Find the value of x. Round to the
nearest tenth.
X
12
x= [?]
Enter

Answer: D. 6 cm

Step-by-step explanation:

V = 4/3πr^3

r = (3 V/4π)^1/3 = (3* 900/4*π)^1/3 = 5.98942

Answer:

TRIANGLE PROBLEM:

area : 6a^4

perimeter : 12a^2

SIMPLIFY problem:

-40c^2+26a^2+30ac

EVALUATE & FACTOR:

(q^2 - p) ( p^2 - q)

and the solved form is 240

hope it helps :)

Step-by-step explanation:

lol im an rsm kid too. but i hope these are right,

first i'm gonna start with 263 c.

AREA = 4a^2 * 3a^2 divided by 2.  

12a^4 divided by 2 = 6a^4.

AREA = 6a^4

Perimeter you can find with the pythag. th.

(4a^2) ^2 + (3a^2 ) ^2 = c^2

16a^4 + 9a^4 = c^2

, the missing side is 5a^2

therefore the perimeter is 4a^2 + 3a^2 + 5a^2 = 12a^2

ok next, im gonna do 266

the answer is -40c^2+26a^2+30ac

make sure to check this w/ symbo or mthway

ok last one!!

factored form is (q^2 - p) ( p^2 - q)

and the solved form is 240

To prove that removing the root of a k-th order binomial tree results in k binomial trees of smaller orders, we will use mathematical induction.

Base case: For k = 1, removing the root of a 1st order binomial tree results in zero smaller binomial trees, which is true.

Inductive hypothesis: Assume that removing the root of a k-th order binomial tree results in k binomial trees of smaller orders, for some positive integer k.

Inductive step: We want to prove that removing the root of a (k+1)-th order binomial tree results in (k+1) binomial trees of smaller orders.

By definition, a (k+1)-th order binomial tree, denoted by B(k+1), is formed by joining two k-th order binomial trees, denoted by Bk, with one of them as the leftmost child of the root of the other. Let us remove the root of B(k+1) to obtain a new binomial tree, denoted by B'.

Since B(k+1) is formed by joining two k-th order binomial trees, we can apply the inductive hypothesis to each of them to obtain that removing their roots results in k smaller binomial trees each. Let these smaller binomial trees be denoted by B1, B2, ..., Bk and C1, C2, ..., Ck,

respectively.

Now, consider B' and observe that it is a k-th order binomial tree, since it has k children, each of which is a smaller binomial tree. Moreover, B' is obtained from B(k+1) by removing the root, which is the parent of the two k-th order binomial trees Bk and Ck. Thus, we have decomposed B' into k smaller binomial trees, namely B1, B2, ..., Bk and C1, C2, ..., Ck.

Therefore, we have shown that removing the root of a (k+1)-th order binomial tree results in (k+1) binomial trees of smaller orders, which completes the induction.

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The mode of the data set given is 63.

Statistics uses the terms mean, median, and mode to describe central tendency. They each provide information about what value in a data set is conventional or representative of the data set in their own unique ways.

The number that appears the most frequently in a piece of data is the mode. Count the occurrences of each number in the data collection. The figure with the largest total is the mode. More than one mode is acceptable. Additionally, there is no mode if all numbers appear exactly once.

Given that:

62,63,67,66,66,63,62,68,69,65,67,63,64,

By rearrangement, we have:

62, 62, 63, 63, 63, 64, 65, 66, 66, 67, 67, 68, 69

Therefore, the highest occurring number(mode) is 63.

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Answer:

58 11/12

Step-by-step explanation:

Add up each item within the suitcase + the suitcase after taking out the items to find the weight of the suitcase at the beginning.

30 + 7 1/4 + 21 2/3

Convert the fractions to have a common denominator

30 + 7 3/12 + 21 8/12

Add these up to get 58 11/12.

Right Bisector also known as Perpendicular Bisector is a line that bisects another line segment at a right angle, through the intersection point.

