Find the value of "k" that makes this a true statement:
5x+1
x-2
4x²+kx+9
x2_5+6
1
x+6
x-3
=

g''(x) > 0 and hence the graph is concave up where x belong to zero to infinity and concave down when x belong to negative infinity to zero

How to find the intervals where a function is concave up and concave down?

In determining intervals where a function is concave upward or concave downward, you first find domain values where f″(x) = 0 or f″(x) does not exist. Then test all intervals around these values in the second derivative of the function. If f″(x) changes sign, then ( x, f(x)) is a point of inflection of the function.

g(x) =5x^3+8x

g'(x) = 15x^2+8

g''(x)= 30x

g''(x)= 0

this implies that

g''(x) > 0 and hence the graph is concave up where x belong to zero to infinity

and concave down when x belong to negative infinity to zero

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The probability that X is greater than 39, P (X>39) is 0.03.

A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

Given,

Mean = 33

Variance = 10

Standard deviation = 3.16

Z score,

= x - mean/standard deviation

= 39 - 33/3.16

= 1.89

P value from Z table,

P( x< 39) = 0.9712

P( x > 39) = 1 - P(x <39)

P( x > 39) = 1 - 0.9712

P(x > 39) = 0.0288

The probability that X is greater than 39, P (X>39) is 0.03.

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Precalculus is an example here, since x=−2 is a vertical type line, there is no  y-intercept as well as the slope is undefined.

The slope is undefined and all of the factors on the road have an x-coordinate of that (a few number). For example, if x = -2, then all factors alongside this line can have an x-coordinate of -2, making it a vertical line. y=−2 is a flat line crossing the factor at (0,−2) consequently the gradient is 0 and the the y intercept is -2.

A terrible slope approach that variables are negatively related; that is, whilst x increases, y decreases, and whilst x decreases, y increases. Graphically, a terrible slope approach that as the road on the road graph movements from left to right, the road falls. The x-coordinate -2 is represented throughout. This is NOT a function.

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Tyler was gone for 45 minutes

Answer: 45 minutes

Step-by-step explanation: First, do 60-25 to find how much time there is till 3. (60-25=35) Then, add 10 because he came back at 3:10, not 3:00.

hope this helps!

please give brainliest!

Answer:

[tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]

Step-by-step explanation:

Here m is the slope and b is the y-intercept.

    y = 13x - 4

     m₁ =  13

Product of slope of the Perpendicular line m * m₁ = -1

                [tex]\sf m = \dfrac{-1}{m_1}\\\\m = \dfrac{-1}{13}[/tex]

Equation of the line:

      [tex]\sf y = \dfrac{-1}{13}x+b[/tex]

The point (9,12) passes through the line. Substitute the coordinates in the above equation and find the value of 'b'.

     [tex]\sf 12 = \dfrac{-1}{13}*9+b\\\\[/tex]

[tex]\sf 12 + \dfrac{9}{13}=b\\\\ \dfrac{156}{13}+ \dfrac{9}{13}=b\\\\\boxed{b= \dfrac{165}{13}}[/tex]

Equation of line:

          [tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]

Answer:

the answer is 768

Step-by-step explanation:

because we should first do cross division multiply the denominator with 96 then get the answer

After solving the values of x are 0,-2.

Given:

f(x)=2x+1 and g(x)=x^2 and f(g(x))=g(f(x))

f(x^2) = g(2x+1)

2(x^2) + 1 = (2x+1)^2

2x^2 + 1 = (2x)^2 + 1^2 + 2*2x*1

2x^2 + 1 = 4x^2 + 1 + 4x

4x^2 - 2x^2 + 4x = 1-1

2x^2 + 4x = 0

2x(x+2) = 0

2x = 0 and x+2 = 0

x = 0    and x = -2

Therefore After solving the values of x are 0,-2.

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The roll with a better value, that is, cheap price is 9 packed toilet roll.

In order to determine the roll with a better value, we will consider the unit price of each roll and make comparison.

Unit price refers to the price of a commodity per each unit.

Unit price = Cost / units

= £2.04 / 4

= £0.51 per unit

Unit price = Cost / units

= £4.68 / 9

= £0.52 per unit

Therefore, it can be concluded that the the roll which has a better value is the 9 packed toilet roll.

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Answer:

[tex]\frac{27}{4}[/tex] or [tex]6\frac{3}{4}[/tex]

Step-by-step explanation:

6.75 = [tex]6\frac{3}{4}[/tex] = [tex]\frac{27}{4}[/tex]

Because 0.75 = [tex]\frac{3}{4}[/tex]

I would appreciate it if you mark my answer as brainliest.

