find the value of x and y that satisfies both the equaties x/y= 2/3 and y/24=3/4

Each sample has an equal chance of being picked as part of the sampling procedure known as random sampling. A randomly selected sample is intended to provide a fair reflection of the entire population.

Step 1: He should identify and decide which population he wants to study

Step 2: He should decide the size of the sample. He can do this using a sample size calculator.

Step 3: Select the Sample Randomly using:

It is to be noted that the lottery and Random Techniques can be manual or computer simulated.

The sample bar graph for the above sample is attached.

40% of 60% is not likely to catalyze a change in the needed change. A more proper percentage should be 90%.

Based on the figures given, 72% of the students agree that the dress code is nice (that is , it requires not change).

This means that it is highly unlikely that any changes will be made to the dress code soon.

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If the vertices of parallelogram ABCD is A(-6,-4),B(0,-4),C(3,4),D(-3,4) ,then the area of parallelogram ABCD will be 48 square units.

Given that the vertices of parallelogram ABCD is A(-6,-4),B(0,-4)

,C(3,4),D(-3,4).

We are required to find the area of parallelogram ABCD.

Let the point of intersection of height of parallelogram from point A is point E.

When we see the graph on which the parallelogram then we will be able to know that point E has coordinates of (-3,-4).

Area of parallelogram=Base*Height

=AB*DE

DE=[tex]\sqrt{(-4-4)^{2} +(-3+3)^{2} }[/tex]

=[tex]\sqrt{64}[/tex]

=8 units

AB=[tex]\sqrt{(-4+4)^{2} +(0+6)^{2} }[/tex]

=[tex]\sqrt{36}[/tex]

=6 units

Area=6*8

=48 square units.

Hence if the vertices of parallelogram ABCD is A(-6,-4),B(0,-4),C(3,4),D(-3,4) ,then the area of parallelogram ABCD will be 48 square units.

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Answer:

= – 5 – 7

Step-by-step explanation:

= –5 – 7

Answer:

"a[b(b + 6) +7(a²-2)]" (the third one)

Step-by-step explanation:

Answer:

9/41

Step-by-step explanation:

Cosine represents adjacent / hypotenuse.

When A is the reference angle, AB is the adjacent side (9) and AC is the hypotenuse (41).

9/41 is already simplified.

Answer:

12:1

Step-by-step explanation:

each pack contains 12 eggs

108/9 = 12

Hope this helps

Using the binomial distribution, there exists a 0.9983 = 99.83% probability that at most eleven of the thirteen babies exists girls.

The formula exists:

[tex]$&P(X=x)=C_{n, x} \cdot p^{x} \cdot(1-p)^{n-x} \\[/tex]

The parameters exists:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

The values of the parameters are: p = 0.5 and n = 13

The probability that at most eleven of the thirteen babies are girls is:

[tex]$P(X \leq 11)=1-P(X > 11)$$[/tex] then

[tex]$P(X > 11)=P(X=12)+P(X=13)$$[/tex]

By using the binomial distribution formula

[tex]$&P(X=x)=C_{n, x} \cdot p^{x} \cdot(1-p)^{n-x} \\[/tex]

substitute the values in the above equation, we get

[tex]$&P(X=12)=C_{13,12} \cdot(0.5)^{12} \cdot(0.5)^{1}=0.0016 \\[/tex]

[tex]$&P(X=13)=C_{13,13} \cdot(0.5)^{13} \cdot(0.5)^{0}=0.0001[/tex]

So, [tex]$&P(X > 11)=P(X=12)+P(X=13)[/tex]

[tex]=0.0016+0.0001=0.0017 \\[/tex]

[tex]$&P(X \leq 11)=1-P(X > 11)[/tex]

[tex]=1-0.0017=0.9983[/tex]

0.9983 = 99.83% probability that at most eleven of the thirteen babies exists girls.

Therefore, the correct answer is option c. 4089/4096

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Answer:

2

Step-by-step explanation:

→ Find 2 points from the line

( 0 , 6 ) and ( - 3 , 0 )

→ Find the change in y coordinates

0 - 6 = -6

→ Find the change in x coordinates

-3 - 0 = -3

→ Divide the 2 results

-6 ÷ -3 = 2

Using it's concept, the approximate perimeter of pentagon ABCDE is given as follows:

34.4 units.

The perimeter of a figure is given by the sum of the lengths of it's outside dimensions.

In this problem, the vertices are in a coordinate-plane, hence the distances are found using the formula for the distance between two points.