First we will draw a line segment AB = 7 cm with the help ruler, then with vertex A, by using compass take more than half of AB and draw arcs, one each side of AB and mark them X and Y and then with vertex B, by using compass with same length again, cut the previous arcs at X and Y respectively.

Now, with help of ruler join the point X and Y. Thus XY is the perpendicular bisector of line AB.

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At least number of students who must have signed up to have all nine clubs is equal to 207.

Number of clubs school going to start after school = 9 clubs

At least number of students need to sign up in each one of the club is equal to 23 students.

At least number of students need to sign up to have all in nine clubs is equal to :

At least number of student in 1 club  > 23

⇒ At least number of student in 9 club  > 23 × 9

At least number of student in 9 club  > 207

Therefore, at least number of students need to signed up to have in all nine given clubs are 207 students.

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Answer:

339.3 cubic m

Step-by-step explanation:

r = Base radius

  = [tex]\frac{Diameter}{2}[/tex]

  = [tex]\frac{6}{2}[/tex] m

Base radius = 3 m

h = Perpendicular height

  = 12 m

Volume of a cylinder: [tex]\pi r^{2} h[/tex]

                                 = [tex]\pi (3 m)^{2} (12 m)[/tex]

                                 = [tex]\pi (108)m^{3}[/tex]

                                 = 339.3 cubic m (Rounded to the nearest tenths place)

The results are given below.

Two triangles are said to be congruent if all the corresponding sides are equal and all the corresponding angles are equal. The symbol of congruency is '≅'

Consider the first triangles,

Given, L is the midpoint of KN and MP.

To find ΔMKL ≅ΔPNL

Using side-angle-side congruency ,

Here, the corresponding sides , KM and MP, KL and LP are equivalent.

But the angle ∠L is not an included angle.

So this triangles are non congruent.

Consider the next triangles.

BD bisects ∠ABC ∠BAD≅∠BCD

To find ΔABC≅BCD

By side- side-side congruency,

The corresponding sides AB and BD, AD and DC, BD are equivalent.

Therefore this ΔABC≅BCD  proved.

Hence the proof.

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Probability that a randomly chosen part (a) has a P(flaw) = 0.2 and

has no major flaws b) P(No major flaws) = 0.95

The probability that an event will occur is determined by probability: P(A) = f / N. Probability and odds are related, but probability determines what the odds are. Probability is required before calculating the likelihood that an event will occur.

To find the probability of flaws, we can find the probability of no flaws first by dividing by 100:

P(no flaw) = 80/100 = 0.8

So then:

P(flaw) = 1 - P(no flaw) = 1 - 0.8 = 0.2

P(flaw) = 0.2

B) First, we need to find the probability of major flaws:

P(major flaws) =

P(Major flaws) = 0.05

So to find the probability of no major flaws:

P(No major flaws) = 1 - P(major flaws) = 1 - 0.05 = 0.95

P(No major flaws) = 0.95

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The system of equations has a unique solution. The solution of the system of equations is (-3,4).

What is the system of equations?

Simultaneous equations, a system of equations Two or more equations in algebra must be solved jointly (i.e., the solution must satisfy all the equations in the system). The number of equations must match the number of unknowns for a system to have a singular solution.

Given equations are

y = x + 7   ......(i)

y = -7/3x - 3   ......(ii)

Putting x = 0 in equations (i) and (ii):

y = 0 + 7

y = 7

y = -7/3 × 0 - 3

y = -3

Putting x = 3 in equations (i) and (ii):

y = 3 + 7

y =10

y = -7/3 × 3 - 3

y = -10

Putting x = -3 in equations (i) and (ii):

y = -3 + 7

y = 4

y = -7/3 × (-3) - 3

y = 4

The points in equation (i) are (0,7), (3,10), (-3,4)

The points in equation (ii) are (0,-4), (3,-10), (-3,4)

Plot the points and join the points:

The intersection of the equation is (-3,4).

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5.4%   is the percent error .

