Find the value of x

Help please

Answer:

30 seconds

Step-by-step explanation:

→ Work out how many floors it's going to travel

15 - 3 = 12 floors

→ Work out how many meters 12 floors is

12 × 5 = 60 meters

→ Work out how long that will take

60 ÷ 2 = 30 seconds

Answer:

None of the options is true

Step-by-step explanation:

Given

[tex]y < 3x - 1[/tex]

[tex]y > -x + 4[/tex]

Required

Which makes the above inequality true

The missing options are:

[tex](4,0)\ (1,2)\ (0,4)\ (2,1)[/tex]

[tex](a)\ (x,y) = (4,0)[/tex]

Substitute values for x and y in the inequalities

[tex]y < 3x - 1[/tex]

[tex]0<3*4 - 1[/tex]

[tex]0<12 - 1[/tex]

[tex]0<11[/tex] ---- This is true

[tex]y &gt; -x + 4[/tex]

[tex]0 > -4 + 4[/tex]

[tex]0 > 0[/tex] --- This is false

[tex](b)\ (x,y) = (1,2)[/tex]

Substitute values for x and y in the inequalities

[tex]y &lt; 3x - 1[/tex]

[tex]2<3 * 1 - 1[/tex]

[tex]2<3 - 1[/tex]

[tex]2<2[/tex] --- This is false (no need to check the second inequality)

[tex](c)\ (x,y) = (0,4)[/tex]

Substitute values for x and y in the inequalities

[tex]y &lt; 3x - 1[/tex]

[tex]4< 3*0-1[/tex]

[tex]4< 0-1[/tex]

[tex]4<-1[/tex] --- This is false (no need to check the second inequality)

[tex](d)\ (x,y) = (2,1)[/tex]

Substitute values for x and y in the inequalities

[tex]y &lt; 3x - 1[/tex]

[tex]1<3*2-1[/tex]

[tex]1<6-1[/tex]

[tex]1<5[/tex] --- This is true

[tex]y &gt; -x + 4[/tex]

[tex]1 > -2+4[/tex]

[tex]1 > 2[/tex] -- This is false

Hence, none of the options is true

Answer:

Population

Step-by-step explanation:

A population can be defined as the total number of living organisms living together in a particular place and sharing certain characteristics in common.

A sample survey is a statistical method used for the collection of data from a target population in order to draw an inference and reach a logical conclusion.

In Statistics, sampling can be defined as a process used to collect or select data (objects, observations, or individuals) from a larger statistical population using specific procedures.

In this scenario, the entire group of registered voters in Florida is an example of a population.

Answer:

C.) AA

Step-by-step explanation:

AA is a similarity theorem

hope this helps stay safe :)

Answer:

The answer would be C.

Step-by-step explanation: Hope this helps :)

Answer:

x =48.6

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp side / hypotenuse

sin x = 54 /72

Taking the inverse sin of each side

sin ^ -1( sin x) =sin ^-1 ( 54/72)

x = 48.59037789

To the nearest tenth

x =48.6

Answer:36.9

Step-by-step explanation:

Answer: B

Step-by-step explanation:

multiply all the the sales by 11% and you will get the answers in option b

ex: 1300*0.11=143

Answer:

44

Step-by-step explanation:

5+8/4*3

5+24/4

20+24

44

Answer:

She Dives 13 Feet

Step-by-step explanation:

3+10=13

Mila's depth from the diving board to the bottom of the pool is 13 feet.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that Mila first stands on a diving board 3 feet above the surface of the water .she then dives to the bottom of the pool to a depth of 10 feet.

The total depth will be calculated as below:-

Depth = 3 + 10

Depth = 13 feet

Therefore, Mila's depth from the diving board to the bottom of the pool is 13 feet.

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Answer:

[tex]y=\frac{15\sqrt{3}}{4}[/tex]

Step-by-step explanation:

We are given that

[tex]\theta_1=60^{\circ}[/tex]

[tex]\theta_2=30^{\circ}[/tex]

We have to find the missing part.

[tex]\frac{x}{15}=cos\theta_1=cos60^{\circ}[/tex]

Using the formula

[tex]\frac{base}{hypotenuse}=cos\theta[/tex]

[tex]x=15cos60^{\circ}=\frac{15}{2}[/tex]

[tex]\frac{z}{15}=sin60^{\circ}[/tex]

Using the formula

[tex]\frac{Perpendicular\;arm}{hypotenuse}=sin\theta[/tex]

[tex]z=15\times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3}}{2}[/tex]

Now,

[tex]\frac{a}{x}=cos60^{\circ}[/tex]

[tex]\frac{a}{\frac{15}{2}}=\frac{1}{2}[/tex]

[tex]a=\frac{1}{2}\times 15/2=\frac{15}{4}[/tex]

[tex]y=x sin60^{\circ}[/tex]

[tex]y=\frac{15}{2}\times \frac{\sqrt{3}}{2}[/tex]