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

The length of segment AB is:

[tex]AB = \sqrt{(6 - 0)^2+(0 - 7)^2} = 9.2[/tex]

The length of segment BC is:

[tex]BC = \sqrt{(6 - 3)^2+(0 + 4)^2} = 5[/tex]

The length of segment CD is:

[tex]CD = \sqrt{(-3 -3)^2+(-4 + 4)^2} = 6[/tex]

The length of segment DE is:

[tex]DE = \sqrt{(-6 + 3)^2+(0 + 4)^2} = 5[/tex]

The length of segment EA is:

[tex]EA = \sqrt{(-6 +0)^2+(0 - 7)^2} = 9.2[/tex]

Hence the perimeter is:

P = AB + BC + CD + DE + EA = 9.2 + 5 + 6 + 5 + 9.2 = 34.4 units.

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The solution for the initial value problem is [tex]y_{g} = e^{-2x} (-12cos(x) + 5sin(x)) + 7e^{-4x}[/tex]

Given,

y" + 4y' + 5y = 35[tex]e^{-4x}[/tex]

y(0) = -5

y'(0) = 1

Solve this homogenous equation to get [tex]y_{h}[/tex]

According to differential operator theorem,

[tex]y_{h}[/tex] = [tex]e^{ax}[/tex]( A cos (bx) + B sin (bx)), where A and B are constants.

Therefore,

y" + 4y' + 5y = 0

([tex]D^{2}[/tex] + 4D + 5)y = 0

D = -2± i    

[tex]y_{h} = e^{-2x} ( A cos (x) + B sin (x))[/tex]

Now, solve for [tex]y_{p}[/tex]

A function of the kind [tex]ce^{-4x}[/tex] is the function on the right, we are trying a solution of the form [tex]y_{p} =ce^{-4x}[/tex], here c is a constant.

[tex]y_{p} " + 4y_{p} ' + 5y_{p} = 35e^{-4x} \\=16ce^{-4x} -16ce^{-4x} +5ce^{-4x} = 35e^{-4x} \\= 5ce^{-4x} =35e^{-4x} \\c=\frac{35}{5} =7\\y_{p} =7e^{-4x}[/tex]

Then the general solution will be like:

[tex]y_{g} =y_{h} +y_{p} \\[/tex]

    = [tex]e^{-2x} (Acos(x)+Bsin(x))+7e^{-4x}[/tex]

[tex]y_{g}(0)=-5=A+7=-12\\y_{g} '(0)=e^{-2x} (-Asin(x)+Bcos(x))-2e^{-2x} (Acos(x)+Bsin(x))-28e^{-4x} \\y'_{g} (0)=1=B-2A-28\\[/tex]

       B = 1 - 24 + 28 = 5

Then the solution for the given initial value problem is

[tex]y_{g} =e^{-2x} (-12cos(x)+5sin(x))+7e^{-4x}[/tex]

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Answer:

Step-by-step explanation:

The relevant relations here are ...

The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:

  arc DA = 180° -CD = 180° -125° = 55°

Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.

 ∠ABO = 90° -∠AOB = 90° -55°

  ∠ABO = 35°

In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.

  ∠ACB = 90° -∠ABC = 90° -55°

  ∠ACB = 35°

In the figure, angles ABO and ACB have measures of 35°.

Profit function in terms of x = 33x + 390.

What is a profit in business?

Given that revenue, in dollars, of a company that makes skateboards can be modeled by the polynomial

[tex]2x^{3} + 30x - 130[/tex]

The cost, in dollars, of producing the skateboards can be modeled by

[tex]2x^{3} -3x - 520[/tex]

Profit function = Revenue - cost

                         = [tex]2x^{3} + 30x - 130 - ( 2x^{3} - 3x - 520)[/tex]

                          = 33x + 390

Therefore, profit function in terms of x = 33x + 390

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The width on the blueprint is 4 inches.

The blueprint is a scale drawing of the building. A scale drawing is a reduced form in terms of dimensions of an original image / building / object

The scale of a drawing is usually written in this format - length in the drawing, a colon (:), then the matching length on the original image. An example of a scale is 1 inch 12 feet. This scale means that 1 inch of the blueprint represents 12 feet of the building.

Width of the building on the blueprint = 48 / 12 = 4 inches

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Answer:

300 degrees

Step-by-step explanation:

pi should be 180 degrees so 5*180/3 = 5*60=300

Answer:

[tex] {216 \: in}^{3} [/tex]

Step-by-step explanation:

Split the chimney into 2 rectangular prisms. One is the short one, and the other is the tall one.

The dimensions of the short prism are 4 x 3 x 2. The volume of that prism is found by multiplying those numbers together, which is 24.

The dimensions of the tall prism are 4 x 4 x 12. The volume of that prism is 192.