Answer:

6 3/4

Step-by-step explanation:

so first 1/4 equals to 0.25

so if 1/4 is 0.25 than 3/4 would be 0.75

6 in this equation represents 24/4

so it would be (24+3)/4

which is 27/4

after simplifying you would get 6 3/4

For provide normal distribution such that

x ~ n(15, 3), 68.27% of the data lie between the values of x as x= 12 to x= 18 .The range of x-values is centered around the mean of the distribution (that is, 15).

Normal Probability:

This problem uses the Z-score formula to calculate the range such that 68.27% of the data falls within the range. Z-scores are normal scores, plotted on a normal curve with mean 0 and variance 1. The Excel function NORM.S.INV() is used to get the score value.

We have given that

Mean, μ = 15

Standard deviation, σ = 3

P( a <X<b) = 0.6827

P( (a − μ)/(σ < X − μ )/σ <(b− μ)σ) = 0.6827

P ( a- 15) /3 < Z < (b- 15)/3) = 0.6827

P( Z< (b-15)/3) - P( Z< ( a - 15)/3) = 0.6827

1 - P( Z > (b-15)/3) - P( Z< ( a - 15)/3) = 0.6827

(Symmetrical Property)

We know that,

P( Z> (b-15)/3) = P( Z< ( a - 15)/3) ( symmetric)

2 × P( Z< ( a - 15)/3) = 0.3173

P( Z< ( a - 15)/3) = 0.15865

Now,

Excel function for the value of z score:

=NORM.S.INV(0.15865)

(a − 15)/3 = -1.00

=> a-15 = -3

=> a = 12 and b = 15 + 3 = 18

Hence, the values of x are 12 and 18 where 68.27% data lie.

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ANOVA is appropriate because the independent variable is categorical and has three classes. The dependent variable is continuous, so ANOVA can be used to determine if there is a significant difference between the means of the three groups.

There are many different types of statistical tests that can be used to analyze data. When choosing a statistical test, it is important to consider the type of data that is being analyzed. In this case, the researcher is looking at an independent variable that is categorical and has three classes. The dependent variable is continuous. In this situation, the best test to use is an analysis of variance (ANOVA).

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Answer: 10 and X and 0

Step-by-step explanation:

The length of the PQ is twice of the Length of the ST .

The length of the line segment connecting two points in a plane is defined as distance between two points. The method for calculating the distance between two points is typically written as

d=√((x_2-x_1)²+(y_2-y_1)²)

This formula is used to calculate the distance between two locations on a coordinate plane or an x-y plane.

from the graph

P(2,4), Q(-4,-6), S (7,2) and T (4, -3)

Find the Length of the PQ = √((x_2-x_1)²+(y_2-y_1)²)

= [tex]\sqrt{ (-4-2)^2 + (-6-4)^2}[/tex]

= [tex]\sqrt{136} =11.66[/tex]

ST = [tex]\sqrt{ (4-7)^2 + (-3-2)^2}[/tex] =[tex]\sqrt{34}[/tex] = 5.83

hence verified

The length of the PQ is twice of the Length of the ST .

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Answer:

There’s no restrictions if I’m not mistaken.

Step-by-step explanation:

You’re correct

By solving a system of two simultaneous linear equation, it can be calculated that

There are 6 1p coin, 8 2p coin, 5 5p coin and 1 10p coins in the pot

What is simultaneous linear equation?

At first it is important to know about linear equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A one degree equation is known as linear equation.

Two or more linear equations, which can be solved together to obtain common solution are known as simultaneous linear equation.

Here a system of two simultaneous linear equation needs to be solved

Let the larger number be x and the smaller number be y

Two times the smaller of two number added with nine time the larger is 215.

9x + 2y = 215 ... (1)

Six time the larger added with seven time the smaller give -89.

6x + 7y = -89

Multiplying (1) by 2

18x + 4y = 430  ..... (3)

Multiplying (2) by 3

18x + 21y = -267 ... (4)

Subtracting (4) from (3)

-17y = 697

y = [tex]-\frac{697}{17}[/tex]

y = -41

Putting the value of y in (1)

9x + 2 [tex]\times[/tex] (-41)  = 215

9x = 215 + 82

9x = 297

x = [tex]\frac{297}{9}[/tex]

x = 33

The two numbers are 33 and -41

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Answer: The zero of a function is the value of y when x equals zero.

