}^{2} = {(2 \sqrt{3y)} }^{2} = 12y [/tex]

Putting value of eq. 1 in the following:

[tex] {x}^{4 } = {(12y)}^{2} = 144{y}^{2} = 144 \times 20 = 2880[/tex]


a) which function has the graph with the greatest y intercept?
b) which functions have graphs with slopes less than -3
c) which functions graph is the least steep?​

Answers

Answer:

a =4,b=2, c=3

Step-by-step explanation:

An escalator moves at the rate of 2 feet per second. At what rate does the escalator move in miles per hour? 5280 feet=1 mile

Answers

Answer:

7200ft/per Hour divide it by mile ( 5280) makes 1.363 so maybe 1.4 Miles

Step-by-step explanation:

Answer: Approximately 1.363636 mph

Work Shown:

1 mile = 5280 feet

1 hour = 3600 seconds (since 60*60 = 3600)

[tex]2 \text{ ft per sec} = \frac{2 \text{ ft}}{1 \text{ sec}}\\\\2 \text{ ft per sec} = \frac{2 \text{ ft}}{1 \text{ sec}}*\frac{1 \text{ mi}}{5280 \text{ ft}}*\frac{3600 \text{ sec}}{1 \text{ hr}}\\\\2 \text{ ft per sec} = \frac{2*1*3600}{1*5280*1} \text{ mph}\\\\2 \text{ ft per sec} = \frac{7200}{5280} \text{ mph}\\\\2 \text{ ft per sec} \approx 1.363636 \text{ mph}\\\\[/tex]

The result is approximate and the "36" portion repeats forever.

Help please!! Thank you

Answers

Answer:

D

Step-by-step explanation:

-3, 3, 6, 9, 15, 18, 21,

Just list all the integers in that range, and check each one to see if it matches the requirements. (You can avoid checking every single one if you notice the pattern). Then count how many matches there were.

Matches: [-3, 3, 6, 9, 15, 18, 21]
There are seven matches.
Answer D.

The lines shown below are parallel. If the green line has a slope of -1/2, what is the slope of the red line?



A.
2

B.
-

C.
-2

D.

Answers

Answer:  B) -1/2

Explanation: Parallel lines have the same slopes, but different y intercepts.

Answer:

the slope of the red line is also -1/2

Step-by-step explanation:

A baseball player has a batting average of 0.26. What is the probability that he has exactly 2 hits in his next 7 at bats

Answers

Answer:

The probability is  [tex]P(2) = 0.426[/tex]

Step-by-step explanation:

From the question we are told that

         The probability of  success is [tex]p = 0.26[/tex]

          The number of hits is  n =  7

         

Generally this probability follows a binomial distribution given there can only be two outcome i.e the probability of success and the probability of failure

       The probability of failure is  [tex]q = 1- p[/tex]

substituting values

               [tex]q = 1 - 0.26[/tex]

               [tex]q = 0.74[/tex]

Now the probability of  exactly 2 hits in his next 7 at bats is mathematically evaluated as

     [tex]P(2) = \left n} \atop {}} \right. C_2 *p^{2} * q^{n- 2}[/tex]

substituting values

    [tex]P(2) = \left 7} \atop {}} \right. C_2 *p^{2} * q^{7- 2}[/tex]

Here [tex]\left 7} \atop {}} \right. C_2[/tex] means 7  combination 2 and using a calculator(reference calculator soup website) to compute, the value obtained is  

          [tex]\left 7} \atop {}} \right. C_2 =21[/tex]

So

     [tex]P(2) = 21 *(0.26)^{2} * (0.74)^{5}[/tex]

     [tex]P(2) = 0.426[/tex]

Apply the square root principle to solve (x-5)^2-40=0

Answers

Answer: {5 ± 2√10, 5 - 2√10}

Step-by-step explanation: First isolate the binomial squared by adding 40 to both sides to get (x - 5)² = 40.

Next, square root both sides to get x - 5 = ± √40.

Notice that root of 40 can be broken down to 2√10.

So we have x - 5 = ± 2√10.

To get x by itself, add 5 to both sides to get x = 5 ± 2√10.

So our answer is just {5 ± 2√10, 5 - 2√10}.

As a matter of form, the number will always come before the

radical term in your answer to these types of problems.

In other words, we use 5 ± 2√10 instead of ± 2√10 + 5.

What fraction of a pound is an ounce?

Answers

Answer:

1/16

Step-by-step explanation:

there are 16 ounces in a pound

Answer:

1/16 pounds

Step-by-step explanation:

What is the critical F value when the sample size for the numerator is seven and the sample size for the denominator is six

Answers

Answer:

Critical F value  = 4.9503

Step-by-step explanation:

Given that:

The sample size of the numerator = 7

The sample size of the denominator = 6

The degree of freedom for the numerator df = n -1

The degree of freedom for the numerator df = 7 - 1

The degree of freedom for the numerator df = 6

The degree of freedom for the denominator df = n - 1

The degree of freedom for the denominator df = 6 - 1

The degree of freedom for the denominator df = 5

The assume that the test is two tailed and using a level of significance of ∝ = 0.10

The significance level for the two tailed test = 0.10/2 = 0.05

From the standard normal F table at the level of significance of 0.05

Critical F value  = 4.9503

will rate you brainliest need help

Answers

Answer:

x = 0.09

Step-by-step explanation:

[tex] {3}^{x + 2} = {2}^{3} [/tex]

Taking Logarith both sides, we get :

Using the properties of Logarithms:

[tex](x + 2) log(3) = 3 log(2) [/tex]

[tex](x + 2) = 1.91[/tex]

(taking log2= 0.3 and log3= 0.47)

x = 0.09

Other Questions
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