Adding those 2 volumes together, you will get the volume of the composite figure. 192 + 24 = 216

Volume is always in cubic units

Answer:

Step-by-step explanation: This example is saying that adding a negative number is the same as subtracting a positive number. For example 2-3 = 2 + (-3).

The solution to the system of equations y = 1/2x - 6, x = -4 is x = -4 and y = -8. (x, y) = (-4, -8)

There are different types of equation. Namely;

y = 1/2x - 6

x = -4

y = 1/2x - 6

y = 1/2(-4) - 6

= -4/2 - 6

= -2 - 6

y = -8

Therefore,

The solution to the system of equations y = 1/2x - 6, x = -4 is x = -4 and y = -8. (x, y) = (-4, -8)

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The term "altitude" is the same as "height of a triangle". It is perpendicular to the base. Since we can rotate the triangle to have any side be horizontal, there are effectively 3 possible bases. Hence, there are 3 heights. It all depends how you look at it.

Let h1, h2, and h3 be the three altitudes or heights.

Without loss of generality, we'll focus on the first two heights h1 and h2. Their respective bases are b1 and b2.

If we use b1 as the base, then the area is...

area = 0.5*base*height = 0.5*b1*h1

Similarly, the other base gives the area of:

area = 0.5*b2*h2

------------------------

Since both formulas refer to the same area (because we're working with the same triangle), we can set the expressions equal to one another

0.5*b1*h1 = 0.5*b2*h2

b1*h1 = b2*h2

Let's see what happens when b1 = b2, so,

b1*h1 = b2*h2

b1*h1 = b1*h2

b1h1 - b1h2 = 0

b1(h1 - h2) = 0

b1 = 0 or h1 - h2 = 0

b1 = 0 or h1 = h2

If the bases b1 and b2 were equal, then either those bases must be 0 which isn't possible, or the altitudes must be equal. However, the initial premise is that the heights must be different from one another.

Therefore, the bases b1 and b2 can't be the same length.

We could follow the same steps and logic to conclude that if the altitudes h1 and h3 were different, then the bases b1 and b3 can't be the same. Similarly, we would conclude that b2 and b3 can't be the same. This is where the "without loss of generality" kicks in.

In other words, we only need to focus on one subcase to extend the logic to the other cases, without having to actually do every single step. That would be a bit tedious busywork.

In conclusion, we've shown that if the heights are different, then their respective bases must be different. This leads to wrapping up the proof that we have a scalene triangle.

Side note: I used an indirect proof or proof by contradiction. I assumed that a non-scalene triangle was possible and it led to a contradiction of h1 = h2.

The step which contains the first error in calculation is: B. Step 2 - the sine ratio was applied incorrectly.

The law of sines is also referred to as sine law or sine rule and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.

Mathematically, the law of sines is given by this equation:

[tex]\frac{sinA}{a} =\frac{sinB}{b}[/tex]

For any right-angled triangle, the ratio of the length of its opposite sides to the length of its hypotenuse is generally referred to as sine ratio. Thus, sine ratio is given by this formula:

cos(θ) = Opp/Hyp

Where:

In this context, we can infer and logically deduce that the step which contains the first error in calculation is step 2:

sin(W) = y/XZ; XZsin(W) = y.

In conclusion, the correct step should have been written as follows:

sin(W) = XZ/y; ysin(W) = XZ.

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Answer:

step 2 is incorrect

Step-by-step explanation:

B. Step 2 - the sine ratio was applied incorrectly

Answer:

w = -11

Step-by-step explanation:

[tex]\sqrt{3 - 2w} = w + 6[/tex]

[tex](\sqrt{3 - 2w})^2 = (w + 6)^2[/tex]

[tex] 3 - 2w = w^2 + 12w + 36 [/tex]

[tex] w^2 + 14w + 33 = 0 [/tex]

[tex] (w + 11)(w + 3) = 0 [/tex]

[tex] w + 11 = 0 [/tex]   or   [tex] w + 3 = 0 [/tex]

[tex] w = -11 [/tex]   or   [tex] w = -3 [/tex]

When you square both sides of an equation, you must check all solutions for extraneous solutions.

Check w = -11.

[tex]\sqrt{3 - 2w} = w + 6[/tex]

[tex] \sqrt{3 - 2(-11)} = -11 + 6 [/tex]

[tex] \sqrt{3 + 22} = -5 [/tex]

[tex] \sqrt{25} = -5 [/tex]

[tex] 5 = -5 [/tex]

This is a false statement, so the solution w = -11 is extraneous since it does not satisfy the original equation.

Check w = -3.

[tex]\sqrt{3 - 2w} = w + 6[/tex]

[tex] \sqrt{3 - 2(-3)} = -3 + 6 [/tex]

[tex] \sqrt{3 + 6} = 3 [/tex]

[tex] \sqrt{9} = 3 [/tex]

[tex] 3 = 3 [/tex]

This is a true statement, so the solution w = -3 is valid.

Answer: w = -11

Answer:

70

Step-by-step explanation:

8 choose 4: 8!/(4!*4!)=70

Answer:

1680

Step-by-step explanation:

the order matters so 8P4

The general soultion of the given differential equation  12y'' − 5y' − 3y = 0 is

y = [tex]c_{1}e^{\frac{-1}{3}x } +c_{2}e^{\frac{3}{4} x}[/tex].

According to the given question.

We have a differential equation

[tex]12y^{"} -5y^{'} -3y = 0[/tex]

The above equation can be written as

[tex](12D^{2} -5D -3)y = 0[/tex]

The auxillary equation for the above differential equation is

[tex]12m^{2} -5m-3 = 0[/tex]

[tex]\implies 12m^{2} -9m+4m -3 = 0[/tex]

⇒ 3m(4m - 3) +1(4m - 3) = 0

⇒ (3m + 1)(4m -3) = 0

⇒ m = -1/3 or 3/4

Therefore,

[tex]C.f = c_{1}e^{\frac{-1}{3}x } +c_{2}e^{\frac{3}{4} x}[/tex]

Here, P.I = 0

As we know that the general solution of the differential equation is given by

y = PI + CF

Thereofre, the general soultion of the given differential equation  12y'' − 5y' − 3y = 0 is

y = [tex]c_{1}e^{\frac{-1}{3}x } +c_{2}e^{\frac{3}{4} x}[/tex].

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Answer:

a = 12

x = 5.714

Step-by-step explanation:

sf = 15 / 9

20 / (15 / 9) = 12

a = 12

sf = 21 / 6

20 / (21 / 6)

x = 5.714

Answer: 8

Step-by-step explanation:

PEMDAS

**Disclaimer** Hi there! I am not fully sure what [ T ] represents. From the answer that I got [ 38π / 3 ], it does not match any one of them, so I choose none of the above. If there's a specific meaning of [ T ] and I am incorrect, please let me know and I will modify my answer.

Answer: None of above

Step-by-step explanation:

Given formula

S = r θ

Given information

radius = 19 ft

Angle = 2π / 3

Substitute values into the formula

S = r θ

S = (19) (2π / 3)

Simplify by multiplication

[tex]\Large\boxed{S=\frac{38\pi}{3} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

If the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.

Given that the faster car is travelling 20 mph faster than slower car and when slower car travels 165 miles the faster car travels 225 miles.

We are required to find the speed of slower car and faster car.

let the speed of slower car be x mph.

In this way the speed of faster car be (x+20) mph.

Speed=Distance/ time

We have to first take slower car.

x=165/Time

Time=165/x-----------1

Now by taking faster car.

x+20=225/time

Time=225/(x+20)-------2

From equation 1 an equation 2.

165/x=225/(x+20)

225x=165x+3300

225x-165x=3300

60x=3300

x=55 mph

Faster car=55+20

=75 mph.

Hence if the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.

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Answer: (2,9)

Step-by-step explanation:

The point lies in the region that is shaded by both inequalities.

The best information that describes your routes is the second route was steeper than your first, and the second route was higher up the mountain.

The slope of a linear equation is the change in the rise over the run. So, the slope of a linear equation shows that the larger the slope, the steeper the line becomes.

From the given information:

y = 2x + 4  --- (1)

y = 4x + 1  --- (2)

Using the slope-intercept formula:

y = mx + b

From the first equation, the slope is 2 and in the second equation, the slope is 4.

Therefore, we can conclude that the second route was steeper than your first, and the second route was higher up the mountain.

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There is only one statement that is true: B. The graph of the function is a parabola.

In this question we have a quadratic equation, whose characteristics have to be inferred and analyzed. We need to prove each of the five choices presented in the statement:

Choice A:

If we know that x = - 10, then we evaluated it at the function:

f(- 10) = (- 10)² - 5 · (- 10) + 12

f(- 10) = 162

False

Choice B:

By analytical geometry we know that all functions of the form y = a · x² + b · x + c always represent parabolae.

True

Choice C:

The quadratic function opens up as its leading coefficient is greater that 0.

False

Choice D:

If we know that x = 20, then we evaluate it at the function:

f(20) = 20² - 5 · (20) + 12

f(20) = 312

False

Choice E:

If we know that x = 0, then we evaluate it at the function:

f(0) = 0² - 5 · (0) + 12

f(0) = 12

There is only one statement that is true: B. The graph of the function is a parabola.

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