Step-by-step explanation: The zero of a function is the value of y when x equals zero. It is also known as an x-intercept. In this case, I believe there is a mistake in this question, as when x equals 0, it shows on the table that it is 6. The zero of the function should be (0,6). They say that the zero is -2, but that is not possible as that would be the y-intercept, where y is zero.

For your homework, I would ask the teacher about the question as it seems to be an error. You can use the response above, since it is correct, but make sure to check with your teacher for review.  

The alternate includes inequality, this is a two-tailed test.

Given:

A sample of 32 observations is selected from a normal population. The sample mean is 66, and the population standard deviation is 5. Conduct the following test of hypothesis using the 0.10 significance level. H0: μ = 68 H1: μ ≠ 68 rev: 10_12_2016_QC_CS-65155 12. value: 1.00 points Required information.

Number of sample observations:

n = 32

Sample mean:

x = 66

Population standard deviation:

σ = 5

Significance level:

α = 0.10

The hypothesis is stated as,

[tex]H_0[/tex] : μ = 68

[tex]H_1[/tex] : μ ≠ 68

Since The alternate includes inequality, this is a two-tailed test.

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1. The preparation of the journal entries for Wildhorse Company is as follows:

Date              Account Titles and Explanation     Debit      Credit

July 1, 2022: Cash                                              $98,000

                     Notes Payable                                              $98,000

Nov. 1, 2022: Cash                                          $101,000

                      Notes Payable                                           $101,000

2. The preparation of the adjusting entries for Wildhorse Company is as follows:

Date                 Account Titles and Explanation     Debit      Credit

Dec. 31, 2022: Interest Expenses                         $3,920

                        Interest Payable                                           $3,920

Dec. 31, 2022: Interest Expense                             $1,010

                        Interest Payable                                           $1,010

3. The preparation of the journal entries for Wildhorse Company is as follows:

Date              Account Titles and Explanation     Debit      Credit

Feb. 1, 2023: Interest Expense                           $505

                      Interest Payable                          $1,010

                     Notes Payable                         $101,000

                     Cash                                                           $102,515

Apr. 1, 2023: Interest Expense                         $1,960

                     Interest Payable                         $3,920

                     Notes Payable                         $98,000

                     Cash                                                        $103,880

Adjusting journal entries are made at the end of the financial period to agree with the accounting records according to the accrual concept of generally accepted accounting principles.

Other journal entries are made to recognize the business transactions in the accounting records as they occur.

July 1, 2022: Cash $98,000 Notes Payable $98,000 (9-month, 8% note)

Nov. 1, 2022: Cash $101,000 Notes Payable $101,000 (3-month, 6%)

Dec. 31, 2022: Interest Expenses $3,920 Interest Payable $3,920

Dec. 31, 2022: Interest Expense $1,010 Interest Payable $1,010.

Feb. 1, 2023: Interest Expense $505 Interest Payable $1,010 Notes Payable $101,000 Cash $102,515

Apr. 1, 2023:Interest Expense $1,960  Interest Payable $3,920 Notes Payable $98,000 Cash $103,880

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The expression which gives a difference of 4 3/12 from the given options is 10 2/3 - 5 1/12 - 1 2/6. option C

The Subtraction of the expressions with different denominators are

The expression with a difference of 4 3/12

Check all that applies:

7 3/4 - 1 2/4 - 2 1/3

= 31/4 - 6/4 - 7/3

= (93-18-28) / 12

= 47/12

= 3 11/12

9 8/12 - 1 3/6 - 4 1/2

= 116/12 - 9/6 - 9/2

= (116-18-54) / 12

= 44/12

= 3 8/12

10 2/3 - 5 1/12 - 1 2/6

= 32/3 - 61/12 - 8/6

= (128-61-16) / 12

= 51/12

= 4 3/12

20 2/12 - 14 1/4 - 2 1/6

= 242/12 - 57/4 - 13/6

= (242-171 - 26) / 12

= 45/12

= 3 9/12

2.

= 23/3 - 19/6 - 20/9

common denominator is 18

= (138 - 57 - 40) / 18

= 41/18

= 2 5/18

= 119/12 - 10/3 - 34/8

common denominator is 24

= (238 - 80 - 102) / 24

= 56/24

= 2 8/24

= 2 1/8

In conclusion, the Subtraction of the mixed number with unlike denominators are:

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The area of triangle (A) is 210 cm².

What is the area of the triangle and perimeter of the triangle?

If a, b, and c are the sides of the triangle, then

Perimeter of the triangle = (a + b + c) units.

Area of the triangle = [tex]\sqrt{(s(s - a) (s - b) (s - c)) }[/tex]

The semi-perimeter of the triangle, s = (a + b + c)/2

Let the triangle is ABC,

and AB = 3x - 1, BC = 4x + 1 and AC = 3x.