What is the formula for errors?

The difference between the estimated value and the actual value in relation to the actual value is given as a percentage and is known as the percent error.

                             The relative error is multiplied by 100 to calculate the % error, in other words. The absolute value of the difference between the measured value and the actual value is divided by the actual value, then multiplied by 100 to get the percent error. 

 = 500 - 473/500  * 100

 =   27/500 * 100

 =   5.4%

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There were originally 10 puppies in the litter, as of the given condition.

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,
We can represent the number of original puppies as "x", and the sequence of events can be represented as:

Sold half of the puppies, so they have x/2 left - 1 sold to the local pet shop.

Sold half of the remaining puppies, so they have (x/2 - 1)/2 left sold to poodle palace.

One puppy was given to Grace, so they have ((x/2 - 1)/2- 1 = x - 2 / 4 - 1 remaining.

Since they are left with x - 2 / 4 - 1  puppies in the end, we can set this equal to 1 (the remaining puppy given to Grace), and solve for x:

x - 2 / 4 - 1  = 1

x - 2 = {1 + 1} * 4
x = 8 + 2
x = 10

Therefore, there were originally 10 puppies in the litter.

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The algebraic expression for the amount of etergent remaining in the container isy = x - 13 - 4 - 73

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are given that;

13 4 73

Let's define the variable 'x' to represent the amount of detergent initially present in the container.

Then, if 'y' represents the amount of detergent remaining in the container, we can write an algebraic expression for it as:

y = x - 13 - 4 - 73

where:

13 represents the amount of detergent used on the first day

4 represents the amount of detergent used on the second day

73 represents the amount of detergent used on the third day

By subtracting the total amount of detergent used from the initial amount 'x', we get the remaining amount 'y'.

Therefore, the expression will be y = x - 13 - 4 - 73.

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The transformed functions is

a) The absolute value function reflected across the x axis and shifted up 2 units is y₁ = -| x₁ | + 2

b) The absolute value function that is shifted left 3 units and is compressed by a third is y₂ = ( 1/3 ) | x₂ + 3 |

c) The absolute value function reflected across the x axis stretched vertically by 5 units shifted left 4 units and up 6 units is y₃ = -5 | x₃ + 4 | + 6

The transformation of a function may involve any change.

Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs), etc.

If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:

Horizontal shift (also called phase shift):

Left shift by c units: y=f(x+c) (same output, but c units earlier)

Right shift by c units: y=f(x-c)(same output, but c units late)

Vertical shift:

Up by d units: y = f(x) + d

Down by d units: y = f(x) - d

Stretching:

Vertical stretch by a factor k: y = k × f(x)

Horizontal stretch by a factor k: y = f(x/k)

Given data ,

a) The absolute value function reflected across the x axis and shifted up 2 units is y₁

The absolute value function is y₁ = | x₁ |

when reflected over x axis , the new function is

y₁ = - | x |

when shifted up 2 units ,

y₁ = -| x₁ | + 2

b)The absolute value function that is shifted left 3 units and is compressed by a third is y₂

The absolute value function is y₂ = | x₂ |

when shifted left 3 units ,

y₂ = | x₂ + 3 |

when compressed by a third , the new function is

y₂ = ( 1/3 ) | x₂ + 3 |

c)The absolute value function reflected across the x axis stretched vertically by 5 units shifted left 4 units and up 6 units is y₃

The absolute value function is y₃ = | x₃ |

when reflected across the x axis ,

y₃ = - | x₃ |

when stretched vertically by 5 units ,

y₃ = - 5 | x₃ |

when shifted 4 units left ,

y₃ = - 5 | x₃ + 4 |

when shifted 6 units up ,

y₃ = -5 | x₃ + 4 | + 6

Hence , the transformation of functions are solved

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The histogram of the magazine ranks the best paying college degrees in a country is illustrated below.