[tex]y=\frac{15\sqrt{3}}{4}[/tex]

Hello,

Let 's  n the number of sides,

R the radius of the circonscrit circle,

c the side of the polygon (c like côté)

Angle in the center is 360/n and its half is 180/n

(c/2)/R=sin(180/n)

Inside angles are (180-360/n)/2 = 90-180/n (°)

Answer:

x = 0

Step-by-step explanation:

This is a vertical line, in fact the y- axis

The equation of a vertical line is

x = c

where c is the value of the x- coordinates the line passes through

All of the x- coordinates on the y- axis are zero, then

x = 0 ← equation of line

Answer:

X = 88 degrees

Step-by-step explanation:

Because its an isosceles triangle the two top angles are 46.

46 + 46 = 98

then you take the degree of the triangle 180 and subtract 98 from it to get 88 degrees

The ordered pairs of the transformation are A'(1,2), B'(1,-2), C'(-2,2) of the coordinates of the triangle ABC are A(2,3),B(2,-1),C(-1,-1).

What is meant by coordinates?

They are the points which together when jointed form a triangle.

How to do transformation of a triangle?

The transformation of triangle whose coordinates are as A(2,3), B(2,-1), C(-1,-1) is done as follows:

A'=(2-1,3-1)=(1,2)

B'=(2-1,-1-1)=(1,-2)

C'=(-1-1,-1-1)=(-2,-2)

Hence the ordered pairs are (1,2)(1,-2)(-2,-2).

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Answer:

Vertex= (-5,-4)

Another point=(0, -129)

Step-by-step explanation:

The vertex is also the maximum, and the point is also the y-intercept.

Answer:

B

Step-by-step explanation:

The explicit rule for a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 64 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{128}{64}[/tex] = 2 , then

[tex]a_{n}[/tex] = 64 [tex](2)^{n-1}[/tex] → B

Answer:

b).

[tex]{ \tt{a _{n} = a( {r}^{n - 1} )}} \\ { \tt{a _{n} = 64( {2}^{n - 1}) }}[/tex]

Answer:

yeah,I think it's 16 ...

Step-by-step explanation:

=(g-f)(n)

=4n+7-2n-3

=2n+4

pls mark me as brainlist

thanks a lot

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

[tex](a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x[/tex]

[tex](b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)[/tex]

[tex](c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x[/tex]

[tex](d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x[/tex]

Thus, all the identities are correct.

A. Not an identity

B. An identity

C. Not an identity

D. An identity

To check whether each expression is an identity, we need to verify if the equation holds true for all values of the variable x. If it is true for all values of x, then it is an identity. Let's check each option:

A. [tex]\((\sin x + \cos x)^2 = 1 + \sin 2x\)[/tex]

To check if this is an identity, let's expand the left-hand side (LHS):

[tex]\((\sin x + \cos x)^2 = \sin^2 x + 2\sin x \cos x + \cos^2 x\)[/tex]

Now, we can use the trigonometric identity [tex]\(\sin^2 x + \cos^2 x = 1\)[/tex] to simplify the LHS:

[tex]\(\sin^2 x + 2\sin x \cos x + \cos^2 x = 1 + 2\sin x \cos x\)[/tex]

The simplified LHS is not equal to the right-hand side (RHS) 1 + sin 2x since it is missing the sin 2x term. Therefore, option A is not an identity.

B. [tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]

To check if this is an identity, we can use the double-angle identity for sine:[tex]\(\sin 2\theta = 2\sin \theta \cos \theta\)[/tex]

Let [tex]\(2\theta = 6x\)[/tex], which means [tex]\(\theta = 3x\):[/tex]

[tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]

The equation holds true with the double-angle identity, so option B is an identity.

C. [tex]\(\frac{\sin 3x}{\sin x \cos x} = 4\cos x - \sec x\)[/tex]

To check if this is an identity, we can simplify the right-hand side (RHS) using trigonometric identities.

Recall that [tex]\(\sec x = \frac{1}{\cos x}\):[/tex]

[tex]\(4\cos x - \sec x = 4\cos x - \frac{1}{\cos x} = \frac{4\cos^2 x - 1}{\cos x}\)[/tex]

Now, using the double-angle identity for sine, [tex]\(\sin 2\theta = 2\sin \theta \cos \theta\),[/tex] let [tex]\(\theta = x\):[/tex]

[tex]\(\sin 2x = 2\sin x \cos x\)[/tex]

Multiply both sides by 2: [tex]\(2\sin x \cos x = \sin 2x\)[/tex]

Now, the left-hand side (LHS) becomes:

[tex]\(\frac{\sin 3x}{\sin x \cos x} = \frac{\sin 2x}{\sin x \cos x}\)[/tex]

Using the double-angle identity for sine again, let [tex]\(2\theta = 2x\):[/tex]

[tex]\(\frac{\sin 2x}{\sin x \cos x} = \frac{2\sin x \cos x}{\sin x \cos x} = 2\)[/tex]

So, the LHS is 2, which is not equal to the RHS [tex]\(\frac{4\cos^2 x - 1}{\cos x}\)[/tex]. Therefore, option C is not an identity.