       Perimeter = 70

       AB + BC + AC = 70

      3x-1 + 4x + 1 +3x = 70

       10x = 70

          x = 7

AB = a = 3x - 1 = 20

BC = b = 4x + 1 = 29

AC = c = 3x = 21

Now semi-perimeter = s = 70/2

                                     s = 35

      Area of the triangle = [tex]\sqrt{(s(s - a) (s - b) (s - c)) }[/tex] 

                                    [tex]=\sqrt{35(35-20)(35-29)(35-21)}\\\\\\=\sqrt{35(15)(6)(14)}\\\\=\sqrt{44100}\\\\=210[/tex]

        Area of the triangle = 210 square cm.

Hence, the area of triangle (A) is 210 cm².

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The point estimator is 0.0129, the 95% CI on variance ([tex]\sigma^2[/tex]) is (0.0082, 0.0233), the 95% CI on standard deviation (σ) is (0.0905, 0.1527), and it is surprised to hear the director that the standard deviation is more than 0.2 seconds.

n = total data = 30

[tex]\bar x[/tex] = mean or average

[tex]\sigma^2[/tex] = variance

σ = standard deviation

α = significance level = 1 - 95% = 0.05

A) First, calculate unbiased point estimator with this formula

[tex]\sigma^2[/tex] = [tex]\frac{1}{n-1}\times \sum(x_i-\bar x)^2[/tex]

[tex]\sigma^2[/tex] = 0.0129 (detail calculation in excel)

Before we calculate confidence interval, we first find out some of the values needed from the chi-square table.

Lower limit = [tex]X^2_{\alpha /2,n-1}[/tex] = [tex]X^2_{0.025,29}[/tex] = 45.722

Upper limit = [tex]X^2_{1-\alpha /2,n-1}[/tex] = [tex]X^2_{0.975,29}[/tex] = 16.047

B) Next, we calculate confidence interval on variance,

CI on [tex]\sigma^2[/tex] = ( [tex]\frac{(n-1)\times \sigma^2}{X^2_{\alpha /2,n-1}}[/tex], [tex]\frac{(n-1)\times \sigma^2}{X^2_{1-\alpha /2,n-1}}[/tex] )

= ( [tex]\frac{(30-1)\times 0.0129}{45.722}[/tex], [tex]\frac{(30-1)\times 0.0129}{16.047}[/tex] )

= (0.0082, 0.0233)

C) Then, for confidence interval on standard deviation,

CI on σ = [tex]\sqrt{\text{CI on }\sigma^2}[/tex] = ( [tex]\sqrt{\frac{(n-1)\times \sigma^2}{X^2_{\alpha /2,n-1}}}[/tex], [tex]\sqrt{\frac{(n-1)\times \sigma^2}{X^2_{1-\alpha /2,n-1}}}[/tex] )

= ([tex]\sqrt{0.0082}[/tex], [tex]\sqrt{0.0233}[/tex])

= (0.0905, 0.1527)

D) Confidence interval on standard deviation guarantee 95% that standard deviation in response time is between 0.0905 and 0.1527. So, it will be surprised if director claim that the standard deviation in response time is more than 0.2 seconds.

Thus, The point estimator of response time data is 0.0129, and the 95% confidence interval on variance is (0.0082, 0.0233), and the 95% confidence interval on standard deviation is (0.0905, 0.1527), and it's surprised if director said standard deviation is more than 0.2 seconds.

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The scale used but Brenda is 1 inch = 5 feet

A scale is used to give context to the user about the size of the area that map covers. It is made by converting real-life measurements into physical measurements for quick calculations.

Brenda measured the middle school and made a scale drawing.

The actual length of the gym = 90 ft.

The length she used in her drawing = 18 inches.

So we will now find the scale used for this drawing,

18 inches = 90 ft.

therefore, 1 inch = 90/18 ft.

             i.e. 1 inch = 5 ft.

Hence, The scale used but Brenda is 1 inch = 5 feet.

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The integral that is an equivalent iterated integral in three of the five possible other orders is

I= [tex]\int\limits^9_0[/tex]   [tex]\int\limits^{9-z}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex]  f(x, y, z)dzdydx

An integral in mathematics assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that come from merging infinitesimal data. The process of determining integrals is known as integration.