A histogram is a graphical representation of data that displays the frequency distribution of a set of continuous or discrete data

To construct a histogram, we would first need to determine the range of the data. In this case, the range would be the difference between the highest and lowest starting salaries or mid-career salaries. We would then divide the range into several intervals or "bins" of equal width.

For example, if we use a bin width of $10,000, the first bin would be $40,000-$49,999, the second bin would be $50,000-$59,999, and so on.

We would then count the number of degrees that fall into each bin and plot the counts as bars on a graph, with the bin ranges on the x-axis and the frequency counts on the y-axis. The resulting graph would be a histogram, showing the distribution of the data.

It is important to label the axes of the histogram and include a title that accurately reflects the data being presented.

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Complete Question:

Suppose a magazine ranks the best paying college degrees in a country. The following data show the median starting salary, the mid- career salary, and the percentage increase from starting salary to mid-career salary for the 20 college degrees with the highest mid- career salary.

Degree                     Starting Salary | Mid-Career Salary | % Increase

College Degree A      59,400                     104,000                       75 College Degree B     56,400                      101,000                        79 College Degree C     54,800                      101,000                        84             College Degree D     64,800                      104,000                        60    College Degree E      53,500                       93,400                        75           College Degree F       61,200                       87,700                        43              College Degree G       56,200                      97,700                        74            College Degree H       50,400                      87,000                        73            College Degree I         48,800                     97,800                       100                                College Degree J         60,800                     107,000                      76 College Degree K       47,500                      91,500                              

Frequency 40-49.9

Using a class width of 10, construct a histogram for the percentage increase in the starting salary.

Gloria walked  500500 Miles from nearest bus stop to home.

How to convert yards into miles ?

To convert a yard measurement to a mile measurement, divide the length by the conversion ratio.

Since one mile is equal to 1,760 yards, you can use this simple formula to convert:

miles = yards ÷ 1,760

The length in miles is equal to the yards divided by 1,760.

Given:

Gloria traveled : 888 miles

1 Mile = 1760 yards

880880880 yards = 500500 Miles

So she walked  500500 Miles from nearest bus stop to home.

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The area of the composite figure is equal to 254 m² square metres.

The composite figure can be observed to be a vertical rectangle, a square and an horizontal rectangle, so we shall calculate for the areas of the three figures and then add the result to get the total area of the composite figure as follows:

area of the vertical rectangle = 19 m × 7 m

area of the vertical rectangle = 133 m²

area of the square = 5 m × 5 m

area of the square = 25 m²

area of the horizontal rectangle = 16 m × 6 m

area of the horizontal rectangle = 96 m²

total area of the composite figure = 133 m² + 25 m² + 96 m²

total area of the composite figure = 254 m²

Therefore, the area of the composite figure is equal to 254 m² square metres.

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Answer:

93

Step-by-step explanation:

Answer:

27

28

Step-by-step explanation:

Answer:feet occurs most often. Mick recorded the lengths of 10 Steller sea lions.

Step-by-step explanation:feet occurs most often. Mick recorded the lengths of 10 Steller sea lions.

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{135\% of 160}}{\left( \cfrac{135}{100} \right)160}\implies \text{\LARGE 216}[/tex]

On solving the provided question, we can say that  Here, 21 and 22 only share a single element, which is 1. Since they are co-prime factor, their HCF equals 1.

Any natural number other than 1 with just itself and the number 1 as its divisors is considered a prime factor. Actually, 2, 3, 5, 7, 11, and so on are some of the first prime numbers. an amount that has been multiplied to produce another amount. By dividing 15 by 3 and 5, for instance, we get 3 5 = 15. main elements: Prime factors include all factors that are prime but are not composite. A few prime factors of 30 are 2, 3, and 5. Only 2 and 3 are prime factors of 12, so listing 2 twice as 2 2 3 (or 22 3) is necessary to factorize 12. The sum of 2 + 3 is not 12.

21 and 22:

1, 3, 7, and 21 are the factors of 21.

1, 2, 11, and 22 are the factors of 22.