D. [tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \tan x\)[/tex]

To check if this is an identity, we can use the sum-to-product trigonometric identities:

[tex]\(\sin A - \sin B = 2\sin \frac{A-B}{2} \cos \frac{A+B}{2}\)\(\cos A + \cos B = 2\cos \frac{A+B}{2} \cos \frac{A-B}{2}\)[/tex]

Let A = 3x and B = x:

[tex]\(\sin 3x - \sin x = 2\sin x \cos 2x\)\(\cos 3x + \cos x = 2\cos 2x \cos x\)[/tex]

Now, we can rewrite the expression:

[tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \frac{2\sin x \cos 2x}{2\cos 2x \cos x} = \frac{\sin x}{\cos x} = \tan x\)[/tex]

The equation holds true, so option D is an identity.

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Answer:

A

Step-by-step explanation:

6/3 = 2

Answer:

$2 each

Step-by-step explanation:

3 pounds of apples for $6

$6÷3 lbs= $2 each pound

Hello,

[tex]f^{-1}(f(58))=(f^{-1}*f)(58)=1(58)=58\\f(f(5)=f(9)=11\\[/tex]

Answer:

It is d

Step-by-step explanation:

Answer:

7 cajas grandes y 3 cajas pequeñas  

Step-by-step explanatio:

Answer:

Step-by-step explanation:

Answer:

The second one

Step-by-step explanation:

Obejctive: Real Wolrd Algebra.

X represent number of pound peaches sold and Y represent the total cost of the peaches. We can represent this as

[tex]y = 2x[/tex]

If someone sell something, they cant get negative profit from it, and if no one buy it, it doesnt mean that it will decrease the seller profit.

Using that knowledge, let go through each answer.

The first one is wrong, Real Numbers include negative numbers and you can't negatively sell something so that means you cant lose profit for not selling something( In some instances, you can but for this sake of the problem, you cant).

The second one is right It is possible that you dont sell nothing and gain no money from it. So y and xcan be zero. it also possible you sell something and get money from it.

The third one is wrong, it is possible that you sell something and get profit from it.

The fourth one is wrong, x can be any real number as long its greater than zero. Y can be any real number as long as it greater than zero, but it doesnt have to be a interger( counting number). What if you sell 1.3 pounds of peaches, you will get 2.6

Answer:

A=2

B=8

C=-38

X=2.8/X=-6.8

Step-by-step explanation:

(x-2)(x+2) is factorize is given eq

Answer:

Step-by-step explanation:

The ages of Raju and Ravi are in the ratio 3:4 .Four years from now the ratio of their ages will be 4:5 . Find their present ages.

Ratio of ages at present = 3:4

Age of Raju = 3x

Age of Ravi = 4x

Age after four years:

Raju's age  = 3x + 4

Ravi's age = 4x + 4

Ratio of ages after four year = 4 : 5

3x +4 : 4x + 4 = 4 : 5

(4x + 4)*4 = (3x + 4)*5

16x + 16 = 15x + 20  

Subtract 16 from both sides

16x  = 15x + 20 - 16

16x = 15x + 4

Subtract 15x from both sides

16x - 15x = 4

 x = 4

Age of Raju = 3x = 3*4 = 12 years

Age of Ravi = 4x = 4*4 = 16 years

Step-by-step explanation:

oh oh can you capture a picture of it because you don't understand

Answer:

The actual price of the article was Rs. 1200.

Step-by-step explanation:

mp (marked price)

ap (actual price)

[tex]mp = 1380[/tex]

[tex]mp = ap + 15\%(ap)[/tex]

[tex]1 380 = ap + \frac{15}{100} ap[/tex]

[tex]1380 = \frac{100}{100} ap + \frac{15}{100} ap[/tex]

[tex]1380 = \frac{115}{100} ap[/tex]

[tex]1380 \div \frac{115}{100} = ap[/tex]

[tex]1380 \times \frac{100}{115} = ap[/tex]

[tex] \frac{138000}{115} = ap[/tex]

[tex]1200 = ap[/tex]

The actual price of the article is given by the equation A = $ 1,200

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the actual price of the article be A

Now , the equation will be

The marked price of the article be = $ 1380

The percentage of increase from the actual price = 15 %

So , the equation is

The actual price + percentage of increase from the actual price = 1380

Substituting the values in the equation , we get

A + ( 15/100 )A = 1380   be equation (1)

( 115/100 ) A = 1380

Multiply by 100 on both sides of the equation , we get

115A = 138000

Divide by 115 on both sides of the equation , we get

A = $ 1200

Therefore , the value of A is $ 1200

Hence , the actual price of the article is $ 1200

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