Consider the integral,

I=  [tex]\int\limits^3_0[/tex]   [tex]\int\limits^9_{9-x^{2}}[/tex]  [tex]\int\limits^{9-y}_0[/tex]f(x, y, z)dzdydx

This implies that the solid is bounded by

0≤z≤9-y

9-x²≤y≤9

0≤x≤3

Therefore, y+z=9, z=0

y=9-x², y=9

x=0, x=3

Now, the region is given by,

y=9-x², y=9, x=3, x=0

The shaded region is the required region of the figure region.

For the next integral,

√9-y≤x≤3

0≤y≤9

I= [tex]\int\limits^9_0[/tex]  [tex]\int\limits^3_{\sqrt{9-y}[/tex]  [tex]\int\limits^{9-y}_0[/tex]f(x, y, z)dzdydx

Here we have,

y+z =9, z=0

y=9-x², y=9

x=0, x=3

So, √9-y≤x≤3

The projection on the yz plane is,

y+z=0, z=0

y=9

0≤z≤9-y

0≤y≤9

I= [tex]\int\limits^9_0[/tex]   [tex]\int\limits^{9-y}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex] f(x, y, z)dzdydx

Again, 0≤y≤9-z

0≤z≤9

I= [tex]\int\limits^9_0[/tex]   [tex]\int\limits^{9-z}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex]  f(x, y, z)dzdydx

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Answer:

Below

Step-by-step explanation:

Move it to the other side of the fraction ( make it an inverse to change it to a + exponent)

Examples     5^-2 =   1/ ( 5^2)

      1 / (x^-23)   = x ^23

     x^2 y^-3  = x^2 / y^3           etc

Answer:

8.21%

Step-by-step explanation:

r = (1/t)(A/P - 1)

t = 13

A = 6200

P = 3000

        1          6200

r = (-------) ((------------) - 1))

       13         3000

        1          31

r = (-------) ( ------ - 1)

       13         15

        1          16

r = (-------) ( ------ )

       13         15

       16

r = --------  =  0.0820512

       195

r = 0.0820512 x 100 = 8.20512

r ≈ 8.21%

I hope this helps!

Answer:

Step-by-step explanation:

Compounded Monthly:

Use A=P(1+r/n)^nt

A=6200

P=3000

t=13

n=12

​

Plug in and simplify:

1. Multiply 12 times 13

2. Divide out the 3000

3. Raise both sides to the 1/156 power to cancel out the exponent

4. Subtract 1 from both sides

5. Multiply by 12 on both sides

R should equal 0.0559716

That is about 5.60%

5.60%

The value of diameter for the given triangle inscribed in a circle will be 22.

A circle is a geometrical figure which becomes by plotting a point around a fixed point by keeping a constant distance.

In our daily life, we always see circular objects for example our bike wheel.

The longest line which can be drawn inside the circle will be the diameter.

As per the given triangle inscribed a circle.

The length x +2 and 2x - 7 will be the radius of the circle and the sides of the triangle will be the tangent of the circle.

x + 2 = 2x - 7

2 = 2x - x - 7

x = 9

Thus, radius = 9 + 2 = 11

Diameter = 11 x 2 = 22 units.

Hence "The value of diameter for the given triangle inscribed in a circle will be 22".

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Answer: Understand the context.

Make a plan.

Identify the “who” and “why”

Weigh the pros and cons.

Get a second opinion.

Limit your choices.

Set deadlines.

Evaluate the outcome.

Step-by-step explanation:

The graph that correspond to the inequality is the graph in option D

some interpretation on the information from the question include

With the equation: -2x - 3y < 6. Bearing less than, using the guide above, we lookout for graph that have dotted line and shaded above the line

The quality described makes the 4th graph the correct option

other consideration is the intercept

the first equation at x= 0, -2x - 3y < 6  y < -2  (0, -2)

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The value of x from the given equation is x=(c-b)/2. Therefore, in the given steps, the person has done mistake in step 3.

The given equation is 2x+b=c.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation cab solved as follows

Subtract b from both sides

2x+b-b=c-b

Combine like terms/simplify

2x=c-b

Divide 2 from both sides to get x isolated

x=(c-b)/2

The value of x from the given equation is x=(c-b)/2. Therefore, in the given steps, the person has done mistake in step 3.

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The expression √n^2 can be simplified as n

The square root of a number is that factor of a number which when multiplied by itself gives the original number.

Squares and square roots are special exponents. Consider the number 9. When 3 is multiplied by itself, it gives 9 as the product. This can be written as 3 × 3 or 32. Here, the exponent is 2, and we call it a square. Now when the exponent is 1/2, it refers to the square root of the number. For example, √n = n^½, where n is a positive integer.

Therefore √n^2 = n^½×2= n

the value of √n^2 = 2

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