Here, 21 and 22 only share a single element, which is 1. Since they are co-prime, their HCF equals 1.

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The piecewise function for the graph is given as follows:

A piecewise function is a function that has different definitions, depending on the input x of the function.

The three different definitions for the function in this problem are given as follows:

For x < -4, the function is constant at y = -2, hence:

y = -2, x < -4.

For -4 < x ≤ 2, the function is linear, with an slope of 0.5 and intercept of 4, hence:

y = 0.5x + 4, -4 < x ≤ 2

For x > 2, the function is also linear, with slope of -1.5, hence at x = 0 it would assume a value of 1, thus:

y = -1.5x + 1, x > 1.

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The probability distribution of the random variable Y is 0.63, 0.25, 0.12. The mean of y is 0.4899 and the std deviation of y is 0.6999 and the mean of the selling price for the fat quarters sold by Company G is $4.4 and the std deviation for the same is $0.99

a) x = number of defects on a fat quarter

to be sold, X must be, X ≤ 2

y = number of defects on the sellable fat quarter,

now from the table, P [fat quarter being sellable]

=P [X ≤ 2]

=0.58 + 0.23 + 0.11

= 0.92

Therefore, P[y-0] = P[x=0Ix≤2]

=[tex]\frac{P[x=0][x < 2]}{P[x < 2]}[/tex]

=P[y=0] = 0.63

P[y=1] = P[x=1Ix≤2]

P[y=1] = [tex]\frac{0.23}{0.92}[/tex]

=0.25

P[y=2] = P[x=2Ix≤2]

P[y=2] = [tex]\frac{0.11}{0.92}[/tex]

= 0.12

y------------------0--------1---------2

probability---0.63----0.25----0.12

b)mean of y = E(y)

=0²×0.063+1×0.25+2×0.12

=0.25+0.24

=0.49

now we know that E(y²) = 0²×0.63+1²×0.25+2²×0.12

=0.25+0.48

=0.73

E(y²) - [E(y)]²

=0.73-0.49²

=0.4899

std deviation of y = 0.6999

c) now that we have E(G) = 0.40, √v(G) = 0.66

let s be selling price of fat quarters, then s = 5.00 - 1.50 × (G)

therefore = 5-1.5×0.4

=5-0.6

=$4.4 is the mean selling price.

now for the standard deviation price = v[5-1.5G]

=v(5)+1.5² v(G)

=0+2.25×0.66²

=v(s)= 0.9801

standard deviation of sp =√v(s)

=$0.99

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Answer:

788883332220+2648340

Step-by-step explanation:

what is energy transferred

Answer:

1. $1900

2. $9

Step-by-step explanation:

Part a:

‘If she doesn’t sell any copies of History is Fun’ means x = 0:

[tex]y = 1900 + 9(0)[/tex]

∴ y = Melissa’s total pay = $1900

Part b:
Rearranging the equation:

[tex]y = 9x + 1900[/tex]

∴m = slope of equation = positive 9

  c = y-intercept = 1900

The shape of the graph would be increasing or ascending. And since the Number of copies (x) can never be negative, this means that the amount of pay CANNOT be less than $1900. The amount of $1900 is her minimum pay

The value of m for this equation indicates the change in Melissa’s total pay for every copy she sells.

∴Change in Melissa’s total pay = 9 dollars

Answer: A parabola can be defined as the set of all points that are equidistant from a focus and a directrix. Based on the information provided, the focus of the parabola is (0, 4) and the directrix is y =.

The parabola will open upwards or downwards depending on the location of the focus and the directrix. Since the focus is at (0, 4), and the directrix is at y =, the parabola must open upwards. The axis of symmetry of the parabola will pass through the focus and will be perpendicular to the directrix.

Without more information, it is not possible to fully determine the shape and equation of the parabola. The shape of the parabola and its equation can be found by using the focus and directrix and other information, such as the vertex or a point on the parabola.

Step-by-step explanation:

Answer: 5 1/4

Step-by-step explanation: